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Adding css when form submitted javascript

I want to add css to a class when my form is submitted because it take long time, but nothing change! here is my form
<form method="post" class="std" enctype="multipart/form-data">
<button type="submit" name="submitAddProduct" class="btn btn-default button button-medium">
<span>Garder<i class="icon-chevron-right right"></i></span>
</button>
</form>
the div I want to change :
<div id="circlecontainer"></div>
and my script :
$('form.std').submit(function(e){
$( "#circlecontainer" ).removeClass('whatever').addClass('whatever');
});
I want the button to be disabled too when the submit goes on?

Try this.
<form id="myForm" method="post" class="std" enctype="multipart/form-data">
<button type="submit" id="submitBtn" name="submitAddProduct" class="btn btn-default button button-medium">
<span>Garder<i class="icon-chevron-right right"></i></span>
</button>
</form>
$('#myForm').submit(function(e){
$("#circlecontainer").addClass('whatever');
$("#submitBtn").prop('disabled', true).html('Please Wait...');
});

Reason 1. you will need e.preventDefault(), otherwise submit the form will refresh the whole page
Reason 2. Since reason 1, You will need to use ajax to post the form data instead of using default form event, please refer to this question for how to set it up in your submit function jQuery AJAX submit form
<script type="text/javascript">
$( "#circlecontainer" ).removeClass('whatever')
var frm = $('.std');
frm.submit(function (ev) {
$.ajax({
type: frm.attr('method'),
url: //'your post url',
data: frm.serialize(),
success: function (data) {
$("#circlecontainer").addClass('whatever');
}
});
ev.preventDefault();
});
</script>

Simple add a listener to your button and change the class attribute
var divClassChanger=function()
{
var div=document.getElementByID("circlecontainer");
div.setAttribute("class", "someotherclass");
document.getElementById("yourBtnId").disabled = true;
};
document.getElementById("yourBtnId").addEventListener("click",divClassChanger);
you only need a id in you button

You really need to consider using Ajax request as this will definitely solve your problem. As you have it
<form method="post" class="std" enctype="multipart/form-data">
<button type="submit" name="submitAddProduct" class="btn btn-default button button-medium">
<span>Garder<i class="icon-chevron-right right"></i></span>
</button>
</form>
AJAX Request Script
$('form').on("submit", function(e) {
e.preventDefault();
var $form = $(this), url = $form.attr('action');//url could be your PHP script
var posting = $.post(url, {$('yourinputs').val()});
posting.done(function(data){
$('.circlecontainer').removeClass('yourclass');
});
});
This should work.

jquery - hide not working

By clicking on "empty cart?", I am unsetting the cart array which is working fine. Now I wanted another form to be hidden if this "empty cart" button is clicked.
html:
<form id="f1" action="checkout.php" method="post">
<input name="cust_login" type="submit" value="Continue" />
</form>
<br>
<button>empty cart?</button>
javascript:
<script>
$(document).ready(function(){
$("button").click(function(){
$("#f1").hide();
});
});
</script>
php code for unsetting array:
if (isset($_GET['cmd']) && $_GET['cmd'] == "emptycart") {
unset($_SESSION["cart_array"]);
But hide is not working here.
My question is, can we use button and link together as I have written ? If not, then how to implement it?

Try to use this:
$(document).ready(function(){
var cmd = '<?php echo $_GET["cmd"] ;?>' ;
if(cmd == "emptycart")
{
$("#f1").hide();
}
});

You can try
$(document).ready(function(){
$("button").click(function(){
$("#f1").attr('style','display: block !important')
});
});
or to add a class to style file that do the same and then just add this class when clicking on the button.

<form id="f1"
action="checkout.php"
style="<?= (isset($_SESSION['cart_array']) && count($_SESSION['cart_array']))? "display:none;": ""; ?>"
method="post">
<input name="cust_login" type="submit" value="Continue" />
</form>
<br>
<button>empty cart?</button>
On rendering form - check if cart is empty - render it on hidden state
But in this case your js code had no sense. So you can add
<script>
$(document).ready(function(){
$(document).on('click', "a[href='cart.php?cmd=emptycart']", function(ev){
ev.preventDefault();
$.get($(this).attr('href', function() {
$("#f1").hide();
});
});
});
</script>
Istead of your js code - this one prevent page reload ( which happens when you click on link ) and send request via AJAX

You can try this solution
HTML
<form id="f1" action="checkout.php" method="post">
<input name="cust_login" type="submit" value="Continue" />
</form>
<br>
<button>empty cart?</button>
JS
$(document).ready(function(){
$("button").click(function(){
//$("#f1").hide();
window.location.href = "cart.php?cmd=emptycart";
});
});

Submit and hide all labels with a containing form chekbox checked

I'd like to create a function that that submits all the formularies with a checkbox checked and hides with their respective div tags
I put the following code as an example
<html>
<script>
//the jquery function to submit all forms
$(function () {
$(".formerasemessage").each(function () {
var par_div = $(this).closest(".demo"); //finding the closest div
$(this).validate({
submitHandler: function (formbeingsubmitted) {
$.post('remove.php', $(formbeingsubmitted).serialize(), function (data) {
$(formbeingsubmitted).hide("slow");
par_div.hide('slow'); //hide the div
});
}
});
});
});
</script>
<body>
<div class="demo">
<form method="post" class="formerasemessage">
<input type="checkbox" id="checkItem"></form>
</div>
<div class="demo">
<form method="post" class="formerasemessage">
<input type="checkbox" id="Checkbox1"></form>
</div>
<div class="demo">
<form method="post" class="formerasemessage">
<input type="checkbox" id="Checkbox2"></form>
</div>
<input type="button" value="Submit all checked">
</body>
</html>
I need to reprogram the function Jquery so that it can perform the desired function.
the visual result would be something like this:
that's my inbox of Outlook, checked my mails and then I click in 'remove' and my emails are hidden and deleted

$(document).ready(function(){
$('button').click(function(){
$(":checked",".formerasemessage").each(function () {
var par_div = $(this).closest(".demo"); //finding the closest div
var form = $(this).closest('form');
form.validate({submitHandler: function () {
$.post('remove.php', form.serialize(), function (data) {
form.hide("slow");
par_div.hide('slow'); //hide the div
});
}
}).submit();
});
});
});

You could call the input using document.getElementById("inputid").value. To hide anything, use a css code :
#inputid {visibility: hidden}
You can also archieve the same effect using javascript.
Archive to execute a js function with for instance : I can be clicked
You'll find several options online (W3schools) such as onclick, onmousein, onchange ...

jQuery Popup submit not responding

I have created a popup which allows users to edit a value then they can submit it again
Html:
<body>
<input id="submit" type="submit" value="Submit" data-theme="b" data-icon="check" data-rel="popup"/>
<div id="success" data-role="popup">
</div>
<div id="fail" data-role="popup">
<p>Fail</p>
</div>
</body>
jQuery:
$('#submit').click(function(){
var doStuff = true;
if(doStuff === true){
$("#success").empty();
$("#success").append('<p> <input type="text" value="' + doStuff + '" /> <input type="submit" id="popupConfirm" value="Submit" /> </p>');
$("#success").popup("open");
}else{
$("#fail").popup("open");
}
});
$('#popupConfirm').click(function(){
console.log("jhasgd");
});
Currently the click is not working at all that's why I have gibberish in the console.log and also I am not sure how to get the value of the entered input.
So my question is first how can I get the submit click to work and then output what they wrote?
fiddle of the code

$(document).on('click', '#popupConfirm', function(){
console.log("jhasgd");
});

Where are you adding the jQuery code at? If you are adding it all above the HTML, it might be trying to bind the #submit input before it exists in the DOM. Can you try to wrap the code in a document ready so it won't do the click binding before the DOM gets filled up.
$( document ).ready(function()
{
$('#submit').click(function(){
console.log("clicked the button");
});
});
Edit: I just saw the comment where you figured this out above. You didn't really have a code solution provided, so I will just leave this as is.

Form submit through AJAX not working

My form will not submit through AJAX to show the return of the PHP page, 'myscript.php'.
This is the HTML I'm using:
<form name="myform" id="myform" method="post" action="#" enctype="multipart/form-data" accept-charset="utf-8" class="taxonomy-drilldown-dropdowns">
<ul>
<li>
<label>Destination:</label>
<select name="city" id="city">
<option class="level-0" value="atlanta">Atlanta</option>
<option class="level-0" value="miami">Miami</option>
</select>
</li>
</ul>
<input class="srch_btn" type="button" value="{{submit-text}}" />
</form>
Here is the javascript earlier in the page:
jQuery(document).ready(function($) {
$('#city').change(function() {
$(this).parents("form").submit();
});
$('#myform').submit(function() {
$.post(
'myscript.php',
$(this).serialize(),
function(data){
$("#mydiv").html(data)
}
);
return false;
});
});
Here is the myscript.php:
<?php
if ($_POST['city'] == "atlanta") {
echo "Div contents 1";
}
if ($_POST['city'] == "miami") {
echo "Div contents 2";
}
?>
The submit button won't respond at this point or make an attempt to access the 'myscript.php' file. Help is appreciated. Thanks in advance!

It is better to use .closest() rather than .parents() in this case.. As parents selector gets all the ancestors that match the selector.
$('#city').change(function() {
$(this).closest("form").submit();
});
And to stop the Default action use e.preventDefault instead of return false
$('#myform').submit(function(e) {
e.preventDefault();
// Your code here
});

In you HTML code, I think you should change input type=button to input type=submit
<input class="srch_btn" type="submit" value="{{submit-text}}" />
Then when you click that button, the form will be submitted to your php page.
Also, about select change event in your jQuery code, I think you can just try following selector, as you have the name/id attribute available in your HTML.
$('#city').change(function() {
$('#myform').submit();
});

One issue with your code is that it does not actually stop the form from being submitted. return false; does not exactly work in jQuery in the way that you think it does. Instead, to stop the default action, you would have to do something like this.
$('#myform').submit(function(event) {
event.preventDefault();
http://api.jquery.com/event.preventDefault/
On top of that, if you don't want the form submit to take place, and you want to replace it with your own AJAX submition, why are you calling form submit at all in this code? Why not just put the AJAX directly into your change code?

dqhendricks was right - why use form submit when you can just access ajax directly? In the below example, I added a div (#responder) below the form to show the output. Try it -- you'll see that it works perfectly.
You really don't need the button, although I left it there, because the data is sent/received the moment the drop-down is changed. You will see your messages appear in the div I included below the form.
REVISED HTML:
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<form name="myform" id="myform" method="post" action="#" enctype="multipart/form-data" accept-charset="utf-8" class="taxonomy-drilldown-dropdowns">
<ul>
<li>
<label>Destination:</label>
<select name="city" id="city">
<option class="level-0" value="atlanta">Atlanta</option>
<option class="level-0" value="miami">Miami</option>
</select>
</li>
</ul>
<input class="srch_btn" type="button" value="Go" />
</form>
<div id="responder"></div>
REVISED JAVASCRIPT/JQUERY:
$(document).ready(function() {
$('#city').change(function() {
//var cty = $('#city').val();
$.ajax({
type: "POST",
url: "myscript.php",
data: "city=" + $(this).val(),
success:function(data){
$('#responder').html(data);
}
});
});
});