I need a regular expression which needs to satisfy the following :-
It should accepts alphanumeric
only one space OR hyphen Or both can be there. But in any case it should be only one space or one hyphen
Max Total length should be 10 characters
For example valid data
W1A 1HQ
1234-456
IT-12345
12345
So far I have tried with below expression but it is not working properly
(^[a-zA-Z0-9][^\s\-].*[^\s\-][a-zA-Z0-9]){0,8}
Do I need to modify anything here ?
Edit
The solution posted here doesn't accept the combination of one space and one hypen within String.
Please provide an expression that will support all the requirement together in combinations.
You can use regex /^(?=.{0,10}$)[a-z0-9]+(?:[\s-][a-z0-9]+)?$/i
DEMO :
$('#input').on('input', function() {
$('#res').text(this.value.match(/^(?=.{0,10}$)[a-z0-9]+(?:[\s-][a-z0-9]+)?$/i) ? 'Valid' : 'Not Valid')
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<input id="input">
<div id="res"></div>
Explanation here
^(?=.{0,10}$)[a-z0-9]+(?:[\s-][a-z0-9]+)?$
UPDATE :
only one space OR hyphen Or both can be there
/^(?=.{0,10}$)[a-z0-9]+(?:([\s-])[a-z0-9]*(?:(?!\1)[\s-])?[a-z0-9]+)?$/i
$('#input').on('input', function() {
$('#res').text(this.value.match(/^(?=.{0,10}$)[a-z0-9]+(?:([\s-])[a-z0-9]*(?:(?!\1)[\s-])?[a-z0-9]+)?$/i) ? 'Valid' : 'Not Valid')
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<input id="input">
<div id="res"></div>
^(?=.{0,10}$)[a-z0-9]+(?:([\s-])[a-z0-9]*(?:(?!\1)[\s-])?[a-z0-9]+)?$
This expression also validates:
only one space OR hyphen Or both can be there
and allows hyphens/spaces at the beggining or end of the string.
Regex
/^(?!(?:[^-]*-){2}|(?:[^ ]* ){2})[- a-z0-9]{0,10}$/i
regex101 demo
It matches:
^ Start of string
(?!(?:[^-]*-){2}|(?:[^ ]* ){2}) Not followed by: (negative lookahead)
(?:[^-]*-){2}) 2 hyphens, or
(?:[^ ]* ){2} 2 spaces
[- a-z0-9]{0,10} alphanumerics, hyphens or spaces, with max length of 10
$ End of string
Mode /i: case insensitive match
Code
str = "-ABC 123";
re = /^(?!(?:[^-]*-){2}|(?:[^ ]* ){2})[- a-z0-9]{0,10}$/i;
if (str.match(re)) {
document.body.innerText += "VALID";
} else {
document.body.innerText += "Invalid string";
}
// Parameter: String which has to be checked with a
// regular Expression.
function checkString(toCheck) {
if (toCheck.length <= 10) {
var reg = /^[a-zA-Z0-9]+(\s|-|\s-|-\s)?[a-zA-Z0-9]+$/;
if (reg.test(toCheck)) {
return true;
}
}
return false;
}
Complete example on codepen:
http://codepen.io/mizech/pen/EVMRJG
Try this one:
^(?=.{1,10}$)([a-zA-Z0-9]+\s{0,1}[a-zA-Z0-9]*\-{0,1}[a-zA-Z0-9]+)$
Detailed explanation is available here: https://regex101.com/r/hV3rJ2/1
My account must have number and letters.And its length range 4 and 8.
It's not only number and it's not only letters.
Right ex: a111 ,1a1bb, aa111a, 111aaa. Error ex: abcdef, 12345, a123!.
How can I write the Regular Expression.
I tried write that:([a-z]+[0-9]+[a-z]*){4,10}|([0-9]+[a-z]+[0-9]*){4,10}.
But it's not match. Where is my error?
Try this: update ^((?=.*\d)(?=.*[a-zA-Z])[a-zA-Z0-9]{4,20})$
Here
^(
(?=.*\d) // must contains one digit from 0-9
(?=.*[a-zA-Z]) //must contains one lowercase Uppercase characters
[a-zA-Z0-9] //match any letter or number previous condition checking
{4,20} //length at least 4 characters and maximum of 20
)$
Live demo
Try this:
/^(?=.[a-z]+[0-9]|[0-9]+[a-z].)[a-zA-Z\d*]{4,8}$/
var filter = /^(?=.*[a-z]+[0-9]|[0-9]+[a-z].*)[a-zA-Z\d*]{4,8}$/;
var vals = "11aa11";
if (filter.test(vals)){
alert('working');
}else {
alert('not working');
}
Try this
var patt = new RegExp("(([A-Za-z][0-9]) |([0-9][A-Za-z])) ([A-Za-z]*[0-9]*){2,6}");
var res = patt.exec(test_str);
I have a function which validates the phone number entered by the user using regexp. However it does not seem to evaluate true even though the regexp is correct. I am not sure what i am doing incorrectly.
Html
<body class="claro">
<form id="myform" data-dojo-type="dijit/form/Form">
<input
data-dojo-type="dijit/form/ValidationTextBox"
data-dojo-props="
required: true,
invalidMessage: 'Invalid Phone Number !',
missingMessage: 'Phone Number Required !'"
id="phone" title="Phone Number"
placeholder="Your Phone Number"
onkeydown="validatePhoneNumberFormat()"/>
</form>
</body>
Javascript
//test phone number 188-123-1234
function validatePhoneNumberFormat(){
var phoneNumber = dijit.byId("phone");
var phoneFormat = new RegExp('^[0-9]\d{2}-\d{3}-\d{4}$');
phoneNumber.validator = function(value){
console.log(value);
console.log(phoneFormat.test(value.trim()));
return phoneFormat.test(value.trim());
}
}
You need to double escape \d inside RegExp constructor, so use this:
var phoneFormat = new RegExp('^\\d{3}-\\d{3}-\\d{4}$');
Or else use regex literal:
var phoneFormat = /^\d{3}-\d{3}-\d{4}$/;
Since RegExp takes a string as an argument you need to double escape all the special meta characters as one escape is used for String and second is for regex engine.
This will work:
function validatePhoneNumberFormat(){
var phoneNumber = dijit.byId("phone");
var phoneFormat = /^\d{3}-\d{3}-\d{4}$/;
phoneNumber.validator = function(value){
console.log(value);
console.log(phoneFormat.test(value.trim()));
return phoneFormat.test(value.trim());
}
}
REGEX EXPLANATION
/^\d{3}-\d{3}-\d{4}$/
Assert position at the beginning of the string «^»
Match a single character that is a “digit” (ASCII 0–9 only) «\d{3}»
Exactly 3 times «{3}»
Match the character “-” literally «-»
Match a single character that is a “digit” (ASCII 0–9 only) «\d{3}»
Exactly 3 times «{3}»
Match the character “-” literally «-»
Match a single character that is a “digit” (ASCII 0–9 only) «\d{4}»
Exactly 4 times «{4}»
Assert position at the very end of the string «$»
Trying to get the correct regex for this - only letters, spaces, hypens, and commas. So far this only works if you only input 1 charactor. Any more then that, and it returns false. Anyone able to help?
$('#submit').click(function () {
var locationtest = /[^a-zA-Z \-\.\,]/;
if (!locationtest.test($('#location').val())) {
alert('Nope, try again!');
$('#location').val('')
return false;
} else {
alert('You got it!');
}
});`
This should do it, it matches 1 or more characters within the set you described
/^[a-zA-Z \-\,]+$/
I took out the \., your description says letters, spaces, hyphens, commas
You're close, you just need to specify how many times you want the character to appear.
The following code would specify 0 or more times
var locationtest = /[^a-zA-Z -.\,]*/;
And this code would specify 1 or more times
var locationtest = /[^a-zA-Z -.\,]+/;
The importance being the * and + characters.
Add a quantifier + and the global flag /g:
var locationtest = /[^a-zA-Z \-\.\,]+/g;
Your expression is correct, you just need to invert the match result.
/[^a-zA-Z \-\.\,]/
Will match if the string contains any char that is not what you want (the leading ^ in the character class).
I.e remove the !:
var locationtest = /[^a-zA-Z \-\.\,]/;
if (locationtest.test($('#location').val())) {
alert('Nope, try again!');
$('#location').val('')
return false;
} else {
alert('You got it!');
}
Note that empty string will pass as valid, if you don't want that, you can use this instead:
/[^a-zA-Z \-\.\,]|^$/
I need to find a reg ex that only allows alphanumeric. So far, everyone I try only works if the string is alphanumeric, meaning contains both a letter and a number. I just want one what would allow either and not require both.
/^[a-z0-9]+$/i
^ Start of string
[a-z0-9] a or b or c or ... z or 0 or 1 or ... 9
+ one or more times (change to * to allow empty string)
$ end of string
/i case-insensitive
Update (supporting universal characters)
if you need to this regexp supports universal character you can find list of unicode characters here.
for example: /^([a-zA-Z0-9\u0600-\u06FF\u0660-\u0669\u06F0-\u06F9 _.-]+)$/
this will support persian.
If you wanted to return a replaced result, then this would work:
var a = 'Test123*** TEST';
var b = a.replace(/[^a-z0-9]/gi, '');
console.log(b);
This would return:
Test123TEST
Note that the gi is necessary because it means global (not just on the first match), and case-insensitive, which is why I have a-z instead of a-zA-Z. And the ^ inside the brackets means "anything not in these brackets".
WARNING: Alphanumeric is great if that's exactly what you want. But if you're using this in an international market on like a person's name or geographical area, then you need to account for unicode characters, which this won't do. For instance, if you have a name like "Âlvarö", it would make it "lvar".
Use the word character class. The following is equivalent to a ^[a-zA-Z0-9_]+$:
^\w+$
Explanation:
^ start of string
\w any word character (A-Z, a-z, 0-9, _).
$ end of string
Use /[^\w]|_/g if you don't want to match the underscore.
/^([a-zA-Z0-9 _-]+)$/
the above regex allows spaces in side a string and restrict special characters.It Only allows
a-z, A-Z, 0-9, Space, Underscore and dash.
^\s*([0-9a-zA-Z]*)\s*$
or, if you want a minimum of one character:
^\s*([0-9a-zA-Z]+)\s*$
Square brackets indicate a set of characters. ^ is start of input. $ is end of input (or newline, depending on your options). \s is whitespace.
The whitespace before and after is optional.
The parentheses are the grouping operator to allow you to extract the information you want.
EDIT: removed my erroneous use of the \w character set.
For multi-language support:
var filtered = 'Hello Привет 你好 123_456'.match(/[\p{L}\p{N}\s]/gu).join('')
console.log(filtered) // --> "Hello Привет 你好 123456"
This matches any letter, number, or space in most languages.
[...] -> Match with conditions
[ab] -> Match 'a' OR 'b'
\p{L} -> Match any letter in any language
\p{N} -> Match any number in any language
\s -> Match a space
/g -> Don't stop after first match
/u -> Support unicode pattern matching
Ref: https://javascript.info/regexp-unicode
This will work
^(?=.*[a-zA-Z])(?=.*[0-9])[a-zA-Z0-9]+$
It accept only alphanumeriuc characters alone:
test cases pased :
dGgs1s23 - valid
12fUgdf - valid,
121232 - invalid,
abchfe - invalid,
abd()* - invalid,
42232^5$ - invalid
or
You can also try this one. this expression satisfied at least one number and one character and no other special characters
^(?=.*[0-9])(?=.*[a-zA-Z])([a-zA-Z0-9]+)$
in angular can test like:
$scope.str = '12fUgdf';
var pattern = new RegExp('^(?=.*[0-9])(?=.*[a-zA-Z])([a-zA-Z0-9]+)$');
$scope.testResult = pattern.test($scope.str);
PLUNKER DEMO
Refered:Regular expression for alphanumeric in Angularjs
Instead of checking for a valid alphanumeric string, you can achieve this indirectly by checking the string for any invalid characters. Do so by checking for anything that matches the complement of the valid alphanumeric string.
/[^a-z\d]/i
Here is an example:
var alphanumeric = "someStringHere";
var myRegEx = /[^a-z\d]/i;
var isValid = !(myRegEx.test(alphanumeric));
Notice the logical not operator at isValid, since I'm testing whether the string is false, not whether it's valid.
I have string similar to Samsung Galaxy A10s 6.2-Inch (2GB,32GB ROM) Android 9.0, (13MP+2MP)+ 8MP Dual SIM 4000mAh 4G LTE Smartphone - Black (BF19)
Below is what i did:
string.replace(/[^a-zA-Z0-9 ,._-]/g, '').split(',').join('-').split(' ').join('-').toLowerCase()
Notice i allowed ,._- then use split() and join() to replace , to - and space to - respectively.
I ended up getting something like this:
samsung-galaxy-a10s-6.2-inch-2gb-32gb-rom-android-9.0-13mp-2mp-8mp-dual-sim-4000mah-4g-lte-smartphone-black-bf19-20 which is what i wanted.
There might be a better solution but this is what i found working fine for me.
Extend the string prototype to use throughout your project
String.prototype.alphaNumeric = function() {
return this.replace(/[^a-z0-9]/gi,'');
}
Usage:
"I don't know what to say?".alphaNumeric();
//Idontknowwhattosay
Even better than Gayan Dissanayake pointed out.
/^[-\w\s]+$/
Now ^[a-zA-Z0-9]+$ can be represented as ^\w+$
You may want to use \s instead of space. Note that \s takes care of whitespace and not only one space character.
Input these code to your SCRATCHPAD and see the action.
var str=String("Blah-Blah1_2,oo0.01&zz%kick").replace(/[^\w-]/ig, '');
JAVASCRIPT to accept only NUMBERS, ALPHABETS and SPECIAL CHARECTERS
document.getElementById("onlynumbers").onkeypress = function (e) {
onlyNumbers(e.key, e)
};
document.getElementById("onlyalpha").onkeypress = function (e) {
onlyAlpha(e.key, e)
};
document.getElementById("speclchar").onkeypress = function (e) {
speclChar(e.key, e)
};
function onlyNumbers(key, e) {
var letters = /^[0-9]/g; //g means global
if (!(key).match(letters)) e.preventDefault();
}
function onlyAlpha(key, e) {
var letters = /^[a-z]/gi; //i means ignorecase
if (!(key).match(letters)) e.preventDefault();
}
function speclChar(key, e) {
var letters = /^[0-9a-z]/gi;
if ((key).match(letters)) e.preventDefault();
}
<html>
<head></head>
<body>
Enter Only Numbers:
<input id="onlynumbers" type="text">
<br><br>
Enter Only Alphabets:
<input id="onlyalpha" type="text" >
<br><br>
Enter other than Alphabets and numbers like special characters:
<input id="speclchar" type="text" >
</body>
</html>
A little bit late, but this worked for me:
/[^a-z A-Z 0-9]+/g
a-z : anything from a to z.
A-Z : anything from A to Z (upper case).
0-9 : any number from 0 to 9.
It will allow anything inside square brackets, so let's say you want to allow any other character, for example, "/" and "#", the regex would be something like this:
/[^a-z A-Z 0-9 / #]+/g
This site will help you to test your regex before coding.
https://regex101.com/
Feel free to modify and add anything you want into the brackets.
Regards :)
It seems like many users have noticed this these regular expressions will almost certainly fail unless we are strictly working in English. But I think there is an easy way forward that would not be so limited.
make a copy of your string in all UPPERCASE
make a second copy in all lowercase
Any characters that match in those strings are definitely not alphabetic in nature.
let copy1 = originalString.toUpperCase();
let copy2 = originalString.toLowerCase();
for(let i=0; i<originalString.length; i++) {
let bIsAlphabetic = (copy1[i] != copy2[i]);
}
Optionally, you can also detect numerics by just looking for digits 0 to 9.
Try this... Replace you field ID with #name...
a-z(a to z),
A-Z(A to Z),
0-9(0 to 9)
jQuery(document).ready(function($){
$('#name').keypress(function (e) {
var regex = new RegExp("^[a-zA-Z0-9\s]+$");
var str = String.fromCharCode(!e.charCode ? e.which : e.charCode);
if (regex.test(str)) {
return true;
}
e.preventDefault();
return false;
});
});
Save this constant
const letters = /^[a-zA-Z0-9]+$/
now, for checking part use .match()
const string = 'Hey there...' // get string from a keyup listner
let id = ''
// iterate through each letters
for (var i = 0; i < string.length; i++) {
if (string[i].match(letters) ) {
id += string[i]
} else {
// In case you want to replace with something else
id += '-'
}
}
return id
Alphanumeric with case sensitive:
if (/^[a-zA-Z0-9]+$/.test("SoS007")) {
alert("match")
}
Also if you were looking for just Alphabetical characters, you can use the following regular expression:
/[^a-zA-Z]/gi
Sample code in typescript:
let samplestring = "!#!&34!# Alphabet !!535!!! is safe"
let regex = new RegExp(/[^a-zA-Z]/gi);
let res = samplestring.replace(regex,'');
console.log(res);
Note: if you are curious about RegEx syntax, visit regexr and either use the cheat-sheet or play with regular expressions.
Edit: alphanumeric --> alphabetical
Only accept numbers and letters (No Space)
function onlyAlphanumeric(str){
str.value=str.value.replace(/\s/g, "");//No Space
str.value=str.value.replace(/[^a-zA-Z0-9 ]/g, "");
}
<div>Only accept numbers and letters </div>
<input type="text" onKeyUp="onlyAlphanumeric(this);" >
Here is the way to check:
/**
* If the string contains only letters and numbers both then return true, otherwise false.
* #param string
* #returns boolean
*/
export const isOnlyAlphaNumeric = (string: string) => {
return /^(?=.*[a-zA-Z])(?=.*[0-9])[a-zA-Z0-9]+$/.test(string);
}
Jquery to accept only NUMBERS, ALPHABETS and SPECIAL CHARECTERS
<html>
<head>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
</head>
<body>
Enter Only Numbers:
<input type="text" id="onlynumbers">
<br><br>
Enter Only Alphabets:
<input type="text" id="onlyalpha">
<br><br>
Enter other than Alphabets and numbers like special characters:
<input type="text" id="speclchar">
<script>
$('#onlynumbers').keypress(function(e) {
var letters=/^[0-9]/g; //g means global
if(!(e.key).match(letters)) e.preventDefault();
});
$('#onlyalpha').keypress(function(e) {
var letters=/^[a-z]/gi; //i means ignorecase
if(!(e.key).match(letters)) e.preventDefault();
});
$('#speclchar').keypress(function(e) {
var letters=/^[0-9a-z]/gi;
if((e.key).match(letters)) e.preventDefault();
});
</script>
</body>
</html>
**JQUERY to accept only NUMBERS , ALPHABETS and SPECIAL CHARACTERS **
<!DOCTYPE html>
$('#onlynumbers').keypress(function(e) {
var letters=/^[0-9]/g; //g means global
if(!(e.key).match(letters)) e.preventDefault();
});
$('#onlyalpha').keypress(function(e) {
var letters=/^[a-z]/gi; //i means ignorecase
if(!(e.key).match(letters)) e.preventDefault();
});
$('#speclchar').keypress(function(e) {
var letters=/^[0-9a-z]/gi;
if((e.key).match(letters)) e.preventDefault();
});
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js">
Enter Only Numbers:
Enter Only Alphabets:
Enter other than Alphabets and numbers like special characters:
</body>
</html>