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Disable or enable only the current button

With a PHP for each cycle, I'm bringing articles from the database. In those articles, we have a comment section with a form. I want to check with jQuery if there is something written on the input before the comment is sent.
As the articles are being brought with a PHP cycle, I want to check only the article in which it is being written a comment, but jQuery checks all the articles and only enables or disables the first or top result being brought from the database. I want jQuery to check only on the article with a written comment.
Here's what I'm doing:
$(document).ready(function() {
$(".comment-submit").attr("disabled", true);
$("#group-post-comment-input").keyup(function() {
if ($(this).val().length != 0) {
$(".comment-submit").attr("disabled", false);
} else {
$(".comment-submit").attr("disabled", true);
}
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form action="comment.php" method="POST">
<input autocomplete="off" type="text" placeholder="Add a comment" id="group-post-comment-input">
<button class="comment-submit">
Comment
</button>
</form>
<br>
<form action="comment.php" method="POST">
<input autocomplete="off" type="text" placeholder="Add a comment" id="group-post-comment-input">
<button class="comment-submit">
Comment
</button>
</form>
<br>
<form action="comment.php" method="POST">
<input autocomplete="off" type="text" placeholder="Add a comment" id="group-post-comment-input">
<button class="comment-submit">
Comment
</button>
</form>
As you can see on the snippet above, the buttons only get enabled when text is written on the first input only. I want the buttons to get enabled when text is written on their dependent input. If input 2 has text on it, enable button 2, and so on and so on.
How can I do that?

Since IDs must be unique to the DOM tree, you might consider using a class instead.
$(function() {
$(".group-post-comment-input").on('keyup', function() {
let $button = $(this).next('.comment-submit');
let disabled = !this.value;
$button.prop('disabled', disabled);
});
});
form {
margin: 0 0 1em;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form action="comment.php" method="POST">
<input autocomplete="off" type="text" placeholder="Add a comment" class="group-post-comment-input">
<button class="comment-submit" disabled>Comment</button>
</form>
<form action="comment.php" method="POST">
<input autocomplete="off" type="text" placeholder="Add a comment" class="group-post-comment-input">
<button class="comment-submit" disabled>Comment</button>
</form>
<form action="comment.php" method="POST">
<input autocomplete="off" type="text" placeholder="Add a comment" class="group-post-comment-input">
<button class="comment-submit" disabled>Comment</button>
</form>
In my demonstration, I use jQuery's next() to traverse from the input on which the "keyup" event is fired to its associated button.
.next( [selector ] )
Get the immediately following sibling of each element in the set of matched elements. If a selector is provided, it retrieves the next sibling only if it matches that selector.
Another method is to traverse up to the form element with closest() and back down to the button with find(). This might be useful if you expect your HTML structure to change in a way that could break the next() traversal.
let $button = $(this).closest('form').find('.comment-submit');
I also recommend using prop() instead of attr() to enable and disable inputs.

ID must be unique,
but you need to use a name for sending information to your PHP server
document.querySelectorAll('button.comment-submit').forEach( bt => bt.disabled = true )
document.querySelectorAll('input[name="group-post-comment-input"]').forEach( inEl =>
inEl.oninput = e =>inEl.nextElementSibling.disabled = (inEl.value.trim().length === 0) )
<form action="comment.php" method="POST">
<input autocomplete="off" type="text" placeholder="Add a comment" name="group-post-comment-input">
<button class="comment-submit"> Comment </button>
</form>
<br>
<form action="comment.php" method="POST">
<input autocomplete="off" type="text" placeholder="Add a comment" name="group-post-comment-input">
<button class="comment-submit"> Comment </button>
</form>
<br>
<form action="comment.php" method="POST">
<input autocomplete="off" type="text" placeholder="Add a comment" name="group-post-comment-input">
<button class="comment-submit"> Comment </button>
</form>

Why is jQuery input tag not working when appending input field?

I am trying to create multiple tag fields with jQuery.
The tag script that I am using is from http://codepen.io/k-ivan/pen/NxxGPv
It works perfectly fine, however, when adding more fields by appending, the script stops working.
Can anyone suggest a solution?
HTML:
<form role="form" method="POST" enctype="multipart/form-data" action="../test.php">
<label for="default">Default
<input type="text" id="default" class="tagged form-control" name="tag-1" data-removeBtn="true" placeholder="create tag">
</label>
<input type="button" value ="add More" id="add">
<input type="submit" value="submit">
</form>
jQuery for adding more fields (adding works perfectly fine):
<script >
$(document).ready(function(){
var Count =2;
$('#add').click(function(){
$('#add').before($('<div/>',{
class:'row',
})
.fadeIn('slow')
.append(' <input type="text" id="default" class="tagged form-control" name="tag'+Count+'" data-removeBtn="true" placeholder="create tag">')
)
Count++;
});
});
</script>
I would also like to ask how a PHP script can be added inside this append event?

HTML form action search, one text box, 2 buttons, 2 possible results

I am trying these days to do a search form that sends to two different pages with two different buttons with a single text box. So far I am doing this:
<form action="http://www.youtube.com/results" method="get">
<input name="search_query" type="text" maxlength="128" />
<input type="submit" value="YouTube" />
</form>
<form action="https://torrentz.eu/search" method="get">
<input name="q" type="text" maxlength="128" />
<input type="submit" value="TorrentZ" />
</form>
of course the result is this:
I can work with that, but I want to make it "cuter" like this:
So far I have tried using a script but I did not get it so I scraped it, then I tried making an if/elseif but yet again, I was not sure what I was doing, I am not a good planner for what I see, a toggle button or a dropbox is not as fast, as I just need to press tab once or twice and enter to just search where I want.
As an extra note, I am just making my personal "new tab" for chrome, as the basic and the ones I find in extensions are pretty heavy for my mini laptop.

In HTML5 you can use formaction attribute.
<!DOCTYPE html>
<html>
<body>
<form>
<input name="search_query" type="text" maxlength="128" />
<input type="submit" formaction="http://www.youtube.com/results" value="YouTube" />
<input type="submit" formaction="https://torrentz.eu/search" value="TorrentZ" />
</form>
</body>
</html>

Since you tried and failed a script, let's look at ways we can achieve this.
Using form
Be extremely wary of what you do here. It is easy to send a get request using form but it always "flushes" out the query strings already present in the action URL, and submits the request by adding name-value pairs in its child nodes. Make sure to create your query as a child node.
<input type="text" id="box" name="searchbox" maxlength="128" placeholder="Type text to be searched here" autofocus />
<input type="button" value="Youtube" onclick="search_youtube()"/>
<input type="button" value="Torrentz" onclick="search_torrentz()"/>
<script>
function search_youtube(){
var add="https://www.youtube.com/results";
var box = document.getElementById("box");
box.name="search_query"
if(box.value)
{
var form = open().document.createElement("form");
form.action=add;
form.appendChild(box.cloneNode(false))
form.submit();
}
}
function search_torrentz(){
var add="https://www.torrentz.com/search";
var box = document.getElementById("box");
box.name="q"
if(box.value)
{
var form = open().document.createElement("form");
form.action=add;
form.appendChild(box.cloneNode(false))
form.submit();
}
}
</script>
Using HTML5 formaction attribute
<form action="https://www.youtube.com/results" method="GET">
<input type="text" id="box" name="search_query" maxlength="128" placeholder="Type text to be searched here" autofocus />
<input type="submit" value="Torrentz" formaction="https://www.torrentz.com/search" onclick="document.getElementById('box').name='q'" />
<input type="submit" name="submit" value="Youtube" />
</form>

Buttons that hide/show PHP generated forms

I've got two forms in PHP that have different purposes to them. Right now they are only made visible if the admin is logged in. This code works fine for it
<?php
if (isset($_SESSION['username']))
{
echo '</nav>
<br><br> <div class="blogscript">
<form id="form1" action="sent.php" method="post"> New page<br>
<input type="text" placeholder="Title" method="POST" name="pagetitle" /><br><br>
<textarea id="message" name="message</textarea><br>
<input type="submit" value="Confirm" />
</form></div>';
}
if (isset($_SESSION['username']))
{
echo '</nav>
<br><br> <div class="collagescript">
<form id="form2" action="sent.php" method="post"> New collage<br>
<textarea id="collage" name="message"></textarea><br>
<input type="submit" value="Confirm" />
</form></div>';
}
?>
I don't want the default of the forms to be visible even for the admin, I only want to show them when buttons are clicked that say "Show form 1" and "Show form 2".
How would I need to approach that? I don't know whether to use Javascript or pure PHP for it, in the case of PHP, I don't how how to toggle the visibility. I'm more comfortable with javascript, but I don't even know to the extent you can combine php with javascript.
PS: By toggling visibility, I don't mean toggling the opacity.

The earlier answer links to how this can be accomplished with jQuery. To do the same thing without loading the jQuery library, this should get you started:
//On document ready
document.addEventListener('DOMContentLoaded', docReady, false);
function docReady(){
document.getElementById('f1').addEventListener('click', fnF1, false )
document.getElementById('f2').addEventListener('click', fnF2, false )
}
function fnF1(){
document.getElementsByClassName('blogscript')[0].style.display = 'block';
this.style.display = 'none';
}
function fnF2(){
document.getElementsByClassName('collagescript')[0].style.display = 'block';
this.style.display = 'none';
}
.blogscript{display:none;}
.collagescript{display:none;}
<div class="blogscript">
<form id="form1" action="sent.php" method="post">New page
<div>
<input type="text" placeholder="Title" method="POST" name="pagetitle" />
</div>
<div>
<textarea id="message" name="message"></textarea>
</div>
<input type="submit" value="Confirm" />
</form>
</div>
<div class="collagescript">
<form id="form2 " action="sent.php " method="post ">New collage
<div>
<textarea id="collage " name="message "></textarea>
</div>
<input type="submit " value="Confirm " />
</form>
</div>
<button id="f1">Show Form 1</button>
<button id="f2">Show Form 2</button>
Notes:
(1) To create a pure js slideUp/slideDown effect, see:
https://gist.github.com/ludder/4226288
(2) jQuery is much simpler and significantly less typing, but requires the jQuery library to be loaded. To load the jQuery library, just include a link to its CDN location either in the <head> tags or just before the </body> tag:
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.2/jquery.min.js"></script>
</head>

This question has been asked hundreds of times. But in case you couldn't find the link:
Jquery Toggle Show/Hide Div
You will want to use javascript for this. The linked method is pretty easy. You could also go pure CSS, but Javascript is more compatible.

Jquery Cookbook Modal button

I've been at this for two days and can't seem to get it. Basically, I'm using the JQuery Cookbook modal from scratch. My problem is the form html page loads fine but the code will not recognize my submit button. Here's the relevant parts of the code:
Separate HTML:
<div id="contact">
<form action="" id="register_form" method="post">
<p>First Name <br />
<input type="text" id="firstname" name="firstname" /></p>
<p>Last Name <br />
<input type="text" id="lastname" name="lastname" /></p>
<p>Username: <span class="micro">Must be a valid email address</span></span><br />
<input type="text" id="username" name="username" /></p>
<p><input type="submit" value="Register" id="register" /></p>
</form>
</div>
Here's the relevant parts of the modal code:
// Insert modal at end of </body>.
$('body').append('<div id="modal_wrapper"><!--[if IE 6]><iframe id="modal_iframe" frameborder="0"></iframe><![endif]--><div id="modal_overlay"></div><div id="modal_window"><div id="modal_bar"><strong>Modal window</strong>Close</div><div id="modal_content"><div id="contact"><form><p><input id="firstname" /></p><p><input id="register" /></p></form></div></div></div>');
$('#modal_content').load('mediaKitF.html#contact'.replace('#', ' #'), '', showModal);
$("input[type=text]").focus(function(){
// Select field contents
this.select();
});
$('input #firstname').focus();
$('#register').click(function () {
alert("hello there");
});

$('#modal_content').load() is an asynchronous method, which means that you are trying to attach your click event to the $('#register') element before receiving the new content. You need to either use $('#register').live('click', function() {}) or move the code attaching the click handler into your showModal function.