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Cycle through classes on Jquery to animate

enter image description here
I'm trying to create an animation where if you click the button the circles animate around the path and changes size. I'm not sure how i would cycle the classes on the next click ?
http://bluemoontesting.co.uk/bluemoon2016/people.html
I'm using an svg and have targeted the elements with this so far:
<script>
$(".animate-slider").click(function() {
$('.st7').toggleClass("top-left");
$('#XMLID_292_').toggleClass("left");
$('#XMLID_293_').toggleClass("center-right");
$('#XMLID_297_').toggleClass("top-right");
$('#XMLID_301_').toggleClass("top");
$('#XMLID_283_').toggleClass("top-center");
});
</script>
If anyone could help me i'd be very grateful :)
Thanks

I would take a little different approach. Instead of toggling classes, to get it to move to more than two positions, you will need to cycle the classes assigned to each element instead. Storing the class names in an array would allow you to move them in the array to cycle the position that each element moves to next. I created a simplified example.
$(document).ready(function () {
var steps = ['right', 'bottom-right', 'bottom-left', 'left', 'top'],
allClasses = steps.join(' ');
$('#go').click(function() {
$('#a').removeClass(allClasses).addClass(steps[0]);
$('#b').removeClass(allClasses).addClass(steps[1]);
$('#c').removeClass(allClasses).addClass(steps[2]);
$('#d').removeClass(allClasses).addClass(steps[3]);
$('#e').removeClass(allClasses).addClass(steps[4]);
steps.push(steps.shift()); // move first element to the end
// to cycle in the other direction you would pop and unshift instead
// steps.unshift(steps.pop()); // move last element to the beginning
});
});

You could just use setInterval like so:
var $st7 = $('.st7'); //class selectors can be expensive, so cache them
function rotate() {
$st7.toggleClass("top-left");
$('#XMLID_292_').toggleClass("left");
$('#XMLID_293_').toggleClass("center-right");
$('#XMLID_297_').toggleClass("top-right");
$('#XMLID_301_').toggleClass("top");
$('#XMLID_283_').toggleClass("top-center");
}
//2000 is milliseconds, so that's two seconds
var rotateIntervalId = setInterval(rotate, 2000);
//optionally consider stopping/starting the effect on mouse hover/exit
$('#Layer_1').on('hover', function() {
clearInterval(rotateIntervalId);
}).on('blur', function() {
rotateIntervalId = setInterval(rotate, 2000);
});

jQuery clone an image with a class of active and set it as background image of a div

I am using twitter bootstrap's default carousel for a simple slider. What I want to achieve is that whichever item is active, the img inside that item should also be cloned and set as the background image of the div with the class of 'testimonials-bg'.
I have tried the following code but it does not seem to be working:
$("#testimonial-carousel .item.active").each(function() {
var $myBg = $(".testimonial-bg", this),
$myImg = $(".testimonial-img img", this);
$myBg.css({backgroundImage: "url('"+ $myImg[0].src +"')"});
});
I have made a Fiddle for this:
https://jsfiddle.net/4t17wxxw/

Subscribe to slid.bs.carousel event and change the background image to the active one:
var $myBg = $(".testimonial-bg");
$('#testimonial-carousel').on('slid.bs.carousel', function () {
var $img = $('img','.carousel-inner>.item.active');
$myBg.css({backgroundImage: "url('"+ $img[0].src +"')"});
console.log($img[0].src);
});
Working fiddle

Your code is run only once when the script starts but you want to run it everytime the slide changes. Therefore, you can subscribe to the 'slid.bs.carousel' event which fires everytime the carousel displays a new slide.
You can read more about the event here: http://getbootstrap.com/javascript/#carousel-events.
// Testimonial Background from active slide
$('#testimonial-carousel').on('slid.bs.carousel', function () {
$("#testimonial-carousel .item.active").each(function() {
var $myBg = $(".testimonial-bg", this),
$myImg = $(".testimonial-img img", this);
$myBg.css({backgroundImage: "url('"+ $myImg[0].src +"')"});
});
});

There is no class called "testimonial-bg", here is the code which should call on each slide rotate or when you need to assign background image.
$("#testimonial-carousel .item.active").each(function() {
$(this).css("background", "url('"+$(this).find(".testimonial-img img").attr('src')+"')" );
});
Fiddle demo link
Cheers

How to make an image popup on click?

So my incremental has come a long way, I got assistance here to make the original popup and it works great, now i really want to make the popup an image?
so far i have:
$("#coffeeButton").click(function(e) {
var obj = $("#clone").clone();
$("body").append(obj);
obj.html("+"+ cookRate);
coffee += cookRate;
totalCoffee += cookRate;
document.getElementById("coffee").innerHTML = prettify(coffee);
document.getElementById("totalCoffee").innerHTML = prettify(totalCoffee);
obj.css('position','absolute');
obj.offset({left: e.pageX-10, top: e.pageY-25});
obj.animate({"top": "-=80px"}, 1000, "linear", function() {
$(this).remove();
});
});
and it works great and gives me a popup, but how the hell do i make it an image?
I have tried creating a div, putting an image inside that div and instead of calling "clone" calling on the div...
Am i on the right track?
Example of what i want from cookie clicker - http://orteil.dashnet.org/cookieclicker/
my game so far - retiredgamers.net/
jsfiddle - http://jsfiddle.net/edznycyy/6/

There are probably a lot of ways you could do this. To keep things as close to what you have now as possible here's what I would do...essentially just create 2 elements the first being your numbers and the second being the image, make sure the number is above the image using css's z-index, then animate them both in tandem:
Here's a working jsfiddle
HTML changes:
<img title = "" id="myImg" src="http://blog.beautyfix.com/wp-content/uploads/2012/09/Coffee_iStock_000006160362Medium.jpg" style="display:none" width="30" height="30">
Javascript changes:
$("#coffeeButton").click(function(e) {
var obj = $("#clone").clone(); //im guessing you chose to use clone here to make it easier to work with the object, so I did the same for the image
var img = $("#myImg").clone();
$("body").append(obj);
$("body").append(img);
obj.html("+"+ cookRate);
coffee += cookRate;
totalCoffee += cookRate;
document.getElementById("coffee").innerHTML = prettify(coffee);
document.getElementById("totalCoffee").innerHTML = prettify(totalCoffee);
obj.css('position','absolute');
obj.css('z-index', '2');
img.css('position','absolute');
img.show();
obj.offset({left: e.pageX-10, top: e.pageY-25});
img.offset({left: e.pageX-10, top: e.pageY-25});
obj.animate({"top": "-=80px"}, 1000, "linear", function() {
$(this).remove();
});
img.animate({"top": "-=80px"}, 1000, "linear", function() {
$(this).remove();
});
});

if you don't want to the trouble of doing it your self, you can use a jquery plugin that does it quite easily. I am sure there is a lot more in the,
Here is what i found!
Here is the demo page for full-screan popup plugin
....
<script src="//code.jquery.com/jquery-1.11.1.min.js"></script>
<script src="jquery.fullscreen-popup.js"></script>
....
<a class="open-popup" href="#popup">Open popup</a>
...
<div id="popup" style="display: none; width: 640px">
...
</div>
<script>
$(function() {
$(".open-popup").fullScreenPopup({
// Options
});
});
</script>
Example is from here and you can download the plugin from here and a list that contains many more

How do I show or hide div, based on position of another div

I have the following jquery that slides a div horizontally:
$('.nextcol').click(function() {
$('.innerslide').animate({'left': '-=711px'}, 1000);
});
$('.prevcol').click(function() {
$('.innerslide').animate({'left': '+=711px'}, 1000);
});
What I want to happen is this... if the div.innerslide has a position that is left: 0px then I want to hide div.backarrow. If the position is not left: 0px, then it shows it.
Any help would be greatly appreciated.
EDIT (added HTML Markup)
<div class="backarrow prevcol">
<div id="mainleft" class="overflowhidden">
<div class="innerslide">
<div class="col">my content including next</div>
<div class="col">my content including next</div>
<div class="col">my content including next</div>
</div>
</div>

Try this:
if ($('.innerslide').css("left") == 0) {
$('div.backarrow').hide();
} else {
$('div.backarrow').show();
}
Fix for Double-Click Issue:
From what you described in your comment about the issue when the visitor double-clicks, it sounds like the double-click is causing two of the animation events to fire. To keep this from happening, you can either disable the click handler while the animation is running and re-enable it once it is finished, or you can try to write a new thread to continually check the element's position. One of these solutions is not a good idea - I'll let you figure out which one :) - but the other actually has a very simple solution that requires little change to your existing code (and may actually reduce your overhead by a teeny weeny amount):
$('.nextcol').on("click.next", function() {
$('.innerslide').animate({'left': '-=711px'}, 1000, showHideBack());
$(this).off("click.next");
});
$('.prevcol').on("click.prev", function() {
$('.innerslide').animate({'left': '+=711px'}, 1000, showHideForward());
$(this).off("click.prev");
});
Then add this this line to showHideBack() (and a complementary one to showHideForward() if you are using that):
$('.nextcol').on("click.next".....
I suggest that you write a function to set each click handler and another to remove each one. This will make your live very easy and the whole solution should reduce overhead by removing unnecessary click handlers while the animation is running.
Note: the animation method often calls its callback before the animation finishes. As such, you may wish to use a delay before calling the showHide... method(s).
Let me know if you have any questions. Good luck! :)
UPDATE:
Here is the updated version of the fiddle you gave me with all bugs ironed out. It looks like I misunderstood part of your goal in my original solution, but I straightened it out here. I have also included the updated jQuery, here:
var speed = 1000;
var back = $("div.backarrow");
var next = $(".nextcol");
var prev = $(".prevcol");
var inner = $(".innerslide");
function clickNext(index) {
next.off("click.next");
inner.animate({
'left': '-=711px'
}, speed, function() {
back.show(); //this line will only be hit if there is a previous column to show
next.delay(speed).on("click.next", function() {
clickNext();
});
});
}
function clickPrev() {
prev.off("click.prev");
inner.animate({
'left': '+=711px'
}, speed, function() {
if (inner.css("left") == "0px") {
back.delay(speed).hide();
prev.delay(speed).on("click.prev", function() {
clickPrev();
});
} else {
back.delay(speed).show();
prev.delay(speed).on("click.prev", function() {
clickPrev();
});
}
});
}
next.on("click.next", function() {
clickNext();
});
prev.on("click.prev", function() {
clickPrev();
});​
I was going to also include a condition to check if you were viewing the last column, but, as I don't know what your final implementation will be, I didn't know if it would be applicable. As always, let me know if you need help or clarification on any of this. :)

You could try the step option — a callback function that is fired at each step of the animation:
$('.prevcol').click(function() {
$('.innerslide').animate({ left: '+=711px' },
{
duration: 1000,
step: function(now, fx) {
if (now === 0 ) {
$('div.backarrow').hide();
} else {
$('div.backarrow').show();
}
}
});
});
More examples of usage in this article The jQuery animate() step callback function

JQuery if hovering on either element

So I have 2 divs. One is "top" and one is "menu." I got "menu" to fade in when you hover on "top" in JQuery, as shown:
$(".top").mouseover(function(){
$(".menu").fadeIn(200);
});
$(".top").mouseout(function(){
$(".menu").fadeOut(200);
});
But I want to make it so if I'm also hovering on "menu," "menu" will stay faded in. How would I do this?

I believe this will do it for you. It waits half a second before hiding the menu. If the user hovers over the menu in that time, then it cancels the hide operation.
var timer;
$(".top").mouseover(function(){
clearTimeout(timer);
$(".menu").fadeIn(200);
});
$(".top, .menu").mouseout(function(){
timer = setTimeout(function() {
$(".menu").fadeOut(200);
}, 500);
});
$(".menu").mouseover(function() {
clearTimeout(timer);
});

Add a variable that remembers if you are hovering on the menu:
var isHoveringMenu;
$(".menu").mouseover(function(){
isHoveringMenu = true;
});
$(".menu").mouseout(function(){
isHoveringMenu = false;
$(".menu").fadeOut(200); // you probably want this here
});
$(".top").mouseover(function(){
$(".menu").fadeIn(200);
isHoveringMenu = true; // not necessary, but sounds good
});
$(".top").mouseout(function(){
if (!isHoveringMenu) {
$(".menu").fadeOut(200);
}
});
You may want to tweak this slightly -- the best solution depends on the spatial relationship between the two divs, so we 'd need to see the layout first.