Onclick shouldn't trigger form data submission - javascript

I just found out that every time onclick event for my <button> placed inside <form> tag triggers, form submits it's data as if i clicked <input type='submit'>.
I don't want that. Buttons inside my form serve other task, form shouldn't submit data after i clicked one of them.
To be more clear, i want this code:
<form action="http://www.google.com" method="POST">
<button onclick="alert('hi!')">Button</button>
<br>
<input type="submit" value="submit"/>
</form>
to show alert "hi!" when i click on the Button and it shouldn't open Google after that. It should only show Google when i press "submit".

Specify type="button":
<button type="button" onclick="alert('hi!')">Button</button>
From the linked article:
This [submit] is the default if the attribute is not specified

Try this..
onclick="alert('hi!'); return false;"

With jQuery use a span rather than an input, put use the .button call and then set a click event.

Related

onclick vs. $.post how to isolate a button function vs. submission? [duplicate]

I just found out that every time onclick event for my <button> placed inside <form> tag triggers, form submits it's data as if i clicked <input type='submit'>.
I don't want that. Buttons inside my form serve other task, form shouldn't submit data after i clicked one of them.
To be more clear, i want this code:
<form action="http://www.google.com" method="POST">
<button onclick="alert('hi!')">Button</button>
<br>
<input type="submit" value="submit"/>
</form>
to show alert "hi!" when i click on the Button and it shouldn't open Google after that. It should only show Google when i press "submit".
Specify type="button":
<button type="button" onclick="alert('hi!')">Button</button>
From the linked article:
This [submit] is the default if the attribute is not specified
Try this..
onclick="alert('hi!'); return false;"
With jQuery use a span rather than an input, put use the .button call and then set a click event.

How to turn off form validation in Angular when clicking by button that shoulden't send form

I have a form like this one:
<form name="myForm">
<input id="myName" ng-model="myName" required/>
...
<button ng-click="doSomePrepare()">Do some prepare</button>
...
<button ng-click="saveForm()" ng-disabled="myForm.$invalid">Save</button>
</form>
I want validate form only when "Save" button clicked.
But if I'm click "Do some prepare", browser(chrome) ask me to fill "myName" input.
It's make me problems, cause in real world "Do some prepare" button may be a datepicker button or a dropdown or somethig like that.
P.S. I'm use Angular 1.2 version, but as far as I know this can be reprodused with version 1.0
JSfiddle: http://jsfiddle.net/se_panfilov/wQF4S/4/
Make your first button a non-form-submitting button:
<button type="button" ng-click="doSomePrepare()">Do some prepare</button>
You can test it here
The default type attribute of a button tag is submit. Try setting the type to reset or to button to prevent the submit event from firing when you click it.
Working demo: http://jsfiddle.net/wQF4S/3/

Submit with javascript

How can I specify which submit button to submit with?
The current example just submits the first submit button, with $("form").submit(); but how can I make it so it chooses the submit button by id or name?
<html>
<script>
$("form").submit();
</script>
<form action="<?=$_SERVER['PHP_SELF']?>" method="post" />
//other inputs
<input type="submit" value="Enter" name="enter" id="enter">
<input type="submit" value="Void" name="void" id="void">
<input type="submit" value="Refund" name="refund" id="refund">
</form>
</html>
Simulate a click to that element:
$("#circle2").click();
Also, you don't need action="<?=$_SERVER['PHP_SELF']?>". Forms submit to the current page by default.
First of all, why do you want to submit the same form with 3 different buttons?
It is a bad structure. Your code also has all the 3 buttons with the "id" attribute which is included in the <input> tag twice.
Based on your question, I could figure out you would want the submit button to say different things under different conditions.
Have a single button like this :
<input type="submit" name="submit" value="Enter">
You could always change what your button says, or how it looks like with JQuery :
if(condition){
$('#submit').val('.....');
// You can also change more stuff as you want.
}
Then you would want to submit the form
$('#submit').click(function(e)){
e.preventDefault();
$('form').submit();
}
By id
You can select the element by id easily with $('#my_btn') and you can click on it using the jQuery method click().
By name (or any other attribute
Other attributes are a bit harded (but not complex)
You select the element with $('input[name=some_name]')
Examlpe using your code
Here is an example which shows how you can get elements by name and click on them, click the submit buttons to see what happens: http://jsfiddle.net/nabil_kadimi/99v93/2/

Using two buttons (submit button and a normal button) which should submit the same form differently

I have used jquery wizard plugin to create this form.
The form get submitted when I use the ID = "next" submit button.
when I use the ID = "quick" button it will redirect to the Feedback.Form but it will not submitted properly. (I cant see the db has been updated properly.)
$j("#quick").click(function(){
$j('#feedbackForm').submit();
});
<form id="feedbackForm" method="post" action="<openmrs:contextPath/>/module/feedback/addFeedback.form" class="bbq" enctype="multipart/form-data" >
<div id="bottomNavigation">
<input id="back" value="Back" type="reset" />
<input id="next" value="Next" type="submit" />
<input id="quick" value="Just submit now with all the defaults!" type="button" />
</div>
Please can any one help me on this?
Thanks,
Harsha
Full source : https://gist.github.com/3227043
Convert the "next" button to normal button and add and if or switch selection into the jquery code. So both buttons were normal and Jquery will decide which ones takes to submit getting the name of the button who calls the click event. Or you can do it trough a javascript function, well, you can do it in any way as you want, but both buttons must be "button" type

How do I detect how a form was submitted via JavaScript?

I have a form with multiple submit buttons and I'm listening for the 'submit' event via JavaScript. I want to know which submit button or form field (if the user pressed 'Enter/Return') triggered the submit event. Is there a way to get the HTML element that the user clicked on or pressed 'Enter/Return' in?
Update since people aren't understanding me:
This is via JavaScript before the form is submitted. No server-side detection allowed. I also need to handle the form being submitted via the user pressing Enter or Return.
Code
<form action="" method="POST">
<input type="text" name="first_name">
<input type="text" name="item">
<input type="submit" value="Add item">
<input type="submit" value="Submit">
</form>
Clicking 'Add Item' or pressing Return/Enter inside name="item" will add another form field.
Final Note
As far as I can tell, there isn't a way to detect which form field triggered a form submission. If you need to prevent submitting a form that has multiple buttons and/or from Enter/Return, you'll need to use <input type="button"> and bind event handlers to the form fields you want to stop form submission from.
If you have multiple submit buttons, the way you can tell is by giving each of them a unique name attribute, like this:
<input type="submit" name="submit1" value="Submit 1"/>
<input type="submit" name="submit2" value="Submit 2"/>
<input type="submit" name="submit3" value="Submit 3"/>
The one that is focused is sent along with the form submit, so if you clicked the one with a name of "submit2", that would come through in the form POST (or GET). If enter is hit, the first button in the source (in this case submit1) is considered the default and is sent along. You could set it to display:none to use as a dummy for detecting whether enter was pressed vs actually clicking a submit button.
EDIT:
In response to your comments, to capture the enter key getting pressed in certain elements you can do this with jQuery.
Note, you'll need to give first_name and add_item id attributes, and turn add_item into a type="button" instead of type="submit".
HTML:
<form action="" method="POST">
<input type="text" name="first_name"/>
<input type="text" id="item" name="item"/>
<input type="button" id="add_item" value="Add item"/>
<input type="submit" value="Submit"/>
</form>
JS:
$("#item").keydown(function(event){
if(event.keyCode == 13) {
addFields();
event.preventDefault();
event.stopPropagation();
}
});
$("#add_item").click(function(event) {
addFields();
});
You could set the onclick event on each element you are interested and call a javascript function with a different parameter for each element clicked.
From that function you send the idendifier of the button to the server side as a parameter
Just put a different name on each submit button, whichever one was clicked will be submitted (i.e. its name/value pair) with the form. Forms have worked like this since the begining of (WWW) time.
If the form is sumitted by enter or other keypress, no the first submit button name/value pair will be submitted.
Edit
Re-reading your question, you may want to determine how the form was submitted before it is sent. A click listener on the form can remember the last submit button clicked, but in Firefox, pressing enter in an input dispatches a fake click on the first submit button so you can't detect it.
I think you can't do it reliably other than using the basic method suggested above or Jordan's hidden submit button. If you say why you need to do this, perhaps more help can be provided.
here's an option if you don't mind using jQuery:
example: http://jsfiddle.net/U4Tpw/
use something like
$('form').submit(function() {
// identify the form by getting the id attribute
handleWhichForm($(this).attr('id'));
});

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