I find no doc for the sort modifier. The only insight is in the unit tests:
spec.lib.query.js#L12
writer.limit(5).sort(['test', 1]).group('name')
But it doesn't work for me:
Post.find().sort(['updatedAt', 1]);
In Mongoose, a sort can be done in any of the following ways:
Post.find({}).sort('test').exec(function(err, docs) { ... });
Post.find({}).sort([['date', -1]]).exec(function(err, docs) { ... });
Post.find({}).sort({test: 1}).exec(function(err, docs) { ... });
Post.find({}, null, {sort: {date: 1}}, function(err, docs) { ... });
This is how I got sort to work in mongoose 2.3.0 :)
// Find First 10 News Items
News.find({
deal_id:deal._id // Search Filters
},
['type','date_added'], // Columns to Return
{
skip:0, // Starting Row
limit:10, // Ending Row
sort:{
date_added: -1 //Sort by Date Added DESC
}
},
function(err,allNews){
socket.emit('news-load', allNews); // Do something with the array of 10 objects
})
As of Mongoose 3.8.x:
model.find({ ... }).sort({ field : criteria}).exec(function(err, model){ ... });
Where:
criteria can be asc, desc, ascending, descending, 1, or -1
Note: Use quotation marks or double quote
use "asc", "desc", "ascending", "descending", 1, or -1
UPDATE:
Post.find().sort({'updatedAt': -1}).all((posts) => {
// do something with the array of posts
});
Try:
Post.find().sort([['updatedAt', 'descending']]).all((posts) => {
// do something with the array of posts
});
Mongoose v5.x.x
sort by ascending order
Post.find({}).sort('field').exec(function(err, docs) { ... });
Post.find({}).sort({ field: 'asc' }).exec(function(err, docs) { ... });
Post.find({}).sort({ field: 'ascending' }).exec(function(err, docs) { ... });
Post.find({}).sort({ field: 1 }).exec(function(err, docs) { ... });
Post.find({}, null, {sort: { field : 'asc' }}), function(err, docs) { ... });
Post.find({}, null, {sort: { field : 'ascending' }}), function(err, docs) { ... });
Post.find({}, null, {sort: { field : 1 }}), function(err, docs) { ... });
sort by descending order
Post.find({}).sort('-field').exec(function(err, docs) { ... });
Post.find({}).sort({ field: 'desc' }).exec(function(err, docs) { ... });
Post.find({}).sort({ field: 'descending' }).exec(function(err, docs) { ... });
Post.find({}).sort({ field: -1 }).exec(function(err, docs) { ... });
Post.find({}, null, {sort: { field : 'desc' }}), function(err, docs) { ... });
Post.find({}, null, {sort: { field : 'descending' }}), function(err, docs) { ... });
Post.find({}, null, {sort: { field : -1 }}), function(err, docs) { ... });
For Details: https://mongoosejs.com/docs/api.html#query_Query-sort
Update
There is a better write up if this is confusing people; check out finding documents and how queries work in the mongoose manual. If you want to use the fluent api you can get a query object by not providing a callback to the find() method, otherwise you can specify the parameters as I outline below.
Original
Given a model object, per the docs on Model, this is how it can work for 2.4.1:
Post.find({search-spec}, [return field array], {options}, callback)
The search spec expects an object, but you can pass null or an empty object.
The second param is the field list as an array of strings, so you would supply ['field','field2'] or null.
The third param is the options as an object, which includes the ability to sort the result set. You would use { sort: { field: direction } } where field is the string fieldname test (in your case) and direction is a number where 1 is ascending and -1 is desceding.
The final param (callback) is the callback function which receives the collection of docs returned by the query.
The Model.find() implementation (at this version) does a sliding allocation of properties to handle optional params (which is what confused me!):
Model.find = function find (conditions, fields, options, callback) {
if ('function' == typeof conditions) {
callback = conditions;
conditions = {};
fields = null;
options = null;
} else if ('function' == typeof fields) {
callback = fields;
fields = null;
options = null;
} else if ('function' == typeof options) {
callback = options;
options = null;
}
var query = new Query(conditions, options).select(fields).bind(this, 'find');
if ('undefined' === typeof callback)
return query;
this._applyNamedScope(query);
return query.find(callback);
};
HTH
you can sort your query results by
Post.find().sort({createdAt: "descending"});
This is how I got sort to work in mongoose.js 2.0.4
var query = EmailModel.find({domain:"gmail.com"});
query.sort('priority', 1);
query.exec(function(error, docs){
//...
});
Chaining with the query builder interface in Mongoose 4.
// Build up a query using chaining syntax. Since no callback is passed this will create an instance of Query.
var query = Person.
find({ occupation: /host/ }).
where('name.last').equals('Ghost'). // find each Person with a last name matching 'Ghost'
where('age').gt(17).lt(66).
where('likes').in(['vaporizing', 'talking']).
limit(10).
sort('-occupation'). // sort by occupation in decreasing order
select('name occupation'); // selecting the `name` and `occupation` fields
// Excute the query at a later time.
query.exec(function (err, person) {
if (err) return handleError(err);
console.log('%s %s is a %s.', person.name.first, person.name.last, person.occupation) // Space Ghost is a talk show host
})
See the docs for more about queries.
app.get('/getting',function(req,res){
Blog.find({}).limit(4).skip(2).sort({age:-1}).then((resu)=>{
res.send(resu);
console.log(resu)
// console.log(result)
})
})
Output
[ { _id: 5c2eec3b8d6e5c20ed2f040e, name: 'e', age: 5, __v: 0 },
{ _id: 5c2eec0c8d6e5c20ed2f040d, name: 'd', age: 4, __v: 0 },
{ _id: 5c2eec048d6e5c20ed2f040c, name: 'c', age: 3, __v: 0 },
{ _id: 5c2eebf48d6e5c20ed2f040b, name: 'b', age: 2, __v: 0 } ]
with the current version of mongoose (1.6.0) if you only want to sort by one column, you have to drop the array and pass the object directly to the sort() function:
Content.find().sort('created', 'descending').execFind( ... );
took me some time, to get this right :(
This is how I managed to sort and populate:
Model.find()
.sort('date', -1)
.populate('authors')
.exec(function(err, docs) {
// code here
})
Post.find().sort({updatedAt: 1});
As of October 2020, to fix your issue you should add .exec() to the call. don't forget that if you want to use this data outside of the call you should run something like this inside of an async function.
let post = await callQuery();
async function callQuery() {
return Post.find().sort(['updatedAt', 1].exec();
}
Others worked for me, but this did:
Tag.find().sort('name', 1).run(onComplete);
Post.find().sort({updatedAt:1}).exec(function (err, posts){
...
});
Starting from 4.x the sort methods have been changed. If you are using >4.x. Try using any of the following.
Post.find({}).sort('-date').exec(function(err, docs) { ... });
Post.find({}).sort({date: -1}).exec(function(err, docs) { ... });
Post.find({}).sort({date: 'desc'}).exec(function(err, docs) { ... });
Post.find({}).sort({date: 'descending'}).exec(function(err, docs) { ... });
Post.find({}).sort([['date', -1]]).exec(function(err, docs) { ... });
Post.find({}, null, {sort: '-date'}, function(err, docs) { ... });
Post.find({}, null, {sort: {date: -1}}, function(err, docs) { ... });
This is what i did, it works fine.
User.find({name:'Thava'}, null, {sort: { name : 1 }})
// Ascending with updatedAt field
Post.find().sort('updatedAt').exec((err, post) => {...});
// Descending with updatedAt field
Post.find().sort('-updatedAt').exec((err, post) => {...});
Refer here: https://mongoosejs.com/docs/queries.html
you can also use aggregate() for sorting
const sortBy = req.params.sort;
const limitNum = req.params.limit;
const posts = await Post.aggregate([
{ $unset: ['field-1', 'field-2', 'field-3', 'field-4'] },
{ $match: { field-1: value} },
{ $sort: { [sortBy]: -1 } }, //-------------------> sort the result
{ $limit: Number(limitNum) },
]);
Solution :
posts.find().sort({field:1})
// for ascending and for descending order just use -1 instead of 1
Related
This is my Operator Models:
const operatorSchema = new Schema({
operatorName: {
type: String
},
users:[{
email:String,
payment:Number,
paymentsData: Date,
product: String,
}],
});
I need to filter by operatorName and email in users block. But when I try with this I get all users in related OperatorName how can I query correctly ?
Operators.find( { $and: [{operatorName: operatorName}, {'users.email': 'super#m.com'}]}, function (err, docs) {
) {
if (err) console.log(err)
else {
docs.forEach(function(data){
console.log(data)
})
// res.render('total_earns_operator_tables', { operators: docs });
}
});
EDIT
I also try with aggregate method like this but again, I get same result and I gel all bunch of user data, but I want only demouser#mail.com
Operators.aggregate([
{ $match: {$and: [{ operatorName: operatorName},{'users.email':
'demouser#mail.com' }]}},
]
,function (err, docs) {
// console.log(Operators)
// Operators.find( { $and: [{operatorName: operatorName}, {users: {$elemMatch: {email:['super#m.com']}}}]}, function (err, docs) {
// Operators.find( {operatorName: operatorName, "users.email": "demouser#mail.com"}, function (err, docs) {
if (err) console.log(err)
else {
docs.forEach(function(data){
console.log(data)
})
// res.render('total_earns_operator_tables', { operators: docs });
}
});
It is very basic but I couldnt find solution.
Your query is doing exactly what it is supposed to do. It is returning all documents that satisfy you two criteria: 1. having a specified operatorName and 2. users array having at least one user matching the specified email.
If you want to reashape your documents by filtering the user array to only include the user matching your condition, you'll have to use an aggregation.
EDIT
As per your edit: Your aggregation only have a $match stage, which is identical to your query above. To change the shape of a document, the aggregation framework provides you with the $project stage, see the example below:
Operators.aggregate([
{
$match: {
operatorName: operatorName,
"users.email": "demouser#mail.com"
}
},
{
$project: {
operatorName: '$operatorName',
users: {
$filter: {
input: "$users",
as: "user",
cond: {
$eq: [
"$$user.email",
"demouser#mail.com"
]
}
}
}
}
}
]
Here, we first filter the collection to get only the documents you want, using the $match stage, then we use the $filteroperator in $project stage, to return only the matching users within the array.
See the working playground
i have a collection which i would like to update all of it's documents according to field email and convert it to lower case.
const addressBookSchema = new Schema({
email: String,
});
const addressBook = mongoose.model("address_book", addressBookSchema)
i'm trying to do the following:
addressBook.update({}, {$set: {email: email.toLowerCase()}}, {multi: true});
But that doesn't work.
how do i get the email field and set it to lowercase?
By the below method you are able to update multiple document with lower case aggregate function.
db.addressBook.updateMany(
{},
[{$set : {email :{ $toLower: "$email" } }}],
)
For doing it on all documents,
addressBook.find({}, {email: 1})
.exec((err, docs) => {
if (err || docs == undefined || docs.length == 0)
;
else {
docs.forEach((doc) => {
addressBook.findOneAndUpdate({_id: doc._id},
{$set: {email: doc.email.lowercase()}})
.exec();
});
}
});
If you have such a large dataset, you should use the bulkWrite() function
addressBook.bulkWrite([
{
updateMany: {
filter: {},
update: { email: email.lowercase()}
}
},
]).then(handleResult);
I'm trying to update an array in document by adding object if it doesn't exist, and replacing the object in array otherwise. But nothing ($push, $addToSet) except the $set parameter does anything, and $set works as expected - overwrites the whole array.
My mongoose schema:
var cartSchema = mongoose.Schema({
mail: String,
items: Array
});
The post request handler:
app.post('/addToCart', function(req, res) {
var request = req.body;
Cart.findOneAndUpdate({
"mail": request.mail
}, {
$addToSet: {
"items": request.item
}
}, {
upsert: true
},
function(err, result) {
console.log(result);
}
);
res.send(true);
});
The data that I'm sending from the client:
{
"mail":"test#gmail.com",
"item":{
"_id":"59da78db7e9e0433280578ec",
"manufacturer":"Schecter",
"referenceNo":"Daemon-412",
"type":"Gitare",
"image":"images/ba9727909d6c3c26412341907e7e12041507489988265.jpeg",
"__v":0,
"subcategories":[
"Elektricne"
]
}
}
EDIT:
I also get this log when I trigger 'addToCart' request:
{ MongoError: The field 'items' must be an array but is of type object in
document {_id: ObjectId('5a19ae2884d236048c8c91e2')}
The comparison in $addToSet would succeeded only if the existing document has the exact same fields and values, and the fields are in the same order. Otherwise the operator will fail.
So in your case, request.item always need to be exactly the same.
I would recommend creating a model of "item". Then, your cart schema would be like:
var cartSchema = mongoose.Schema({
mail: String,
items: [{
type: ObjectId,
ref: 'item',
}],
});
And let MongoDB determine if the item exist.
this should work you just need to implement objectExits function that test if the item is that one you're looking for :
Cart.findOne({ "mail": request.mail })
.exec()
.then(cart => {
var replaced = cart.items.some((item, i) => {
if (item._id == request.item._id)) {
cart.items[i] = request.item;
return true;
}
})
if (!replaced) {
cart.items.push(request.item);
}
cart.save();
return cart;
})
.catch(err => {
console.log(err)
});
i am trying to toggle a boolean value inside a object, which is a subdocument, i am having hard time to update a particular object within an array.
Document:
"_id" : ObjectId("54afaabd88694dc019d3b628")
"Invitation" : [
{
"__v" : 0,
"ID" : ObjectId("54af6ce091324fd00f97a15f"),
"__t" : "USER",
"_id" : ObjectId("54b4ceb50fc380001bea1752"),
"Accepted" : false
},
{
"__v" : 0,
"ID" : ObjectId("54afac5412f5fdcc007a5c4d"),
"__t" : "USER",
"_id" : ObjectId("54b4cebe0fc380001bea1753"),
"Accepted" : false
}
],
Controller:
User.aggregate([{$match: {_id: ObjectId(54afaabd88694dc019d3b628)}},{$unwind: '$Invitation'},{$project: {_id: '$_id',Invitation: '$Invitation'}}],function(err,results){
function updateInvitation(_id){
var query = {'_id': _id, 'Invitation.ID': ObjectId("54af6ce091324fd00f97a15f")};
var operator = {$inc: {'Invitation.Accepted': 1}};
User.update(query,operator,{multi:true},function(err,updated){
if(err){
console.log(err);
}
console.log('updating'+updated);
});
}
res.jsonp(results);
updateInvitation(results[0]._id);
});
i tried using $set but it didnt worked out as whole Invitation array got replaced with 'Accepted = 1'
How can i toggle 'Accepted' field of the document with particular 'ID'.
Invitation.$.Accepted
Positional operator doesnot apply to field containing array so can't iterate to Accepted field
EDIT:
User.find({_id: req.user._id},'Invitation',function(err,docs){
if(err){
console.log(err);
}
console.log(docs);
var results = [];
async.each(docs,function(doc,err) {
if(err){
console.log('error'+ err);
}
async.each(docs.Invitation,function(invite,callback) {
console.log('second async');
User.update(
{ '_id': doc._id, 'Invitation._id': invite._id },
{ '$set': {'Invitation.$.Accepted': !invite.Accepted}},
function(err,doc) {
results.push(doc);
console.log('updated'+doc);
callback(err);
}
);
});
},function(err) {
if (err)
console.log(err);
console.log(results);
});
});
The control is not getting inside second async.each, error is thrown on first async here is the error:
error-function () {
if (called) throw new Error("Callback was already called.");
called = true;
fn.apply(root, arguments);
}
I really don't think that even as a feeder query the aggregation framework is the right operation to use here. All you are doing is "denormalizing" the array as individual documents. There really should be no need. Just fetch the document instead:
var query = {}; // whatever criteria
Users.find(query,"Invitation",function(err,docs) {
if (err) {
console.log(err);
var results = [];
async.each(docs,function(doc,callback) {
async.each(docs.Invitation,function(invite,callback) {
Users.findOneAndUpdate(
{ "_id": doc._id, "Invitation._id": invite._id },
{ "$set": { "Invitation.$.Accepted": !invite.Accepted } },
function(err,doc) {
results.push( doc );
callback(err);
}
);
},callback);
},function(err) {
if (err)
console.log(err);
console.log(results);
});
});
So there is no problem iterating the list of documents in a response for what you are doing, it's just that you also want to iterate the array members as well. The catch is when issuing any kind of .update() that you need to be aware then the asynchronous call is complete.
So I'm using async.each but you probably want async.eachLimit to control the looping. The matching of the element comes from the positional $ operator, corresponding to the matched array element in the query.
It's just JavaScript code, so simply "toggle" the value with !invite.accepted which will inverse it. For additional fun, return the "results" array by pushing the modified document from .findOneAndUpdate().
Use the positional update operator for this:
http://docs.mongodb.org/manual/reference/operator/update/positional/
User.update(
{
"_id": ObjectId("54afaabd88694dc019d3b628"),
"Invitation": {"$elemMatch": {"ID" : ObjectId("54af6ce091324fd00f97a15f"), "Accepted":false}}
},
{
"$set" : {
"Invitation.$.Accepted" : true
}
},{multi:false, upsert:false, safe:true}, function (err, numAffectedDocuments){
// TODO
}
);
Note : you don't need the aggregation step since it actually does nothing.
Basic problem
I have a bunch of records and I need to get latest (most recent) and the oldest (least recent).
When googling I found this topic where I saw a couple of queries:
// option 1
Tweet.findOne({}, [], { $orderby : { 'created_at' : -1 } }, function(err, post) {
console.log( post );
});
// option 2
Tweet.find({}, [], {sort:[['arrival',-1]]}, function(err, post) {
console.log( post );
});
Unfortunatly they both error:
TypeError: Invalid select() argument. Must be a string or object.
The link also has this one:
Tweet.find().sort('_id','descending').limit(15).find(function(err, post) {
console.log( post );
});
and that one errors:
TypeError: Invalid sort() argument. Must be a string or object.
So how can I get those records?
Timespan
Even more ideally I just want the difference in time (seconds?) between the oldest and the newest record, but I have no clue on how to start making a query like that.
This is the schema:
var Tweet = new Schema({
body: String
, fid: { type: String, index: { unique: true } }
, username: { type: String, index: true }
, userid: Number
, created_at: Date
, source: String
});
I'm pretty sure I have the most recent version of mongoDB and mongoose.
EDIT
This is how I calc the timespan based on the answer provided by JohnnyHK:
var calcDays = function( cb ) {
var getOldest = function( cb ) {
Tweet.findOne({}, {}, { sort: { 'created_at' : 1 } }, function(err, post) {
cb( null, post.created_at.getTime() );
});
}
, getNewest = function( cb ) {
Tweet.findOne({}, {}, { sort: { 'created_at' : -1 } }, function(err, post) {
cb( null, post.created_at.getTime() );
});
}
async.parallel({
oldest: getOldest
, newest: getNewest
}
, function( err, results ) {
var days = ( results.newest - results.oldest ) / 1000 / 60 / 60 / 24;
// days = Math.round( days );
cb( null, days );
}
);
}
Mongoose 3.x is complaining about the [] parameter in your findOne calls as the array format is no longer supported for the parameter that selects the fields to include.
Try this instead to find the newest:
Tweet.findOne({}, {}, { sort: { 'created_at' : -1 } }, function(err, post) {
console.log( post );
});
Change the -1 to a 1 to find the oldest.
But because you're not using any field selection, it's somewhat cleaner to chain a couple calls together:
Tweet.findOne().sort({created_at: -1}).exec(function(err, post) { ... });
Or even pass a string to sort:
Tweet.findOne().sort('-created_at').exec(function(err, post) { ... });
Fast and Simple - One Line Solution
Get 10 latest documents
MySchema.find().sort({ _id: -1 }).limit(10)
Get 10 oldest documents
MySchema.find().sort({ _id: 1 }).limit(10)
In case you want sorting based on some other property i.e. createdAt and get the oldest or latest. It is similar to the above query.
MySchema.find().sort({ createdAt: -1 }).limit(10) // 10 latest docs
MySchema.find().sort({ createdAt: 1 }).limit(10) // 10 oldest docs
for version ~3.8 mongoose
to find the last entry
model.findOne().sort({ field: 'asc', _id: -1 }).limit(1)
or using
model.findOne().sort({ field: -_id }).limit(1)
collectionName.findOne().sort({$natural: -1}).limit(1).exec(function(err, res){
if(err){
console.log(err);
}
else{
console.log(res);
}
}
This will give you the last document recorded on the database. Just follow the same concept.
await Model.find().sort({$natural:-1}).limit(1); //for the latest record
await Model.find().sort({$natural:1}).limit(1); //for the oldest record
This one works for me. using mongodb natural order https://docs.mongodb.com/manual/reference/operator/meta/natural/
We have method called sort using that we can able to get first element(old document) which means 1 for sort field or last element(new document) which means -1 for sort field of collection.
The best way is to have an async function like that:
async function findLastElement () {
return await Mymodel.findOne().sort('-_id');
}
this way you get the last element and you ensure reusability.
Here is the answer with async - await
const olderDoc: any = await Model.findOne().sort({ createdAt: 1 }).lean().exec()
console.log('olderDoc', olderDoc)
const newerDoc: any = await Model.findOne().sort({ createdAt: -1 }).lean().exec()
console.log('newerDoc', newerDoc)