How To Create This RegExp - javascript

I am looking to find this in a string: XXXX-XXX-XXX Where the X is any number.
I need to find this in a string using JavaScript so bonus points to those who can provide me the JavaScript too. I tried to create a regex and came out with this: ^[0-9]{4}\-[0-9]{3}\-[0-9]{3}$
Also, I would love to know of any cheat sheets or programs you guys use to create your regular expressions.

i suppose this is what you want:
\d{4}-\d{3}-\d{3}
in doubt? Google for "RegEx Testers"

With your attempt:
^[0-9]{4}\-[0-9]{3}\-[0-9]{3}$
Since the - is not a metacharacter, there is no need to escape it -- thus you are looking for explicit backslash characters.
Also, you've anchored the match at the beginning and end of the string -- this will match only strings that consist only of your number. (Well, assuming the rest were correct.)
I know most people like the {3} style of counting, but when the thing being matched is a single digit, I find this more legible:
\d\d\d\d-\d\d\d-\d\d\d
Obviously if you wanted to extend this to matching hexadecimal digits, extending this one would be horrible, but I think this is far more legible than alternatives:
\d{4}-\d{3}-\d{3}
[[:digit:]]{4}-[[:digit:]]{3}-[[:digit:]]{3}
[0-9]{4}-[0-9]{3}-[0-9]{3}
Go with whatever is easiest for you to read.
I tend to use the perlre(1) manpage as my main reference, knowing full well that it is far more featureful than many regexp engines. I'm prepared to handle the differences considering how conveniently available the perlre manpage is on most systems.

var result = (/\d{4}\-\d{3}\-\d{3}/).exec(myString);

Related

Searching all emails over large document [duplicate]

I've seen regex patterns that use explicitly numbered repetition instead of ?, * and +, i.e.:
Explicit Shorthand
(something){0,1} (something)?
(something){1} (something)
(something){0,} (something)*
(something){1,} (something)+
The questions are:
Are these two forms identical? What if you add possessive/reluctant modifiers?
If they are identical, which one is more idiomatic? More readable? Simply "better"?
To my knowledge they are identical. I think there maybe a few engines out there that don't support the numbered syntax but I'm not sure which. I vaguely recall a question on SO a few days ago where explicit notation wouldn't work in Notepad++.
The only time I would use explicitly numbered repetition is when the repetition is greater than 1:
Exactly two: {2}
Two or more: {2,}
Two to four: {2,4}
I tend to prefer these especially when the repeated pattern is more than a few characters. If you have to match 3 numbers, some people like to write: \d\d\d but I would rather write \d{3} since it emphasizes the number of repetitions involved. Furthermore, down the road if that number ever needs to change, I only need to change {3} to {n} and not re-parse the regex in my head or worry about messing it up; it requires less mental effort.
If that criteria isn't met, I prefer the shorthand. Using the "explicit" notation quickly clutters up the pattern and makes it hard to read. I've worked on a project where some developers didn't know regex too well (it's not exactly everyone's favorite topic) and I saw a lot of {1} and {0,1} occurrences. A few people would ask me to code review their pattern and that's when I would suggest changing those occurrences to shorthand notation and save space and, IMO, improve readability.
I can see how, if you have a regex that does a lot of bounded repetition, you might want to use the {n,m} form consistently for readability's sake. For example:
/^
abc{2,5}
xyz{0,1}
foo{3,12}
bar{1,}
$/x
But I can't recall ever seeing such a case in real life. When I see {0,1}, {0,} or {1,} being used in a question, it's virtually always being done out of ignorance. And in the process of answering such a question, we should also suggest that they use the ?, * or + instead.
And of course, {1} is pure clutter. Some people seem to have a vague notion that it means "one and only one"--after all, it must mean something, right? Why would such a pathologically terse language support a construct that takes up a whole three characters and does nothing at all? Its only legitimate use that I know of is to isolate a backreference that's followed by a literal digit (e.g. \1{1}0), but there are other ways to do that.
They're all identical unless you're using an exceptional regex engine. However, not all regex engines support numbered repetition, ? or +.
If all of them are available, I'd use characters rather than numbers, simply because it's more intuitive for me.
They're equivalent (and you'll find out if they're available by testing your context.)
The problem I'd anticipate is when you may not be the only person ever needing to work with your code.
Regexes are difficult enough for most people. Anytime someone uses an unusual syntax, the question
arises: "Why didn't they do it the standard way? What were they thinking that I'm missing?"

Comma-separated list of integers with max 5 elements [duplicate]

I've seen regex patterns that use explicitly numbered repetition instead of ?, * and +, i.e.:
Explicit Shorthand
(something){0,1} (something)?
(something){1} (something)
(something){0,} (something)*
(something){1,} (something)+
The questions are:
Are these two forms identical? What if you add possessive/reluctant modifiers?
If they are identical, which one is more idiomatic? More readable? Simply "better"?
To my knowledge they are identical. I think there maybe a few engines out there that don't support the numbered syntax but I'm not sure which. I vaguely recall a question on SO a few days ago where explicit notation wouldn't work in Notepad++.
The only time I would use explicitly numbered repetition is when the repetition is greater than 1:
Exactly two: {2}
Two or more: {2,}
Two to four: {2,4}
I tend to prefer these especially when the repeated pattern is more than a few characters. If you have to match 3 numbers, some people like to write: \d\d\d but I would rather write \d{3} since it emphasizes the number of repetitions involved. Furthermore, down the road if that number ever needs to change, I only need to change {3} to {n} and not re-parse the regex in my head or worry about messing it up; it requires less mental effort.
If that criteria isn't met, I prefer the shorthand. Using the "explicit" notation quickly clutters up the pattern and makes it hard to read. I've worked on a project where some developers didn't know regex too well (it's not exactly everyone's favorite topic) and I saw a lot of {1} and {0,1} occurrences. A few people would ask me to code review their pattern and that's when I would suggest changing those occurrences to shorthand notation and save space and, IMO, improve readability.
I can see how, if you have a regex that does a lot of bounded repetition, you might want to use the {n,m} form consistently for readability's sake. For example:
/^
abc{2,5}
xyz{0,1}
foo{3,12}
bar{1,}
$/x
But I can't recall ever seeing such a case in real life. When I see {0,1}, {0,} or {1,} being used in a question, it's virtually always being done out of ignorance. And in the process of answering such a question, we should also suggest that they use the ?, * or + instead.
And of course, {1} is pure clutter. Some people seem to have a vague notion that it means "one and only one"--after all, it must mean something, right? Why would such a pathologically terse language support a construct that takes up a whole three characters and does nothing at all? Its only legitimate use that I know of is to isolate a backreference that's followed by a literal digit (e.g. \1{1}0), but there are other ways to do that.
They're all identical unless you're using an exceptional regex engine. However, not all regex engines support numbered repetition, ? or +.
If all of them are available, I'd use characters rather than numbers, simply because it's more intuitive for me.
They're equivalent (and you'll find out if they're available by testing your context.)
The problem I'd anticipate is when you may not be the only person ever needing to work with your code.
Regexes are difficult enough for most people. Anytime someone uses an unusual syntax, the question
arises: "Why didn't they do it the standard way? What were they thinking that I'm missing?"

Validate field for all language characters through REGEX

i need to validate a field for empty. But it should allow English and the Foreign languages characters(UTF-8) but not the special characters. I'm not good at Regex. So any help on this would be great...
If you want to support a wide range of languages, you'll have to work by excluding only the characters you don't want, since specifying all of the ranges you do want will be difficult.
You'll need to look at the list of Unicode blocks and or the character database to identify the blocks you want to exclude (like, for instance, U+0000 through U+001F. This Wikipedia article may also help.
Then use a regular expression with character classes to look for what you want to exclude.
For example, this will check for the U+0000 through U+001F and the U+007F characters (obviously you'll be excluding more than just these):
if (/[\u0000-\u001F\u007F]/.exec(theString)) {
// Contains at least one invalid character
}
The [] identify a "character class" (list and/or range of characters to look for). That particular one says look for \u0000 through \u001F (inclusive) as well as \u007F.
It would have been nice if I could say "Just do /^\w+$/.test(word)", but...
See this answer for the current state of unicode support (or rather lack of) in JavaScript regular expressions.
You can either use the library he suggests, which might be slow or enlist the help of the server for this (which might be slower).
You can test for a unicode letter like this:
str.match(/\p{L}/u)
Or for the existence of a non-letter like this:
str.match(/[^\p{L}]/u)

is there any way to get all the possible outcomes of a regular expression pattern?

is there any way to get all the possible outcomes of a regular expression pattern?. everything I've seen refers to a pattern that is evaluated against a string. but what I need is to have a pattern like this:
^EM1650S(B{1,2}|L{1,2})?$
generate all possible matches:
EM1650S
EM1650SB
EM1650SBB
EM1650SL
EM1650SLL
In the general case, no. In this case, you have almost no solution space.
There's a section covering this in Higher Order Perl (PDF) and a Perl module. I never re-implemented it in anything else, but I had a similar problem and this solution was adequate for similarly-limited needs.
There are tools that can display all possible matches of a regex.
Here is one written in Haskell: https://github.com/audreyt/regex-genex
and here is a Perl module: http://metacpan.org/pod/Regexp::Genex
Unfortunately I couldn't find anything for JavaScript
In this particular case, yes. The regex generates a finite number of valid string, so they can be counted up.
You'll just have to parse the regex. Some part of that (EM1650S) is mandatory, so think for the rest. Parse by the | (or) symbol. Then enumerate the strings for both sides of it. Then you can get all possible combinations of them.
Some regex (containing * or + symbols) can represent an infinite number of strings, so they cannot be counted.
From a computational theoretic standpoint, regular expressions are equivalent to finite state machines. This is part of "automata theory." You could create a finite state machine that is equivalent to a regular expression and then use graph traversal algorithms to traverse all paths of the FSM. In the general case a countably infinite number of strings may match a regular expression, so your program may never terminate depending on the input regular expression.

Wipe a string but keep its middle part

With a string like "HorsieDoggieBirdie", is there a non-capturing regex replace that would kill "Horsie" and "Birdie", yet keep "Doggie" intact? I can only think of a capturing solution:
s/(Horsie)(Doggie)(Birdie)/$2/g
Is there a non-capturing solution like:
s/Horsie##Doggie##Birdie//g
where ## is some combination of regex codes? The specific problem is in JavaScript (innerHTML.replace) but I'll take Perl suggestions, too.
You don't have to capture the Horsie or the Birdie.
s/Horsie(Doggie)Birdie/$1/g;
A similar thing should work for Javascript as well. This is probably as efficient as it gets, and at least as fast as using look-around assertions; although you should benchmark it if you want to know for sure. (The results, of course, will depend on the horsies, doggies and birdies in question.)
Mandatory disclaimer: you should know what happens when you use regular expressions with HTML...
You can use Look-Around Assertions:
s/(?:Horsie(?=Doggie))|(?:(?<=Doggie)Birdie)//g;

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