We Keep Coding

Cannot get $_POST('input') using jQuery .submit()

I was trying to upload a form using jQuery's submit() and success in redirect the page to uploadAll.php, but when I was trying to get the input array using $_POST['inputname'] I can not obtain the value.
I was trying to use serialize() but I get confused in where I should put my PHP page reference.
<form id="regForm" action="uploadAll.php" method="post" enctype="multipart/form-data">
//some inputs and a hidden input here
</form>
document.getElementById("regForm").submit(function() {
var inputValues = $(this).serialize();
$.ajax({
url: "uploadAll.php",
type: "POST",
data: inputValues
}).done(function(data) {
alert(data);
});
});
return false;
Can I just submit without using serialize()? It seems my serialize does not work. Any help is appreciated

trust me, your code is wrong..
try use this code instead:
$("#regForm").on('submit', function(e) {
e.preventDefault();
var inputValues = $(this).serialize();
$.ajax({
url: "uploadAll.php",
type: "POST",
data: inputValues
}).done(function(data) {
alert(data);
});
});

LARAVEL: Use a javascript variable in php

I would like to get an id from a button. I need this id in my ajax request. This is my button:
<form>
<div class="form-group">
<button class="btn btn-primary" name="deletecar" id="{{$car->id}}">Delete</button>
</div>
</form>
I'm getting the id of the button this way:
<script type="text/javascript">var JcarID = this.id;</script>
Finally my Ajax Request.
$('[name="deletecar"]').click(function (e)
{
var JcarId = this.id;
e.preventDefault();
$.ajax({
type: "POST",
url: '{{ action('CarController#delete', [$user->id, $car->id])}}',
success: function (data)
{
// alert(data);
}
});
});
Thx for reading!
SOLUTION
Changed some bits in my code. I changed the url of my request.
$('[name="deletecar"]').click(function (e)
{
e.preventDefault();
$.ajax({
type: "POST",
url: '/users/{{$user->id}}/deletecar/'+this.id,
success: function (data)
{
// alert(data);
}
});
});

Hard to guess what is your requirement yet either if you want to get the button id value
this.attr('id'); or this.prop('id');
Or if you want to set the id value of button
$('[name="deletecar"]').attr('id', yourvalue)

I think you want to use JcarId rather $car->id in ajax request. Here what you can do rather than directly using PHP code in ajax call.
$('[name="deletecar"]').click(function (e)
{
var JcarId = this.id;
e.preventDefault();
$.ajax({
type: "POST",
url: '/CarController/delete',
data: {'carId':JcarId}
success: function (data)
{
// alert(data);
}
});
});

PHP Serialize on ajax array Not Working

I have the following HTML fields being created inside a PHP look
<td><input type=\"checkbox\" name=\"investigator_id[]\" id=\"investigator_id\" value=\"$name_degree[$i]\">
<td><input type=text name=\"inv_rank[]\" id=inv_rank maxlength=\"2\" size=\"2\"></td>
<td><textarea name=\"inv_comm[]\" id=inv_comm rows=2 cols=20></textarea></td>
I am trying to save the data in these fields by calling a jquery function based on clicking on this button
Here is the script that is being called. I know that the js is being called because the "alert("now")" is poping up, but the dataString is not being populated correctly. I tested this on http://jsfiddle.net/ and it worked fine, but won't work on my site.
<script>
$(document).ready(function() {
$("#submit").click(function() {
alert("now");
var dataString = $("'[name=\"investigator_id\[\]\"]', '[name=\"inv_rank\[\]\"]','[name=\"inv_comm\[\]\"]'").serialize();
alert("ee"+dataString);
$.ajax({
type: "POST",
url: "save_data.php",
dataType: "json",
data: dataString,
success: function(data){
alert("sure"+data);
$("#myResponse").html(data);
},
error : function(XMLHttpRequest, textStatus, errorThrown) {
alert("There was an error.");
}
});
});
});
</script>

Try this with the help of FormID like this:
<form method="post" id="yourFromID">
//Your form fields.
</form>
JS Code:
$("#yourFromID").submit(function (e){
e.preventDefault();
var dataString = $(this).serialize();
// then you can do ajax call, like this
$.ajax({
url: 'site.com',
data: dataString,
methodL 'post',
success: function(){...}
})
return false;
});

How to send multiple variables through ajax?

The code below sends the id of item to more.php to load more content. It works fine. Now to add some more features I need to send one more id to more.php through the same code.
<script type="text/javascript">
$(document).ready(function(){
$(document).on('click','.show_more',function(){
var ID = $(this).attr('id');
$('.show_more').hide();
$('.loding').show();
$.ajax({
type:'POST',
url:'more.php',
data:'id='+ID,
success:function(html){
$('#show_more_main'+ID).remove();
$('.display').append(html);
}
});
});
});
</script>
Suppose second id is var catid = '<?php echo $cat ?>'; how to send this catid through the same ajax code. data : {id : id, catid : catid} is something I should do but can't get how to deal in current situation when my data carries data:'id='+ID,.

your should look like. specify your data as an object:
<script type="text/javascript">
$(document).ready(function () {
$(document).on('click', '.show_more', function () {
var ID = $(this).attr('id');
$('.show_more').hide();
$('.loding').show();
$.ajax({
type: 'POST',
url: 'more.php',
data: { id:ID, userid: userid },
success: function (html) {
$('#show_more_main' + ID).remove();
$('.display').append(html);
}
});
});
});

To retrieve multiple input's I suggest combining them in a Form:
first embed your inputs in an form with a submit button, you should also not use the same name twice because it won't work now, create unique names
<form action="GET" id="myForm">
<input id="string" type="text" name="string" />
<input id="string2" type="text" name="string" />
<input type="submit" value="Go" />
</form>
and write code to submit the ajax way
$('#myForm').submit(function(event) {
// Stop form from submitting normally
event.preventDefault();
var $form = $(this);
$.ajax({
type: "GET",
url: "retrieve.php",
data: $form.serialize(), //make it JSON
success: function() {
console.log("it worked");
}
});
});

Using JQuery and AJAX to pass data to a PHP script

I have an HTML form that Is only composed of a button with a value. I would like to leave it this way. I am using AJAX/JQuery to pass the form data to a PHP script. But, for some reason, the button value is not sent. What could I be doing wrong?
HTML:
<form id="friend-send" method="post" action="">
<button type="submit" class="foll" name="approve-friend" value="4"> Approve </button>
</form>
AJAX/JQUERY:
$(document).ready(function() {
$("#friend-send").submit(function(e) {
var $this = $(this);
var dataString = $this.serialize();
e.preventDefault();
$.ajax({
type: "POST",
url: "relate.php",
data: dataString,
async: false,
success: function() {
$this.hide();
}
});
});
});

JQuery won't serialize a button, use a hidden field instead
<form id="friend-send" method="post" action="">
<input type="hidden" name="approve-friend" value="4" />
<button type="submit" class="foll"> Approve </button>
</form>
Also, You need to serialze the form by id, not the button by id
Instead of this
$("#friend-request-buttons")
It should be this
$("#friend-send")
Lastly, since you are using ajax to post, you can simplfy your form open tag to this...
<form id="friend-send">

<button>
tags are not supported by serialize https://api.jquery.com/serialize/
You would need to use an input of some kind. A hidden one would work.

Don't use serialize, create the input data yourself:
var dataString = {};
var $button = $this.find("[type=submit]");
dataString[$button.attr('name')] = $button.val();
When you provide an object as the data: argument to $.ajax, jQuery will serialize it automatically.

This answer would be if you are set on using the button alone
$(document).ready(function() {
$("#friend-send").submit(function(e) {
var $this = $(this);
var dataString = "?" + $(this).find('button').attr('name') + "=" + $(this).find('button').attr('value');
e.preventDefault();
$.ajax({
type: "POST",
url: "relate.php",
data: dataString,
async: false,
success: function() {
$this.hide();
}
});
});
});