I'm trying to make a gallery with highslide.
I have two thumbnails, a larger but cropped one listed on the page opening the large image if clicked on, and a smaller one with varying aspect ratio for the thumbstrip.
How do I configure highslide to actually use different images for the thumbstrip?
For example this is a part of the markup:
<a href="highslide/sample-images/picture12.jpg" class="highslide"
title="Caption from the anchor's title attribute"
onclick="return hs.expand(this, config1 )">
<img src="highslide/sample-images/picture12.thumb.jpg" alt=""/>
</a>
The link is pointing to the large picture, the img is showing the cropped thumbnail.
Can I override a function for example to use two thumbnails like:
<a href="highslide/sample-images/picture12.jpg" class="highslide"
title="Caption from the anchor's title attribute"
onclick="return hs.expand(this, config1 )">
<img class="thumb" src="highslide/sample-images/picture12.thumb.jpg" alt=""/>
<img class="strip" src="highslide/sample-images/picture12.strip.jpg" style="display: none" alt="" />
</a>
Actually I found a solution to this some time ago:
On the highslide api reference http://highslide.com/ref/ there is a function stripItemFormatter. The parameter of the function is the element you expand (the element).
the string returned by this function will be parsed as html, and used as an item of the thumbstrip.
If you check this example: http://highslide.com/ref/hs.stripItemFormatter you can see how it's done.
Related
Trying to change img src attribute to src matching another picture on site which user hovered over. I have 1 (main) picture and I have 3 below it (sub), acting as a gallery. When user hovers over one of those 3, I want src attribute of main to change to src of sub image.
All resolutions I found so far, use either 1 image whose source is changed in code or only specific sources declared but I don't want to add sources in code every time a new image is added, instead, using i.e. gallery(this) for each sub-image should resolve it but I'm having no luck so far.
Apologies if there is same question, I just couldn't find it. If this explanation is too complicated, feel free to ask, I'm looking forward resolving this, if possible.
Tried to use function name(this) to exploit source of image and add it to main picture.
I'm really just starting with all of this so this what I tried so far probably isn't even close enough, hope you will understand.
<img class="hover" src="imgs/mountain.jpg" id="hover" alt="">
<div class="imgs">
<img onmouseover="gallery(this)" src="imgs/castle.jpg" alt="">
<img onmouseover="gallery(this)" src="imgs/mountain.jpg" alt="">
<img onmouseover="gallery(this)" src="imgs/tree.jpg" alt="">
</div>
<script>
function gallery(element) {
x = document.getElementById('hover');
x.src.element;
}
</script>
You aren't actually changing the src. You can do so by setting x.src to element.src:
function gallery(element) {
x = document.getElementById('hover');
x.src = element.src;
}
<div class="imgs">
<img onmouseover="gallery(this)" src="https://picsum.photos/100?random=1" alt="">
<img onmouseover="gallery(this)" src="https://picsum.photos/100?random=2" alt="">
<img onmouseover="gallery(this)" src="https://picsum.photos/100?random=3" alt="">
</div>
<img id="hover" alt="hover">
As Kobe states in their answer, to set the src you can use img.src = {source}.
I would recommend that you add event listeners to each image, rather than using attributes to call the function. This provides a much cleaner solution. I have added the .gallery class to each image, then, it loops through these elements adding the event listener.
function displayImage() {
x.src = this.src;
}
// Pull this out of the function to avoid the lookup every time
var x = document.getElementById('hover');
// Loop through each element with the gallery class and add the event listener
document.querySelectorAll(".gallery").forEach(function(img) {
img.addEventListener("mouseover", displayImage);
});
<div class="imgs">
<img class="gallery" src="https://picsum.photos/100?random=1" alt="">
<img class="gallery" src="https://picsum.photos/100?random=2" alt="">
<img class="gallery" src="https://picsum.photos/100?random=3" alt="">
</div>
<img id="hover" alt="hover">
I have the following code for viewing an image in a new window. Both code snippets are able to produce the same HTML in the new window but the first one is not rendering the image and the second one is working fine.
<a onclick="window.open(this.href);return false;" href="javascript: var i = new Image(250, 250);i.src='image_url'; document.body.appendChild(i);" >VIEW1</a>
<a onclick="window.open(this.href);return false;" href="javascript: document.body.innerHTML='<img width="250" height="250" src="image_url"/>';">VIEW2</a>
I want to know why innerHTML is working and appendChild not working
The "URL" is for the link to the picture, and the "text" is there as a description if the Image should for some reason not load (broken requests)
<a onclick="window.open(this.href);return false;" href="javascript: document.body.innerHTML='<div><Img width="250" height="250" src="file:///home/lt-176/tudip-image.jpg" alt="text"></div>';">VIEW2</a>
image src path to give full path...is working
This seems to be a Safari exclusive bug, and I can't seem to find any information on why it might even be happening.
It's only on Safari, and only using SVG.
I am using the Data Attribute rollover technique using jQuery.
$("img.rollover").hover (->
imgRolloverSwap($(#))
), ->
imgRolloverSwap($(#))
imgRolloverSwap = ($img)->
srcName = $img.attr('src')
$img.attr('src', $img.data('rollover'))
$img.data('rollover', srcName)
The SVG is embedded with the IMG tag, and basically all it does is switch out the rollover image for the one inside the data attribute.
My HTML is thus:
<div id="social-links">
<a href="https://www.facebook.com/pages/StackCommerce/220449001487225">
<img data-rollover="/assets/img/footer/facebook-rollover.svg" class="rollover" type='image/svg+xml' src="/assets/img/footer/facebook.svg" />
<!-- <img class="rollover" src="/assets/img/footer/facebook.svg" alt="facebook link" target="_blank"> -->
</a>
<a href="https://www.linkedin.com/company/stackcommerce">
<img class="rollover" src="/assets/img/footer/linkedin.svg" alt="linkedin link" target="_blank">
</a>
<a href="https://plus.google.com/u/0/b/104759401634432683234/104759401634432683234/aboute">
<img class="rollover" src="/assets/img/footer/google.svg" alt="google plus link" target="_blank">
</a>
<a href="https://twitter.com/stackcommerce">
<img class="rollover" src="/assets/img/footer/twitter.svg" alt="twitter link" target="_blank">
</a>
</div>
The CSS(Sass) is this:
#social-links {
#extend .col-xs-12, .col-sm-3, .col-md-2;
a {
#extend .col-xs-3, .col-sm-6;
margin-bottom: 15px;
}
img {
#extend .img-responsive;
}
}
However, on first hover the image works, but when you roll off, the image gets smaller.
This happens if you use the jQuery technique or if you use vanilla JS to change out the src name with a regular expression.
This doesn't happen to other image formats, and I have tried setting different 100% widths on nearly every element of the cascade.
Fixes from these threads don't seem to be fixes:
SVG resizes on hover in safari only
Scaling/Resizing SVG in an HTML
Rollover SVG images resizing in Safari and IE
Perhaps someone can shed some light on why this is happening, or a technique to help in Safari?
You can see it here on this page, and at the bottom of it in the footer.
http://beta.stackcommerce.com.s3-website-us-east-1.amazonaws.com/publishers/
Thanks in advance!
I have a WooCommerce setup where I have a gallery. One is big image and others are thumbnails.
What I want to do is when someone clicks on the thumbnail, it replaces the big image and the big image comes there at the thumbnail. How do I do that? Any JavaScript guru here to help?
Here is the full HTML output.
<div class="images product-gallery ">
<div class="big_image">
<a title="" href="http://www.domain.com/image001.jpg" itemprop="image" class="woocommerce-main-image zoom"><img width="300" height="300" alt="" class="attachment-shop_single wp-post-image" src="http://www.domain.com/image001-300x300.jpg"></a>
</div>
<div class="thumbnails">
<a title="" class="zoom first" href="http://www.domain.com/image002.jpg"><img width="90" height="90" alt="" class="attachment-shop_thumbnail" src="http://www.domain.com/image002-90x90.jpg"><div class="numbers">1</div></a>
<a title="" class="zoom" href="http://www.domain.com/image003.jpg"><img width="90" height="90" alt="" class="attachment-shop_thumbnail" src="http://www.domain.com/image003-90x90.jpg"><div class="numbers">2</div></a>
<a title="" class="zoom last" href="http://www.domain.com/image004.jpg"><img width="90" height="90" alt="" class="attachment-shop_thumbnail" src="http://www.domain.com/image004-90x90.jpg"><div class="numbers">3</div></a>
<a title="" class="zoom first" href="http://www.domain.com/image005.jpg"><img width="90" height="90" alt="" class="attachment-shop_thumbnail" src="http://www.domain.com/image005-90x90.jpg"><div class="numbers">4</div></a>
</div>
<div class="clear"></div>
</div>
I don't need that <a href=" part on image. So, you can ignore them.
I have very little knowledge in JavaScript, so please help me out. All I want is when someone click on any of the thumbnail image, the thumbnail image replaces the big image and the big image replace the clicked thumbnail. So basically the alter positions.
Please pardon me for my poor English.
Jquery
You can use src attr() in onclick event
$("#target").attr("src","newUrlOfTheImg");
or with plain java script
document.getElementById("target").src="newUrlOfTheImg";
And have look once
document.getElementById("target").src="myNewImage.extension";
Pure javascript alternative that you can use on the onclick event.
$(document).ready(function() {
$('.zoom').on('click', function() {
$('.big_image').find('img').attr('src', $(this).find('img').attr('src'));
});
});
You should try this out, however it would be better to have separate thumbnail and big-images files for loading purposes.
With Fancybox 2 the example below works flawlessly (left out other code)
<a class="fancybox" href="https://si0.twimg.com/profile_images/2169856486/avatar.jpg" title="some title">
<img src="http://a0.twimg.com/profile_images/2169856486/avatar_normal.jpg" alt="" />
</a>
but the code below load the image on a separate page
<a class="fancybox" href="https://api.twitter.com/1/users/profile_image?screen_name=boris&size=original" title="some title">
<img src="http://a0.twimg.com/profile_images/2169856486/avatar_normal.jpg" alt="" />
</a>
The problem seem to be with the image URL the Twitter API supplies which returns a (301) redirect to the actual location of the full image. Is there any way i can get Fancybox to work with images that are supplied using a redirect and that the popup window still has the size of the served image.
Help would be appreciated.
Frank
Since the second code/link doesn't contain an image extension (jpg, gif, png), fancybox cannot determine what type of content is trying to open so you need to tell it.
Either do :
One: Add the type option to your custom script
$(".fancybox").fancybox({
type: "image"
});
Two : add the data-fancybox-type attribute to your link
<a class="fancybox" data-fancybox-type="image" href="https://api.twitter.com/1/users/profile_image?screen_name=boris&size=original" title="some title"><img src="http://a0.twimg.com/profile_images/2169856486/avatar_normal.jpg" alt="" /></a>