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Javascript how to adding minus number and positive number

i made a simple program convert number to word. and i got problem when i want to convert minus number.
I want to find the index in the array 'satuan' so that later I add the word 'minus'
in my code i use Indonesian language btw.
js code:
// i have array like this
var satuan = ['', 'satu', 'dua', 'tiga', 'empat', 'lima', 'enam', 'tujuh', 'delapan', 'sembilan'];
// and my function to convert minus number like this
function convert_minesPuluhan(num) {
var c = Math.abs(num) + Math.abs(num);
if (num < 0 && num > -10) {
return satuan[num + c];
}
}
but when i console.log(num + c). the result is (example the num value is -1) -12.
but what I want is -1 + 1 + 1 = 1
// so i want like this
satuan[1];
how to solve this?

You are most likely getting a string for num
So, you'll have to do num = parseInt(num) first to convert it into an int datatype.
i.e.
function convert_minesPuluhan(num) {
num = parseInt(num)
var c = Math.abs(num) + Math.abs(num);
if (num < 0 && num > -10) {
return satuan[num + c];
}
}

Try this, your code is working fine. I understand that you need to add the 'minus' keyword before negative numbers.
var satuan = ['', 'satu', 'dua', 'tiga', 'empat', 'lima', 'enam', 'tujuh', 'delapan', 'sembilan'];
// and my function to convert minus number like this
function convert_minesPuluhan(num) {
var c = Math.abs(num) + Math.abs(num);
if (num < 0 && num > -10) {
console.log("minus " + satuan[num + c])
return "minus " + satuan[num + c];
}
}
convert_minesPuluhan(-5)

You need to convert the input of your function to integer
You are adding 2 strings in your function "-1" and "2" and thats why youre getting "-12" which is undefined.
let num = parseInt(num);
Try this inside your function and rest all is the same.

Calculations on formatted text fields

I have a form that will collect various data about properties. The user enters in values to select fields and onBlur, those values are formatted with comma's, dollar signs, and/or percentage signs.
I'm trying to create some real time calculations based on those inputs, but I'm having a hard time getting started on this. I have created a jfiddle page and have been playing around with ideas for the past few hours, but I just cannot seem to get the first calculation working.
I know I need to strip out any characters and have tried parseInt, parseFloat, replace, ect. Just nothing seems to work.
Thank you in advance.
function formatNumber(number, digits, decimalPlaces, withCommas)
{
number = number.toString();
var simpleNumber = '';
// Strips out the dollar sign and commas.
for (var i = 0; i < number.length; ++i)
{
if ("0123456789.".indexOf(number.charAt(i)) >= 0)
simpleNumber += number.charAt(i);
}
number = parseFloat(simpleNumber);
if (isNaN(number)) number = 0;
if (withCommas == null) withCommas = false;
if (digits == 0) digits = 1;
var integerPart = (decimalPlaces > 0 ? Math.floor(number) :
Math.round(number));
var string = "";
for (var i = 0; i < digits || integerPart > 0; ++i)
{
// Insert a comma every three digits.
if (withCommas && string.match(/^\d\d\d/))
string = "," + string;
string = (integerPart % 10) + string;
integerPart = Math.floor(integerPart / 10);
}
if (decimalPlaces > 0)
{
number -= Math.floor(number);
number *= Math.pow(10, decimalPlaces);
string += "." + formatNumber(number, decimalPlaces, 0);
}
return string;
}
function sumCalc() { // function to remove comma and then calculate
var glasf =
document.getElementById('gross_land_sf').value.replace(/,/g, "");
document.getElementById('gross_land_acre').value = formatNumber(glasf/43560);
}
https://jsfiddle.net/vva3x3wu/4/

Is this what you want ? I did some fixes:
https://jsfiddle.net/vva3x3wu/11/
In the link you put in the comment you removed class .cal from the first input, so calculations will not star until you tab from the last input.

JS for-loop how to get the first value

I'm sorry for the dumb question. I've been trying to do this for hours now, and i really can't get it to work. So i have a for-loop that loops though some numbers.
But it doesn't take the first value(71990000).
How can this be achieved?
This is what i've got so far:
var minNr = 0000;
var maxNr = 10000;
var prefix = 7199;
function Nummer(min,max)
{
var regex = /^(\d{2})\1$/;
var guld_nr;
for(guld_nr = minNr; guld_nr < maxNr;)
{
if(regex.test(guld_nr))
{
$(".resultat").append(prefix + "" + guld_nr + "<br>");
}
guld_nr++;
}
}
The output is this:
71991010
71991111
71991212
71991313
But i also need the number: 71990000
How can i do that ?

It's because your regex is rejecting the number 0; the first time through the loop, minNr has the numeric value 0 (setting it to 0000 doesn't help; it's just a fancy way of saying 0). The regex expects two digits followed by the same pattern, but what you're giving it is the string '0'.
You could set minNr to be a string instead on the first pass through ('0000'), and this will solve the problem for '0000', but you will miss '0101', '0202', etc. (which will convert to the strings '101', '202', and so on.)
One solution would be to zero pad the string representation of your number. The following function will take any number and left zero pad it to fit a given width:
function zeropad(n, w) {
n = String(n);
while(n.length < w) n = '0' + n;
return n;
}
You can use it to convert minNr for the regex:
regex.test(zeropad(guld_nr, 4))
Also note that Number is a built-in object wrapper for literals in JavaScript (all of the primitives have object wrappers: Number, Boolean, String), and by creating a function called Number, you are occluding this built-in object, which is inadvisable (code that needs to use it will invoke your function instead, which is incompatible and has a different purpose).

Use string:
var minNr = '0000';
It's the start value for the regex test, and you need the four zeroes for that. If it would be a number, then you get only one zero for testing. it would help, if you pad it with leading zeroes.
var minNr = '0000',
maxNr = 10000,
prefix = 7199;
function Nummer(min,max) {
var regex = /^(\d{2})\1$/;
var guld_nr;
for(guld_nr = minNr; guld_nr < maxNr;guld_nr++) {
if(regex.test(guld_nr)) {
document.write(prefix + "" + guld_nr + "<br>");
}
}
}
Nummer(minNr, maxNr);

Numbers don't zero-pad themselves; 0000; // 0
Make a custom zero-pad method for it so you can do zpad(0, 4); // "0000"
function zpad(x, digits) {
var pad = '0';
x = x.toString();
digits -= x.length;
while (digits > 0) {
if (digits & 1) x = pad + x;
pad += pad;
digits >>>= 1;
}
return x;
}
Now adjust Nummer accordingly
function Nummer(min, max, prefix) {
var regex = /^(\d{2})\1$/,
i, str;
prefix = prefix || '';
for(i = min; i < max; ++i) {
str = zpad(i, 4);
if(regex.test(str)) console.log(prefix + str);
}
}
and use
Nummer(minNr, maxNr, '7199');
Side note
Nummer is not constructing an Object, consider camel casing it

You could use arithmetic to do the digit pattern check, and keep the result numerical:
var minNr = 0; // it does not help to put 4 zeroes here.
var maxNr = 10000;
var prefix = 7199;
function Nummer(min,max) {
for (var guld_nr = min; guld_nr < max; guld_nr++) {
if (Math.floor(guld_nr/100) === guld_nr % 100 ) {
$(".resultat").append((prefix * 10000 + guld_nr) + "<br>");
}
}
}
Nummer(minNr, maxNr);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="resultat"></div>
The problem with your code is when the lower numbers are tested against the regular expression, they are implicitly converted to string, and do not get prefixed zeroes, so they fail on the regular expression.
Anyway, the code will be more efficient when sticking to numbers instead of strings, so I would suggest working with numbers all the way up to the point of outputting them in the browser.
Even more efficient is this code:
var minNr = 0; // it does not help to put 4 zeroes here.
var maxNr = 10000;
var prefix = 7199;
function Nummer(min,max) {
var test = Math.floor(min/100)*100 + Math.floor(min/100)%100;
var guld_nr = test < min ? test + 101 : test;
for (; guld_nr < max; guld_nr+=101) {
$(".resultat").append((prefix * 10000 + guld_nr) + "<br>");
}
}
Nummer(minNr, maxNr);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="resultat"></div>

Converting input into nicely formatted numbers (javascript)

Two part question.
Part 1 is easy, but I'm wondering what you think is the most elegant solution:
What would be the best procedure to use to convert input into cleanly formatted and WITH "normal" comma placement. The input could range from:
$8000
8200
8,000.50
And I want it to output simply: 8,000
Part 2, may be easy I just don't know the right operation. I want to round numbers so that: it is rounded based on the number of digits. So that there are TWO unrounded digits at all time.
45,643 should be 46,000
453 should be 450
59,023,920 should be 59,000,000

The following code should answer both parts of the question:
var input = "$820322310"; // String input
input = input.replace(/[^0-9\.]/g, ""); // remove all unnecessary characters
input = input.replace(/\.[0-9]+/, ""); // remove all after decimal (convert to integer)
if(parseInt(input[2]) >= 5) { // rounding to two decimal places
input[1] = input.slice(0, 1) + (parseInt(input[1]) + 1) + input.slice(2, input.length);
}
var count = 0;
for(var i = input.length-1; i >= 0; i--) {
if(i > 2) {
input = input.slice(0, i-1) + "0" + input.slice(i, input.length);
}
if(++count == 3 && i != 0) {
count = 0;
input = input.slice(0, i) + "," + input.slice(i, input.length);
}
}
See this at JSFiddle.

how to divide a number a in a series of all whole numbers?

Hi sorry for asking this if this is a stupid question.
I would like to ask how to securely divide a number in Javascript that it will always
output the result in a way that it will output pure whole numbers.
example:
10 / 2 ---> 5, 5 ( it would be 2 fives so it is whole number )
BUT
10 / 3 ---> 3, 3, 4 ( it would have two 3 and one 4 so that it would still result to 10 )

10/3 will give you 3.333333..., never four... if you want to check is a number will give you "whole numbers" as you say, use modulo (%).
Modulo finds the remainder of division of one number by another.
For example
10%5 = 0 because 10 divided by 5 is a "whole number"
10%3 = 1 because the closest 10/3 is 3... 3x3=9... 10-9=1
So in your code, if you want to know if a number divided by another number is whole, you need to do
if (number1%number2 == 0) { ... }
Read more about it here
EDIT :
I read your question again and I think this fiddle is what you want
var number1 = 10,
number2 = 3;
if (number1 / number2 == 0) {
alert('the numbers are whole');
} else {
var remainder = number1%number2;
var wholes = Math.floor(number1 / number2);
var output = '';
for (var i = 0; i < (wholes - 1); i++) {
output+= number2 + ', ';
}
output += (number2 + remainder);
alert(output);
}

Whatever your result is,just pass it through the parseInt function,For Eg:-
Suppose your answer is 4.3,
The whole number close to it will can be accounted using,
parseInt(4.3)
Which equals 4.

Another posibility: make the number a string and walk all the elements
var a = 11 / 4;
//turn it into a string and remove all non-numeric chars
a = a.toString().replace(/\D/g, '');
//split the string in seperate characters
a = a.split("");
var num = new Array();
//convert back to numbers
for (var i = 0; i < a.length; i++) {
num.push(parseFloat(a[i]));
}
alert(num);
On a sidenote, you'll have to do some kind of rounding, to prevent eternally repeating numbers, like 10/3.
Here is a fiddle

Look at this very simple example:
var x = 10;
var y = 3;
var result = x/y;
var rest = x%y;
for (var i=0; i<y; i++) {
var output;
if(i==y-1){
output = parseInt(result + rest);
}
else{
output = parseInt(result);
}
alert(output);
}
http://jsfiddle.net/guinatal/469Vv/4/