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How to check if last day of month is on friday Javascript

I'm supposed to write a code for codewars to find out the number of times a month ends with a Friday within a range of years.
To start off, I did research and found out several solutions but I still couldn't figure out the results in the console.log.
The first solution is from this tutorial:
In this code, the solution is
let LastDay = new Date(1998, 5 + 1, 0).getDate();
I was able to get the date, but it wasn't clear which day the date falls upon.
Then I found another solution at w3schools. This solution also set the date to be the last day of this month:
var d = new Date();
d.setMonth(d.getMonth() +1, 0);
document.getElementById("demo").innerHTML = d;
However, it works if it displays it as innerHTML = Sat Nov 30 2019 00:57:09 GMT-0500 (Eastern Standard Time). However, when I tried to rewrite the code and console.log it like in this example:
let d = new Date();
let month = d.getMonth()+1;
let lastday = d.setMonth(month, 0);
console.log(lastday);
The result I got was 1575093343211. I don't understand how it displays those numbers instead of the dates I was expecting. I thought that if it does display the dates, starting with the day, I can convert the date to string or array and check if the first element is Friday and then add it to the counter in the code I'm writing. How do I get the code to display the way I want it to.

something like this will work...
function LastDayOfMonth(Year, Month) {
return new Date((new Date(Year, Month, 1)) - 1);
}
var d = LastDayOfMonth(new Date().getYear(), new Date().getMonth())
//var d = LastDayOfMonth(2009, 11)
var dayName = d.toString().split(' ')[0];
console.log(dayName)

The result I got was 1575093343211. I don't understand how it displays those numbers instead of the dates I was expecting
Because you console.log the output of the setMonth method, not the date object:
let lastday = d.setMonth(month, 0);
console.log(lastday);
According to the documentation, the setMonth method returns:
The number of milliseconds between 1 January 1970 00:00:00 UTC and the updated date.
Instead you should use that output to create a new instance of the date object:
let lastday = new Date(d.setMonth(month, 0));
console.log(lastday);

Algorithms to get the last day of the month are generally based on setting a date to day 0 of the following month, which ends up being the last day of the required month.
E.g. to get the last day for June, 2019 (noting that 6 is July, not June):
let endOfJune = new Date(2019, 6, 0):
Once you have the date, you can get the day where 0 is Sunday, 1 is Monday, etc. and 5 is Friday:
let endOfJuneDay = endOfJune.getDay();
The set* methods modify the Date they're called on and return the time value for the modified date. So you don't need to assign the result to anything:
let d = new Date();
let month = d.getMonth() + 1;
// Set date to the new month
d.setMonth(month, 0);
console.log(d);
So if you want to loop over the months for a range of years and get the number that end with a Friday (or any particular day), you might loop over the months something like:
/*
** #param {number} startYear - start year of range
** #param {number} endYear - end year of range
** #param {number} dat - day number, 0 = Sunday, 1 = Monday, etc.
** default is 0 (Sunday)
*/
function countEOMDay(startYear, endYear, day = 0) {
// startYear must be <= end year
if (startYear > endYear) return;
// Start on 31 Jan of start year
let start = new Date(startYear, 0, 31);
// End on 31 Dec of end year
let end = new Date(endYear, 11, 31);
let count = 0;
// Loop over months from start to end
while (start <= end) {
// Count matching days
if (start.getDay() == day) {
++count;
}
// Increment month to end of next month
start.setMonth(start.getMonth() + 2, 0);
}
return count;
}
console.log(countEOMDay(2019, 2019, 5)); // 1
console.log(countEOMDay(2018, 2019, 5)); // 3

You can use setMonth() method to set the month of a date object. The return value of setMonth() method is milliseconds between the date object and midnight January 1 1970. That's what you get from console.log(lastday);
Your return value,
1575093343211
is milliseconds between your date object (d) and midnight January 1 1970.
If you want to get the expected date, you have to console log your date object instead the lastday, as follows:
let d = new Date();
let month = d.getMonth()+1;
let lastday = d.setMonth(month, 0);
console.log(d);
output: Sat Nov 30 2019 00:02:47 GMT+0530 (India Standard Time)
This is an alternative solution I wrote to solve your problem. This will return the number of times a month ends with a Friday within a range of years. Hope this will help you :)
var days = [];
var count = 0;
function getLastFridaysCount(startYear, endYear) {
for (var year = startYear; year <= endYear; year++) {
days = [
31,
0 === year % 4 && 0 !== year % 100 || 0 === year % 400 ? 29 : 28,
31, 30, 31, 30, 31, 31, 30, 31, 30, 31
];
for (var month = 0; month <= 11; month++) {
var myDate = new Date();
myDate.setFullYear(year);
myDate.setMonth(month);
myDate.setDate(days[month]);
if(myDate.getDay() == 5)
{
count++;
}
}
}
return count;
}
console.log("count", getLastFridaysCount(2014, 2017));

this is the solution, in the code can find the comments "//" explaining of what happens in each iteration.
function lastDayIsFriday(initialYear, endYear) {
let count = 0;
//according to when the year ends starts the loop
if (endYear !== undefined) {
let start = new Date(initialYear, 0, 31);
let end = new Date(endYear, 11, 31);
while(start <= end) { //check if the start date is < or = to the end
//The getDay() method returns the day of the week (from 0 to 6) for the specified date.
if(start.getDay() === 5) { //if = to FriYAY!!!
count++; //count the day
}
start.setMonth(start.getMonth()+2, 0);// returns the month (from 0 to 11) .getMonth
} //& sets the month of a date object .setMonth
return count;
} else {
let start = new Date(initialYear, 0, 31);
console.log(start.toString());
for(let i = 0; i < 12; i++) {
if(start.getDay() === 5) {
count++;
}
start.setMonth(start.getMonth() + 2, 0);
// console.log(start.toString());
}
return count;
}
}

How to get the Week wise Start and End date in angularjs

Before I am using angularjs-DatePicker from this npm.
Here,I am able to select the date from the date picker.But now I have to fields as FromDate and ToDate which means the week StartDate and EndDate should show when any date pick in that week.
Ex: Like in Calender 01-08-2017 Start on Tue, So whenever Selects Any date from 01 to 05 then the two fields should show as FromDate as 01 and TODate as 06 and in the same whenever the user selects the 31-07-2017 the the Two fields should show as 30 and 31 of july.
I have an idea to achieve the ToDate from FromDate Calender control onchange event in DotNet as like below mentioned code
Convert.ToDouble(objstart.DayOfWeek)).ToString("dd-MM-yyyy")
But how to achieve this usecase in the angularjs.
Thanks

Ok, so what I'd do is to calculate different dates, and take the min/max depending on the start or end of the week.
Here:
//Use the date received, UTC to prevent timezone making dates shift
var pickedDate = new Date("08-03-2017UTC");
var startSunday = new Date(pickedDate);
startSunday.setDate(pickedDate.getDate() - pickedDate.getDay());
var startMonth = new Date(pickedDate);
startMonth.setDate(1);
var startDate = Math.max(startMonth,startSunday);
console.log("Start:" , new Date(startDate));
var endSaturday = new Date(pickedDate);
endSaturday.setDate(pickedDate.getDate() + (7-pickedDate.getDay()));
var endMonth = new Date(pickedDate);
endMonth.setMonth(pickedDate.getMonth()+1);//Add a month
endMonth.setDate(0);// to select last day of previous month.
var endDate = Math.min(endMonth,endSaturday);
console.log("End" , new Date(endDate));
The trick was to play with the dates, find all the possible start and end dates, then choose the right one with Math.min and Math.max which will compare the dates using their timestamp.

There is very good Library available in JavaScript to handle Date Manipulations.
https://github.com/datejs/Datejs
There is a method
Date.parse('next friday') // Returns the date of the next Friday.
Date.parse('last monday')
Using these method you can get the start and ending date of the week based on the current week.
I hope that it will help.

You can simply achieve this using the library moment. There are a lot of useful functions in this library.
var selectedDate = moment('Mon Aug 10 2017');
//If you want to get the ISO week format(Monday to Sunday)
var weekStart = selectedDate.clone().startOf('isoweek').format('MMM Do');
var weekEnd = selectedDate.clone().endOf('isoweek').format('MMM Do');
//If you want to get the Sunday to Saturday week format
var weekStart = selectedDate.clone().startOf('week').format('MMM Do');
var weekEnd = selectedDate.clone().endOf('week').format('MMM Do');

No need angular directive here, you could use the JavaScript extension which is below.
//get week from date
Date.prototype.getWeekNumber = function (weekstart) {
var target = new Date(this.valueOf());
// Set default for weekstart and clamp to useful range
if (weekstart === undefined) weekstart = 1;
weekstart %= 7;
// Replaced offset of (6) with (7 - weekstart)
var dayNr = (this.getDay() + 7 - weekstart) % 7;
target.setDate(target.getDate() - dayNr + 0);//0 means friday
var firstDay = target.valueOf();
target.setMonth(0, 1);
if (target.getDay() !== 4) {
target.setMonth(0, 1 + ((4 - target.getDay()) + 7) % 7);
}
return 1 + Math.ceil((firstDay - target) / 604800000);;
};
//get date rance of week
Date.prototype.getDateRangeOfWeek = function (weekNo, weekstart) {
var d1 = this;
var firstDayOfWeek = eval(d1.getDay() - weekstart);
d1.setDate(d1.getDate() - firstDayOfWeek);
var weekNoToday = d1.getWeekNumber(weekstart);
var weeksInTheFuture = eval(weekNo - weekNoToday);
var date1 = angular.copy(d1);
date1.setDate(date1.getDate() + eval(7 * weeksInTheFuture));
if (d1.getFullYear() === date1.getFullYear()) {
d1.setDate(d1.getDate() + eval(7 * weeksInTheFuture));
}
var rangeIsFrom = eval(d1.getMonth() + 1) + "/" + d1.getDate() + "/" + d1.getFullYear();
d1.setDate(d1.getDate() + 6);
var rangeIsTo = eval(d1.getMonth() + 1) + "/" + d1.getDate() + "/" + d1.getFullYear();
return { startDate: rangeIsFrom, endDate: rangeIsTo }
};
Your code can be look like this
var startdate = '01-08-2017'
var weekList = [];
var year = startdate.getFullYear();
var onejan = new Date(year, 0, 1);//first january is the first week of the year
var weekstart = onejan.getDay();
weekNumber = startdate.getWeekNumber(weekstart);
//generate week number
var wkNumber = weekNumber;
var weekDateRange = onejan.getDateRangeOfWeek(wkNumber, weekstart);
var wk = {
value: wkNumber
, text: 'Week' + wkNumber.toString()
, weekStartDate: new Date(weekDateRange.startDate)
, weekEndDate: new Date(weekDateRange.endDate)
};
weekList.push(wk);

I guess there is no directive or filter for this, you need to create one for yourself. you can refer date object from date-time-object

How to calculate number of day name between 2 dates in javascript

I have 2 datepickers and a list of checkboxes of week days. A user can select a start date or end date and check any checkbox day. I want to count the number of
week days between 2 days.
For example: I want to join any yoga classes then I will select start or end date and also select week day like Monday , Tuesday .
Now i want to count the number of all Mondays and Tuesdays between 2 dates
date1 = Mar 01,2016
date2 = Apr 01,2016
I want to count number of day name between these date like this:
no of sunday: 4
no of monday: 4
no of tuesday: 5 etc..
I have tried this code
var d = new Date(date1);
var now = new Date(Date.now());
var daysOfYear = [];
count = 0;
for (d ; d <= date1 ; d.setDate(d.getDate() + 1)) {
val = $("#ch_"+d.getDay());
if(val.is(':checked')){
count++;
}
}
But it gives a TypeError: d.getDay is not a function

You need to iterate between dates and check the day
First convert the dates into a date object
date1 = convertToDateObj(date1); //assuming you already have a way to parse this string to date
date2 = convertToDateObj(date2); //assuming you already have a way to parse this string to date
Now iterate throught them
var dayCount = {0:0,1:0,2:0,3:0,4:0,5:0,6:0}; //0 is sunday and 6 is saturday
for (var d = date1; d <= date2; d.setDate(d.getDate() + 1))
{
dayCount[d.getDay()]++;
}
console.log(dayCount);

Set the time range

I would be grateful for your help. How to set the range from 15 December to 15 January?
$(document).ready(function() {
var month = (new Date()).getMonth();
if (month < 2 || month === 11) {
$("#block").css("background-color", "#1D30C4");
}
else {
$("#block").css("background-color", "#C41D2C");
}
});

var block=$('#block');
var cd= new Date();
var startDate= new Date(cd.getFullYear(),11,15,0,0,0,0);
var endDate= new Date(cd.getFullYear()+1,0,15,0,0,0,0);
if(cd.getTime()>=startDate.getTime() && cd.getTime()<=endDate.getTime()){
$("#block").css("background-color", "#1D30C4");
}else{
$("#block").css("background-color", "#C41D2C");
}
please note that month in javascript starts with 0
here is jsbin link
https://jsbin.com/tafijucono/edit?html,css,js,output

Try the following:
var d = new Date();
var day = d.getDate();
var month = d.getMonth();
if((month > 11 && day > 14) || (month < 2 && day < 16)){ ...

Dates can be compared as if they are integers (since they contain a time value that is an integer representing an instant in time). So if you want to see if a date is between two other dates, then you can create two date objects and see if others lie between them:
// See if currently between 15 December 2015 and 15 January 2016 inclusive
// Start at 15-Dec-2015 00:00:00
var startDate = new Date(2015,11,15);
// End at 16-Jan-2015 00:00:00 so includes 15 Jan but not 16 Jan
var endDate = new Date(2016,0,16);
var now = new Date();
if (now > startDate && now < endDate) {
document.write("In range");
} else {
document.write("Out of range");
}

exclude weekends in javascript date calculation

I have two sets of codes that work. Needed help combining them into one.
This code gets me the difference between two dates. works perfectly:
function test(){
var date1 = new Date(txtbox_1.value);
var date2 = new Date(txtbox_2.value);
var diff = (date2 - date1)/1000;
var diff = Math.abs(Math.floor(diff));
var days = Math.floor(diff/(24*60*60));
var leftSec = diff - days * 24*60*60;
var hrs = Math.floor(leftSec/(60*60));
var leftSec = leftSec - hrs * 60*60;
var min = Math.floor(leftSec/(60));
var leftSec = leftSec - min * 60;
txtbox_3.value = days + "." + hrs; }
source for the above code
The code below by #cyberfly appears to have the answer of excluding sat and sun which is what i needed. source. However, its in jquery and the above code is in JS. Therefore, needed help combining as i lacked that knowledge :(
<script type="text/javascript">
$("#startdate, #enddate").change(function() {
var d1 = $("#startdate").val();
var d2 = $("#enddate").val();
var minutes = 1000*60;
var hours = minutes*60;
var day = hours*24;
var startdate1 = getDateFromFormat(d1, "d-m-y");
var enddate1 = getDateFromFormat(d2, "d-m-y");
var days = calcBusinessDays(new Date(startdate1),new Date(enddate1));
if(days>0)
{ $("#noofdays").val(days);}
else
{ $("#noofdays").val(0);}
});
</script>
EDIT
Made an attempt at combining the codes. here is my sample. getting object expected error.
function test(){
var date1 = new Date(startdate.value);
var date2 = new Date(enddate.value);
var diff = (date2 - date1)/1000;
var diff = Math.abs(Math.floor(diff));
var days = Math.floor(diff/(24*60*60));
var leftSec = diff - days * 24*60*60;
var hrs = Math.floor(leftSec/(60*60));
var leftSec = leftSec - hrs * 60*60;
var min = Math.floor(leftSec/(60));
var leftSec = leftSec - min * 60;
var startdate1 = getDateFromFormat(startdate, "dd/mm/yyyy hh:mm");
var enddate1 = getDateFromFormat(enddate, "dd/mm/yyyy hh:mm");
days = calcBusinessDays(new Date(startdate1),new Date(enddate1));
noofdays.value = days + "." + hrs; }
start: <input type="text" id="startdate" name="startdate" value="02/03/2015 00:00">
end: <input type="text" id="enddate" name="enddate" value="02/03/2015 00:01">
<input type="text" id="noofdays" name="noofdays" value="">

When determining the number of days between two dates, there are lots of decisions to be made about what is a day. For example, the period 1 Feb to 2 Feb is generally one day, so 1 Feb to 1 Feb is zero days.
When adding the complexity of counting only business days, things get a lot tougher. E.g. Monday 2 Feb 2015 to Friday 6 February is 4 elapsed days (Monday to Tuesday is 1, Monday to Wednesday is 2, etc.), however the expression "Monday to Friday" is generally viewed as 5 business days and the duration Mon 2 Feb to Sat 7 Feb should also be 4 business days, but Sunday to Saturday should be 5.
So here's my algorithm:
Get the total number of whole days between the two dates
Divide by 7 to get the number of whole weeks
Multiply the number of weeks by two to get the number of weekend days
Subtract the number of weekend days from the whole to get business days
If the number of total days is not an even number of weeks, add the numbe of weeks * 7 to the start date to get a temp date
While the temp date is less than the end date:
if the temp date is not a Saturday or Sunday, add one the business days
add one to the temp date
That's it.
The stepping part at the end can probably be replaced by some other algorithm, but it will never loop for more than 6 days so it's a simple and reasonably efficient solution to the issue of uneven weeks.
Some consequences of the above:
Monday to Friday is 4 business days
Any day to the same day in a different week is an even number of weeks and therefore an even mutiple of 5, e.g. Monday 2 Feb to Monday 9 Feb and Sunday 1 Feb to Sunday 8 Feb are 5 business days
Friday 6 Feb to Sunday 7 Feb is zero business days
Friday 6 Feb to Monday 9 Feb is one business day
Sunday 8 Feb to: Sunday 15 Feb, Sat 14 Feb and Fri 13 Feb are all 5 business days
Here's the code:
// Expects start date to be before end date
// start and end are Date objects
function dateDifference(start, end) {
// Copy date objects so don't modify originals
var s = new Date(+start);
var e = new Date(+end);
// Set time to midday to avoid dalight saving and browser quirks
s.setHours(12,0,0,0);
e.setHours(12,0,0,0);
// Get the difference in whole days
var totalDays = Math.round((e - s) / 8.64e7);
// Get the difference in whole weeks
var wholeWeeks = totalDays / 7 | 0;
// Estimate business days as number of whole weeks * 5
var days = wholeWeeks * 5;
// If not even number of weeks, calc remaining weekend days
if (totalDays % 7) {
s.setDate(s.getDate() + wholeWeeks * 7);
while (s < e) {
s.setDate(s.getDate() + 1);
// If day isn't a Sunday or Saturday, add to business days
if (s.getDay() != 0 && s.getDay() != 6) {
++days;
}
}
}
return days;
}
I don't know how it compares to jfriend00's answer or the code you referenced, if you want the period to be inclusive, just add one if the start or end date are a business day.

Here's a simple function to calculate the number of business days between two date objects. As designed, it does not count the start day, but does count the end day so if you give it a date on a Tuesday of one week and a Tuesday of the next week, it will return 5 business days. This does not account for holidays, but does work properly across daylight savings changes.
function calcBusinessDays(start, end) {
// This makes no effort to account for holidays
// Counts end day, does not count start day
// make copies we can normalize without changing passed in objects
var start = new Date(start);
var end = new Date(end);
// initial total
var totalBusinessDays = 0;
// normalize both start and end to beginning of the day
start.setHours(0,0,0,0);
end.setHours(0,0,0,0);
var current = new Date(start);
current.setDate(current.getDate() + 1);
var day;
// loop through each day, checking
while (current <= end) {
day = current.getDay();
if (day >= 1 && day <= 5) {
++totalBusinessDays;
}
current.setDate(current.getDate() + 1);
}
return totalBusinessDays;
}
And, the jQuery + jQueryUI code for a demo:
// make both input fields into date pickers
$("#startDate, #endDate").datepicker();
// process click to calculate the difference between the two days
$("#calc").click(function(e) {
var diff = calcBusinessDays(
$("#startDate").datepicker("getDate"),
$("#endDate").datepicker("getDate")
);
$("#diff").html(diff);
});
And, here's a simple demo built with the date picker in jQueryUI: http://jsfiddle.net/jfriend00/z1txs10d/

const firstDate = new Date("December 30, 2020");
const secondDate = new Date("January 4, 2021");
const daysWithOutWeekEnd = [];
for (var currentDate = new Date(firstDate); currentDate <= secondDate; currentDate.setDate(currentDate.getDate() + 1)) {
// console.log(currentDate);
if (currentDate.getDay() != 0 && currentDate.getDay() != 6) {
daysWithOutWeekEnd.push(new Date(currentDate));
}
}
console.log(daysWithOutWeekEnd, daysWithOutWeekEnd.length);

#RobG has given an excellent algorithm to separate business days from weekends.
I think the only problem is if the starting days is a weekend, Saturday or Sunday, then the no of working days/weekends will one less.
Corrected code is below.
function dateDifference(start, end) {
// Copy date objects so don't modify originals
var s = new Date(start);
var e = new Date(end);
var addOneMoreDay = 0;
if( s.getDay() == 0 || s.getDay() == 6 ) {
addOneMoreDay = 1;
}
// Set time to midday to avoid dalight saving and browser quirks
s.setHours(12,0,0,0);
e.setHours(12,0,0,0);
// Get the difference in whole days
var totalDays = Math.round((e - s) / 8.64e7);
// Get the difference in whole weeks
var wholeWeeks = totalDays / 7 | 0;
// Estimate business days as number of whole weeks * 5
var days = wholeWeeks * 5;
// If not even number of weeks, calc remaining weekend days
if (totalDays % 7) {
s.setDate(s.getDate() + wholeWeeks * 7);
while (s < e) {
s.setDate(s.getDate() + 1);
// If day isn't a Sunday or Saturday, add to business days
if (s.getDay() != 0 && s.getDay() != 6) {
++days;
}
//s.setDate(s.getDate() + 1);
}
}
var weekEndDays = totalDays - days + addOneMoreDay;
return weekEndDays;
}
JSFiddle link is https://jsfiddle.net/ykxj4k09/2/

First Get the Number of Days in a month
totalDays(month, year) {
return new Date(year, month, 0).getDate();
}
Then Get No Of Working Days In A Month By removing Saturday and Sunday
totalWorkdays() {
var d = new Date(); // to know present date
var m = d.getMonth() + 1; // to know present month
var y = d.getFullYear(); // to knoow present year
var td = this.totalDays(m, y);// to get no of days in a month
for (var i = 1; i <= td; i++) {
var s = new Date(y, m - 1, i);
if (s.getDay() != 0 && s.getDay() != 6) {
this.workDays.push(s.getDate());// working days
}else {
this.totalWeekDays.push(s.getDate());//week days
}
}
this.totalWorkingDays = this.workDays.length;
}

I thought the above code snippets others shared are lengthy.
I am sharing a concise snippet that gives date after considering the total number of days specified. we can also customize dates other than Saturdays and Sundays.
function getBusinessDays(dateObj, days) {
for (var i = 0; i < days; i++) {
if (days > 0) {
switch (dateObj.getDay()) {
// 6 being Saturday and 0 being Sunday.
case 6, 0:
dateObj.setDate(dateObj.getDate() + 2)
break;
//5 = Friday.
case 5:
dateObj.setDate(dateObj.getDate() + 3)
break;
//handle Monday, Tuesday, Wednesday and Thursday!
default:
dateObj.setDate(dateObj.getDate() + 1)
//console.log(dateObj)
break;
}
}
}
return dateObj;
}
console.log(getBusinessDays(new Date(), 11))
//Mon Dec 20 2021 18:56:01 GMT+0530 (India Standard Time)