These are Dynamic dependent select controls. The sets of values of (1-3, 4-6, 7-9) determine the use hide/show divs function. The problem is the function i have only hide/show depending on the div id. How can i make the function hide/show div depended on the values(1-3, 4-6, 7-9) found in the selectbox?
Jquery
$('#select').change(function() {
$('#sub1, #sub2, #sub3').hide();
$('#sub' + $(this).find('option:selected').attr('id')).show();
});
Html Setup
<html>
<select size="6" id="category">
<option value="">categories 1-3 </option>
<option value="">----</option>
<option value="">----</option>
</select>
<div id="sub1" style="display:none">
<select name="subc1" size="6">
<option value="1">subcategories 4-6</option>
<option value="2">---</option>
<option value="3">---</option>
</select>
</div>
<div id="sub2" style="display:none">
<select name="subc2" size="6">
<option value="4">subcategories 7-9</option>
<option value="5">----</option>
<option value="6">----</option>
</select>
</div>
<div id="sub3" style="display:none">
<select name="subc3" size="6">
<option value="7">End</option>
<option value="8">----</option>
<option value="9">----</option>
</select>
</div>
</html>
select the value from drop down change function and do the operation depends on the value of drop down, following is the sample code
$(function() // Shorthand for $(document).ready(function() {
$('select').change(function() {
if($(this).val() == 1)
{
$('#sub1').hide();
$('#sub2').show();
}
});
});
You nee to change minor change in your category select
<select size="6" id="category">
<option value="1">categories 1-3 </option>
<option value="2">----</option>
<option value="3">----</option>
</select>
$('select#category').on('change', function() {
$('div[id=^sub]:visible').hide();
$('div#sub' + this.value).show();
});
can also use .change() instead of .on('change').
$('select#category').change(function() {
$('div[id=^sub]:visible').hide();
$('div#sub' + this.value).show();
});
NOTE:
$('div[id=^sub]:visible') will point to all divs that have id start with sub and visible.
You are trying with $('#select') which need to be $('#category') or $('select#category').
According to your comment:
Complete solution will look like following:
function isOnlyDashed(text) {
return text.replace(/-/g, '').length === 0;
}
$('select#category').change(function() {
var text = $('option:selected', this).text();
if (!isOnlyDashed(text)) {
$('div[id=^sub]:visible').hide();
$('div#sub' + this.value).show();
}
});
$('select[name^=subc]').change(function() {
var text = $('option:selected', this).text();
if (!isOnlyDashed(text)) {
$(this).parent() // jump to parent div
.next('div[id^=sub]:hidden') // go to next hidden div
.show();
}
});
Complete Workout
The problem with your code is that you have an incorrect selector.
$('#select')...
should be
$('select')...
Also, this part is wrong
$('#sub' + $(this).find('option:selected').attr('id')).show();
Replace it with this
$('#sub' + $(this).val()).show();
Finally, having different elements with the same name/id "sub1" is probably a bad idea, though technically not illegal. It is certainly confusing.
working demo http://jsfiddle.net/FwBb2/1/
I have made minor changes in your Jquery code as well as added value in your first select drop-down list which was missing rest hope this helps.
Please lemme know if I missed anything! B-)
code
$('select').change(function() {
$('#sub1, #sub2, #sub3').hide();
$('#sub' + $(this).val()).show();
});
HTML
<html>
<select id="category">
<option value="1">categories 1-3 </option>
<option value="2">----</option>
<option value="3">----</option>
</select>
<div id="sub1" style="display:none">
<select name="subc1" size="6">
<option value="1">subcategories 4-6</option>
<option value="2">---</option>
<option value="3">---</option>
</select>
</div>
<div id="sub2" style="display:none">
<select name="subc2" size="6">
<option value="4">subcategories 7-9</option>
<option value="5">----</option>
<option value="6">----</option>
</select>
</div>
<div id="sub3" style="display:none">
<select name="subc3" size="6">
<option value="7">End</option>
<option value="8">----</option>
<option value="9">----</option>
</select>
</div>
</html>
Related
I have some issues with options, can someone help me ?
I have a button with id="colorButton" but I don't know how to change his color with options.
<form>
<select id="colorSelect">
<option selected disabled>Text-Align : </option>
<option value="1">Red</option>
<option value="2">Blue</option>
<option value="3">Green</option>
</select>
</form>
It can be a javascript answer, jquery... please :(
I have this in script :
$(document).ready(function(){
if ($("#colorSelect").click().val("1"){
$("#testButton").css("color", "red");
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
But ofc it don't work :(
Your code contains lots bugs, you just need to bind a change event handler and set color based on selected option.
$(document).ready(function() {
$("#colorSelect").change(function() {
$("#testButton").css("color", $(':selected', this).text());
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<select id="colorSelect">
<option selected disabled>Text-Align : </option>
<option value="1">Red</option>
<option value="2">Blue</option>
<option value="3">Green</option>
</select>
</form>
<div id="testButton">button</div>
You need to bind to the change event of the select like:
$(document).ready(function() {
$("#colorSelect").change(function() {
if ($(this).val() == 1) $("#testButton").css("color", "red");
})
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<select id="colorSelect">
<option selected disabled>Text-Align : </option>
<option value="1">Red</option>
<option value="2">Blue</option>
<option value="3">Green</option>
</select>
</form>
<button id="testButton">button</button>
Everyone is focusing on making your code functional. I put the effort to solve your problem in different way.
Each option has data-color attribute. When you change dropdown then selected option's data-color value get picked and changes color. In this way, you don't need multiple if-else.
$(document).ready(function() {
$('#colorSelect').on('change', function(){
var color = $(this).find(':selected').data('color');
$("#testButton").css("color", color);
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<select id="colorSelect">
<option selected disabled>Text-Align : </option>
<option data-color='red'>Red</option>
<option data-color='blue'>Blue</option>
<option data-color='green'>Green</option>
</select>
<button id="testButton">button</button>
</form>
I need to remove some options from the 2nd dropdown menu based on the first.
I have tried quite a few iterations to get it done but still it is not working.
Kindly provide with solutions
In the below code I need to remove the option from the 2nd dropdown already selected in the 1st one.
I have tried the mentioned HTML & Javascript Code
HTML
<form>
Source:
<select id = "box1" name="a">
<option>select</option>
<option value="Apple">Apple</option>
<option value="Banana">Banana</option>
<option value="Carrot">Carrot</option>
</select>
Destination:
<select id="box2" name="b">
<option>select</option>
<option value="Apple">Apple</option>
<option value="Mango">Mango</option>
<option value="Dice">Dice</option>
<option value="Carrot">Carrot</option>
</select>
</form>
JAVASCRIPT
var main = function(){
$("#box1").change(function(){
var a = $('#box1 option:selected').val();
$("#box2 option[value='a']").remove();
});
}
$(document).ready(main);
I have tried entering the value as variable a with and without quotes but no effect. Although when i replaced 'a' with a specific value like 'Apple', then the code is working.
I think this is your answer ;)
var main = function(){
$("#box1").change(function(){
var a = $('#box1 option:selected').val();
$("#box2 option[value="+a+"]").hide().siblings().show();
});
}
$(document).ready(main);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<select id="box1" name="b">
<option>select</option>
<option value="Apple">Apple</option>
<option value="Mango">Mango</option>
<option value="Dice">Dice</option>
<option value="Carrot">Carrot</option>
</select>
<select id="box2" name="b">
<option>select</option>
<option value="Apple">Apple</option>
<option value="Mango">Mango</option>
<option value="Dice">Dice</option>
<option value="Carrot">Carrot</option>
</select>
Hi kindly check https://jsfiddle.net/RRR0308/uubuumrz/1/
HTML
<select id="box1">
<option>111</option>
<option>222</option>
<option>333</option>
<option>444</option>
</select>
<select id="box2">
<option>999</option>
<option>222</option>
<option>888</option>
<option>444</option>
</select>
jQuery
$(document).ready(function(){
$('#box1').on('change', function(){
var x=$(this).val();
$('#box2 option').each(function(){
if($(this).val()==x){
$(this).remove();
}
});
});
});
hide().siblings().show()
instead of.remove()`
The .remove() permanently removes the selected option in box1 from box2. so if you use .hide() and .show(), it would hide and show. try making these changes.
$('#box1').change(function(){
var v = $(this).val();
$('#box2').find("option[value="+v+"]").remove(); });
Try this simple one
I'm able to clone the #ingredient_1 div with the Add button. However, after pressing Add several times, then deleting random cloned divs with their specific X buttons, the Add button stops working.
I've replicated this problem across several browsers. Any advice would go a long way.
$('#add_more').click(function() {
var num = $('.clone').length;
var newNum = num + 1;
var newElem = $('#ingredient_1').clone().attr('id', 'ingredient' + '_' + newNum);
$('#ingredient_' + num).after(newElem);
});
$('#main').on('click', '.remove', function() {
$(this).parent().remove();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="main">
<div id="ingredient_1" class="clone">
<select id="1">
<option selected="selected">Please Select</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
</select>
<input type="text" name="name" placeholder="Amount" />
<select id="2">
<option selected="selected">Units</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
</select>
<select id="3">
<option selected="selected">Time</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
</select>
<button class="remove">X</button>
</div>
<div id="add_button">
<input type="button" id="add_more" value="Add" />
</div>
</div>
Once you delete the first row the element you're cloning no longer exists. Clone the element outside your click function so it's not overwritten:
var newElem = $('#ingredient_1').clone().attr('id', 'ingredient' + '_' + newNum);
var num = 1;
$('#add_more').click(function() { ... });
Also, declare your ID incrementor outside the function and simply add 1 each time the click function runs with num++. I'm guessing that it doesn't really matter what the ID values are, so as long as they're unique this works.
The problem is that you're using .length to calculate newNum. If you delete DIVs in the middle, you'll end up with duplicate IDs. For instance, suppose you first add 3 DIVs, you'll have DIVs numbered 1, 2, 3, 4. Then you delete #3. The next time you click Add, $(".clone").length will be 3, so you'll set newNum = 4;. But there's still a DIV with that ID.
Instead of using $(".clone").length, get the ID of $(".clone:last"), get the number at the end of it, and add 1 to that.
You're cloning, which if you have at least one static item, is fine. I fixed up your code so your initial row is hidden, and you have an ID variable that is auto incremented. On top of which, on load, it creates clones and creates the first row. Your back end code will just have to ignore a case where the style is set to display:none.
var id = 1;
$(function () {
var first = $('.clone');
first.attr('style', 'display:none');
NewRow();
});
$('#add_more').click(function () {
NewRow();
});
function NewRow() {
console.log('num = ' + id++);
var newElem = $('.clone:last').clone().attr('id', 'ingredient' + '_' + id + '_x');
newElem.attr('style', '');
$('.clone:last').after(newElem);
}
$('#main').on('click', '.remove', function () {
$(this).parent().remove();
});
You'll notice that I changed your click event to call the function NewRow(), this was done so that you can call a function in the Document.Ready event, as well as on the button click.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="main">
<div id="ingredient_1" class="clone">
<select id="1">
<option selected="selected">Please Select</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
</select>
<input type="text" name="name" placeholder="Amount" />
<select id="2">
<option selected="selected">Units</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
</select>
<select id="3">
<option selected="selected">Time</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
<option value="">Select</option>
</select>
<button class="remove">X</button>
</div>
<div id="add_button">
<input type="button" id="add_more" value="Add" />
</div>
</div>
Working JSFiddle is here
Here is a JSFiddle:
https://jsfiddle.net/7jknnn2n/
HTML:
<select class="base-choice">
<option value="English">English</option>
<option value="Spanish">Spanish</option>
</select>
<label class="contrastText" for="user_natives_language">Native Language</label>
<select class="first-choice" id="user_natives_language" name="user[natives_language]">
<option value="English">English</option>
<option value="Spanish">Spanish</option>
</select>
<label class="contrastText" for="user_next_language">I Want To Learn</label>
<select class="second-choice" id="user_next_language" name="user[next_language]">
<option value="Spanish">Spanish</option>
</select>
JS:
var $secondOption = $('.base-choice>option').clone();
$(".first-choice").change(function () {
var userSelected = $(this).val();
$('.second-choice').html($secondOption);
$('.second-choice option[value="' + userSelected + '"').remove()
});
CSS:
.base-choice{
display:none !important;
}
What I would like to do with the above JSFiddle is make it such that the .base-choice dropdown selector is hidden completely from the results portion of the fiddle. Also, when I toggle the Native Language dropdown and select something different you can see that the option for the I want to learn dropdown is no longer bolded. Any thoughts on how to fix this.
Since there is no way in CSS to select parent element you must use javascript.
In this updated fiddle I just found the select with base-choice and set the parent element (surrounding div) to also display:none.
$(".base-choice").parent().addClass("invisible");
https://jsfiddle.net/7jknnn2n/4/
Here is an updated fiddle https://jsfiddle.net/RachGal/7avurszn/1
var $secondOption = $('.base-choice>option').clone();
$(".first-choice").change(function () {
var userSelected = $(this).val();
$('.second-choice').html($secondOption);
$('.second-choice option[value="' + userSelected + '"').remove()
});
#select-3-button {
display:none!important;
padding:0!important;
opacity:0!important!;
}
.first-choice, .second-choice{opacity:.5; font-weight:normal;}
<script src="http://code.jquery.com/mobile/1.4.2/jquery.mobile-1.4.2.js"></script>
<select class="base-choice">
<option value="English">English</option>
<option value="Spanish">Spanish</option>
</select>
<label class="contrastText" for="user_natives_language">Native Language</label>
<select class="first-choice" id="user_natives_language" name="user[natives_language]">
<option value="English">English</option>
<option value="Spanish">Spanish</option>
</select>
<label class="contrastText" for="user_next_language">I Want To Learn</label>
<select class="second-choice" id="user_next_language" name="user[next_language]">
<option value="Spanish">Spanish</option>
</select>
I have this code:
<select>
<option disabled selected>Select Method</option>
<option value="question">Question</option>
<option value="password">Password</option>
<option value="email">Email</option>
<option value="none">None</option>
</select>
Now I want when user select each of them some div that hidden in css with display:none; get visible for example when user select Question the div that have question id get visible or when Password selected the div that have password id get visible.
I try this but not work:
$(document).ready(function(){
if ($("#auth option:selected").text() == "question"){
$("#question").css("display","block");
}
});
So how can I do this?
If you follow the pattern you have done so far, you have to write code for each option. If your options and div elements are coupled with value and id, you can simply do like this,
$("select").change(function() {
$("div").hide();
$("#" + $(this).val()).show();
});
Demo Fiddle
Here is Demo for this , remove disabled from select tag so that user can select the options
Jsfiddle
http://jsfiddle.net/adarshkr/z9gcf40r/2/
Code
HTML
<select id="showdiv">
<option disabled selected>Select Method</option>
<option value="question">Question</option>
<option value="password">Password</option>
<option value="email">Email</option>
<option value="none">None</option>
</select>
<div id="question" class="hide">
<p>question</p>
</div>
<div id="password" class="hide">
<p>password</p>
</div>
<div id="email" class="hide">
<p>email</p>
</div>
<div id="none" class="hide">
<p>none</p>
</div>
CSS
.hide{
display:none
}
JAVASCRIPT
$("select").change(function(){
$("div").hide();
$("#"+$(this).val()).show();
});
try this,
$('#auth').on('change', function() {
var that = $(this).val();
if (that === "question"){
$("#question").css("display","block");
}
});
Better check value than the text.
$(document).ready(function(){
if ($("#auth option:selected").val() == "question"){
$("#question").css("display","block");
}
});