The following snippet of code is taken from Eloquent JavaScript.
var noCatsAtAll = {};
if ("constructor" in noCatsAtAll)
console.log("Yes, there definitely is a cat called 'constructor'.");
I find it quite mystifying. Why does the 'if' return true?
JavaScript objects have a function called constructor which is the function that created the object's instance. It's built-in to all objects. The in operator tests for the presence of something called "constructor" in the instance of your dictionary, so it returns true. The same thing would happen if you tested for length, for example.
All instances of Object have a constructor property that specifies the function that constructs the Object's prototype.
https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Object#Properties_2
The in operator looks at all properties, including inherited ones. If you only want to see the properties on the object itself, you can use hasOwnProperty:
var a = {};
"constructor" in a; // true
a.hasOwnProperty("constructor"); // false
Note that while the in operator sees "constructor", a for (key in a) loop wouldn't. This is because the "constructor" property is non-enumerable.
It is the constructor of the Object type. A reference to the constructor function is available directly on that property ("constructor") of an object (it applies to constructors you write too).
In turn, the names of properties present are in objects.
constructor is a method of Object. You can find the constructor method throughout all objects unless you modify it. The in operator will find methods through the prototype chains. Which is is why it's recommended to use hasOwnProperty to test for properties in your own objects.
var noCatsAtAll = {};
if ("constructor" in noCatsAtAll)
console.log("Yes, there definitely is a cat called 'constructor'.");
if ('constructor' in Object)
console.log("Yes, there is also a method called constructor");
var noCon = Object.create(null); // create a completetly empty object
console.log('constructor' in noCon); // false
function hasConstructorToo() {}
console.log('constructor' in hasConstructorToo) // true
console.log('constructor' in []); // true
http://jsfiddle.net/Xsb3E/3`
Related
In JavaScript is Object the root of all entities or Function is the root?
For example in the following source objects-functions-and-prototypes-in.html, first the author says "Every entity in Javascript is an object", and later it says "any new object can only be created as an instance of a function (even when you do 'var a = new Object;', Object is a function btw)". The author is basically contradicting himself as far as I can see.
And I see the same chaotic comments in so many other resources on JavaScript. In Java it is easy, you know the first entity in any class Hierarchy is the Object class, but in JavaScript, all I see is chaos.
So, can someone please clarify if Object comes first or Function? What is the root.
I believe the end of the line is Object.prototype, which is an object. This is what makes me think so:
Function.prototype; // the empty function object
Function.prototype.__proto__; // the default Object prototype
Object.prototype; // the default Object prototype
Object.prototype.__proto__; // null
The ECMAScript 5.1 specification states it like this:
In 15.3.4 Properties of the Function Prototype Object:
The value of the [[Prototype]] internal property of the Function prototype object is the standard built-in Object prototype object
And in 15.2.4 Properties of the Object Prototype Object
The value of the [[Prototype]] internal property of the Object prototype object is null
Here's what the MDN docs for Object.prototype have to say:
all objects inherit methods and properties from Object.prototype, although they may be overridden (except an Object with a null prototype, i.e. Object.create(null)).
In other words, Object.prototype is the root of almost all objects. Both Object and Function are children of Function.prototype, which is itself a child of Object.prototype.
I find inheritance in Javascript to be far easier to understand when I ignore the constructor functions, and instead focus on prototype chains. Doing this, for me, makes both the questions as well as the answers simpler; questions like:
what is the prototype chain of an object?
given two objects x and y, is x in y's prototype chain? (or: does y inherit from x?)
You can easily investigate prototype chains yourself with this little snippet (helpful docs here):
function getPrototypes(obj) {
var protos = [],
parent = obj;
while ( true ) {
parent = Object.getPrototypeOf(parent);
if ( parent === null ) {
break;
}
protos.push(parent);
}
return protos;
}
According to this function, primitives don't have prototypes:
> getPrototypes(3)
TypeError: Object.getPrototypeOf called on non-object
So let's leave primitives out of the picture.
For objects, the hierarchy looks like this (where the children are indented to the right of their parent). As far as I know, true multiple inheritance is impossible in Javascript, and so every object has a single parent, with the exception of Object.prototype, which has no parent:
Object.create(null)
Object.prototype
arguments
Object.create(Object.prototype)
{}
Object.create({}) -- assuming {} is the object from the previous line, not a separate new object
JSON
Math
Array.prototype
[]
new Array()
Function.prototype
Array
Object
Function
Number
Boolean
String
RegExp
function MyFunction() {}
Object.keys
Object.prototype.toString
Object.prototype.toString.call
getPrototypes
MyFunction.prototype
new MyFunction()
String.prototype
new String('abc')
Object.create(new String('abc'))
Number.prototype
new Number(41)
Boolean.prototype
new Boolean()
new Object(false)
RegExp.prototype
/a/
This is very confusing! Notice that for most cases, X.prototype is not a prototype of X! If we had some better terminology, the situation would probably be improved; however ... we don't :( As you can see, constructors such as Number and Boolean are in a separate sub-hieararchy from the objects they produce. Also, Object itself inherits from Function.prototype inherits from Object.prototype.
If you try these examples out, you will also find that using the constructor property is a poor way to inspect an object's prototypes, for a couple of reasons. Given var str1 = new String('abc'); var str2 = Object.create(str1);, here's why:
an object can be an instance of multiple constructors: str1 instanceof String and str1 instanceof Object are both true. This isn't reflected in the constructor property: str1.contructor === String
sometimes, we can't find a constructor function for each object in an object's prototype chain: Object.getPrototypeOf(str2).constructor === String. This is because the constructor property is inherited from String.prototype: both str1.hasOwnProperty('constructor') and str2.hasOwnProperty('constructor') are false, while Object.getPrototypeOf(str1).hasOwnProperty('constructor') is true. Fortunately, you can use the Object.prototype.isPrototypeOf method for this instead: str1.isPrototypeOf(str2) is true.
You're misunderstanding it.
Everything in Javascript (including all functions) is an object.
However, every object is an instance of a function. (as specified by the object's constructor property)
So as long as anything in Javascript is actually an object, what makes an object behave as a function? What internal properties and labels make an object behave as an object we can call instead of just using it to store values?
There is an internal property, [[Call]], that determines what will be executed, when the object is called.
Plain objects don't have this interal property, so they aren't callable, and can't be made to be callable.
The only callables in JS are functions (which are also objects), classes (which are actually functions, and therefore objects as well), and Proxy objects that wrap callables.
To create a callable object, create a function, and make it have the properties and prototypes you would like.
So as long as anything in javascript is actually an object
Well, not everything in JavaScript is an object. For instance, primitives such as strings, booleans and numbers are not objects. JavaScript just wraps these primitives in objects when properties are accessed.
what makes an object behave as a function what internal properties and
labels did this job to make an object behave as an execution code
instead of just storing variables
You're correct about functions being objects, however, unlike regular objects which just store key-value pairs, function objects have a special internal method which they implement known as [[Call]]. This call method is what executes the code associated with the function object and is invoked when you call a function (func_name()). So, any object which implements the internal [[Call]] method is callable. You yourself cannot make an object callable by implementing this property as it is not part of the ECMAScript language itself, but rather a method name used by the spec. Instead, we use the function keyword for that. Function objects are still objects at the end of the day, so you can assign properties to them as well as access preexisting properties:
function foo(a) {
return a;
}
foo.bar = "foobar";
console.log(foo.length); // able to access pre-existing properties
console.log(foo.bar); // able to access our own properties
console.log(foo(2)); // able to invoke (due to [[Call]])
You can read more about function objects here
You could assign an object to a function to get a callable function.
var object = { foo: 42 },
callable = Object.assign(function () {}, object);
console.log(callable)
console.log(callable())
console.log(Object.keys(callable));
You can't make an object callable.
You can add properties to an already existing Function object though. You will still retain call() behavior, but can also get and set properties.
var object = { increment: function(x){
return x+1
} ,
foo: 'foo'
};
var decrement = function(x){
return x-1
}
callable = Object.assign(decrement, object);
console.log(callable.increment(12)) //13
console.log(callable(67)) //66
console.log(Object.keys(callable));//[ 'increment', 'foo' ]
There are different prototypes in javascript. E.g. Object.prototype, Function.prototype, Array.prototype. Javsacript works based on prototypical inheritance. This defines what is the type of any object.
When you create a function, its __proto__ (also called as "dunder proto") is set to Function.prototype. Basically a function inherits from Function.prototype which in turn inherits from Object.prototype. Following example is taken from MDN. (Note - I think __proto__ is not standardized. Object.getPrototypeOf should be used)
function f() {
return 2;
}
// Functions inherit from Function.prototype
// (which has methods call, bind, etc.)
// f ---> Function.prototype ---> Object.prototype ---> null
MDN has a great explanation for prototypical inheritance. For more information read this https://developer.mozilla.org/en-US/docs/Web/JavaScript/Inheritance_and_the_prototype_chain
Consider this code:
function foo(something) {
this.a = something;
}
var obj1 = {};
var bar = foo.bind(obj1);
Now the following statement doesn't execute:
bar.prototype.newprop = "new"; // Cannot execute this
As I understood, every function has a prototype object. Then why can't we execute the above statement?
And bar is indeed a function as we can call it:
bar(2);
console.log(obj1.a); // 2
As I understood, every function has a prototype object.
Well, there are exceptions to every rule :-) You found one: bound functions don't have a .prototype property because they don't need it. When you call a bound function with new, it calls the original function as a constructor, using the original's .prototype object as the prototype of the new instance.
In fact, since ECMAScript 6 many functions don't have a .prototype property with an object, because they are not constructors - they cannot be called with new so they don't need it. Among those are
arrow functions (() => {…})
methods (method() { … } in object literals and classes)
builtin non-constructor functions (like Math.sin)
See the specification:
Function.prototype.bind ( thisArg , ...args)
[...]
NOTE 1 Function objects created using Function.prototype.bind are exotic objects. They also do not have a prototype property.
The returned function from .bind() has no prototype object. You can give it one:
bar.prototype = { newprop: "new" };
It is not true that "every function has a prototype object". Every function can have a prototype object, but the value of the "prototype" property can be anything, including null or undefined.
Additionally, there are "special" functions that may not behave like ordinary functions in all cases.
Adding properties to the prototype means you want to create an object by using the function as a constructor.
When you create an object like by calling new on a function, the this value is the new object being created. So it makes no sense to bind this to another value.
Why the prototype of instance is not the same like the prototype of its constructor if to use the Object.getPrototypeOf() function?
function A(n){this.n=n;};
let a = new A(1);
console.log('Object.getPrototypeOf(a) == Object.getPrototypeOf(A); // ',
Object.getPrototypeOf(a) == Object.getPrototypeOf(A));
console.log('Object.getPrototypeOf(a) == A.prototype; // ',
Object.getPrototypeOf(a) == A.prototype);
Object.getPrototypeOf() returns the value of the internal [[Prototype]] property, which is not the same as the prototype property. When you create a function (or a class), it gets a prototype property, and when you create an instance of it, the created object has the internal [[Prototype]] property set to the prototype property of the class.
Your first example evaluates to false, because [[Prototype]] of a is A.prototype, but [[Prototype]] of A is Function.prototype, because every function is an instance of the Function class.
You are seeing this because A's prototype (the prototype object from which A is derived) is Function.prototype, not A.prototype:
function A(n){this.n=n;};
console.log('Object.getPrototypeOf(A) === Function.prototype');
console.log(Object.getPrototypeOf(A) === Function.prototype);
let a = new A(1);
console.log('Object.getPrototypeOf(a) === A.prototype');
console.log(Object.getPrototypeOf(a) === A.prototype);
Object.getPrototypeOf(x) is not just a convoluted way of writing x.prototype.
Object.getPrototypeOf(x) returns the prototype from which x is derived.
x.prototype is the prototype of objects created using x as a constructor.
Although it seems simple at a glance but the answer will become more clear if you know how protoypal inheritance works in JS.
Still I would try to explain it in short, how prototype works.
In JS, everything is an object. Although primitive values such as numbers, strings, boolean do not look like objects but are treated like objects internally.
For a quick reference see below. Everything is an object.
Now lets come to the case mentioned in question. Whenever you create anything in JS, it uses some existing prototype. It depends on what kind of item you are creating.
The below line is basically doing a lot of things in background. It is creating a function with name as 'A'. While doing so the JS engine uses an already existing special object in the browser called Function.prototype. This contains the basic characteristics of any function that you are creating. Then it creates a brand new object that has only two properties by default: constructor and a link to the default object prototype(referenced by proto). And then assign the new function definition that you have written to this newly created function.
function A(n){this.n=n;};
Hence we have two prototypes to understand here:
Function.prototype
A.prototype
Function.prototype would give that existing object we discussed above which is provided by the engine to create new functions.
A.prototype is the new object that gets created when A is declared. Note that we haven't yet used our new function A to create objects.
While running the below code, JS engine creates a new object which would inherit properties from A.prototype, runs the function definition which is stored in A(this.n = n etc..) and returns the newly created object.
let a = new A(1);
To summarize
a is an object that inherits from A.prototype
A is a function(a special object) that inherits from Function.prototype
I think now it should be clear what the below code means.
Object.getPrototypeOf(a) === A.prototype // true
Object.getPrototypeOf(A) === Function.prototype //true
function Gadget(name, color)
{
this.name = name;
this.color = color;
}
Gadget.prototype.rating = 3
var newtoy = new Gadget("webcam", "black")
newtoy.constructor.prototype.constructor.prototype.constructor.prototype
It always returns the object with rating = 3.
But if I do the following:
newtoy.__proto__.__proto__.__proto__
The chain ends up returning null.
Also in Internet Explorer how would I check the null if there is not a __proto__ property?
I've been trying to wrap my head around this recently and finally came up with this "map" that I think sheds full light over the matter
http://i.stack.imgur.com/KFzI3.png
I know I'm not the first one making this up but it was more interesting figuring it out that finding it :-). Anyway, after that I found e.g. this another diagram that I think says basicly the same:
Javascript object layout
The most surprising thing for me was discovering that Object.__proto__ points to Function.prototype, instead of Object.prototype, but I'm sure there's a good reason for that :-)
I paste the code mentioned in the image here as well for if anyone wants to test it. Note that some properties are added to the objects for making easy to know where we are after some jumps:
Object.O1='';
Object.prototype.Op1='';
Function.F1 = '';
Function.prototype.Fp1 = '';
Cat = function(){};
Cat.C1 = '';
Cat.prototype.Cp1 = '';
mycat = new Cat();
o = {};
// EDITED: using console.dir now instead of console.log
console.dir(mycat);
console.dir(o);
constructor is a pre-defined [[DontEnum]] property of the object pointed to by the prototype property of a function object and will initially point to the function object itself.
__proto__ is equivalent to the internal [[Prototype]] property of an object, ie its actual prototype.
When you create an object with the new operator, its internal [[Prototype]] property will be set to the object pointed to by the constructor function's prototype property.
This means that .constructor will evaluate to .__proto__.constructor, ie the constructor function used to create the object, and as we have learned, the protoype property of this function was used to set the object's [[Prototype]].
It follows that .constructor.prototype.constructor is identical to .constructor (as long as these properties haven't been overwritten); see here for a more detailed explanation.
If __proto__ is available, you can walk the actual prototype chain of the object. There's no way to do this in plain ECMAScript3 because JavaScript wasn't designed for deep inheritance hierarchies.
The Prototypal Inheritance in JavaScript is based on __proto__ property in a sense that each object is inheriting the contents of the object referenced by its __proto__ property.
The prototype property is special only for Function objects and only when using new operator to call a Function as constructor. In this case, the created object's __proto__ will be set to constructor's Function.prototype.
This means that adding to Function.prototype will automatically reflect on all objects whose __proto__ is referencing the Function.prototype.
Replacing constructor's Function.prototype with another object will not update __proto__ property for any of the already existing objects.
Note that __proto__ property should not be accessed directly, Object.getPrototypeOf(object) should be used instead.
To answer the first question, I've created a bespoke diagram of __proto__ and prototype references, unfortunately stackoverflow does not allow me to add the image with "less than 10 reputation". Maybe some other time.
[Edit]
The figure uses [[Prototype]] instead of __proto__ because that is how ECMAScript specification refers to internal objects. I hope you can figure everything out.
Here are some hints to help you understand the figure:
red = JavaScript Function constructor and its prototype
violet = JavaScript Object constructor and its prototype
green = user-created objects
(first created using Object constructor or object literal {},
second using user-defined constructor function)
blue = user-defined function and its prototype
(when you create a function, two objects are created in memory:
the function and its prototype)
Note that constructor property does not exist in created objects, but is inherited from the prototype.
Object is Eve, and Function is Adam, Adam (Function) uses his bone (Function.prototype) to create Eve (Object). Then who created Adam (Function)? -- The Inventor of the JavaScript language :-).
According to utsaina's answer, I want to add more useful info.
The most surprising thing for me was discovering that Object.__proto__
points to Function.prototype, instead of Object.prototype, but I'm
sure there's a good reason for that :-)
It should NOT be. Object.__proto__ should NOT point to Object.prototype. Instead, the instance of Object o, o.__proto__ should point to Object.prototype.
(Forgive me for using the terms class and instance in JavaScript, but you know it :-)
I think the class Object itself is an instance of Function, that's why Object.__proto__ === Function.prototype. Therefore: Object is Eve, and Function is Adam, Adam (Function) uses his bone (Function.prototype) to create Eve (Object).
Furthermore, even the class Function itself is an instance of Function itself, that is Function.__proto__ === Function.prototype, that's also why Function === Function.constructor
Further furthermore, the regular class Cat is an instance of Function, that is Cat.__proto__ === Function.prototype.
The reason for the above is, when we create a class in JavaScript, actually, we are just creating a function, which should be an instance of Function. Object and Function are just special, but they are still classes, while Cat is a regular class.
As a matter of factor, in Google Chrome JavaScript engine, the following 4:
Function.prototype
Function.__proto__
Object.__proto__
Cat.__proto__
They are all === (absolutely equal) to the other 3, and their value is function Empty() {}
> Function.prototype
function Empty() {}
> Function.__proto__
function Empty() {}
> Object.__proto__
function Empty() {}
> Cat.__proto__
function Empty() {}
> Function.prototype === Function.__proto__
true
> Function.__proto__ === Object.__proto__
true
> Object.__proto__ === Cat.__proto__
true
OK. Then who creates the special function Empty() {} (Function.prototype)? Think about it :-)
I really don't know why people didn't correct you about where the actual problem in your understanding.
This would make a lot easier for you to spot the problem
So let's see what's going on :
var newtoy = new Gadget("webcam", "black")
newtoy
.constructor //newtoy's constructor function is newtoy ( the function itself)
.prototype // the function has a prototype property.( all functions has)
.constructor // constructor here is a **property** (why ? becuase you just did `prototype.constructor`... see the dot ? ) ! it is not(!) the constructor function !!! this is where your mess begins. it points back to the constructor function itself ( newtoy function)
.prototype // so again we are at line 3 of this code snippet
.constructor //same as line 4 ...
.prototype
rating = 3
Great , so now let's look at this __proto__
Before that , please remember 2 things regarding __proto__ :
When you create an object with the new operator, its internal [[Prototype]]/proto__ property will be set to the prototype property(1) of its constructor function or "creator" if you like .
Hard coded within JS — : Object.prototype.__proto__ is null.
Let's refer to these 2 points as "bill"
newtoy
.__proto__ // When `newtoy` was created , Js put __proto__'s value equal to the value of the cunstructor's prototype value. which is `Gadget.prototype`.
.__proto__ // Ok so now our starting point is `Gadget.prototype`. so regarding "bill" who is the constructor function now? watch out !! it's a simple object ! a regular object ! prototype is a regular object!! so who is the constructor function of that object ? Right , it's the `function Object(){...}`. Ok .( continuing "bill" ) does it has a `prototype` property ? sure. all function has. it's `Object.prototype`. just remember that when Gadget.prototype was created , it's internal `__proto__` was refered to `Object.prototype` becuase as "bill" says :"..will be set to the `prototype` property of its `constructor function`"
.__proto__ // Ok so now our satrting point is `Object.prototype`. STOP. read bullet 2.Object.prototype.__proto__ is null by definition. when Object.prototype ( as an object) was created , they SET THE __PROTO__ AS NULL HARDCODED
Better?
Every functions creates it's prototype.
And when we create an object using that function constructor then the __proto__ property of my object will start pointing to the prototype of that function.
If all those figures were overwhelming, let's take a look what the properties mean.
STH.prototype
When creating a new function, there is an empty object being created in parallel and linked to the function with [[Prototype]] chain. To access this object, we use prototype property of the function.
function Gadget() {}
// in background, new object has been created
// we can access it with Gadget.prototype
// it looks somewhat like {constructor: Gadget}
Bear in mind that prototype property is only available for functions.
STH.constructor
The prototype object mentioned above has no properties except for one - constructor. This property represents a function that created the prototype object.
var toy = new Gadget();
When creating Gadget function, we created an object like {constructor: Gadget} as well - that is nothing like Gadget.prototype. As constructor refers to a function that created an object prototype, toy.constructor represents Gadget function. We write toy.constructor.prototype and we are getting {constructor: Gadget} again.
Therefore, there's a vicious circle: you can use toy.constructor.prototype.constructor.prototype.constructor.prototype.constructor.prototype.constructor.prototype.constructor.prototype.constructor.prototype.constructor.prototype and it always will be Gadget.prototype.
toy
.constructor // Gadget
.prototype // {constructor: Gadget}
.constructor // Gadget
.prototype // {constructor: Gadget}
// ...
STH.__proto__
While prototypeis a property specific for functions, __proto__ is available for all objects as it lays in Object.prototype. It refers to prototype of a function that can create an object.
[].__proto__ === Array.prototype
// true
({}).__proto === Object.prototype
// true
Here, toy.__proto__ is Gadget.prototype. As Gadget.prototype is an object ({}) and objects are created with Object function (see the example above), we get Object.prototype. This is the higher object in JavaScript and its __proto__ can only indicate null.
toy
.__proto__ // Gadget.prototype (object looking like {constructor: Gadget})
.__proto__ // Object.prototype (topmost object in JS)
.__proto__ // null - Object.prototype is the end of any chain
Short answer: __proto__ is a reference to the prototype property of the constructor that created the object.
Objects in JavaScript
A JavaScript object is a built-in type for a collection of zero or more properties. Properties are containers that hold other objects, primitive values, or functions.
Constructors in JavaScript
Functions are regular objects (which implement [[Call]] in ECMA-262 terms) with the additional capability of being callable but play another role in JavaScript: they become constructors (factories for objects) if invoked via the new operator. Constructors are thus a rough analog to classes in other languages.
Every JavaScript function is actually an instance of the Function built-in function object that has a special property named prototype used to implement prototype-based inheritance and shared properties. Every object created by a constructor function has an implicit reference (called the prototype or __proto__) to the value of its constructor prototype.
The constructor prototype is a sort of blueprint for building objects since every object created by the constructor inherits a reference to its prototype.
The prototype chain
An object specifies its prototype via the internal property [[Prototype]] or __proto__. The prototype relationship between two objects is about inheritance: every object can have another object as its prototype. The prototype may be the null value.
The chain of objects connected by the __proto__ property is called the prototype chain. When a reference is made to a property in an object, that reference is to the property encountered in the first object in the prototype chain that contains a property of that name. The prototype chain behaves as if it were a single object.
Whenever you try to access a property in an object, JavaScript starts the search for it in that object and continues with its prototype, the prototype's prototype and so on until the property is encountered or if __proto__ holds the value null.
This type of inheritance using the prototype chain is often called delegation to avoid confusion with other languages using the class chain.
Almost all objects are instances of Object, because Object.prototype is last in their prototype chain. But Object.prototype is not an instance of Object because Object.prototype.__proto__ holds the value null.
You can also create an object with a null prototype like this:
var dict = Object.create(null);
Such an object is a better map (dictionary) than a literal object, which is why this pattern is sometimes called the dict pattern (dict for dictionary).
Note: literal objects created using {} are instances of Object since ({}).__proto__ is a reference to Object.prototype.
Prototypes in JavaScript are confusing for Everyone
A constructor on any type (Object, String, Array, etc) is initially connected with the Function Object that creates them. Once the object types value/objects are created, only then are they assigned their own prototypes, which is a unique property and object the Functions constructor creates when each value is created. But the prototyopes of all objects/types (Object, String, Array, etc) in JavaScript starting out are all Function.prototype. They all derive from functions and their constructors needed to create instances of objects and primitive values in memory! It is not till their values get created by their function constructors that they get assigned their own unique prototypes, both the "prototyoe" property and the Object prototype they inherit from.
This is what 99% of online web pages on the Internet do not tell you!
For example, the Number (or String Array, Boolean, etc.) type always has a constructor, or Number.constructor, which derives from the Function Object assigned to the "Number" type. This is why "Number" is called an "Constructor". So, its prototype is Function.prototype when you check. Once its function or constructor has built a true Number primitive or type, its assigned its own unique prototype of Number.prototype. Let's prove that below!
Here is a simpler explanation. Below is how most objects in JavaScript inherit starting with null down to the object type:
String < Function < Object < null
Array < Function < Object < null
Object < Function < Object < null
Function < Function < Object < null
Here is proof!
Below I am just asking for the prototype found for each object. Note: Object.prototype.toString.call() just tells us the string name of the prototype:
Object.prototype.toString.call(String);// [object Function]
Object.prototype.toString.call(Array);// [object Function]
Object.prototype.toString.call(Object);// [object Function]
Object.prototype.toString.call(Function);// [object Function]
Object.prototype.toString.call(String.__proto__);// [object Function]
Object.prototype.toString.call(Array.__proto__);// [object Function]
Object.prototype.toString.call(Object.__proto__);// [object Function]
Object.prototype.toString.call(Function.__proto__);// [object Function]
Object.prototype.toString.call(String.__proto__.__proto__);// [object Object]
Object.prototype.toString.call(Array.__proto__.__proto__);// [object Object]
Object.prototype.toString.call(Object.__proto__.__proto__);// [object Object]
Object.prototype.toString.call(Function.__proto__.__proto__);// [object Object]
Object.prototype.toString.call(String.__proto__.__proto__.__proto__);// [object Null]
Object.prototype.toString.call(Array.__proto__.__proto__.__proto__);// [object Null]
Object.prototype.toString.call(Object.__proto__.__proto__.__proto__);// [object Null]
Object.prototype.toString.call(Function.__proto__.__proto__.__proto__);// [object Null]
Please note that the string "[object Function]" is saying that the "prototype" or parent object for the type was "Function.prototype". So it a representation of the underlying prototype parent objects assigned at each level. Now let's explain this in more depth...
A prototype in JavaScript is a word that means the following:
All Objects in JavaScript ultimately inherit from a series of prototypes or "base classes" that assign their various properties and features through inheritance. This cascades down a tree to the child at the bottom. In JavaScript ALL OBJECTS ultimately inherit from the Object.prototype which is close to the top of that inheritance tree.
The term "prototype" means a special object with properties and methods inherited by child objects
"prototype" is also a special property given to all Objects in JavaScript that assigns a given object as the parent prototype to a child but also grants access to changing the prototype. It controls the actual prototype assigned to a child object, but also acts like a true Class Property in that you can use it to manipulate the prototype of a child object. I do not recommend you do this, but you can modify the original Object.prototype inherited by all object by adding new properties using a simple property addition or adding properties via a Object Literal containing properties:
Object.prototype.myproperty = "Hello World";
Object.prototype.myobjectproperties = {text1: "Hello", text2: "World"};
"prototype" the property is expressed in combination with the Child Object name as "MyObjectType.prototype". This new name is now both a identifier for the parent prototype and also a tool to change it. But it is NOT a reference to the actual prototype object! (That is done below using __proto__). It is assigned to all new objects when created of that type. It is first assigned to the function constructor that built the object, then passed to the object the function constructor creates.
"__proto__" is a reference to the actual prototype object assigned to the child. Its also a property but its a reference. So its used to go up the tree of prototypes objects inherited by a child object and access them and their properties. This example below goes up the tree from an object literal created and ends at the top with "null":
alert({}.__proto__.__proto__);// null
Weirdness in Prototype
So, in JavaScript inheritance, everything starts with a Function type! Why is that? Its because you cannot create any of the object "types" (Object, Array, Function, String, etc.) without a Function. And when you do, they still get constructed from a "constructor" called somewhere in a function. A Function and its constructor is what not only creates new objects from types, but also assigns the "prototype" property, the "__proto__" property, and the actual tree of inherited prototypes or objects the child object will use.
There are two states of objects in JavaScript, the "types" and the actual instantiated Objects. That is why "Object" is not the same as a created Object as "const x = {}". And that is why the "type" starts out with a different inheritance or prototypes from its final one.
Check this out!
// The Array type has a prototype of "Function.prototype"
alert(Object.prototype.toString.call(Array));// [object Function]
// But an instance of an Array object has a NEW prototype of "Array.prototype" that the function prototype's constructor created for the object!
const myarray = [];
alert(Object.prototype.toString.call(myarray));// [object Array]
So what happened?
It turns out the FUNCTION CONSTRUCTOR creates and assigns the final prototype when the object is created. But that custom prototype can be modified both before and after the array object is created with many more properties, objects, etc. So the final assigned prototype is set by the constructor of the Function object which as shown above was the Array types initial prototype.
So realize, the Function.prototype is the primary prototype of all Object types in JavaScript! It lies underneath all objects, but is a tool to creating the final instantiated object that is assigned its own prototype when created. Note that the "Array.prototype" has a parent prototype of Object.prototype who has a parent of "null". So the Object.prototype remains the top parent inherited by all these objects. But in the creation of them the constructor changes the immediate parent of all child objects when new objects get created.
Note that the Function.prototype gets many of its features from its own Object.prototype it too inherits. The prototype it builds for your created objects are also made from this parent prototype. So in the end. the Object.prototype provides the goodies needed for Function types and all types to get created and manage the prototype assigned to them. Just remember Function like Object is a special pre-built type with special tools and features needed to create all types of objects!
Last test....lets see how prototype works for CUSTOM OBJECTS we create. The example below proves that the function constructor (part of the Function.prototype) assigns the "prototype" property to the created objects BUT can be customized with various properties and methods before or after being assigned to the objects prototype of MyCustomObject.prototype. This shows that the final prototype of your object need not be a static copy of the Object.prototype's inherited properties, but can be something you create that is entirely new!
let newPet;
function Pet() {
this.fourlegs = true;
}
var Cat = {
type : "cat"
}
var Dog = {
type : "dog"
}
// We can see the prototype our constructor created for us
// and modify it as we like! Here we assigned it to an object
// which only means the prototype will merge "Cat" object's
// properties into the Pet.prototype.
Pet.prototype = Cat;
newPet = new Pet();
alert(newPet.type);// cat - inherited the Cat Object's properties in the prototype
Pet.prototype = Dog;
newPet = new Pet();
alert(newPet.type);// dog - inherited the Dog Object's properties in the prototype
alert(newPet.fourlegs);// true - this shows, even though you replace prototype, it ADDs the new types but does NOT erase the existing object properties! This must mean "prototype" is dynamically additive and rebuilt until the final "Pet" prototype is complete.
// Now change the "Pet.prototype" so all new objects have a new property.
Pet.prototype.furcolor = "white";
newPet = new Pet();
alert(newPet.furcolor);// "white"
// So you can see the "Pet.prototype" is dynamic, something you can tell the function constructor to modify!