jQuery: Grouping Similar Items - javascript

Using jQuery, I'm trying to group similar items in a list. Here's what I'm trying to do. Given a list like the following:
<ul>
<li class="foo">Item #1</li>
<li class="foo">Item #2</li>
<li class="foo">Item #3</li>
<li class="bar">Item #4</li>
<li class="bar">Item #5</li>
<li class="foo">Item #6</li>
<li class="foo">Item #7</li>
<li class="bar">Item #8</li>
</ul>
I'd like to end up with the following:
<ul>
<li class="foo">Item #1 <a>2 More Like This</a>
<ul>
<li class="foo">Item #2</li>
<li class="foo">Item #3</li>
</ul>
</li>
<li class="bar">Item #4</li>
<li class="bar">Item #5</li>
<li class="foo">Item #6 <a>1 More Like This</a>
<ul>
<li class="foo">Item #7</li>
</ul>
</li>
<li class="bar">Item #8</li>
</ul>
In short, anytime there's 2 or more items with class="foo", they should be grouped together up until reaching a non-class="foo" item. I can then use a link to show or hide the grouped items.

Here's one possibility:
Example: http://jsbin.com/ipiki3/3/
$('ul > li.foo')
.filter(function() {
var $th = $(this);
return $th.next('li.foo').length && !$th.prev('li.foo').length;
})
.each(function() {
var $th = $(this);
var len= $th.append(' more like this')
.nextUntil(':not(li.foo)').wrapAll('<ul>').length;
$th.next('ul').appendTo(this);
$th.children('a').prepend(len);
});
EDIT: Fixed a mistake with the len variable, and added an example.
Explanation: What's happening with the .filter() is that it is narrowing the li.foo elements down to the first in a group (has at least one li.foo after it, and none before).
Then with the .each() it appends the <a>, get's the next elements until it reaches one that is not li.foo, wraps those with a <ul> and returns how many there were using the length property.
Then we traverse over to that new <ul> and append it to the first li.foo in the group.
Finally we prepend the quantity we stored in the length property to the <a> element.

I come up with this:
$(document).ready(function() {
var groups = {}
$('ul li').each(function() {
var self = $(this);
var class_name = self.attr('class');
if (class_name) {
if (typeof groups[class_name] == 'undefined') {
groups[class_name] = [];
}
groups[class_name].push(self);
}
});
var ul = $('ul');
ul.empty();
for (var class_name in groups) {
var array = groups[class_name];
ul.append('<li class="' + class_name + '">' + $(array[0]).html() +
'<a>More Like this</a><ul></ul>');
$(array.splice(1)).each(function() {
ul.find('li.' + class_name + ' ul').append(this);
});
}
});

Related

add each class for each parent li in navbar

my html structure is like this
<ul>
<li>items1</li>
<li>items2
<ul>
<li>items2.1</li>
</ul>
</li>
<li>items3
<ul>
<li>items3.1</li>
</ul>
</li>
<li>items4</li>
</ul>
I want to add classes for each parent li like below, using JavaScript is there any possibility to do this?
<ul>
<li class="a">items1</li>
<li class="b">items2
<ul>
<li>items2.1</li>
</ul>
</li>
<li class="c">items3
<ul>
<li>items3.1</li>
</ul>
</li>
<li class="d">items4</li>
</ul>
Using not() filter and addClass(function)
$('li').not('li li').addClass(function(i) {
return String.fromCharCode(i + 97)
})
.a {color:red}
.b {color:orange}
.c {color:green}
.d {color:blue}
li li {color:black}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul>
<li>items1</li>
<li>items2
<ul>
<li>items2.1</li>
</ul>
</li>
<li>items3
<ul>
<li>items3.1</li>
</ul>
</li>
<li>items4</li>
</ul>
var letters = "abcd";
$("ul").first().children().each(function(index, el)
{
$(el).addClass(letters[index]);
});
Assuming that there could be n number of list items, we can use: String.fromCharCode(97 + index) to get the letter (up to z).
$("ul").first().children("li").each((index, item) => {
const letterFromIndex = String.fromCharCode(97 + index);
let $item = $(item);
$item.addClass(letterFromIndex);
});
If we want add different names for the li u can use this code also
var names = ["ab", "bc", "cd", "de"];
$("ul").first().children().each(function(index, el)
{
$(el).addClass(names[index]);
});

Using jQuery .nextUntil() on split lists

Is it possible to get the .nextUntil() to work on split lists, or get the same functionality?
So I am trying to implement the ever so popular shift select for my items, and since they are ordered in a list in my application I want to be able to select across <ul> borders.
I have the following set of DOM elements:
<ul class="current">
<li class="item">first</li>
<li class="item clicked">second</li>
<li class="item">third</li>
<li class="item">fourth</li>
</ul>
<ul class="later">
<li class="item">fifth</li>
<li class="item selected">sixth</li>
<li class="item">seventh</li>
</ul>
And using something like this:
$('li.clicked').nextUntil('li.selected');
I'd like a list containing the following elements
[ <li class="item">third</li>,
<li class="item">fourth</li>,
<li class="item">fifth</li> ]
However all I get is the elements leading up to the split </ul>. Is there any way of doing this? I have also tried to first selecting all items with $('.item')and then using .nextUntil() on them without any luck.
Is this what you are looking for?
$('li').slice($('li').index($('.clicked'))+1,$('li').index($('.selected')));
For reference
Jquery.Index
Jquery.Slice
Edit
So if you do
$('li')
you will get an array of all elements 'li' getting:
[<li class=​"item">​first​</li>​,
<li class=​"item clicked">​second​</li>​,
<li class=​"item">​third​</li>​,
<li class=​"item">​fourth​</li>​,
<li class=​"item">​fifth​</li>​,
<li class=​"item selected">​sixth​</li>​,
<li class=​"item">​seventh​</li>​]
Since it is an array you can slice him to get an sub array you just need two positions, where to start and here to finish.
//start
$('li').index($('.clicked'))+1 // +1 because you dont want to select him self
//end
$('li').index($('.selected'))
For better preformance you should before create an array with all li so it will not search all dom 3 times for the array of 'li'
var array = $('li');
var subarray = array.slice(array.index($('.clicked'))+1,array.index($('.selected')));
Assuming these lists cannot be merged into one, it is impossible using the nextUntil method. This is because of how jQuery performs traversing. According to the documentation,
Get all following siblings of each element up to but not including the element matched by the selector, DOM node, or jQuery object passed.
fifth is not a sibling of the clicked element, but rather it is a child of the sibling of the element's parents.
I came up with two possible solutions.
Solution 1: Combine NEXT and PREV traversals
Assuming that .clicked is always in the first list and .selected is always in the second list, combining prevAll() with nextAll() should do the trick. This assumes that the order is the same.
var siblings = $("li.clicked").nextAll()
Get all siblings of the current element AFTER the element itself.
var distantSiblings = $("li.selected").prevAll();
Get all distant siblings after the first element, but before the second one.
siblings.push(distantSiblings);
Combine them into two and then iterate over each element.
var siblings = $("li.clicked").nextAll()
var distantSiblings = $("li.selected").prevAll();
siblings.push(distantSiblings);
siblings.each(function() {
$(this).addClass("blue");
});
.blue { color: blue; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul class="current">
<li class="item">first</li>
<li class="item clicked">second</li>
<li class="item">third</li>
<li class="item">fourth</li>
</ul>
<ul class="later">
<li class="item">fifth</li>
<li class="item selected">sixth</li>
<li class="item">seventh</li>
</ul>
http://jsfiddle.net/r15z10o4/
Note:
You will notice that the above code works, however it might not be the optimal solution. This is only confirmed to work for your example above. There may also be a less verbose solution.
Solution 2 (Find index of all list items)
Another idea is to find the index of all items, and collect the elements that are sandwiched between those two indices. You will then want to use the 'slice' selector to get the range in between.
var items = $(".item");
var clicked = $(".clicked");
var selected = $(".selected");
var clickIndex = items.index(clicked);
var selectIndex = items.index(selected);
$("li").slice(clickIndex + 1, selectIndex).addClass("blue");
var clicked = $(".clicked");
var selected = $(".selected");
var clickIndex = $("li").index(clicked);
var selectIndex = $("li").index(selected);
$("li").slice(clickIndex+1, selectIndex).addClass("blue");
.blue { color: blue; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul class="current">
<li class="item">first</li>
<li class="item clicked">second</li>
<li class="item">third</li>
<li class="item">fourth</li>
</ul>
<ul class="later">
<li class="item">fifth</li>
<li class="item selected">sixth</li>
<li class="item">seventh</li>
</ul>
You can do it manually by selecting all these items at once, and using loops.
Consider the parent element, let's say "container":
<div id="container">
<ul class="current">
<li class="item">first</li>
<li class="item clicked">second</li>
<li class="item">third</li>
<li class="item">fourth</li>
</ul>
<ul class="later">
<li class="item">fifth</li>
<li class="item selected">sixth</li>
<li class="item">seventh</li>
</ul>
</div>
Now, you can select all these items:
var $items = $("#container > ul > li.item"); // or simply $("#container .item");
And iterate through them:
var $items = $(".item"), $result = $(), found = false;
for (var i = 0; i < $items.length; i++)
{
$currentItem = $items.eq(i);
if ($currentItem.is('.clicked')) {
found = true;
continue;
}
if ($currentItem.is('.selected'))
break;
if (found)
$result = $result.add($currentItem);
}
console.log($result);
Here is the working JSFiddle demo.
In any case it feels like you will need to define groups of li.
I think the easiest is to create a function getting a list of lis that you can request any way you want then to filter the el you are interested in.
function elRange(elList, start, end){
// we do not use indexOf directly as elList is likely to be a node list
// and not an array.
var startI = [].indexOf.call(elList, start);
var endI = [].indexOf.call(elList, end);
return [].slice.call(elList, startI, endI + 1);
}
// request the group of *ordered* elements that can be selected
var liList = document.querySelectorAll('ul.current > li, ul.later > li');
var selectionEnd = document.querySelector('.selected');
[].forEach.call(liList, function(li){
li.addEventListener('click', function(){
var selected = elRange(liList, li, selectionEnd);
selected.forEach(function(el){
el.classList.add('red');
})
});
});
.selected {
color: blue;
}
.red {
color: red;
}
<ul class="current">
<li class="item">first</li>
<li class="item">second</li>
<li class="item">third</li>
<li class="item">fourth</li>
</ul>
<ul class="later">
<li class="item">fifth</li>
<li class="item selected">sixth</li>
<li class="item">seventh</li>
</ul>

Next child LI that is wrapped in a different UL

I have the following list:
<ul>
<li class="item">One</li>
<li class="item">Two</li>
<li class="item">Three
<ul>
<li class="item">Something Original</li>
<li class="item selected">Something</li>
</ul>
</li>
<li>Four
<ul>
<li class="item">I want this selected next</li>
<li class="item">Good</li>
</ul>
</li>
</ul>
Using jQuery, how do I find the next li with the class="item" since it is wrapped in a different container. Obviously I cannot do $(".selected").next(".item") so how else can I do it?
JSFiddle: http://jsfiddle.net/q3f6v7zz/
Since the li elements are nested and you know that you want the next appearing li with a particular class, you can use .index() and do something like this
var $li = $('.item'); // <--- get the list of all lis with class .item
var index = $li.index($('.selected')); // <--- find the index of the one with .selected amongst all the lis
console.log($li.eq(index+1).html()); // <--- index+1 because you need the next appearing li after selected
If you want to move the selected class on keydown something like this should do
var $li = $('.item');
$(document).on('keydown', function(e) {
if (e.keyCode == 40) {
var index = $li.index($('.selected'));
$li.eq(index).removeClass('selected');
index = (index+1) % $li.length; // <--- to rotate the values from 0 to count of li.item elements
$li.eq(index).addClass('selected');
}
});
var $li = $('.item');
$(document).on('keydown', function(e) {
if (e.keyCode == 40) {
var index = $li.index($('.selected'));
$li.eq(index).removeClass('selected');
index = (index+1) % $li.length;
$li.eq(index).addClass('selected');
}
});
.selected {
background: green;
color: white;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<ul>
<li class="item">One</li>
<li class="item">Two</li>
<li>Three
<ul>
<li class="item">Something</li>
<li class="item selected">Something Else</li>
</ul>
</li>
<li>Four
<ul>
<li class="item">I want this selected next</li>
<li class="item">Good</li>
</ul>
</li>
</ul>
You can get the index of the selected element within all lis, and then increment that index to get the next one.
$("ul").on("click", "li.item.selected", function() {
var all_li = $("li.item");
var selected_index = all_li.index(this);
var next_li = all_li.eq((selected_index + 1) % all_li.length);
$(this).removeClass("selected");
next_li.addClass("selected");
});
.item.selected {
background-color: yellow;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul>
<li class="item">One</li>
<li class="item">Two</li>
<li class="item">Three
<ul>
<li class="item selected">Something</li>
</ul>
</li>
<li>Four
<ul>
<li class="item">I want this selected next</li>
<li class="item">Good</li>
</ul>
</li>
</ul>
I used the modulus so it will wrap around at the end.
Not sure what you are exactly looking for but you can use $(Element").parent().parent().find("li");
So in other words .parent() may be what you are looking for there is also .sibling() to find or you may want $('li').closest('ul').find('li')
which will go up the tree to find the nearest ul to the one you are looking for
https://api.jquery.com/closest/
You may also use:
Vanilla JS to do something similar to what was discussed by others with $index if it makes more sense to you:
Again this isn't as efficient but that is basically what JQuery is doing:
var myLis = document.getElementsByTagName('li');
var wantedIndex;
for(var i = 0;i<myLis.length; i++){
if(myLis[i].className === "active"){
wantedIndex = i+1; //gets the li which is next when selecting all lis
}
}

get list equal height inside div element

Please take a look at this FIDDLE. I have two pairs of unordered lists, each of which is inside a div element.pricing-table. The following code can find the li with the same classes, get the max height and set the height of all of them to the same. But I want to limit it to getting the max-height of each pair of lists inside each div element.
I think this line is giving me problem because it is getting all the lists with the same classes in the document:
var elems = $('.pricing-table ul li.' + elem.className),
I don't think I can use $(this) and update it like $(this +elem.className). Any suggestions?
Jquery script:
$(document).ready( function(){
$('.pricing-table ul li').each(function(i, elem) {
var elems = $('.pricing-table ul li.' + elem.className),
heights = $.map(elems, function(li) {
return $(li).height();
}),
max = Math.max.apply(null, heights);
elems.height(max);
});
});
HTML
<div class="pricing-table">
<ul>
<li class="heading">Bronze</li>
<li class="year">2003<p>(Text)..........</li>
<li class="package">Starter package</li>
<li class="location">Africa (Text).......)</li>
<li class="description">Text............ </li>
</ul>
<ul class="feature">
<li class="heading">Silver</li>
<li class="year">2004</li>
<li class="package">Intermediate package</li>
<li class="location">Asia</li>
<li class="description">Text............ </li>
</ul>
</div>
<div class="pricing-table">
<ul>
<li class="heading">Bronze</li>
<li class="year">2003<p>(Text)..........</li>
<li class="package">Starter package</li>
<li class="location">Africa (Text).......)</li>
<li class="description">Text............ </li>
</ul>
<ul class="feature">
<li class="heading">Silver</li>
<li class="year">2004</li>
<li class="package">Intermediate package</li>
<li class="location">Asia</li>
<li class="description">Text............ </li>
</ul>
</div>
You’d need to get only the li that are descendants of your current .pricing-table element, so you’ll have to iterate over the latter first:
$(document).ready(function () {
$('.pricing-table').each(function (i, e) {
$(e).find('ul li').each(function (i, elem) {
var elems = $(e).find('ul li.' + elem.className),
heights = $.map(elems, function (li) {
return $(li).height();
}),
max = Math.max.apply(null, heights);
elems.height(max);
});
});
});
… or something like that. http://jsfiddle.net/p3sfy/3867/
(Still kinda ugly, since it will iterate over the li multiple times, so that’s rather just a “quick fix” – but I don’t wanna think about anything more sophisticated here before I have not first heard a convincing argument why this data is not marked up using tables in the first place …?)

jquery ordering and group li elements

Let's say I have a list of items under a div or UL. I want to take all the list items with the same title attribute and wrap a UL around it. The next part though is that I want that UL to be under the LI with the same attribute. So, I'm trying to group basically.
So.... I start with.....
<li>Insurance</li>
<li>Education</li>
<li>Sports</li>
<li>Construction</li>
<li title ="Insurance">Malpractice</li>
<li title ="Construction">Carpentry</li>
<li title ="Education">College</li>
<li title ="Insurance">Automobile</li>
<li title ="Education">High School</li>
<li title ="Construction">Iron Worker</li>
and I want to get to......
<li>Insurance
<ul>
<li title ="Insurance">Malpractice</li>
<li title ="Insurance">Automobile</li>
</ul>
</li>
<li>Education
<ul>
<li title ="Education">College</li>
<li title ="Education">High School</li>
</ul>
</li>
<li>Sports</li>
<li>Construction
<ul>
<li title ="Construction">Carpentry</li>
<li title ="Construction">Iron Worker</li>
</ul>
</li>
Any help would be appreciated. Obviously new to the jquery and javascript world so I'm trying to wrap my brain around this.
Input:
<div id="stuffs">
<li>Insurance</li>
<li>Education</li>
<li>Sports</li>
<li>Construction</li>
<li title ="Insurance">Malpractice</li>
<li title ="Construction">Carpentry</li>
<li title ="Education">College</li>
<li title ="Insurance">Automobile</li>
<li title ="Education">High School</li>
<li title ="Construction">Iron Worker</li>
</div>
jQuery:
​$("#stuffs li").each(function(){
$("#stuffs li[title='"+$(this).text()+"']").appendTo($(this)).wrapAll("<ul />");
});​​​​​​​​​​
Output:
<div id="stuffs">
<ul>
<li>Insurance
<ul>
<li title="Insurance">Malpractice</li>
<li title="Insurance">Automobile</li>
</ul>
</li>
<li>Education
<ul>
<li title="Education">College</li>
<li title="Education">High School</li>
</ul>
</li>
<li>Sports</li>
<li>Construction
<ul>
<li title="Construction">Carpentry</li>
<li title="Construction">Iron Worker</li>
</ul>
</li>
</ul>
</div>
Smile :-)
Demo here
// first we fetch all items without title attribute
var topLevel = $('li:not([title])');
// for each of those...
topLevel.each(function() {
var li = $(this),
// ... we get its text ...
title = li.text(),
// ... and other li elements with the corresponding title
children = $('li[title="' + title + '"]');
// if there are any...
if (children.length > 0) {
// ... create an empty list ...
var ul = $('<ul></ul>');
// ... fill it and ...
children.appendTo(ul);
// ... append it to the original li element
ul.appendTo(li);
}
});
jQuery documentation: :not(), [title], each(), appendTo()
This should work
$('#id li:not([title])').append('<ul />');
$('#id li[title]').each(function() {
$(this).appendTo('#id li:contains(' + $(this).attr('title') + ') ul');
})
A demo

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