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Is it possible to solve this situation with JavaScript/jQuery? [duplicate]

This question already has answers here:
How to allow only one radio button to be checked?
(8 answers)
Closed 3 years ago.
I have a code that checks if radio buttons are checked and if they are it set background color. It's all working fine, my problem is when I want to select another radio button, result is that all my radio buttons are selected on click but it needs to be just one.
$("input[type='radio']").each(function () {
if ($(this).is(":checked")) {
$(this).css("background", "yellow");
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<input type="radio">
<input type="radio" checked>
You can test this out. Just try to select another radio button, you will see that radio buttons are selected (2 radio buttons).
What I want to achieve is that when you click on another radio button it needs to remove this checked class or any other idea. I can't switch between radio buttons.

Give them the same name:
$("input[type='radio']").each(function() {
if ($(this).is(":checked")) {
$(this).css("background", "yellow");
}
});
<script src="https://code.jquery.com/jquery-3.3.1.js"></script>
<input type="radio" name="radio">
<input type="radio" name="radio" checked>

Radio button can be easily handle with name attribute below code may help you
<input type="radio" name="color">
<input type="radio" name="color" checked>
$("input[name='color']").each(function () {
if ($(this).is(":checked")) {
$(this).css("background", "yellow");
}
});

<input type="radio" name="sameName">
<input type="radio" name="sameName">
set their name like this way

To achieve the desired behavior with visible background color for each radio button, you could wrap each radio <input /> with a span element which would achieve the visual effect of a background color for the radio buttons:
/* Reusable selection of radio buttons */
const radioButtons = $("input[type='radio']");
/* Updates selected radio button parent backgrounds based on checked state */
function updateBackground() {
radioButtons.each(function() {
$(this).parent().css('background', $(this).is(":checked") ? 'yellow' : '');
});
}
/* Attach click behavior to each causing the background colors to update */
radioButtons.click(updateBackground);
/* Initalise the backgrounds and */
updateBackground();
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<!-- Wrap each radio button with a span, which will be used to show a colored background
when the radio button is checked -->
<span>
<input type="radio" name="radio-group-name" checked>
</span>
<span>
<input type="radio" name="radio-group-name">
</span>

Add required to input of hidden div when radio is checked

What I'm trying to do is to set hidden div with inputs depended on checked radio input.
This is the logic:
If the first radio is checked the first div is shown, there I want to add hidden inputs with some values...
If the second radio is checked I want the input to be added with required..
And, it shouldn't be required if the 2nd radio isn't checked...
I've tried a few things over some time and got some effects but can't get it work as I want, Here is the code that i'm currently trying to work with, sorry but it's messed up and fails...
So Any help will be much appreciated...
/*
// this code is working but I messed the HTML while trying to get it work with the other code below...
$(document).ready(function() {
$("div.hiddendiv").hide();
check();
$("input[name$='name02']").change(check);
function check() {
var test = $("input[name$='name02']:checked").val();
$("div.hiddendiv").hide();
$("#" + test).show();
}
}
*/
// The code i'm trying to work with...
$(function() {
var radio = $("#closed");
var hidden = $("#hide");
hidden.hide();
checkbox.change(function() {
if (checkbox.is(':checked')) {
hidden.show();
//add required
$('#name02').prop('required', true);
} else {
hidden.hide();
//clear when hidden checked
$("#name02").val("");
//remove required
$('#name02').prop('required', false);
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="radio" id="closed" value="01"> Closed
<input type="radio" id="open" value="02"> Open
<div name="01" class="hiddendiv">
<input name="name01" type="hidden" value="code">
</div>
<div name="02" id="hide" class="hiddendiv">
<input name="name02" type="text" value="">
</div>
Here is the JSFiddle,

try this code
give same name of radio button so it will work as a group and
also set id of input tag as name02 so its use as a #name02 in jquery
so it will work
$(function() {
var radio = $("#closed");
var hidden = $("#hide");
hidden.hide();
$(this).click(function() {
if ($('#closed').is(':checked')) {
hidden.show();
$('#name02').prop('required', true);
} else {
hidden.hide();
//clear when hidden checked
$("#name02").val("");
//remove required
$('#name02').prop('required', false);
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="radio" name='btn' id="closed" value="01"> Closed
<input type="radio" name='btn' id="open" value="02"> Open
<div name="01" class="hiddendiv">
<input name="name01" type="hidden" value="code">
</div>
<div name="02" id="hide" class="hiddendiv">
<input name="name02" id="name02" type="text" value="">
</div>

Part of your problem is that you need to set the name attribute of your radio buttons to be the same value, otherwise the HTML won't know that they belong to the same group.
I've updated the JSfiddle here
https://jsfiddle.net/hba4d83k/2/
What i have done is add a change event handler to your the radio group and then did some conditional logic to show/hide the relevant inputs.

Show / Hide contents base on radio button selection

I am trying to toggle a content DIV base on the selection of radio buttons.
HTML for radio button.
<div class="row-fluid">
<label class="radio">
<input type="radio" name="account" id="yes" value="yes" checked>
Yes, I have an existing account
</label>
<label class="radio">
<input type="radio" name="account" id="no" value="no">
No, I don't have an account
</label>
</div>
Content DIV
<div id="account_contents">
<p>This is account contents.......</p>
</div>
This is how I tried it in jquery.
$('#no').bind('change',function(){
$('#account_contents').fadeToggle(!$(this).is(':checked'));
$('#account_contents').find("input").val("");
$('#account_contents').find('select option:first').prop('selected',true);
});
But it doesn't work for me correctly. Here I want to show this content DIV only if user don't have an account.
Can anybody tell me how to fix this problem?

seems you need .on('change') for radio buttons not just for one of them
$('input[type="radio"][name="account"]').on('change',function(){
var ThisIt = $(this);
if(ThisIt.val() == "yes"){
// when user select yes
$('#account_contents').fadeOut();
}else{
// when user select no
$('#account_contents').fadeIn();
$('#account_contents').find("input").val("");
$('#account_contents').find('select option:first').prop('selected',true);
}
});
Working Example

$(document).ready(function(){
$('.radio input[type="radio"]').on("click", function(){
if($('.radio input[type="radio"]:checked').val() === "yes"){
$("#account_contents").slideDown("slow");
}else{
$("#account_contents").slideUp("slow");
}
});
});

I'm not sure if I got you right, but this fiddle toggles #account_contents depending on which button you click:
This was how i tweaked the script:
$('#no').bind('change',function(){
$('#account_contents').fadeToggle(!$(this).is(':checked'));
$('#account_contents').find("input").val("");
$('#account_contents').find('select option:first').prop('selected',true);
});
$("#yes").bind("change", function() {
$('#account_contents').fadeOut();
});

Condtionally disable button by Radio and Checkbox

I would like to conditionally disable a button based on a radio and checkbox combination. The radio will have two options, the first is checked by default. If the user selects the second option then I would like to disable a button until at least one checkbox has been checked.
I have searched at length on CodePen and Stack Overflow but cannot find a solution that works with my conditionals. The results I did find were close but I couldn't adapt them to my needs as I am a Javascript novice.
I am using JQuery, if that helps.
If needed:
http://codepen.io/traceofwind/pen/EVNxZj
<form>
<div id="input-option1">First option: (required)
<input type="radio" name="required" id="required" value="1" checked="checked">Yes
<input type="radio" name="required" id="required" value="2">No
<div>
<div id="input-option2">Optionals:
<input type="checkbox" name="optionals" id="optionals" value="2a">Optional 1
<input type="checkbox" name="optionals" id="optionals" value="2b">Optional 2
<div>
<div id="input-option3">Extras:
<input type="checkbox" name="extra" id="extra" value="3">Extra 1
<div>
<button type="button" id="btn">Add to Cart</button>
</form>
(Please excuse the code, it is in short hand for example!)
The form element IDs are somewhat fixed. The IDs are generated by OpenCart so I believe the naming convention is set by group, rather than unique. I cannot use IDs such as radio_ID_1 and radio_ID_2, for example; this is an OpenCart framework facet and not a personal choice.
Finally, in pseudo code I am hoping someone can suggest a JQuery / javascript solution along the lines of:
if radio = '2' then
if checkboxes = unchecked then
btn = disabled
else
btn = enabled
end if
end if

Here is a quick solution and I hope that's what you were after.
$(function() {
var $form = $("#form1");
var $btn = $form.find("#btn");
var $radios = $form.find(":radio");
var $checks = $form.find(":checkbox[name='optionals']");
$radios.add($checks).on("change", function() {
var radioVal = $radios.filter(":checked").val();
$btn.prop("disabled", true);
if (radioVal == 2) {
$btn.prop("disabled", !$checks.filter(":checked").length >= 1);
} else {
$btn.prop("disabled", !radioVal);
}
});
});
Here is a demo with the above + your HTML.
Note: Remove all the IDs except the form ID, button ID (since they're used in the demo) as you can't have duplicate IDs in an HTML document. an ID is meant to identify a unique piece of content. If the idea is to style those elements, then use classes.

If you foresee a lot of JavaScript development in your future, then I would highly recommend the JavaScript courses made available by Udacity. Although the full course content is only available for a fee, the most important part of the course materials--the videos and integrated questions--are free.
However, if you don't plan to do a lot of JavaScript development in the future and just need a quick solution so you can move on, here's how to accomplish what you are trying to accomplish:
$(document).ready(function(){
$('form').on('click', 'input[type="radio"]', function(){
conditionallyToggleButton();
});
$('form').on('click', 'input[type="checkbox"]', function(){
conditionallyToggleButton();
});
});
function conditionallyToggleButton()
{
if (shouldDisableButton())
{
disableButton();
}
else
{
enableButton();
}
}
function shouldDisableButton()
{
if ($('div#input-option1 input:checked').val() == 2
&& !$('form input[type="checkbox"]:checked').length)
{
return true;
}
return false;
}
function disableButton()
{
$('button').prop('disabled', true);
}
function enableButton()
{
$('button').prop('disabled', false);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<div id="input-option1">First option: (required)
<input type="radio" name="required" id="required" value="1" checked="checked">Yes
<input type="radio" name="required" id="required" value="2">No
<div>
<div id="input-option2">Optionals:
<input type="checkbox" name="optionals" id="optionals" value="2a">Optional 1
<input type="checkbox" name="optionals" id="optionals" value="2b">Optional 2
<div>
<div id="input-option3">Extras:
<input type="checkbox" name="extra" id="extra" value="3">Extra 1
<div>
<button type="button" id="btn">Add to Cart</button>
</form>
Note that the JavaScript code above is a quick-and-dirty solution. To do it right, you would probably want to create a JavaScript class representing the add to cart form that manages the behavior of the form elements and which caches the jQuery-wrapped form elements in properties.

Disappearing radio button and clickable labels

I want to make radio buttons disappear and instead of buttons, the label of the radio buttons will be clickable itself and i will change the background color of the selected radio. How can i do this? For example, I have "yes" and "no" labels and these labels will be clickable and there will be no radio buttons at all. These are only changing color of background but showing radio buttons which is not wanted.
Javascript
$(document).ready(function(){
var ok = "green";
var notok = "red";
$.each($(":radio"), function(){
if($(this).prop("checked") == false)
{
$(this).parent().css("background", notok);
}
else
{
$(this).parent().css("background", ok );
}
})
$(":radio").click(function(){
$("[name='"+$(this).prop("name")+"']").parent().css("background", notok);
$(this).parent().css("background", ok );
})
})
HTML
<FORM name="form1">
<div>
<input type="radio" id="yes" name="q"checked="checked"/> Yes
</div>
<div>
<input type="radio" id="no" name="q"/>No
</div>
</FORM>
Thanks

This one is actually deceptively easy. If you just use a "label" tag, it will be clickable. Then you can simply hide the radio button.
<input id="yes" type="radio" name="q" value="radiobutton" style="display:none;" />
<label for="yes">Yes </label>
<input id="no" type="radio" name="q" value="radiobutton" style="display:none;" />
<label for="no">No</label>
btw, here's a JSFiddle of it working: http://jsfiddle.net/scGE9/2/

If I understand what you're asking, I'd hide the radio buttons, then attach a click handler to the labels that changed the background color:
$('label').click(function () {
$('label').removeClass('selected');
$(this).addClass('selected');
});
Here's a jsfiddle to demonstrate.
In short, when a label is clicked, remove the 'selected' class controlling the background color from all relevant labels, and apply it to the one that was clicked.