I have a table that receives a .JSON.
I have created some filters and I would like to save them but without saving the information that I received at that time with the filter.
I already tried:
pivot.getData({},
function(data) {
console.log(data);
},
function(data) {
console.log(data);
}
);
Too
var report = pivot.getReport();
console.log(report);
by last
pivot.save({filename:'reporte.json',embedData : false });
Thanks for your help
There are several ways to achieve what you need:
You can still use:
var report = pivot.getReport();
the data information is stored in report["dataSource"]. In such a
case, you can easily remove the unnecessary object the following
way:
delete report["dataSource"];
After that, the JSON config is saved as a file to the disk using
the following approach:
JavaScript: Create and save file.
The disadvantage of such a solution is that you cannot use the saved
JSON config to restore the view since it lacks the data part. You will need to add the "dataSource" part when you decide to restore
the view. Therefore, the solution that described below looks better
for me.
You can create a web service that returns the data file or simply put the JSON data file to the server. In such a case,
WebDataRocks will load the data for you. Then, when you decide to
save the config, only the link to the data will be saved to config.
Here is the reference to docs:
https://www.webdatarocks.com/doc/data-source-object/. The
"filename" property represents the link which leads to your data
file.
In such a case you don't need any additional customization for the
"Save" functionality. You can use a default one. Then it is easy to restore the view using the saved config.
I started to write a scraper for the site to collect data on cars. As it turned out, the data structure can change, since the sellers do not fill all the fields, because of what there are fields that can change, and during the scraper as a result in the csv file, the values are in different fields.
page example:
https://www.olx.ua/obyavlenie/prodam-voikswagen-touran-2011-goda-IDBzxYq.html#87fcf09cbd
https://www.olx.ua/obyavlenie/fiat-500-1-4-IDBjdOc.html#87fcf09cbd
data example:
Data example
One approach was to check the field name with text () = "Category name", but I'm not sure how to correctly write the result to the correct cells.
Also I use the built-in Google developer tool, and with the help of the command document.getElementsByClassName('margintop5')[0].innerText
I brought out the whole contents of the table, but the results are not structured.
So, if the output can be in json format then it would solve my problem?
innerText result
In addition, when I studied the page code, I came across a javascript script in which all the necessary data is already structured, but I do not know how to get them.
<script type="text/javascript">
var GPT = GPT || {};
GPT.targeting = {"cat_l0":"transport","cat_l1":"legkovye-avtomobili","cat_l2":"volkswagen","cat_l0_id":"1532","cat_l1_id":"108","cat_l2_id":"1109","ad_title":"volkswagen-jetta","ad_img":"https:\/\/img01-olxua.akamaized.net\/img-olxua\/676103437_1_644x461_volkswagen-jetta-kiev.jpg","offer_seek":"offer","private_business":"private","region":"ko","subregion":"kiev","city":"kiev","model":["jetta"],"modification":[],"motor_year":[2006],"car_body":["sedan"],"color":["6"],"fuel_type":["543"],"motor_engine_size":["1751-2000"],"transmission_type":["546"],"motor_mileage":["175001-200000"],"condition":["first-owner"],"car_option":["air_con","climate-control","cruise-control","electric_windows","heated-seats","leather-interior","light-sensor","luke","on-board-computer","park_assist","power-steering","rain-sensor"],"multimedia":["acoustics","aux","cd"],"safety":["abs","airbag","central-locking","esp","immobilizer","servorul"],"other":["glass-tinting"],"cleared_customs":["no"],"price":["3001-5000"],"ad_price":"4500","currency":"USD","safedealads":"","premium_ad":"0","imported":"0","importer_code":"","ad_type_view":"normal","dfp_user_id":"e3db0bed-c3c9-98e5-2476-1492de8f5969-ver2","segment":[],"dfp_segment_test":"76","dfp_segment_test_v2":"46","dfp_segment_test_v3":"46","dfp_segment_test_v4":"32","adx":["bda2p24","bda1p24","bdl2p24","bdl1p24"],"comp":["o12"],"lister_lifecycle":"0","last_pv_imps":"2","user-ad-fq":"2","ses_pv_seq":"1","user-ad-dens":"2","listingview_test":"1","env":"production","url_action":"ad","lang":"ru","con_inf":"transportxxlegkovye-avtomobilixx46"};
data in json dict
How can I get the data from the pages using python and scrapy?
You can do it by extracting the JS code from the <script> block, using a regex to get only the JS object with the data and then loading it using the json module:
query = 'script:contains("GPT.targeting = ")::text'
js_code = response.css(query).re_first('targeting = ({.*});')
data = json.loads(js_code)
This way, data is a python dict containing the data from the JS object.
More about the re_first method here: https://doc.scrapy.org/en/latest/topics/selectors.html#using-selectors-with-regular-expressions
I have json file with given data (total.json)
var data = {"trololo":{"info":"61511","path".... }}
I need to get object "info" and then print data "61511" in alert window
I include my json like
var FILE = 'total'
var data_file_names = {};
data_file_names[FILE] = 'total.json';
And then i use it like
var data_trololo = data_file_names[FILE];
Plese, help me print object "info". Maybe there is another way to solve this problem
You need to make an ajax call to the json file. Then you can access the array like the below example.
Note : Your json wasn't properly formatted.
var data = {
"trololo":{
"info": ["61511","path"]
}
};
console.log(data.trololo.info[0]); //this one will print 61511
Usually one can make an ajax call to read the file on the server.
But if you are ok with using HTML5 features then go through the link find out how to read the file on the browser itself. Though File API being part of HTML5 spec is stable across browsers.
http://www.html5rocks.com/en/tutorials/file/dndfiles/
I set up a datatables that initially gets from server some data and represents it, but then everything is left to the client. Some options are:
serverSide: false,
sAjaxSource: mySource,
My $.fn.DataTable.version is 1.10.2.
Then I need to change, client-side, the aaData under the table because some working on data is performed. I need to update the DT to show the client-altered temporary data without send another request to server (for two reason: prevent useless traffic and because that data is being altered).
I am looking for a way to edit the underlying DT databean to edit it, so then calling again
myTable.draw();
on my table I obtain a refresh realtime without sending another get to the server.
The question is, can I access DT data array, and can I edit it?
How is it done if is possible?
EDIT: I need to feed the table the full bean array as it initially took from the server, same format. So individual row/cell add/edit and client-side building functions are not suitable in my case, unless I manually cicle all objects.
SOLUTION
Use the code below:
// Retrieve data
var data = table.ajax.json();
// Modify data
$.each(data.data, function(){
this[0] = 'John Smith';
});
// Clear table
table.clear();
// Add updated data
table.rows.add(data.data);
// Redraw table
table.draw();
DEMO
See this jsFiddle for code and demonstration.
I'm creating an android app which takes in some json data, is there a way to set up a directory such as;
http://......./jsons/*.json
Alternatively, a way to add into a json file called a.json, and extend its number of containing array data, pretty much add more data into the .json file this increase its size.
It could be by PHP or Javascript.
Look into Parsing JSON, you can use the JSON.parse() function, in addition, I'm not sure about getting all your JSON files from a directory call, maybe someone else will explain that.
var data ='{"name":"Ray Wlison",
"position":"Staff Author",
"courses":[
"JavaScript & Ajax",
"Buildinf Facebook Apps"]}';
var info = JSON.parse(data);
//var infostoring = JSON.stringify(info);
One way to add to a json file is to parse it, add to it, then save it again. This might not be optimal if you have large amounts of data but in that case you'll probably want a proper database anyway (like mongo).
Using PHP:
$json_data = json_decode(file_get_contents('a.json'));
array_push($json_data, 'some value');
file_put_contents('a.json', json_encode($json_data));