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Regex, separate by comma, javascript

My string:
AA,$,DESCRIPTION(Sink, clinical),$
Wanted matches:
AA
$
DESCRIPTION(Sink, clinical)
$
My regex sofar:
\+d|[\w$:0-9`<>=&;?\|\!\#\+\%\-\s\*\(\)\.ÅÄÖåäö]+
This gives
AA
$
DESCRIPTION(Sink
clinical)
I want to keep matches between ()
https://regex101.com/r/MqFUmk/3

Here's my attempt at the regex
\+d|[\w$:0-9`<>=&;?\|\!\#\+\%\-\s\*\.ÅÄÖåäö]+(\(.+\))?
I removed the parentheses from within the [ ] characters, and allowed capture elsewhere. It seems to satisfy the regex101 link you posted.
Depending on how arbitrary your input is, this regex might not be suitable for more complex strings.
Alternatively, here's an answer which could be more robust than mine, but may only work in Ruby.
((?>[^,(]+|(\((?>[^()]+|\g<-1>)*\)))+)

That one seems to work for me?
([^,\(\)]*(?:\([^\(\)]*\))?[^,\(\)]*)(?:,|$)
https://regex101.com/r/hLyJm5/2
Hope this helps!

Personally, I would first replace all commas within parentheses () with a character that will never occur (in my case I used # since I don't see it within your inclusions) and then I would split them by commas to keep it sweet and simple.
myStr = "AA,$,DESCRIPTION(Sink, clinical),$"; //Initial string
myStr = myStr.replace(/(\([^,]+),([^\)]+\))/g, "$1#$2"); //Replace , within parentheses with #
myArr = myStr.split(',').map(function(s) { return s.replace('#', ','); }); //Split string on ,
//myArr -> ["AA","$","DESCRIPTION(Sink, clinical)","$"]
optionally, if you're using ES6, you can change that last line to:
myArr = myStr.split(',').map(s => s.replace('#', ',')); //Yay Arrow Functions!
Note: If you have nested parentheses, this answer will need a modification

At last take an aproximation of what you need:
\w+(?:\(.*\))|\w+|\$
https://regex101.com/r/MqFUmk/4

match everything between brackets

I need to match the text between two brackets. many post are made about it but non are supported by JavaScript because they all use the lookbehind.
the text is as followed
"{Code} - {Description}"
I need Code and Description to be matched with out the brackets
the closest I have gotten is this
/{([\s\S]*?)(?=})/g
leaving me with "{Code" and "{Description" and I followed it with
doing a substring.
so... is there a way to do a lookbehind type of functionality in Javascript?

You could simply try the below regex,
[^}{]+(?=})
Code:
> "{Code} - {Description}".match(/[^}{}]+(?=})/g)
[ 'Code', 'Description' ]

Use it as:
input = '{Code} - {Description}';
matches = [], re = /{([\s\S]*?)(?=})/g;
while (match = re.exec(input)) matches.push(match[1]);
console.log(matches);
["Code", "Description"]

Actually, in this particular case, the solution is quite easy:
s = "{Code} - {Description}"
result = s.match(/[^{}]+(?=})/g) // ["Code", "Description"]

Have you tried something like this, which doesn't need a lookahead or lookbehind:
{([^}]*)}
You would probably need to add the global flag, but it seems to work in the regex tester.
The real problem is that you need to specify what you want to capture, which you do with capture groups in regular expressions. The part of the matched regular expression inside of parentheses will be the value returned by that capture group. So in order to omit { and } from the results, you just don't include those inside of the parentheses. It is still necessary to match them in your regular expression, however.
You can see how to get the value of capture groups in JavaScript here.

How to extract a particular text from url in JavaScript

I have a url like http://www.somedotcom.com/all/~childrens-day/pr?sid=all.
I want to extract childrens-day. How to get that? Right now I am doing it like this
url = "http://www.somedotcom.com/all/~childrens-day/pr?sid=all"
url.match('~.+\/');
But what I am getting is ["~childrens-day/"].
Is there a (definitely there would be) short and sweet way to get the above text without ["~ and /"] i.e just childrens-day.
Thanks

You could use a negated character class and a capture group ( ) and refer to capture group #1. The caret (^) inside of a character class [ ] is considered the negation operator.
var url = "http://www.somedotcom.com/all/~childrens-day/pr?sid=all";
var result = url.match(/~([^~]+)\//);
console.log(result[1]); // "childrens-day"
See Working demo
Note: If you have many url's inside of a string you may want to add the ? quantifier for a non greedy match.
var result = url.match(/~([^~]+?)\//);

Like so:
var url = "http://www.somedotcom.com/all/~childrens-day/pr?sid=all"
var matches = url.match(/~(.+?)\//);
console.log(matches[1]);
Working example: http://regex101.com/r/xU4nZ6
Note that your regular expression wasn't actually properly delimited either, not sure how you got the result you did.

Use non-capturing groups with a captured group then access the [1] element of the matches array:
(?:~)(.+)(?:/)
Keep in mind that you will need to escape your / if using it also as your RegEx delimiter.

Yes, it is.
url = "http://www.somedotcom.com/all/~childrens-day/pr?sid=all";
url.match('~(.+)\/')[1];
Just wrap what you need into parenteses group. No more modifications into your code is needed.
References: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/RegExp

You could just do a string replace.
url.replace('~', '');
url.replace('/', '');
http://www.w3schools.com/jsref/jsref_replace.asp

Javascript regex expression to replace multiple strings?

I've a string done like this: "http://something.org/dom/My_happy_dog_%28is%29cool!"
How can I remove all the initial domain, the multiple underscore and the percentage stuff?
For now I'm just doing some multiple replace, like
str = str.replace("http://something.org/dom/","");
str = str.replace("_%28"," ");
and go on, but it's really ugly.. any help?
Thanks!
EDIT:
the exact input would be "My happy dog is cool!" so I would like to get rid of the initial address and remove the underscores and percentage and put the spaces in the right place!
The problem is that trying to put a regex on Chrome "something goes wrong". Is it a problem of Chrome or my regex?

I'd suggest:
var str = "http://something.org/dom/My_happy_dog_%28is%29cool!";
str.substring(str.lastIndexOf('/')+1).replace(/(_)|(%\d{2,})/g,' ');
JS Fiddle demo.
The reason I took this approach is that RegEx is fairly expensive, and is often tricky to fine tune to the point where edge-cases become less troublesome; so I opted to use simple string manipulation to reduce the RegEx work.
Effectively the above creates a substring of the given str variable, from the index point of the lastIndexOf('/') (which does exactly what you'd expect) and adding 1 to that so the substring is from the point after the / not before it.
The regex: (_) matches the underscores, the | just serves as an or operator and the (%\d{2,}) serves to match digit characters that occur twice in succession and follow a % sign.
The parentheses surrounding each part of the regex around the |, serve to identify matching groups, which are used to identify what parts should be replaced by the ' ' (single-space) string in the second of the arguments passed to replace().
References:
lastIndexOf().
replace().
substring().

You can use unescape to decode the percentages:
str = unescape("http://something.org/dom/My_happy_dog_%28is%29cool!")
str = str.replace("http://something.org/dom/","");

Maybe you could use a regular expression to pull out what you need, rather than getting rid of what you don't want. What is it you are trying to keep?
You can also chain them together as in:
str.replace("http://something.org/dom/", "").replace("something else", "");

You haven't defined the problem very exactly. To get rid of all stretches of characters ending in %<digit><digit> you'd say
var re = /.*%\d\d/g;
var str = str.replace(re, "");

ok, if you want to replace all that stuff I think that you would need something like this:
/(http:\/\/.*\.[a-z]{3}\/.*\/)|(\%[a-z0-9][a-z0-9])|_/g
test
var string = "http://something.org/dom/My_happy_dog_%28is%29cool!";
string = string.replace(/(http:\/\/.*\.[a-z]{3}\/.*\/)|(\%[a-z0-9][a-z0-9])|_/g,"");

Match word in a string that does not end in ellipsis

Let's say I have the following string:
ZD:123123 ZD:213123 ZD:2e213 [ZD:213123] [ZD#221313] ZD:234...
I want to pattern match every occurrence except ZD:234... because I don't want any words that have an elipses.
This pattern was doing nicely for me in JavaScript:
/(\[|\(|)ZD[:#]\w+(\]|\)|)/g
However, it still captures the ZD:234 part of ZD:234... which I absolutely don't want it to do.
How can I prevent regex from doing this?

An easy fix is to use a negative lookahead:
/(\[|\(|)ZD[:#]\w+\b(\]|\)|)(?!\.\.\.)/g
Note that I've also added \b to avoid matching on ZD:23.
A bit simplified:
/[\[(]?ZD[:#]\w+\b[\])]?(?!\.\.\.)/g
In case you want matching brackets (no [ZD:123)):
/(?:ZD[:#]\w+|\[ZD[:#]\w+\]|\(ZD[:#]\w+\))\b(?!\.\.\.)/g

There is more than one way to skin a cat. The following will work in more browsers by using a simpler regular expression:
function trim(s) {
return s.replace(/^ | $/g,'').replace(/\s+/g,' ');
}
var x = 'ZD:123123 ZD:213123 ZD:2e213... [ZD:213123] [ZD#221313] ZD:234...';
alert(
trim(x.replace(/(^| )[^ ]+[\.]{3}( |$)/g,' ')).split(/\s+/)
);
/* shows: ZD:123123,ZD:213123,[ZD:213123],[ZD#221313] */
It removes any space delimited "word" of characters ending in ... and then splits on the space.