I have dynamically added div.In which i have text box.While adding dynamic div i can put a value to the current div but not the previously open divs. I want to ask how to add Value to the previously open text boxes of Div.
Thank You
here is a solution that refresh ALL. (I don't understand the "previously open text box" part of your question. Well I understand it, but it doesn't show in your code. I assume the "rhythm" column of your table is an input/textarea html element (since you use it's value).
Please note I'm not sure what the vitalset function is supposed to accomplish, or what "vitals_form_readings_1_rhythm" is.
function queryDb(statement)
{
dbQuery = new air.SQLStatement();
dbQuery.sqlConnection = db;
dbQuery.text = statement //"SELECT * FROM rhythm";
//alert(dbQuery.text);
try {
dbQuery.execute();
} catch (error) {
air.trace("Error retrieving notes from DB:", error);
air.trace(error.message);
return;
}
return (dbQuery.getResult());
}
function crhythm()
{
var statement = "SELECT * FROM rhythm";
return queryDb(statement)
}
function reading_speedcode()
{
if (!cvitals) {
var crhythms = crhythm();
var i=0;
$(crhythms).each( function () {
crhythm = this.crhythm;
var pr = 'card_' + i;
$('#rhythm1').append('<br/><td class="content_big" id="'+pr+'" name="'+pr+'">' + crhythm + ' </td>');
i++
});
}
});
$(document).ready( function () {
reading_speedcode();
$('#rhythm1 .content_big').live('click', function(event) {
$('#rhythm1').empty()
reading_speedcode();
});
});
now, there are several things about your code.
variable naming. (for god sake use meaningful names!)
reading full table when you need one row
where is cvitals declared or assigned?
string parsing. Jquery is good at working with set of elements, there should be no need to parse "pr" to recover the row number.
if a value is inserted in rhythm table (or deleted) before your click, the vitalset logic fails. you might want to use the table id instead.
make sure "#vitals_form_readings_1_rhythm" is unique, not retrieved from the table.
if you can answer my question from the top of this post(vitalset function, vitals_form_readings_1_rhythm, cvitals) I will try improve the code.
Related
Here is the situation.
I'm trying to remove an div class item based when the user clicks on a rating.
The problem I have is that every time I click on the item it goes away, however when I move the mouse the item that I removed comes back.
Here is my current code:
<div class="star_'.($iPos+1).' ratings_stars ratings_vote" onmouseover="overRating(this);" onmouseout="outRating(this);" onClick="selectEmailRating(this);" ></div>
The above item is the div that is calling the JavaScript. When I click on the rating I run the code that is in the following function below:
function selectEmailRating(elem) {
var star = elem;
var rating = widget.data('fsr').rating;
if($(star).attr('class') === 'star_'+ rating + ' ratings_stars ratings_over ratings_vote'){
$(elem).andSelf().removeClass();
$(star).attr('class', 'star_'+ rating + ' ratings_stars');
$(star).attr('class').unbind('onmouseover').unbind('onmouseout');
}
function outRating(elem) {
$(elem).prevAll().andSelf().removeClass('ratings_over');
setRating($(elem).parent());
}
function overRating(elem) {
$(elem).prevAll().andSelf().addClass('ratings_over');
$(elem).nextAll().removeClass('ratings_vote');
}
function setRating(widget) {
var votes = $(widget).data('fsr').rating;
$(widget).find('.star_' + votes).prevAll().andSelf().addClass('ratings_vote');
$(widget).find('.star_' + votes).nextAll().removeClass('ratings_vote');
}
As you see in the code, it is removing the item, however, it is coming back when I move the mouse. Is there a way to make sure when I click on the item to remove it stays removed?
I may be wrong here, but you didn't "bind" the onmouse* events to the element, you added attributes.
You may overwrite the onmouse* attributes with $(elemment).attr('onmouseout', '') or something alike.
and you might want to have a look at https://api.jquery.com/hasclass/
Well I found a solution..
After trying to figure out why the rating keeps coming back, it was the due to the fact that the outRating function was causing the problem. Here is what I did...
The old outRating function:
function outRating(elem) {
$(elem).prevAll().andSelf().removeClass('ratings_over');
setRating($(elem).parent());
}
The new outRating function:
function outRating(elem) {
var star = elem;
var widget = $(elem).parent();
var rating = widget.data('fsr').rating;
$(elem).prevAll().andSelf().removeClass('ratings_over');
if($(star).attr('class') !== 'star_'+ rating + ' ratings_stars') {
setRating($(elem).parent());
}
}
I use data table plugin with table as data source. I have to change some column value via javascript when the user types in some numbers into an input (this input is part of the table too and I have to export this values to). It is working well but when I want to export the table the columns witch was changed with javascript is not displayed in the exported file.
I think the problem is that I have not refreshed the datatable plugin. Is this correct? If yes how do I refresh the datasource? If no what can be the problem and how can I solve it?
I tried the refresh() method (var dataTableObject = $(this).parents('table').dataTable(); dataTableObject.refresh();) and the $(this).parents('table').dataTable() but is not working.
Edit: Here is how do I change the cell value:
$item.find('input.quantity-coefficient').each(function (i, d) {
$(d).off('change').on('change', function () {
var multiplier = $(this).val();
//var dataTableObject = $(this).parents('table').dataTable();
$($(this).data("row-price-info-class")).each(function (i, d) {
var priceContainer = $(d);
var price = parseFloat(priceContainer.data('price-value'));
var priceInfoRatioContainer = $(priceContainer.data("ratio-input-class"));
if (multiplier * price == 0) {
priceInfoRatioContainer.closest("td").addClass("no-euro");
priceInfoRatioContainer.html(" ");
} else {
priceInfoRatioContainer.closest("td").removeClass("no-euro");
priceInfoRatioContainer.html(localizeNumber(multiplier * price));
}
});
//TODO redrow the data
$(this).parents('table').dataTable().fnDraw();;
});
});
You can refresh the dataTable with fnDraw(). In your example:
$(this).parents('table').dataTable().fnDraw();
Thank you guys but I think I found the solution in this post: jquery DataTables - change value of a cell not just display value
When I tried it on the first time the problem was that I started the row numbering from 1 and not from 0.
So for the others who may have this issue to, I have to use something like this:
(this).parents('table').dataTable().fnUpdate("new value", 0, 2)
To update the cell value. Actually this is not what I asked because this is not refresh all the table, but this is a solution for me now.
I am making a website that displays profiles of people. Each person is designated a svg button and when that button is clicked, a pop up displays that persons information.
I have this jquery function:
$('.button1').click(function() {
$('.person1-profile').fadeIn();
});
$('.button1-exit').click(function() {
$('.person1-profile').fadeOut();
});
$('.button2').click(function() {
$('.person2-profile').fadeIn();
});
$('.button2-exit').click(function() {
$('.person2-profile').fadeOut();
});
$('.button3').click(function() {
$('.person3-profile').fadeIn();
});
$('.button3-exit').click(function() {
$('.person3-profile').fadeOut();
});
I'm wondering if it is possible to do this with Javascript so that it significantly shortens the coding, and rather than copy & pasting that code every time for each person, if variables can be made for people/profile and so it would be something like:
$('var person + button').click(function() {
$('var person + profile').fadeIn();
});
$('var button + exit').click(function() {
$('var person + profile').fadeOut();
});
Thank you I really appreciate it! Sorry if it is unclear.
You could use data-attributes for this one:
Define your buttons like that:
<button class="openButton" data-person="3">Open</button>
<button class="closeButton" data-person="3">Close</button>
And your open/close-code like that:
$('.openButton').click(function() {
var personNumber = $(this).attr("data-person");
$('.person'+personNumber+"-profile").fadeIn();
});
$('.closeButton').click(function() {
var personNumber = $(this).attr("data-person");
$('.person'+personNumber+"-profile").fadeOut();
});
In action: http://jsfiddle.net/ndx4fn9n/
I can think of few ways of doing it.
You could read only 7th character of the class name. This limits you to having only 10 fields. Or you could put id on very end like this person-profile1 and read 16th and up character.
You could also set up additional tag to your container. But this will cause your web page to not HTML validate.
<div class="person" personid="1">// content</div>
You can do this in your selector:
var buttons = document.getElementsByTagName(svgButtonSelector);
for (i = 0; i > buttons.length; i++) {
$(".button" + index).click(function() {
$(".person" + index + "-profile").fadeIn();
});
}
This will attach the event to every svg button you've got on your page. You just gotta make sure the scope of selection for the buttons is declared right (I'm using document as an example).
hey guys having trouble figuring out how to make it so that i can make it only open one table at once, once you open another the other should close any help here?
function showRow(cctab){
if (document.getElementById(cctab)) {
document.getElementById(cctab).style.display = '';
}
}
function hideRow(row1){
if (document.getElementById(cctab)) {
document.getElementById(cctab).style.display = 'none';
}
}
function toggleRow(cctab){
if (document.getElementById(cctab)) {
if (document.getElementById(cctab).style.display == 'none') {
showRow(cctab)
} else {
hideRow(cctab)
}
}
}
Now I want to make it so that only one table "cctab" opens after I suggest the onClick="javascript:toggleRow(cctab);" anyhelp?
Well you could save a reference to the previously shown item and hide it when another is shown:
var currentTab;
function showRow(cctab){
if (document.getElementById(cctab))
document.getElementById(cctab).style.display = '';
if (currentTab && currentTab != cctab)
hideRow(currentTab);
currentTab = cctab;
}
Note that doing inline event handler attributes is so 1999, but assuming you're sticking with it for whatever reason you don't need the javascript: in onClick="javascript:toggleRow(cctab);". (Just say onClick="toggleRow(cctab);")
First you need to store the old row somewhere.
What you've got is a system where you're using <element onclick="..."> to pass the id of the current element into the controller that shows or hides the row.
But if you look at that, what you're missing is a way of telling what the last open row was.
So what your code will need is a central object, or variables which store the old element and the new element.
How you do this is up to you, but if you did something like this:
var table_rows = { current : null /* or set a default */, previous : null };
function rowController (cctab) {
var newRow = document.getElementById(cctab);
if (newRow === table_rows.current) { toggleRow(newRow); }
else {
table_rows.previous = table_rows.current;
table_rows.current = newRow;
showRow(table_rows.current);
hideRow(table_rows.previous);
}
}
Note:
This deals with elements directly, so you don't have to do getById in your functions;
that's handled one time, and then that element is passed around and saved and checked against.
It assumes that the click is happening on the row itself, and not on anything inside of the row;
that's a separate issue that your code has.
Unless it's obvious and easy to click on the row, and not the cells inside of the row, it's difficult to tell how you want users to be able to open and close rows.
What I mean is if only the table-row has an onclick, and somebody clicks on a table-column, then then onclick isn't going to fire.
I have child divs that I'm trying to sort based on a jquery .data() value that I give them that is just a single number. This code works perfectly, but only once, after that I can't figure out how the heck it's sorting them. Here is a simplified version:
var myArray = $('#container div').get();
myArray.sort(function(x,y) {
return $(x).data('order') - $(y).data('order');
});
$('#container').empty().append(myArray);
I've tried so many other different methods of sorting, other plugins, etc., and I can't get anything to work right. This is as close as I can get. I just have this running on a jquery change event.
Here is the whole thing in case I'm doing something stupid elsewhere:
$('#attorneyFilter').change(function() {
//get array of links for sorting
var myArray = $('#attorneyBlocks div').get();
var selectedArea = $(this).val();
//sort alphabetically when "all" is selected
if (selectedArea == 'all') {
$('#attorneyBlocks div').show();
myArray.sort(function(a,b) {
return $(a).text() > $(b).text() ? 1 : -1;
});
//filter attorneys based on practice area and then assign its order# to the div with data, getting all values from the div's class
} else {
$('#attorneyBlocks div').hide().each(function() {
var attorneyArea = $(this).attr('class').split(', ');
for (var i=0;i<attorneyArea.length;i++) {
var practiceArea = attorneyArea[i].split('-');
if (selectedArea == practiceArea[0]) {
$(this).show().data('order',practiceArea[1]);
}
}
});
//sort based on order, the lower the number the higher it shows up
myArray.sort(function(x,y) {
return $(x).data('order') - $(y).data('order');
});
}
//append order back in
$('#attorneyBlocks').empty().append(myArray);
});
And a link to the page in question
Here's a jsFiddle with this working using .detach() instead of .empty() to keep the data.
http://jsfiddle.net/shaneblake/Tn9u8/
Thanks for the link to the site, that made it clear.
It seems to me you never clear out the data from the prior time. You hide everything but maybe something like this will solve your problem (here I set everything hidden to the bottom, you can clear it or use a different value -- as long as it is not the same as any sort key):
$('#attorneyBlocks div').hide().data('order',999999).each(function() {
var attorneyArea = $(this).attr('class').split(', ');
for (var i=0;i<attorneyArea.length;i++) {
var practiceArea = attorneyArea[i].split('-');
if (selectedArea == practiceArea[0]) {
$(this).show().data('order',practiceArea[1]);
}
}
});
Also, the code on the server is missing the 2nd line you have above:
var myArray = $('#attorneyBlocks div').get();
The problem is the change event is tied to the original items. After the sort you make all new items. They don't have any event tied to them. You will need to use .live()
Eventually figured it out, the data values from hidden divs were screwing with my sorting, so I changed my sorting code to only pay attention to :visible divs and that did the trick. Doh! Thanks for your help everyone.