How can you use a function that is defined below its usage? - javascript

I always thought that function a(){} is identical to a = function(){};
However, these two snippets behave differently:
a();
function a() {
alert("Booya");
}
Prints Booya.
a();
a = function() {
alert("Booya");
}
Fails with an exception, which makes sense, since a is really not defined when called.
So - what kind of 'magic' lets the first snippet work, even though a() is defined below its point of usage?

This is the difference between function declaration and function expression. This difference described well for example here.

In JavaScript all the declarations are hoisted. Means the variable can be used before it has been declared and function can be used before its declared.
It’s JavaScript’s default behaviour to move all the declarations at top of the current script.
But this feature may lead to bugs in application so we use strict mode directive to avoid bugs. Strict mode does not allow to use variables without declaration.
more info at here

See this article for an explanation: http://www.adequatelygood.com/2010/2/JavaScript-Scoping-and-Hoisting
Function declarations and variable declarations are always moved ("hoisted") invisibly to the top of their containing scope by the JavaScript interpreter.

No magic, proper coding is required. AFAIK
document is loaded and parsed, functions are 'loaded'. The the script is being executed. So far no problem _a() _ is found.
no function is 'maped'. The script si executed line by line. It tries to call a() and THEN assign function to a global variable a

Functions are defined global. But if you assign a function to a variable, as you do in the second case, the scope rules for variables come into effect: You can not call the function before its variable was defined.

Related

Javascript Hoisting - How are we Accessing Certain Variables?

I have two questions about hoisting:
The way function declarations are hoisted is that they go to the very top, even above variable declarations, to my understanding.
If we have this code:
function fn() {
callback();
}
function callback() {
console.log('why does this show');
}
I don't understand how this works, since both functions are hoisted to the top (which effectively produces the same code that already exists). But callback is still created below fn, and I don't see why we can access it in fn. My guess is it has something to do with the top level objects being able to access each other regardless of lexical position.
Similarly:
var a = 10;
function fn() {
console.log(a);
}
fn();
How does this work? Because the way I understand hoisting makes it seem like the function should be hoisted even above var a, which makes it seem like variables should always be inaccessible in functions.
We can go down the rabbit hole with this but I want to try to give a brief explanation on how your examples work.
Whenever the JavaScript engine creates an execution context (also known as calling stack) whether through functions or code in the global scope it creates an lexical environment. Which is a data structure that holds a collection of name/value pairs about variables and functions in it's own scope or from it's parent scope by using a reference.
About your first example. Both functions get added to the global execution context. If you call fn() in your first example initially. It will then add callback() to the call stack of fn() and execute it accordingly. So, the order of your functions don't really matter in this case.
You're second example is a different case. The execution context knowns you are referring to the global variable and therefor adding a reference to the lexical environment and that makes it able to use the variable inside fn().
This can be quite hard to get a grasp of. There are a ton of resources related to hoisting, scopes, lexical environments and execution contexts so be sure to check those out. :)
This is because how our Javascript Engine parse and compile the code.
I'm not an expert but V8 (The Chorme Engine for JS) in the first file get all the variables and functions names and store all the function references. So, you can "use" a function before "declare" because JS know where the function is.
Some languages, even C++ you could do that and is a nice feature :)

Scoping Rules in JavaScript

I am going through the book JavaScript: The Complete Reference, Third Edition By: Thomas Powell; Fritz Schneider to have a detailed understanding of the concepts.
Scoping Rules
Outside of a function or object, variables are within the global space whether explicitly defined with var or not. Within a function or object, if the var statement is used, the defined variable will be local to the construct; without the statement, it will be global.
Commonly, JavaScript developers make assumptions about scoping rules with var that aren’t quite true. For example, a var statement found within a for loop does not scope that value to the loop. In this case, it is scoped to either the function it is within or to the global space if it is outside a function or an object.
Just to see what happens consequently, I coded like this,
When I press Ctrl+Space in Eclipse IDE for it to show JavaScript proposals, why am I able to access the variable jLocal outside the function?
As per the author description:
For example, a var statement found within a for loop does not scope that value to the loop. In this case, it is scoped to either the function it is within or to the global space if it is outside a function or an object.
Because at the bottom of your code you have:
...
jLocal = jLocal + j; // defined not in any functions
...
Making it global, but not necessary defined.
It isn't the case of a local function. myFunc is global, just as the variable jLocal is (albeit the name). Because of hoisting, jLocal is assumed to be declared on top of parent scope.
Looking more carefully, there's two variable's named jLocal. One local to myFunc and an implicit one on global scope.
Want a tip?
Put "use strict"; just before var global1 = true;. An HTML 5 implementation would be able to catch and show your error.

What's getting placed in the initialization stage of JavaScript?

I'm reading about function declarations and function expressions. It say's that function declarations get placed in the initialization stage of JavaScript. Later I found out that variables also get placed in there, but they get the value of undefined, and when the interpreter reaches that variable it will then be assigned.
I can't find a good article about it. Now I'm wondering what else gets in the initialization stage of JavaScript?
Try searching for javascript hoisting (W3Schools).
It basically means, no matter where you declare a function or a variable, when the code is run the functions and variables are hoisted to the top and declared. This is why you can declare functions after you've used them and they still run fine.
However, initializing them is different. From W3Schools
JavaScript only hoists declarations, not initializations.
This means that the variables only get their assigned value when they reach the relevant line; functions are the same.
If you use a function expression such as:
var foo = function() {
// your code
}
In this case only the variable name will be hoisted and given the value undefined, and then if the function gets called above the function expression it will error as it has not have been assigned the function at this point in the code.

Why does this work in javascript?

Just now,I saw some code like this:
if(condition){
var xx='sss';
}
//do something
if(condition){
console.info(xx);
}
Now, I just wonder why the second if statement work? How can it access the xx variable since it is a local variable defined in another if statement?
var in JavaScript is scoped to the containing execution context (e.g., the whole function's scope, or the whole global scope if the var is at global scope), not the block. JavaScript doesn't (yet) have block scope (ECMAScript6 looks likely to add it, via the new let keyword).
The code you've quoted is exactly equivalent to this:
var xx;
if(condition){
xx='sss';
}
//do something
if(condition){
console.info(xx);
}
This is covered by Section 10.5 of the specification, which describes what the engine does when entering a new execution context. (It's basically a two-phase process, first setting up all the declarations, and then executing step-by-step code.)
More: Poor misunderstood var
In JavaScript the scope is exacted to the closure (the last enclosing function block, or defaults to the window object). When a variable is declared anywhere within that function block it is hoisted to the top of the scope, so in essence a variable exists as undefined starting at the very top of the scope if it is declared anywhere in the scope.
Think of it like this, when the code begins executing it scans all the instructions for declarations and allocates the symbol name starting immediately.
console.log(x); // undefined
console.log(y); // error: Uncaught ReferenceError: y is not defined
var x;
for that matter you can take it to extremes:
console.log(x); // undefined, not an error
while (false) {
if (false) {
var x;
}
}
even though var x can't possibly be reached, and during execution would be optimized away completely. the engine will still hoist the variable to the top of the scope
hope this helps -ck
useful link: http://www.youtube.com/watch?v=taaEzHI9xyY&feature=youtu.be#t=42m57s
var declarations affect the entire scope of the smallest containing function or program. JavaScript is not block scoped.
Crock says:
Variable Declarations
All variables should be declared before used. JavaScript does not require this, but doing so makes the program easier to read and makes it easier to detect undeclared variables that may become implied globals. Implied global variables should never be used.
The var statements should be the first statements in the function body.
It is preferred that each variable be given its own line and comment. They should be listed in alphabetical order.
var currentEntry; // currently selected table entry
var level; // indentation level
var size; // size of table
JavaScript does not have block scope, so defining variables in blocks can confuse programmers who are experienced with other C family languages. Define all variables at the top of the function.
Use of global variables should be minimized. Implied global variables should never be used.
Note, this is changing with the let statement, and in current JavaScript (EcmaScript 5), the variable name in a catch block is block scoped.
javascript doesn't have block scope, so var xx='sss' is either locally scoped (if your sample code is inside a function) or globally scoped (if your sample code is not contained in a function).
JavaScript is a dynamic language, that isn't always picky about things like variable scoping. So, this "feature" allows you to write the code
if (condition) {
var xx = 'sss';
} else {
var xx = 'ttt';
}
// do something
if (condition) {
console.info(xx);
}
I would recommend avoiding this, since it makes your program harder to understanda and reason about.
If you declare a variable using var within a function, the variable is scoped to within that function. An if statement is not a function.
I'm assuming in this case both if statements are within the same function and therefore xx is in scope?
If a variable is declared inside a conditional statement, it is still available anywhere following the declaration in the containing function (or globally if the conditional is not in a function). However, it will equal undefined if the condition evaluates to false, unless the variable is later assigned a value.
If a local variable is referenced globally or in another function, a JavaScript error will occur. Depending on your browser, the error may say the variable "is not defined" or "is undefined". This is different from the variable equaling undefined like mentioned above, because a variable that equals undefined can still be referenced.

What is the scope of a function in Javascript/ECMAScript?

Today I had a discussion with a colleague about nested functions in Javascript:
function a() {
function b() {
alert('boo')
}
var c = 'Bound to local call object.'
d = 'Bound to global object.'
}
In this example, trials point out that b is not reachable outside the body of a, much like c is. However, d is - after executing a(). Looking for the exact definition of this behaviour in the ECMAScript v.3 standard , I didn't find the exact wording I was looking for; what Sec.13 p.71 does not say, is which object the function object created by the function declaration statement is to be bound to. Am I missing something?
This is static scoping. Statements within a function are scoped within that function.
Javascript has a quirky behavior, however, which is that without the var keyword, you've implied a global variable. That's what you're seeing in your test. Your "d" variable is available because it is an implied global, despite being written within the body of a function.
Also, to answer the second part of your question: A function exists in whatever scope it is declared, just like a variable.
Sidenote:
You probably don't want global variables, especially not implied ones. It's recommended that you always use the var keyword, to prevent confusion and to keep everything clean.
Sidenote:
The ECMA Standard isn't probably the most helpful place to find answers about Javascript, although it certainly isn't a bad resource. Remember that javascript in your browser is just an implementation of that standard, so the standards document will be giving you the rules that were (mostly) followed by the implementors when the javascript engine was being built. It can't offer specific information about the implementations you care about, namely the major browsers. There are a couple of books in particular which will give you very direct information about how the javascript implementations in the major browsers behave. To illustrate the difference, I'll include excerpts below from both the ECMAScript specification, and a book on Javascript. I think you'll agree that the book gives a more direct answer.
Here's from the ECMAScript Language Specification:
10.2 Entering An Execution Context
Every function and constructor call
enters a new execution context, even
if a function is calling itself
recursively. Every return exits an
execution context. A thrown exception,
if not caught, may also exit one or
more execution contexts.
When control
enters an execution context, the scope
chain is created and initialised,
variable instantiation is performed,
and the this value is determined.
The
initialisation of the scope chain,
variable instantiation, and the
determination of the this value depend
on the type of code being entered.
Here's from O'Reilly's Javascript: The Definitive Guide (5th Edition):
8.8.1 Lexical Scoping
Functions in JavaScript are lexically
rather than dynamically scoped. This
means that they run in the scope in
which they are defined, not the scope
from which they are executed. When a
function is defined, the current scope
chain is saved and becomes part of
the internal state of the function.
...
Highly recommended for covering these kinds of questions is Douglas Crockford's book:
JavaScript, The Good Parts http://oreilly.com/catalog/covers/9780596517748_cat.gif
Javascript, The Good Parts, also from O'Reilly.
As I understand it, these are equivalent as far as scoping is concerned:
function a() { ... }
and
var a = function() { ... }
It seems important to note that while d is being created as a "global", it is in reality being created as a property of the window object. This means that you could inadvertently be overwriting something that already exists on the window object or your variable might actually fail to be created at all. So:
function a() {
d = 'Hello World';
}
alert(window.d); // shows 'Hello World'
But you cannot do:
function a() {
document = 'something';
}
because you cannot overwrite the window.document object.
For all practical purposes you can imaging that all of your code is running in a giant with(window) block.
Javascript has two scopes. Global, and functional. If you declare a variable inside a function using the "var" keyword, it will be local to that function, and any inner functions. If you declare a variable outside of a function, it has global scope.
Finally, if you omit the var keyword when first declaring a variable, javascript assumes you wanted a global variable, no matter where you declare it.
So, you're calling function a, and function a is declaring a global variable d.
...
function a() {
function b() {
alert('boo')
}
var c = 'Bound to local call object.'
d = 'Bound to global object.'
}
without being preceded by var, d is global. Do this to made d private:
function a() {
function b() {
alert('boo')
}
var c = 'Bound to local call object.'
var d = 'Bound to local object.'
}

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