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Why Doesn't Modal FadeOut Slowly?

I inherited this modal/overlay/content close/empty method that works, but abruptly:
method.close = function () {
$modal.hide();
$overlay.hide();
$content.empty();
$(window).unbind('resize.modal');
};
To fade out gradually, I modified the method like below, but elements are left behind and subsequent clicks don't open new modals loaded with content, only the overlay:
method.close = function () {
$modal.fadeOut('slow', function() {
$(this).hide();
});
$overlay.fadeOut('slow', function() {
$(this).hide();
});
$content.fadeOut('slow', function() {
$(this).empty();
});
$(window).unbind('resize.modal');
};
What am I missing?
UPDATE: The solution is a single nested callback, based on garryp's answer, like this:
method.close = function() {
$overlay.fadeOut('slow', function() {
$overlay.hide();
$content.empty();
});
$modal.hide();
$(window).unbind('resize.modal');
};

Hide is asynchronous; the calls you have in your original code do not block while the transition occurs, execution moves immediately to the next. You need to use callbacks, like this:
var me = $(this); //Added to ensure correct this context
$modal.fadeOut('slow', function () {
me.hide(function () {
$overlay.fadeOut('slow', function () {
me.hide(function () {
$content.fadeOut('slow', function () {
me.empty();
});
});
});
});
});
Assuming the rest of your code is correct this should ensure the transitions fire one after the next.

Firstly, you do not need $(this).hide(). JQuery fadeOut automatically set display: none at the end of fading animation (read more: http://api.jquery.com/fadeout/).
That mean, in your case $content element will also have display: none after fadeOut animation. I expect you forgot to add $content.show() in modal open method.

Jquery mouseover / mouseleave

I'm not sure what to search for exactly but here is my issue.
<script>
function Gbox () {
var hide = document.getElementById('g-box').style.display = "none";
}
Gbox();
$("#g-plus").mouseover(function () {
$("#g-box").show(400);
});
$("#g-plus").mouseleave(function () {
$("#g-box").hide(400);
});
</script>
Said Jquery works without a problem.
Only issue is that if i hover in and out fast 2 times on #g-plus the Jquery runs it 4 times as in show,hide,show,hide and it looks retarded when it happens
How can i avoid this issue?

$("#g-plus").hover(function () {
$("#g-box").show(400);
},function () {
$("#g-box").hide(400);
});

What you need is .stop() to stop the previous animation
function Gbox() {
$("#g-box").hide();
}
Gbox();
$("#g-plus").hover(function () {
$("#g-box").stop().show(400);
}, function () {
$("#g-box").stop().hide(400);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<button id="g-plus">g-plus</button>
<div id="g-box">g-box</div>
Note: You can use .hover() as a short cut to register the mouseenter and mouseleave handlers

jQuery hide and show text input

I want to do a simple function in Jquery: when a button is clicked show the input text, when it's clicked again- hide the input text.
<div>
<div id="btnNewGroup">New Group</div>
<input type="text" id="newGroup" style="display:none" />
</div>
and this is the scrupt section:
$(document).ready(function () {
$("#btnNewGroup").click(function () {
if ($("#newGroup").hide()) {
$("#newGroup").show();
}
else {
$("#newGroup").hide()
}
});
});
when I click the button the text input is showing, when I click it again I want the input text to be hidden, but nothing happens.

You can use toggle() to show / hide
Live Demo
$("#btnNewGroup").click(function () {
$("#newGroup").toggle();
});
The problem with the condition you have is that you are hiding the element instead of checking if it is hidden. You can is with :hidden like is(':hidden') to check if element is hidden.
if ($("#newGroup").is(':hidden')) {
$("#newGroup").show();
else
$("#newGroup").hide();

if ($("#newGroup").hide())
The hide function does not return a boolean value so you can't use it in an if statement. It returns a jQuery object which is always true so your second block never gets hit.
You can try two things:
$(document).ready(function () {
$("#btnNewGroup").click(function () {
if ($("#newGroup").is(":visible")) {
$("#newGroup").hide();
}
else {
$("#newGroup").show()
}
});
});
Or a simple toggle:
$(document).ready(function () {
$("#btnNewGroup").click(function () {
$("#newGroup").toggle();
});
});
Additionally, when working with selectors multiple times it's a good idea to cache the element - otherwise jQuery tries to find the element each time you try:
$(document).ready(function () {
$("#btnNewGroup").click(function () {
var $newGroup = $("#newGroup"); // Cache it here
if ($newGroup.is(":visible")) {
$newGroup.hide();
}
else {
$newGroup.show()
}
});
});

use .toggle() for hide and show alternatively in jquery
$("#btnNewGroup").click(function () {
$("#newGroup").toggle();
});

Demo
Use .toggle() function
$("#btnNewGroup").click(function () {
$("#newGroup").toggle()
});
Or use :visible pseudo selector with is()
Demo
$(document).ready(function () {
$("#btnNewGroup").click(function () {
if ($("#newGroup").is(":visible")) {
$("#newGroup").hide();
}
else {
$("#newGroup").show()
}
});
});
Note :hide() function does not return boolean value. Use is(:visible) or is(:hidden)

You need to change
if ($("#newGroup").hide()) {
to (just one possible solution)
if ($("#newGroup").css('display')=='none') {
Because $("#newGroup").hide() will always return true.
And here are the full code:
$(document).ready(function () {
$("#btnNewGroup").click(function () {
if ($("#newGroup").css('display')=='none') {
$("#newGroup").show();
}
else {
$("#newGroup").hide()
}
});
});

Have a look at the .toggle() function within the API.
http://api.jquery.com/toggle/

document.getElementById("username").style.display='block';

fade in fade out with two divs does not work

I have the following code http://jsfiddle.net/largan/2n2Lf/25/
The idea is the div called soc_text to fade and fade out when hover on the soc_button div.
I have this script, but it doesn't seems to work.
$(document).ready(function()
{
$("div.soc_button").hover(
function () {
$("div.soc_text").fadeIn('slow');
},
function () {
$("div.soc_text").fadeOut('slow');
}
);
});
Any ideas?
Thanks

$(document).on("mouseover", "div.soc_button", function(){
$(this).find("div.soc_text").fadeToggle("slow");
});

Here's the answer:
$(document).ready(function () {
$("div.soc_button img").hover(
function () {
console.log();
$(this).parent().find('div.soc_text').fadeIn('slow');
},
function () {
$(this).parent().find('div.soc_text').fadeOut('slow');
}
);
});
I guess the code is self explanatory,
Regards

This applies the method to all matches with all div tags with soc_text css class
$("div.soc_text").fadeIn('slow');
Change this to
$(this).children('div.soc_text').fadeIn('slow');

mouseover doesn't show hidden div

<script>
$("#menu-item-58").mouseover(function() { $("#simple_sidenav-3").css('visibility','visible'); });
$("#menu-item-58").mouseout(function() { $("#simple_sidenav-3").css('visibility','hidden'); });
</script>
#simple_sidenav-3 {
visibility:hidden;
}
simple_sidenav-3 is a hidden div.
So why doesn't it show when mouse is over #menu-item-58?
Please check it here http://mentor.com.tr/wp/?page_id=164

try this instead:
jQuery("#menu-item-58").mouseover(function() {
jQuery("#simple_sidenav-3").css('visibility','visible');
});
$ is undefined.

You haven't wrapped your code in the jQuery DOM ready function. Put this between your <script> tags:
$(document).ready(function()
{
$("#menu-item-58").mouseover(function() { $("#simple_sidenav-3").css('visibility','visible'); });
$("#menu-item-58").mouseout(function() { $("#simple_sidenav-3").css('visibility','hidden'); });
}
This will bind the mouse events to the elements when the document (page) has been loaded.

Try changing #simple_sidenav-3 from visibility:hidden; to display:none; Then call something like .slideDown() for a nice effect.
Also, here's some improvements to your code:
jQuery(function() { //waits till the document is ready
jQuery("#menu-item-58").mouseover(function () {
jQuery("#simple_sidenav-3").slideDown();
}).mouseout(function () { //no need to use $("#menu-item-58") twice
jQuery("#simple_sidenav-3").slideUp();
});
});