I want to design form with many fields. Some fields are dependent on the first drop-down list.
How to design to show only those that are needed?
You should hide those that you might not be needed in CSS.
Then, you should create some javascript to show/hide fields depending on the value of the select. Example with jQuery:
$('select[name=yourselect]').change(function() {
switch($(this).val()) {
case 'someval':
$('input[name=somefield]').show();
$('input[name=someotherfield]').hide();
break;
// add as many cases as you want, one for each value
}
})
// this is useful when your select has an initial value,
// to show/hide the fields depending on the initially selected option
$('select[name=yourselect]').trigger('change');
You can also make server side checks with your form clean() method.
If you want to make a dynamic form in multiple steps in which second form depends on first forms values then you can use Django Form Wizard. This is good if you don't want to use jquery. In this way you can also apply customized clean function for individual forms.
Check the form wizard documentation. I hope this will be useful for you.
Related
I'm building a simple asp page on which I have list of peoples with checkbox on left of every name.
I've managed to create a simple jQuery script that allows hiding and showing rows of table based on input:
http://jsfiddle.net/Tq97v/ (first part)
As You can see I can enter part of name and then specific row are hidden.
Using red "x" I can uncheck all checkboxes.
What I'm trying to do now is to change that static red "x" into tristate checkbox.
Don't have idea how to even start.
Do I must add change listener to every checkbox in my list?
Second thing - how to create multiple instances of the same "plugin" on site.
Right now I'm identifying input by it, but it would be nice to call function with that input as param, and it would fine table after that input and create necessary logic.
This way I could call function multiple times on page to have more than one list.
I'm not asking for whole solution (of course it is always welcome :) ) but what I need is idea how to accomplish this in efficient way and as optimized as possible, because sometimes my list has 500+ elements.
P.S. don't look at HTML code, it is ASP generated.
I found this plugin: https://github.com/bcollins/jquery.tristate, but I have no idea how to use it with my list.
UPDATE:
I've managed to turn my code into functions, but right now I must call 3 functions for every list.
Here is my updated code: http://jsfiddle.net/65MEV/4/
How can I change it to one function? Will it be better?
This is my updated code. Still thinking about way of doing that Indeterminate Checkbox instead of my remove image.
UPDATE2
I build working code :)
http://jsfiddle.net/65MEV/9/
But I would like to improve it as much as possible.
Any suggestions are welcome!
A tristate checkbox is like the Three-Portal Device: an illusion.
What you actually want is to make the checkbox indeterminate (by setting the property of the same name to true). To implement this, you will need a change (or click) handler on each checkbox, then you'll need to check if all of them are in the same state, and if not then you set the indeterminate property. It's a hassle, really, because you rarely see indeterminate checkboxes and so most users don't know what to do with them. To be avoided, if possible.
To create multiple instances of the same plugin access elements relatively to an other element.
For example: in your case instead of keeping the item in a jQuery object var $tableRows = $('table.myList tr'); access them in the event.
$('#user_name').keyup(function () {
var sValue = $.trim($('input#user_name').val());
if(lastInput==sValue) return;
var $tableRows = $(this).next().next().find("table.myList tr");
if (sValue == '') {
$tableRows.show();
} else {
$tableRows.each(function () {
var oLabel = $(this).find('label');
if (oLabel.length > 0) {
if (oLabel.text().toLowerCase().indexOf(sValue.toLowerCase()) >= 0) {
$(this).show();
} else {
$(this).hide();
}
}
});
lastInput=sValue;
}
});
and you only have your actual list.
And for the tree state checkbox you don t need a plugin just add a button or link and every click check it status you can keep the status by jQuery data and change the element image according to this data.
I have a weird situation (don't we all?) with datepickers and want to get some advice.
I have a screen with a list of Locations, and for each Location, they can click Edit and edit that location. The Edit displays below the Edit link, and they can edit multiple locations at one time. This means the same View is rendered on the screen multiple times, and therefore multiple fields will exist with the same id (editing 4 locations will result in 4 "DateOpened" fields).
So, when I load my View, javascript adds datepickers to any fields that need it like so:
$(document).ready(function () {
var elements = $(".NeedsDatePicker > td > input");
$(".NeedsDatePicker > td > input").datepicker();
$(".NeedsDatePicker").removeClass("NeedsDatePicker");
});
Works fine, but, as you've probably already figured out, when I click a date on the calender, it populates the first "DateOpened" field when multiple Edit windows are open.
Is there a way to tell the datepicker to use the field WITHIN a certain parent, like you can for general jQuery selects?
$("#DateOpened", "Location-134").doWhatever...
...or is there a way to give the fields different id's without breaking MVC's UpdateModel() function? Or any other advice?
You should definitely keep IDs unique within an HTML DOM. Most, if not all, DOM manipulation libraries/frameworks, including jQuery, have this assumption built-in.
There are a few questions on SO WRT to avoid the same IDs in the form:
two forms with same input id in asp.net mvc
how to prevent html input id duplication on asp.net mvc 3 when a model contains multiple elements
Just wondering if there is a system out there that will basically allow for the following :
Displaying a grid of hours in a week that a user can click on to select and reclick to deselect and when the form is submitted it will send the blocks off to MySQL to store.
Since I havent done this before Im not sure on the best course of action, intial thoughts were to load up a pixel.gif and use onclick to tally clicks but before I reinvent the wheel as a square I thought it best to ask questions first to save trouble later.
You could create a table where the checked td's have one class and the unchecked td's have another class, and all of them have a unique ID. Then set the onclick action for each of the two classes to send the id of the td as an argument to a javascript function that uses ajax to update the database and changes the class of the td to selected or unselected.
The html would look like:
<td id='19_09_2011_12am' class='unselected_td'/></td>
<td id='19_09_2011_12am' class='selected_td'/></td>
The css would look like:
.unselected_td{background-color:blue;}
.selected_td{background-color:yellow;}
And the javascript:
$('.unselected_td').click(function(){
var cell = this.id;
$.ajax({
type:'post',
url:'path/file.php',
data:"cell="+cell+"&checked=1",
success:function(){
$(this).removeClass('unselected_td').addClass('selected_td');
}
});
});
And vice-versa for the selected ones, sending a 0 to the server instead. I'm not 100% sure about the syntax I used in the jquery, but the idea of this should work
I think the easiest way to achieve this would be to use buttons or checkboxes to represent the dates/hours selected. Checkboxes would be the simplest, since they could just be set to a value of '1', and only the selected checkboxes would show up as $_POST variables when you submit the form.
Buttons could have more style applied to them, but you would have to use some javascript code to toggle the value and style of the button when it's clicked. This is very easy to do in jQuery.
I am trying to make a very simple dynamic form. I am using Rails 3.1 and formtastic. Basically, I want to change a couple of fields based on a radio button.
It would look something like..
What kind of a shape are you making?
(Radio Button with a choice of square or rectangle)
If square is selected one new field for size is displayed. If rectangle is selected two fields are displayed for size.
The table will actually have only one size column, so the model will munge the potentially two fields into one before the ultimately hit the database (i think, still working on this issue as well)
Anyway, it is my understanding that I would need to use javascript in order to change the form. I am pretty javascript illiterate and really don't understand how to use it with formtastic. Any pointers would help.
Thanks!
Yes, you should use js to do that. If you're new to js don't hesitate and learn jQuery, it's becoming sort of js standard for rails now.
To do what you want you should display both size fields in your view and show/hide second field depending on radio values. It can be something like that:
$(function() {
var $radios = $("input[name=radioName]");
var $size2 = $("#size_field_2");
function toggleSizeField() {
$size2.toggle($radios.filter(":checked").val() == 0);
}
$radios.click(toggleSizeField);
toggleSizeField();
});
I am new to JavaScript and jQuery, but have used HTML and CSS before. In any case, I appreciate the help. I have implemented the script discussed here http://net.tutsplus.com/tutorials/javascript-ajax/using-jquery-to-manipulate-and-filter-data/ for filtering data and the one discussed here http://www.dustindiaz.com/check-one-check-all-javascript/ for a check one to check all script. The problem is, when I filter the list of items and then use the check all box, it is checking even the JS items that are hidden from the user due to filtering. Does this make sense?
I have been trying to figure out how to edit the check all script so that only items with the "visible" class (as added to visible checkboxes with the filtering script) are checked with the checkAll button. The original script had:
var checks = document.getElementsByName('del[]');
I was trying to do something like this (it wasn't working, of course):
var visiblechecks = $('input:del[]:checked.visible');
among other things.
Thank you! Also, if you have a recommended resource, I would appreciate it.
var visiblechecks = $('input[name="del[]"]:checked:visible');
Your selector just needs a bit of refinement. Try:
$(".myCheckAllSelector").change(function () {
$("input[name='del[]']:visible").attr("checked", $(this).is(":checked"));
});
This should set the checked attribute of all currently visible checkboxes with the name del[] to the checked status of the check all box. You simply need to update the check all selector appropriately to target your master checkbox element.
You don't necessarily "need" to add a visible class as there is a :visible filter you can use to make that determination for you. However, just change your selector from input to input.visible if you still wish to use the class and remove the :visible filter..