Get result displayed in form / textfield - javascript

I have an ajax script which fetches results from a web-service and displays them in a div, however I would like them to be displayed in an input area / text field.
My main script:
<script type="text/javascript">
function get_CODES_Results() {
document.getElementById("results").innerHTML = "<img src=\'loading.gif\' />";
var url = document.location;
if (window.XMLHttpRequest) req = new XMLHttpRequest();
else if (window.ActiveXObject) req = new ActiveXObject("Microsoft.XMLHTTP");
req.onreadystatechange = processRequest;
//req.open("GET", url, true);
//req.send(null);
req.open("POST",url,true);
req.setRequestHeader("Content-type","application/x-www-form-urlencoded");
req.send("codes="+document.getElementById("codes").value);
function processRequest() {
if (req.readyState == 4) {
document.getElementById("results").innerHTML = req.responseText;
}
}
}
</script>
And here the area where it is being displayed:
<p>
<h3>Results:</h3>
<div id="results"></div>
</p>
My question:
How can I achieve that my result is displayed in an input/text-field?
Some advice would be highly appreciated - thank you, Patrick

Try with this:
document.getElementById("results").value = req.responseText;
And then you results should be an input:
<input type="text" id="results" />

this?
document.getElementById("results").value = req.responseText;
<input id="results" type="text" />

Suppose this is your text field:
<input type="text" id="whatever" value="" />
Simply set the response to its value:
document.getElementById('whatever').value = req.responseText;

Related

image upload using javascript?

This is my HTML and javascript.
I'm trying to upload an image using javascript.
I did find some examples using jquery, but was hoping if this function below can be modified to do the same.
The image upload script is a PHP script, which works when the form is posted normally, but when using this function below, it doesn't send the image to the PHP script. $_FILES is empty.
How can I modify this function to send the image as well?
<html><head>
<script type="text/javascript">
function jax( ){
pd = document.getElementById("pd").innerHTML;
i = document.getElementById("i").value;
url= "ajax.php"; //?act=uploadPic&title=" + pd + "&i=" + i;
q="act=uploadPic&title=" + pd + "&i=" + i;
var ajaxRequest;
try{
ajaxRequest = new XMLHttpRequest();
}
catch (e){
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
}
catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
}
catch (e){
alert("Your browser does not support ajax. Allow Active scriptting in internet settings."); return false;
}
}
}
ajaxRequest.onreadystatechange= function(){
if(ajaxRequest.readyState == 4){
r =ajaxRequest.responseText;
alert(r);
}
}
ajaxRequest.open("POST", url, true);
ajaxRequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
ajaxRequest.send(q);
}//func
</script>
</head>
<body>
<form action="upload.php" method="post" enctype="multipart/form-data">
<p> Title: <input type="text" name="pd" id="pd" value=" Title here " />
<p> Image: <input type="file" name="i" id="i" />
<p> <button onclick=" jax( ) "> Upload </button>
</form>
</body>
</html>
The PHP script to verify if image is send:
ajax.php
<?php print_r($_FILES); ?>
this is my function,but can't working lower than ie8:
function jax(){
url= "ajax.php?act=uploadPic";
var formData = new FormData(document.forms[0]);
var xhr = new XMLHttpRequest();
xhr.open('post',url,true);
xhr.onreadystatechange = function(){
if (xhr.readyState == 4) {
if (xhr.status == 200) {
console.log(xhr.responseText);
}
}
}
xhr.addEventListener('progress',function(e){
if (e.lengthComputable) {
console.log(e.loaded+'/'+e.total);
}
},false);
xhr.send(formData);
}

How can I print PHP POST data using AJAX? (no jQuery)

So basically I've got this HTML.
<form method="post" id="myform" onsubmit="getData()">
<fieldset>
<legend>Form</legend>
<label>Color: <input type='text' id="color" name='color'></label>
<label><input type="submit"></label>
</fieldset>
</form>
<div id="showoutput">
</div>
This PHP:
<?php
$color = $_POST['color'];
if($color != "")
{
$color = htmlentities($color, ENT_QUOTES);
print "<p>The color is $color</p>";
}
else
{
print "<p>Fill out form!</p>";
}
?>
And this JS:
window.onload = getData;
var req = new XMLHttpRequest();
function getData()
{
var poststr = "color=" + encodeURI( document.getElementById("color").value );
req.open("POST", "lab11-1.php", true);
req.onreadystatechange = useResponse;
req.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
req.send(poststr);
}
function useResponse()
{
if(req.readyState == 4)
{
if(req.status == 200)
{
document.getElementById('showoutput').innerHTML = req.responseText;
}
}
}
I'm trying to be able to input a color in the form, hit submit, and use AJAX to print the PHP to the "showoutput" div in my HTML. I've tried everything I can think of and haven't been able to figure it out.
I think this is not correct.
Ajax don't need form submit function,
I did do like this, I think you want it.
<form method="post" id="myform">
<fieldset>
<legend>Form</legend>
<label>Color: <input type='text' id="color" name='color'></label>
<label><input type="button" onclick="getData()" value="submit"></label>
</fieldset>
</form>
<div id="showoutput">
</div>
<script>
window.onload = getData;
var req = new XMLHttpRequest();
function getData()
{
var poststr = "color=" + encodeURI( document.getElementById("color").value );
req.open("POST", "test.php", true);
req.onreadystatechange = useResponse;
req.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
req.send(poststr);
}
function useResponse()
{
if(req.readyState == 4)
{
if(req.status == 200)
{
document.getElementById('showoutput').innerHTML = req.responseText;
}
}
}
</script>

Submit multiple values of a form using AJAX (but no jQuery) - XMLHttpRequest

Normally I'd use jQuery for this, but to cut a long story short, on this I can't.
I've successfully submitted a form via AJAX which has only one element of a form, like this:
<div id="response"></div>
<form onsubmit="submitStuff(this.datatosend.value);this.reset();return false;">
<input id="datatosend" type="text" />
<input type="submit" />
</form>
<script>
function submitStuff(e) {
if (e == "") {
document.getElementById("response").innerHTML = "";
return
}
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest
} else {
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP")
}
xmlhttp.onreadystatechange = function () {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("response").innerHTML = xmlhttp.responseText
}
};
xmlhttp.open("GET", "sumbitData.php?data=" + e, true);
xmlhttp.send()
}
</script>
Now say I have this form:
<form onsubmit="????????????????????;this.reset();return false;">
<input id="datatosend1" type="text" />
<input id="datatosend2" type="text" />
<input type="submit" />
</form>
How do I do the same, submitting both values?
I'm a bit new to Javascript, especially 'pure' Javascript so please be a bit patient!
Build up the string
var data1 = encodeURIComponent(document.getElementById("datatosend1").value);
var data2 = encodeURIComponent(document.getElementById("datatosend2").value);
var url = "sumbitData.php?data1=" + data1 + "&data2=" + data2;
Read the form values and make a string to attach to the url:
var child=document.getElementById(form_id).getElementsByTagName('input');
var data=new Array();
for(var i=0;i<child.length;i++){
data.push(child[i].id + '='+ encodeURIComponent(child[i].value));
}
data='?' + data.join('&');

JSONRequest.post not functioning

I am developing a web page and the purpose is to perform an http POST from form input elements, in JSON format. While the JSON element to be sent is formed properly, the request is never performed. Here is the code I have been using.
Form
<form id="input" action="javascript:snifForm()" >
User ID:
<input type="text" name="userId" id="userId" required>
Name:
<input type="text" name="name" id="name" required>
<div class="form-submit"><input type="submit" value="Submit" color="#ffffff" > </div></p>
</form>
Javascript (JSON.js, JSONRequest.js and JSONRequestError.js are imported)
<script type="text/javascript">
var requestNumber;
function snifForm()
{
var a1=document.getElementById("userId").value;
var a2=document.getElementById("name").value;
var toSend= {interactions: {id_user:a1, id_name:a2}};
var jToSend=JSON.stringify(toSend);
requestNumber = JSONRequest.post(
"http://someurl.com",
jToSend,
function (requestNumber, value, exception) {
if (value) {
processResponse(value);
alert(value);
} else {
processError(exception);
}
}
);
alert(requestNumber);
}
</script>
I also tried the more classic form:
var xmlhttp = new XMLHttpRequest();
var out;
xmlhttp.onreadystatechange = function() {
if(xmlhttp.readyState == 4 && xmlhttp.status == 200) {
out = xmlhttp.responseText;
alert(out);
}
else alert('nothing');
}
xmlhttp.open("POST", "the_same_url", true);
xmlhttp.setRequestHeader("Content-type", "application/json");
xmlhttp.setRequestHeader("Connection", "close");
xmlhttp.send(jToSend);
After checking the server logs, no post is done ever :/
You should be attaching the event to the submit action of the form and you need to make sure to cancel the submit action.
I would not add the events directly to the form, but it is
<form id="input" onsubmit="snifForm(); return false;">

submit a form with ajax and js

so i tried to "parse" the form object with js and pass stuff that was supposed to be used to URL and submit a form with ajax.the code did not work.both A and B parameters were not successfully passed to server and response as i thought at the first place.
<html>
<head>
<script type="text/javascript">
function ajaxForm(form){
form = document.getElementById(form);
var elements = form.elements;
var content="";
var element;
for(i=0;i<elements.length;i++){
element = elements[i];
if(element.type=="text"){
content += encodeURIComponent(element.name)+"="+encodeURIComponent(element.value)+"&";
}
}
ajaxSubmit(content);
}
function ajaxSubmit(content){
if(content.length==0){
document.getElementById("txtinput").innerHTML="";
}
if(windows.XMLHttpRequest){
xmlhttp = new XMLHttpRequest();
}
else{
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function(){
if(xmlhttp.readyState == 4 && xmlhttp.status == 200){
document.getElementById("txtinput").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","process.php?"+content,true);
xmlhttp.send();
}
</script>
</head>
<body>
<form id="ajax_form">
A:<input type="text" name="A" />
<br/>
B:<input type="text" name="B" />
<input type="submit" onsubmit="ajaxForm('ajax_form')" />
</form>
<p>Elevator:<span id="txtinput" ></span><br/></p>
</body>
</html>
process.php:
<?php
$response = "This is simply an example for debugging purposes";
echo $response;
?>
AjaxForm and AjaxSubmit are never getting called, instead the form is getting submitted in the normal way. You need something like
<form id="ajax_form" onsubmit="ajaxForm('ajax_form');return false;">
try changing encodeURLComponent to ecodeURIComponent

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