Here's a link i saw but still confused over the answers provided for them : jQuery Ajax returns the whole page
My situation is something similar.
I have a index.php that calls for a popup login form, that tries to submit this login information to a ajax call to another php called login_check.php.
This is my index.php :
var dataString = 'email='+ email.val() + '&password=' + password.val();
$.ajax({
type: "POST",
url: "login_check.php",
data: dataString,
cache: false,
error: function (request, status, error) {
alert("An error occured while trying to complete your request: " + error);
},
success: function(data)
{
alert(data);
}
});
This is what is in my login_check.php :
session_start();
//input from login form
$myemail = htmlspecialchars(trim($_POST['email']));
$mypassword = htmlspecialchars(trim($_POST['password']));
//selecting from database to check user account
$sql="SELECT * FROM user WHERE email='$myemail' and password='$mypassword'";
$result=mysql_query($sql);
$row=mysql_fetch_array($result);
$count=mysql_num_rows($result);
//If result matched $myemail and $mypassword, table row must be 1 row
if($count==1)
{
echo 'true';
session_register("myemail");
$_SESSION['login_user']=$myemail;
}
else if($count==0)
{
echo 'false';
}
And the output of the alert box is the full html of the page i am currently in, i.e. index.php.
And i have no idea whyy. ):
Same happen here, I figured it out it has a conflict with other plugin, deactivate your plugin and it should works.
Hope it helps on other looking for this solution.
You might also want to try this syntax of making an Ajax POST request.
$.post('login_check.php',{'email':email.val(),'password':password.val()},function(response){
alert(response);
},"json");
No clue whether this solves your problem, but it's always a good idea to encode the data:
var dataString = encodeURIComponent('email='+ email.val() + '&password=' + password.val());
Maybe this solves your problem, too...
Related
I have used before these jquery-ajax and php codes. Everything was fine but know there is a problem that success function not working. However, php codes are working, I can add data to mysql database, but I couldn't post info back to javascript file again by use "echo" or any way. Is this problem could originate because of server? I need your support.
I have checked php file is working or not and there was no problem about php. In javascript file in ajax codes, I have tried beforeSend and complete functions, everything were fine. But success function not working.
JS codes:
var userCookie = 1;
var question_txt = document.getElementById("question_txt").value;
var category_slct = document.getElementById("category_slct").value;
$.ajax({
type: "POST",
url: websitePHP + "ask.php",
data: {
user : userCookie,
quest : question_txt,
cat : category_slct
},
beforeSend: function(){
},
success: function(data){
alert(data);
if(data == 'ok'){
alert('Question added');
}
}
})
PHP codes:
include("ayar.php");
$userID = $_POST['user'];
$categoryID = $_POST['cat'];
$question_txt = $_POST['quest'];
$askedTime = time();
$addQuestion = $vt->prepare("INSERT INTO ".$QUESTIONS." (userID, categoryID, question, image, link, sight, pinned, bestAnswerID, askedTime, publishedTime, published)
VALUES (?,?,?,?,?,?,?,?,?,?,?)");
$addQuestion->execute(array(''.$userID.'',''.$categoryID.'', ''.$question_txt.'', '', '', 0, 0, '', ''.$askedTime.'', '', 0));
echo 'ok';
exit();
I need to get back response from php to js by success function in ajax.
Thanks for your help,
Best regards.
Can you try
return 'ok'; instead of echo 'ok'; and removing exit(); function
I am building my best attempt at a twitter clone and have run into a bit of a problem. I want to be able to click on a post and, without a page refresh, display that post in the overlay of the page (as you would on a twitter feed to look at replies, etc.).
In script.js, I check for a click and try to change the url.
$('body').on("click", ".chirp", function(){
var uid = $_GET['id'];
var pid = $(this).attr("id");
var pidSplit = pid.split("chirp");
var messageID = pidSplit[1];
var obj = {foo: "status"};
$('.chirpOverlay').addClass("active");
window.history.pushState(obj, "Status", "profile.php?id="+uid+"&status="+pid);
});
The javascript works as intended...but as I will soon find out, the victory is short-lived.
In profile.php, I attempt to GET the status id from the URL parameter.
<?php
$status_id = $_GET['status'];
$sql = $db->query("SELECT * FROM chirps WHERE id='$status_id'");
if (mysqli_num_rows($sql) > 0) {
$c = $sql->fetch_object();
}
?>
This doesn't work because, as I've learned, using 'window.history.pushState' only changes the url- but doesn't load the page. Thus the $_GET statement fails. I need a way to get the id of the post I click on into profile.php without a page refresh. Even if it means taking a different approach (instead of using a URL parameter).
PS: I tried to do an XMLHttpRequest as well- to no avail. :(
Thanks in advance!
$('body').on("click", ".chirp", function(){
var uid = $_GET['id'];
var pid = $(this).attr("id");
var pidSplit = pid.split("chirp");
var messageID = pidSplit[1];
var obj = {foo: "status"};
$('.chirpOverlay').addClass("active");
$.ajax({
url: "profile.php?id="+uid+"&status="+pid,
type: "GET",
data: obj,
dataType: "html",
success: function(data){
console.log(data);
}
});
});
You need to just get something up and going that works and then you can add more to it as you figure things out. This should give you a good starting place.
Here are your two files. Make sure they are both in the same directory.
You will need to make sure you have a jquery version loaded. Put this on whatever page you are calling the script.js from.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
script.js
$(document).ready(function(){
$('body').click(function(){
var id; //define your id.
var pid; //define your pid.
var datastring = 'id=' + uid + '&status=' + pid;
console.log(datastring);
$.ajax({
url: 'profile.php',
type: 'POST',
cache: false,
data: datastring,
dataType: 'json',
success: function(data){
console.log('Made it to the success function: ' + data);
if (data) {
//It works, do something.
console.log(data);
} else{
//It does not work, do something.
console.log('Your ajax failed to get the info from your php page. Keep troubleshooting');
}
}
});
});
});
profile.php
<?php
/*
$status_id = $_POST['status']; //This needs to be sanitized and validated.
$sql = $db->query("SELECT * FROM chirps WHERE id='$status_id'"); //This is unsafe sql practice.
if (mysqli_num_rows($sql) > 0) {
$c = $sql->fetch_object();
}
echo json_encode($c); //This is what gets sent back to script.js
*/
echo 'You made it to your php page.';
?>
A few things:
You can not call any php variable from within your js. var uid = $_GET['id']; does not work.
Any value that you pass to the php page needs to be validated to make sure it is a legitimate value.
Your SQL query is prone to sql injections. Please read up on how to parameterize your queries. Good Mysqli Practices
I have finally found a AJAX-based solution to my problem.
I created a new php file called "chirp_open_ref.php" and added this ajax to script.js:
var datastring = 'status=' + messageID;
$.ajax({
url: "chirp_open_ref.php",
type: "POST",
data: datastring,
cache: false,
dataType: "text",
success: function(data){
$('.chirp-container').html(data);
}
});
Inside of 'chirp_open_ref.php':
<?php
require 'core.inc.php';
if (isset($_POST['status']) && isset($_SESSION['user_id'])){
$chirp_id = $_POST['status'];
$c = "";
$sql = $db->query("SELECT * FROM chirps WHERE id='$chirp_id'");
if (mysqli_num_rows($sql) > 0){
$c = $sql->fetch_object();
}
include'chirp.inc.php';
}
?>
'chirp.inc.php' is simply a template for the layout/structure of each post.
This works like a charm, but I am always open to any criticism of how I am performing this. Thanks for all the help guys!
I have a page where users can put comments below photos, everything works fine in php, comments go to the database and displayed below the photo.
Now I'm trying to make it work with ajax but I have some troubles.
I have an javascript document with this:
$(document).ready(function(){
$("#btnSubmit").on("click", function(e){
var update = $("#activitymessage").val()
$.ajax({
method: "POST",
url: "./ajax/save_comment.php",
//data: { update: update}, - first version, not correct
data: { activitymessage: update},
datatype: 'json'
})
.done(function(response) {
console.log("ajax done");
console.log (response.message);
var ht = "<li>" + update + "</li>";
$("#listupdates").append(ht);
});
e.preventDefault();
});
});
The php page (save_comment.php) where I tell what to do with the input text:
<?php
spl_autoload_register(function ($class) {
include_once("../classes/" . $class . ".class.php");
});
$activity = new Comment();
if (!empty($_POST['activitymessage'])) {
$activity->Text = $_POST['activitymessage'];
try {
//$activity->idPost = $_GET['nr'];
//$activity->idUser = $_SESSION['user_id'];
// with this it works, but not yet correct
$activity->idPost = 66;
$activity->idUser = 3;
$activity->SavePost();
$response['status'] = 'succes';
$response['message'] = 'Update succesvol';
} catch (Exception $e) {
$error = $e->getMessage();
$response['status'] = "error";
$response['message'] = $feedback;
}
header('Content-type: application/json');
echo json_encode($response);
}
There is also the file Comment.class.php with the 'Comment' class and the function SavePost(). This works without ajax, so I assume the function is correct.
What works
the comment (var update) is printed on the screen into the list.
The console says : "ajax done"
What don't work
The input text don't insert into the database (and disappears when page refresh)
The console says: "undefined" (there must be something wrong with the 'response I use in this function)
I hope you guys can help me out. Thanx
update
I changed the: data: { activitymessage: update} line in the js file, and set manually values for the $activity->idPost = 66; $activity->idUser = 3; And everything works !
Only one thing I want to get fixed
the values of the $_GET['nr'] and $_SESSION['user_id'] are now set manually. Is this possible to get these automatic?
The $_GET['nr'] is the id of the page were the photo is and the comments. In this way I can make a query that returns all comments for this page.
The $_SESSION['user_id'] is the id of the user,so I can echo the username and profile photo.
You are sending data with the key being update not activitymessage
Change data to:
data: { activitymessage: update}
Or change $_POST['activitymessage'] to $_POST['update']
Also you have no $_GET['nr'] in url used for ajax. Nothing shown would help us sort that out but you would need the url to look more like:
url: "./ajax/save_comment.php?nr=" + nrSourceValue,
Not sure why you need to use $_GET['nr'] and don't use $_POST for that also and and nr property to data object being sent
I am trying to get the contents from some autogenerated divs (with php) and put the contents in a php file for further processing. The reason for that is I have counters that count the number of clicks in each div. Now, I ran into a problem. When I echo back the data from the php file, the call is made, but I get undefined in the form-data section of the headers, and NULL if I do var_dump($_POST). I am almost certain I am doing something wrong with the AJAX call. I am inexperienced to say the least in AJAX or Javascript. Any ideas? The code is pasted below. Thanks for any help / ideas.
The AJAX:
$(document).ready(function(e) {
$("form[ajax=true]").submit(function(e) {
e.preventDefault();
var form_data = $(this).find(".test");
var form_url = $(this).attr("action");
var form_method = $(this).attr("method").toUpperCase();
$.ajax({
url: form_url,
type: form_method,
data: form_data,
cache: false,
success: function(returnhtml){
$("#resultcart").html(returnhtml);
}
});
});
});
The PHP is a simple echo. Please advise.
Suppose you have a div
<div id="send_me">
<div class="sub-item">Hello, please send me via ajax</div>
<span class="sub-item">Hello, please send me also via ajax</span>
</div>
Make AJAX request like
$.ajax({
url: 'get_sorted_content.php',
type: 'POST', // GET is default
data: {
yourData: $('#send_me').html()
// in PHP, use $_POST['yourData']
},
success: function(msg) {
alert('Data returned from PHP: ' + msg);
},
error: function(msg) {
alert('AJAX request failed!' + msg);
}
});
Now in PHP, you can access this data passed in the following manner
<?php
// get_sorted_content.php
if(!empty($_POST['yourdata']))
echo 'data received!';
else
echo 'no data received!';
?>
It's sorted. Thanks to everyone. The problem was I didn't respect the pattern parent -> child of the divs. All I needed to do was to wrap everything in another div. I really didn't know this was happening because I was echoing HTML code from PHP.
I have a modal that will display when the user clicks a delete button. Once they hit the delete button I am using AJAX to subimit the form. Eveything works fine, but it is not display my success message which is set in PHP.
Here is my AJAX code:
function deleteUser(){
var id = <?php echo $userdetails['id'] ?>;
$.ajax({
type: "POST",
url: 'admin_user.php?id=' + id,
data: $('form.adminUser').serialize(),
error: function(e){
alert(e);
},
success: function () {
// This is empty because i don't know what to put here.
}
});
}
Here is the PHP code:
if ($deletion_count = deleteUsers($deletions)) {
$successes[] = lang("ACCOUNT_DELETIONS_SUCCESSFUL", array($deletion_count));
} else {
$errors[] = lang("SQL_ERROR");
}
And then I call it like this:
<div class="col-lg-12" id="resultBlock">
<?php echo resultBlock($errors,$successes); ?>
</div>
When I use AJAX it does not display the message. This works fine on other pages that does not require AJAX to submit the form.
I think you are getting confused with how AJAX works, the PHP script you call will not directly output to the page, consider the below simplified lifecycle of an AJAX request:
Main Page -> Submit Form -> Put form data into array
|
--> Send array to a script to be processed on the server
|
|----> Callback from the server script to modify DOM (or whatever you want to do)
There are many callbacks, but here lets discuss success and error
If your PHP script was not found on the server or there was any other internal error, an error callback is returned, else a success callback is fired, in jQuery you can specify a data array to be received in your callback - this contains any data echoed from your PHP script.
In your case, you should amend your PHP file to echo your arrays, this means that if a successful request is made, the $successes or $errors array is echoed back to the data parameter of your AJAX call
if ($deletion_count = deleteUsers($deletions)) {
$successes[] = lang("ACCOUNT_DELETIONS_SUCCESSFUL", array($deletion_count));
echo $successes;
} else {
$errors[] = lang("SQL_ERROR");
echo $errors;
}
You can then test you received an object by logging it to the console:
success: function(data) {
console.log(data);
}
Well, it's quite not clear what does work and what does not work, but two things are bothering me : the function for success in Ajax is empty and you have a header function making a refresh in case of success. Have you tried removing the header function ?
success: function(data) {
alert(data);
}
In case of success this would alert the data that is echoed on the php page. That's how it works.
I'm using this a lot when I'm using $.post
Your header will not do anything. You'll have to show the data on the Java script side, maybe with alert, and then afterwards redirect the user to where you want in javascript.
you need put some var in success function
success: function(data) {
alert(data);
}
then, when you read var "data" u can do anything with the text
Here is what I changed the PHP to:
if ($deletion_count = deleteUsers($deletions)) {
$successes[] = lang("ACCOUNT_DELETIONS_SUCCESSFUL", array($deletion_count));
echo resultBlock($errors,$successes);
} else {
$errors[] = lang("SQL_ERROR");
echo resultBlock($errors,$successes);
}
And the I changed the AJAX to this:
function deleteUser(){
var id = <?php echo $userdetails['id'] ?>;
$.ajax({
type: "POST",
url: 'admin_user.php?id=' + id,
data: $('form.adminUser').serialize(),
error: function(e){
alert(e);
},
success: function (data) {
result = $(data).find("#success");
$('#resultBlock').html(result);
}
});
}
Because data was loading all html I had to find exactly what I was looking for out of the HTMl so that is why I did .find.