Okay I have a simple Javascript problem, and I hope some of you are eager to help me. I realize it's not very difficult but I've been working whole day and just can't get my head around it.
Here it goes: I have a sentence in a Textfield form and I need to reprint the content of a sentence but WITHOUT spaces.
For example: "My name is Slavisha" The result: "MynameisSlavisha"
Thank you
You can replace all whitespace characters:
var str = "My name is Slavisha" ;
str = str.replace(/\s+/g, ""); // "MynameisSlavisha"
The /\s+/g regex will match any whitespace character, the g flag is necessary to replace all the occurrences on your string.
Also, as you can see, we need to reassign the str variable because Strings are immutable -they can't really change-.
Another way to do it:
var str = 'My name is Slavisha'.split(' ').join('');
Related
I'm trying to replace everything between special characters of a string in Javascript.
var text = "Hello,\n>> Someone lalalala\nMore Text\n<<";
I've tried the following code:
var newText = text.replace(/>>.*<</, ">>Some other text<<");
But at the end it actually returns the text variable.
I'd appreciate some thoughts about this. Thanks.
Regexes are "greedy", meaning they'll try to match the longest substring possible. Since .* means literally any character, it's going to include your delimiter << as well. Thus, .* reaches all the way to the end of your string, and then it can't find << after that, so the match will fail. You have to exclude it in your expression:
text.replace(/>>[^<]*<</, ">>Some other text<<");
The problem is that '.' does not match new lines. Using this answer:
var text = "Hello,\n>> Someone lalalala\nMore Text\n<<";
var newText = text.replace(/>>[\s\S]*<</m, ">>Some other text<<");
console.log(newText);
I'm trying to fix some typos and one common one is a space missing betweens sentences: "This is a sentence.Here is another sentence." I want to match and add a space so I wrote this regular expression:
var re = /\.(?=[A-Z]|\()/g;
var res = str.replace(re, '. ');
That covers the squished together sentences, as well as another typo involving parenthesis which is not important for this question.
The problem is that there are acronyms that show up, which are also matched and (incorrectly) replace. Example: "The U.S. is a country" is replaced to "The U. S. is a country". I'm trying to prevent these acronyms from being matched. I think maybe what I want is a "lookbehind", but javascript doesn't support that.
Any idea how to solve this?
You could try:
\.(?=[A-Z]|\()(?![A-Z]\.)
This ensures the proceeding characters after the "." do not include a capital letter followed by a "."
This seems to work:
var str = "A sentance.Another sentance with an A.C.R.O.N.Y.M.Yet another sentence."
var re = /\.(?=[A-Z][^.]|\()/g;
var res = str.replace(re, '. ');
res // => "A sentance. Another sentance with an A.C.R.O.N.Y.M. Yet another sentence."
I'm trying to match characters before and after a symbol, in a string.
string: budgets-closed
To match the characters before the sign -, I do: ^[a-z]+
And to match the other characters, I try: \-(\w+) but, the problem is that my result is: -closed instead of closed.
Any ideas, how to fix it?
Update
This is the piece of code, where I was trying to apply the regex http://jsfiddle.net/trDFh/1/
I repeat: It's not that I don't want to use split; it's just I was really curious, and wanted to see, how can it be done the regex way. Hacking into things spirit
Update2
Well, using substring is a solution as well: http://jsfiddle.net/trDFh/2/ and is the one I chosed to use, since the if in question, is actually an else if in a more complex if syntax, and the chosen solutions seems to be the most fitted for now.
Use exec():
var result=/([^-]+)-([^-]+)/.exec(string);
result is an array, with result[1] being the first captured string and result[2] being the second captured string.
Live demo: http://jsfiddle.net/Pqntk/
I think you'll have to match that. You can use grouping to get what you need, though.
var str = 'budgets-closed';
var matches = str.match( /([a-z]+)-([a-z]+)/ );
var before = matches[1];
var after = matches[2];
For that specific string, you could also use
var str = 'budgets-closed';
var before = str.match( /^\b[a-z]+/ )[0];
var after = str.match( /\b[a-z]+$/ )[0];
I'm sure there are better ways, but the above methods do work.
If the symbol is specifically -, then this should work:
\b([^-]+)-([^-]+)\b
You match a boundry, any "not -" characters, a - and then more "not -" characters until the next word boundry.
Also, there is no need to escape a hyphen, it only holds special properties when between two other characters inside a character class.
edit: And here is a jsfiddle that demonstrates it does work.
I have the below String value to be displayed in text area and i want to remove the first characters ##*n|n from the string .
The string is as follows :
Symbol-001
##*n|nClaimant Name
##*n|nTransaction
I have used the below code to deal with removing the special characters
var paramVal1 = parent.noteText; //paramVal1 will have the string now
var pattern = /[##*n|n]/g;
var paramVal1 = paramVal1.replace(pattern,'');
document.getElementById("txtNoteArea").value = paramval1;//appending the refined string to text area
For the above used code am getting the out put string as below
Symbol-001
|Claimat Name //here 'n' is missing and i have an extra '|' character
|Transactio //'n' is missing here too and an extra '|' character
Kindly help to remove the characters ##*n|n without affecting the other values
What your regex is saying is "remove any of the following characters: #|*n". Clearly this isn't what you want!
Try this instead: /##\*n\|n/g
This says "remove the literal string ##*n|n". The backslashes remove the special meaning from * and |.
You are using regular expression reserved chars in your pattern, you need to escape them
You can use this expression:
var pattern = /[\#\#\*n\|n]/g;
i think use this /[##*n\|n]/g regEx
If you want to replace the first occurrence as you say on your question, you don't need to use regex. A simple string will do, as long as you escape the asterisk:
var str = "Symbol-001 ##*n|nClaimant Name ##*n|nTransaction";
var str2 = str.replace("##\*n|n", ""); //output: "Symbol-001 Claimant Name ##*n|nTransaction"
If you want to replace all the occurrences, you can use regex, escaping all the characters that have a special meaning:
var str3 = str.replace(/\#\#\*n\|n/g, ""); //output: "Symbol-001 Claimant Name Transaction"
Have a look at this regex builder, might come in handy - http://gskinner.com/RegExr/
I have a string and I need to fix it in order to append it to a query.
Say I have the string "A Basket For Every Occasion" and I want it to be "A-Basket-For-Every-Occasion"
I need to find a space and replace it with a hyphen. Then, I need to check if there is another space in the string. If not, return the fixed string. If so, run the same process again.
Sounds like a recursive function to me but I am not sure how to set it up. Any help would be greatly appreciated.
You can use a regex replacement like this:
var str = "A Basket For Every Occasion";
str = str.replace(/\s/g, "-");
The "g" flag in the regex will cause all spaces to get replaced.
You may want to collapse multiple spaces to a single hyphen so you don't end up with multiple dashes in a row. That would look like this:
var str = "A Basket For Every Occasion";
str = str.replace(/\s+/g, "-");
Use replace and find for whitespaces \s globally (flag g)
var a = "asd asd sad".replace(/\s/g,"-");
a becomes
"asd-asd-sad"
Try
value = value.split(' ').join('-');
I used this to get rid of my spaces. Instead of the hyphen I made it empty and works great. Also it is all JS. .split(limiter) will delete the limiter and puts the string pieces in an array (with no limiter elements) then you can join the array with the hyphens.