I would like to create a structure within javascript. I have a pair of informations, I would like to use, example:
array[1] = new Struct();
array[1].name = "parameter-name";
array[1].value = "parameter-value";
array[2] = new Struct();
array[2].name = "parameter-name2";
array[2].value = "parameter-value2";
This can be on a diffrent page with diffrent values, maybe on element within my array, maybe 2-20..
Later, within my generic javascript, I would like to parse the array and continue with my parameters, example:
for(i=1 to length_of_my_array) {
_tag.array[i].name = array[i].value;
}
How can I realize this with pure javascript? Thanks for any hint!
As long as you don't want any fancy features, it's really easy to create such structures in JavaScript. In fact, the code you posted will almost work, if you replace the new Struct() with this:
array[1] = {};
This creates an empty object, and you can put any properties you want in it, such as name and value.
To create an array, you can do something like this:
var array = []; // empty array
// object literal notation to create your structures
array.push({ name: 'abc', value: 'def' });
array.push({ name: 'ghi', value: 'jkl' });
...
And to iterate over the array:
for (var i = 0; i < array.length; i++) {
// use array[i] here
}
It would be good to find out more regarding the problem you are attempting to resolve.
I don't think there is an object in JavaScript called Struct, unless you define one.
I think what you are looking for is a JavaScript object instead of Struct. There are a number of ways to create a new object, and they can be nested in an array or in other objects.
myArray[0] = new Object();
myArray[0].name = "parameter-name";
myArray[0].value = "parameter-value";
myArray[1] = new Object();
myArray[1].name = "parameter-name2";
myArray[1].value = "parameter-value2";
Notice that I have changed your code in a couple of ways:
1. "array" is named "myArray" to clarify that we are referring to a particular array.
2. The first instance of myArray is 0. Arrays start at 0 in Javascript.
3. Struct is changed to Object.
myarray = [
{
"name":"parameter-name",
"value":"parameter-value"
},
{
"name":"parameter-name2",
"value":"parameter-value2"
}
];
This is an alternative syntax for doing the same thing. It uses "literal notation" to designate an array (the square brackets), and the objects (the curly brackets).
for(var i = 0; i < myArray.length; i++) {
for(key in myArray[i]) {
alert(key + " :: " myArray[i][key]);
}
}
This will loop over the array and alert you for each property of the object.
alert(myArray[0]['value']) //parameter-value
myArray[0]['value'] = "bar";
alert(myArray[0]['value']) //bar
Each property of each object can also be assigned a new value.
You can define arrays and generic objects in pure JavaScript/json:
var array = []; // empty array
array.push({name: 'parameter-name', value: 'parameter-value'});
array.push({name: 'parameter-name2', value: 'parameter-value2'});
console.log(array);
// Output:
// [Object { name="parameter-name", value="parameter-value2"}, Object { name="parameter-name2", value="parameter-value2"}]
You can also define the same array like so:
var array = [
{name: 'parameter-name', value: 'parameter-value'},
{name: 'parameter-name2', value: 'parameter-value2'}
];
As far as looping through the array:
for (var i = 0; i<array.length; i++) {
var elem = array[i];
console.log(elem.name, elem.value);
}
// Outputs:
// parameter-name parameter-value2
// parameter-name2 parameter-value2
I'd store object literals in the array, like so:
var myArray = [];
myArray[0] = {name:"some name", value:"some value"};
myArray[1] = {name:"another name", value:"another value"};
for (i=0; i < myArray.length; i++) {
console.log(myArray[i].name + ' / ' + myArray[i].value);
}
// initialize empty array
var myArray = [];
// fill it with an object - the equivalent of a struct in javascript
myArray.push({
name: 'example-name'
value: 'example-value'
});
// repeat as neccessary
// walking through the array
for (var i = 0; i < myArray.length; i++)
{
// retrieving the record
record = myArray[i];
// and accessing a field
doSomething(record.name);
}
var array = {paramName: 'paramValue', paramName2: 'paramValue2'};
for(i in array) {
_tag.i = array.i;
}
There is no "Struct" in JavaScript only Object
my_array = new Array();
my_array.push({name: 'john', age:31});
my_array.push({name: 'da_didi', age:120});
for (i=0; i<my_array.length; i++)
{
alert(my_array[i].name);
}
How about
function Struct(name, value) {
this.name = name;
this.value = value;
}
arr[0] = new Struct("name1", "value1");
Javascript objects are loose objects: properties can be added and removed dynamically. So making a new Struct(), as you suggest, does -not- guarantee that the returned object will always have the properties you expect it to have. You have to check the availability of properties at the point of usage (duck typing):
var i, element;
for (i = 0; i < array.length; i++) {
element = array[i];
if (Object.hasOwnProperty.call(element, "name")
&& Object.hasOwnProperty.call(element, "value")) {
_tag[element.name] = element.value;
}
}
(Also, I'm just guessing that _tag is an object itself, but that wasn't clear from your example.)
You could probably use a more succinct syntax, but that depends heavily on the values of the properties. For example, you -might- be able to use something like this:
var i, element;
for (i = 0; i < array.length; i++) {
element = array[i];
if (element.name && element.value) {
_tag[element.name] = element.value;
}
}
But you need to realize that the above condition will be false not only if one or both of the properties (name and value) are undefined but also if the value of either or both refers to the empty string, null, 0, NaN, or false.
Related
I have the following:
var params = {status: [69,71]};
var getTasks = function(params) {
if (params.status.constructor === Array) {
var statuses = params.status;
var newParams = [];
for (var i = 0; i < statuses.length; i++) {
params.status = statuses[i];
newParams.push(params);
}
console.log(newParams);
}
// else {
// ...
// }
};
Calling getTasks(params) logs newParams as:
[ { status: 71 }, { status: 71 } ].
I would expect this to log out
[ { status: 69 }, { status: 71 } ].
What am I missing here?
You're pushing the same Object twice, the most recent change to the Object is visible.
var obj;
for (var i = 0; i < statuses.length; i++) {
// construct obj as desired
obj = {}; // notice this new object is created inside the loop
obj.status = statuses[i];
// push to your array
newParams.push(obj);
}
newParams.push(params); is pushing the object referenced by params to your array. You have an array full of references to the same object, any modifications to that object will be present in each of the array elements, since they are all the same object. Create a new object each time instead of reusing the same one:
for (var i = 0; i < statuses.length; i++) {
newParams.push( { status: statuses[i] } );
}
params is a single object. Inside of your for loop, by doing the following:
for (var i = 0; i < statuses.length; i++) {
params.status = statuses[i];
newParams.push(params);
}
... you are overwriting the status field and pushing the object into the newParams array. However, the object isn't copied - instead, a reference to it is appended to the array. Thus, all elements of newParams are actually the same element.
Essentially, you need to push a clone of the params object into the array in the loop. If you're using jQuery or underscore, an easy way to clone is using the extend() function:
// jQuery
newParams.push(jQuery.extend({}, params));
// or Underscore
newParams.push(_.extend({}, params));
#PaulPro and #PaulS gave correct answers, but there's always an opportunity to learn something new. In this case, I'd recommend to take a look at Array.map which can greatly simplify your code:
function statutify(value) {
return { status: value };
}
var getTasks = function(params) {
if (params.status.constructor === Array) {
var newParams = params.status.map(statutify);
console.log(newParams);
}
// ...
};
Or, it can't hurt to learn something about other libraries like #voithos suggests.
I have an array of objects which contain certain duplicate properties: Following is the array sample:
var jsonData = [{x:12, machine1: 7}, {x:15, machine2:7},{x:12, machine2: 8}];
So what i need is to merge the objects with same values of x like the following array:
var jsonData = [{x:12, machine1:7, machine2:8}, {x:15, machine2:7}]
I like the lodash library.
https://lodash.com/docs#groupBy
_.groupBy(jsonData, 'x') produces:
12: [ {x=12, machine1=7}, {x=12, machine2=8} ],
15: [ {x=15, machine2=7} ]
your desired result is achieved like this:
var jsonData = [{x:12, machine1: 7}, {x:15, machine2:7},{x:12, machine2: 8}];
var groupedByX = _.groupBy(jsonData, 'x');
var result = [];
_.forEach(groupedByX, function(value, key){
var obj = {};
for(var i=0; i<value.length; i++) {
_.defaults(obj, value[i]);
}
result.push(obj);
});
I'm not sure if you're looking for pure JavaScript, but if you are, here's one solution. It's a bit heavy on nesting, but it gets the job done.
// Loop through all objects in the array
for (var i = 0; i < jsonData.length; i++) {
// Loop through all of the objects beyond i
// Don't increment automatically; we will do this later
for (var j = i+1; j < jsonData.length; ) {
// Check if our x values are a match
if (jsonData[i].x == jsonData[j].x) {
// Loop through all of the keys in our matching object
for (var key in jsonData[j]) {
// Ensure the key actually belongs to the object
// This is to avoid any prototype inheritance problems
if (jsonData[j].hasOwnProperty(key)) {
// Copy over the values to the first object
// Note this will overwrite any values if the key already exists!
jsonData[i][key] = jsonData[j][key];
}
}
// After copying the matching object, delete it from the array
// By deleting this object, the "next" object in the array moves back one
// Therefore it will be what j is prior to being incremented
// This is why we don't automatically increment
jsonData.splice(j, 1);
} else {
// If there's no match, increment to the next object to check
j++;
}
}
}
Note there is no defensive code in this sample; you probably want to add a few checks to make sure the data you have is formatted correctly before passing it along.
Also keep in mind that you might have to decide how to handle instances where two keys overlap but do not match (e.g. two objects both having machine1, but one with the value of 5 and the other with the value of 9). As is, whatever object comes later in the array will take precedence.
const mergeUnique = (list, $M = new Map(), id) => {
list.map(e => $M.has(e[id]) ? $M.set(e[id], { ...e, ...$M.get(e[id]) }) : $M.set(e[id], e));
return Array.from($M.values());
};
id would be x in your case
i created a jsperf with email as identifier: https://jsperf.com/mergeobjectswithmap/
it's a lot faster :)
I am working in javascript and I would like to find the index of an element in an array .
var task = [{taskno:'1',todo:'cooking'},{taskno:'2',todo:'play'}];
now i want to find the index of task which has todo as cooking and i dont know its task no .... is there any inbuilt function ?
I have tried this code but It's not working:
var index = task.indexOf(todo:'cooking');
Now I'm using a for loop is there any other way?
Thanks in advance :)
indexOf will give you the index of an object in an array, but you must already have a reference to that object.
e.g.
var o1 = { val: 'o1' },
o2 = { val: 'o2' };
[o2, o1].indexOf(o1); //1
If you do not have a reference to the object, you will have to create your own search algorithm.
var tasks = [{taskno:'1',todo:'cooking'}, {taskno:'2',todo:'play'}];
var index = indexOfFirstMatch(tasks, function (task) {
return task.todo === 'cooking';
});
console.log(index); //0
function indexOfFirstMatch(arr, matcher) {
var i = 0, len = arr.length;
for (; i < len; i++) {
if (matcher(arr[i])) return i;
}
return -1;
}
If you need the actual object, vs. just it's index. You could use the underscore library and it's findWhere function:
var task_wanted = _findWhere(task, {todo: "Cooking"});
If you actually need the index, then use task_wanted to search the array with indexOf().
Lets say I have this object here:
var items = [
{name:"Foo"},
{name:"Bar"},
{name:"foo"},
{name:"bar"},
{name:"foobar"},
{name:"barfoo"}
];
Since it only has one item in each object, I want to just return a list of them.
I tried this:
var getSingle = function(rows){
var items = [];
//This should only return one column
for (var i = 0; i < rows.length; i++) {
var r = rows[i];
var c = 0;
for (var n in r) {
if(c == 0)
items.push(r[n]);
c += 1;
}
}
return items;
}
But it doesn't seem to work. Any thoughts?
PS. name could be anything.
I used a different approach than the others, because I make two assumptions:
1/ you do not know the name of the key, but there is only one key for every item
2/ the key can be different on every item
I will give you a second option, with the second assumption as: 2/ all item have only one key but that's the same for all of them
First Options :
var items = [
{name:"Foo"},
{name:"Bar"},
{name:"foo"},
{name:"bar"},
{name:"foobar"},
{name:"barfoo"}
];
// object keys very simple shim
Object.keys = Object.keys || function(o) {
var result = [];
for(var name in o) {
if (o.hasOwnProperty(name))
result.push(name);
}
return result;
};
// function to get the value of every first keys in an object
// just remember that saying "first key" does not make real sense
// but we begin with the assumption that there IS ONLY ONE KEY FOR EVERY ITEM
// and this key is unknown
function getFirstKeysValues(items) {
var i = 0, len = items.length, item = null, key = null, res = [];
for(i = 0; i < len; i++) {
item = items[i];
key = Object.keys(item).shift();
res.push(item[key]);
}
return res;
}
console.log(getFirstKeysValues(items)); //["Foo", "Bar", "foo", "bar", "foobar", "barfoo"]
Second options will use a map, because we believe that every child possess the same key (I wouldn't use this one, because I do not like .map that much - compatibility):
var items = [
{name:"Foo"},
{name:"Bar"},
{name:"foo"},
{name:"bar"},
{name:"foobar"},
{name:"barfoo"}
];
// object keys very simple shim
Object.keys = Object.keys || function(o) {
var result = [];
for(var name in o) {
if (o.hasOwnProperty(name))
result.push(name);
}
return result;
};
// function to get the value of every first keys in an object
// just remember that saying "first key" does not make real sense
// but we begin with the asumption that there IS ONLY ONE KEY FOR EVERY ITEM
// and this key is unknown but the same for every child
function getFirstKeysValues(items) {
var key = items.length > 0 ? Object.keys(items[0]).shift() : null;
items = items.map(function (item) {
return item[key];
});
return items;
}
console.log(getFirstKeysValues(items));
This is usually accomplished using the map method, see the documentation here.
var justNamesArray = items.map(function(elem) { return elem.name});
The documenation page also includes a useful shim, that is a way to include it in your code to support older browsers.
Accompanying your request in the edit, if you would just like to get those that contain this property there is a nifty filter method.
var valuesWithNamePropert= items.filter(function(elem) { return elem.hasOwnProperty("name")});
You can chain the two to get
var justNamesWhereContains = items.filter(function(elem) { return elem.hasOwnProperty("name")}).
.map(function(elem) { return elem.name});
This approach (mapping and filtering), is very common in languages that support first order functions like JavaScript.
Some libraries such as underscore.js also offer a method that does this directly, for example in underscore that method is called pluck.
EDIT: after you specific that the property can change between objects in the array you can use something like:
var justReducedArray = items.map(function(elem) { for(i in elem){ return elem[i]}});
your var items = [] is shadowing your items parameter which already contains data. Just by seeing your code I thought that maybe your parameter should be called rows
If you're in a world >= IE9, Object.keys() will do the trick. It's not terribly useful for the Array of Objects, but it will help for the iteration of the Array (you would use Array.forEach to iterate the array proper, but then you would use the Object.keys(ob)[0] approach to get the value of the first property on the object. For example:
var someArr = [{ prop1: '1' },{ prop2: '2' },{ prop3: '3' }];
var vals = [];
someArr.forEach( function(obj) {
var firstKey = Object.keys(obj)[0];
vals.push(obj[firstKey]);
});
//vals now == ['1','2','3']
Obviously this isn't null safe, but it should get you an array of the values of the first property of each object in the original array. Say that 3 times fast. This also decouples any dependency on the name of the first property--if the name of the first property is important, then it's a trivial change to the forEach iteration.
You can override the Array.toString method for items, so using String(items) or alert(items) or items+='' will all return the string you want-
var items = [{name:"Foo"}, {name:"Bar"},{name:"foo"},
{name:"bar"},{name:"foobar"},{name:"barfoo"}];
items.toString= function(delim){
delim=delim || ', ';
return this.map(function(itm){
return itm.name;
}).join(delim);
}
String(items)
/* returned value: (String)
Foo, Bar, foo, bar, foobar, barfoo
*/
instead of the default string-'[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]'
Suppose I have this code:
var myArray = new Object();
myArray["firstname"] = "Bob";
myArray["lastname"] = "Smith";
myArray["age"] = 25;
Now if I wanted to remove "lastname"?....is there some equivalent of
myArray["lastname"].remove()?
(I need the element gone because the number of elements is important and I want to keep things clean.)
Objects in JavaScript can be thought of as associative arrays, mapping keys (properties) to values.
To remove a property from an object in JavaScript you use the delete operator:
const o = { lastName: 'foo' }
o.hasOwnProperty('lastName') // true
delete o['lastName']
o.hasOwnProperty('lastName') // false
Note that when delete is applied to an index property of an Array, you will create a sparsely populated array (ie. an array with a missing index).
When working with instances of Array, if you do not want to create a sparsely populated array - and you usually don't - then you should use Array#splice or Array#pop.
Note that the delete operator in JavaScript does not directly free memory. Its purpose is to remove properties from objects. Of course, if a property being deleted holds the only remaining reference to an object o, then o will subsequently be garbage collected in the normal way.
Using the delete operator can affect JavaScript engines' ability to optimise code.
All objects in JavaScript are implemented as hashtables/associative arrays. So, the following are the equivalent:
alert(myObj["SomeProperty"]);
alert(myObj.SomeProperty);
And, as already indicated, you "remove" a property from an object via the delete keyword, which you can use in two ways:
delete myObj["SomeProperty"];
delete myObj.SomeProperty;
Hope the extra info helps...
None of the previous answers address the fact that JavaScript does not have associative arrays to begin with - there is no array type as such, see typeof.
What JavaScript has, are object instances with dynamic properties. When properties are confused with elements of an Array object instance then Bad Things™ are bound to happen:
Problem
var elements = new Array()
elements.push(document.getElementsByTagName("head")[0])
elements.push(document.getElementsByTagName("title")[0])
elements["prop"] = document.getElementsByTagName("body")[0]
console.log("number of elements: ", elements.length) // Returns 2
delete elements[1]
console.log("number of elements: ", elements.length) // Returns 2 (?!)
for (var i = 0; i < elements.length; i++)
{
// Uh-oh... throws a TypeError when i == 1
elements[i].onmouseover = function () { window.alert("Over It.")}
console.log("success at index: ", i)
}
Solution
To have a universal removal function that does not blow up on you, use:
Object.prototype.removeItem = function (key) {
if (!this.hasOwnProperty(key))
return
if (isNaN(parseInt(key)) || !(this instanceof Array))
delete this[key]
else
this.splice(key, 1)
};
//
// Code sample.
//
var elements = new Array()
elements.push(document.getElementsByTagName("head")[0])
elements.push(document.getElementsByTagName("title")[0])
elements["prop"] = document.getElementsByTagName("body")[0]
console.log(elements.length) // Returns 2
elements.removeItem("prop")
elements.removeItem(0)
console.log(elements.hasOwnProperty("prop")) // Returns false as it should
console.log(elements.length) // returns 1 as it should
That only deletes the object, but it still keeps the array length the same.
To remove the element from the array, you need to do something like:
array.splice(index, 1);
While the accepted answer is correct, it is missing the explanation why it works.
First of all, your code should reflect the fact that this is not an array:
var myObject = new Object();
myObject["firstname"] = "Bob";
myObject["lastname"] = "Smith";
myObject["age"] = 25;
Note that all objects (including Arrays) can be used this way. However, do not expect for standard JavaScript array functions (pop, push, etc.) to work on objects!
As said in accepted answer, you can then use delete to remove the entries from objects:
delete myObject["lastname"]
You should decide which route you wish to take - either use objects (associative arrays / dictionaries) or use arrays (maps). Never mix the two of them.
There is an elegant way in the Airbnb Style Guide to do this (ECMAScript 7):
const myObject = {
a: 1,
b: 2,
c: 3
};
const { a, ...noA } = myObject;
console.log(noA); // => { b: 2, c: 3 }
Copyright: https://codeburst.io/use-es2015-object-rest-operator-to-omit-properties-38a3ecffe90
As other answers have noted, you are not using a JavaScript array, but a JavaScript object, which works almost like an associative array in other languages except that all keys are converted to strings. The new Map stores keys as their original type.
If you had an array and not an object, you could use the array's .filter function, to return a new array without the item you want removed:
var myArray = ['Bob', 'Smith', 25];
myArray = myArray.filter(function(item) {
return item !== 'Smith';
});
If you have an older browser and jQuery, jQuery has a $.grep method that works similarly:
myArray = $.grep(myArray, function(item) {
return item !== 'Smith';
});
Use method splice to completely remove an item from an object array:
Object.prototype.removeItem = function (key, value) {
if (value == undefined)
return;
for (var i in this) {
if (this[i][key] == value) {
this.splice(i, 1);
}
}
};
var collection = [
{ id: "5f299a5d-7793-47be-a827-bca227dbef95", title: "one" },
{ id: "87353080-8f49-46b9-9281-162a41ddb8df", title: "two" },
{ id: "a1af832c-9028-4690-9793-d623ecc75a95", title: "three" }
];
collection.removeItem("id", "87353080-8f49-46b9-9281-162a41ddb8df");
You are using Object, and you don't have an associative array to begin with. With an associative array, adding and removing items goes like this:
Array.prototype.contains = function(obj)
{
var i = this.length;
while (i--)
{
if (this[i] === obj)
{
return true;
}
}
return false;
}
Array.prototype.add = function(key, value)
{
if(this.contains(key))
this[key] = value;
else
{
this.push(key);
this[key] = value;
}
}
Array.prototype.remove = function(key)
{
for(var i = 0; i < this.length; ++i)
{
if(this[i] == key)
{
this.splice(i, 1);
return;
}
}
}
// Read a page's GET URL variables and return them as an associative array.
function getUrlVars()
{
var vars = [], hash;
var hashes = window.location.href.slice(window.location.href.indexOf('?') + 1).split('&');
for(var i = 0; i < hashes.length; i++)
{
hash = hashes[i].split('=');
vars.push(hash[0]);
vars[hash[0]] = hash[1];
}
return vars;
}
function ForwardAndHideVariables() {
var dictParameters = getUrlVars();
dictParameters.add("mno", "pqr");
dictParameters.add("mno", "stfu");
dictParameters.remove("mno");
for(var i = 0; i < dictParameters.length; i++)
{
var key = dictParameters[i];
var value = dictParameters[key];
alert(key + "=" + value);
}
// And now forward with HTTP-POST
aa_post_to_url("Default.aspx", dictParameters);
}
function aa_post_to_url(path, params, method) {
method = method || "post";
var form = document.createElement("form");
// Move the submit function to another variable
// so that it doesn't get written over if a parameter name is 'submit'
form._submit_function_ = form.submit;
form.setAttribute("method", method);
form.setAttribute("action", path);
for(var i = 0; i < params.length; i++)
{
var key = params[i];
var hiddenField = document.createElement("input");
hiddenField.setAttribute("type", "hidden");
hiddenField.setAttribute("name", key);
hiddenField.setAttribute("value", params[key]);
form.appendChild(hiddenField);
}
document.body.appendChild(form);
form._submit_function_(); // Call the renamed function
}
If, for whatever reason, the delete key is not working (like it wasn't working for me), you can splice it out and then filter the undefined values:
// To cut out one element via arr.splice(indexToRemove, numberToRemove);
array.splice(key, 1)
array.filter(function(n){return n});
Don’t try and chain them since splice returns removed elements;
By using the "delete" keyword, it will delete the array element from array in JavaScript.
For example,
Consider following statements.
var arrayElementToDelete = new Object();
arrayElementToDelete["id"] = "XERTYB00G1";
arrayElementToDelete["first_name"] = "Employee_one";
arrayElementToDelete["status"] = "Active";
delete arrayElementToDelete["status"];
The last line of the code will remove the array element whose key is "status" from the array.
You can do the following if you want a more functional and elegant approach:
const o = { firstName: "foo", lastName: "bar" };
const { lastName, ...removed } = o;
lastName // bar
removed // { firstName: "foo" }
Note that the value of removed will be undefined if there are no items left in the object.
You can remove an entry from your map by explicitly assigning it to 'undefined'. As in your case:
myArray["lastname"] = undefined;
We can use it as a function too. Angular throws some error if used as a prototype. Thanks #HarpyWar. It helped me solve a problem.
var removeItem = function (object, key, value) {
if (value == undefined)
return;
for (var i in object) {
if (object[i][key] == value) {
object.splice(i, 1);
}
}
};
var collection = [
{ id: "5f299a5d-7793-47be-a827-bca227dbef95", title: "one" },
{ id: "87353080-8f49-46b9-9281-162a41ddb8df", title: "two" },
{ id: "a1af832c-9028-4690-9793-d623ecc75a95", title: "three" }
];
removeItem(collection, "id", "87353080-8f49-46b9-9281-162a41ddb8df");
It's very straightforward if you have an Underscore.js dependency in your project -
_.omit(myArray, "lastname")
The only working method for me:
function removeItem (array, value) {
var i = 0;
while (i < array.length) {
if(array[i] === value) {
array.splice(i, 1);
} else {
++i;
}
}
return array;
}
Usage:
var new = removeItem( ["apple","banana", "orange"], "apple");
// ---> ["banana", "orange"]
For "Arrays":
If you know the index:
array.splice(index, 1);
If you know the value:
function removeItem(array, value) {
var index = array.indexOf(value);
if (index > -1) {
array.splice(index, 1);
}
return array;
}
The most upvoted answer for delete works well in case of objects but not for the real arrays. If I use delete it removes elements from loops but keeps the element as empty and length of array wont change. This may be a problem in some scenarios.
For example, if I do myArray.toString() on myArray after removal via delete, it creates an empty entry, i.e. ,,.
var myArray = newmyArray = new Object();
myArray["firstname"] = "Bob";
myArray["lastname"] = "Smith";
myArray["age"] = 25;
var s = JSON.stringify(myArray);
s.replace(/"lastname[^,}]+,/g, '');
newmyArray = JSON.parse(p);
Without looping/iterates we get the same result.