I have two websites (ASP.NET MVC 3, but I don't think that's very important). The first one has a button; when the user clicks that button, the site needs to make a POST call to the second website and display the result in a popup. The result is a wizard of sorts - it has several steps that require clicking buttons. The final step should close the popup.
My main problem is: how can I make the popup AND the POST? I can do a POST from the code-behind in my first site, but if I just display the resulting HTML in the popup window (replacing its content or something), the browser still knows that the page came from the first site, so the next button click tries to go to the first site. I need the popup to know its contents came from the second site.
Is this possible?
View Site A in browser. POST to Site B. Site B sends minimal HTML to browser, and that HTML creates the popup.
Does that help? Can clarify further if needed.
Related
I have just seen a website that can create a link to any website and display a modal when the link is clicked on someone else website. I was just curious if anyone knows how this is done?
Here's the test link that does this:
https://twitter.com/workladuk/status/955752813333766144
Here's how this scheme works:
Notice that clicking on the link in the tweet mentioned in your comment (seen at https://twitter.com/workladuk/status/955752813333766144) doesn't actually take you to StackOverflow, even though it appears to point to this article.
It takes you to http://readr.me/vc-25, a totally different site. This is clear from the browser address bar.
By inspecting the HTML of that page using the browser developer tools, we can see that it actually is a totally different page containing an overlay with the signup form, and also an iframe containing the page the user was hoping to visit, giving the illusion that they're on the page and just need to close the popup to view it. Once they do close the popup, it actually makes a whole new HTTP request and redirects the user to the real page.
Interestingly, this was even more obvious given the example you used, because when going to the site with the signup form, the StackOverflow page displayed underneath it showed I was not signed in, even though I was signed in to SO in other tabs in the browser. This will be because running it in an iframe caused it to be run in a separate session, in which I was not signed in. This was a another big clue to show that I was not on the real Stackoverflow page.
So to be clear, it is absolutely not making a popup appear on another website, because that's impossible without hacking it. Instead it's actually creating another page containing the signup form, redirecting the user to that page and embedding the "real" page within that to create an illusion.
I am new to angularjs. I have a requirement which says that a flash page needs to appear before the main page is displayed which would look something like this,
Only on click of the button, I should be able to navigate to the main page. Please note that I need to be displaying a HTML page and not alert.
I have just started working with Oracle APEX and would like users to be able to download reports from my application.The problem is I have a number of reports which have a large number of rows. Each time a user clicks on a page tab, the page is resubmitted and the query for the reports are executed again. This results in a lot of delay and is becoming frustrating for the users!
Is it possible to stop APEX from resubmitting the page until the user clicks a refresh button or is it possible to stop the query for reports from executing everytime the user clicks on a page tab?
To prevent submitting you can change the page template. Open page properties, in the section Shared Components find Templates. Near the word Page you will see a link to its template. Follow this link, then find a section Standard Tab Attributes. In the field Current Tab you will see something like this:
<li>#TAB_LABEL##TAB_INLINE_EDIT#</li>
Change this value to:
<li><a class="active">#TAB_LABEL#</a>#TAB_INLINE_EDIT#</li>
After that an active item in a menu will be displayed as a static text, not as a link.
All pages with this page template will have this behavior. If you don't need to change behavior of all pages: before changing template make copy of it, change the copy and choose the new template in a page properties.
Have you tried with the conditions?? I pretty new with Apex too, I had a similar problem, what I did was put conditions to the buttoms and regions.
After that I good a nice result. Hope it helps you.
Good luck
I am making a blog app in Django and I want to do the following things
When the user submits the preview button I want to open the partially completed blog in a new tab in the same window.
Secondly if the user does not close the tab and again presses preview button, I want to display the updated blog in the tab which was previously opened.
How can I do this?
Edit:
As told in the answer below I am trying to use this code snippet to open it in a new window, but this does not work
<script>
var current_link = $(location).attr('href');
$('.preview_button').onClick(function() {
window.open(current_link,'preview_tab');
});
</script>
Also I currently have 3 submit buttons and I want to provide this feature only for 1 submit button i.e. preview So I cannot directly do (#form).onSubmit. For the the other two buttons, one updates the content via Ajax and the other redirects to a new page.
Try using a Javascript onSubmit to open the appropriate preview page with window.open, passing a name as the second parameter. It does almost exactly that. (If you want to support having different preview tabs associated with different editing tabs, include something in the name based on a tab ID of some kind -- maybe the article ID plus a random number, or something.)
You'll have to also send the updated content into the server via AJAX.
I am planning to create some dynamic content in a Facebook tab for my fan page. It should have content displayed if the visitor is not a fan, and then upon them clicking the Like button, changing the content to display hidden carrots (metaphorically). Is it possible to capture the event of the click on the Like button from inside the iframe?
On a Facebook fan page, when the user clicks the Like button, the whole page gets reloaded and Facebook sends an HTTP post to your website with a parameter called signed_request that you would need to decode and look at with server code, not javascript. The code to decode it will obviously vary depending on what language you are using, but the process is documented on Facebooks site. Once decoded, you will need to look at the page.liked value.