I have two <div>, one nested into the other defined like this:
<div class="wrapper">
<div class="content">
[..] Content [..]
</div>
</div>
The css:
#div.wrapper
{
width: 660px;
overflow: hidden;
float: left;
}
#div.content
{
white-space: nowrap;
}
The effect is what i want, the content lays down horizontally within the inner but is hidden when it exceeds, (i then scroll it with jQuery).
Since I don't know the content of .content (nor it is predictable), I need to know the real width of it (defined by the content), but both .width() and .innerWidth() give me the same result that is 660 when first called (like the container div) and 660 + x when I call it after having scrolled it by setting a negative margin-left (x is the left shift set with the margin).
How to get the real, content dependent width of the element? Thanks
Divs by default take full width in their parent, so width will always be the width of the parent.
If you don't want that, you would use
#div.content
{
white-space: nowrap;
display: inline-block;
}
or possibly
#div.content
{
white-space: nowrap;
float: left;
}
as to turn the #div.content element into an inline or float element respectively, which only takes up as much space as it needs (i.e. not necessarily all the space that the parent provides). So that should work!
I wasn't sure why you used #div.* since that would mean you have an element with id div. If you mean to specify a div with a certain class, use div.class-name. Since a div resides as a child inside another div, it takes its parent's width. Setting the float to left allows it to expand outside this limit.
div.wrapper {
width: 660px;
overflow: hidden;
float: left;
}
div.content {
white-space: nowrap;
float: left;
}
Scrolling example: http://jsfiddle.net/9E8G7/6/
Here's a quick jQuery example I wrote, can be improved I'm sure. It scrolls until it reaches the end of the content.
$(document).ready(function(){
var content = $('.content');
var margin = 0;
var scrollFunc = function() {
margin--;
content.css('margin-left', margin);
var diff = content.width() - $('.wrapper').width();
if (margin > -diff) {
var scroll = setTimeout(scrollFunc, 10);
}
};
scrollFunc();
});
Did you try: jQuery.outerWidth(), I mean $(yourelement).outerWidth()?
Have you tried element.offsetWidth?
Related
I am trying to place a position: absolute div inside a scrolling div and make it stay on the left when scrolling left or right. This is because I want the div to move like one unit (when scrolling left, right, top, bottom). It's working great on screen that lower then 2K but on HD screens (ie. 2k, 3k, 4k...) the child div is jumping around and looks bad.
Is there a better way to do it? What change should I make to the CSS for HD screens?
#parent {
overflow: auto;
width: 100%;
height: 100%;
position: relative;
}
#child {
overflow: hidden;
width: 20%;
height: 100%;
z-index:1;
position: absolute;
}
<div id="parent">
<div id="child"></div>
</div>
$("#parent").on('scroll', function (event) {
$("#child")[0].style.marginLeft = this.scrollLeft+"px";
});
You can use jQuery's css function to set the value. And use the parent element as jQuery object to use scrollLeft() function:
$("#parent").on("scroll", function() {
$("#child").css("margin-left", $(this).scrollLeft() + "px");
});
But I would not use jQuery for this at all. Why not use a fixed position in css for this? Like in this example. It should not flicker on any screen.
I have a situation where I need to make a div the same size as an absolutely positioned sidebar. I sorted that using this bit of jQuery;
$('#main').height('auto');
top_height = $('.toolbar').outerHeight();
side_height = $('#RightSideBar').height();
body_height = $('#main').innerHeight();
console.log(body_height + ' ' + side_height);
if (body_height < side_height){
$('#main').height(side_height + top_height);
}
else {
$('#main').height(body_height);
}
I have ran into a new problem due to the dynamic nature of some content on some pages. Since the height of #main is absolutely set if the size of its content increases the size of the div will not increase with it and vice versa.
I need the div to be set the same height as the sidebar and remain fluid with its content. So the div would increase and decrease in height up to the height of the sidebar.
I hope that is easily understandable, if its not please say so.
instead of setting the height of #main with your calculations, try setting the min-height:
if (body_height < side_height){
$('#main').css('min-height', side_height + top_height);
}
else {
$('#main').css('min-height', body_height);
}
You can do this without javascript. You need a relative positioned parent that will auto size to side bar and then an absolute positioned div that adopts 100% height of parent. Never is there a set height, always fluid.
DEMO http://jsfiddle.net/nSBaA/1/
#wrapper {
position: relative;
}
#main {
position: absolute;
height: 100%;
width: 70%;
}
#sidebar {
float: right;
width: 20%;
}
I have a page, where I'm showing images side by side according to the category they belong to, each image array begins with the category it belongs to. Images vary in their width & height, but are put into a div with an absolute height of 330px.
CSS:
.front-index {
margin: 0 1em 0 2em;
}
.front-work {
margin: 0 2em 2em 0;
display: table;
width: 66px;
position: relative;
height: 330px;
background-color:#f0f0f0;
}
.front-work img {
margin: .3em 0 .3em 0;
}
.wraptocenter {
display: table-cell;
text-align: center;
vertical-align: middle;
}
.wraptocenter * {
vertical-align: middle;
}
.front-index,
.front-work {
float: left;
}
HTML:
<div class="front-index"><p>How to get<br /> this text on the same line with<br /> yellow image on the right?</p></div>
<div class="front-work">
<div class="wraptocenter">
<img width="162" height="250" src="http://images.fanpop.com/images/image_uploads/Yellow-Wallpaper-yellow-646738_800_600.jpg"/>
</div>
</div>
<div class="front-work">
<div class="wraptocenter">
<img width="250" height="166" src="http://www.takenseriouslyamusing.com/wp-content/uploads/2012/08/Blue.png"/>
</div>
</div>
…
JSFIDDLE: http://jsfiddle.net/rCAKa/9/
I'd like to align the text to the same line as the first image on the right.
What I had in mind, is that may-be this should be done in jquery. Ie. somehow measure the image distance from the top inside the .front-work div and then assign the value to the .front-index div as an inline code (top: whatever px ).
Maybe someone of you have faced this kind of problem and know a solution to this kind of problem? CSS or JS.
In my humble opinion I don't think that what you're doing is possible through CSS - it requires some simple JavaScript trickery because you have to know the relative position (from the top of the container) of the first image on the right in order to position the text - something which CSS isn't quite designed for.
The strategy in JS would be:
Loop through each element with text that you want to position
Fetch the vertical top offset of the first image to the right (relative to containing parent)
Set top padding matching to top position of image. Alternatively, you can set the top position, paddings or margins of the child elements, or other ways to reposition the text.
$(document).ready(function() {
$(".front-index").each(function() {
var fromTop = $(this).next().find("img").position().top;
$(this).css({
"padding-top":fromTop
});
});
});
I have forked your fiddle, and you can see it in action here - http://jsfiddle.net/teddyrised/LT54V/1/
p/s: On a related note, .wraptocenter * { } is probably not the best (as in, most efficient) selector out there, because if you have many child elements in the element (who may or may have even more child elements), CSS will have to iterate through all of them. Instead, try using .wraptocenter > * { } or just .wraptocenter img { } :)
I first tried to solve the problem using css. After a while I figured out the following logics:
Create a div with the same height as the cell on the right with the display set as table
Make a table-cell div in the first one that centers vertically
In this div make another subdiv with the same height as the image.
The HTML code is then this:
<div class="front-index">
<div class="front-index-inner">
<div style="height:250px;">
<p>How to get<br /> this text on the same line with<br /> yellow image on the right?</p>
</div>
</div>
</div>
and as my CSS part this:
.front-index {
margin: 0 1em 0 2em;
display: table;
height: 330px;
overflow: hidden;
}
.front-index-inner {
display: table-cell;
width: 100%;
vertical-align: middle;
}
You can see the result over here: http://jsfiddle.net/rCAKa/10/
I hope this brings a solution to you that is clear, understandable and useful.
Greetings,
Jef
I have a div with some text inside and absolute position. I can set the left or the right, but is there a way to set the center, so Div's text would expand in both directions.
So far I could only think about creating exstremly long div and centering text inside.
If your div is positioned absolutely, you can simply set it's left property so that it's centered.
Example:
HTML:
<div class="outer">
<div class="inner">Some text...</div>
</div>
CSS:
.outer {
position: relative;
width: 900px;
}
.inner {
position: absolute;
width: 500px;
top: 0;
left: 200px;
}
If you don't know the width of the inner element, you'll have to rely on javascript.
Here's an example using jQuery:
var $el = $('.inner');
$el.css('left',
( $el.parent().width() - $el.width() ) / 2
);
and here's the fiddle: http://jsfiddle.net/aa93G/ . Play around with the text inside .inner, and you'll see that the text stays centered.
to centralize inner text and inline elements use text-align: center in the parent element.
If you're dealing with block elements, you should use margin: auto in the element itself. but you must first set a width for the element, otherwise it will just occupy the whole width of the parent.
I have a .wall div with a some .toy divs inside it. I want to arrange the toys inside the wall. float:left property has done it for me nicely.
Now the problem is I want to add position:absolute for the toy divs to make it draggable later. How can I do this either via Javascript or via CSS?
Applying position:absolute, all toys will come to the top left corner of the wall overlying and hiding each other.
The width and height of the wall is constant but the width and height of the toys is variable, also the number of toy divs is dynamic and as the number increases toys need to arrange as rows.
Any suggessions will be helpful, please note the I can not avoid the use of position:absolute for dragging.
<script type="text/javascript" src="jquery-1.4.2.min.js"></script>
<style>
body{
text-align:center;
}
.clearfix{
clear:both;
}
.wall {
border: 5px solid #cde;
margin:auto;
width:200px;
padding:10px;
}
.toy{
background-color: #BBCCEE;
border:1px solid #8899BB;
margin:5px;
width: auto;
padding:5px;
float:left;
}
.tall{
padding-top:10px;
}
</style>
<script>
$(document).ready(function() {
$('.toy').each(function(index) {
var position = $(this).offset();
var prevPosition = $(this).prev().offset();
$(this).css({
//top: position.top,
//left:position.left,
//position:'absolute',
});
});
});
</script>
<div class='wall'>
<div class='toy'>T1</div>
<div class='toy'>T2</div>
<div class='toy'>T3333333</div>
<div class='toy'>T4</div>
<div class='toy'>T5</div>
<div class='toy tall'>T6</div>
<div class='toy'>T7</div>
<div class='toy'>T8</div>
<div class='clearfix'></div>
</div>
Here is the code at JSBin.
Add
position:relative
To the wall div
I am working on a website that does exactly that (sorry for the non-english stuff):
http://moveit.canassa.com/cartao/4/
The link is now broken but here is a jsFiddle that shows what I am talking about:
http://jsfiddle.net/canassa/Z9N3L/
The "toy" div is using a position absolute:
.toy{
width: 100px;
height: 25px;
position: absolute;
z-index: 0;
}
The problem with the position absolute is that the toy will be relative to page and not the "wall" container, in order to fix that you must make the wall container relative:
#wall{
position: relative;
overflow: hidden;
}
The overflow:hidden is also a nice trick that I found. It makes the draggable objects go "under" the wall container.
There is no big secret to make it draggable, using jQuery:
// Creates a toy div inside the wall
$(MV.wallId).append('<div class="toy" id="' + this.getId() + '"></div>');
box = this.getBox(); // return the "toy" that I've just created.
$('#' + this.getId()).draggable(); // make it draggable
This would be a lot easier if you just used the jQueryUI .draggable(). It doesn't require the elements to be positioned.
If you're dead set on using this plugin, then you have the right idea. Let the elements flow into place and then calculate their position and set position: absolute and whatever the left and top end up being at runtime.
Set the .wall to be position: relative. Then:
var tPos;
$('.toy').each(function(index) {
tPos = $(this).position();
$(this).css({
left: tPos.left,
top: tPos.top
});
};
$('.toy').css({
position: absolute
});
The height of the .wall and the width of each .toy collapse when the toys are absolutely positioned but you can just add a few more lines to get/set their width and height in the above .each loops.
This obviously doesn't work if new toys can be added dynamically without a page reload as you suggest. To handle that you could switch them back to position: relative, add the new one, get the position of the new one in the flow, then set the position and switch back to position: absolute. Any elements that had been dragged out of place would be gaps in the flow, but I don't see any easy way around that.
the element in that the absolute should be positioned, must have the style position:relative.
(must be a parent of the target element)
The container div for every .toy must have position:relative set. That way, the position 0 for its children elements becomes its top left corner. Like this:
<div class="parent">
<div class="child">Blah.</div>
<div class="child">Blah.</div>
</div>
And:
.parent {
position: relative;
}
.child {
position: absolute;
left: 10px; /* This is 10 pixels from the parents left side */
top: 10px; /* This is 10 pixels from the parents top side */
}
Good luck.