I'm passing as parameter an id to a javascript function, because it comes from UI, it's left zero padded. but it seems to have (maybe) "strange" behaviour?
console.log(0000020948); //20948
console.log(0000022115); //9293 which is 22115's octal
console.log(parseInt(0000022115, 10)); // 9293 which is 22115's octal
console.log(0000033959); //33959
console.log(20948); //20948
console.log(22115); //22115
console.log(33959); //33959
how can I make sure they are parsing to right numebr they are? (decimal)
EDIT:
just make it clearer:
those numbers come from the server and are zero padded strings. and I'm making a delete button for each one.
like:
function printDelButton(value){
console.log(typeof value); //output string
return '<img src="images/del.png">'
}
and
function printDelButton(value){
console.log(typeof value); //output numeric
console.log(value); //here output as octal .... :S
}
I tried :
console.log(parseInt(0000022115, 10)); // 9293 which is 22115's octal
and still parsing as Octal
If you receive your parameters as string objects, it should work to use
parseInt(string, 10)
to interpret strings as decimal, even if they are beginning with 0.
In your test, you pass the parseInt method a number, not a string, maybe that's why it doesn't return the expected result.
Try
parseInt('0000022115', 10)
instead of
parseInt(0000022115, 10)
that does return 221115 for me.
If you start it with a 0, it's interpreted as an Octal number.
See http://www.hunlock.com/blogs/The_Complete_Javascript_Number_Reference#quickIDX2
Note the article's warning here:
You should never precede a number with a zero unless you are
specifically looking for an octal conversion!
Consider looking here for ideas on removing the leadings 0s:
Truncate leading zeros of a string in Javascript
Leading 0s indicate that the number is octal.
parseInt parses a string containing a number.
parseInt(0000022115, 10) passes a numeric literal. The literal is parsed in octal by the JS interpreter, so you're passing a raw numeric value to parseInt.
Unless you can intercept a string version of this number, you're out of luck.
That being said, if you can get a string version of your octal (calling toString() won't help), this will work:
parseInt(variable_string.replace(/^0+/, ''), 10);
Try
/^[0]*([1-9]\d)/.exec(numberFromUI)[0]
That should give you just the numbers stripping the zeros (if you have to support decimals, you'll need to edit to account for the '.', and of course ',' is fun too... and I really hope you don't have to handle all the crazy different ways Europeans write numbers! )
If number came from server as zero padded string then use +"0000022115"
console.log(+"0000022115")
if (021 < 019) console.log('Paradox');
JS treat zero padded numbers like octal only if they are valid octal - if not then it treat it as decimal. To not allow paradox 'use strict' mode
'use strict'
if (021 < 019) console.log('Paradox');
Related
I realized that in javascript all 101/100, "101"/100, 101/"100" and "101"/"100" result in 1.01 (checked on Chrome, FF and IE11). But I cannot find a piece of documentation regarding this behaviour.
Therefore my question is if it is (cross-browser) safe to use this feature, and if it is a good practice to do so (or rather to use parseInt before division if the variable can be a string)?
When you use / on strings, the strings are implicitly converted to numbers and then division operation is performed.
This may work in all browsers, but it's always good practice to convert to number explicitly using parseInt or parseFloat or other method.
parseInt("101", 10) / 100
Or
parseFloat("101") / 100
ECMAScript Specifications for Division Operator
Therefore my question is if it is (cross-browser) safe to use this feature...
It depends on your definition of "safe." With the division operator, yes, it's specified behavior: Each operand is converted (implicitly coerced) to a number, and then numeric division is done.
But beware of generalizing this too far. You'll be okay with /, *, and - but it will bite you on +, because if either operand to + is a string, + does string concatenation, not addition.
Another way that it may or may not be "safe" depending on your point of view is the implicit coercion: It uses the browser's JavaScript engine's rules for converting strings to numbers. Some older browsers went beyond the specification (which they were allowed to in the past) and treated numbers starting with a 0 as octal (base 8) rather than decimal. Naturally, end users who type in, say, "0123" as a number probably mean the number 123, not the number 83 (123 in octal = 83 decimal). JavaScript engines are no longer allowed to do that, but some older ones do.
In general, it's probably best to explicitly coerce or convert those operands. Your choices for doing so:
The unary + operator: value = +value will coerce the string to a number using the JavaScript engine's standard rules for that. Any non-digits in the string (other than the e for scientific notation) make the result NaN. Also, +"" is 0, which may not be intuitive.
The Number function: value = Number(value). Does the same thing as +.
The parseInt function, usually with a radix (number base): value = parseInt(value, 10). The downside here is that parseInt converts any number it finds at the beginning of the string but ignores non-digits later in the string, so parseInt("100asdf", 10) is 100, not NaN. As the name implies, parseInt parses only a whole number.
The parseFloat function: value = parseFloat(value). Allows fractional values, and always works in decimal (never octal or hex). Does the same thing parseInt does with garbage at the end of the string, parseFloat("123.34alksdjf") is 123.34.
So, pick your tool to suit your use case. :-)
Type coercion is at play here. Quoting #Barmar's answer from What exactly is Type Coercion in Javascript?
Type coercion means that when the operands of an operator are of different types, one of them will be converted to an "equivalent" value of the other operand's type.
The reason for your observation is valid for other operations too -
1 + "2" will give you "12"
1 - "2" will give you -1
(because "-" operation on strings is not defined like division")
In the case "101/100" the operation "/" will decide the coercion, since there is no operation defined on strings with that operator "/", but is there for "numbers".
Using it is safe (at least in modern browsers) as long as you are clear how type coercion will play out in your operation.
Good day,
In my java action file, I have a list:
protected ArrayList< String > deletedCorpRegisteredAccountRefNo = new ArrayList< String >( );
And then I put in some data inside this ArrayList, and print it out:
System.out.println( "deletedCorpRegisteredAccountRefNo : "+
deletedCorpRegisteredAccountRefNo );
And the result display correctly:
deletedCorpRegisteredAccountRefNo : [0000000000000234324, 0000000000015422629]
Then I go to my jsp and my javaScript function, I tried to assign this ArrayList value to a var call refNoList, and print out:
var refNoList = ${actionBean.deletedCorpRegisteredAccountRefNo};
console.log(refNoList);
I am expected I will see my browser console will print out something like what I see in Java System.out.println(), but I get another result:
[80084, 15422629]
The 15422629 is still acceptable, because maybe JavaScript auto trim the 0. But not understand why 0000000000000234324 will become 80084, this is totally different.
I try to google to find what is the root cause, but fail to get it, I think I am asking the wrong question in Google.
Kindly advise.
If a JavaScript number starts with zero, it can be interpreted as an octal value. And
var x = 0234324;
console.log(x);
this writes out 80084, because in decimal, this is the same value, as 234324 in octal.
You need to trim the trailing zeroes from the strings, and it will work as you want it to.
Other number definitions
In JavaScript the numbers can be interpreted as binary, octal, decimal or hexadecimal. Here a little list of different literals:
123 - normal decimal
0123 - octal: decimal value is 83
0x123 - hexadecimal: decimal value is 291
0o123 - octal: decimal value is 123
0b101 - binary: decimal value is 5
The problem with the second example (0123) is that it is only interpreted as octal when it is possible. E.g. 09123 and 081 will be interpreted as decimal. Moral of the story, you should not depend on this behaviour, if you need an octal, use 0o explicitely, if you need decimals, trim those zeroes.
Fixing the issue
To parse the number as a decimal, no matter what, you can simply give the radix value as a parameter to parseInt(number, radix):
var x = "000000123";
console.log(parseInt(x, 10)); // prints out 123
I have just observed that the parseInt function doesn't take care about the decimals in case of integers (numbers containing the e character).
Let's take an example: -3.67394039744206e-15
> parseInt(-3.67394039744206e-15)
-3
> -3.67394039744206e-15.toFixed(19)
-3.6739e-15
> -3.67394039744206e-15.toFixed(2)
-0
> Math.round(-3.67394039744206e-15)
0
I expected that the parseInt will also return 0. What's going on at lower level? Why does parseInt return 3 in this case (some snippets from the source code would be appreciated)?
In this example I'm using node v0.12.1, but I expect same to happen in browser and other JavaScript engines.
I think the reason is parseInt converts the passed value to string by calling ToString which will return "-3.67394039744206e-15", then parses it so it will consider -3 and will return it.
The mdn documentation
The parseInt function converts its first argument to a string, parses
it, and returns an integer or NaN
parseInt(-3.67394039744206e-15) === -3
The parseInt function expects a string as the first argument. JavaScript will call toString method behind the scene if the argument is not a string. So the expression is evaluated as follows:
(-3.67394039744206e-15).toString()
// "-3.67394039744206e-15"
parseInt("-3.67394039744206e-15")
// -3
-3.67394039744206e-15.toFixed(19) === -3.6739e-15
This expression is parsed as:
Unary - operator
The number literal 3.67394039744206e-15
.toFixed() -- property accessor, property name and function invocation
The way number literals are parsed is described here. Interestingly, +/- are not part of the number literal. So we have:
// property accessor has higher precedence than unary - operator
3.67394039744206e-15.toFixed(19)
// "0.0000000000000036739"
-"0.0000000000000036739"
// -3.6739e-15
Likewise for -3.67394039744206e-15.toFixed(2):
3.67394039744206e-15.toFixed(2)
// "0.00"
-"0.00"
// -0
If the parsed string (stripped of +/- sign) contains any character that is not a radix digit (10 in your case), then a substring is created containing all the other characters before such character discarding those unrecognized characters.
In the case of -3.67394039744206e-15, the conversion starts and the radix is determined as base 10 -> The conversion happens till it encounters '.' which is not a valid character in base 10 - Thus, effectively, the conversion happens for 3 which gives the value 3 and then the sign is applied, thus -3.
For implementation logic - http://www.ecma-international.org/ecma-262/5.1/#sec-15.1.2.2
More Examples -
alert(parseInt("2711e2", 16));
alert(parseInt("2711e2", 10));
TO note:
The radix starts out at base 10.
If the first character is a '0', it switches to base 8.
If the next character is an 'x', it switches to base 16.
It tries to parse strings to integers. My suspicion is that your floats are first getting casted to strings. Then rather than parsing the whole value then rounding, it uses a character by character parsing function and will stop when it gets to the first decimal point ignoring any decimal places or exponents.
Some examples here http://www.w3schools.com/jsref/jsref_parseint.asp
parseInt has the purpose of parsing a string and not a number:
The parseInt() function parses a string argument and returns an
integer of the specified radix (the base in mathematical numeral
systems).
And parseInt calls the function ToString wherein all the non numerical characters are ignored.
You can use Math.round, which also parses strings, and rounds a number to the nearest integer:
Math.round("12.2e-2") === 0 //true
Math.round("12.2e-2") may round up or down based on the value. Hence may cause issues.
new Number("3.2343e-10").toFixed(0) may solve the issue.
Looks like you try to calculate using parseFloat, this will give you the correct answer.
parseInt as it says, returns an integer, whereas parseFloat returns a floating-point number or exponential number:
parseInt(-3.67394039744206e-15) = -3
parseFloat(-3.67394039744206e-15) = -3.67394039744206e-15
console.log('parseInt(-3.67394039744206e-15) = ' , parseInt(-3.67394039744206e-15));
console.log('parseFloat(-3.67394039744206e-15) = ',parseFloat(-3.67394039744206e-15));
I have an application that reads in a number via ajax, the number is hexadecimal and I parse it and convert to decimal.
The numbers come in through a wireless serial link and are not 100% reliable so I need to check them before I start processing the data. The numbers take the form ****025781610403e5**** for example. The **** is just a way of checking the start and end of the number that I have used in the past with non web based projects and could be changed.
Anyway to my question at last: As part of error checking I thought I would check for NaN as I do get NaN errors when I have been testing but while *1234 gives a positive NaN 12**34 does not, why is that? and what else can I do to test?
Here is some of the code I have used, please note I am fairly new to javascript.
function readSliceConvert()
{
functionReadForm()
testVal = hexString.slice(4,18);
document.getElementById("battDb4").innerHTML=testVal;
testNum1 = h2d(testVal)
document.getElementById("battDb5").innerHTML=testNum1.toString();
testNum2 = parseInt(testVal);
document.getElementById("battDb6").innerHTML=testNum2.toString();
if (isNaN(testNum2))
{
errorCount++;
document.getElementById("battDb3").innerHTML=errorCount.toString();
document.getElementById("battDb4").innerHTML=testVal;
return;
}
}
That's because you are using parseInt, it will silently ignore characters at the end of the string when there are some digit in the beginning of the string that it can parse.
I don't know what your h2d function is doing, but it seems that you are converting the hexadecimal string to a number, then to a string in decimal form, then back to a number. I don't see any reason why the output of parsing the hexadecimal string couldn't be a number.
For example like this, returning null if the parsing fails:
function h2i(str) {
var num = 0;
var digits = "0123456789abcdef";
str = str.toLowerCase();
for (var i = 0; i < str.length; i++) {
var n = digits.indexOf(str.substr(i, 1));
if (n == -1) return null;
num = num * 16 + n;
}
return num;
}
Demo: http://jsfiddle.net/Guffa/6yAaP/
Usage:
testVal = hexString.slice(4,18);
document.getElementById("battDb4").innerHTML = testVal;
testNum = h2i(testVal)
document.getElementById("battDb5").innerHTML = testNum.toString();
if (testNum == null)
{
errorCount++;
document.getElementById("battDb3").innerHTML = errorCount.toString();
document.getElementById("battDb4").innerHTML = testVal;
return;
}
Do you know what parseInt() does?
From MDN
parseInt is a top-level function and is not associated with any
object.
The parseInt function converts its first argument to a string, parses
it, and returns an integer or NaN. If not NaN, the returned value will
be the decimal integer representation of the first argument taken as a
number in the specified radix (base). For example, a radix of 10
indicates to convert from a decimal number, 8 octal, 16 hexadecimal,
and so on. For radices above 10, the letters of the alphabet indicate
numerals greater than 9. For example, for hexadecimal numbers (base
16), A through F are used.
If parseInt encounters a character that is not a numeral in the
specified radix, it ignores it and all succeeding characters and
returns the integer value parsed up to that point. parseInt truncates
numbers to integer values. Leading and trailing spaces are allowed.
Run the code in the console
console.log( parseInt("12**34",10) );
So you are running isNaN against a number since parseInt returns 12.
When you have the * as the first character, there are no leading numbers to return.
console.log( parseInt("*1234",10) );
You're seeing weird behaviour because isNan is broken (see the mozilla docs for details).
A better way to test your data is correctly formatted would be a quick regular expression, like serial.test(/^\d+$/), which will succeed if the entire serial is entirely numeric, or serial.test(/^\*{4}\d+\*{4}$/) which will succeed if the serial is four asterisks, followed by one or more number, followed by another four asterisks.
Update: #Guffa's answer is correct, and should be accepted, but I'll leave this here as I think there's a valid argument in the bigger picture that you could better accomplish what you're trying to do with a regular expression.
Running test on the string executes the supplied regular expression, and returns true if it matches the string.
Regular expressions are just patterns describing text, which can be incredibly complex or as simple as the example I've given (\d+ means match a number (\d) one or more times (+), with anchors for the beginning (^) and end ($) of the string to indicate that we want to match the whole string, not just part of it. They're ridiculously useful, so it's almost certainly worth taking the time to learn the basics of how they work, and expand you knowledge over time. There's a great tutorial on regular-expressions.info that'll get you started in no time.
i am using eval to convert string decimals to decimals.
eval("000451.01");
When i am using the above statement javascript it throws exception 'expected ;'
and when using eval("000451"); it gives me a different result.
anyone has got any idea??
You should not use eval to parse numbers; it will be orders of magnitude slower than normal methods.
Instead, you should use the parseFloat function. like this: parseFloat("000451.01").
The reason you're getting the error is that Javascript treats numbers that begin with 0 as octal numbers, which cannot have decimals.
If you want to parse an integer, call parseInt, and make sure to give a second parameter of 10 to force it to parse base 10 numbers, or you'll get the same problem.
In Javascript, a token starting with zero is an integer literal in base 8. 000451 in base 8 is 297 in base 10, and 000451.01 is parsed as int(297) dot int(1) instead of a single number literal.
Remove the initial zeros and it should work.
Numbers starting with a zero are interpreted as octal numbers. But octal numbers are only integers and not floating point numbers. So try this:
eval("451.01")
But it would be better if you use the parseFloat function:
parseFloat("000451.01")