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ASP.NET Core view model when disabling form fields with jQuery.validate

I have an HTML form, and I would like it so that when the user clicks the submit button, the button and all input elements (textboxes mainly) in the form are disabled, to prevent them from changing any data, or clicking the button a second time. I'm using jQuery.validate on the form without the unobtrusive plug-in.
The markup for the form looks like this (irrelevant markup removed for clarity)...
<form method="post" asp-controller="Home" asp-action="Jim">
<div class="form-group row">
<label for="Name">Your name</label>
<input type="text" id="UserName" name="UserName">
</div>
<div class="form-group row">
<label for="Email">Email</label>
<input type="text" id="Email" name="Email">
</div>
<div class="form-group row">
<div>
<button type="submit">Submit</button>
</div>
</div>
</form>
I have the following JavaScript that uses jQuery.validate...
$("form").validate({
rules: {
UserName: {
required: true,
minlength: 3
},
Email: {
required: true
},
Message: {
required: true
}
},
submitHandler: function(form) {
form.submit();
}
});
That's all the JavaScript on the page.
This works fine. However, if I add one line into the submitHandler function...
submitHandler: function(form) {
$("form input").prop('disabled', true);
form.submit();
}
...then when the form is submitted, Request.Form is empty, so none of my data is sent to the server.
It seems to be related to jQuery.validate, as if I completely replace the JavaScript with this...
$(function() {
$("form").submit(function(form) {
$("form input").prop('disabled', true);
});
});
...then the controls are disabled and my data comes through fine. This seem to imply I'm doing something wrong with jQuery.validate.
Anyone able to explain why my data doesn't come through when I disable the controls when using jQuery.validate?

The reason is that disabled inputs are not submitted with the form.Refer to here and here.
You should use the readonly attribute rather than disabled. Read-only fields cannot be edited by the user, but are still submitted with the form.
submitHandler: function (form) {
$("form input").prop('readonly', true);
form.submit();
}

Submit Form With Both Action and Onsubmit Function

My JS is not that great so I have been fiddling with this for a while now.
I have a form which is being POST to another file when the submit button is clicked. When it is clicked I also want to show an alert then redirect the user back to a URL.
The redirecting code works just fine on a button where I call the function "onclick" like so:
<button onclick="test()">Return</button>
But I don't want to have an extra button for this...I want the form to POST then show an alert box then go to URL specified but I get not a function error from console, thanks.
<iframe name="noreloadhack" style="display:none;"></iframe>
<form action="http://www.example.com/test.php" onsubmit="return test();" method="post" target="noreloadhack">
JS:
<script>
function test() {
alert('Hello World');
var return_url = document.getElementById('return_url').value;
window.location.href= return_url;
}
</script>
If it makes a difference I have the form target set to a hidden iframe as a hack to not reload page on submit (I know, not the best method). I'm pretty much using 4 form attributes here.

I have some old code that I used to solve a similar situation. Where I wanted to submit a form but not reload the page, here it is. Since there were only 4 input fields I just grabbed the values using jquery.
Javascript:
function processForm() {
var teamMembers=new Array();
console.log($("#"));
var schoolName=$("#schoolname").val();
var teamMembers=new Array();
teamMembers.push($("#contestant1").val());
teamMembers.push($("#contestant2").val());
teamMembers.push($("#contestant3").val());
$.ajax({
method: "POST",
url: "php/register.php",
data: { schoolname: schoolName, teammembers:teamMembers.toString()}
})
.done(function( msg ) {
alert( "Your team is now registered " + msg );
$('#register').hide();
location.reload();
});
// You must return false to prevent the default form behavior
// default being reloading the page
return false;
}
HTML:
<form id="registration_form" onsubmit="return processForm()" method="POST">
<p style="margin:0px;">School Name:</p>
<input type="text" id="schoolname" name="schoolname" autocomplete="off" class="input" required>
<hr>
<p style="margin:0px;">Contestants</p>
<div id="teammembers">
<input type="text" id="contestant1" name="contestant1" autocomplete="off" class="input" required>
<p></p>
<input type="text" id="contestant2" name="contestant2" autocomplete="off" class="input" required>
<p></p>
<input type="text" id="contestant3" name="contestant3" autocomplete="off" class="input" required>
</div>
<input type="submit" id="registered">

jQuery .submit() method sends undefined instead of written content after AJAX call

I'm adding some content through form to the database and then reload this part of page to update the content. And then I want to add the next content and again reload but the .submit method I use, sends undefined instead of the written content. Here's the HTML code:
<form id="addForm" method="post" action="/addContent">
<input type="text" id="content" name="name" value="" placeholder="New content" required/><br/><br/>
<input name="submitted" id="submitted" value="Add content" class="submit" type="submit" />
</form>
And here's JS:
<script>
$('#addForm').submit(function() {
$.post('/addContent', {
data: $('#addForm').serializeArray(),
}, function(response) {
$('#contentPart').html(response);
});
return false;
});
</script>
Can anyone help me? I'll be gratefull.

You need to assign your event on any addForm form that may appear in DOM in the future:
$(document).on('submit', '#addForm', function() {
...
});

Single click event acts as double click event

I'm using Ajax to submit the login form without refreshing the page. I've added a function to see whether the data returns 'error' (which comes up when the user enters an incorrect email/password). If it does not return 'error', the user has been logged in and will be transferred to the page within 2 seconds.
The problem is that my button acts like a double-click button and I cannot see why. This is my JS file:
$(function() {
$("#goLogin").click(function() {
$.ajax({
type: "POST",
url: "db-requests/db-login.php",
data: $("#loginForm").serialize(),
success: function(data,textStatus,jqXHR){ finishLogin(data,textStatus,jqXHR); }
});
});
});
function finishLogin( data , textStatus ,jqXHR ) {
if ( data == "error" ) {
$('.errorMsg').fadeIn(500).hide();
$('.succesMsg').fadeOut(300).hide();
} else {
$('.succesMsg').fadeIn(500).show();
$('.errorMsg').fadeOut(300).hide();
setTimeout("location.href = 'protected.php';",2000);
}
}
I've tried placing it between the document_ready tags, but that isn't working either.
Part of the HTML code:
<div class="login form">
<div class="login-header">Please Login</div>
<form method="post" id="loginForm" name="form">
<label for="email" class="short">Email*</label>
<input type="text" name="email" id="email" class="required" placeholder="" />
<label for="password" class="short">Password *</label>
<input type="password" name="password" id="password" class="required" placeholder="" maxlength="15" />
</form>
<div id="login-functions">
<div class="loginbtn-container">
<input type="submit" id="goLogin" name="goLogin" class="button green" value="Login" />
</div>
<div class="login form actions">
<p class="register account">Register an account</p>
<p class="request password">Lost your password?</p>
</div>
</div>
</div>
<div class="errorMsg">Incorrect. Please recheck your details</div>
<div class="succesMsg"><b>You've been logged in!</b> Please wait while we transfer you</div>

$('.errorMsg').fadeIn(500).hide();
$('.succesMsg').fadeOut(300).hide();
did you mean tto hide both? I see the click is working fine, though you should ideally do submit
Take your submit inside the form, and prevent normal form submit using preventDefault()
$("#goLogin").submit(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "db-requests/db-login.php",
data: $("#loginForm").serialize(),
success: function(data,textStatus,jqXHR){ finishLogin(data,textStatus,jqXHR); }
});
});

Please move your submit button inside the form closing tag first
<input type="submit" id="goLogin" name="goLogin" class="button green" value="Inloggen" />
The above button is placed after the </form> tag.

Because you click on input type submit and progress Ajax on it; it cause submit 2 times.
To avoid it, you can use as Zach Leighton said above ; or use as below
$("#goLogin").click(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "db-requests/db-login.php",
data: $("#loginForm").serialize(),
success: function(data,textStatus,jqXHR){ finishLogin(data,textStatus,jqXHR); }
});
});

html form submiting more fields than expected

I'm dealing with a awful issue, I developed a form with multi fields set (using normal div)
and when I test the submit action I got in the URL the one input not filled, also hidden in
the markup as showed bellow.
http://127.0.0.1:8000/exform.html?user=test&pwd=QWERT1234&user_reg=
And here is the code for the form:
<form id="exform">
<div class="fields" id="login">
<div class="txt">
<label for="user"></label>
<input id="user" type="text" name="user"/>
</div>
<div class="txt">
<label for="pwd"</label>
<input id="pwd" type="password" name="pwd" />
</div>
<input type="submit" value="test" id="test"/>
</div>
<div class="fields" id="register">
<div class="txt">
<label for="user_reg"></label>
<input id="user_reg" name="user_reg" type="text"/>
</div>
<div class="txt">
<label for="pwd2"></label>
<input id="pwd2" type="password" />
</div>
<div class="txt">
<label for="pwdc"></label>
<input id="pwdc" type="password"/>
</div>
<div class="buttons">
<input type="submit" value="OK" id="ok"/>
</div>
</div>
</form>
The strange is that the second field set isn't available in the screen, because in the css
there is a rule to only show the first group with the class "fields"
/*Hide all except first div with class div*/
#exform .fields:not(:first-of-type) {
display: none;
}
So I really want to know why the form is submitting fields out of the scope.
For example, if the second group fieldset is used, when the button submit with value OK is clicked the result produced is similar. In the URL, only the user_reg field parameter is showed filled with the two another fields for the first group without values:
http://127.0.0.1:8000/exform.html?user=&pwd=&user_reg=test
The following code is for submit test:
$(function() {
$('#test').click(function() {
$('#exform').submit(function(event) {
console.log("form Submited:" + document.forms['exform'] + "test");
});
});
$('#ok').click(function() {
$('#exform').submit(function(event) {
console.log("form Submited:" + document.forms['exform'] + "ok");
});
});
});
Doesn't matter I'm got the same URL results
This
http://127.0.0.1:8000/exform.html?user=test&pwd=QWERT1234&user_reg=
or
http://127.0.0.1:8000/exform.html?user=&pwd=&user_reg=test
Instead I'm receiving:
// on #test click
http://127.0.0.1:8000/exform.html?user=test&pwd=QWERT1234
// on #ok click
http://127.0.0.1:8000/exform.html?user_reg=test&pwd2=QWERT1234&pwdc=QWERT123
I can't retrieve the values for pwd2 and pwdc fields in the URL as parameters obtained after submitting.
This got me crazy.

If you do not specify the method method of the form, the default is GET while submitting it. This is the reason to see all form elements in your URL.
Try this:
<form id="exform" method="post">
<!-- form contents -->
See here for details.

When you submit form you submit all it's input fields at ones.
Even if you hide something with css it still exists in html.
When you processed the form you can add a hidden field "input type="hidden"" and give that field a value that tells your script witch fields you want processed in witch case.
And i also fink that post method is better (more secure) especially if you send password.