Finding the URL of an XMLHttpRequest - javascript

I've got some code that does an ajax request using jQuery, and handles success and error conditions. On an error, I want to find out what the URL I called was, so I can log it. This information appears to be contained in the XMLHttpRequest.channel, but firefox is complaining about accessing this -
Permission denied for <http://localhost:8081> to get property XMLHttpRequest.channel
Any ideas how I can determine the URL associated with an XMLHttpRequest? What's the security issue getting hold of this information? Cheers,
Colin

Ok - sorry about this - an answer is here
http://api.jquery.com/ajaxError/
specifically this code from above link -
$('.log').ajaxError(function(e, xhr, settings, exception) {
if (settings.url == 'ajax/missing.html') {
$(this).text('Triggered ajaxError handler.');
}
});
shows how to access the request url in the event of an ajax error. Doesn't explain why the XMLHttpRequest.channel object is a no go though. Anyway, hopefully that will help others with a similar problem.

Well, you just add it ;]
XMLHttpRequest.prototype.baseOpen = XMLHttpRequest.prototype.open;
XMLHttpRequest.prototype.open = function(method, url, async) { this._url = url; return XMLHttpRequest.prototype.baseOpen.apply(this, arguments); };
then you can later ask for xhr._url in your error handler.
PS: Sorry, just discovered this thread is old.

The security issue is cross domain XHR requests.
In FF2 you used to be able to override this in about:config, also see this blog and especially this preference:
user_pref("capability.policy.default.XMLHttpRequest.channel", "allAccess");
But that's all not possible anymore in FF3. And with a good reason.
Note that XMLHttpRequest.channel is Gecko-specific, so this wouldn't have worked in non-Gecko browsers.

Firebug presents this error with a trace that shows the URI used.

Related

Showing pop up when internet connection is lost in php [duplicate]

How to detect the Internet connection is offline in JavaScript?
Almost all major browsers now support the window.navigator.onLine property, and the corresponding online and offline window events. Run the following code snippet to test it:
console.log('Initially ' + (window.navigator.onLine ? 'on' : 'off') + 'line');
window.addEventListener('online', () => console.log('Became online'));
window.addEventListener('offline', () => console.log('Became offline'));
document.getElementById('statusCheck').addEventListener('click', () => console.log('window.navigator.onLine is ' + window.navigator.onLine));
<button id="statusCheck">Click to check the <tt>window.navigator.onLine</tt> property</button><br /><br />
Check the console below for results:
Try setting your system or browser in offline/online mode and check the log or the window.navigator.onLine property for the value changes.
Note however this quote from Mozilla Documentation:
In Chrome and Safari, if the browser is not able to connect to a local area network (LAN) or a router, it is offline; all other conditions return true. So while you can assume that the browser is offline when it returns a false value, you cannot assume that a true value necessarily means that the browser can access the internet. You could be getting false positives, such as in cases where the computer is running a virtualization software that has virtual ethernet adapters that are always "connected." Therefore, if you really want to determine the online status of the browser, you should develop additional means for checking.
In Firefox and Internet Explorer, switching the browser to offline mode sends a false value. Until Firefox 41, all other conditions return a true value; since Firefox 41, on OS X and Windows, the value will follow the actual network connectivity.
(emphasis is my own)
This means that if window.navigator.onLine is false (or you get an offline event), you are guaranteed to have no Internet connection.
If it is true however (or you get an online event), it only means the system is connected to some network, at best. It does not mean that you have Internet access for example. To check that, you will still need to use one of the solutions described in the other answers.
I initially intended to post this as an update to Grant Wagner's answer, but it seemed too much of an edit, especially considering that the 2014 update was already not from him.
You can determine that the connection is lost by making failed XHR requests.
The standard approach is to retry the request a few times. If it doesn't go through, alert the user to check the connection, and fail gracefully.
Sidenote: To put the entire application in an "offline" state may lead to a lot of error-prone work of handling state.. wireless connections may come and go, etc. So your best bet may be to just fail gracefully, preserve the data, and alert the user.. allowing them to eventually fix the connection problem if there is one, and to continue using your app with a fair amount of forgiveness.
Sidenote: You could check a reliable site like google for connectivity, but this may not be entirely useful as just trying to make your own request, because while Google may be available, your own application may not be, and you're still going to have to handle your own connection problem. Trying to send a ping to google would be a good way to confirm that the internet connection itself is down, so if that information is useful to you, then it might be worth the trouble.
Sidenote: Sending a Ping could be achieved in the same way that you would make any kind of two-way ajax request, but sending a ping to google, in this case, would pose some challenges. First, we'd have the same cross-domain issues that are typically encountered in making Ajax communications. One option is to set up a server-side proxy, wherein we actually ping google (or whatever site), and return the results of the ping to the app. This is a catch-22 because if the internet connection is actually the problem, we won't be able to get to the server, and if the connection problem is only on our own domain, we won't be able to tell the difference. Other cross-domain techniques could be tried, for example, embedding an iframe in your page which points to google.com, and then polling the iframe for success/failure (examine the contents, etc). Embedding an image may not really tell us anything, because we need a useful response from the communication mechanism in order to draw a good conclusion about what's going on. So again, determining the state of the internet connection as a whole may be more trouble than it's worth. You'll have to weight these options out for your specific app.
IE 8 will support the window.navigator.onLine property.
But of course that doesn't help with other browsers or operating systems. I predict other browser vendors will decide to provide that property as well given the importance of knowing online/offline status in Ajax applications.
Until that happens, either XHR or an Image() or <img> request can provide something close to the functionality you want.
Update (2014/11/16)
Major browsers now support this property, but your results will vary.
Quote from Mozilla Documentation:
In Chrome and Safari, if the browser is not able to connect to a local area network (LAN) or a router, it is offline; all other conditions return true. So while you can assume that the browser is offline when it returns a false value, you cannot assume that a true value necessarily means that the browser can access the internet. You could be getting false positives, such as in cases where the computer is running a virtualization software that has virtual ethernet adapters that are always "connected." Therefore, if you really want to determine the online status of the browser, you should develop additional means for checking.
In Firefox and Internet Explorer, switching the browser to offline mode sends a false value. All other conditions return a true value.
if(navigator.onLine){
alert('online');
} else {
alert('offline');
}
There are a number of ways to do this:
AJAX request to your own website. If that request fails, there's a good chance it's the connection at fault. The JQuery documentation has a section on handling failed AJAX requests. Beware of the Same Origin Policy when doing this, which may stop you from accessing sites outside your domain.
You could put an onerror in an img, like <img src="http://www.example.com/singlepixel.gif" onerror="alert('Connection dead');" />.
This method could also fail if the source image is moved / renamed, and would generally be an inferior choice to the ajax option.
So there are several different ways to try and detect this, none perfect, but in the absence of the ability to jump out of the browser sandbox and access the user's net connection status directly, they seem to be the best options.
As olliej said, using the navigator.onLine browser property is preferable than sending network requests and, accordingly with developer.mozilla.org/En/Online_and_offline_events, it is even supported by old versions of Firefox and IE.
Recently, the WHATWG has specified the addition of the online and offline events, in case you need to react on navigator.onLine changes.
Please also pay attention to the link posted by Daniel Silveira which points out that relying on those signal/property for syncing with the server is not always a good idea.
You can use $.ajax()'s error callback, which fires if the request fails. If textStatus equals the string "timeout" it probably means connection is broken:
function (XMLHttpRequest, textStatus, errorThrown) {
// typically only one of textStatus or errorThrown
// will have info
this; // the options for this ajax request
}
From the doc:
Error: A function to be called if the request
fails. The function is passed three
arguments: The XMLHttpRequest object,
a string describing the type of error
that occurred and an optional
exception object, if one occurred.
Possible values for the second
argument (besides null) are "timeout",
"error", "notmodified" and
"parsererror". This is an Ajax Event
So for example:
$.ajax({
type: "GET",
url: "keepalive.php",
success: function(msg){
alert("Connection active!")
},
error: function(XMLHttpRequest, textStatus, errorThrown) {
if(textStatus == 'timeout') {
alert('Connection seems dead!');
}
}
});
window.navigator.onLine
is what you looking for, but few things here to add, first, if it's something on your app which you want to keep checking (like to see if the user suddenly go offline, which correct in this case most of the time, then you need to listen to change also), for that you add event listener to window to detect any change, for checking if the user goes offline, you can do:
window.addEventListener("offline",
()=> console.log("No Internet")
);
and for checking if online:
window.addEventListener("online",
()=> console.log("Connected Internet")
);
The HTML5 Application Cache API specifies navigator.onLine, which is currently available in the IE8 betas, WebKit (eg. Safari) nightlies, and is already supported in Firefox 3
I had to make a web app (ajax based) for a customer who works a lot with schools, these schools have often a bad internet connection I use this simple function to detect if there is a connection, works very well!
I use CodeIgniter and Jquery:
function checkOnline() {
setTimeout("doOnlineCheck()", 20000);
}
function doOnlineCheck() {
//if the server can be reached it returns 1, other wise it times out
var submitURL = $("#base_path").val() + "index.php/menu/online";
$.ajax({
url : submitURL,
type : "post",
dataType : "msg",
timeout : 5000,
success : function(msg) {
if(msg==1) {
$("#online").addClass("online");
$("#online").removeClass("offline");
} else {
$("#online").addClass("offline");
$("#online").removeClass("online");
}
checkOnline();
},
error : function() {
$("#online").addClass("offline");
$("#online").removeClass("online");
checkOnline();
}
});
}
an ajax call to your domain is the easiest way to detect if you are offline
$.ajax({
type: "HEAD",
url: document.location.pathname + "?param=" + new Date(),
error: function() { return false; },
success: function() { return true; }
});
this is just to give you the concept, it should be improved.
E.g. error=404 should still mean that you online
I know this question has already been answered but i will like to add my 10 cents explaining what's better and what's not.
Window.navigator.onLine
I noticed some answers spoke about this option but they never mentioned anything concerning the caveat.
This option involves the use of "window.navigator.onLine" which is a property under Browser Navigator Interface available on most modern browsers. It is really not a viable option for checking internet availability because firstly it is browser centric and secondly most browsers implement this property differently.
In Firefox: The property returns a boolean value, with true meaning online and false meaning offline but the caveat here is that
"the value is only updated when the user follows links or when a script requests a remote page." Hence if the user goes offline and
you query the property from a js function or script, the property will
always return true until the user follows a link.
In Chrome and Safari: If the browser is not able to connect to a local area network (LAN) or a router, it is offline; all other
conditions return true. So while you can assume that the browser is
offline when it returns a false value, you cannot assume that a true
value necessarily means that the browser can access the internet. You
could be getting false positives, such as in cases where the computer
is running a virtualization software that has virtual ethernet
adapters that are always "connected".
The statements above is simply trying to let you know that browsers alone cannot tell. So basically this option is unreliable.
Sending Request to Own Server Resource
This involves making HTTP request to your own server resource and if reachable assume internet availability else the user is offline. There are some few caveats to this option.
No server availability is 100% reliant, hence if for some reason your server is not reachable it would be falsely assumed that the user is offline whereas they're connected to the internet.
Multiple request to same resource can return cached response making the http response result unreliable.
If you agree your server is always online then you can go with this option.
Here is a simple snippet to fetch own resource:
// This fetches your website's favicon, so replace path with favicon url
// Notice the appended date param which helps prevent browser caching.
fetch('/favicon.ico?d='+Date.now())
.then(response => {
if (!response.ok)
throw new Error('Network response was not ok');
// At this point we can safely assume the user has connection to the internet
console.log("Internet connection available");
})
.catch(error => {
// The resource could not be reached
console.log("No Internet connection", error);
});
Sending Request to Third-Party Server Resource
We all know CORS is a thing.
This option involves making HTTP request to an external server resource and if reachable assume internet availability else the user is offline. The major caveat to this is the Cross-origin resource sharing which act as a limitation. Most reputable websites blocks CORS requests but for some you can have your way.
Below a simple snippet to fetch external resource, same as above but with external resource url:
// Firstly you trigger a resource available from a reputable site
// For demo purpose you can use the favicon from MSN website
// Also notice the appended date param which helps skip browser caching.
fetch('https://static-global-s-msn-com.akamaized.net/hp-neu/sc/2b/a5ea21.ico?d='+Date.now())
.then(response => {
// Check if the response is successful
if (!response.ok)
throw new Error('Network response was not ok');
// At this point we can safely say the user has connection to the internet
console.log("Internet available");
})
.catch(error => {
// The resource could not be reached
console.log("No Internet connection", error);
});
So, Finally for my personal project i went with the 2nd option which involves requesting own server resource because basically there are many factors to tell if there is "Internet Connection" on a user's device, not just from your website container alone nor from a limited browser api.
Remember your users can also be in an environment where some websites or resources are blocked, prohibited and not accessible which in turn affects the logic of connectivity check. The best bet will be:
Try to access a resource on your own server because this is your users environment (Typically i use website's favicon because the response is very light and it is not frequently updated).
If there is no connection to the resource, simply say "Error in connection" or "Connection lost" when you need to notify the user rather than assume a broad "No internet connection" which depends on many factors.
I think it is a very simple way.
var x = confirm("Are you sure you want to submit?");
if (x) {
if (navigator.onLine == true) {
return true;
}
alert('Internet connection is lost');
return false;
}
return false;
The problem of some methods like navigator.onLine is that they are not compatible with some browsers and mobile versions, an option that helped me a lot was to use the classic XMLHttpRequest method and also foresee the possible case that the file was stored in cache with response XMLHttpRequest.status is greater than 200 and less than 304.
Here is my code:
var xhr = new XMLHttpRequest();
//index.php is in my web
xhr.open('HEAD', 'index.php', true);
xhr.send();
xhr.addEventListener("readystatechange", processRequest, false);
function processRequest(e) {
if (xhr.readyState == 4) {
//If you use a cache storage manager (service worker), it is likely that the
//index.php file will be available even without internet, so do the following validation
if (xhr.status >= 200 && xhr.status < 304) {
console.log('On line!');
} else {
console.log('Offline :(');
}
}
}
I was looking for a client-side solution to detect if the internet was down or my server was down. The other solutions I found always seemed to be dependent on a 3rd party script file or image, which to me didn't seem like it would stand the test of time. An external hosted script or image could change in the future and cause the detection code to fail.
I've found a way to detect it by looking for an xhrStatus with a 404 code. In addition, I use JSONP to bypass the CORS restriction. A status code other than 404 shows the internet connection isn't working.
$.ajax({
url: 'https://www.bing.com/aJyfYidjSlA' + new Date().getTime() + '.html',
dataType: 'jsonp',
timeout: 5000,
error: function(xhr) {
if (xhr.status == 404) {
//internet connection working
}
else {
//internet is down (xhr.status == 0)
}
}
});
How about sending an opaque http request to google.com with no-cors?
fetch('https://google.com', {
method: 'GET', // *GET, POST, PUT, DELETE, etc.
mode: 'no-cors',
}).then((result) => {
console.log(result)
}).catch(e => {
console.error(e)
})
The reason for setting no-cors is that I was receiving cors errors even when disbaling the network connection on my pc. So I was getting cors blocked with or without an internet connection. Adding the no-cors makes the request opaque which apperantly seems to bypass cors and allows me to just simply check if I can connect to Google.
FYI: Im using fetch here for making the http request.
https://www.npmjs.com/package/fetch
My way.
<!-- the file named "tt.jpg" should exist in the same directory -->
<script>
function testConnection(callBack)
{
document.getElementsByTagName('body')[0].innerHTML +=
'<img id="testImage" style="display: none;" ' +
'src="tt.jpg?' + Math.random() + '" ' +
'onerror="testConnectionCallback(false);" ' +
'onload="testConnectionCallback(true);">';
testConnectionCallback = function(result){
callBack(result);
var element = document.getElementById('testImage');
element.parentNode.removeChild(element);
}
}
</script>
<!-- usage example -->
<script>
function myCallBack(result)
{
alert(result);
}
</script>
<a href=# onclick=testConnection(myCallBack);>Am I online?</a>
Just use navigator.onLine if this is true then you're online else offline
request head in request error
$.ajax({
url: /your_url,
type: "POST or GET",
data: your_data,
success: function(result){
//do stuff
},
error: function(xhr, status, error) {
//detect if user is online and avoid the use of async
$.ajax({
type: "HEAD",
url: document.location.pathname,
error: function() {
//user is offline, do stuff
console.log("you are offline");
}
});
}
});
You can try this will return true if network connected
function isInternetConnected(){return navigator.onLine;}
Here is a snippet of a helper utility I have. This is namespaced javascript:
network: function() {
var state = navigator.onLine ? "online" : "offline";
return state;
}
You should use this with method detection else fire off an 'alternative' way of doing this. The time is fast approaching when this will be all that is needed. The other methods are hacks.
There are 2 answers forthis for two different senarios:-
If you are using JavaScript on a website(i.e; or any front-end part)
The simplest way to do it is:
<h2>The Navigator Object</h2>
<p>The onLine property returns true if the browser is online:</p>
<p id="demo"></p>
<script>
document.getElementById("demo").innerHTML = "navigator.onLine is " + navigator.onLine;
</script>
But if you're using js on server side(i.e; node etc.), You can determine that the connection is lost by making failed XHR requests.
The standard approach is to retry the request a few times. If it doesn't go through, alert the user to check the connection, and fail gracefully.

Check whether content can be displayed in iFrame does not work

I have the following code to check whether the webpage can be framed or not at all:
var req = new XMLHttpRequest();
var test = req.open('GET', link, false);
console.log("test",test); //ALWAYS undefined
if(req.send(null)){ //ALWAYS throws error NS_ERROR_FAILURE
var headers = req.getAllResponseHeaders().toLowerCase();
console.log("headers");
}else{
console.log("FAILED");
}
I tested it with several links, frameable or not, but always fails. Do you know exactly why?
Links:
http://www.joomlaworks.net/images/demos/galleries/abstract/7.jpg
http://www.facebook.com (...)
test is undefined because open() is declared void, it does not return any value. Check out MDN on the open method.
Why are you passing null to send? (see edit) If you intend to call the overload of send that doesn't take any argument you should just call req.send(); instead if you want to call another version of the method you should pass a Blob, Document, DOMString or FormData, but null won't work.
EDIT: Often the method is invoked as send(null); it seems to be because at some point in history (is that old?) the argument of send was mandatory. This question unravels the mystery.
Moreover, again send doesn't return any value so the condition in the if will never evaluate true. MDN documents also the send method.
Last, you are performing a cross-domain request, i.e. you're asking for content that is located on another domain. XMLHttpRequest doesn't handle that, most likely you will end up with this error:
XMLHttpRequest cannot load link. No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin origin is therefore not allowed access.
Check out this question and this on StackOverflow if you need more information about that.
You may want to take a look at Using XMLHttpRequest again on the MDN network, it has many reliable examples that can help you get acquainted with these requests.
EDIT: expanding on the topic iframe embeddability.
Detecting reliably if a website can be embedded in an iframe is difficult, as this question shows. Detecting (or preventing) frame buster in JavaScript is like a dog chasing its own tail.
Nevertheless, a website that doesn't want to be incorporated, hopefully would send the X-Frame-Options: DENY header in its response. This is not very useful, because you can't perform cross domain requests: your request would fail before getting to know if the X-Frame-Options header is even set. For completeness, this is the way of checking if the response to an XMLHttpRequest contains a given header (but note that this would work only within the same domain, which is presumably under your control, and you would know already if a page is 'frameable'):
function checkXFrame() {
var xframe = this.getResponseHeader("X-Frame-Options");
if (!xframe) {
alert("Frameable.");
return;
}
xframe = xframe.toLowerCase();
if (xframe == "deny") {
alert("Not frameable.");
} else if (xframe == "sameorigin") {
alert("Frameable within the same domain.");
} else if (xframe.startsWith("allow-from")) {
alert("Frameable from certain domains.");
} else {
alert("Someone sent a weird header.");
}
}
var oReq = new XMLHttpRequest();
oReq.open("HEAD" /* use HEAD if you only need the headers! */, "yourpage.html");
oReq.onload = checkXFrame;
oReq.send();
(this code doesn't check for 404 or any other error!)

XHR IE7 Operation Aborted JSON Error

I'm trying to send an AJAX post request in IE 7, but I'm getting an "Operation Aborted" error, seemingly from the JSON I'm sending, even though everything seems right. I've been messing around with this for an hour or so now, and haven't made any progress, so thought I would post it here to see if anyone could see anything wrong with it.
The "Operation Aborted" error keeps mentioning DOM loading issues, but I only see it when I try to make this post request, so I imagine it's something different in this situation.
var request = new XMLHttpRequest();
request.open("POST", url, false);
request.setRequestHeader("Content-Type", "application/json");
try {
request.send('{"param":"value"}');
} catch (e) {
alert(e.message);
}
It might be that the URL your trying to post data to simply doesn't work on IE7. Try updating to IE8.
http://support.microsoft.com/kb/927917
Stuff like this happens when a script tries to alter an element that hasn't finished loading yet. This website explains it quite well:
http://blogs.msdn.com/b/ie/archive/2008/04/23/what-happened-to-operation-aborted.aspx
changing request.send('{"param":"value"}'); to request.send('{ "param" : "value" }') fixed the issue, sigh.

XMLHttpRequest.send() throws exception when asked for a DOM object

I want to retrieve a HTML page as document inside a Firefox/Greasemonkey userscript.
Edit: This is not a cross-domain request.
Here's my example code:
var r = new XMLHttpRequest();
r.open("GET", document.location.href, true);
r.responseType = "document";
r.send(null);
This looks just like the example in https://developer.mozilla.org/en/HTML_in_XMLHttpRequest ,
but r.send(null) causes a TypeError. Causes, not throws! Wrapping the line in a try...catch won't change anything, it seems like a callback or an event handler raises the exception:
TypeError: document.location is null
The traceback refers to a Firefox-internal event.js file, but not to my script.
Removing the line setting the responseType gets rid of the exception, adding callbacks does not.
However, the response is valid and responseXML provides a DOM tree.
I'm using FF 13.0.1.
Am I missing something or is this a bug?
Solution: This had something to do with an extension created by Mozilla's Addon Builder, not Firefox.
The script is running on google.com and you are trying to fetch google.de, right? That's a cross-domain request. (Also, the question code is not a valid synch or asynch use of XMLHttpRequest.)
To do cross-domain (or not) AJAX in a Greasemonkey script (Or Chrome), use GM_xmlhttpRequest().
Note that GM_xmlhttpRequest() does not currently let you specify responseType, but you don't need to do that in this case anyway. If you want a nice parsed document, use DOMParser.
Putting it all together:
GM_xmlhttpRequest ( {
method: 'GET',
//url: 'https://www.google.de/',
url: location.href, // self get, checking for updates
onload: function (respDetails) {
processResponse (respDetails);
}
} );
function processResponse (respDetails) {
// DO ALL RESPONSE PROCESSING HERE...
var parser = new DOMParser ();
var doc = parser.parseFromString (respDetails.responseText, "text/html");
//--- Example showing that the doc is fully parsed/functional...
console.log (doc.querySelectorAll ("p") );
}
PS: Since this is not cross-domain after all, the original code, corrected would be:
var r = new XMLHttpRequest();
r.onload = function () {
// DO ALL RESPONSE PROCESSING HERE...
console.log (this.response.querySelectorAll ("div") );
}
r.open ("GET", location.href, true);
r.responseType = "document";
r.send (null);
for an asynchronous request.
Unfortunately, you cannot do Ajax from one domain to another:
http://en.wikipedia.org/wiki/Same_origin_policy
You can read into CORS:
http://en.wikipedia.org/wiki/Cross-origin_resource_sharing
or JSONP as possible solutions:
http://en.wikipedia.org/wiki/JSONP
However, browsers are designed in such a way so that people can't just randomly create Ajax requests across domains due to this being a security issue.
If you absolutely need to grab content off a different domain, I'd look into creating your own server API using cURL, serving your own content on the same domain, and then using Ajax there. Otherwise, you'll have to see if Google will grant CORS access or has some sort of built in JSONP request.

MooTools Request Failing

So I have a bit of a problem. When I ask MooTools to send a request it comes back as failed every time. I can't seem to diagnose the problem either because if I try to get the returned header info the console just gives me "Refused to get unsafe header 'Status'" Message. The only thing I can think of is that the server isn't letting me access outside resources but maybe I just coded it wrong.
Here's the request code:
var finfo = current.textFontData();
var url = 'http://antiradiant.com/clients/TMW/rbwizard/mailer.php?s='+current.size+'&b='+current.box+'&l='+current.lidWood+'&c='+current.cartID+'&f='+finfo.font+'&l1='+finfo.line1+'&l2='+finfo.line2;
console.log(url);
var req = new Request({
url: url,
onSuccess: function() {
console.log('success');
//atc2.send();
},
onFailure: function() {
console.log('failure');
console.log(this.getHeader('Status'));
//atc2.send();
},
onException: function(headerName, value) {
console.log('exception');
console.log(headerName+': '+value);
}
});
req.send();
This code is derived from the resource rb_wizard.js (lines 81-103) on http://tylermorriswoodworking.myshopify.com/pages/recipe-box-wizard?b=maple&l=cherry&s=3x5&c=42042892
Mootools has a class called Request.JSONP that will help with your cross domain problem. Its sub class of the Request class, so your methods should work the same. I believe you need to call .post() or .get() at the end instead of send, but thats about all that should chnge. I'm not sure what version you're running on but here is the link tot he docs Mootools Request.JSONP
The error message "Refused to get unsafe header 'Status'" is spat out by WebKit based browsers (Safari, Chrome, etc) when you violate the cross-domain security model.
Therefore, it seems likely that the code you pasted is located on a domain other than antiradiant.com, and therefore is not allowed (by the browser) to request sites on antiradiant.com.
What I ended up doing was just using an iframe. All I really had to do was send data to another site and not receive any so it worked out.

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