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How to revert toLocaleString

I need to convert a formatted number to JS default number format.
This is my code:
String.prototype.toJsFloatFormat = function() {
debugger;
var newVal = this;
return newVal;
}
//Example of use
var input = 10000.22; //default js format
var formatted = input.toLocaleString("es"); // result is: 10.000,22
var unformatted = formatted.toJsFloatFormat(); //expected result = 10000.22;
The problem is when I need to get the formatted number (10.000,22) and I make operations with this formatted number (parseFloat(10.000,22) + 1000) I have bad results ( parseFloat(10.000,22) + 1000 = 1010)
thanks in advance.

It's not easy. There's a reason why most of the comments have said "Don't try -
do your calculations on the number itself, not the formatted value".
You need to work out what the decimal and thousand separator characters are. For that, you will need to know which locale the number was converted into.
(1234.5).toLocaleString("es").match(/(\D+)/g);
// -> [".", ","]
Once you have that, you can replace characters in the formatted string.
function unformatString(string, locale) {
var parts = (1234.5).toLocaleString(locale).match(/(\D+)/g);
var unformatted = string;
unformatted = unformatted.split(parts[0]).join("");
unformatted = unformatted.split(parts[1]).join(".");
return parseFloat(unformatted);
}
There is no way of working out the locale - you have to know it and pass it to the function.

no need to reinvent the wheel -
https://github.com/globalizejs/globalize#readme
var input = 10000.22;
Globalize.parseFloat(input );

I did it this way(in my case it was the 'ru' local format, so I did replace the 'space' symbol):
var myNumber = 1000000;
var formated = myNumber.toLocaleString('ru');
var unformated = parseInt(formated.replace(/\s/g, ''));
your case:
var formated = myNumber.toLocaleString('en');
var unformated = parseInt(formated.replace(/,/g, ''));

I did this, that's fine for me
function localeStringToFloat(locale){
if(!locale) return locale
let test=1000
test=test.toLocaleString(undefined,{minimumFractionDigits: 2,maximumFractionDigits: 2});
let separator=test[1]
let decimalSeparator=test[5]
return parseFloat(locale.replaceAll(separator,'').replace(decimalSeparator,'.'))
}

My functions for format and unFormat currency numbers to 'en-US'. I hope helps
function myFormatPrice(num,digits){
return num.toLocaleString('en-US', {maximumFractionDigits:digits});
}
function myUnFormatPrice(formated){
return parseFloat( formated.replaceAll(',','') );
}

RegEx test method returns false when it should be true

I've tested the three of the regex's on http://www.regexpal.com/ and they are what I need, but when doing a regex test 2 of them return false (BTC and CAD) and only the Bitcoin address seems to work (you may test with this wallet below).
13dHNxtbckAFM4PzdBqWgymFJmcv3Yzi32
https://jsfiddle.net/ps2fj1ff/1
(all the relevant code is in the html section)
var regWallet = new RegExp("^[13][a-km-zA-HJ-NP-Z1-9]{25,34}$");
var regBTC = new RegExp("^\d*\.\d*$");
var regCAD = new RegExp("^\d+(\.(\d{2}))?$");
$('#button1').on('click', function() {
var btcCheck = $('#amount_btc').val();
if (regBTC.test(btcCheck)) {
} else {
alert("Invalid BTC value!");
}
var cadCheck = $('#amount_cad').val();
if (regCAD.test(cadCheck)) {
} else {
alert("Invalid CAD value!");
}
var walletCheck = $('#wallet').val();
if (regWallet.test(walletCheck)) {
} else {
alert("Invalid Bitcoin address, please make sure you've entered a valid address!");
}
});

The reason is that in var regBTC = new RegExp("^\d*\.\d*$"); the \ is used to escape the character so if you console.log(regBTC) you will see it as ^d*.d*$.
To prevent this you will have to double escape it: var regBTC = new RegExp("^\\d*\\.\\d*$");
Or better yet use / instead: var regBTC = /^\d*\.\d*$/;
The same goes for the other regex too.
(I initially thought single quote would work too, but apparently not in javascript)

Use this instead:
var regBTC = /^\d*\.\d*$/;
var regCAD = /^\d+(\.(\d{2}))$/;
It's cleaner and more readable as most editors will give you regexp syntax highlighting in this format.
There really isn't any good reason to use new RegExp which forces you to write the expression as a string, which forces you to use confusing escapes, when there is a proper regular expression syntax built into JavaScript.

Javascript method to check for digits within a string (validation of input data)

Im trying to implement a validation for an input field in IBM BPM.
Im not really familiar with java script but I try to get method that returns
ture if a string contains any numbers.
awdadw = valid
awdawd2d = invalid
I tried this method:
function hasNumbers(t)
{
var pattern=new RegExp("^[A-Za-z]+$");
return pattern.test(t); // true if string. Returns false for numbers
}
When I try this function, it says that method / variable RegExp is unknown. Since it is rather basci stuff I hope to get some sources where this topic is explained.

You can use this:
function validate(){
var re = /^[A-Za-z]+$/;
if(re.test(document.getElementById("inputID").value))
alert('Valid Name.');
else
alert('Invalid Name.');
}

Based on adre3wap this worked for me:
function validate(t){
var re = /^[A-Za-z]+$/;
if(re.test(t))
return false;
else
return true;
}

DateTime Validation in javascript

I am new to javascript. I am fixing bug programmed by others. I see validation code in javascript as:
function validateTime(str) {
var pattern = new RegExp(/^(([0-9])|([0-1][0-9])|([2][0-3])):(([0-9])|([0-5][0-9]))$/);
if (pattern.test(str)) {
return true;
}
else {
return false;
}
}
But it does't validate time:- 22-05-2015
How can it be done?

You can use the Date object's parse method to verify a date string.
You can then check if the value of Date.parse(str) is equal to "Invalid Date" to see if it is malformed. No need for regex at all.

Your regex validates time, not date. To check against date in your format, use this:
var pattern = new RegExp(/^(0[1-9]|[12][0-9]|3[01])-(0[1-9]|1[012])-(19|20)\d\d$/);
You can check this pattern here:
https://regex101.com/r/kB5nV2/1

function parseDate(str) {
var m = str.match(/^(\d{1,2})-(\d{1,2})-(\d{4})$/);
return (m) ? new Date(m[3], m[2]-1, m[1]) : null;
}
The function validateTime(str) used in your code is for time validation. Try the parseDate(str) for date validation.

How to test different format of dates in javascript / jquery?

I am developing a application. In this application have a input field. where the user can input the dates by different formats like
ddmmyy, ddmmyyyy, dd-mm-yy, mm-dd-yy
And I need to verify the date whether that valid or not. I can able to validate this way:
YYYY-MM-DD using:
var myDate = new Date("1987-08-06") // it returns me the date while this valid.
But I can't able to validate with other formats. how can i validate that?
example:
var myDate = new Date("08-06-1987")..etc?
I developed my app using jQuery. I am looking some solution without using a plug-in. since i used no.of plugins already.
thanks in advance!

I would do it with regular expressions. You could define a regexp pattern for each of your formats. Then you can test if the String from the input field matches any of the pattern.
Somthing like this:
var regExpDDMMYY = /[0-9]{2}[0-1][0-9][0-9]{2}/g;
var regExpddmmyyyy = ...;
...
...
if (regExpDDMMYY.test(yourInputStringFromDateField)) {
// handleDateAs DDMMYY
} else if (regExpddmmyyyy .test(yourInputStringFromDateField)) {
...
} else {
throw new YourException();
}
You can find an example here:
http://www.w3schools.com/js/js_regexp.asp

Unfortunately, there's no "parseExact" in native JS, that would also be crossbrowser. So you either need to use Date.js library or write some converter.
For this task i'd recommend you to use "Chain of responsibility" pattern
function DateTimeParser() {
this.parse = function (input) {
for (var key in Parsers) {
var result = Parsers[key].parse(input);
if (result !== null)
return result;
}
return null;
};
this.parseExact = function (input, format) {
var parser = Parsers[format];
return parser ? parser.parse(input) : null;
};
var ConcreteDateTimeParser = function (expression, parser) {
this.parse = function (input) {
if (!input.match(expression))
return null;
var result = parser(input);
return isNaN(result.getDate()) ? null : result;
};
};
var Parsers = {
"dd-mm-yyyy": new ConcreteDateTimeParser(/\d{2}\-\d{2}\-\d{4}/, function (input) {
var dd = parseInt(input.slice(0, 2)),
mm = parseInt(input.slice(3, 5)),
yyyy = parseInt(input.slice(-4));
return new Date(yyyy, mm, dd);
}),
"ddmmyyyy": new ConcreteDateTimeParser(/\d{8}/, function (input) {
var dd = parseInt(input.slice(0, 2)),
mm = parseInt(input.slice(2, 4)),
yyyy = parseInt(input.slice(-4));
return new Date(yyyy, mm, dd);
})
};
};
var instance = new DateTimeParser();
instance.parse('22122012');
instance.parseExact('22122012', 'ddmmyyyy');
instance.parseExact('22122012', 'dd-mm-yyyy'); // null
From this you can extend your Parsers lib with additional parsers. You also can use different sets of parsers by passing them into DateTimeParser as a constructor argument. My code is pretty trivial, for i didn't want to write it mega-deep, just wanted to show the way =)