Can this be done using javascript?
If you're trying to find out if more than one element share one id, with jQuery you could do $('[id=blah]').length - that will return a count of all elements where the id is equal to 'blah'. See the fiddle. If it's greater than 1 then you have a duplicate id.
Edit: I've tested this in Chrome, FF and IE6, and all of them show that there are two elements with the same id. I agree that it's really bad form to have more than one element share an id, but this code does work.
Maybe (if I understand the question)
if (document.getElementById('theId')) {
}
Also, in order to print all duplicates:
var elems = document.getElementsByTagName('*');
var num = elems.length;
var ids = [ ];
for(i=0; i<num; i++ ) {
var id = elems[i].getAttribute('id');
if(id != null) {
if(ids.indexOf(id) >=0 ) {
console.debug(id); // found in table
} else {
ids.push(id); // new id found, add it to array
}
}
}
if(!document.getElementById('search')) { return; }
Yes it is.
iterate thru document.getElementsByTagName('*'), use element.getAttribute('id')
Related
This should work but its not. What am I doing wrong? I want to output "selected" to tags I have on a meteor page
Template.editor.onRendered( function() {
var cats = ["Comedy","Action","Self Help"];
var arrayLength = cats.length;
for (var i = 0; i < arrayLength; i++) {
if(cats[i].indexOf(getDocument.category) != -1){
//found
var id = cats[i].trim().toLowerCase();
$("body").find("#"+id).attr("selected=selected");
console.log(id);
} else {
console.log(getDocument.category)
}
}
}
also
getDocument.category = ["Action", "Comedy"]
Maybe change
$("body").find("#"+id).attr("selected=selected");
with
$("body").find("#"+id).attr("selected","selected");
Edit:
if(cats[i].indexOf(getDocument.category) != -1){
I think you have here a wrong direction
try this instead:
if(getDocument.category.indexOf(cats[i]) != -1){
If I do not mistakenly understand what you asking for, you are trying to find the elements of 'cats' array if exist in the getDocument.category. If so, the above approach is wrong. Take a look at this line:
if(cats[i].indexOf(getDocument.category) != -1){...}
the result of this if checking will always returning -1, the explanation is below:
cats[i] will return the element (with index i) of cats, so if i=0 the result will be "Comedy". Then, indexOf will be executed on it, "Comedy".indexOf() ,
to find the position of getDocument.category (which is an array).
That's means you are looking for an array inside a string? that's will not work.
Actually, we can check if an element exists in array with includes methods. So maybe the complete code will be looked like this:
Template.editor.onRendered(function() {
var cats = ["Comedy", "Action", "Self Help"];
var arrayLength = cats.length;
for (var i = 0; i < arrayLength; i++) {
if (getDocument.category.includes(cats[0])) {
//found
var id = cats[i].trim().toLowerCase();
$("body").find("#" + id).attr("selected=selected");
console.log(id);
} else {
console.log(getDocument.category)
}
}
})
Hope this will help, thanks
You need to change a line to set selected attribute
$("body").find("#"+id).attr("selected","selected");
Or try the following:
$(document).find("#"+id).attr("selected","selected");
I have a few different tables on the same page but unfortunately they were not assigned any unique id's. I want to remove a table using a JS command, but since id cannot be used, is it possible to delete a table based on a certain attribute it has? For example, is there a command to delete all tables on the page that have the attribute: width="25%" ?
You can use querySelectorAll to do that.
var x = document.querySelectorAll("table[width='25%']");
for (var i=0; i<x.length; i++) { //returns array of elements that match the attribute selector
x[i].remove(); //call prototype method defined below
}
Removing is tricky, I found this code that makes a nice remove method
Element.prototype.remove = function() {
this.parentElement.removeChild(this);
}
NodeList.prototype.remove = HTMLCollection.prototype.remove = function() {
for(var i = 0, len = this.length; i < len; i++) {
if(this[i] && this[i].parentElement) {
this[i].parentElement.removeChild(this[i]);
}
}
}
This creates a prototype remove() function that iterates the node and deletes the children.
Please note that querySelectorAll will not work in IE8 or below, but the poster of the prototype method said that it should work in IE8 but not 7.
I know this already has some solutions, but I'll offer up one more alternative.
var tables = document.getElementsByTagName('table');
for(var i = 0; i < tables.length; i++){
if(tables[i].getAttribute('width') == "25%"){
tables[i].parentNode.removeChild(tables[i]);
}
}
Demo at http://codepen.io/michaelehead/pen/HfdKx.
Yes you can. The easiest way is to use JQuery.
In your javascript code you would just write:
$("[attribute=value]").remove()
So in your case it could be something like $("table[width='25%']").remove()
the problem is I have a list with contacts and when someone change his/her status I try to move them to the top of the list. Everything worked till now, with IE9, and Firefox 4 is not working. I show you the code:
function sortByStatus()
{
var divs = getElementsByClassName(document,"status_sort");
divs.sort(compare);
for (var i = 0; i < divs.length; i++)
{
$("#contact_info").append(divs[i]);
}
}
function compare(div1, div2)
{
var id1 = div1.getAttribute("id");
var id2 = div2.getAttribute("id");
if (id1 > id2)
return 1;
else if (id1 < id2)
return -1;
else
return 0;
}
Any idea or possible fix? Thank you.
update
I have tried MrBuuBuu solution and it works patially, because now the sort by status works but the alphabetic sort is not working. I had to change part of MrBuuBuu solution, the compare function, because I compare the name of the contacts with a number just before the name that represent the status (ex. 2John , 2 means offline, and 1 online) so I have to compare with '<' and '>' and return 1, -1 or 0.
But what is worst, now it doesn't work with IE7 or IE8... the sort by status is not working.
Really weird, any idea?
document.getElementsByClassName returns a NodeList, not an array. So you have to convert it to an array first. I also cleaned up your compare() function.
function compare(div1, div2)
{
var id1 = div1.id;
var id2 = div2.id;
if (id1 < id2) {
return - 1;
}
if (id1 == id2) {
return 0;
}
return 1;
}
function sortByStatus()
{
var divs = document.getElementsByClassName("status_sort");
var divArray = $.map(divs, function(div) { return div; });
divArray.sort(compare);
$.each(divArray, function(i, div){
$("#contact_info").append(div);
});
}
If you're using the browser's native getElementsByClassName function, you may be ending up with a DOM node collection that is not a sortable Array.
When you say it's not working, are you getting any errors or is it just that the array doesn't get sorted? I'm assuming you're getting an error because sort in not defined.
One thing you could try is to clone the node collection to a plain JavaScript Array before sorting:
divs = [].slice.call(divs);
divs.sort(...
I don't have IE9 to test this, but with Chrome:
// undefined
document.getElementsByClassName("someclass").sort
But:
// the sort function
[].slice.call(document.getElementsByClassName("someclass")).sort
Are you sure it has been working? There's no such function as getElementsByClassName in the global scope.
Try using document.getElementsByClassName("status_sort") instead.
I have been working on creating a custom script to help manage a secret questions form for a login page. I am trying to make all the seperate select lists dynamic, in that if a user selects a question in one, it will no longer be an option in the rest, and so on. Anyways, the problem I am having is when I try to set the variables in the other lists to null. I am currently working with only 3 lists, so I look at one list, and find/delete matches in the other 2 lists. Here is my loop for deleting any matches.
for(i=0; i<array1.length; i++) {
if(array2[i].value == txtbox1.value) {
document.questions.questions2.options[i] = null
}
if(array3[i].value == txtbox1.value) {
document.questions.questions3.options[i] = null
}
}
This works fine if both the matches are located at the same value/position in the array. But if one match is at array1[1] and the other match is at array3[7] for example, then only the first match gets deleted and not the second. Is there something I am missing? Any help is appreciated. Thanks!
I don't see too many choices here, considering that the position in each array can vary.
Do it in separate loops, unless of course you repeat values in both arrays and share the same position
EDTI I figured out a simple solution, it may work, create a function. How about a function wich recives an array as parameter.
Something like this:
function finder(var array[], var valueToFound, var question) {
for (i=0; i<array.lenght; i++) {
if (array[i].value == valueToFound) {
switch (question) {
case 1: document.questions.questions1.options[i] = null;
break;
}
return;
}
}
}
I think i make my point, perhaps it can take you in the right direction
My bet is that the code isn't getting to array3[7] because either it doesn't exist or that array2 is too short and you're getting a JavaScript exception that's stopping the code from doing the check. Is it possible that array2 and array3 are shorter than array1?
It is more code, but I would do it like this:
var selectedvalue == txtbox1.value;
for(i=0; i<array2.length; i++) { // iterate over the length of array2, not array1
if(array2[i].value == selectedvalue) {
document.questions.questions2.options[i] = null;
break; // found it, move on
}
}
for(i=0; i<array3.length; i++) {
if(array3[i].value == selectedvalue) {
document.questions.questions3.options[i] = null;
break; // you're done
}
}
I'm trying to loop over ALL elements on a page, so I want to check every element that exists on this page for a special class.
So, how do I say that I want to check EVERY element?
You can pass a * to getElementsByTagName() so that it will return all elements in a page:
var all = document.getElementsByTagName("*");
for (var i=0, max=all.length; i < max; i++) {
// Do something with the element here
}
Note that you could use querySelectorAll(), if it's available (IE9+, CSS in IE8), to just find elements with a particular class.
if (document.querySelectorAll)
var clsElements = document.querySelectorAll(".mySpeshalClass");
else
// loop through all elements instead
This would certainly speed up matters for modern browsers.
Browsers now support foreach on NodeList. This means you can directly loop the elements instead of writing your own for loop.
document.querySelectorAll('*').forEach(function(node) {
// Do whatever you want with the node object.
});
Performance note - Do your best to scope what you're looking for by using a specific selector. A universal selector can return lots of nodes depending on the complexity of the page. Also, consider using document.body.querySelectorAll instead of document.querySelectorAll when you don’t care about <head> children.
Was looking for same. Well, not exactly. I only wanted to list all DOM Nodes.
var currentNode,
ni = document.createNodeIterator(document.documentElement, NodeFilter.SHOW_ELEMENT);
while(currentNode = ni.nextNode()) {
console.log(currentNode.nodeName);
}
To get elements with a specific class, we can use filter function.
var currentNode,
ni = document.createNodeIterator(
document.documentElement,
NodeFilter.SHOW_ELEMENT,
function(node){
return node.classList.contains('toggleable') ? NodeFilter.FILTER_ACCEPT : NodeFilter.FILTER_REJECT;
}
);
while(currentNode = ni.nextNode()) {
console.log(currentNode.nodeName);
}
Found solution on
MDN
As always the best solution is to use recursion:
loop(document);
function loop(node){
// do some thing with the node here
var nodes = node.childNodes;
for (var i = 0; i <nodes.length; i++){
if(!nodes[i]){
continue;
}
if(nodes[i].childNodes.length > 0){
loop(nodes[i]);
}
}
}
Unlike other suggestions, this solution does not require you to create an array for all the nodes, so its more light on the memory. More importantly, it finds more results. I am not sure what those results are, but when testing on chrome it finds about 50% more nodes compared to document.getElementsByTagName("*");
Here is another example on how you can loop through a document or an element:
function getNodeList(elem){
var l=new Array(elem),c=1,ret=new Array();
//This first loop will loop until the count var is stable//
for(var r=0;r<c;r++){
//This loop will loop thru the child element list//
for(var z=0;z<l[r].childNodes.length;z++){
//Push the element to the return array.
ret.push(l[r].childNodes[z]);
if(l[r].childNodes[z].childNodes[0]){
l.push(l[r].childNodes[z]);c++;
}//IF
}//FOR
}//FOR
return ret;
}
For those who are using Jquery
$("*").each(function(i,e){console.log(i+' '+e)});
Andy E. gave a good answer.
I would add, if you feel to select all the childs in some special selector (this need happened to me recently), you can apply the method "getElementsByTagName()" on any DOM object you want.
For an example, I needed to just parse "visual" part of the web page, so I just made this
var visualDomElts = document.body.getElementsByTagName('*');
This will never take in consideration the head part.
from this link
javascript reference
<html>
<head>
<title>A Simple Page</title>
<script language="JavaScript">
<!--
function findhead1()
{
var tag, tags;
// or you can use var allElem=document.all; and loop on it
tags = "The tags in the page are:"
for(i = 0; i < document.all.length; i++)
{
tag = document.all(i).tagName;
tags = tags + "\r" + tag;
}
document.write(tags);
}
// -->
</script>
</head>
<body onload="findhead1()">
<h1>Heading One</h1>
</body>
</html>
UPDATE:EDIT
since my last answer i found better simpler solution
function search(tableEvent)
{
clearResults()
document.getElementById('loading').style.display = 'block';
var params = 'formAction=SearchStocks';
var elemArray = document.mainForm.elements;
for (var i = 0; i < elemArray.length;i++)
{
var element = elemArray[i];
var elementName= element.name;
if(elementName=='formAction')
continue;
params += '&' + elementName+'='+ encodeURIComponent(element.value);
}
params += '&tableEvent=' + tableEvent;
createXmlHttpObject();
sendRequestPost(http_request,'Controller',false,params);
prepareUpdateTableContents();//function js to handle the response out of scope for this question
}
Getting all elements using var all = document.getElementsByTagName("*"); for (var i=0, max=all.length; i < max; i++); is ok if you need to check every element but will result in checking or looping repeating elements or text.
Below is a recursion implementation that checks or loop each element of all DOM elements only once and append:
(Credits to #George Reith for his recursion answer here: Map HTML to JSON)
function mapDOMCheck(html_string, json) {
treeObject = {}
dom = new jsdom.JSDOM(html_string) // use jsdom because DOMParser does not provide client-side Window for element access
document = dom.window.document
element = document.querySelector('html')
// Recurse and loop through DOM elements only once
function treeHTML(element, object) {
var nodeList = element.childNodes;
if (nodeList != null) {
if (nodeList.length) {
object[element.nodeName] = []; // IMPT: empty [] array for parent node to push non-text recursivable elements (see below)
for (var i = 0; i < nodeList.length; i++) {
console.log("nodeName", nodeList[i].nodeName);
if (nodeList[i].nodeType == 3) { // if child node is **final base-case** text node
console.log("nodeValue", nodeList[i].nodeValue);
} else { // else
object[element.nodeName].push({}); // push {} into empty [] array where {} for recursivable elements
treeHTML(nodeList[i], object[element.nodeName][object[element.nodeName].length - 1]);
}
}
}
}
}
treeHTML(element, treeObject);
}
Use *
var allElem = document.getElementsByTagName("*");
for (var i = 0; i < allElem.length; i++) {
// Do something with all element here
}
i think this is really quick
document.querySelectorAll('body,body *').forEach(function(e) {
You can try with
document.getElementsByClassName('special_class');