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How can I port this JavaScript logic as a single-line RegEx to be used in PHP?

I am trying to recreate the following conditions to validate string syntax in a single RegEx to be used with PHP. What would be the fastest regular expression to use, returning TRUE if these conditions are all met?
String must not be empty
Total string length: >= 3 and <= 16 characters
Allowed characters in string: a-z,0-9,-,.
No upper case letters allowed
First character must be a lower case letter: a-z
Last character must be a lower case letter or digit: a-z or 0-9
Cannot have two consecutive hyphens - anywhere in string
Bonus Trickyness: If a dot/period . exists, the string becomes segmented using the . as a delimiter. These "segments" have special rules:
All previous rules also still apply to the string as a whole
Segment must start with a letter: a-z
Segment end with a letter or digit: a-z 0-9
Segment can only have letters, digits, or hyphens: a-z 0-9 -
Segment must be => 3 characters long
This "segment" logic is really throwing me for a loop (no pun intended). I'm not sure how to incorporate everything together.
Here's an example of JavaScript that achieves the goal. I am working in PHP and need a single line RegEx that will validate TRUE if all criteria is met. I don't need the logic to return why it failed (out of scope). I only need a TRUE/FALSE RegEx. Just leaving this snippet in case it is helpful:
export function validateAccountName(value) {
let i, label, len, suffix;
suffix = "Account name should ";
if (!value) {
return suffix + "not be empty.";
}
const length = value.length;
if (length < 3) {
return suffix + "be longer.";
}
if (length > 16) {
return suffix + "be shorter.";
}
if (/\./.test(value)) {
suffix = "Each account segment should ";
}
const ref = value.split(".");
for (i = 0, len = ref.length; i < len; i++) {
label = ref[i];
if (!/^[a-z]/.test(label)) {
return suffix + "start with a letter.";
}
if (!/^[a-z0-9-]*$/.test(label)) {
return suffix + "have only letters, digits, or dashes.";
}
if (/--/.test(label)) {
return suffix + "have only one dash in a row.";
}
if (!/[a-z0-9]$/.test(label)) {
return suffix + "end with a letter or digit.";
}
if (!(label.length >= 3)) {
return suffix + "be longer";
}
}
return null;
}
Thanks!

You might use a positive lookahead to assert the length, including the first and last character, and another negative lookahead to assert not 2 consecutive hyphens.
^(?=[a-z][a-z\d.-]{1,14}[a-z\d]$)(?!.*--)[a-z\d-]+(?:\.[a-z][a-z\d-]+[a-z\d])*$
The pattern matches
^ Start of string
(?=[a-z][a-z\d.-]{1,14}[a-z\d]$) Positive lookahead to assert 3-16 chars, starting with a-z and end with a-z\d
(?!.*--) Negative lookahead to assert not --
[a-z\d-]+ Match 1+ times any of the listed chars (without a dot)
(?: Non capture group
\.[a-z][a-z\d-]+[a-z\d] Match a . and repeat segments of at least 3 chars starting with a-z, then 1+ times any of the listed without a dot and ending on a-z\d without the hyphen
)* Close the non capture group and optionally repeat
$ End of string
Regex demo
If all the parts should be at least 3 chars when there is a dot present, you can repeat matching at least 3 character and shorten the pattern a bit by repeating the first group using (?1) or see the pattern without the group.
^(?=[a-z][a-z\d.-]{1,14}[a-z\d]$)(?!.*--)([a-z][a-z\d-]+[a-z\d]+)(?:\.(?1))*$
Regex demo

You may try this regex as well:
^[a-z](?!.*--)(?!.*\.([^.]{0,2}(\.|$)|[.\d-]))[a-z.\d-]{1,14}[a-z\d]$
RegEx Demo
RegEx Explained:
^: Start
[a-z]: Match a a-z character
(?!.*--): Negative lookahead to fail the match if 2 consecutive hyphen are found anywhere
(?!.*\.([^.]{0,2}(\.|$)|[.\d-])): Negative lookahead to fail the match if there are less than 3 non-dot characters after a dot or a non-alpha character after dot
[a-z.\d-]{1,14}: Match 1 to 14 instances of a a-z or a digit or a dor or a hyphen character
[a-z\d]: Match a a-z or digit
$: End

JavaScript RegEx, check if string contains * symbol and follows a set of specific rules [duplicate]

I want a regular expression to check that:
A password contains at least eight characters, including at least one number and includes both lower and uppercase letters and special characters, for example #, ?, !.
It cannot be your old password or contain your username, "password", or "websitename"
And here is my validation expression which is for eight characters including one uppercase letter, one lowercase letter, and one number or special character.
(?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$"
How can I write it for a password must be eight characters including one uppercase letter, one special character and alphanumeric characters?

Minimum eight characters, at least one letter and one number:
"^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{8,}$"
Minimum eight characters, at least one letter, one number and one special character:
"^(?=.*[A-Za-z])(?=.*\d)(?=.*[#$!%*#?&])[A-Za-z\d#$!%*#?&]{8,}$"
Minimum eight characters, at least one uppercase letter, one lowercase letter and one number:
"^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[a-zA-Z\d]{8,}$"
Minimum eight characters, at least one uppercase letter, one lowercase letter, one number and one special character:
"^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$"
Minimum eight and maximum 10 characters, at least one uppercase letter, one lowercase letter, one number and one special character:
"^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,10}$"

You may use this regex with multiple lookahead assertions (conditions):
^(?=.*?[A-Z])(?=.*?[a-z])(?=.*?[0-9])(?=.*?[#?!#$%^&*-]).{8,}$
This regex will enforce these rules:
At least one upper case English letter, (?=.*?[A-Z])
At least one lower case English letter, (?=.*?[a-z])
At least one digit, (?=.*?[0-9])
At least one special character, (?=.*?[#?!#$%^&*-])
Minimum eight in length .{8,} (with the anchors)

Regular expressions don't have an AND operator, so it's pretty hard to write a regex that matches valid passwords, when validity is defined by something AND something else AND something else...
But, regular expressions do have an OR operator, so just apply DeMorgan's theorem, and write a regex that matches invalid passwords:
Anything with less than eight characters OR anything with no numbers OR anything with no uppercase OR or anything with no lowercase OR anything with no special characters.
So:
^(.{0,7}|[^0-9]*|[^A-Z]*|[^a-z]*|[a-zA-Z0-9]*)$
If anything matches that, then it's an invalid password.

Use the following Regex to satisfy the below conditions:
Conditions:
Min 1 uppercase letter.
Min 1 lowercase letter.
Min 1 special character.
Min 1 number.
Min 8 characters.
Max 30 characters.
Regex:
/^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$#!%&*?])[A-Za-z\d#$#!%&*?]{8,30}$/

Just a small improvement for #anubhava's answer: Since special character are limited to the ones in the keyboard, use this for any special character:
^(?=.*?[A-Z])(?=(.*[a-z]){1,})(?=(.*[\d]){1,})(?=(.*[\W]){1,})(?!.*\s).{8,}$
This regex will enforce these rules:
At least one upper case English letter
At least one lower case English letter
At least one digit
At least one special character
Minimum eight in length

I had some difficulty following the most popular answer for my circumstances. For example, my validation was failing with characters such as ; or [. I was not interested in white-listing my special characters, so I instead leveraged [^\w\s] as a test - simply put - match non word characters (including numeric) and non white space characters. To summarize, here is what worked for me...
at least 8 characters
at least 1 numeric character
at least 1 lowercase letter
at least 1 uppercase letter
at least 1 special character
/^(?=.*?[A-Z])(?=.*?[a-z])(?=.*?[0-9])(?=.*?[^\w\s]).{8,}$/
JSFiddle Link - simple demo covering various cases

 
✅ The following 4 regex patterns can help you to write almost any password validation
 
 
Pattern 1:
 
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, one special character, no space, and it must be 8-16 characters long.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*\W)(?!.* ).{8,16}$/
 
Explanation:
 
(?=.*[0-9]) means that the password must contain a single digit from 1 to 9.
 
(?=.*[a-z]) means that the password must contain one lowercase letter.
 
(?=.*[A-Z]) means that the password must contain one uppercase letter.
 
(?=.*\W) means that the password must contain one special character.
 
.{8,16} means that the password must be 8-16 characters long. We must use this at the end of the regex, just before the $ symbol.
 
What are ^ and $:
 
^ indicates the beginning of the string. $ indicates the end of the string.
If we don't use these ^ & $, the regex will not be able to determine the maximum length of the password. In the above example, we have a condition that the password can't be longer than 16 characters, to make that condition work, we have used these ^ & $
 
Remove maximum length restriction:
 
Instead of .{8,16}, if we used .{8,}, it would mean that the password must be at least 8 characters long. So, there will not be any condition for checking the maximum length of the password.
 
Don't accept any number(digit):
 
Instead of (?=.*[0-9]), if we used (?!.*[0-9]), it would mean that the password must not contain any digit from 1-9 (Difference with the (?=.*[0-9]) is the use of ! instead of =)
 
Don't accept any spcecial character:
 
Instead of (?=.*\W), if we used (?!.*\W), it would mean that the password must not contain any special characters (The difference with the (?=.*\W) is the use of ! instead of =)
 
Alternative Syntax for number(digit):
 
Instead of (?=.*[0-9]), we could have used (?=.*\d). (?=.*\d) also means that the password must contain a single digit from 1 to 9.
 
 
Pattern 2:
 
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, one underscore but no other special character, no space and it must be 8-16 characters long.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*_)(?!.*\W)(?!.* ).{8,16}$/
 
Difference with the Pattern 1
 
Here, we have used (?=.*_) which wasn't on the Pattern 1.
 
(?=.*_)(?!.*\W) means that the password must contain an underscore but can not contain any other special character.
 
Pattern 3:
 
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, one underscore, no space and it must be 8-16 characters long. Usage of any other special character other than underscore is optional.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*_)(?!.* ).{8,16}$/
 
Difference with the Pattern 2
 
Here, we have not used (?!.*\W) what was on the Pattern 2.
 
But it still has the (?=.*_)
 
By just removing the (?!.*\W), special characters have become optional. Now, one underscore is required but any other special character can be used or not as it's optional.
 
Pattern 4:
 
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, and one underscore, and it must be 8-16 characters long. Usage of any other special character and usage of space is optional.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z]).{8,16}$/
 
Difference with the Pattern 3
 
Here, we have not used (?=.*_) & (?!.* ) which was on the Pattern 3.
 
By removing (?=.*_), it's no longer mandatory to pass one underscore. Now, passing special characters is optional.
 
By removing the (?!.* ), usage of space has become optional too.

I would reply to Peter Mortensen, but I don't have enough reputation.
His expressions are perfect for each of the specified minimum requirements. The problem with his expressions that don't require special characters is that they also don't ALLOW special characters, so they also enforce maximum requirements, which I don't believe the OP requested. Normally you want to allow your users to make their password as strong as they want; why restrict strong passwords?
So, his "minimum eight characters, at least one letter and one number" expression:
^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{8,}$
achieves the minimum requirement, but the remaining characters can only be letter and numbers. To allow (but not require) special characters, you should use something like:
^(?=.*[A-Za-z])(?=.*\d).{8,}$ to allow any characters
or
^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d$#$!%*#?&]{8,}$ to allow specific special characters
Likewise, "minimum eight characters, at least one uppercase letter, one lowercase letter and one number:"
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[a-zA-Z\d]{8,}$
meets that minimum requirement, but only allows letters and numbers. Use:
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d).{8,}$ to allow any characters
or
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[A-Za-z\d$#$!%*?&]{8,} to allow specific special characters.

A more "generic" version(?), allowing none English letters as special characters.
^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*[^\w\s])\S{8,}$
var pwdList = [
'##V4-\3Z`zTzM{>k',
'12qw!"QW12',
'123qweASD!"#',
'1qA!"#$%&',
'Günther32',
'123456789',
'qweASD123',
'qweqQWEQWEqw',
'12qwAS!'
],
re = /^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*[^\w\s])\S{8,}$/;
pwdList.forEach(function (pw) {
document.write('<span style="color:'+ (re.test(pw) ? 'green':'red') + '">' + pw + '</span><br/>');
});

Import the JavaScript file jquery.validate.min.js.
You can use this method:
$.validator.addMethod("pwcheck", function (value) {
return /[\#\#\$\%\^\&\*\(\)\_\+\!]/.test(value) && /[a-z]/.test(value) && /[0-9]/.test(value) && /[A-Z]/.test(value)
});
At least one upper case English letter
At least one lower case English letter
At least one digit
At least one special character

For standard password requirements I found this to be useful:
At least 1 alphabet
At least 1 digit
Contains no space
Optional special characters e.g. #$!%*#?&^_-
Minimum 8 characters long
/^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d#$!%*#?&^_-]{8,}$/
You can also set the upper limit for example {8,32} up to 32 characters long.

Try this one:
Minimum six characters
At least one uppercase character
At least one lowercase character
At least one special character
Expression:
"/^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[$#$!%*?&.])[A-Za-z\d$#$!%*?&.]{6, 20}/"
Optional Special Characters:
At least one special character
At least one number
Special characters are optional
Minimum six characters and maximum 16 characters
Expression:
"/^(?=.*\d)(?=.*[a-zA-Z]).{6,20}$/"
If the min and max condition is not required then remove .{6, 16}
6 is minimum character limit
20 is maximum character limit
?= means match expression

This worked for me:
^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*[#$!%*?&])([a-zA-Z0-9#$!%*?&]{8,})$
At least 8 characters long;
One lowercase, one uppercase, one number and one special character;
No whitespaces.

Not directly answering the question, but does it really have to be a regex?
I used to do lots of Perl, and got used to solving problems with regexes. However, when they get more complicated with all the look-aheads and other quirks, you need to write dozens of unit tests to kill all those little bugs.
Furthermore, a regex is typically a few times slower than an imperative or a functional solution.
For example, the following (not very FP) Scala function solves the original question about three times faster than the regex of the most popular answer. What it does is also so clear that you don't need a unit test at all:
def validatePassword(password: String): Boolean = {
if (password.length < 8)
return false
var lower = false
var upper = false
var numbers = false
var special = false
password.foreach { c =>
if (c.isDigit) numbers = true
else if (c.isLower) lower = true
else if (c.isUpper) upper = true
else special = true
}
lower && upper && numbers && special
}

For a more strict validation where the following is required:
At least One Upper Case Character
At least one Lower Case character
At least one digit
At least one symbol/special character #$!%*#?&^_-
Minimum 8 characters/digits
Regex:
/(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[#$!%*#?&^_-]).{8,}/
I hope it helps someone with a more stringent.

What about considering the following regex solution:
^(?=.*[\w])(?=.*[\W])[\w\W]{8,}$
Which validates the following:
At least one lowercase
At least one uppercase
At least one digit
At least one special character
At least it should have 8 characters long.
Check it out working at the following link https://regex101.com/r/qPmC06/4/

^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9])(?=.*[!##$%^&*()_+,.\\\/;':"-]).{8,}$

Another option is to make use of contrast in the lookahead assertions using a negated character class, optionally matching any character except that is listed before matching the character that should be matched.
^(?=[^A-Z\n]*[A-Z])(?=[^a-z\n]*[a-z])(?=[^0-9\n]*[0-9])(?=[^#?!#$%^&*\n-]*[#?!#$%^&*-]).{8,}$
See a regex demo
In parts, the pattern matches:
^ Start of string
(?=[^A-Z\n]*[A-Z]) Positive lookahead, assert 0+ times any char except A-Z or a newline. Then match a char A-Z
(?=[^a-z\n]*[a-z]) The same approach for a char a-z
(?=[^0-9\n]*[0-9]) The same approach for a digit 0-9
(?=[^#?!#$%^&*\n-]*[#?!#$%^&*-]) The same approach for a char that you would consider special
.{8,} Match 8 or more times any character except a newline
$ End of string
Notes
A dot can also match a space. If you do not want to allow matching a space, then .{8,} can be changed to \S{8,} to match 8 or more non whitespace characters
Using either . or \S can match more characters than are specified in the lookahead assertions. If you only want to match the characters that are used in the assertions, you can change .{8,} to match only the allowed characters [#?!#$%^&*A-Za-z0-9-]{8,} using a character class
const regex = /^(?=[^A-Z\n]*[A-Z])(?=[^a-z\n]*[a-z])(?=[^0-9\n]*[0-9])(?=[^#?!#$%^&*\n-]*[#?!#$%^&*-]).{8,}$/;
[
"abcA1#!A",
"#!asdfSFD1;",
"# a f F1 ;",
"1111111111",
"aaaaaaaa",
"11111111",
"AAAAAAAA",
"########",
"aA1#"
].forEach(s =>
console.log(regex.test(s) ? `Match --> ${s}` : `No match --> ${s}`)
);

/^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9]).*$/
this the simple way to use it while validate atleast 1 uppercase 1 lowercase and 1 number
and this is the example while I use in express validation
check('password')
.notEmpty()
.withMessage('Password cannot be null')
.bail()
.isLength({ min: 6 })
.withMessage('Password must be at least 6 characters')
.bail()
.matches(/^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9]).*$/)
.withMessage(
'Must have atleast 1 uppercase, 1 lowercase letter and 1 number'
),

Testing this one in 2020:
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$
Verify yourself
const regex = /^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$/;
const str = `some12*Nuts`;
let m;
if ((m = regex.exec(str)) !== null) {
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}

#ClasG has already suggested:
^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*[^\w\s])\S{8,}$
but it does not accept _(underscore) as a special character (eg. Aa12345_).
An improved one is:
^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*([^\w\s]|[_]))\S{8,}$

I've found many problems here, so I made my own.
Here it is in all it's glory, with tests:
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*([^a-zA-Z\d\s])).{9,}$
https://regex101.com/r/DCRR65/4/tests
Things to look out for:
doesn't use \w because that includes _, which I'm testing for.
I've had lots of troubles matching symbols, without matching the end of the line.
Doesn't specify symbols specifically, this is also because different locales may have different symbols on their keyboards that they may want to use.

Demo:
function password_check() {
pass = document.getElementById("password").value;
console.log(pass);
regex = /^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$/;
if (regex.exec(pass) == null) {
alert('invalid password!')
}
else {
console.log("valid");
}
}
<input type="text" id="password" value="Sample#1">
<input type="button" id="submit" onclick="password_check()" value="submit">

var strongRegex = new RegExp("^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])(?=.*[!##\$%\^&\*])(?=.{8,})");
var mediumRegex = new RegExp("^(((?=.*[a-z])(?=.*[A-Z]))|((?=.*[a-z])(?=.*[0-9]))|((?=.*[A-Z])(?=.*[0-9])))(?=.{6,})");
Best For javascript

Keep it simple stupid:
This should do the trick for you, always.
Regex: ^(.{0,7}|[^a-z]{1,}|[^A-Z]{1,}|[^\d]{1,}|[^\W]{1,})$|[\s]
If your password matches the regex above, it is invalid.
If there's no match, your password is valid and contains has at least 8 characters, one upper case letter, one lower case letter and one symbol or special character. And it also contains no spaces, tabs or line breaks.
Breakdown of Regex
.{0,7} - matches if password has between 0 to 7 characters.
[^a-z]{1,} - matches if no lower case is found
[^A-Z]{1,} - matches if no upper case is found
[^\d]{1,} - matches if no number (between [0-9]) is found
[\s] - matches if a white space, tab or line break is found.
With this approach there's no limit or restriction in terms of symbols allowed. If you want to limit to few symbols allowable, just change [^\W] with [^YourSymbols].

(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*[##$%^&+-]).{6}

According to your need this pattern should work just fine. Try this,
^(?=(.*\d){1})(.*\S)(?=.*[a-zA-Z\S])[0-9a-zA-Z\S]{8,}
Just create a string variable, assign the pattern, and create a boolean method which returns true if the pattern is correct, else false.
Sample:
String pattern = "^(?=(.*\d){1})(.*\S)(?=.*[a-zA-Z\S])[0-9a-zA-Z\S]{8,}";
String password_string = "Type the password here"
private boolean isValidPassword(String password_string) {
return password_string.matches(Constants.passwordPattern);
}

Use the following Regex to satisfy the below conditions:
Conditions: 1] Min 1 special character.
2] Min 1 number.
3] Min 8 characters or More
Regex: ^(?=.*\d)(?=.*[#$#!%&*?])[A-Za-z\d#$#!%&*?]{8,}$
Can Test Online: https://regex101.com

Just we can do this by using HTML5.
Use below code in pattern attribute,
pattern="(?=^.{8,}$)((?=.*\d)(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$"
It will work perfectly.

You can use the below regular expression pattern to check the password whether it matches your expectations or not.
((?=.*\\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[~!##$%^&*()]).{8,20})

Regex with lowercase, uppercase, alphanumeric, special characters and no more than 2 identical characters in a row with a minimum length of 8 chars [duplicate]

This question already has answers here:
Regex for password must contain at least eight characters, at least one number and both lower and uppercase letters and special characters
(42 answers)
Closed 3 years ago.
I'm trying to create a regex that allows the 4 main character types (lowercase, uppercase, alphanumeric, and special chars) with a minimum length of 8 and no more than 2 identical characters in a row.
I've tried searching for a potential solution and piecing together different regexes but no such luck! I was able to find this one on Owasp.org
^(?:(?=.*\d)(?=.*[A-Z])(?=.*[a-z])|(?=.*\d)(?=.*[^A-Za-z0-9])(?=.*[a-z])|(?=.*[^A-Za-z0-9])(?=.*[A-Z])(?=.*[a-z])|(?=.*\d)(?=.*[A-Z])(?=.*[^A-Za-z0-9]))(?!.*(.)\1{2,})[A-Za-z0-9!~<>,;:_=?*+#."&§%°()\|\[\]\-\$\^\#\/]{8,32}$
but it uses at least 3 out of the 4 different characters when I need all 4. I tried modifying it to require all 4 but I wasn't getting anywhere. If someone could please help me out I would greatly appreciate it!

Can you try the following?
var strongRegex = new RegExp("^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])(?=.*[!##\$%\^&\*])(?=.{8,})");
Explanations
RegEx Description
(?=.*[a-z]) The string must contain at least 1 lowercase alphabetical character
(?=.*[A-Z]) The string must contain at least 1 uppercase alphabetical character
(?=.*[0-9]) The string must contain at least 1 numeric character
(?=.[!##\$%\^&]) The string must contain at least one special character, but we are escaping reserved RegEx characters to avoid conflict
(?=.{8,}) The string must be eight characters or longer
or try with
(?=.{8,100}$)(([a-z0-9])(?!\2))+$ The regex checks for lookahead and rejects if 2 chars are together
var strongerRegex = new RegExp("^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])(?=.*[!##\$%\^&\*])(?=.{8,100}$)(([a-z0-9])(?!\2))+$");
reference

I think this might work from you (note: the approach was inspired by the solution to this SO question).
/^(?:([a-z0-9!~<>,;:_=?*+#."&§%°()|[\]$^#/-])(?!\1)){8,32}$/i
The regex basically breaks down like this:
// start the pattern at the beginning of the string
/^
// create a "non-capturing group" to run the check in groups of two
// characters
(?:
// start the capture the first character in the pair
(
// Make sure that it is *ONLY* one of the following:
// - a letter
// - a number
// - one of the following special characters:
// !~<>,;:_=?*+#."&§%°()|[\]$^#/-
[a-z0-9!~<>,;:_=?*+#."&§%°()|[\]$^#/-]
// end the capture the first character in the pair
)
// start a negative lookahead to be sure that the next character
// does not match whatever was captured by the first capture
// group
(?!\1)
// end the negative lookahead
)
// make sure that there are between 8 and 32 valid characters in the value
{8,32}
// end the pattern at the end of the string and make it case-insensitive
// with the "i" flag
$/i

You could use negative lookaheads based on contrast using a negated character class to match 0+ times not any of the listed, then match what is listed.
To match no more than 2 identical characters in a row, you could also use a negative lookahead with a capturing group and a backreference \1 to make sure there are not 3 of the same characters in a row.
^(?=[^a-z]*[a-z])(?=[^A-Z]*[A-Z])(?=[^0-9]*[0-9])(?=[^!~<>,;:_=?*+#."&§%°()|\[\]$^#\/-]*[!~<>,;:_=?*+#."&§%°()|\[\]$^#\/-])(?![a-zA-Z0-9!~<>,;:_=?*+#."&§%°()|\[\]$^#\/-]*([a-zA-Z0-9!~<>,;:_=?*+#."&§%°()|\[\]$^#\/-])\1\1)[a-zA-Z0-9!~<>,;:_=?*+#."&§%°()|\[\]$^#\/-]{8,}$
^ Start of string
(?=[^a-z]*[a-z]) Assert a-z
(?=[^A-Z]*[A-Z]) Assert A-Z
(?=[^0-9]*[0-9]) Assert 0-9
(?= Assert a char that you would consider special
[^!~<>,;:_=?*+#."&§%°()|\[\]$^#\/-]*
[!~<>,;:_=?*+#."&§%°()|\[\]$^#\/-]
)
(?! Assert not 3 times an identical char from the character class in a row
[a-zA-Z0-9!~<>,;:_=?*+#."&§%°()|\[\]$^#\/-]*
([a-zA-Z0-9!~<>,;:_=?*+#."&§%°()|\[\]$^#\/-])\1\1
)
[a-zA-Z0-9!~<>,;:_=?*+#."&§%°()|\[\]$^#\/-]{8,} Match any of the listed 8 or more times
$ End of string
Regex demo

Check password valid using regex in javascript

The password must be eight characters or longer
The password must contain at least 2 lowercase alphabetical character.
The password must contain at least 2 uppercase alphabetical character.
The password must contain at least 2 numeric character.
The password must contain at least 2 special character.
My code
function checkPass(pw) {
var regx = new RegExp("^(?=.*[a-z]{2})(?=.*[A-Z]{2})(?=.*[0-9]{2})(?=.*[!##\$%\^&\*\)\(]{2})(?=.{8,})");
return regx.test(pw);
}
checkPass('PAssword12#$') => true
checkPass('PaSsword12#$') => false
I want to funtion return true when 2 uppercase character is not sequential.
Thanks!

You need to use the $ anchor to check for length (and best is to move that check out from lookaheads) and to allow some non-uppercase letters in between like this:
function checkPass(pw) {
var regx = /^(?=(?:[^a-z]*[a-z]){2})(?=(?:[^A-Z]*[A-Z]){2})(?=(?:\D*\d){2})(?=(?:[^!##$%^&*)(]*[!##$%^&*)(]){2}).{8,}$/;
return regx.test(pw);
}
document.write(checkPass('PAssword12#$') + "<br>");
document.write(checkPass('PaSsword12#$'));
Note that I used the principle of contrast: (?:[^a-z]*[a-z]){2} matches 2 sequences of symbols other than a-z zero or more times followed by 1 lowercase letter. I modified all the lookaheads the same way.

Rather than having [A-Z]{2} which will only match two uppercase characters together, you'll have to put in an optional match for any other characters in between two separate ranges (you'll have to do this for the lowercase, numbers and symbols as well). So you would instead put
[A-Z].*?[A-Z]
You also don't actually need to check whether it's at least 8 characters, because any password meeting the criteria for lowercase/uppercase letters, numbers and symbols has to be 8 characters at minimum anyway.

validating variable in javascript

Hi i have a field in php that will be validated in javascript using i.e for emails
var emailRegex = /^[\w-\.]+#([\w-]+\.)+[\w-]{2,4}$/;
What i'm after is a validation check which will look for the
first letter as a capital Q
then the next letters can be numbers only
then followed by a .
then two numbers only
and then an optional letter
i.e Q100.11 or Q100.11a
I must admit i look at the above email validation check and i have no clue how it works but it does ;)
many thanks for any help on this
Steve

The ^ marks the beginning of the string, $ matches the end of the string. In other words, the whole string should exactly match this regular expression.
[\w-\.]+: I think you wanted to match letters, digits, dots and - only. In that case, the - should be escaped (\-): [\w\-\.]+. The plus-sign makes is match one or more times.
#: a literal # match
([\w-]+\.)+ letters, digits and - are allowed one or more times, with a dot after it (between the parentheses). This may occur several times (at least once).
[\w-]{2,4}: this should match the TLD, like com, net or org. Because a TLD can only contain letters, it should be replaced by [a-z]{2,4}. This means: lowercase letters may occur two till four times. Note that the TLD can be longer than 4 characters.
An regular expression which should follow the next rules:
a capital Q (Q)
followed by one or more occurrences of digits (\d+)
a literal dot (.)
two digits (\d{2})
one optional letter ([a-z]?)
Result:
var regex = /Q\d+\.\d{2}[a-z]?/;
If you need to match strings case-insensitive, add the i (case-insensitive) modifier:
var regex = /Q\d+\.\d{2}[a-z]?/i;
Validating a string using a regexp can be done in several ways, one of them:
if (regex.test(str)) {
// success
} else {
// no match
}

var emailRegex = /^Q\d+\.\d{2}[a-zA-Z]?#([\w-]+\.)+[a-zA-Z]+$/;
var str = "Q100.11#test.com";
alert(emailRegex.test(str));

var regex = /^Q[0-9]+\.[0-9]{2}[a-z]?$/;
+ means one or more
the period must be escaped - \.
[0-9]{2} means 2 digits, same as \d{2}
[a-z]? means 0 or 1 letter
You can check your regex at http://regexpal.com/