I am using both javascript and jquery code on the same html page. For some reason, the jQuery library is stopping my native javascript code from working properly.
I found this page: jQuery No Conflict that says you can use a jquery.noConflict to release $ back to javascript. However, I'm not sure how to do this?
Specifically, I'm not sure how to implement this correctly? Where does the the Jquery code go, where does the JS code go?
My code is below:
<script type="text/javascript">
$.noConflict();
// Code that uses other library's $ can follow here.
</script>
jQuery.noConflict will reset the $ variable so it's no longer an alias of jQuery. Aside from just calling it once, there's not much else you really need to do. Though, you can create your own alias with the return value, if you'd like:
var jq = jQuery.noConflict();
And, generally, you want to do this right after including jQuery and any plugins:
<script type="text/javascript" src="/path/to/jquery.js"></script>
<script type="text/javascript" src="/path/to/jquery-plugin.js"></script>
<script type="text/javascript">
jQuery.noConflict();
// Code that uses other library's $ can follow here.
</script>
<script type="text/javascript" src="/path/to/prototype.js"></script>
You can also go one step further and free up jQuery with noConflict(true). Though, if you take this route, you'll definitely want an alias as neither $ nor jQuery will probably be what you want:
var jq = jQuery.noConflict(true);
I think this last option is mostly used for mixing versions of jQuery, particularly for out-dated plugins when you want to update jQuery itself:
<script type="text/javascript" src="jquery-1.4.4.js"></script>
<script type="text/javascript" src="jquery-older-plugin.js"></script>
<script type="text/javascript">
var jq144 = jQuery.noConflict(true);
</script>
<script type="text/javascript" src="jquery-1.6.4.js"></script>
<script type="text/javascript" src="jquery-newer-plugin.js"></script>
By default, jquery uses the variable jQuery and the $ is used for your convenience. If you want to avoid conflicts, a good way is to encapsulate jQuery like so:
(function($){
$(function(){
alert('$ is safe!');
});
})(jQuery)
If I'm not mistaken:
var jq = $.noConflict();
then you can call jquery function with jq.(whatever).
jq('#selector');
It's typically used if you are using another library that uses $.
In order to still use the $ symbol for jQuery, I typically use:
jQuery.noConflict()(function($){
// jQuery code here
});
It allows for you to give the jQuery variable a different name, and still use it:
<script type="text/javascript">
$jq = $.noConflict();
// Code that uses other library's $ can follow here.
//use $jq for all calls to jQuery:
$jq.ajax(...)
$jq('selector')
</script>
If you look at the examples on the api page there is this:
Example: Creates a different alias instead of jQuery to use in the rest of the script.
var j = jQuery.noConflict();
// Do something with jQuery
j("div p").hide();
// Do something with another library's $()
$("content").style.display = 'none';
Put the var j = jQuery.noConflict() after you bring in jquery and then bring in the conflicting scripts. You can then use the j in place of $ for all your jquery needs and use the $ for the other script.
In addition to that, passing true to $.noConflict(true); will also restore previous (if any) global variable jQuery, so that plugins can be initialized with correct jQuery version when multiple versions are being used.
You simply assign a custom variable for JQuery to use instead of its default $. JQuery then wraps itself in a new function scope so $ no longer has a namespace conflict.
<script type="text/javascript">
$jQuery = $.noConflict();
// Other library code here which uses '$'
$jQuery(function(){ /* dom ready */ }
</script>
The noConflict() method releases the $ shortcut identifier, so that other scripts can use it for next time.
Default jquery $ as:
// Actin with $
$(function(){
$(".add").hide();
$(".add2").show();
});
Or as custom:
var j = jQuery.noConflict();
// Action with j
j(function(){
j(".edit").hide();
j(".add2").show();
});
<script src="JavascriptLibrary/jquery-1.4.2.js"></script>
<script>
var $i = jQuery.noConflict();
// alert($i.fn.jquery);
</script>
<script src="JavascriptLibrary/jquery-1.8.3.js"></script>
<script>
var $j = jQuery.noConflict();
//alert($j.fn.jquery);
</script>
<script src="JavascriptLibrary/jquery.colorbox.js"></script>
<script src="Js/jquery-1.12.3.js"></script>
<script>
var $NJS = jQuery.noConflict();
</script>
You can do it like this:
<script>
$i.alert('hi i am jquery-1.4.2.js alert function');
$j.alert('hi i am jquery-1.8.3.js alert function');
</script>
Today i have this issue because i have implemented "bootstrap menu" that uses a jQuery version along with "fancybox image gallery". Of course one plugin works and the other not due to jQuery conflict but i have overcome it as follow:
First i have added the "bootstrap menu" Js in the script footer as the menu is presented allover the website pages:
<!-- Top Menu Javascript -->
<script type="text/javascript" src="js/jquery.min.js"></script>
<script type="text/javascript" src="js/bootstrap.min.js"></script>
<script type="text/javascript">
var jq171 = jQuery.noConflict(true);
</script>
And in the "fancybox" image gallery page as follow:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script>window.jQuery || document.write('<script src="fancybox/js/libs/jquery-1.7.1.min.js"><\/script>')</script>
And the good thing is both working like a charm :)
Give it a try :)
I fixed that error by adding this conflict code
<script type="text/javascript">
jQuery.noConflict();
</script>
after my jQuery and js files and get the file was the error (found by the console of browser) and replace all the '$' by jQuery following this on all error js files in my Magento website. It's working for me good.
Find more details on my blog here
/* The noConflict() method releases the hold on the $ shortcut identifier, so that other scripts can use it. */
var jq = $.noConflict();
(function($){
$('document').ready(function(){
$('button').click(function(){
alert($('.para').text());
})
})
})(jq);
Live view example on codepen that is easy to understand: http://codepen.io/kaushik/pen/QGjeJQ
Related
A project I'm working on requires the use of jQuery on customers' Web pages. Customers will insert a chunk of code that we'll supply which includes a few <script> elements that build a widget in a <script>-created <iframe>. If they aren't already using the latest version of jQuery, this will also include (most likely) a <script> for Google's hosted version of jQuery.
The problem is that some customers may already have an older version of jQuery installed. While this may work if it's at least a fairly recent version, our code does rely on some recently introduced functionality in the jQuery library, so there are bound to be instances when a customer's jQuery version is just too old. We can't require that they upgrade to the latest version of jQuery.
Is there any way to load a newer version of jQuery to use only within the context of our code, that will not interfere with, or affect, any code on the customer's page? Ideally, maybe we could check for the presence of jQuery, detect the version, and if it's too old, then somehow load the most recent version just to use for our code.
I had the idea of loading jQuery in an <iframe> in the customer's domain that also includes our <script>, which seems like it might be feasible, but I'm hoping there's a more elegant way to do it (not to mention without the performance and complexity penalties of extra <iframe>s).
Yes, it's doable due to jQuery's noconflict mode. http://blog.nemikor.com/2009/10/03/using-multiple-versions-of-jquery/
<!-- load jQuery 1.1.3 -->
<script type="text/javascript" src="http://example.com/jquery-1.1.3.js"></script>
<script type="text/javascript">
var jQuery_1_1_3 = $.noConflict(true);
</script>
<!-- load jQuery 1.3.2 -->
<script type="text/javascript" src="http://example.com/jquery-1.3.2.js"></script>
<script type="text/javascript">
var jQuery_1_3_2 = $.noConflict(true);
</script>
Then, instead of $('#selector').function();, you'd do jQuery_1_3_2('#selector').function(); or jQuery_1_1_3('#selector').function();.
After looking at this and trying it out I found it actually didn't allow more than one instance of jquery to run at a time. After searching around I found that this did just the trick and was a whole lot less code.
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" type="text/javascript"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js" type="text/javascript"></script>
<script>var $j = jQuery.noConflict(true);</script>
<script>
$(document).ready(function(){
console.log($().jquery); // This prints v1.4.2
console.log($j().jquery); // This prints v1.9.1
});
</script>
So then adding the "j" after the "$" was all I needed to do.
$j(function() {
$j('.button-pro').on('click', function() {
var el = $('#cnt' + this.id.replace('btn', ''));
$j('#contentnew > div').not(el).animate({
height: "toggle",
opacity: "toggle"
}, 100).hide();
el.toggle();
});
});
Taken from http://forum.jquery.com/topic/multiple-versions-of-jquery-on-the-same-page:
Original page loads his "jquery.versionX.js" -- $ and jQuery belong to versionX.
You call your "jquery.versionY.js" -- now $ and jQuery belong to versionY, plus _$ and _jQuery belong to versionX.
my_jQuery = jQuery.noConflict(true); -- now $ and jQuery belong to versionX, _$ and _jQuery are probably null, and my_jQuery is versionY.
You can have as many different jQuery versions on your page as you want.
Use jQuery.noConflict():
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js" type="text/javascript"></script>
<script>
var $i = jQuery.noConflict();
alert($i.fn.jquery);
</script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script>
var $j = jQuery.noConflict();
alert($j.fn.jquery);
</script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script>
var $k = jQuery.noConflict();
alert($k.fn.jquery);
</script>
DEMO | Source
It is possible to load the second version of the jQuery use it and then restore to the original or keep the second version if there was no jQuery loaded before. Here is an example:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>
<script type="text/javascript">
var jQueryTemp = jQuery.noConflict(true);
var jQueryOriginal = jQuery || jQueryTemp;
if (window.jQuery){
console.log('Original jQuery: ', jQuery.fn.jquery);
console.log('Second jQuery: ', jQueryTemp.fn.jquery);
}
window.jQuery = window.$ = jQueryTemp;
</script>
<script type="text/javascript">
console.log('Script using second: ', jQuery.fn.jquery);
</script>
<script type="text/javascript">
// Restore original jQuery:
window.jQuery = window.$ = jQueryOriginal;
console.log('Script using original or the only version: ', jQuery.fn.jquery);
</script>
I would like to say that you must always use jQuery latest or recent stable versions. However if you need to do some work with others versions then you can add that version and renamed the $ to some other name. For instance
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js" type="text/javascript"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" type="text/javascript"></script>
<script>var $oldjQuery = $.noConflict(true);</script>
Look here if you write something using $ then you will get the latest version. But if you need to do anything with old then just use$oldjQuery instead of $.
Here is an example:
$(function(){console.log($.fn.jquery)});
$oldjQuery (function(){console.log($oldjQuery.fn.jquery)})
Demo
<script type="text/javascript"
src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script>var $j = $.noConflict(true);</script>
It was not working for me then I changed it to
<script>var jQuery = $.noConflict(true);</script>
and it worked for me.
To further improve Juan Vidal's answer, it is worth noting that if you use multiple jquery plugins with one version (eg 3.3.1) and multiple jquery plugins with another version(eg 1.10.2), for older version to work (and it's plugins) you must dig into plugin's minified/unminified .js file(s) and alter the line that will be something like this:
Example 1: module.exports=a:a(jQuery) to module.exports=a:a(my_jQuery)
Example 2: b(a,require("jquery")):b(a,a.jQuery)} to this: or b(a,require("jquery")):b(a,a.my_jQuery)}
A project I'm working on requires the use of jQuery on customers' Web pages. Customers will insert a chunk of code that we'll supply which includes a few <script> elements that build a widget in a <script>-created <iframe>. If they aren't already using the latest version of jQuery, this will also include (most likely) a <script> for Google's hosted version of jQuery.
The problem is that some customers may already have an older version of jQuery installed. While this may work if it's at least a fairly recent version, our code does rely on some recently introduced functionality in the jQuery library, so there are bound to be instances when a customer's jQuery version is just too old. We can't require that they upgrade to the latest version of jQuery.
Is there any way to load a newer version of jQuery to use only within the context of our code, that will not interfere with, or affect, any code on the customer's page? Ideally, maybe we could check for the presence of jQuery, detect the version, and if it's too old, then somehow load the most recent version just to use for our code.
I had the idea of loading jQuery in an <iframe> in the customer's domain that also includes our <script>, which seems like it might be feasible, but I'm hoping there's a more elegant way to do it (not to mention without the performance and complexity penalties of extra <iframe>s).
Yes, it's doable due to jQuery's noconflict mode. http://blog.nemikor.com/2009/10/03/using-multiple-versions-of-jquery/
<!-- load jQuery 1.1.3 -->
<script type="text/javascript" src="http://example.com/jquery-1.1.3.js"></script>
<script type="text/javascript">
var jQuery_1_1_3 = $.noConflict(true);
</script>
<!-- load jQuery 1.3.2 -->
<script type="text/javascript" src="http://example.com/jquery-1.3.2.js"></script>
<script type="text/javascript">
var jQuery_1_3_2 = $.noConflict(true);
</script>
Then, instead of $('#selector').function();, you'd do jQuery_1_3_2('#selector').function(); or jQuery_1_1_3('#selector').function();.
After looking at this and trying it out I found it actually didn't allow more than one instance of jquery to run at a time. After searching around I found that this did just the trick and was a whole lot less code.
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" type="text/javascript"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js" type="text/javascript"></script>
<script>var $j = jQuery.noConflict(true);</script>
<script>
$(document).ready(function(){
console.log($().jquery); // This prints v1.4.2
console.log($j().jquery); // This prints v1.9.1
});
</script>
So then adding the "j" after the "$" was all I needed to do.
$j(function() {
$j('.button-pro').on('click', function() {
var el = $('#cnt' + this.id.replace('btn', ''));
$j('#contentnew > div').not(el).animate({
height: "toggle",
opacity: "toggle"
}, 100).hide();
el.toggle();
});
});
Taken from http://forum.jquery.com/topic/multiple-versions-of-jquery-on-the-same-page:
Original page loads his "jquery.versionX.js" -- $ and jQuery belong to versionX.
You call your "jquery.versionY.js" -- now $ and jQuery belong to versionY, plus _$ and _jQuery belong to versionX.
my_jQuery = jQuery.noConflict(true); -- now $ and jQuery belong to versionX, _$ and _jQuery are probably null, and my_jQuery is versionY.
You can have as many different jQuery versions on your page as you want.
Use jQuery.noConflict():
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js" type="text/javascript"></script>
<script>
var $i = jQuery.noConflict();
alert($i.fn.jquery);
</script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script>
var $j = jQuery.noConflict();
alert($j.fn.jquery);
</script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script>
var $k = jQuery.noConflict();
alert($k.fn.jquery);
</script>
DEMO | Source
It is possible to load the second version of the jQuery use it and then restore to the original or keep the second version if there was no jQuery loaded before. Here is an example:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>
<script type="text/javascript">
var jQueryTemp = jQuery.noConflict(true);
var jQueryOriginal = jQuery || jQueryTemp;
if (window.jQuery){
console.log('Original jQuery: ', jQuery.fn.jquery);
console.log('Second jQuery: ', jQueryTemp.fn.jquery);
}
window.jQuery = window.$ = jQueryTemp;
</script>
<script type="text/javascript">
console.log('Script using second: ', jQuery.fn.jquery);
</script>
<script type="text/javascript">
// Restore original jQuery:
window.jQuery = window.$ = jQueryOriginal;
console.log('Script using original or the only version: ', jQuery.fn.jquery);
</script>
I would like to say that you must always use jQuery latest or recent stable versions. However if you need to do some work with others versions then you can add that version and renamed the $ to some other name. For instance
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js" type="text/javascript"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" type="text/javascript"></script>
<script>var $oldjQuery = $.noConflict(true);</script>
Look here if you write something using $ then you will get the latest version. But if you need to do anything with old then just use$oldjQuery instead of $.
Here is an example:
$(function(){console.log($.fn.jquery)});
$oldjQuery (function(){console.log($oldjQuery.fn.jquery)})
Demo
<script type="text/javascript"
src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script>var $j = $.noConflict(true);</script>
It was not working for me then I changed it to
<script>var jQuery = $.noConflict(true);</script>
and it worked for me.
To further improve Juan Vidal's answer, it is worth noting that if you use multiple jquery plugins with one version (eg 3.3.1) and multiple jquery plugins with another version(eg 1.10.2), for older version to work (and it's plugins) you must dig into plugin's minified/unminified .js file(s) and alter the line that will be something like this:
Example 1: module.exports=a:a(jQuery) to module.exports=a:a(my_jQuery)
Example 2: b(a,require("jquery")):b(a,a.jQuery)} to this: or b(a,require("jquery")):b(a,a.my_jQuery)}
I have the following references to the javascripts libraries.
<script type="text/javascript" src="jquery-1.8.2.min.js"></script>
<script type="text/javascript" src="modernizr-1.5.min.js"></script>
<script type="text/javascript" src="JavaScript-1.js"></script>
<script>jQuery.noConflict();</script>
<script>
$(document).ready(function () {
$('#tabs-2').html("<p>jQuery add </p>");
});
</script>
In the html there is a div with id tabs-2. I am not able to control the html elements using JQuery scripts. The above simple in-line script is also not working.
I have also added a custom script file which has the jQuery function as stated in this example.
Any inputs on how to add use custom JQuery libraries?
After you call
jQuery.noConflict();
you can no longer use $. You have to use jQuery, or, assign the return value from the noConflict() call to a variable and use that:
var $j = jQuery.noConflict();
$j(document).ready(function($) {
// here you can use $ again
});
To keep your custom scripts compatible whether jQuery is in no-conflict mode or not, you could wrap it with an IIFE:
(function($) {
// your code that uses '$'
})(jQuery);
See: jQuery.noConflict() documentation
The following line
<script>jQuery.noConflict();</script>
means that jQUery runs in no conflict mode. This means that $ is not aliased to the jQuery object and you have to use jQueryisntead of $
You can use the noConflict() function
<script src="other_lib.js"></script>
<script src="jquery.js"></script>
<script>
$.noConflict();
jQuery( document ).ready(function( $ ) {
// Code that uses jQuery's $ can follow here.
});
// Code that uses other library's $ can follow here.
</script>
JQuery.noConflict()
I use jQuery v1.6.4 http://code.jquery.com/jquery-1.6.4.js
and prototype.
I am trying to use the jQuery Tabs widget and it conflicts with prototype. As a result the upload button of an input isn't working.
I tried this to resolve but it doesn't seem to work.
<script type="text/javascript">
jQuery.noConflict();
_ccsjQ(function() {
_ccsjQ( "#tabs" ).tabs();
});
</script>
The funny thing is that if i press F5 the upload button works and when i refresh, doesnt work.
Easy way (IMHO) is just call jQuery.noConflict() then wrap any jQuery code in an anonymous function:
jQuery.noConflict();
(function($){
// use your standard $(...) in here
})(jQuery);
Alternatively, you need to assign jQuery a new alias if you're not going to use jQuery(...) (e.g. var jq = jQuery.noConflict(); then use jq(...)).
Example of both being used:
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/prototype/1.7.1.0/prototype.js"></script>
<script type="text/javascript">
var _cssjQ = jQuery.noConflict();
_cssjQ('.foo').css('color','#f0f');
(function($){
$('.bar').css('color','#f0f');
})(jQuery);
</script>
And the fiddle: http://jsfiddle.net/kbWah/1/
1) Define Jquery first
<script src="http://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
2) Add script after Jquery and Before prototype
<script>
var pjquery = jQuery.noConflict();//pjquery will represent jquery framework now on-wards
</script>
3) Now define prototype.js
<script type = "text/javascript" src = "js/prototype.js" ></script>
Now where ever jquery is to be called use pjquery instead of $ or Jquery.
In my main.js file : I configured the contentScriptFile to be script.js . Also, this script file is embedded in index.html which is a tab which will be opened using tabs.open .
I have self.port.on and jquery related things in that script file . If self.port is written on the top of other jquery things, self.port.on is working and jquery is not working . But, self.port.on is written below, jquery is working fine and self.port is not working.
The script file actually deals with the data obtained using self.port (will come only when tab opened,).
What about wrap all your jQuery code in a safe environment?
Using $:
(function($) {
// use $
})(jQuery)
Using $jq:
(function($jq) {
// use $jq
})(jQuery)
Many JavaScript libraries use $ as a function or variable name, just as jQuery does. In jQuery's case, $ is just an alias for jQuery, so all functionality is available without using $. If we need to use another JavaScript library alongside jQuery, we can return control of $ back to the other library with a call to $.noConflict():
<script type="text/javascript" src="other_lib.js"></script>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$.noConflict();
// Code that uses other library's $ can follow here.
</script>
This technique is especially effective in conjunction with the .ready() method's ability to alias the jQuery object, as within callback passed to .ready() we can use $ if we wish without fear of conflicts later:
<script type="text/javascript" src="other_lib.js"></script>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$.noConflict();
jQuery(document).ready(function($) {
// Code that uses jQuery's $ can follow here.
$("div").hide();
});
// Code that uses other library's $ can follow here.
$("content").style.display = 'none';
</script>
Source: jQuery.noConflict
Use jQuery's noConflict setting.
$jq = jQuery.noConflict(); //use $jq instead of $