I'm currently reading You don't know JS. In it, there is a section that talks about soft binding technique. Basically it's a variation of binding a function to a particular scope/context.
From the book:
It would be nice if there was a way to provide a different default for default binding (not global or undefined), while still leaving the function able to be manually this bound via implicit binding or explicit binding techniques.
if (!Function.prototype.softBind) {
Function.prototype.softBind = function(obj) {
var fn = this,
curried = [].slice.call( arguments, 1 ),
bound = function bound() {
return fn.apply(
(!this ||
(typeof window !== "undefined" &&
this === window) ||
(typeof global !== "undefined" &&
this === global)
) ? obj : this,
curried.concat.apply( curried, arguments )
);
};
bound.prototype = Object.create( fn.prototype );
return bound;
};
}
Generally I understand what the function does except this part:
bound.prototype = Object.create( fn.prototype );
Why do we have to setup a prototype when using this "soft bind" technique?
Why do we have to setup a prototype when using this "soft bind" technique?
It's more for completeness sake than anything else. If someone tries to create a new instance of the soft-bound function, they'd expect the resulting object to [[Prototype]] link to the same object as the original function's .prototype pointed. So, we make sure to set bound.prototype equal to reference that same object.
The chances of someone wanting to call new on a soft-bound function are low, I'd think, but just to be more safe, it's included nonetheless. The same, btw, is true of the polyfill for the built in bind(..) as listed here:
https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_objects/Function/bind#Polyfill
From that page:
Why is new being able to override hard binding useful?
The primary reason for this behavior is to create a function (that can
be used with new for constructing objects) that essentially ignores
the this hard binding but which presets some or all of the function's
arguments. One of the capabilities of bind(..) is that any arguments
passed after the first this binding argument are defaulted as standard
arguments to the underlying function (technically called "partial
application", which is a subset of "currying").
I guess for the softbind to have the same benefits (to provide a constructor that has default arguments passed to it) you have to set the prototype as well or you're missing prototype functions when you use the bound function as a constructor:
//softBind code removed
function Test(arg1,arg2){
this.arg1=arg1;
this.arg2=arg2;
}
Test.prototype.sayArgs=function(){
console.log('args:',this.arg1,this.arg2);
}
//the binding part doesn't do anything so can pass null
var BoundTest = Test.softBind(null, 'arg1');
var bt = new BoundTest('arg2');
bt.sayArgs();//=args:arg1 arg2
If you are going to use it this way though you don't have to add softBind to the Function.prototype, you can use normal bind, either native or the MDN polyfill.
Note that with the polyfill you cannot pass a falsy argument as the first parameter to bind or it'll break.
//Using the MDN bind polyfill you can't pass any falsy
// value like null, undefined,"",0 and false
var BoundTest = Test.bind({}, 'arg1');
var bt = new BoundTest('arg2');
bt.sayArgs();//=args:arg1 arg2;
In the article, the example given is actually broken:
var bar = foo.bind( null, "p1" );
var baz = new bar( "p2" );
Should be:
var bar = foo.bind('anything non falsy' , "p1" );
[update]
//removed if, so it'll set softbind every time
Function.prototype.softBind = function(obj) {
var fn = this,
curried = [].slice.call( arguments, 1 ),
bound = function bound() {
return fn.apply(
(!this ||
(typeof window !== "undefined" &&
this === window) ||
(typeof global !== "undefined" &&
this === global)
) ? obj : this,
curried.concat.apply( curried, arguments )
);
};
bound.prototype = Object.create( fn.prototype );
return bound;
};
function Test(){
//this has the right prototype and has
// the default arguments
console.log('this is:', this,'arguments',arguments);
this.name='test';
}
Test.prototype.something=22
var BoundTest = Test.softBind(null,'arg1','arg2');
var bt = new BoundTest();
//bt is same as new Test('arg1','arg2') would be
console.log('bt is:',bt);
//this.name did not affect window
console.log(window.name);//not test
console.log(bt instanceof Test);//true
I'm trying to determine wether a function in javascript is a simple, plain (anonymous) function, or a constructor ( a function with a prototype ). So far, I've come up with the following function:
function isPlainFunction(value) {
var own = Object.getOwnPropertyNames(value.prototype),
ctorIndex = own.indexOf('constructor');
if ( ctorIndex !== -1 ) {
own.splice( ctorIndex, 1);
}
if (own.length) {
return false;
}
// walk prototype chain
var proto = Object.getPrototypeOf(value.prototype);
if (proto === Object.prototype) {
return true;
}
return isPlainFunction(proto);
}
I'm only targeting ES5, (node.js) but I am uncertain whether this covers all edge cases, or if there's still something I havent found regarding this subject.
I have (roughly) the following testcases in mind:
assert.ok( isPlainFunction(function(){}) );
var bar = function(){};
bar.prototype = { get one(){ return 1 } };
assert.equal( isPlainFunction(bar), false );
var foo = function(){};
foo.prototype = Object.create( bar );
assert.equal( isPlainFunction(bar), false );
That is, any function that has a prototype or inherited a prototype from one of the not-native types...
If what you are trying to test for is whether or not a function should be used as a constructor, then unfortunately this cannot be accurately determined.
You can invoke the new operator on any function, whether intended to be used that way or not without issues.
If I have this method, for instance:
function doSomethingWithThisObject(someValue) {
this.someVariable = someValue;
}
Which has the following prototype:
doSomethingWithThisObject.prototype = { prototypeVariable : 'I came from prototype' };
I could use it in the following ways:
// Use my function as a constructor:
var obj = new doSomethingWithThisObject('hi there!');
console.log(obj.someVariable); // prints "hi there!"
console.log(obj.prototypeVariable); // prints "I came from prototype"
// Use my function in an object:
var myObject = {
doSomething : doSomethingWithThisObject
};
myObject.doSomething('hi again!');
console.log(myObject.someVariable); // prints "hi again!"
console.log(myObject.prototypeVariable); // prints "undefined"
// Use my function to change global state:
doSomethingWithThisObject('you owe me ice cream!');
console.log(someVariable); // prints "you owe me ice cream!"
console.log(prototypeVariable); // prints "undefined"
Determining whether or not one of those use cases is the correct one is impossible unless the intention is specified somewhere in the code.
Some people suggest to name constructor methods with an uppercase first letter to determine that they should be used as constructors. If you decide for this suggestion with your project's coding guidelines, you could simply check if the function's name begins with an uppercase letter which would denote that the person who wrote the function intends for it to be used as a constructor.
As Ben Barkay has said, any function can become a constructor in JS through the new keyword. Behind the scenes all new is doing is setting the function's context -- you can see this with a simple test:
function test() {
console.log(this)
}
test()
output: Window {top: Window, window: Window…}
new test()
output: test {}
test {}
In JS all you need to make a function a constructor is a new keyword, and all a new does is set the function's this variable. So any function can become a constructor.
Distinguishing an anon function is easier: if it doesn't have a name, it's anonymous:
//anon:
(function() {
console.log("I'm anon")
})()
var anon = function() {
console.log("I, too, am anon")
}
If you programmatically need the function's name, you can get it through function.name
To determine whether a function does not have an extended prototype, e.g. can be assumed to be more then a plain function, the following function would return false:
function isPlainFunction(value) {
if (typeof value !== 'function') {
return false;
}
var own = Object.getOwnPropertyNames(value.prototype);
if ( own.length >= 2 || ( own.indexOf('constructor') < 0 && own.length >= 1 ) ) {
return false;
}
return Object.getPrototypeOf(value.prototype) === Object.prototype;
}
If I do the following:
image[i].onmousedown = whatever;
It will work perfectly fine and run the whatever() function on click. However if I do the following:
image[i].onmousedown = whatever( name, what, when, where, how );
It will run the function when it assigns the property. Let's say I create 30 images and want to give them all onmousedown functions, it will run that function 30 times on load just because I added the () after whatever. But how else do I assign my functions the properties I want?
Is the only way to make a function run the function? So do something like
image[i].onmousedown = whatever;
function whatever() {
anotherWhatever( this, name, what, when, where, how );
}
I also have to assign a new value to 'this' it seems? What would you guys suggest or please tell me you have a better way of doing it. Thanks in advance for any help
You can use ecmaScript5 bind function, to bind the context and set the arguments to be passed in.
image[i].onmousedown = whatever.bind(this, name, what, when, where, how );
this here will be the current context where you are binding the event. If you want to get the context of the element itself then:
image[i].onmousedown = whatever.bind(image[i], name, what, when, where, how );
As mentioned in MDN you can place this script in your js for older browser support.
if (!Function.prototype.bind) {
Function.prototype.bind = function (oThis) {
if (typeof this !== "function") {
// closest thing possible to the ECMAScript 5 internal IsCallable function
throw new TypeError("Function.prototype.bind - what is trying to be bound is not callable");
}
var aArgs = Array.prototype.slice.call(arguments, 1),
fToBind = this,
fNOP = function () {},
fBound = function () {
return fToBind.apply(this instanceof fNOP && oThis
? this
: oThis,
aArgs.concat(Array.prototype.slice.call(arguments)));
};
fNOP.prototype = this.prototype;
fBound.prototype = new fNOP();
return fBound;
};
}
You need to wrap it in an anonymous function:
image[i].onmousedown = function () { whatever.call(this, name, what, when, where, how ); };
EDIT: I posted before I thought everything out. Here is a better implementation of what was in my mind: Javascript inheritance idea (part 2)
Okay, so I've seen that the following is bad
function A() {
this.variable = 7;
this.method = function() { alert(this.variable); };
}
alpha = new A();
beta = new A();
because you're duplicating the method for each instance. However, why couldn't you do:
var A = new function() {
this.variable = null;
this.method = function() { alert(this.variable); };
};
var alpha = {variable: 8};
alpha.__proto__ = A;
var beta = {variable: 9};
beta.__proto__ = A;
Then you inherit the methods without wasting memory, and you can specify new instance variables.
Of course, I've never seen this pattern, so what's the obvious reason it's not used?
I think you are looking for pure prototypical inheritance.
The ECMAScript 5th Edition standard introduced the Object.create method, this method creates an object that directly inherits from its first argument passed (which can be either null or an object).
For example:
var A = {
variable: null,
method : function () { alert(this.variable); };
};
var alpha = Object.create(A);
alpha.variable = 8; // or above `Object.create(A, {'variable': { value: 8 } });`
var beta = Object.create(A);
beta.variable = 9;
This method is available on the most recent browsers, however can be roughly emulated on an ECMAScript 3 implementation:
if (!Object.create) {
Object.create = function (o) {
if (arguments.length > 1) { throw Error('Second argument not supported'); }
if (o === null) { throw Error('Cannot set a null [[Prototype]]'); }
if (typeof o != 'object') { throw TypeError('Argument must be an object'); }
function F(){}
F.prototype = o;
return new F;
};
}
Note that there are some features that cannot be emulated on ES3, like the second argument, it expects a property descriptor like the descriptor used by the new Object.defineProperties method.
Also, Object.create allows you to create an object that doesn't inherit from any other object, by setting its [[Prototype]] to null
The obvious reason it's not used is that you're creating the objects yourself instead of letting the constructor create them. If the constructor is changed to work differently later, your code could break.
A better solution would be
function A(value) {
this.variable = value;
}
A.prototype.method = function() { alert(this.variable); };
Javascript already looks at the object's methods, then the object's prototype's methods, when figuring out what to call. So defining your method in A's prototype defines it for every A you will, or even already did, create.
The main reason that pattern is not used is that the __ proto __ is not standard. Works with firefox/chrome. But doesn't work with IE.
Also, the code you suggested doesn't have a constructor. It assumes that you'll initialize the object with the correct structure.
Given a function:
function x(arg) { return 30; }
You can call it two ways:
result = x(4);
result = new x(4);
The first returns 30, the second returns an object.
How can you detect which way the function was called inside the function itself?
Whatever your solution is, it must work with the following invocation as well:
var Z = new x();
Z.lolol = x;
Z.lolol();
All the solutions currently think the Z.lolol() is calling it as a constructor.
As of ECMAScript 6, this is possible with new.target
new.target will be set as true if the function is called with new (or with Reflect.construct, which acts like new), otherwise it's undefined.
function Foo() {
if (new.target) {
console.log('called with new');
} else {
console.log('not called with new');
}
}
new Foo(); // "called with new"
Foo(); // "not called with new"
Foo.call({}); // "not called with new"
NOTE: This is now possible in ES2015 and later. See Daniel Weiner's answer.
I don't think what you want is possible [prior to ES2015]. There simply isn't enough information available within the function to make a reliable inference.
Looking at the ECMAScript 3rd edition spec, the steps taken when new x() is called are essentially:
Create a new object
Assign its internal [[Prototype]] property to the prototype property of x
Call x as normal, passing it the new object as this
If the call to x returned an object, return it, otherwise return the new object
Nothing useful about how the function was called is made available to the executing code, so the only thing it's possible to test inside x is the this value, which is what all the answers here are doing. As you've observed, a new instance of* x when calling x as a constructor is indistinguishable from a pre-existing instance of x passed as this when calling x as a function, unless you assign a property to every new object created by x as it is constructed:
function x(y) {
var isConstructor = false;
if (this instanceof x // <- You could use arguments.callee instead of x here,
// except in in EcmaScript 5 strict mode.
&& !this.__previouslyConstructedByX) {
isConstructor = true;
this.__previouslyConstructedByX = true;
}
alert(isConstructor);
}
Obviously this is not ideal, since you now have an extra useless property on every object constructed by x that could be overwritten, but I think it's the best you can do.
(*) "instance of" is an inaccurate term but is close enough, and more concise than "object that has been created by calling x as a constructor"
1) You can check this.constructor:
function x(y)
{
if (this.constructor == x)
alert('called with new');
else
alert('called as function');
}
2) Yes, the return value is just discarded when used in the new context
NOTE: This answer was written in 2008, when javascript was still in ES3 from 1999. A lot of new functionality has been added since then, so now better solutions exists. This answer is kept for historical reasons.
The benefit of the code below is that you don't need to specify the name of the function twice and it works for anonymous functions too.
function x() {
if ( (this instanceof arguments.callee) ) {
alert("called as constructor");
} else {
alert("called as function");
}
}
Update
As claudiu have pointed out in a comment below, the above code doesn't work if you assign the constructor to the same object it has created. I have never written code that does that and have newer seen anyone else do that eighter.
Claudius example:
var Z = new x();
Z.lolol = x;
Z.lolol();
By adding a property to the object, it's possible to detect if the object has been initialized.
function x() {
if ( (this instanceof arguments.callee && !this.hasOwnProperty("__ClaudiusCornerCase")) ) {
this.__ClaudiusCornerCase=1;
alert("called as constructor");
} else {
alert("called as function");
}
}
Even the code above will break if you delete the added property. You can however overwrite it with any value you like, including undefined, and it still works. But if you delete it, it will break.
There is at this time no native support in ecmascript for detecting if a function was called as a constructor. This is the closest thing I have come up with so far, and it should work unless you delete the property.
Two ways, essentially the same under the hood. You can test what the scope of this is or you can test what this.constructor is.
If you called a method as a constructor this will be a new instance of the class, if you call the method as a method this will be the methods' context object. Similarly the constructor of an object will be the method itself if called as new, and the system Object constructor otherwise. That's clear as mud, but this should help:
var a = {};
a.foo = function ()
{
if(this==a) //'a' because the context of foo is the parent 'a'
{
//method call
}
else
{
//constructor call
}
}
var bar = function ()
{
if(this==window) //and 'window' is the default context here
{
//method call
}
else
{
//constructor call
}
}
a.baz = function ()
{
if(this.constructor==a.baz); //or whatever chain you need to reference this method
{
//constructor call
}
else
{
//method call
}
}
Checking for the instance type of the [this] within the constructor is the way to go. The problem is that without any further ado this approach is error prone. There is a solution however.
Lets say that we are dealing with function ClassA(). The rudimentary approach is:
function ClassA() {
if (this instanceof arguments.callee) {
console.log("called as a constructor");
} else {
console.log("called as a function");
}
}
There are several means that the above mentioned solution will not work as expected. Consider just these two:
var instance = new ClassA;
instance.classAFunction = ClassA;
instance.classAFunction(); // <-- this will appear as constructor call
ClassA.apply(instance); //<-- this too
To overcome these, some suggest that either a) place some information in a field on the instance, like "ConstructorFinished" and check back on it or b) keep a track of your constructed objects in a list. I am uncomfortable with both, as altering every instance of ClassA is way too invasive and expensive for a type related feature to work. Collecting all objects in a list could provide garbage collection and resource issues if ClassA will have many instances.
The way to go is to be able to control the execution of your ClassA function. The simple approach is:
function createConstructor(typeFunction) {
return typeFunction.bind({});
}
var ClassA = createConstructor(
function ClassA() {
if (this instanceof arguments.callee) {
console.log("called as a function");
return;
}
console.log("called as a constructor");
});
var instance = new ClassA();
This will effectively prevent all attempts to trick with the [this] value. A bound function will always keep its original [this] context unless you call it with the new operator.
The advanced version gives back the ability to apply the constructor on arbitrary objects. Some uses could be using the constructor as a typeconverter or providing an callable chain of base class constructors in inheritance scenarios.
function createConstructor(typeFunction) {
var result = typeFunction.bind({});
result.apply = function (ths, args) {
try {
typeFunction.inApplyMode = true;
typeFunction.apply(ths, args);
} finally {
delete typeFunction.inApplyMode;
}
};
return result;
}
var ClassA = createConstructor(
function ClassA() {
if (this instanceof arguments.callee && !arguments.callee.inApplyMode) {
console.log("called as a constructor");
} else {
console.log("called as a function");
}
});
actually the solution is very possible and simple... don't understand why so many words been written for such a tiny thing
UPDATE: thanks to TwilightSun the solution is now completed, even for the test Claudiu suggested! thank you guys!!!
function Something()
{
this.constructed;
if (Something.prototype.isPrototypeOf(this) && !this.constructed)
{
console.log("called as a c'tor"); this.constructed = true;
}
else
{
console.log("called as a function");
}
}
Something(); //"called as a function"
new Something(); //"called as a c'tor"
demonstrated here: https://jsfiddle.net/9cqtppuf/
Extending Gregs solution, this one works perfectly with the test cases you provided:
function x(y) {
if( this.constructor == arguments.callee && !this._constructed ) {
this._constructed = true;
alert('called with new');
} else {
alert('called as function');
}
}
EDIT: adding some test cases
x(4); // OK, function
var X = new x(4); // OK, new
var Z = new x(); // OK, new
Z.lolol = x;
Z.lolol(); // OK, function
var Y = x;
Y(); // OK, function
var y = new Y(); // OK, new
y.lolol = Y;
y.lolol(); // OK, function
There is no reliable way to distinguish how a function is called in JavaScript code.1
However, a function call will have this assigned to the global object, while a constructor will have this assigned to a new object. This new object cannot ever be the global object, because even if an implementation allows you to set the global object, you still haven't had the chance to do it.
You can get the global object by having a function called as a function (heh) returning this.
My intuition is that in the specification of ECMAScript 1.3, constructors that have a defined behavior for when called as a function are supposed to distinguish how they were called using this comparison:
function MyClass () {
if ( this === (function () { return this; })() ) {
// called as a function
}
else {
// called as a constructor
}
}
Anyway, anyone can just use a function's or constructor's call or apply and set this to anything. But this way, you can avoid "initializing" the global object:
function MyClass () {
if ( this === (function () { return this; })() ) {
// Maybe the caller forgot the "new" keyword
return new MyClass();
}
else {
// initialize
}
}
1. The host (aka implementation) may be able to tell the difference, if it implements the equivalent to the internal properties [[Call]] and [[Construct]]. The former is invoked for function or method expressions, while the latter is invoked for new expressions.
In my testing for http://packagesinjavascript.wordpress.com/ I found the test if (this == window) to be working cross-browser in all cases, so that's the one I ended up using.
-Stijn
Until I saw this thread I never considered that the constructor might be a property of an instance, but I think the following code covers that rare scenario.
// Store instances in a variable to compare against the current this
// Based on Tim Down's solution where instances are tracked
var Klass = (function () {
// Store references to each instance in a "class"-level closure
var instances = [];
// The actual constructor function
return function () {
if (this instanceof Klass && instances.indexOf(this) === -1) {
instances.push(this);
console.log("constructor");
} else {
console.log("not constructor");
}
};
}());
var instance = new Klass(); // "constructor"
instance.klass = Klass;
instance.klass(); // "not constructor"
For most cases I'll probably just check instanceof.
From John Resig:
function makecls() {
return function(args) {
if( this instanceof arguments.callee) {
if ( typeof this.init == "function")
this.init.apply(this, args.callee ? args : arguments)
}else{
return new arguments.callee(args);
}
};
}
var User = makecls();
User.prototype.init = function(first, last){
this.name = first + last;
};
var user = User("John", "Resig");
user.name
If you're going hackish, then instanceof is the minimum solution after new.target as by other answers. But using the instanceof solution it would fail with this example:
let inst = new x;
x.call(inst);
Combining with #TimDown solution, you can use ES6's WeakSet if you want compatibility with older ECMAScript versions to prevent putting properties inside instances. Well, WeakSet will be used in order to allow unused objects be garbage collected. new.target won't be compatible in the same source code, as it is a ES6's syntax feature. ECMAScript specifies identifiers cannot be one of the reserved words, and new is not an object, anyways.
(function factory()
{
'use strict';
var log = console.log;
function x()
{
log(isConstructing(this) ?
'Constructing' :
'Not constructing'
);
}
var isConstructing, tracks;
var hasOwnProperty = {}.hasOwnProperty;
if (typeof WeakMap === 'function')
{
tracks = new WeakSet;
isConstructing = function(inst)
{
if (inst instanceof x)
{
return tracks.has(inst) ?
false : !!tracks.add(inst);
}
return false;
}
} else {
isConstructing = function(inst)
{
return inst._constructed ?
false : inst._constructed = true;
};
}
var z = new x; // Constructing
x.call(z) // Not constructing
})();
ECMAScript 3's instanceof operator of is specified as:
11.8.6 The instanceof operator
--- The production RelationalExpression: RelationalExpression instanceof ShiftExpression is evaluated
as follows:
--- 1. Evaluate RelationalExpression.
--- 2. Call GetValue(Result(1)).
--- 3. Evaluate ShiftExpression.
--- 4. Call GetValue(Result(3)).
--- 5. If Result(4) is not an object, throw a TypeError exception.
--- 6. If Result(4) does not have a [[HasInstance]] method, throw a TypeError exception.
--- 7. Call the [[HasInstance]] method of Result(4) with parameter Result(2).
--- 8. Return Result(7).
15.3.5.3 [[HasInstance]] (V)
--- Assume F is a Function object.
--- When the [[HasInstance]] method of F is called with value V, the following steps are taken:
--- 1. If V is not an object, return false.
--- 2. Call the [[Get]] method of F with property name "prototype".
--- 3. Let O be Result(2).
--- 4. If O is not an object, throw a TypeError exception.
--- 5. Let V be the value of the [[Prototype]] property of V.
--- 6. If V is **null**, return false.
--- 7. If O and V refer to the same object or if they refer to objects joined to each other (13.1.2), return true.
--- 8. Go to step 5.
And that means it'll be recursing the left hand side value after going to its prototype until it is not an object or until it is equal to the prototype of the right hand side object with the specified [[HasInstance]] method. What means it'll check if left hand side is an instance of the right hand side, consuming all internal prototypes of the left hand side though.
function x() {
if (this instanceof x) {
/* Probably invoked as constructor */
} else return 30;
}
maybe I`m wrong but (at the cost of a parasite) the following code seems like a solution:
function x(arg) {
//console.debug('_' in this ? 'function' : 'constructor'); //WRONG!!!
//
// RIGHT(as accepted)
console.debug((this instanceof x && !('_' in this)) ? 'function' : 'constructor');
this._ = 1;
return 30;
}
var result1 = x(4), // function
result2 = new x(4), // constructor
Z = new x(); // constructor
Z.lolol = x;
Z.lolol(); // function
Although this thread is ancient, I'm surprised that nobody has mentioned that under strict mode ('use strict') a function's default this value is undefined, instead of set to global/window as before, so to check if new is not used simply test for falsey value of !this
- EG:
function ctor() { 'use strict';
if (typeof this === 'undefined')
console.log('Function called under strict mode (this == undefined)');
else if (this == (window || global))
console.log('Function called normally (this == window)');
else if (this instanceof ctor)
console.log('Function called with new (this == instance)');
return this;
}
If you test that function as-is, you will get undefined as this value, due to the 'use strict' directive at the start of the function. Of course, if already has strict mode on then it won't change if you remove the 'use strict' directive, but otherwise if you remove it the this value will be set to window or global.
If you use new to call the function then the this value will match the instanceof check (although if you checked the other things, then instance is last option so this check is not needed, and to be avoided if you want to inherit instances anyway)
function ctor() { 'use strict';
if (!this) return ctor.apply(Object.create(ctor.prototype), arguments);
console.log([this].concat([].slice.call(arguments)));
return this;
}
This will log the this value and any arguments you pass to the function to console, and return the this value. If the this value is falsey then it creates a new instance using Object.create(ctor.prototype) and uses Function.apply() to re-call the constructor with the same params but with correct instance as this. If the this value is anything other than falsey then it is assumed to be a valid instance and returned.
I believe the solution is to turn your Constructor function into a wrapper of the real Constructor function and its prototype Constructor if required. This method will work in ES5 from 2009 and also work in strict mode. In the code window below I have an example using the module pattern, to hold the real constructor and its prototype's constructor, in a closure, which is accessible through scope within the constructor(wrapper). This works because no property is added to the "this" keyword within the Constructor(wrapper) and the Constructor(wrapper).prototype is not set, so is Object by default; thus the array returned from Object.getpropertyNames will have a length equal to 0, if the new keyword has been used with the Constructor(wrapper). If true then return new Vector.
var Vector = (function() {
var Vector__proto__ = function Vector() {
// Vector methods go here
}
var vector__proto__ = new Vector__proto__();;
var Vector = function(size) {
// vector properties and values go here
this.x = 0;
this.y = 0;
this.x = 0;
this.maxLen = size === undefined? -1 : size;
};
Vector.prototype = vector__proto__;
return function(size){
if ( Object.getOwnPropertyNames(this).length === 0 ) {
// the new keyword WAS USED with the wrapper constructor
return new Vector(size);
} else {
// the new keyword was NOT USED with the wrapper constructor
return;
};
};
})();
Tim Down I think is correct. I think that once you get to the point where you think you need to be able to distinguish between the two calling modes, then you should not use the "this" keyword. this is unreliable, and it could be the global object, or it could be some completely different object. the fact is, that having a function with these different modes of activation, some of which work as you intended, others do something totally wild, is undesirable. I think maybe you're trying to figure this out because of that.
There is an idiomatic way to create a constructor function that behaves the same no matter how it's called. whether it's like Thing(), new Thing(), or foo.Thing(). It goes like this:
function Thing () {
var that = Object.create(Thing.prototype);
that.foo="bar";
that.bar="baz";
return that;
}
where Object.create is a new ecmascript 5 standard method which can be implemented in regular javascript like this:
if(!Object.create) {
Object.create = function(Function){
// WebReflection Revision
return function(Object){
Function.prototype = Object;
return new Function;
}}(function(){});
}
Object.create will take an object as a parameter, and return a new object with that passed in object as its prototype.
If however, you really are trying to make a function behave differently depending on how it's called, then you are a bad person and you shouldn't write javascript code.
If you don't want to put a __previouslyConstructedByX property in the object - because it pollutes the object's public interface and could easily be overwritten - just don't return an instance of x:
function x() {
if(this instanceof x) {
console.log("You invoked the new keyword!");
return that;
}
else {
console.log("No new keyword");
return undefined;
}
}
x();
var Z = new x();
Z.lolol = x;
Z.lolol();
new Z.lolol();
Now the x function never returns an object of type x, so (I think) this instanceof x only evaluates to true when the function is invoked with the new keyword.
The downside is this effectively screws up the behaviour of instanceof - but depending on how much you use it (I don't tend to) that may not be a problem.
If you're goal is for both cases to return 30, you could return an instance of Number instead of an instance of x:
function x() {
if(this instanceof x) {
console.log("You invoked the new keyword!");
var that = {};
return new Number(30);
}
else {
console.log("No new");
return 30;
}
}
console.log(x());
var Z = new x();
console.log(Z);
Z.lolol = x;
console.log(Z.lolol());
console.log(new Z.lolol());
I had this same problem when I tried to implement a function that returns a string instead of an object.
It seems to be enough to check for the existence of "this" in the beginning of your function:
function RGB(red, green, blue) {
if (this) {
throw new Error("RGB can't be instantiated");
}
var result = "#";
result += toHex(red);
result += toHex(green);
result += toHex(blue);
function toHex(dec) {
var result = dec.toString(16);
if (result.length < 2) {
result = "0" + result;
}
return result;
}
return result;
}
Anyway, in the end I just decided to turn my RGB() pseudoclass into an rgb() function, so I just won't try to instantiate it, thus needing no safety check at all. But that would depend on what you're trying to do.
function createConstructor(func) {
return func.bind(Object.create(null));
}
var myClass = createConstructor(function myClass() {
if (this instanceof myClass) {
console.log('You used the "new" keyword');
} else {
console.log('You did NOT use the "new" keyword');
return;
}
// constructor logic here
// ...
});
On the top of the question, below code will auto-fix the issue in case function is called without new.
function Car() {
if (!(this instanceof Car)) return new Car();
this.a = 1;
console.log("Called as Constructor");
}
let c1 = new Car();
console.log(c1);
This can achieved without using ES6 new.target. You can run your code in strict mode and in this case value of this will be undefined if called without new otherwise it will be empty object.
Example::
"use strict"
function Name(){
console.log(this)
if(this){
alert("called by new")
}
else
alert("did not called using new")
}
new Name()
Use this instanceof arguments.callee (optionally replacing arguments.callee with the function it's in, which improves performance) to check if something is called as a constructor. Do not use this.constructor as that can be easily changed.