I wanted to know if Html5 supports shape translation in canvas..For instance I have a rectangle,is it possible to apply a transformation to it?
canvas = document.getElementById('Canvas');
context =canvas.getContext('2d');
context.rect(myRectangle.x,myRectangle.y,myRectangle.width,myRectangle.height);
There's a few different methods for animating and changing the position that you want to draw your thingy. Either way, if you're after an animation, you're going to need to clear your canvas and keep drawing - like a flip book if you will.
Choices for setting the newly drawn item include:
moveTo - to move to the new position of your thing
translate - to translate the centre point of the canvas and keep the drawing positions the same, but move the underlying coordinate system
.rect(newX, newY, height, width) - drawing the specific position
I mocked together a (contrived) example of using translate on a canvas - which will move the the animating box around the position of your cursor. It's done in a loop - and I'd suggest checking out Paul Irish's article on requestAnimFrame for better animation loops. Here's the example: http://jsbin.com/afofur/2/edit#preview
As the comments say in the previous answer - SVG maintains a object model, so you can reference objects on the page, canvas is a bitmap API (basically), and once the pixels are committed to the canvas, there's no reference to the method or shape behind the drawing, it's just pixels to the canvas API.
No, once it is drawn to the canvas you can't change it anymore, there is no in-memory representation of the shapes you draw on the canvas. However, you can transform the canvas before you draw the shape and reset transform (canvas.setTransform(1, 0, 0, 1, 0, 0)) after you've drawn the shape.
Edit
Remember that the canvas API doesn't keep track of which objects you draw. It just fills the pixels with a color where you ask it to draw a rectangle. If you want to make animations, you will have to keep track of which rectangle you drawn yourself (make an object with properties x, y, width, height). Then you will have to do the following in each animation step:
clear the canvas
update the objects for the new time frame
redraw the canvas
You can find a tutorial here.
Related
I'm writing an application that needs static clipping for images on the canvas (as you move the images on the canvas the clipping area stays in one place). I have three cases: polygon, ellipse, any shape specified with an image. I was able to cope with polygon and ellipse, because I can do them with paths and arcs, but when it comes to a mask specified via an image I'm not sure what to do.
Example shape to clip to:
Let's say I am not able to draw it using paths
So I have it specified with an image, I know how to obtain image data from it. What I'm trying to achieve is to clip everything that is out of that figure.
I was trying like this:
canvas.clipTo = function (ctx) {
ctx.drawImage(shape.src, left, top);
};
And like this:
canvas.clipTo = function (ctx) {
ctx.putImageData(imgData, left, top);
};
Of course none of them work as I expect, it just draws that black shape instead of clipping to that region.
Any ideas how to do it?
I do it by creating a new canvas the same size as the mask image. Then draw the image on that canvas, then set the ctx.globalCompositeOperation to "destination-in" draw the mask over the image (masking it) , then draw the that canvas to the on-screen canvas with ctx.drawImage
As this is most definitely a duplicated question I will not give the answer as code, it's been done to death here on stackoverflow.
Oh and I forgot. Using imageData to clip is a very inefficient way to do it.
I want to draw a semi-complex element on a canvas rotated without rotating the canvas so that I don't need to calculate all of the various x/y points of the element.
I think that the basic process I need to use is:
translate the 0,0 point to the spot the drawn element will be rotated around,
rotate the canvas,
draw the element,
rotate the canvas back,
restore the origin point.
I will need to do this more than once. I've read that the rotate / rotate back part can introduce some error, with the final image being off just a bit. Is there a way to avoid this?
Before you perform the rotation and translation, call context.save(). This will create a snapshot of the current transformation of the canvas (as well as some other things, like drawing style, clip region, etc., but not the pixel data) and store it on a stack.
After you drew the shape, call context.restore(). This will pop the last saved state from the state stack and restore the current drawing state of the canvas to it.
You can do this as often as you want without accumulating any rounding differences.
Example function:
function drawImageRotated(x, y, rotation, image) {
context.save();
context.translate(x, y);
context.rotate(rotation);
context.drawImage(image, -image.width / 2, -image.height / 2);
context.restore();
// context translation and rotation are now on the same state they were
// before the function call
}
For more information about the canvas state, refer to the canvas specification.
I have problem with canvas createPattern. I have two boxes, both will move after pressing a keyarrow:
Example:
http://jsfiddle.net/wA73R/1/
The problem is that the box background filled by createPattern also is moving. How to avoid that? Is there any solution? The big box is only an example (drawImage is not the good solution for me, I need something that will repeat background image).
Thank you for help
The problem is that the box background filled by createPattern also is moving.
Actually your problem is that the background is not moving - it is static, while you are drawing your rectangle to different positions.
How to avoid that?
The pattern will always be drawn at the coordinate origin, whose actual position is defined by the current transformation. In future you will be able to transform the pattern itself with the setTransform method, but since that currently is not implemented anywhere you instead will have to change the global transformation matrix.
In your case it means, that instead of drawing your rectangle at x/y, you translate the whole context to x/y and draw your rectangle at 0/0 then:
ctx.fillStyle=pattern;
ctx.save();
ctx.translate(boxes[i].x - left , boxes[i].y);
ctx.fillRect(0, 0, boxes[i].width, boxes[i].height);
ctx.restore();
(updated demo)
I just wonder how do the Canvas transformations work. Lets say i have a canvas with a circle drawn somewhere inside of it, and i want to scale the circle, so its center point will not move.
So i thought about doing the following:
translate(-circle.x, -circle.y);
scale(factor,factor);
translate(circle.x,circle.y);
// Now, Draw the circle by calling arc() and fill()
Is it the right way to do it? I just don't understand whether the canvas was designed to remember the order that i call the transformations.
Thanks.
Yes, you are correct.
The canvas accumulates all transforms and applies them to any future drawing.
So if you scale 2X, your circle will be drawn at 2X…and(!) every draw after that will be 2X.
That’s where saving the context is useful.
If you want to scale your circle by 2X but then have every subsequent drawing be at normal 1X you can use this pattern.
// save the current 1X context
Context.save();
// move (translate) to where you want your circle’s center to be
Context.translate(50,50)
// scale the context
Context.scale(2,2);
// draw your circle
// note: since we’re already translated to your circles center, we draw at [0,0].
Context.arc(0,0,25,0,Math.PI*2,false);
// restore the context to it’s beginning state: 1X and not-translated
Context.restore();
After Context.restore, your translate and scale will not apply to further drawings.
Say I drew a rectangle on the canvas. Surely there is some sort of built in method to get the XY coordinates, and dimensions of that rectangle? But after some googling I came up with nothing. And just to clarify, I am not talking about the coordinates of the canvas element itself, but rather a shape/image that is drawn unto the canvas.
Any help is appreciated.
If you're talking about a 2D canvas drawing, then the drawing maps 1:1 with screen coordinates, so it is just location of <canvas> + location of the drawing.
To clarify, drawing on a <canvas> basically just changes the pixels of the canvas - after you draw to it, you can't reference the drawn object the same way you can reference an html element.
Canvas is 2D table (Array) of numbers (= pixels = colors). When drawing into canvas, you are just editing this table. When you draw into canvas (= change numbers in table), what should be the coordinates of your adjustment?
If you are drawing rectangles only and you can define the coordinates for your rectangle, you must know your coordinates inside a program, because you have just drawn it.
If you want your image to be separated into some "objects" (shapes), you should use SVG.
Basically, you should be using canvas as a means to output graphics to the screen and the rest of your logic goes straight into the JavaScript that powers your game/application. The best way to go about making something like this is to create objects and assign properties to them; in its simplest form that can look like this:
function Player(x, y)
{
this.x = x;
this.y = y;
}
var examplePlayerObject = new Player(20, 20);
By extending this object via prototyping you can create multiple copies of an object that has the exact same functions; such as draw. Drawing the player in this instance could just be a red square that is 20px*20px.
Player.prototype.draw = function()
{
context.clearRect(0, 0, canvas.width, canvas.height);
context.fillStyle = 'red';
context.fillRect(this.x, this.y, 20, 20);
}
Then, you should have an update step with some means of clearing what is on the screen and redrawing the parts which have changed.
function animationStep()
{
examplePlayerObject.x++;
examplePlayerObject.y++;
examplePlayerObject.draw();
}
This animation step should run each frame; look into requestAnimationFrame for smooth animation. Paul Irish has a good shim for older browsers. Add in requestAnimationFrame(animationStep) at the end of that function and you will have a red square moving slowly across the screen. Good luck!