setInterval() only running function once - javascript

I want to periodically query a PHP script for new messages. To do so, I'm using the setInterval() function and AJAX.
$(document).ready(function(){
var queryInterval = 1000; /* How fast we query for new messages */
setInterval(getMessages(), queryInterval);
function getMessages() {
console.log("tick");
}
});
However, when I look at the Javascript console, I'm only seeing "tick" once. I've made sure that the console doesn't ignore any more logs of the same strings, so if the code was working properly it should show "tick" in the console every second.
Anyone know what could be going wrong here?

Change:
setInterval(getMessages(), queryInterval);
To:
setInterval(getMessages, queryInterval);

Actually, setInterval isn't running getMessages at all (not even once). setInterval expects a reference to a function, but you're executing the getMessages function immediately and passing its return value to setInterval (which is undefined). That's what the parens after getMessage do.
Pass a reference to setInterval like this:
setInterval(getMessages, queryInterval);
If this is the only place that getMessages is used, then you could also write it like this:
setInterval(function() {
console.log("tick");
}, queryInterval);

Remove the () after getMessage

This calls getMessages, not schedules it. Remove the parenthesis.
setInterval(getMessages(), queryInterval);
setInterval(getMessages, queryInterval);

Although others have already covered this ground above, both window.setTimeout() and window.setInterval() require function references. Your code provides, instead, the return value from a function invocation.
When you wish to call, or invoke, a JavaScript function, you write, as expected:
DoMyfunction();
The JavaScript engine will execute that function upon encountering that line.
However, what setTimeout() and setInterval() require, is a reference to the function object corresponding to your function. Which you obtain via the following, and similar means:
myFunc = DoMyFunction;
That line copies a reference to the function object corresponding to DoMyFunction() into a new variable. Which you can then pass to setInterval() and setTimeout(), viz:
discard = window.setTimeout(myFunc, 1000);
That line above will direct the JavaScript engine to execute your intended function (namely DoMyFunction()) once, after 1 second has elapsed, and:
discard = window.setInterval(myFunc, 1000);
will direct the JavaScript engine to execute your intended function repeatedly, once every second.
You could, of course, achieve the same effect, without using a new variable, simply as follows:
discard = window.setTimeout(DoMyFunction, 1000);
etc.
If, however, you make the mistake of using:
discard = window.setTimeout(DoMyFunction(), 1000);
what happens instead is that DoMyFunction() is executed, and any return parameter arising therefrom is then passed to the window.setTimeout() function. Since window.setTimeout() is expecting a function object reference to be passed here, and instead receives whatever your function returns (or undefined if your function returns nothing), then the internal checking performed by setTimeout() (and setInterval()) will reveal that it hasn't received a function object reference here, and simply abort silently.
A far more insidious bug, of course, could arise if DoMyFunction() actually does return a valid function object! If you've written DoMyFunction() to do this, then that function object will be passed to setTimeout() instead, and that function will be run! Of course, you could use this intentionally, and write your DoMyFunction() as a closure, returning the actual function you want setTimeout() to execute as a function object return parameter, and if you use that approach, then the form:
discard = window.setTimeout(DoMyFunction(), 1000);
will no longer be erroneous.
Remember, every JavaScript function you write in your code, when that code is parsed, is associated with a function object by the JavaScript engine. To execute the function, use:
DoMyFunction();
To reference the function object instead, use:
DoMyFunction;
Those () can make a huge amount of difference according to context, as a result of JavaScript taking this approach to differentiating between a function object reference and a function execution instruction.

Check your code line:
setInterval(getMessages(), queryInterval);
The setInterval function requires you to pass the reference to your callback function.
When you pass getMessages(), You are actually calling the function and passing its returning object to the setInterval function.
So just change your line to:
setInterval(getMessages, queryInterval);
and it will works fine!

Related

Why getting too many re-renders error in react? [duplicate]

I have the following function
function hello() {
alert("hi!");
}
Take this piece of code:
var elem = document.getElementById("btn");
elem.onclick = hello;
My question might be a bit hard to understand, so bear with me:
What EXACTLY differentiates THIS piece of code from a normal call, or what makes this piece of code require a reference to the function variable rather than a regular call? (hello();)
How can I know where I'm supposed to give a reference to the function, and when I'm supposed to actually call it?
Well, the onclick property expects a reference to a function, for it to execute when the element is clicked. Normally it's either:
element.onclick = funcRef;
or
element.onclick = function () {
funcRef();
};
(but of course, it's best to use addEventListener and attachEvent)
Notice how both of them are references to functions, not calling.
When something expects a reference, you don't call it...you assign a reference to it (first example).
When you want to specifically call a function, you call it with () (second example). But notice how in the second example, there's still a reference to a function that's assigned to onclick - it's just an anonymous function.
Probably the more important part:
Some people think you want to do this:
element.onclick = funcRef();
But that immediately executes the function (because of the ()), and assigns its return value to onclick. Unless the return value is a function, this isn't what you want.
I think the moral of the story is that when you want/need something to execute right now, you call the function. If the function is wanted for later use or needs stored, you don't call it.
Do you want it to execute NOW? Then call it.
a=hello() means "Call hello() ASAP, and set its return value to a".
On the other hand, a=hello means "a is an alias for hello. If you call a(), you get the same results as calling hello()"
You use the latter for callbacks, etc, where you want to tell the browser what you want to happen after an event occurs. For example, you may want to say "call hello() when the user clicks" (as in the example). Or, "When the AJAX query returns a result, call the callback() function on the returned data".
How can I know where I'm supposed to give a reference to the function, and when I'm supposed to actually call it?
Do you need the function to run now?
Than add the () to execute it
Do you need to function to be referenced so it is called later?
Do not add the ().
Pretty much all statements in JavaScript have a return value. Unless otherwise specified, functions in JavaScript will return undefined when called. So, the only context in which it would make sense to call your function in this assignment statement if it were to return a function:
function hello() {
return function() {
alert("hi!");
}
}
elem.onclick = hello();
A reference to your function is needed somewhere no matter how it gets called. The difference here is that you are not explicitly calling the hello function. You are assigning a reference to that function to the elem DOM node's onclick event handler so that when onclick is fired for that Node, your function gets called.
hello() means you call that function, which means the function will be executed directly.
while when you have elem.onclick = hello, this is called a callback. Where hello doesn't get executed directly but only when a certain event is fired (in this case when there's a click on the element)

Node.js passport.use() function: TypeError: Cannot read properties of undefined (reading 'use') [duplicate]

I have the following function
function hello() {
alert("hi!");
}
Take this piece of code:
var elem = document.getElementById("btn");
elem.onclick = hello;
My question might be a bit hard to understand, so bear with me:
What EXACTLY differentiates THIS piece of code from a normal call, or what makes this piece of code require a reference to the function variable rather than a regular call? (hello();)
How can I know where I'm supposed to give a reference to the function, and when I'm supposed to actually call it?
Well, the onclick property expects a reference to a function, for it to execute when the element is clicked. Normally it's either:
element.onclick = funcRef;
or
element.onclick = function () {
funcRef();
};
(but of course, it's best to use addEventListener and attachEvent)
Notice how both of them are references to functions, not calling.
When something expects a reference, you don't call it...you assign a reference to it (first example).
When you want to specifically call a function, you call it with () (second example). But notice how in the second example, there's still a reference to a function that's assigned to onclick - it's just an anonymous function.
Probably the more important part:
Some people think you want to do this:
element.onclick = funcRef();
But that immediately executes the function (because of the ()), and assigns its return value to onclick. Unless the return value is a function, this isn't what you want.
I think the moral of the story is that when you want/need something to execute right now, you call the function. If the function is wanted for later use or needs stored, you don't call it.
Do you want it to execute NOW? Then call it.
a=hello() means "Call hello() ASAP, and set its return value to a".
On the other hand, a=hello means "a is an alias for hello. If you call a(), you get the same results as calling hello()"
You use the latter for callbacks, etc, where you want to tell the browser what you want to happen after an event occurs. For example, you may want to say "call hello() when the user clicks" (as in the example). Or, "When the AJAX query returns a result, call the callback() function on the returned data".
How can I know where I'm supposed to give a reference to the function, and when I'm supposed to actually call it?
Do you need the function to run now?
Than add the () to execute it
Do you need to function to be referenced so it is called later?
Do not add the ().
Pretty much all statements in JavaScript have a return value. Unless otherwise specified, functions in JavaScript will return undefined when called. So, the only context in which it would make sense to call your function in this assignment statement if it were to return a function:
function hello() {
return function() {
alert("hi!");
}
}
elem.onclick = hello();
A reference to your function is needed somewhere no matter how it gets called. The difference here is that you are not explicitly calling the hello function. You are assigning a reference to that function to the elem DOM node's onclick event handler so that when onclick is fired for that Node, your function gets called.
hello() means you call that function, which means the function will be executed directly.
while when you have elem.onclick = hello, this is called a callback. Where hello doesn't get executed directly but only when a certain event is fired (in this case when there's a click on the element)

creating a stopwatch using javascript [duplicate]

I have the following function
function hello() {
alert("hi!");
}
Take this piece of code:
var elem = document.getElementById("btn");
elem.onclick = hello;
My question might be a bit hard to understand, so bear with me:
What EXACTLY differentiates THIS piece of code from a normal call, or what makes this piece of code require a reference to the function variable rather than a regular call? (hello();)
How can I know where I'm supposed to give a reference to the function, and when I'm supposed to actually call it?
Well, the onclick property expects a reference to a function, for it to execute when the element is clicked. Normally it's either:
element.onclick = funcRef;
or
element.onclick = function () {
funcRef();
};
(but of course, it's best to use addEventListener and attachEvent)
Notice how both of them are references to functions, not calling.
When something expects a reference, you don't call it...you assign a reference to it (first example).
When you want to specifically call a function, you call it with () (second example). But notice how in the second example, there's still a reference to a function that's assigned to onclick - it's just an anonymous function.
Probably the more important part:
Some people think you want to do this:
element.onclick = funcRef();
But that immediately executes the function (because of the ()), and assigns its return value to onclick. Unless the return value is a function, this isn't what you want.
I think the moral of the story is that when you want/need something to execute right now, you call the function. If the function is wanted for later use or needs stored, you don't call it.
Do you want it to execute NOW? Then call it.
a=hello() means "Call hello() ASAP, and set its return value to a".
On the other hand, a=hello means "a is an alias for hello. If you call a(), you get the same results as calling hello()"
You use the latter for callbacks, etc, where you want to tell the browser what you want to happen after an event occurs. For example, you may want to say "call hello() when the user clicks" (as in the example). Or, "When the AJAX query returns a result, call the callback() function on the returned data".
How can I know where I'm supposed to give a reference to the function, and when I'm supposed to actually call it?
Do you need the function to run now?
Than add the () to execute it
Do you need to function to be referenced so it is called later?
Do not add the ().
Pretty much all statements in JavaScript have a return value. Unless otherwise specified, functions in JavaScript will return undefined when called. So, the only context in which it would make sense to call your function in this assignment statement if it were to return a function:
function hello() {
return function() {
alert("hi!");
}
}
elem.onclick = hello();
A reference to your function is needed somewhere no matter how it gets called. The difference here is that you are not explicitly calling the hello function. You are assigning a reference to that function to the elem DOM node's onclick event handler so that when onclick is fired for that Node, your function gets called.
hello() means you call that function, which means the function will be executed directly.
while when you have elem.onclick = hello, this is called a callback. Where hello doesn't get executed directly but only when a certain event is fired (in this case when there's a click on the element)

JS timeout not working with function [duplicate]

Simply put...
why does
setTimeout('playNote('+currentaudio.id+', '+noteTime+')', delay);
work perfectly, calling the function after the the specified delay, but
setTimeout(playNote(currentaudio.id,noteTime), delay);
calls the function playNote all at the same time?
(these setTimeout()s are in a for loop)
or, if my explanation is too hard to read, what is the difference between the two functions?
The first form that you list works, since it will evaluate a string at the end of delay. Using eval() is generally not a good idea, so you should avoid this.
The second method doesn't work, since you immediately execute a function object with the function call operator (). What ends up happening is that playNote is executed immediately if you use the form playNote(...), so nothing will happen at the end of the delay.
Instead, you have to pass an anonymous function to setTimeout, so the correct form is:
setTimeout(function() { playNote(currentaudio.id,noteTime) }, delay);
Note that you are passing setTimeout an entire function expression, so it will hold on to the anonymous function and only execute it at the end of the delay.
You can also pass setTimeout a reference, since a reference isn't executed immediately, but then you can't pass arguments:
setTimeout(playNote, delay);
Note:
For repeated events you can use setInterval() and you can set setInterval() to a variable and use the variable to stop the interval with clearInterval().
You say you use setTimeout() in a for loop. In many situations, it is better to use setTimeout() in a recursive function. This is because in a for loop, the variables used in the setTimeout() will not be the variables as they were when setTimeout() began, but the variables as they are after the delay when the function is fired.
Just use a recursive function to sidestep this entire problem.
Using recursion to deal with variable delay times:
// Set original delay
var delay = 500;
// Call the function for the first time, to begin the recursion.
playNote(xxx, yyy);
// The recursive function
function playNote(theId, theTime)
{
// Do whatever has to be done
// ...
// Have the function call itself again after a delay, if necessary
// you can modify the arguments that you use here. As an
// example I add 20 to theTime each time. You can also modify
// the delay. I add 1/2 a second to the delay each time as an example.
// You can use a condition to continue or stop the recursion
delay += 500;
if (condition)
{ setTimeout(function() { playNote(theID, theTime + 20) }, delay); }
}
Try this.
setTimeout(function() { playNote(currentaudio.id,noteTime) }, delay);
Don't use string-timeouts. It's effective an eval, which is a Bad Thing. It works because it's converting currentaudio.id and noteTime to the string representations of themselves and hiding it in the code. This only works as long as those values have toString()s that generate JavaScript literal syntax that will recreate the value, which is true for Number but not for much else.
setTimeout(playNote(currentaudio.id, noteTime), delay);
that's a function call. playNote is called immediately and the returned result of the function (probably undefined) is passed to setTimeout(), not what you want.
As other answers mention, you can use an inline function expression with a closure to reference currentaudio and noteTime:
setTimeout(function() {
playNote(currentaudio.id, noteTime);
}, delay);
However, if you're in a loop and currentaudio or noteTime is different each time around the loop, you've got the Closure Loop Problem: the same variable will be referenced in every timeout, so when they're called you'll get the same value each time, the value that was left in the variable when the loop finished earlier.
You can work around this with another closure, taking a copy of the variable's value for each iteration of the loop:
setTimeout(function() {
return function(currentaudio, noteTime) {
playNote(currentaudio.id, noteTime);
};
}(currentaudio, noteTime), delay);
but this is getting a bit ugly now. Better is Function#bind, which will partially-apply a function for you:
setTimeout(playNote.bind(window, currentaudio.id, noteTime), delay);
(window is for setting the value of this inside the function, which is a feature of bind() you don't need here.)
However this is an ECMAScript Fifth Edition feature which not all browsers support yet. So if you want to use it you have to first hack in support, eg.:
// Make ECMA262-5 Function#bind work on older browsers
//
if (!('bind' in Function.prototype)) {
Function.prototype.bind= function(owner) {
var that= this;
if (arguments.length<=1) {
return function() {
return that.apply(owner, arguments);
};
} else {
var args= Array.prototype.slice.call(arguments, 1);
return function() {
return that.apply(owner, arguments.length===0? args : args.concat(Array.prototype.slice.call(arguments)));
};
}
};
}
I literally created an account on this site to comment on Peter Ajtai's answer (currently highest voted), only to discover that you require 50 rep (whatever that is) to comment, so I'll do it as an answer since it's probably worth pointing out a couple things.
In his answer, he states the following:
You can also pass setTimeout a reference, since a reference isn't executed immediately, but then you can't pass arguments:
setTimeout(playNote, delay);
This isn't true. After giving setTimeout a function reference and delay amount, any additional arguments are parsed as arguments for the referenced function. The below would be better than wrapping a function call in a function.
setTimeout(playNote, delay, currentaudio.id, noteTime)
Always consult the docs.
That said, as Peter points out, a recursive function would be a good idea if you want to vary the delay between each playNote(), or consider using setInterval() if you want there to be the same delay between each playNote().
Also worth noting that if you want to parse the i of your for loop into a setTimeout(), you need to wrap it in a function, as detailed here.
It may help to understand when javascript executes code, and when it waits to execute something:
let foo2 = function foo(bar=baz()){ console.log(bar); return bar()}
The first thing javascript executes is the function constructor, and creates a function object. You can use either the function keyword syntax or the => syntax, and you get similar (but not identical) results.
The function just created is then assigned to the variable foo2
At this point nothing else has been run: no other functions called (neither baz nor bar, no values looked up, etc. However, the syntax has been checked inside the function.
If you were to pass foo or foo2 to setTimeout then after the timeout, it would call the function, the same as if you did foo(). (notice that no args are passed to foo. This is because setTimeout doesn't by default pass arguments, although it can, but those arguments get evaluated before the timeout expires, not when it expires.)
After foo is called, default arguments are evaluated. Since we called foo without passing arguments, the default for bar is evaluated. (This would not have happened if we passed an argument)
While evaluating the default argument for bar, first javascript looks for a variable named baz. If it finds one, it then tries to call it as a function. If that works, it saves the return value to bar.
Now the main body of the function is evaluated:
Javascript looks up the variable bar and then calls console.log with the result. This does not call bar. However, if it was instead called as bar(), then bar would run first, and then the return value of bar() would be passed to console.log instead. Notice that javascript gets the values of the arguments to a function it is calling before it calls the function, and even before it looks up the function to see if it exists and is indeed a function.
Javascript again looks up bar, and then it tries to call it as a function. If that works, the value is returned as the result of foo()
So, function bodies and default arguments are not called immediately, but everything else is. Similarly, if you do a function call (i.e. ()), then that function is executed immediately as well. However, you aren't required to call a function. Leaving off the parentheses will allow you to pass that function around and call it later. The downside of that, though, is that you can't specify the arguments you want the function to be called with. Also, javascript does everything inside the function parentheses before it calls the function or looks up the variable the function is stored in.
Because the second one you're telling it to call the playNote function first and then pass the return value from it to setTimeout.

Javascript setTimeout : Set a delay between beeps [duplicate]

Simply put...
why does
setTimeout('playNote('+currentaudio.id+', '+noteTime+')', delay);
work perfectly, calling the function after the the specified delay, but
setTimeout(playNote(currentaudio.id,noteTime), delay);
calls the function playNote all at the same time?
(these setTimeout()s are in a for loop)
or, if my explanation is too hard to read, what is the difference between the two functions?
The first form that you list works, since it will evaluate a string at the end of delay. Using eval() is generally not a good idea, so you should avoid this.
The second method doesn't work, since you immediately execute a function object with the function call operator (). What ends up happening is that playNote is executed immediately if you use the form playNote(...), so nothing will happen at the end of the delay.
Instead, you have to pass an anonymous function to setTimeout, so the correct form is:
setTimeout(function() { playNote(currentaudio.id,noteTime) }, delay);
Note that you are passing setTimeout an entire function expression, so it will hold on to the anonymous function and only execute it at the end of the delay.
You can also pass setTimeout a reference, since a reference isn't executed immediately, but then you can't pass arguments:
setTimeout(playNote, delay);
Note:
For repeated events you can use setInterval() and you can set setInterval() to a variable and use the variable to stop the interval with clearInterval().
You say you use setTimeout() in a for loop. In many situations, it is better to use setTimeout() in a recursive function. This is because in a for loop, the variables used in the setTimeout() will not be the variables as they were when setTimeout() began, but the variables as they are after the delay when the function is fired.
Just use a recursive function to sidestep this entire problem.
Using recursion to deal with variable delay times:
// Set original delay
var delay = 500;
// Call the function for the first time, to begin the recursion.
playNote(xxx, yyy);
// The recursive function
function playNote(theId, theTime)
{
// Do whatever has to be done
// ...
// Have the function call itself again after a delay, if necessary
// you can modify the arguments that you use here. As an
// example I add 20 to theTime each time. You can also modify
// the delay. I add 1/2 a second to the delay each time as an example.
// You can use a condition to continue or stop the recursion
delay += 500;
if (condition)
{ setTimeout(function() { playNote(theID, theTime + 20) }, delay); }
}
Try this.
setTimeout(function() { playNote(currentaudio.id,noteTime) }, delay);
Don't use string-timeouts. It's effective an eval, which is a Bad Thing. It works because it's converting currentaudio.id and noteTime to the string representations of themselves and hiding it in the code. This only works as long as those values have toString()s that generate JavaScript literal syntax that will recreate the value, which is true for Number but not for much else.
setTimeout(playNote(currentaudio.id, noteTime), delay);
that's a function call. playNote is called immediately and the returned result of the function (probably undefined) is passed to setTimeout(), not what you want.
As other answers mention, you can use an inline function expression with a closure to reference currentaudio and noteTime:
setTimeout(function() {
playNote(currentaudio.id, noteTime);
}, delay);
However, if you're in a loop and currentaudio or noteTime is different each time around the loop, you've got the Closure Loop Problem: the same variable will be referenced in every timeout, so when they're called you'll get the same value each time, the value that was left in the variable when the loop finished earlier.
You can work around this with another closure, taking a copy of the variable's value for each iteration of the loop:
setTimeout(function() {
return function(currentaudio, noteTime) {
playNote(currentaudio.id, noteTime);
};
}(currentaudio, noteTime), delay);
but this is getting a bit ugly now. Better is Function#bind, which will partially-apply a function for you:
setTimeout(playNote.bind(window, currentaudio.id, noteTime), delay);
(window is for setting the value of this inside the function, which is a feature of bind() you don't need here.)
However this is an ECMAScript Fifth Edition feature which not all browsers support yet. So if you want to use it you have to first hack in support, eg.:
// Make ECMA262-5 Function#bind work on older browsers
//
if (!('bind' in Function.prototype)) {
Function.prototype.bind= function(owner) {
var that= this;
if (arguments.length<=1) {
return function() {
return that.apply(owner, arguments);
};
} else {
var args= Array.prototype.slice.call(arguments, 1);
return function() {
return that.apply(owner, arguments.length===0? args : args.concat(Array.prototype.slice.call(arguments)));
};
}
};
}
I literally created an account on this site to comment on Peter Ajtai's answer (currently highest voted), only to discover that you require 50 rep (whatever that is) to comment, so I'll do it as an answer since it's probably worth pointing out a couple things.
In his answer, he states the following:
You can also pass setTimeout a reference, since a reference isn't executed immediately, but then you can't pass arguments:
setTimeout(playNote, delay);
This isn't true. After giving setTimeout a function reference and delay amount, any additional arguments are parsed as arguments for the referenced function. The below would be better than wrapping a function call in a function.
setTimeout(playNote, delay, currentaudio.id, noteTime)
Always consult the docs.
That said, as Peter points out, a recursive function would be a good idea if you want to vary the delay between each playNote(), or consider using setInterval() if you want there to be the same delay between each playNote().
Also worth noting that if you want to parse the i of your for loop into a setTimeout(), you need to wrap it in a function, as detailed here.
It may help to understand when javascript executes code, and when it waits to execute something:
let foo2 = function foo(bar=baz()){ console.log(bar); return bar()}
The first thing javascript executes is the function constructor, and creates a function object. You can use either the function keyword syntax or the => syntax, and you get similar (but not identical) results.
The function just created is then assigned to the variable foo2
At this point nothing else has been run: no other functions called (neither baz nor bar, no values looked up, etc. However, the syntax has been checked inside the function.
If you were to pass foo or foo2 to setTimeout then after the timeout, it would call the function, the same as if you did foo(). (notice that no args are passed to foo. This is because setTimeout doesn't by default pass arguments, although it can, but those arguments get evaluated before the timeout expires, not when it expires.)
After foo is called, default arguments are evaluated. Since we called foo without passing arguments, the default for bar is evaluated. (This would not have happened if we passed an argument)
While evaluating the default argument for bar, first javascript looks for a variable named baz. If it finds one, it then tries to call it as a function. If that works, it saves the return value to bar.
Now the main body of the function is evaluated:
Javascript looks up the variable bar and then calls console.log with the result. This does not call bar. However, if it was instead called as bar(), then bar would run first, and then the return value of bar() would be passed to console.log instead. Notice that javascript gets the values of the arguments to a function it is calling before it calls the function, and even before it looks up the function to see if it exists and is indeed a function.
Javascript again looks up bar, and then it tries to call it as a function. If that works, the value is returned as the result of foo()
So, function bodies and default arguments are not called immediately, but everything else is. Similarly, if you do a function call (i.e. ()), then that function is executed immediately as well. However, you aren't required to call a function. Leaving off the parentheses will allow you to pass that function around and call it later. The downside of that, though, is that you can't specify the arguments you want the function to be called with. Also, javascript does everything inside the function parentheses before it calls the function or looks up the variable the function is stored in.
Because the second one you're telling it to call the playNote function first and then pass the return value from it to setTimeout.

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