javascript var into input value - javascript

can someone help me out getting a javascript var inside the value of a form
input value?
I'm a newbie in javascript but can give you my solution in php.
("Just use php" isn't an option because it have to be client-based :D )
<?php
$value = "Hello!";
?>
<form name="settings" action="">
<input name="color" value="<?php echo $value; ?>" />
</form>
Thanks in advance

Like this:
document.forms["settings"].color.value = "your value goes here...";

<?php
$value = "Hello!";
?>
<form name="settings" action="">
<input name="color" value="" />
</form>
<script>
document.forms["settings"].color.value = "<?php echo $value;?>";
</script>

Related

Form is auto submitting but the data is not getting passed/received

I have a problem in automating a form with hidden inputs in PHP. Basically I'm doing an input for a barcode scanner where the user will input the barcode and it will auto-submit, just like in a cash registry.
The conflict which I think is the cause of the problem is because of a conditional form. Here is a snippet:
<form method="post" id="form1">
<div class="products">
<input type="text" name="code" class="form-control" autofocus required onchange="submit()" />
</div>
</form>
<?php
$query = 'SELECT * FROM product WHERE PRODUCT_CODE='.$code.' GROUP BY PRODUCT_CODE ORDER by PRODUCT_CODE ASC';
$result = mysqli_query($db, $query);
if ($result):
if(mysqli_num_rows($result)>0):
while($product = mysqli_fetch_assoc($result)):
?>
<form id="form2" method="post" action="pos.php?action=add&id=<?php echo $product['PRODUCT_CODE']; ?>" >
<input type="hidden" name="quantity" class="form-control" value="1" />
<input type="hidden" name="name" value="<?php echo $product['NAME']; ?>" />
<input type="hidden" name="price" value="<?php echo $product['PRICE']; ?>" />
<input type="submit" name="addpos" style="margin-top:5px;width: 462px" class="btn btn-info" value="Add"/>
</form>
<?php
endwhile;
endif;
endif;
?>
<script>
function submit() {
document.getElementById("form1").submit();
}
document.getElementById("form2").submit();
</script>
The data from form1 has no trouble auto-submitting, then the form2 will auto-submit but nothing happens. I need help on how can I make form2 auto-submit correctly too. I have tried different event handling for form2 but nothing happens. I only know a little bit of javascript so that's just how my script turned out.
Thank you, Programming kings!
Because the second form is inside the while loop, if there are multiple results there will be multiple forms with the same id = "form2".
You need an increment variable $incrm = 2 inside the loop,
form id='form<?php echo $incrm;?>',
with $incrm++ before ending it. I also recommend to add ann onchange event to the last input 'price' ; onchange = submit(this).
function submit(inp) {
inp.parentElement.submit();
}

Get the values of while loop using button with js

How can I get the values in the while loop using button with js?
<?php
while ($row = mysqli_fetch_array($query))
{
echo '<input type="text" name="sample" value="'.$row['sample'].'">';
}
?>
Thanks
You can get the value of textbox when you click on a button.
<input type="text" name="sample[]" value="abc" class="valueInput">
<input type="text" name="sample[]" value="xyz" class="valueInput">
<input type="text" name="sample[]" value="pqr" class="valueInput">
<input type="button" class="getValue" value="Get Value">
Note: I have set the static input box you can make it dynamic but make sure please add the class as valueInput.
Jquery Code.
$(document).on('click','.getValue',function(){
var valArr = [];
$(".valueInput").each(function(){
valArr.push($(this).val());
});
console.log(valArr);
})
The name of the input field should indicate an array with [].
<form action="action.php" method="POST">
<?php
while ($row = mysqli_fetch_array($query)){
echo '<input type="text" name="sample[]" value="'.$row['sample'].'">';
}
?><input type="submit">
</form>
action.php: (Processes the data on submit)
<?php
echo "<pre>";
print_r($_POST['sample']);
echo "</pre>";

How to keep php $_GET value from a submit button after form submit from javascript?

I have a php page with 2 submit buttons and 2 radio buttons:
<?php
$choiceIdx = 1;
$language = 'English';
if($_GET)
{
if(isset( $_GET['choice'] ))
{
$choiceIdx = $_GET['choice'];
}
if(isset( $_GET['language'] ))
{
$language = $_GET['language'];
}
}
?>
<form method="get">
<button type='submit' name='choice' value='1'>Choice1</button>
<button type='submit' name='choice' value='2'>Choice2</button>
<input id="English" type="radio" name="language" value="English" <?php echo ($language=='English')?'checked':'' ?> onchange="this.form.submit();" />
<label for="English">English</label>
<input id="Slovenian" type="radio" name="language" value="Slovenian" <?php echo ($language=='Slovenian')?'checked':'' ?> onchange="this.form.submit();" />
<label for="Slovenian">Slovenian</label>
</form>
If I click on Slovenian radio button, I get:
http://localhost/index.php?language=Slovenian
If I then click on Choice2 submit button, "language" is saved and I get:
http://localhost/index.php?choice=2&language=Slovenian
If I then click on English radio button, "choice" is not saved and I get:
http://localhost/index.php?language=English
This is my first php page and after hours of googling i added this line:
<input type="hidden" name="choice" value="<?php echo $choiceIdx; ?>">
The "choice" is now saved, but i get:
http://localhost/index.php?choice=1&language=Slovenian&choice=2
I don't want it twice in url. Please explain what i am doing wrong. Thank you!
EDIT: I want to use GET (and not POST) because the URL has to be saved as a bookmark.
Here is an alternate version (as a followup to my first answer) that updates the hidden value when clicking the choice-button:
<script>
function setChoice(val) {
document.getElementById('hiddenChoice').value=val;
}
</script>
<form method="get">
<button type='submit' onClick="setChoice(1);">Choice1</button>
<button type='submit' onClick="setChoice(2);">Choice2</button>
<input type='hidden' id='hiddenChoice' name='choice' value='<?php echo $choiceIdx; ?>'>
<input id="English" type="radio" name="language" value="English" <?php echo ($language=='English')?'checked':'' ?> onchange="this.form.submit();" />
<label for="English">English</label>
<input id="Slovenian" type="radio" name="language" value="Slovenian" <?php echo ($language=='Slovenian')?'checked':'' ?> onchange="this.form.submit();" />
<label for="Slovenian">Slovenian</label>
</form>
If you have more values to retrieve you might want to create a more sofisticated and less specific js-function. You could easily pass in the id of the target input f.e.
Also you should rethink if it's realy neccessary to always submit the form, or if it might be better to first collect all the data and only send one form back to the server.
Add that to your form:
<input type='hidden' name='choiceStored' value='<?php echo $choiceIdx; ?>'>
This will store the last received val for choice and re-send it at the next form submit.
and change your php to:
$choiceIdx = 1;
$language = 'English';
if($_GET)
{
// eighter get new value
if(isset( $_GET['choice'] ))
{
$choiceIdx = $_GET['choice'];
// or if we don't have a new value, take the 'stored' one:
} elseif (isset($_GET['choiceStored']))
{
$choiceIdx = $_GET['choiceStored'];
}
if(isset( $_GET['language'] ))
{
$language = $_GET['language'];
}
}
You are passing the same name twice. 'choice' has been defined as both the hidden value name and the button value name. To be able to differentiate, you should change the hidden value name to something like 'savedchoice'. And reference it by that name

How to set readonly all input beside input that user try to fill data?

How to set readonly all input except input that user try to fill data ?
When user loads page index.php and tries to fill data into EG: <input id="edValue2" ...>, I want to set readonly all input except <input id="edValue2" ...>
But my code not work, how can i do ?
index.php
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<html>
<body>
<form id="form-id" method="post" action="" ENCTYPE = "multipart/form-data" onsubmit="return checkform(this);">
<?PHP
for ($i=1;$i<=5;$i++)
{
?>
<input id="edValue<?PHP echo $i; ?>" type="text" onKeyUp="send_it_register_to_hidden_input<?PHP echo $i; ?>()" onKeyPress="send_it_register_to_hidden_input<?PHP echo $i; ?>()"><br>
<?PHP
}
?>
<br>
<br>
<br>
<input type="text" id="lblValue" value="">
<input type="text" id="lblValue_number" value="">
</form>
</body>
<?PHP
for ($i=1;$i<=5;$i++)
{
?>
<script>
function send_it_register_to_hidden_input<?PHP echo $i; ?>()
{
lblValue.value = $("#edValue<?PHP echo $i; ?>").val();
lblValue_number.value = <?PHP echo $i; ?>;
Check_register_it();
}
</script>
<?PHP
}
?>
<script>
function Check_register_it()
{
$('#form-id input').attr('disabled','disabled'); //disable all
$(this).removeAttr('disabled'); //enable the one that triggers the event
}
</script>
</html>
I strongly suggest don't create functions like that. It just makes your codes complicated. Use classes in this case so that you don't need to setup functions for each id that you want to manipulate:
<body>
<form id="form-id" method="post" action="" ENCTYPE = "multipart/form-data" onsubmit="return checkform(this);">
<?PHP for ($i=1;$i<=5;$i++) { ?>
<input class="input_boxes" type="text" data-i="<?php echo $i; ?>"><br/>
<?PHP } ?>
<br>
<br>
<br>
<input type="text" id="lblValue" value="">
<input type="text" id="lblValue_number" value="">
</form>
</body>
<script src="//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script>
$('.input_boxes').on('keyup', function(e){
var value = $(this).val();
var i_val = $(this).attr('data-i');
$('#lblValue').val(i_val);
$('#lblValue_number').val(value);
$('input').prop('readonly', true);
$(this).prop('readonly', false);
});
</script>
Assuming all inputs are children of the same element (i.e. siblings), you can use jQuery to do this easily:
$('input').on('focus', function(){
$('input').removeAttr('readonly');
$(this).siblings().attr('readonly', 'readonly');
});
JSBin:
http://jsbin.com/qukohosafuje/1/edit
Try this :-
$("input").on('keyup', function () {
$('input').not(this).attr('readonly', 'readonly');
});
DEMO
You have to put all JQuery statement within:
$(function(){
//put your JQuery code here
});
Try and let me know if now works.
You can simply use the html attribute of readonly for the inputs you don't want users to fill.
e.g
<input type="text" id="lblValue" value="" readonly>
if you would required the readonly inputs to be accessible after the necessary input has been filled, you can use jquery to trigger the event.
e.g
$('input').keyUp(function(){
if($('#edValue2').val()!=""){
$('input:not("#edValue2")').removeAttr('readonly');
})

Can only post first result of while loop

I am using a while loop to display results from a query. The while loop is working fine. In hidden fields I would like to post the values of userID and accessID to the user details page. I am submitting the form using javascript to submit from a link. My problem is that regardless of the username I click I can only post the values for the first displayed record. What am I doing wrong?
The code:
<?php
while($row = $result->fetch_array()) { ?>
<form method="post" action="edit_user.php" id="userForm">
<tr>
<td>
<?php echo $row['firstname'].' '.$row['surname']; ?>
<input type="hidden" name="userID" value="<?php echo $row['userID']; ?>" />
<input type="hidden" name="accessID" value="<?php echo $row['accessID']; ?>" />
</td>
</tr>
</form>
<?php } ?>
The javascript used for submitting the form:
function submitForm() {
var form = document.getElementById("userForm");
form.submit();
}
Thank you.
EDIT - I don't want to pass the values in the url.
you are generating multiple <form>s inside loop, move your <form> outside while loop, like:
<form method="post" action="edit_user.php" id="userForm">
<?php
while($row = $result->fetch_array()) { ?>
<tr>
<td>
<?php echo $row['firstname'].' '.$row['surname']; ?>
<input type="hidden" name="userID[]" value="<?php echo $row['userID']; ?>" />
<input type="hidden" name="accessID[]" value="<?php echo $row['accessID']; ?>" />
</td>
</tr>
<?php } ?>
Submit
</form>
You're running into trouble because of this line
var form = document.getElementById("userForm");
In Javascript and HTML, an ID is supposed to be unique to a certain DOM element. In this case, you've got a whole load of form tags that have the same ID. You need to give each form a different ID, and then pass that ID to the submitForm function.
For example:
<?php
$id = 0;
while($row = $result->fetch_array()) { ?>
$id++;
<form method="post" action="edit_user.php" id="<?php echo "userForm".$id ?>">
<tr>
<td>
<?php echo $row['firstname'].' '.$row['surname']; ?>
<input type="hidden" name="userID" value="<?php echo $row['userID']; ?>" />
<input type="hidden" name="accessID" value="<?php echo $row['accessID']; ?>" />
</td>
</tr>
</form>
<?php } ?>
and then
function submitForm(id) {
var form = document.getElementById(id);
form.submit();
}
edit: how do I php? :D

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