Or symbol for JavaScript object declaration - javascript

I just started to read some JavaScript project. Most of the .js file to start with have an object declared as the following:
window.Example || {
bleh: "123";
blah: "ref"
}
What does the || symbol do here?

Objects in Javascript are truthy, so that expression evaluates to either window.Example or the default object if window.Example is falsy (or undefined). Example:
var x = window.Example || {foo: 'bar'};
// x = {foo: 'bar'}, since window.Example is undefined
window.Example = {test: 1};
var y = window.Example || {foo: 'bar'};
// y = {test: 1}, since window.Example is truthy (all objects are truthy)
Read this article for a good explanation on truthy/falsy and short-circuit evaluation.

The || operator in JavaScript is like the "or" operator in other C-like languages, but it's distinctly different. It really means:
Evaluate the subexpresson to the left.
If that value, when coerced to boolean, is true, then that subexpression's value (before coercion to boolean) is the value of the || expression
Else evaluate the right-hand subexpression and yield its value as the value of the || expression.
Thus it's used idiomatically to initialize something that might already be initialized:
var something = window.something || defaultValue;
just means, "check to see if "something" is a property of the window object with a truthy value, and if it's not, then set it to defaultValue."

There's an important bit missing from that code - the variable declaration:
var something = window.Example || {
bleh: "123",
blah: "ref"
}
This roughly translates to "set something to window.Example, unless it doesn't exist, then set it to this new object".

Related

How does the var FOO = FOO || {} idiom in Javascript work?

From this question: What does "var FOO = FOO || {}" (assign a variable or an empty object to that variable) mean in Javascript?
I've learned that var FOO = FOO || {} essentially means "If FOO exists, then leave it untouched, else make it an empty object".
But how?
This is how I would parse this syntax:
var FOO = (FOO || {})
So: If FOO exists AND evaluates to Boolean value of True, then (FOO || {}) will return True, so eventually FOO will be completely overwritten and will hold the Boolean value of True from now on.
Else (FOO || {}) will return to whatever Boolean value {} evalueates to. Since an empty object, which {} is, always evaluates to True...
Then in ANY case (FOO || {}) should evaluate to True, so...
In ANY POSSIBLE CASE, after evaluating var FOO = FOO || {}, FOO should hold the trivial Boolean value of True, regardless of whatever it was holding before. Essentially, to my understanding, var FOO = FOO || {} should be equivalent to var FOO = True.
Where is my mistake?
If FOO exists AND evaluates to Boolean value of True, then (FOO || {}) will return True
That isn't how the || operator works in JS.
A correct interpretation is:
If the left hand side is a true value, evaluate as the left hand side (i.e. FOO), otherwise evaluate as the right hand side (i.e. {}).
var zero = 0;
var one = 1;
var two = 2;
console.log(zero || two);
console.log(one || two);
So: If FOO exists AND evaluates to Boolean value of True, then (FOO || {}) will return True, so eventually FOO will be completely overwritten and will hold the Boolean value of True from now on.
That is wrong, but the below lines surprise you if your background is Strictly Typed Languages :)
The expression doesn't return a boolean value. It returns the expression that can be evaluated to true.
Here is the docs for the same
Returns expr1 if it can be converted to true; otherwise, returns expr2. Thus, when used with Boolean values, || returns true if either operand is true; if both are false, returns false.
Logical operators are typically used with Boolean (logical) values. When they are, they return a Boolean value. However, the && and || operators actually return the value of one of the specified operands, so if these operators are used with non-Boolean values, they may return a non-Boolean value.
Different examples given in docs might help you understand the above words.
o4 = false || (3 == 4) // f || f returns false
o5 = 'Cat' || 'Dog' // t || t returns "Cat"
o6 = false || 'Cat' // f || t returns "Cat"
o7 = 'Cat' || false // t || f returns "Cat"
o8 = '' || false // returns false
JavaScript || operator returns the expression itself not the boolean value. Here's a reference from Mozilla documentation
Returns expr1 if it can be converted to true; otherwise, returns
expr2. Thus, when used with Boolean values, || returns true if either
operand is true.
Reference :
Conversion to True in boolean depends on whether the expression evaluates to a Truthy value.
So: If FOO exists AND evaluates to Boolean value of True, then (FOO ||
{}) will return True
The problem of the concept is the cast. Here the Object is not cast to Boolean, JS leave it untouched.
So, If FOO is defined (FOO || {}) will return FOO and if is not defined will return {}
This is because of Short Circuit Evaluation.
Short-circuit evaluation says, the second argument is executed or evaluated only if the first argument does not suffice to determine the value of the expression: when the first argument of the AND (&&) function evaluates to false, the overall value must be false; and when the first argument of the OR (||) function evaluates to true, the overall value must be true.
But if the first argument of AND function evaluates to true, the second argument has to be executed or evaluated to determine the value of expression; and when the first argument of OR function evaluates to false, the second argument has to be executed or evaluated to determine the value of the expression.
In-case of FOO || {};
This returns FOO if FOO evaluates to TRUE, because there is no need to evaluate second argument if first one is true.
This returns {} if FOO evaluates to FALSE, because the second argument need to be evaluated to get the value of the expression.
See here for more details..

Javascript shorthand to call method if object exists

I have a variable and if that variable is a object I would like to call a method on that object, if not I want to do nothing.
I'm wondering if there is any reason why I shouldn't do it like this.
var foo = null;
////////////////////////////////////////////////
// some code that could change foo to a object
////////////////////////////////////////////////
foo && foo.bar();
With ES6, you can combine optional chaining operator with call:
foo?.bar?.call()
If you want to pass arguments, keep in mind that the first one in call assigns this in function call
var foo = {
bar: function(x) { return x; }
};
first.value = foo?.bar?.call(0,42); // 42
second.value = foo?.baz?.call(0,42); // undefined, no error
<input id="first">
<input id="second">
The quick answer is yes, foo && foo.bar() won't throw an exception if foo is null, and if foo is non-null, bar() will be evaluated, and it's value will be the value of the expression.
Longer answer is that any value can be interpreted as a boolean, in the sense that every value is either truthy or falsey, and that the boolean operators do short-circuit evaluation -- left to right, if we see a false && or a true ||, there's no reason to carry on evaluating.
One last fact is that the value of boolean expression is the value of the expression where the short-circuit happened.
You need to assign an object to foo and a property with a function.
var foo;
foo = {};
foo.bar = function () {
console.log('inside bar');
};
foo && foo.bar && foo.bar();
((typeof foo === 'object') && foo.bar())
or
(!(typeof foo == 'object') || foo.bar())
If foo is of type object then execute.
See my answer here javascript using or operator to iterate over list of strings aswell.
This is a "common" issue for unintended behavior, if some uses assignments inside such a sequence and forgets that evaluation stops in the || sequence after first true , or stops after first false in the && .

jquery find function with || ">*" [duplicate]

I am debugging some JavaScript and can't explain what this || does:
function (title, msg) {
var title = title || 'Error';
var msg = msg || 'Error on Request';
}
Why is this guy using var title = title || 'ERROR'? I sometimes see it without a var declaration as well.
What is the double pipe operator (||)?
The double pipe operator (||) is the logical OR operator . In most languages it works the following way:
If the first value is false, it checks the second value. If that's true, it returns true and if the second value is false, it returns false.
If the first value is true, it always returns true, no matter what the second value is.
So basically it works like this function:
function or(x, y) {
if (x) {
return true;
} else if (y) {
return true;
} else {
return false;
}
}
If you still don't understand, look at this table:
| true false
------+---------------
true | true true
false | true false
In other words, it's only false when both values are false.
How is it different in JavaScript?
JavaScript is a bit different, because it's a loosely typed language. In this case it means that you can use || operator with values that are not booleans. Though it makes no sense, you can use this operator with for example a function and an object:
(function(){}) || {}
What happens there?
If values are not boolean, JavaScript makes implicit conversion to boolean. It means that if the value is falsey (e.g. 0, "", null, undefined (see also All falsey values in JavaScript)), it will be treated as false; otherwise it's treated as true.
So the above example should give true, because empty function is truthy. Well, it doesn't. It returns the empty function. That's because JavaScript's || operator doesn't work as I wrote at the beginning. It works the following way:
If the first value is falsey, it returns the second value.
If the first value is truthy, it returns the first value.
Surprised? Actually, it's "compatible" with the traditional || operator. It could be written as following function:
function or(x, y) {
if (x) {
return x;
} else {
return y;
}
}
If you pass a truthy value as x, it returns x, that is, a truthy value. So if you use it later in if clause:
(function(x, y) {
var eitherXorY = x || y;
if (eitherXorY) {
console.log("Either x or y is truthy.");
} else {
console.log("Neither x nor y is truthy");
}
}(true/*, undefined*/));
you get "Either x or y is truthy.".
If x was falsey, eitherXorY would be y. In this case you would get the "Either x or y is truthy." if y was truthy; otherwise you'd get "Neither x nor y is truthy".
The actual question
Now, when you know how || operator works, you can probably make out by yourself what does x = x || y mean. If x is truthy, x is assigned to x, so actually nothing happens; otherwise y is assigned to x. It is commonly used to define default parameters in functions. However, it is often considered a bad programming practice, because it prevents you from passing a falsey value (which is not necessarily undefined or null) as a parameter. Consider following example:
function badFunction(/* boolean */flagA) {
flagA = flagA || true;
console.log("flagA is set to " + (flagA ? "true" : "false"));
}
It looks valid at the first sight. However, what would happen if you passed false as flagA parameter (since it's boolean, i.e. can be true or false)? It would become true. In this example, there is no way to set flagA to false.
It would be a better idea to explicitly check whether flagA is undefined, like that:
function goodFunction(/* boolean */flagA) {
flagA = typeof flagA !== "undefined" ? flagA : true;
console.log("flagA is set to " + (flagA ? "true" : "false"));
}
Though it's longer, it always works and it's easier to understand.
You can also use the ES6 syntax for default function parameters, but note that it doesn't work in older browsers (like IE). If you want to support these browsers, you should transpile your code with Babel.
See also Logical Operators on MDN.
It means the title argument is optional. So if you call the method with no arguments it will use a default value of "Error".
It's shorthand for writing:
if (!title) {
title = "Error";
}
This kind of shorthand trick with boolean expressions is common in Perl too. With the expression:
a OR b
it evaluates to true if either a or b is true. So if a is true you don't need to check b at all. This is called short-circuit boolean evaluation so:
var title = title || "Error";
basically checks if title evaluates to false. If it does, it "returns" "Error", otherwise it returns title.
If title is not set, use 'ERROR' as default value.
More generic:
var foobar = foo || default;
Reads: Set foobar to foo or default.
You could even chain this up many times:
var foobar = foo || bar || something || 42;
Explaining this a little more...
The || operator is the logical-or operator. The result is true if the first part is true and it is true if the second part is true and it is true if both parts are true. For clarity, here it is in a table:
X | Y | X || Y
---+---+--------
F | F | F
---+---+--------
F | T | T
---+---+--------
T | F | T
---+---+--------
T | T | T
---+---+--------
Now notice something here? If X is true, the result is always true. So if we know that X is true we don't have to check Y at all. Many languages thus implement "short circuit" evaluators for logical-or (and logical-and coming from the other direction). They check the first element and if that's true they don't bother checking the second at all. The result (in logical terms) is the same, but in terms of execution there's potentially a huge difference if the second element is expensive to calculate.
So what does this have to do with your example?
var title = title || 'Error';
Let's look at that. The title element is passed in to your function. In JavaScript if you don't pass in a parameter, it defaults to a null value. Also in JavaScript if your variable is a null value it is considered to be false by the logical operators. So if this function is called with a title given, it is a non-false value and thus assigned to the local variable. If, however, it is not given a value, it is a null value and thus false. The logical-or operator then evaluates the second expression and returns 'Error' instead. So now the local variable is given the value 'Error'.
This works because of the implementation of logical expressions in JavaScript. It doesn't return a proper boolean value (true or false) but instead returns the value it was given under some rules as to what's considered equivalent to true and what's considered equivalent to false. Look up your JavaScript reference to learn what JavaScript considers to be true or false in boolean contexts.
|| is the boolean OR operator. As in JavaScript, undefined, null, 0, false are considered as falsy values.
It simply means
true || true = true
false || true = true
true || false = true
false || false = false
undefined || "value" = "value"
"value" || undefined = "value"
null || "value" = "value"
"value" || null = "value"
0 || "value" = "value"
"value" || 0 = "value"
false || "value" = "value"
"value" || false = "value"
Basically, it checks if the value before the || evaluates to true. If yes, it takes this value, and if not, it takes the value after the ||.
Values for which it will take the value after the || (as far as I remember):
undefined
false
0
'' (Null or Null string)
Whilst Cletus' answer is correct, I feel more detail should be added in regards to "evaluates to false" in JavaScript.
var title = title || 'Error';
var msg = msg || 'Error on Request';
Is not just checking if title/msg has been provided, but also if either of them are falsy. i.e. one of the following:
false.
0 (zero)
"" (empty string)
null.
undefined.
NaN (a special Number value meaning Not-a-Number!)
So in the line
var title = title || 'Error';
If title is truthy (i.e., not falsy, so title = "titleMessage" etc.) then the Boolean OR (||) operator has found one 'true' value, which means it evaluates to true, so it short-circuits and returns the true value (title).
If title is falsy (i.e. one of the list above), then the Boolean OR (||) operator has found a 'false' value, and now needs to evaluate the other part of the operator, 'Error', which evaluates to true, and is hence returned.
It would also seem (after some quick firebug console experimentation) if both sides of the operator evaluate to false, it returns the second 'falsy' operator.
i.e.
return ("" || undefined)
returns undefined, this is probably to allow you to use the behavior asked about in this question when trying to default title/message to "". i.e. after running
var foo = undefined
foo = foo || ""
foo would be set to ""
Double pipe stands for logical "OR". This is not really the case when the "parameter not set", since strictly in JavaScript if you have code like this:
function foo(par) {
}
Then calls
foo()
foo("")
foo(null)
foo(undefined)
foo(0)
are not equivalent.
Double pipe (||) will cast the first argument to Boolean and if the resulting Boolean is true - do the assignment, otherwise it will assign the right part.
This matters if you check for unset parameter.
Let's say, we have a function setSalary that has one optional parameter. If the user does not supply the parameter then the default value of 10 should be used.
If you do the check like this:
function setSalary(dollars) {
salary = dollars || 10
}
This will give an unexpected result for a call like:
setSalary(0)
It will still set the 10 following the flow described above.
Double pipe operator
This example may be useful:
var section = document.getElementById('special');
if(!section){
section = document.getElementById('main');
}
It can also be:
var section = document.getElementById('special') || document.getElementById('main');
To add some explanation to all said before me, I should give you some examples to understand logical concepts.
var name = false || "Mohsen"; # name equals to Mohsen
var family = true || "Alizadeh" # family equals to true
It means if the left side evaluated as a true statement it will be finished and the left side will be returned and assigned to the variable. in other cases the right side will be returned and assigned.
And operator have the opposite structure like below.
var name = false && "Mohsen" # name equals to false
var family = true && "Alizadeh" # family equals to Alizadeh
Quote: "What does the construct x = x || y mean?"
Assigning a default value.
This means providing a default value of y to x,
in case x is still waiting for its value but hasn't received it yet or was deliberately omitted in order to fall back to a default.
And I have to add one more thing: This bit of shorthand is an abomination. It misuses an accidental interpreter optimization (not bothering with the second operation if the first is truthy) to control an assignment. That use has nothing to do with the purpose of the operator. I do not believe it should ever be used.
I prefer the ternary operator for initialization, for example,
var title = title?title:'Error';
This uses a one-line conditional operation for its correct purpose. It still plays unsightly games with truthiness but, that's JavaScript for you.

What does this bit of code mean? [duplicate]

This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Javascript Shorthand - What Does the '||' Operator Mean When Used in an Assignment?
var variable = obj1 || obj2;
Does it mean this?
var variable;
if (obj1)
{
variable = obj1;
}
else if (obj2)
{
variable = obj2:
}
Is it considered bad practise?
The || operator returns its left hand side if resolves to be a true value, otherwise it returns its right hand side.
So it means the same as:
var variable;
if (obj1){
variable = obj1;
} else {
variable = obj2:
}
Note else, not, else if.
It is a common pattern and not usually considered bad practise.
The gotcha is that you need to be sure you want if (obj) and not if (typeof obj !== "undefined").
Yup, that's what it means, and it's good practice
|| is a logical OR, so if obj1 = false you get false OR obj2 so the variable equals obj2
How || expression works
The expression a || b value is determined by the last partial evaluated to determine Boolean truth.
false || 1 is evaluated as 1 is the last one evaluated.
true || 0 is evaluated as true as it is the last one evaluated.
How obj is evaluated in Boolean context
For an object in the context of Boolean value, object is evaluated to true unless null. It means even {} === true.
Combine the above two explanation, var variable = obj1 || obj2 assigns the first none null object from obj1 and obj2 to variable.

What is the difference between null and undefined in JavaScript?

I want to know what the difference is between null and undefined in JavaScript.
undefined means a variable has been declared but has not yet been assigned a value :
var testVar;
console.log(testVar); //shows undefined
console.log(typeof testVar); //shows undefined
null is an assignment value. It can be assigned to a variable as a representation of no value :
var testVar = null;
console.log(testVar); //shows null
console.log(typeof testVar); //shows object
From the preceding examples, it is clear that undefined and null are two distinct types: undefined is a type itself (undefined) while null is an object.
Proof :
console.log(null === undefined) // false (not the same type)
console.log(null == undefined) // true (but the "same value")
console.log(null === null) // true (both type and value are the same)
and
null = 'value' // Uncaught SyntaxError: invalid assignment left-hand side
undefined = 'value' // 'value'
The difference can be explained with toilet tissue holder:
A non-zero value is like a holder with roll of toilet tissue and there's tissue still on the tube.
A zero value is like a holder with an empty toilet tissue tube.
A null value is like a holder that doesn't even have a tissue tube.
An undefined value is similar to the holder itself being missing.
I picked this from here
The undefined value is a primitive value used when a variable has not
been assigned a value.
The null value is a primitive value that represents the null, empty,
or non-existent reference.
When you declare a variable through var and do not give it a value, it will have the value undefined. By itself, if you try to WScript.Echo() or alert() this value, you won't see anything. However, if you append a blank string to it then suddenly it'll appear:
var s;
WScript.Echo(s);
WScript.Echo("" + s);
You can declare a variable, set it to null, and the behavior is identical except that you'll see "null" printed out versus "undefined". This is a small difference indeed.
You can even compare a variable that is undefined to null or vice versa, and the condition will be true:
undefined == null
null == undefined
They are, however, considered to be two different types. While undefined is a type all to itself, null is considered to be a special object value. You can see this by using typeof() which returns a string representing the general type of a variable:
var a;
WScript.Echo(typeof(a));
var b = null;
WScript.Echo(typeof(b));
Running the above script will result in the following output:
undefined
object
Regardless of their being different types, they will still act the same if you try to access a member of either one, e.g. that is to say they will throw an exception. With WSH you will see the dreaded "'varname' is null or not an object" and that's if you're lucky (but that's a topic for another article).
You can explicitely set a variable to be undefined, but I highly advise against it. I recommend only setting variables to null and leave undefined the value for things you forgot to set. At the same time, I really encourage you to always set every variable. JavaScript has a scope chain different than that of C-style languages, easily confusing even veteran programmers, and setting variables to null is the best way to prevent bugs based on it.
Another instance where you will see undefined pop up is when using the delete operator. Those of us from a C-world might incorrectly interpret this as destroying an object, but it is not so. What this operation does is remove a subscript from an Array or a member from an Object. For Arrays it does not effect the length, but rather that subscript is now considered undefined.
var a = [ 'a', 'b', 'c' ];
delete a[1];
for (var i = 0; i < a.length; i++)
WScript.Echo((i+".) "+a[i]);
The result of the above script is:
0.) a
1.) undefined
2.) c
You will also get undefined returned when reading a subscript or member that never existed.
The difference between null and undefined is: JavaScript will never set anything to null, that's usually what we do. While we can set variables to undefined, we prefer null because it's not something that is ever done for us. When you're debugging this means that anything set to null is of your own doing and not JavaScript. Beyond that, these two special values are nearly equivalent.
Please read the following carefully. It should remove all your doubts regarding the difference between null and undefined in JavaScript. Also, you can use the utility function at the end of this answer to get more specific types of variables.
In JavaScript we can have the following types of variables:
Undeclared Variables
Declared but Unassigned Variables
Variables assigned with literal undefined
Variables assigned with literal null
Variables assigned with anything other than undefined or null
The following explains each of these cases one by one:
Undeclared Variables
Can only be checked with the typeof operator which returns string 'undefined'
Cannot be checked with the loose equality operator ( == undefined ), let alone the strict equality operator ( === undefined ),
as well as if-statements and ternary operators ( ? : ) — these throw Reference Errors
Declared but Unassigned Variables
typeof returns string 'undefined'
== check with null returns true
== check with undefined returns true
=== check with null returns false
=== check with undefined returns true
Is falsy to if-statements and ternary operators ( ? : )
Variables assigned with literal undefined
These variables are treated exactly the same as Declared But Unassigned Variables.
Variables assigned with literal null
typeof returns string 'object'
== check with null returns true
== check with undefined returns true
=== check with null returns true
=== check with undefined returns false
Is falsy to if-statements and ternary operators ( ? : )
Variables assigned with anything other than undefined or null
typeof returns one of the following strings: 'bigint', 'boolean', 'function', 'number', 'object', 'string', 'symbol'
Following provides the algorithm for correct type checking of a variable:
Get the typeof our variable and return it if it isn't 'object'
Check for null, as typeof null returns 'object' as well
Evaluate Object.prototype.toString.call(o) with a switch statement to return a more precise value. Object's toString method returns strings that look like '[object ConstructorName]' for native/host objects. For all other objects (user-defined objects), it always returns '[object Object]'
If that last part is the case (the stringified version of the variable being '[object Object]') and the parameter returnConstructorBoolean is true, it will try to get the name of the constructor by toString-ing it and extracting the name from there. If the constructor can't be reached, 'object' is returned as usual. If the string doesn't contain its name, 'anonymous' is returned
(supports all types up to ECMAScript 2020)
function TypeOf(o, returnConstructorBoolean) {
const type = typeof o
if (type !== 'object') return type
if (o === null) return 'null'
const toString = Object.prototype.toString.call(o)
switch (toString) {
// Value types: 6
case '[object BigInt]': return 'bigint'
case '[object Boolean]': return 'boolean'
case '[object Date]': return 'date'
case '[object Number]': return 'number'
case '[object String]': return 'string'
case '[object Symbol]': return 'symbol'
// Error types: 7
case '[object Error]': return 'error'
case '[object EvalError]': return 'evalerror'
case '[object RangeError]': return 'rangeerror'
case '[object ReferenceError]': return 'referenceerror'
case '[object SyntaxError]': return 'syntaxerror'
case '[object TypeError]': return 'typeerror'
case '[object URIError]': return 'urierror'
// Indexed Collection and Helper types: 13
case '[object Array]': return 'array'
case '[object Int8Array]': return 'int8array'
case '[object Uint8Array]': return 'uint8array'
case '[object Uint8ClampedArray]': return 'uint8clampedarray'
case '[object Int16Array]': return 'int16array'
case '[object Uint16Array]': return 'uint16array'
case '[object Int32Array]': return 'int32array'
case '[object Uint32Array]': return 'uint32array'
case '[object Float32Array]': return 'float32array'
case '[object Float64Array]': return 'float64array'
case '[object ArrayBuffer]': return 'arraybuffer'
case '[object SharedArrayBuffer]': return 'sharedarraybuffer'
case '[object DataView]': return 'dataview'
// Keyed Collection types: 2
case '[object Map]': return 'map'
case '[object WeakMap]': return 'weakmap'
// Set types: 2
case '[object Set]': return 'set'
case '[object WeakSet]': return 'weakset'
// Operation types: 3
case '[object RegExp]': return 'regexp'
case '[object Proxy]': return 'proxy'
case '[object Promise]': return 'promise'
// Plain objects
case '[object Object]':
if (!returnConstructorBoolean)
return type
const _prototype = Object.getPrototypeOf(o)
if (!_prototype)
return type
const _constructor = _prototype.constructor
if (!_constructor)
return type
const matches = Function.prototype.toString.call(_constructor).match(/^function\s*([^\s(]+)/)
return matches ? matches[1] : 'anonymous'
default: return toString.split(' ')[1].slice(0, -1)
}
}
null is a special keyword that indicates an absence of value.
think about it as a value, like:
"foo" is string,
true is boolean ,
1234 is number,
null is undefined.
undefined property indicates that a variable has not been assigned a value including null too .
Like
var foo;
defined empty variable is null of datatype undefined
Both of them are representing a value of a variable with no value
AND
null doesn't represent a string that has no value - empty string-
Like
var a = '';
console.log(typeof a); // string
console.log(a == null); //false
console.log(a == undefined); // false
Now if
var a;
console.log(a == null); //true
console.log(a == undefined); //true
BUT
var a;
console.log(a === null); //false
console.log(a === undefined); // true
SO each one has it own way to use
undefined use it to compare the variable data type
null use it to empty a value of a variable
var a = 'javascript';
a = null ; // will change the type of variable "a" from string to object
null: absence of value for a variable; undefined: absence of variable itself;
..where variable is a symbolic name associated with a value.
JS could be kind enough to implicitly init newly declared variables with null, but it does not.
You might consider undefined to represent a system-level, unexpected, or error-like absence of value and null to represent program-level, normal, or expected absence of value.
via JavaScript:The Definitive Guide
The best way to understand the difference is to first clear your mind of the inner workings of JavaScript and just understand the differences in meaning between:
let supervisor = "None"
// I have a supervisor named "None"
let supervisor = null
// I do NOT have a supervisor. It is a FACT that I do not.
let supervisor = undefined
// I may or may not have a supervisor. I either don't know
// if I do or not, or I am choosing not to tell you. It is
// irrelevant or none of your business.
There is a difference in meaning between these three cases, and JavaScript distinguishes the latter two cases with two different values, null and undefined. You are free to use those values explicitly to convey those meanings.
So what are some of the JavaScript-specific issues that arise due to this philosophical basis?
A declared variable without an initializer gets the value undefined because you never said anything about the what the intended value was.
let supervisor;
assert(supervisor === undefined);
A property of an object that has never been set evaluates to undefined because no one ever said anything about that property.
const dog = { name: 'Sparky', age: 2 };
assert(dog.breed === undefined);
null and undefined are "similar" to each other because Brendan Eich said so. But they are emphatically not equal to each other.
assert(null == undefined);
assert(null !== undefined);
null and undefined thankfully have different types. null belongs to the type Null and undefined to the type Undefined. This is in the spec, but you would never know this because of the typeof weirdness which I will not repeat here.
A function reaching the end of its body without an explicit return statement returns undefined since you don't know anything about what it returned.
By the way, there are other forms of "nothingness" in JavaScript (it's good to have studied Philosophy....)
NaN
Using a variable that has never been declared and receiving a ReferenceError
Using a let or const defined local variable in its temporal dead zone and receiving a ReferenceError
Empty cells in sparse arrays. Yes these are not even undefined although they compare === to undefined.
$ node
> const a = [1, undefined, 2]
> const b = [1, , 2]
> a
[ 1, undefined, 2 ]
> b
[ 1, <1 empty item>, 2 ]
A lot of "technical" answers have been given, all of them mostly correct from the limited point of view of JS as a mere programming language.
However, I would like to add the following thoughts, especially when you're writing TypeScript code as part of a bigger project / (enterprise) application:
When talking with a Backend of some kind you'll most probably receive JSON
While some backends correctly avoid the use of "null" in their JSON (removing those properties), others do not
Now, while "null" may mean that the value is missing deliberately, more often it does not convey this meaning. Most databases use "null" just because they don't have an "undefined" type. But the meaning really just is "undefined".
Because of that, you can never know if a "null" value really means deliberate absence. Therefore "null" cannot really mean the deliberate choice of "missing value". It is undecidable in general.
As a consequence, semantically, "null" and "undefined" are exactly the same thing in practice.
Therefore, in an effort to harmonize things I'm strictly against using "null" and want to encourage you to stop using "null" in your code. It's far easier than you might think. Don't get me wrong. I'm not talking about not handling "null" values, only to avoid explicitly using them in your code. Put differently: your code should still be able to work with accidentally passed "null" values coming from outside your application, e.g. via a 3rd party lib like Angular, or a 3rd party backend.
Here are the guidelines that make it possible:
avoid direct undefined type guards (e.g. if (value === undefined) { ... }.
Instead, use indirect type guards (aka truthiness checks) e.g. if (value) { ... }
Whenever 0 or empty strings are meaningful, use either
an explicit helper method like Lodash's isNil
or include the meaningful value in the comparison (e.g. if (!value && value !== 0) { ... })
Consider using a lint rule that disallows the usage of null
null is a special value meaning "no value". null is a special object because typeof null returns 'object'.
On the other hand, undefined means that the variable has not been declared, or has not been given a value.
I'll explain undefined, null and Uncaught ReferenceError:
1 - Uncaught ReferenceError : variable has not been declared in your script, there is no reference to this varaible
2 - undefined: Variable declared but does not initialised
3 - null : Variable declared and is an empty value
null and undefined are two distinct object types which have the following in common:
both can only hold a single value, null and undefined respectively;
both have no properties or methods and an attempt to read any properties of either will result in a run-time error (for all other objects, you get value undefined if you try to read a non-existent property);
values null and undefined are considered equal to each other and to nothing else by == and != operators.
The similarities however end here. For once, there is a fundamental difference in the way how keywords null and undefined are implemented. This is not obvious, but consider the following example:
var undefined = "foo";
WScript.Echo(undefined); // This will print: foo
undefined, NaN and Infinity are just names of preinitialized "superglobal" variables - they are initialized at run-time and can be overridden by normal global or local variable with the same names.
Now, let's try the same thing with null:
var null = "foo"; // This will cause a compile-time error
WScript.Echo(null);
Oops! null, true and false are reserved keywords - compiler won't let you use them as variable or property names
Another difference is that undefined is a primitive type, while null is an object type (indicating the absense of an object reference). Consider the following:
WScript.Echo(typeof false); // Will print: boolean
WScript.Echo(typeof 0); // Will print: number
WScript.Echo(typeof ""); // Will print: string
WScript.Echo(typeof {}); // Will print: object
WScript.Echo(typeof undefined); // Will print: undefined
WScript.Echo(typeof null); // (!!!) Will print: object
Also, there is an important difference in the way null and undefined are treated in numeric context:
var a; // declared but uninitialized variables hold the value undefined
WScript.Echo(a === undefined); // Prints: -1
var b = null; // the value null must be explicitly assigned
WScript.Echo(b === null); // Prints: -1
WScript.Echo(a == b); // Prints: -1 (as expected)
WScript.Echo(a >= b); // Prints: 0 (WTF!?)
WScript.Echo(a >= a); // Prints: 0 (!!!???)
WScript.Echo(isNaN(a)); // Prints: -1 (a evaluates to NaN!)
WScript.Echo(1*a); // Prints: -1.#IND (in Echo output this means NaN)
WScript.Echo(b >= b); // Prints: -1 (as expected)
WScript.Echo(isNaN(b)); // Prints: 0 (b evaluates to a valid number)
WScript.Echo(1*b); // Prints: 0 (b evaluates to 0)
WScript.Echo(a >= 0 && a <= 0); // Prints: 0 (as expected)
WScript.Echo(a == 0); // Prints: 0 (as expected)
WScript.Echo(b >= 0 && b <= 0); // Prints: -1 (as expected)
WScript.Echo(b == 0); // Prints: 0 (!!!)
null becomes 0 when used in arithmetic expressions or numeric comparisons - similarly to false, it is basically just a special kind of "zero". undefined, on the other hand, is a true "nothing" and becomes NaN ("not a number") when you try to use it in numeric context.
Note that null and undefined receive a special treatment from == and != operators, but you can test true numeric equality of a and b with the expression (a >= b && a <= b).
Undefined means a variable has been declared but has no value:
var var1;
alert(var1); //undefined
alert(typeof var1); //undefined
Null is an assignment:
var var2= null;
alert(var2); //null
alert(typeof var2); //object
tl;dr
Use null for set a variable you know it is an Object.
Use undefined for set a variable whose type is mixed.
This is my usage of both 5 primitives and Object type, and that explain the difference between « use case » of undefined or null.
String
If you know a variable is only a string while all lifecycle, by convention, you could initialize it, to "":
("") ? true : false; // false
typeof ""; // "string";
("Hello World") ? true : false; // true
typeof "Hello World"; // "string"
Number
If you know a variable is only a number while all lifecycle, by convention, you could initialize it, to 0 (or NaN if 0 is an important value in your usage):
(0) ? true : false; // false
typeof 0; // "number";
(16) ? true : false; // true
typeof 16; // "number"
or
(NaN) ? true : false; // false
typeof NaN; // "number";
(16) ? true : false; // true
typeof 16; // "number"
Boolean
If you know a variable is only a boolean while all lifecycle, by convention, you could initialize it, to false:
(false) ? true : false; // false
typeof false; // "boolean";
(true) ? true : false; // true
typeof true; // "boolean"
Object
If you know a variable is only an Object while all lifecycle, by convention, you could initialize it, to null:
(null) ? true : false; // false
typeof null; // "object";
({}) ? true : false; // true
typeof {}; // "object"
Note: the smart usage off null is to be the falsy version of an Object because an Object is always true, and because typeof null return object. That means typeof myVarObject return consistent value for both Object and null type.
All
If you know a variable has a mixed type (any type while all lifecycle), by convention, you could initialize it, to undefined.
In addition to a different meaning there are other differences:
Object destructuring works differently for these two values:
const { a = "default" } = { a: undefined }; // a is "default"
const { b = "default" } = { b: null }; // b is null
JSON.stringify() keeps null but omits undefined
const json = JSON.stringify({ undefinedValue: undefined, nullValue: null });
console.log(json); // prints {"nullValue":null}
typeof operator
console.log(typeof undefined); // "undefined"
console.log(typeof null); // "object" instead of "null"
In JavasScript there are 5 primitive data types: String, Number, Boolean, null and undefined.
I will try to explain with some simple examples.
Let's say we have a simple function
function test(a) {
if(a == null) {
alert("a is null");
} else {
alert("The value of a is " + a);
}
}
Also, in above function if(a == null) is the same as if(!a).
Now when we call this function without passing the parameter a
test(); // will alert "a is null";
test(4); // will alert "The value of a is " + 4;
also
var a;
alert(typeof a);
This will give undefined; we have declared a variable but we have not asigned any value to this variable;
but if we write
var a = null;
alert(typeof a); // will give alert as object
so null is an object. In a way we have assigned a value null to 'a'
When you declare a variable in javascript, it is assigned the value undefined. This means the variable is untouched and can be assigned any value in future. It also implies that you don't know the value that this variable is going to hold at the time of declaration.
Now you can explicitly assign a variable null. It means that the variable does not have any value. For example - Some people don't have a middle name. So in such a case its better to assign the value null to the middlename variable of a person object.
Now suppose that someone is accessing the middlename variable of your person object and it has the value undefined. He wouldn't know if the developer forgot to initialize this variable or if it didn't have any value. If it has the value null, then the user can easily infer that middlename doesn't have any value and it is not an untouched variable.
OK, we may get confused when we hear about null and undefined, but let's start it simple, they both are falsy and similar in many ways, but weird part of JavaScript, make them a couple of significant differences, for example, typeof null is 'object' while typeof undefined is 'undefined'.
typeof null; //"object"
typeof undefined; //"undefined";
But if you check them with == as below, you see they are both falsy:
null==undefined; //true
Also you can assign null to an object property or to a primitive, while undefined can simply be achieved by not assigning to anything.
I create a quick image to show the differences for you at a glance.
For the undefined type, there is one and only one value: undefined.
For the null type, there is one and only one value: null.
So for both of them, the label is both its type and its value.
The difference between them. For example:
null is an empty value
undefined is a missing value
Or:
undefined hasn't had a value yet
null had a value and doesn't anymore
Actually, null is a special keyword, not an identifier, and thus you cannot treat it as a variable to assign to.
However, undefined is an identifier. In both non-strict mode and strict mode, however, you can create a local variable of the name undefined. But this is one terrible idea!
function foo() {
undefined = 2; // bad idea!
}
foo();
function foo() {
"use strict";
undefined = 2; // TypeError!
}
foo();
I want to add a knowledge point which pertains to a subtle difference between null and undefined. This is good to know when you are trying to learn Vanilla JavaScript(JS) from ground up:
null is a reserved keyword in JS while undefined is a property on
the global object of the run-time environment you're in.
While writing code, this difference is not identifiable as both null and undefined are always used in right hand side (RHS) of a JavaScript statement. But when you use them in left hand side (LHS) of an expression then you can observe this difference easily. So JS interpreter interprets the below code as error:
var null = 'foo'
It gives below error:
Uncaught SyntaxError: Unexpected token null
At the same time, below code runs successfully although I won't recommend doing so in real life:
var undefined = 'bar'
This works because undefined is a property on the global object (window object in case of JavaScript running in a browser)
null and undefined are both are used to represent the absence of some value.
var a = null;
a is initialized and defined.
typeof(a)
//object
null is an object in JavaScript
Object.prototype.toString.call(a) // [object Object]
var b;
b is undefined and uninitialized
undefined object properties are also undefined. For example "x" is not defined on object c and if you try to access c.x, it will return undefined.
Generally we assign null to variables not undefined.
Per Ryan Morr's thorough article on this subject...
"Generally, if you need to assign a non-value to a variable or property, pass it to a function, or return it from a function, null is almost always the best option. To put it simply, JavaScript uses undefined and programmers should use null."
See Exploring the Eternal Abyss of Null and Undefined
In javascript all variables are stored as key value pairs. Each variable is stored as variable_name : variable_value/reference.
undefined means a variable has been given a space in memory, but no value is assigned to it. As a best practice, you should not use this type as an assignment.
In that case how to denote when you want a variable to be without value at a later point in the code? You can use the type
null ,which is also a type that is used to define the same thing, absence of a value, but it is not the same as undefined, as in this case you actually have the value in memory. That value is null
Both are similar but usage and meaning are different.
The difference in meaning between undefined and null is an accident of JavaScript’s design, and it doesn’t matter most of the time. In cases where you actually have to concern yourself with these values, I recommend treating them as mostly interchangeable.
From the Eloquent Javascript book
As typeof returns undefined, undefined is a type where as null is an initializer indicates the variable points to no object(virtually everything in Javascript is an object).
null - It is an assignment value, which is used with variable to represent no value (it's an object).
undefined - It is a variable which does not have any value assigned to it, so JavaScript will assign an undefined to it (it's a data type).
undeclared - If a variable is not created at all, it is known as undeclared.
Check this out. The output is worth thousand words.
var b1 = document.getElementById("b1");
checkif("1, no argument" );
checkif("2, undefined explicitly", undefined);
checkif("3, null explicitly", null);
checkif("4, the 0", 0);
checkif("5, empty string", '');
checkif("6, string", "string");
checkif("7, number", 123456);
function checkif (a1, a2) {
print("\ncheckif(), " + a1 + ":");
if (a2 == undefined) {
print("==undefined: YES");
} else {
print("==undefined: NO");
}
if (a2 === undefined) {
print("===undefined: YES");
} else {
print("===undefined: NO");
}
if (a2 == null) {
print("==null: YES");
} else {
print("==null: NO");
}
if (a2 === null) {
print("===null: YES");
} else {
print("===null: NO");
}
if (a2 == '') {
print("=='': YES");
} else {
print("=='': NO");
}
if (a2 === '') {
print("==='': YES");
} else {
print("==='': NO");
}
if (isNaN(a2)) {
print("isNaN(): YES");
} else {
print("isNaN(): NO");
}
if (a2) {
print("if-?: YES");
} else {
print("if-?: NO");
}
print("typeof(): " + typeof(a2));
}
function print(v) {
b1.innerHTML += v + "\n";
}
<!DOCTYPE html>
<html>
<body>
<pre id="b1"></pre>
</body>
</html>
See also:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/undefined
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/NaN
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/null
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Comparison_Operators
Cheers!
The difference between undefined and null is minimal, but there is a difference. A variable whose value is undefined has never been initialized. A variable whose value is null was explicitly given a value of null, which means that the variable was explicitly set to have no value. If you compare undefined and null by using the null==undefined expression, they will be equal.
Basically, Undefined is a global variable that javascript create at the run time whether null means that no value has assigned to the variable (actually null is itself an object).
Let's take an example:
var x; //we declared a variable x, but no value has been assigned to it.
document.write(x) //let's print the variable x
Undefined that's what you will get as output.
Now,
x=5;
y=null;
z=x+y;
and you will get 5 as output. That's the main difference between the Undefined and null
Both special values imply an empty state.
The main difference is that undefined represents the value of a variable that wasn’t yet initialized, while null represents an intentional absence of an object.
The variable number is defined, however, is not assigned with an initial value:
let number;
number; // => undefined
number variable is undefined, which clearly indicates an uninitialized variable
The same uninitialized concept happens when a non-existing object property is accessed:
const obj = { firstName: 'Dmitri' };
obj.lastName; // => undefined
Because lastName property does not exist in obj, JavaScript correctly evaluates obj.lastName to undefined.
In other cases, you know that a variable expects to hold an object or a function to return an object. But for some reason, you can’t instantiate the object. In such a case null is a meaningful indicator of a missing object.
For example, clone() is a function that clones a plain JavaScript object. The function is expected to return an object:
function clone(obj) {
if (typeof obj === 'object' && obj !== null) {
return Object.assign({}, obj);
}
return null;
}
clone({name: 'John'}); // => {name: 'John'}
clone(15); // => null
clone(null); // => null
However, clone() might be invoked with a non-object argument: 15 or null (or generally a primitive value, null or undefined). In such case, the function cannot create a clone, so it returns null - the indicator of a missing object.
typeof operator makes the distinction between the two values:
typeof undefined; // => 'undefined'
typeof null; // => 'object'
The strict quality operator === correctly differentiates undefined from null:
let nothing = undefined;
let missingObject = null;
nothing === missingObject; // => false

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