I have a group of radio buttons with the name 'periodType'. There is one radio button in that group which behaves the same way as the others, except for the fact that it displays an additional div. How can I get to know when that particular radio button is checked, as the change function below is quite generic for all the radio buttons in the group:
$('input[name="periodType"]').change(function() {
if(this.checked) {
//do something (for all radio buttons)
//If unique radio button also do this
}
});
<input type="radio" name="periodType" default>
<input type="radio" name="periodType" default>
<input type="radio" name="periodType" default>
<input type="radio" name="periodType" default>
You may want to add a value to your radio inputs:
<input type="radio" name="periodType" value="one" default>
<input type="radio" name="periodType" value="two" default>
<input type="radio" name="periodType" value="three" default>
<input type="radio" name="periodType" value="four" default>
and then query that value:
$('input[name="periodType"]').change(function() {
if (this.value == 'three' && this.checked) {
//do something (for all radio buttons)
//If unique radio button also do this
}
});
$('input[name="periodType"]').change(function() {
if(this.checked) {
//do something (for all radio buttons)
//If unique radio button also do this
var idval = $(this).attr("id");
if (idval == "something")
{
//do something
}
}
});
May be you are looking for something like this. I have added each radio to its own div just to show the behaviour on change. Please let me know if you have any questions.
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title></title>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<style type="text/css">
.selected{background-color: #fad42e;}
.notSelected{background-color: #6f6e73;}
</style>
<script type="text/javascript">
$(document).ready(function () {
$('input[name="periodType"]').change(function() {
$(this).parent('div').removeClass();
$(this).parent('div').addClass('selected');
$('input[name="periodType"]')
.parent('div')
.not($(this).parent("div"))
.each(function(e){
$(this).removeClass();
$(this).addClass("notSelected");
});
});
});
</script>
</head>
<body>
<div>
<input type="radio" name="periodType" >
</div>
<div>
<input type="radio" name="periodType" >
</div>
<div>
<input type="radio" name="periodType" >
</div>
<div>
<input type="radio" name="periodType" >
</div>
</body>
</html>
Related
There are two radio buttons separately. Have different name values. I'm trying to add a css to the div element when both are "checked".
$(document).ready(function(){
$('input[name="nameone"]').click(function(){
if($(this).is(":checked")){
$(".calculate-total").css("display","block")
}
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<label>
<input type="radio" name="nameone" /> Nameone radio
</label>
<br><br>
<label>
<input type="radio" name="nametwo" /> Namtwo radio
</label>
<div class="calculate-total" style="display:none;">If two radio checked both, this div will be visible.</div>
Just add a second if condition like you do for the input[name="nameone"]:
function showDiv() {
if ($('input[name="nameone"]').is(":checked") && $('input[name="nametwo"]').is(":checked")) {
$(".calculate-total").css("display", "block")
}
}
$(document).ready(function() {
$('input[name="nameone"], input[name="nametwo"]').click(function() {
showDiv();
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<label>
<input type="radio" name="nameone" /> Nameone radio
</label>
<br><br>
<label>
<input type="radio" name="nametwo" /> Namtwo radio
</label>
<div class="calculate-total" style="display:none;">If two radio checked both, this div will be visible.</div>
Just check if both of them are checked:
$(document).ready(function(){
$('input[name="nameone"], input[name="nametwo"]').click(function(){
if($('input[name="nameone"]').is(":checked") && $('input[name="nametwo"]').is(":checked")){
$(".calculate-total").css("display","block")
}
});
});
You are only checking if the first radio input is clicked (checked), that's why you the div is showing when you click on the first radio input. You should listen/check for both. If both are clicked (checked). Then that's when you want to do something. You can use the && to get the job done
function showDiv() {
if ($('input[name="nameone"]').is(":checked") && $('input[name="nametwo"]').is(":checked")) {
$(".calculate-total").css("display", "block")
}
}
$(document).ready(function() {
$('input[name="nameone"], input[name="nametwo"]').click(function() {
showDiv();
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<label>
<input type="radio" name="nameone" /> Nameone radio
</label>
<br><br>
<label>
<input type="radio" name="nametwo" /> Namtwo radio
</label>
<div class="calculate-total" style="display:none;">If two radio checked both, this div will be visible.</div>
You have to check if all radio buttons are checked and based on this check you can toggle the visibility of the block.
I added a class to the radiobuttons you want to check. And only if the length of all radiobuttons is equal to the checked onces i show the calculate-total div
$(document).ready(function() {
$('input[type="radio"]').on('change', function() {
if ($('.check-it').filter(':checked').length === $('.check-it').length) {
$(".calculate-total").css("display", "block")
} else {
$(".calculate-total").css("display", "none")
}
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<label>
<input type="radio" name="nameone" class="check-it" /> Nameone radio
</label>
<label>
<input type="radio" name="nameone" /> Nameone radio
</label>
<br><br>
<label>
<input type="radio" name="nametwo" class="check-it" /> Namtwo radio
</label>
<label>
<input type="radio" name="nametwo" /> Namtwo radio
</label>
<div class="calculate-total" style="display:none;">If two radio checked both, this div will be visible.</div>
You need to listen for both radio buttons and check for both each time:
$(document).ready(function(){
$('input:radio').change(function(){
if($('input[name="nameone"]').is(":checked") && $('input[name="nametwo"]').is(":checked")){
$(".calculate-total").css("display","block")
}
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<label>
<input type="radio" name="nameone" /> Nameone radio
</label>
<br><br>
<label>
<input type="radio" name="nametwo" /> Namtwo radio
</label>
<div class="calculate-total" style="display:none;">If two radio checked both, this div will be visible.</div>
I have three radio each one has name started with delivery_option and a submit button with css class continue. I want to test if a radio is checked the button must be enabled, otherwise it should be disabled.
i made the code below
$(document).ready(function() {
$('#checkout-delivery-step input:radio').each(function() {
if ($("input:radio[name*='delivery_option']:checked").length != 0) {
$('.continue').prop('disabled', false);
} else {
$('.continue').prop('disabled', true);
}
});
});
but it does not work, what was the issue?
You are running the code only once. The code has to be run every time when the radio button is clicked or changed. So you need to use the following:
// Make this a function.
function checkProgress() {
if ($("input:radio[name*='delivery_option']:checked").length != 0) {
$('.continue').prop('disabled', false);
} else {
$('.continue').prop('disabled', true);
}
}
$(function () {
// Set the status once the doc loads.
checkProgress();
// Set it again when any of the radio buttons are clicked.
$("input:radio[name*='delivery_option']").on("click change", checkProgress);
});
Snippet
// Make this a function.
function checkProgress() {
if ($("input:radio[name*='delivery_option']:checked").length != 0) {
$('.continue').prop('disabled', false);
} else {
$('.continue').prop('disabled', true);
}
}
$(function () {
// Set the status once the doc loads.
checkProgress();
// Set it again when any of the radio buttons are clicked.
$("input:radio[name*='delivery_option']").on("click change", checkProgress);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<h3>Group 1</h3>
Option 1: <input type="radio" name="delivery_option_1" />
Option 2: <input type="radio" name="delivery_option_1" />
Option 3: <input type="radio" name="delivery_option_1" />
<h3>Group 2</h3>
Option 1: <input type="radio" name="delivery_option_2" />
Option 2: <input type="radio" name="delivery_option_2" />
Option 3: <input type="radio" name="delivery_option_2" />
<p>Submit?</p>
<input type="button" value="Submit" class="continue" disabled />
You can try something like this with removeAttr which will remove the attribute from any element which is already set.
Also, for the radio you can do this way, once it is clicked then you can enable the button because it doesn't provide a way to deselect it.
Finally, the name for elements can be the same if it is a group and only the id must be unique. Check here.
So, proper code will be
<label for="delivery_option1">Option1:</label><input type="radio" id="delivery_option1" name="delivery_option" />
<label for="delivery_option2">Option2:</label> <input type="radio" id="delivery_option2" name="delivery_option" />
<label for="delivery_option3">Option3:</label><input type="radio" id="delivery_option3" name="delivery_option" />
$(function(){
$("input:radio[name*='delivery_option']").click(function(){
$(".continue").removeAttr("disabled");
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
Option1: <input type="radio" name="delivery_option1" />
Option2: <input type="radio" name="delivery_option2" />
Option3: <input type="radio" name="delivery_option3" />
<input type="button" value="Submit" class="continue" disabled />
Hopefully somebody can prompt me into the right direction,
I want a simple 3 radio button form, lets say 1,2,3
once 1 has been selected i want to disable options 2 and 3 until page has been refreshed
so maybe those option would grey out and not be selectable
any help appreciated cant find a thing on google
We will group radio buttons in a div:
<div class="readioBtnDiv">
<input type="radio" name="group1" value="1" />1
</div>
<div class="readioBtnDiv">
<input type="radio" name="group2" value="1" />2
</div>
<div class="readioBtnDiv">
<input type="radio" name="group3" value="1" />3
</div>
Now we will disable another radio button when one is selected:
$("input:radio").click(function() {
var $this = $(this);
var value = $this.val();
$this.closest('.readioBtnDiv')
.siblings('.readioBtnDiv')
.find('input:radio[value="' + value + '"]')
.attr("disabled","disabled");
});
Here we go, jQuery way:
HTML:
<form>
<input type="radio" value="1"> 1
<input type="radio" value="2"> 2
<input type="radio" value="3"> 3
</form>
JS:
<script>
$('input').on('click', function() {
$(this).parent().find('input:not(:checked)').attr( "disabled", "disabled" );
})
</script>
To add jQuery to your project - simply insert
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
inside your <head> </head> tag.
UPDATE:
To keep it after page refreshes you should modify your code to this:
<form>
<input type="radio" value="1" id="radio1"> 1
<input type="radio" value="2" id="radio2"> 2
<input type="radio" value="3" id="radio3"> 3
</form>
<script>
$('#'+localStorage.selected).trigger('click');
$('#'+localStorage.selected).parent().find('input:not(:checked)').attr( "disabled", "disabled" );
$('input').on('click', function() {
$(this).parent().find('input:not(:checked)').attr( "disabled", "disabled" );
localStorage.setItem('selected', $(this).attr('id'));
})
</script>
I think all the answers are right and accurate to your question above but according to me you would find this answer more useful and understandable if you are newbie
<!DOCTYPE html>
<html>
<head>
<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script>
function myFunction1() {
document.getElementById("radio2").disabled = true;
document.getElementById("radio3").disabled = true;
}
function myFunction2() {
document.getElementById("radio1").disabled = true;
document.getElementById("radio3").disabled = true;
}
function myFunction3() {
document.getElementById("radio2").disabled = true;
document.getElementById("radio1").disabled = true;
}
</script>
</head>
<body>
<div class="block">
<input onclick="myFunction1();" type="radio" id="radio1" value="Radio1" /><label>Radio1</label>
<input onclick="myFunction2();" type="radio" id="radio2" value="Radio2" /><label>Radio2</label>
<input onclick="myFunction3();" type="radio" id="radio3" value="radio3" /><label>radio3</label>
</div>
</body>
</html>
It's a working example according to your need. Cheers :)
I guess the problem is pretty simple but I couldn't find a solution anywhere. I want to check whether a radio button is checked or not. From here a possible solution:
For these inputs
<input type="radio" name="gender" id="gender_Male" value="Male" />
<input type="radio" name="gender" id="gender_Female" value="Female" />
you can simply
if(document.getElementById('gender_Male').checked) {
//Male radio button is checked
}else if(document.getElementById('gender_Female').checked) {
//Female radio button is checked
}
Yet my inputs are like this:
<label><input id="16" type="radio" value="14" name="Q3"></input>Yes</label>
<label><input id="16" type="radio" value="15" name="Q3"></input>No</label>
id is not unique by itself but only in combination with value... How do I check whether Yes or No are selected?
As #Markasoftware said, id should always be unique. But browser still parse your html with the same ids.
So key point is that you can select an element without id.
Try document.querySelectorAll or document.querySelector. Here is code:
document.querySelectorAll('input[value="14"]') // you can select all the `value='14'` inputs
document.querySelectorAll('input[name="Q3"]') // you can select all the `value='Q3'` inputs
You can compose these css3 selectors and reach your goal.
You can try the next selector:
$('input#16.14').is(':checked'){
//YES is checked
}
$('input#16.15').is(':checked'){
//NO is checked
}
But id should be unique.
Another way to check which one is selected it's using the input name:
$('input[name=Q3]:checked').val()
This way you will get 14 if YES is checked or 15 if No is checked
Assuming the yes/no element is next element of your gender radio, you can try something like:
$('[name="gender"]').change(function(){
if($(this).val() == 'Male'){
$(this).next('input[type="radio"][value="14"]').prop('checked',true);
}else{
//Female
}
});
Add a class to your radio buttons.
$('.radioGroup').change(function(){
if($(this).val() == 'Male'){
///
} else {
//female
}
});
<html>
<head>
<meta charset="utf-8">
<link rel="stylesheet" href="//code.jquery.com/ui/1.10.4/themes/smoothness/jquery-ui.css">
<script src="//code.jquery.com/jquery-1.9.1.js"></script>
<script src="//code.jquery.com/ui/1.10.4/jquery-ui.js"></script>
</head>
<body>
<label><input id="16" type="radio" value="14" name="Q3"/>Yes</label>
<label><input id="16" type="radio" value="15" name="Q3"/>No</label>
<script type="text/javascript">
$('input[name=Q3]').change(function () {
if ($('input[name=Q3]:checked').length > 0) {
var k = $('input[name=Q3]:checked').val();
alert(k);
}
});
</script>
</body>
</html>
$(':radio').on('change',function() {
if( this.checked && this.value === "14" ) {
alert( "'Yes' was selected!" );
} else if( this.checked && this.value === "15" ) {
alert( "'No' was selected!" );
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<label><input id="Q3_1" type="radio" value="14" name="Q3">Yes</label>
<label><input id="Q3_2" type="radio" value="15" name="Q3">No</label>
I'm using this in a form to check whether a radio button group has a certain value (Yes/No). The HTML for one of these is:
<form id="registerHere">
<div class="control-group">
<label class="radio">
<input type="radio" value="Yes" name="freemedia">
Yes
</label>
<label class="radio">
<input type="radio" value="No" name="freemedia" checked="checked">
No
</label>
</div></form>
And I'm using the following JS (jQuery.validate.js is included):
<script type="text/javascript">
$(document).ready(function(){});
$("#registerHere").validate({
rules:{
freemedia:{
required:true,
equalTo: "Yes"
},
},
messages:{
freemedia:{
required:"Please select",
equalTo:"Please apply to the 'freemedia' group first.</a>"
},
},
});
});
</script>
However, it is not checking the value correctly, as it always shows me the message, regardless of whether 'Yes' or 'No' is checked.
Where am I going wrong?
I cleaned up some of your jquery, you had a few errors in there.
Also, digging around in the plugin I noticed that you can use the 'equalTo' parameter to specify which control is required. It just uses the 'equalTo' as a selector for a query. So if you treat your 'equalTo' setting as a jquery selector, it should work. It may be a bit of a hack, but I had it working.
All you need to do is assign an id to your radio buttons and you should be good to go
<div class="control-group">
<label class="radio">
<input id="chkYes" type="radio" value="Yes" name="freemedia" />
Yes
</label>
<label id="chkNo" class="radio">
<input type="radio" value="No" name="freemedia" />
No
</label>
<input type="submit" value="Submit" />
</div>
<script type="text/javascript">
$(document).ready(function () {
$("#registerHere").validate({
rules:
{
freemedia:
{
required: true,
equalTo: "#chkYes"
}
},
messages:
{
freemedia:
{
required: "Please select",
equalTo: "Please apply to the 'freemedia' group first."
}
}
});
});
</script>
You want to check your value selected at the time of form submission ,That's the good way to do it Give a predefined selected radio button and then check the selected Radio at the time of form sub mission that what done here
<!DOCTYPE html>
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
</head>
<body>
<input type="radio" name="sex" value="Male" checked>Male</input>
<input type="radio" name="sex" value="Female">Female</input>
<input type="radio" name="sex" value="Unknown" >Unknown</input>
<div onclick="CheckMe();"> check Selected Radio button</div>
</body>
<script>
function CheckMe()
{
alert("value selected "+$('input:radio[name=sex]:checked').val());
}
</script>
</html>
Now Suppose you have not selected any Radio button by default then you can check that whether user has selected any radio butoon or not and if selected what is it?
Following code helps you in doing that
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
</head>
<body>
<input type="radio" name="sex" value="Male">Male</input>
<input type="radio" name="sex" value="Female">Female</input>
<input type="radio" name="sex" value="Unknown">Unknown</input>
<div onclick="CheckMe();"> check Selected Radio button</div>
</body>
<script>
function CheckMe()
{
if ($('input:radio[name=sex]:checked').val())
alert("value selected "+ $('input:radio[name=sex]:checked').val());
else
alert("Please select Radio button");
}
</script>
</html>
Enjoy..!
In jquery validation plug-in "equalTo" is used to compare value between the fields, not on same field.(It's my study if any one knows more about it.Please let me know.)
You can add your custom method to it.
$.validator.addMethod("check_for_yes", function(value, element) {
return $('.freemedia').val() != "Yes"
}, "* Please apply to the 'freemedia' group first.");
Validation -
rules : {
freemedia : {
check_for_yes: true
}
}
OR
You can check it on Jquery click event of radio button by showing alert.