Help with JS and functions parameters - javascript

Does JS support two functions with the same name and different parameters ?
function f1(a, b)
{
// a and b are numbers
}
function f1(a, b, c)
{
// a is a string
//b and c are numbers
}
Can I use those JS function for IE7, FF, Opera with no problem?

JavaScript doesn't support what you would call in other languages method overloading, but there are multiple workarounds, like using the arguments object, to check with how many arguments a function has been invoked:
function f1(a, b, c) {
if (arguments.length == 2) {
// f1 called with two arguments
} else if (arguments.length == 3) {
// f1 called with three arguments
}
}
Additionally you could type-check your arguments, for Number and String primitives is safe to use the typeof operator:
function f1(a, b, c) {
if (typeof a == 'number' && typeof b == 'number') {
// a and b are numbers
} else if (typeof a == 'string' && typeof b == 'number' &&
typeof c == 'number') {
// a is a string, b and c are numbers
}
}
And there are much more sophisticated techniques like the one in the following article, that takes advantage of some JavaScript language features like closures, function application, etc, to mimic method overloading:
JavaScript method overloading

No, you can't use function overloading in JS.
But, you can declare just the version with 3 parameters, and then check whether the third argument === undefined, and provide differentiated behaviour on that basis.

No, that will not work, only the 2nd function will be defined on your page. Here's a source.

Javascript only uses the function that was defined last.
http://weblogs.asp.net/jgalloway/archive/2005/10/02/426345.aspx
You will need to implement your own logic inside the function to determine which parameters were passed in.

No you can't do that ... unless it is OK with you to only have your last definition hold.

You can also use instanceof, example with basic polymorphism.
First create a superclass (ball)
// superclass
function Ball() {
this.play = function() {
alert("Ball throw");
};
}
and now for some subclasses (types of balls)
// subclass
function Basketball() {
this.play = function() {
alert("basketball throw");
};
}
// subclass
function Soccerball() {
this.play = function() {
alert("soccer ball kick/throw");
console.debug("here");
};
}
// subclass
function Baseball() {
this.play = function() {
alert("strike 3 you're out");
console.debug("here");
};
}
Give them Ball functionality, aka set their superclass via prototype
// set subclass functionality
Basketball.prototype = new Ball();
Soccerball.prototype = new Ball();
Baseball.prototype = new Ball();
Some polymorphism (create a bunch of balls and play with them all, but play based on type)
var bunchOfBalls = [new Baseball(), new Soccerball(), new Basketball()];
for (var i = 0; i < bunchOfBalls.length; i++) {
bunchOfBalls[i].play();
}
Now write a function that takes a ball but only want to to work for specific type of balls (mimic function overloading, more or less)
//overloading dependent upon type
function BasketbalOrBaseballOnlyPlay(aBall) {
if (aBall instanceof Basketball) {
//special basketball function
}
if (aBall instanceof Baseball) {
//special baseball function
}
}
If aBall is a Basketball so aBall = new Basketball(); then aBall instanceof Basketball would return true for Basketball and false for baseball but true for Ball.
So aBall instanceof Ball would return true because a Basketball is a Ball.
See code live at http://jsfiddle.net/kLCPB/

Related

Can I extend a function in TypeScript?

I want to create my super awesome container class that holds a single value.
let a = new Container(42);
An I want to get values like this
a(); // 42
and set values like this
a(43);
Is there a way to achieve this in TypeScript?
Operator overloading is not properly supported in JavaScript / TypeScript.
You cannot define functions (except constructors) which are called if you try to call a class.
Is there a way to achieve this in TypeScript?
Why not. For it can be done in plain JavaScript, it easily should be achieved in TypeScript too. As almost always with Functions, scope is the keyword for our approach.
A constructor then of course gets misused just as a closure without creating types that would respond to e.g. Container via the typeof operator. Such a factory function will just return another function that then is used as getter/setter for the constructor's enclosed initial value.
TypeScript example ...
class Container {
constructor(storageValue: any) {
return (function (value: any) {
if (arguments.length !== 0) {
storageValue = value;
}
return storageValue;
});
}
}
... in plain JavaScript ...
var Container = (function ContainerClass () {
var Constructor = (function Container (storageValue) {
return (function (value) {
if (arguments.length !== 0) {
storageValue = value;
}
return storageValue;
});
});
return Constructor;
}());
var a = new Container(24);
console.log("a() : ", a()); // 24
console.log("a(4) : ", a(4)); // 4
console.log("a() : ", a()); // 4
var b = new Container(72);
console.log("b() : ", b()); // 72
console.log("b(5) : ", b(5)); // 5
console.log("b() : ", b()); // 5
console.log("a() : ", a()); // 4

in javascript which way is better for check variable types [duplicate]

I created a JavaScript object, but how I can determine the class of that object?
I want something similar to Java's .getClass() method.
There's no exact counterpart to Java's getClass() in JavaScript. Mostly that's due to JavaScript being a prototype-based language, as opposed to Java being a class-based one.
Depending on what you need getClass() for, there are several options in JavaScript:
typeof
instanceof
obj.constructor
func.prototype, proto.isPrototypeOf
A few examples:
function Foo() {}
var foo = new Foo();
typeof Foo; // == "function"
typeof foo; // == "object"
foo instanceof Foo; // == true
foo.constructor.name; // == "Foo"
Foo.name // == "Foo"
Foo.prototype.isPrototypeOf(foo); // == true
Foo.prototype.bar = function (x) {return x+x;};
foo.bar(21); // == 42
Note: if you are compiling your code with Uglify it will change non-global class names. To prevent this, Uglify has a --mangle param that you can set to false is using gulp or grunt.
obj.constructor.name
is a reliable method in modern browsers. Function.name was officially added to the standard in ES6, making this a standards-compliant means of getting the "class" of a JavaScript object as a string. If the object is instantiated with var obj = new MyClass(), it will return "MyClass".
It will return "Number" for numbers, "Array" for arrays and "Function" for functions, etc. It generally behaves as expected. The only cases where it fails are if an object is created without a prototype, via Object.create( null ), or the object was instantiated from an anonymously-defined (unnamed) function.
Also note that if you are minifying your code, it's not safe to compare against hard-coded type strings. For example instead of checking if obj.constructor.name == "MyType", instead check obj.constructor.name == MyType.name. Or just compare the constructors themselves, however this won't work across DOM boundaries as there are different instances of the constructor function on each DOM, thus doing an object comparison on their constructors won't work.
This getNativeClass() function returns "undefined" for undefined values and "null" for null.For all other values, the CLASSNAME-part is extracted from [object CLASSNAME], which is the result of using Object.prototype.toString.call(value).
getAnyClass() behaves the same as getNativeClass(), but also supports custom constructors
function getNativeClass(obj) {
if (typeof obj === "undefined") return "undefined";
if (obj === null) return "null";
return Object.prototype.toString.call(obj).match(/^\[object\s(.*)\]$/)[1];
}
function getAnyClass(obj) {
if (typeof obj === "undefined") return "undefined";
if (obj === null) return "null";
return obj.constructor.name;
}
getClass("") === "String";
getClass(true) === "Boolean";
getClass(0) === "Number";
getClass([]) === "Array";
getClass({}) === "Object";
getClass(null) === "null";
getAnyClass(new (function Foo(){})) === "Foo";
getAnyClass(new class Foo{}) === "Foo";
// etc...
We can read Class's name of an instance by just doing 'instance.constructor.name' like in this example:
class Person {
type = "developer";
}
let p = new Person();
p.constructor.name // Person
To get the "pseudo class", you can get the constructor function, by
obj.constructor
assuming the constructor is set correctly when you do the inheritance -- which is by something like:
Dog.prototype = new Animal();
Dog.prototype.constructor = Dog;
and these two lines, together with:
var woofie = new Dog()
will make woofie.constructor point to Dog. Note that Dog is a constructor function, and is a Function object. But you can do if (woofie.constructor === Dog) { ... }.
If you want to get the class name as a string, I found the following working well:
http://blog.magnetiq.com/post/514962277/finding-out-class-names-of-javascript-objects
function getObjectClass(obj) {
if (obj && obj.constructor && obj.constructor.toString) {
var arr = obj.constructor.toString().match(
/function\s*(\w+)/);
if (arr && arr.length == 2) {
return arr[1];
}
}
return undefined;
}
It gets to the constructor function, converts it to string, and extracts the name of the constructor function.
Note that obj.constructor.name could have worked well, but it is not standard. It is on Chrome and Firefox, but not on IE, including IE 9 or IE 10 RTM.
You can get a reference to the constructor function which created the object by using the constructor property:
function MyObject(){
}
var obj = new MyObject();
obj.constructor; // MyObject
If you need to confirm the type of an object at runtime you can use the instanceof operator:
obj instanceof MyObject // true
i had a situation to work generic now and used this:
class Test {
// your class definition
}
nameByType = function(type){
return type.prototype["constructor"]["name"];
};
console.log(nameByType(Test));
thats the only way i found to get the class name by type input if you don't have a instance of an object.
(written in ES2017)
dot notation also works fine
console.log(Test.prototype.constructor.name); // returns "Test"
In keeping with its unbroken record of backwards-compatibility, ECMAScript 6, JavaScript still doesn't have a class type (though not everyone understands this). It does have a class keyword as part of its class syntax for creating prototypes—but still no thing called class. JavaScript is not now and has never been a classical OOP language. Speaking of JS in terms of class is only either misleading or a sign of not yet grokking prototypical inheritance (just keeping it real).
That means this.constructor is still a great way to get a reference to the constructor function. And this.constructor.prototype is the way to access the prototype itself. Since this isn't Java, it's not a class. It's the prototype object your instance was instantiated from. Here is an example using the ES6 syntactic sugar for creating a prototype chain:
class Foo {
get foo () {
console.info(this.constructor, this.constructor.name)
return 'foo'
}
}
class Bar extends Foo {
get foo () {
console.info('[THIS]', this.constructor, this.constructor.name, Object.getOwnPropertyNames(this.constructor.prototype))
console.info('[SUPER]', super.constructor, super.constructor.name, Object.getOwnPropertyNames(super.constructor.prototype))
return `${super.foo} + bar`
}
}
const bar = new Bar()
console.dir(bar.foo)
This is what that outputs using babel-node:
> $ babel-node ./foo.js ⬡ 6.2.0 [±master ●]
[THIS] [Function: Bar] 'Bar' [ 'constructor', 'foo' ]
[SUPER] [Function: Foo] 'Foo' [ 'constructor', 'foo' ]
[Function: Bar] 'Bar'
'foo + bar'
There you have it! In 2016, there's a class keyword in JavaScript, but still no class type. this.constructor is the best way to get the constructor function, this.constructor.prototype the best way to get access to the prototype itself.
For Javascript Classes in ES6 you can use object.constructor. In the example class below the getClass() method returns the ES6 class as you would expect:
var Cat = class {
meow() {
console.log("meow!");
}
getClass() {
return this.constructor;
}
}
var fluffy = new Cat();
...
var AlsoCat = fluffy.getClass();
var ruffles = new AlsoCat();
ruffles.meow(); // "meow!"
If you instantiate the class from the getClass method make sure you wrap it in brackets e.g. ruffles = new ( fluffy.getClass() )( args... );
If you need to not only GET class but also EXTEND it from having just an instance, write:
let's have
class A{
constructor(name){
this.name = name
}
};
const a1 = new A('hello a1');
so to extend A having the instance only use:
const a2 = new (Object.getPrototypeOf(a1)).constructor('hello from a2')
// the analog of const a2 = new A()
console.log(a2.name)//'hello from a2'
I find object.constructor.toString() return [object objectClass] in IE ,rather than function objectClass () {} returned in chome. So,I think the code in http://blog.magnetiq.com/post/514962277/finding-out-class-names-of-javascript-objects may not work well in IE.And I fixed the code as follows:
code:
var getObjectClass = function (obj) {
if (obj && obj.constructor && obj.constructor.toString()) {
/*
* for browsers which have name property in the constructor
* of the object,such as chrome
*/
if(obj.constructor.name) {
return obj.constructor.name;
}
var str = obj.constructor.toString();
/*
* executed if the return of object.constructor.toString() is
* "[object objectClass]"
*/
if(str.charAt(0) == '[')
{
var arr = str.match(/\[\w+\s*(\w+)\]/);
} else {
/*
* executed if the return of object.constructor.toString() is
* "function objectClass () {}"
* for IE Firefox
*/
var arr = str.match(/function\s*(\w+)/);
}
if (arr && arr.length == 2) {
return arr[1];
}
}
return undefined;
};
In javascript, there are no classes, but I think that you want the constructor name and obj.constructor.toString() will tell you what you need.
getClass() function using constructor.prototype.name
I found a way to access the class that is much cleaner than some of the solutions above; here it is.
function getClass(obj) {
// if the type is not an object return the type
if((let type = typeof obj) !== 'object') return type;
//otherwise, access the class using obj.constructor.name
else return obj.constructor.name;
}
How it works
the constructor has a property called name accessing that will give you the class name.
cleaner version of the code:
function getClass(obj) {
// if the type is not an object return the type
let type = typeof obj
if((type !== 'object')) {
return type;
} else { //otherwise, access the class using obj.constructor.name
return obj.constructor.name;
}
}
Agree with dfa, that's why i consider the prototye as the class when no named class found
Here is an upgraded function of the one posted by Eli Grey, to match my way of mind
function what(obj){
if(typeof(obj)==="undefined")return "undefined";
if(obj===null)return "Null";
var res = Object.prototype.toString.call(obj).match(/^\[object\s(.*)\]$/)[1];
if(res==="Object"){
res = obj.constructor.name;
if(typeof(res)!='string' || res.length==0){
if(obj instanceof jQuery)return "jQuery";// jQuery build stranges Objects
if(obj instanceof Array)return "Array";// Array prototype is very sneaky
return "Object";
}
}
return res;
}
Here's a implementation of getClass() and getInstance()
You are able to get a reference for an Object's class using this.constructor.
From an instance context:
function A() {
this.getClass = function() {
return this.constructor;
}
this.getNewInstance = function() {
return new this.constructor;
}
}
var a = new A();
console.log(a.getClass()); // function A { // etc... }
// you can even:
var b = new (a.getClass());
console.log(b instanceof A); // true
var c = a.getNewInstance();
console.log(c instanceof A); // true
From static context:
function A() {};
A.getClass = function() {
return this;
}
A.getInstance() {
return new this;
}
Don't use o.constructor because it can be changed by the object content. Instead, use Object.getPrototypeOf()?.constructor.
const fakedArray = JSON.parse('{ "constructor": { "name": "Array" } }');
// returns 'Array', which is faked.
fakedArray.constructor.name;
// returns 'Object' as expected
Object.getPrototypeOf(fakedArray)?.constructor?.name;
I suggest using Object.prototype.constructor.name:
Object.defineProperty(Object.prototype, "getClass", {
value: function() {
return this.constructor.name;
}
});
var x = new DOMParser();
console.log(x.getClass()); // `DOMParser'
var y = new Error("");
console.log(y.getClass()); // `Error'
You can also do something like this
class Hello {
constructor(){
}
}
function isClass (func) {
return typeof func === 'function' && /^class\s/.test(Function.prototype.toString.call(func))
}
console.log(isClass(Hello))
This will tell you if the input is class or not
If you have access to an instance of the class Foo (say foo = new Foo()) then there is exactly one way to get access to the the class from the instance: foo.Contructor in Javascript = foo.getClass() in Java.
eval() is another way, but since eval() is never recommended and works for everything (analogous to Java reflection), that answer is not recommended. foo.Constructor = Foo
Javascript is a class-less languages: there are no classes that defines the behaviour of a class statically as in Java. JavaScript uses prototypes instead of classes for defining object properties, including methods, and inheritance. It is possible to simulate many class-based features with prototypes in JavaScript.
Question seems already answered but the OP wants to access the class of and object, just like we do in Java and the selected answer is not enough (imho).
With the following explanation, we can get a class of an object(it's actually called prototype in javascript).
var arr = new Array('red', 'green', 'blue');
var arr2 = new Array('white', 'black', 'orange');
You can add a property like this:
Object.defineProperty(arr,'last', {
get: function(){
return this[this.length -1];
}
});
console.log(arr.last) // blue
But .last property will only be available to 'arr' object which is instantiated from Array prototype. So, in order to have the .last property to be available for all objects instantiated from Array prototype, we have to define the .last property for Array prototype:
Object.defineProperty(Array.prototype,'last', {
get: function(){
return this[this.length -1];
}
});
console.log(arr.last) // blue
console.log(arr2.last) // orange
The problem here is, you have to know which object type (prototype) the 'arr' and 'arr2' variables belongs to! In other words, if you don't know class type (prototype) of the 'arr' object, then you won't be able to define a property for them. In the above example, we know arr is instance of the Array object, that's why we used Array.prototype to define a property for Array. But what if we didn't know the class(prototype) of the 'arr'?
Object.defineProperty(arr.__proto__,'last2', {
get: function(){
return this[this.length -1];
}
});
console.log(arr.last) // blue
console.log(arr2.last) // orange
As you can see, without knowing that 'arr' is an Array, we can add a new property just bu referring the class of the 'arr' by using 'arr.__proto__'.
We accessed the prototype of the 'arr' without knowing that it's an instance of Array and I think that's what OP asked.
There is one another technique to identify your class
You can store ref to your class in instance like below.
class MyClass {
static myStaticProperty = 'default';
constructor() {
this.__class__ = new.target;
this.showStaticProperty = function() {
console.log(this.__class__.myStaticProperty);
}
}
}
class MyChildClass extends MyClass {
static myStaticProperty = 'custom';
}
let myClass = new MyClass();
let child = new MyChildClass();
myClass.showStaticProperty(); // default
child.showStaticProperty(); // custom
myClass.__class__ === MyClass; // true
child.__class__ === MyClass; // false
child.__class__ === MyChildClass; // true

How to check if a variable is an ES6 class declaration?

I am exporting the following ES6 class from one module:
export class Thingy {
hello() {
console.log("A");
}
world() {
console.log("B");
}
}
And importing it from another module:
import {Thingy} from "thingy";
if (isClass(Thingy)) {
// Do something...
}
How can I check whether a variable is a class? Not a class instance, but a class declaration?
In other words, how would I implement the isClass function in the example above?
If you want to ensure that the value is not only a function, but really a constructor function for a class, you can convert the function to a string and inspect its representation. The spec dictates the string representation of a class constructor.
function isClass(v) {
return typeof v === 'function' && /^\s*class\s+/.test(v.toString());
}
Another solution would be to try to call the value as a normal function. Class constructors are not callable as normal functions, but error messages probably vary between browsers:
function isClass(v) {
if (typeof v !== 'function') {
return false;
}
try {
v();
return false;
} catch(error) {
if (/^Class constructor/.test(error.message)) {
return true;
}
return false;
}
}
The disadvantage is that invoking the function can have all kinds of unknown side effects...
I'll make it clear up front here, any arbitrary function can be a constructor. If you are distinguishing between "class" and "function", you are making poor API design choices. If you assume something must be a class for instance, no-one using Babel or Typescript will be be detected as a class because their code will have been converted to a function instead. It means you are mandating that anyone using your codebase must be running in an ES6 environment in general, so your code will be unusable on older environments.
Your options here are limited to implementation-defined behavior. In ES6, once code is parsed and the syntax is processed, there isn't much class-specific behavior left. All you have is a constructor function. Your best choice is to do
if (typeof Thingy === 'function'){
// It's a function, so it definitely can't be an instance.
} else {
// It could be anything other than a constructor
}
and if someone needs to do a non-constructor function, expose a separate API for that.
Obviously that is not the answer you are looking for, but it's important to make that clear.
As the other answer here mentions, you do have an option because .toString() on functions is required to return a class declaration, e.g.
class Foo {}
Foo.toString() === "class Foo {}" // true
The key thing, however, is that that only applies if it can. It is 100% spec compliant for an implementation to have
class Foo{}
Foo.toString() === "throw SyntaxError();"
No browsers currently do that, but there are several embedded systems that focus on JS programming for instance, and to preserve memory for your program itself, they discard the source code once it has been parsed, meaning they will have no source code to return from .toString() and that is allowed.
Similarly, by using .toString() you are making assumptions about both future-proofing, and general API design. Say you do
const isClass = fn => /^\s*class/.test(fn.toString());
because this relies on string representations, it could easily break.
Take decorators for example:
#decorator class Foo {}
Foo.toString() == ???
Does the .toString() of this include the decorator? What if the decorator itself returns a function instead of a class?
Checking the prototype and its writability should allow to determine the type of function without stringifying, calling or instantiating the input.
/**
* determine if a variable is a class definition or function (and what kind)
* #revised
*/
function isFunction(x) {
return typeof x === 'function'
? x.prototype
? Object.getOwnPropertyDescriptor(x, 'prototype').writable
? 'function'
: 'class'
: x.constructor.name === 'AsyncFunction'
? 'async'
: 'arrow'
: '';
}
console.log({
string: isFunction('foo'), // => ''
null: isFunction(null), // => ''
class: isFunction(class C {}), // => 'class'
function: isFunction(function f() {}), // => 'function'
arrow: isFunction(() => {}), // => 'arrow'
async: isFunction(async function () {}) // => 'async'
});
There are subtle differences between a function and a class, and we can take this advantage to distinguish between them, the following is my implementation:
// is "class" or "function"?
function isClass(obj) {
// if not a function, return false.
if (typeof obj !== 'function') return false;
// ⭐ is a function, has a `prototype`, and can't be deleted!
// ⭐ although a function's prototype is writable (can be reassigned),
// it's not configurable (can't update property flags), so it
// will remain writable.
//
// ⭐ a class's prototype is non-writable.
//
// Table: property flags of function/class prototype
// ---------------------------------
// prototype write enum config
// ---------------------------------
// function v . .
// class . . .
// ---------------------------------
const descriptor = Object.getOwnPropertyDescriptor(obj, 'prototype');
// ❗functions like `Promise.resolve` do have NO `prototype`.
// (I have no idea why this is happening, sorry.)
if (!descriptor) return false;
return !descriptor.writable;
}
Here are some test cases:
class A { }
function F(name) { this.name = name; }
isClass(F), // ❌ false
isClass(3), // ❌ false
isClass(Promise.resolve), // ❌ false
isClass(A), // ✅ true
isClass(Object), // ✅ true
What about:
function isClass(v) {
return typeof v === 'function' && v.prototype.constructor === v;
}
This solution fixes two false positives with Felix's answer:
It works with anonymous classes that don't have space before the class body:
isClass(class{}) // true
It works with native classes:
isClass(Promise) // true
isClass(Proxy) // true
function isClass(value) {
return typeof value === 'function' && (
/^\s*class[^\w]+/.test(value.toString()) ||
// 1. native classes don't have `class` in their name
// 2. However, they are globals and start with a capital letter.
(globalThis[value.name] === value && /^[A-Z]/.test(value.name))
);
}
const A = class{};
class B {}
function f() {}
console.log(isClass(A)); // true
console.log(isClass(B)); // true
console.log(isClass(Promise)); // true
console.log(isClass(Promise.resolve)); // false
console.log(isClass(f)); // false
Shortcomings
Sadly, it still won't work with node built-in (and probably many other platform-specific) classes, e.g.:
const EventEmitter = require('events');
console.log(isClass(EventEmitter)); // `false`, but should be `true` :(
Well going through some of the answers and thinks to #Joe Hildebrand for highlighting edge case thus following solution is updated to reflect most tried edge cases. Open to more identification where edge cases may rest.
Key insights: although we are getting into classes but just like pointers and references debate in JS does not confirm to all the qualities of other languages - JS as such does not have classes as we have in other language constructs.
some debate it is sugar coat syntax of function and some argue other wise. I believe classes are still a function underneath but not so much so as sugar coated but more so as something that could be put on steroids. Classes will do what functions can not do or didn't bother upgrading them to do.
So dealing with classes as function for the time being open up another Pandora box. Everything in JS is object and everything JS does not understand but is willing to go along with the developer is an object e.g.
Booleans can be objects (if defined with the new keyword)
Numbers can be objects (if defined with the new keyword)
Strings can be objects (if defined with the new keyword)
Dates are always objects
Maths are always objects
Regular expressions are always objects
Arrays are always objects
Functions are always objects
Objects are always objects
Then what the heck are Classes?
Important Classes are a template for creating objects they are not object per say them self at this point.
They become object when you create an instance of the class somewhere, that instance is considered an object.
So with out freaking out we need to sift out
which type of object we are dealing with
Then we need to sift out its properties.
functions are always objects they will always have prototype and arguments property.
arrow function are actually sugar coat of old school function and have no concept of this or more the simple return context so no prototype or arguments even if you attempt at defining them.
classes are kind of blue print of possible function dont have arguments property but have prototypes. these prototypes become after the fact object upon instance.
So i have attempted to capture and log each iteration we check and result of course.
Hope this helps
'use strict';
var isclass,AA,AAA,BB,BBB,BBBB,DD,DDD,E,F;
isclass=function(a) {
if(/null|undefined/.test(a)) return false;
let types = typeof a;
let props = Object.getOwnPropertyNames(a);
console.log(`type: ${types} props: ${props}`);
return ((!props.includes('arguments') && props.includes('prototype')));}
class A{};
class B{constructor(brand) {
this.carname = brand;}};
function C(){};
function D(a){
this.a = a;};
AA = A;
AAA = new A;
BB = B;
BBB = new B;
BBBB = new B('cheking');
DD = D;
DDD = new D('cheking');
E= (a) => a;
F=class {};
console.log('and A is class: '+isclass(A)+'\n'+'-------');
console.log('and AA as ref to A is class: '+isclass(AA)+'\n'+'-------');
console.log('and AAA instance of is class: '+isclass(AAA)+'\n'+'-------');
console.log('and B with implicit constructor is class: '+isclass(B)+'\n'+'-------');
console.log('and BB as ref to B is class: '+isclass(BB)+'\n'+'-------');
console.log('and BBB as instance of B is class: '+isclass(BBB)+'\n'+'-------');
console.log('and BBBB as instance of B is class: '+isclass(BBBB)+'\n'+'-------');
console.log('and C as function is class: '+isclass(C)+'\n'+'-------');
console.log('and D as function method is class: '+isclass(D)+'\n'+'-------');
console.log('and DD as ref to D is class: '+isclass(DD)+'\n'+'-------');
console.log('and DDD as instance of D is class: '+isclass(DDD)+'\n'+'-------');
console.log('and E as arrow function is class: '+isclass(E)+'\n'+'-------');
console.log('and F as variable class is class: '+isclass(F)+'\n'+'-------');
console.log('and isclass as variable function is class: '+isclass(isclass)+'\n'+'-------');
console.log('and 4 as number is class: '+isclass(4)+'\n'+'-------');
console.log('and 4 as string is class: '+isclass('4')+'\n'+'-------');
console.log('and DOMI\'s string is class: '+isclass('class Im a class. Do you believe me?')+'\n'+'-------');
shorter cleaner function covering strict mode, es6 modules, null, undefined and what ever not property manipulation on object.
What I have found so far is since from above discussion classes are blue print not as such object on their own before the fact of instance. Thus running toString function would almost always produce class {} output not [object object] after the instance and so on. Once we know what is consistent then simply run regex test to see if result starts with word class.
"use strict"
let isclass = a =>{
return (!!a && /^class.*{}/.test(a.toString()))
}
class A {}
class HOO {}
let B=A;
let C=new A;
Object.defineProperty(HOO, 'arguments', {
value: 42,
writable: false
});
console.log(isclass(A));
console.log(isclass(B));
console.log(isclass(C));
console.log(isclass(HOO));
console.log(isclass());
console.log(isclass(null));
console.log(HOO.toString());
//proxiy discussion
console.log(Proxy.toString());
//HOO was class and returned true but if we proxify it has been converted to an object
HOO = new Proxy(HOO, {});
console.log(isclass(HOO));
console.log(HOO.toString());
console.log(isclass('class Im a class. Do you believe me?'));
Lead from DOMI's disucssion
class A {
static hello (){console.log('hello')}
hello () {console.log('hello there')}
}
A.hello();
B = new A;
B.hello();
console.log('it gets even more funnier it is properties and prototype mashing');
class C {
constructor() {
this.hello = C.hello;
}
static hello (){console.log('hello')}
}
C.say = ()=>{console.log('I said something')}
C.prototype.shout = ()=>{console.log('I am shouting')}
C.hello();
D = new C;
D.hello();
D.say();//would throw error as it is not prototype and is not passed with instance
C.say();//would not throw error since its property not prototype
C.shout();//would throw error as it is prototype and is passed with instance but is completly aloof from property of static
D.shout();//would not throw error
console.log('its a whole new ball game ctaching these but gassumption is class will always have protoype to be termed as class');
I'm shocked lodash didnt have the answer. Check this out - Just like Domi I just came up with a solution to fix the glitches. I know its a lot of code but its the most working yet understandable thing I could produce by now. Maybe someone can optimize it by a regex-approach:
function isClass(asset) {
const string_match = "function";
const is_fn = !!(typeof asset === string_match);
if(!is_fn){
return false;
}else{
const has_constructor = is_fn && !!(asset.prototype && asset.prototype.constructor && asset.prototype.constructor === asset);
const code = !asset.toString ? "" : asset.toString();
if(has_constructor && !code.startsWith(string_match)){
return true;
}
if(has_constructor && code.startsWith(string_match+"(")){
return false;
}
const [keyword, name] = code.split(" ");
if(name && name[0] && name[0].toLowerCase && name[0].toLowerCase() != name[0]){
return true;
}else{
return false;
}
}
}
Just test it with:
console.log({
_s:isClass(String),
_a:isClass(Array),
_o:isClass(Object),
_c:isClass(class{}),
fn:isClass(function(){}),
fnn:isClass(function namedFunction(){}),
fnc:isClass(()=>{}),
n:isClass(null),
o:isClass({}),
a:isClass([]),
s:isClass(""),
n:isClass(2),
u:isClass(undefined),
b:isClass(false),
pr:isClass(Promise),
px:isClass(Proxy)
});
Just make sure all classes have a frist uppercased letter.
Maybe this can help
let is_class = (obj) => {
try {
new obj();
return true;
} catch(e) {
return false;
};
};

How do I inherit javascript functions ?

// Don't break the function prototype.
// pd - https://github.com/Raynos/pd
var proto = Object.create(Function.prototype, pd({
"prop": 42
}));
var f = function() { return "is a function"; };
f.__proto__ = proto;
console.log(f.hasOwnProperty("prop")); // false
console.log(f.prop); // 42
console.log(f()); // "is a function"
.__proto__ is non-standard and deprecated.
How am I supposed to inherit prototypically creating an object but having that object be a function.
Object.create returns an Object not a Function.
new Constructor returns an Object not a Function.
Motivation: - A cross-browser finherit
var finherit = function (parent, child) {
var f = function() {
parent.apply(this, arguments);
child.apply(this, arguments);
};
f.__proto__ = parent;
Object.keys(child).forEach(function _copy(key) {
f[key] = child[key];
});
return f;
};
I don't believe this is possible, so we should probably propose a Function.create to the es-discuss mailing list
/*
Creates a new function whose prototype is proto.
The function body is the same as the function fbody.
The hash of propertydescriptors props is passed to defineproperties just like
Object.create does.
*/
Function.create = (function() {
var functionBody = function _getFunctionBody(f) {
return f.toString().replace(/.+\{/, "").replace(/\}$/, "");
};
var letters = "abcdefghijklmnopqrstuvwxyz".split("");
return function _create(proto, fbody, props) {
var parameters = letters.slice(0, fbody.length);
parameters.push(functionBody(fbody));
var f = Function.apply(this, parameters);
f.__proto__ = proto;
Object.defineProperties(f, props);
return f;
};
})();
Related es-discuss mail
As mentioned in the es-discuss thread there exists a ES:strawman <| prototype operator which would allow for this.
Let's see what it would look like using <|
var f1 = function () {
console.log("do things");
};
f1.method = function() { return 42; };
var f2 = f1 <| function () {
super();
console.log("do more things");
}
console.log(f1.isPrototypeOf(f2)); // true
console.log(f2()); // do things do more things
console.log(f2.hasOwnProperty("method")); // false
console.log(f2.method()); // 42
I hope that I'm understanding this right.
I believe you want a functor that's both an instance of a predefined prototype (yes, a class, just not a classic class) as well as directly callable? Right? If so, then this makes perfect sense and is very powerful and flexible (especially in a highly asynchronous environment like JavaScript). Sadly there is no way to do it elegantly in JavaScript without manipulating __proto__. You can do it by factoring out an anonymous function and copying all of the references to all of the methods (which seems to be the direction you were heading) to act as a proxy class. The downsides to this are...
It's very costly in terms of runtime.
(functorObj instanceof MyClass) will never be true.
Properties will not be directly accessible (if they were all assigned by reference this would be a different story, but primitives are assigned by value). This can be solved with accessors via defineProperty or simply named accessor methods if necessary (it appears that that is what you're looking for, just add all properties to the functor with defineProperty via getters/setters instead of just functions if you don't need cross-engine support/backwards compatability).
You're likely to run into edge cases where final native prototypes (like Object.prototype or Array.prototype [if you're inheriting that]) may not function as expected.
Calling functorObj(someArg) will always make the this context be the object, regardless of if it's called functorObj.call(someOtherObj, someArg) (this is not the case for method calls though)
Because the functor object is created at request time, it will be locked in time and manipulating the initial prototype will not affect the allocated functor objects like a normal object would be affected (modifying MyClass.prototype will not affect any functor objects and the reverse is true as well).
If you use it gently though, none of this should be a big deal.
In your prototype of your class define something like...
// This is you're emulated "overloaded" call() operator.
MyClass.prototype.execute = function() {
alert('I have been called like a function but have (semi-)proper access to this!');
};
MyClass.prototype.asFunctor = function(/* templateFunction */) {
if ((typeof arguments[0] !== 'function') && (typeof this.execute !== 'function'))
throw new TypeError('You really should define the calling operator for a functor shouldn\'t you?');
// This is both the resulting functor proxy object as well as the proxy call function
var res = function() {
var ret;
if (res.templateFunction !== null)
// the this context here could be res.asObject, or res, or whatever your goal is here
ret = res.templateFunction.call(this, arguments);
if (typeof res.asObject.execute === 'function')
ret = res.asObject.execute.apply(res.asObject, arguments);
return ret;
};
res.asObject = this;
res.templateFunction = (typeof arguments[0] === 'function') ? arguments[0] : null;
for (var k in this) {
if (typeof this[k] === 'function') {
res[k] = (function(reference) {
var m = function() {
return m.proxyReference.apply((this === res) ? res.asObject : this, arguments);
};
m.proxyReference = reference;
return m;
})(this.asObject[k]);
}
}
return res;
};
Resulting usage would look something like...
var aobj = new MyClass();
var afunctor = aobj.asFunctor();
aobj.someMethodOfMine(); // << works
afunctor.someMethodOfMine(); // << works exactly like the previous call (including the this context).
afunctor('hello'); // << works by calling aobj.execute('hello');
(aobj instanceof MyClass) // << true
(afunctor instanceof MyClass) // << false
(afunctor.asObject === aobj) // << true
// to bind with a previous function...
var afunctor = (new MyClass()).asFunctor(function() { alert('I am the original call'); });
afunctor() // << first calls the original, then execute();
// To simply wrap a previous function, don't define execute() in the prototype.
You could even chain bind countless other objects/functions/etc until the cows came home. Just refactor the proxy call a bit.
Hope that helps. Oh, and of course you could change the factory flow so that a constructor called without the new operator then instantiates a new object and returns the functor object. However you prefer (you could surely do it other ways too).
Finally, to have any function become the execution operator for a functor in a bit more elegant of a manner, just make the proxy function a method of Function.prototype and pass it the object to wrap if you want to do something like (you would have to swap templateFunction with this and this with the argument of course)...
var functor = (function() { /* something */ }).asFunctor(aobj);
With ES6 it's possible to inherit from Function, see (duplicate) question
javascript class inherit from Function class
default export Attribute extends Function {
...
}

Function overloading in Javascript - Best practices [closed]

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What is the best way(s) to fake function overloading in Javascript?
I know it is not possible to overload functions in Javascript as in other languages.
If I needed a function with two uses foo(x) and foo(x,y,z) which is the best / preferred way:
Using different names in the first place
Using optional arguments like y = y || 'default'
Using number of arguments
Checking types of arguments
Or how?
The best way to do function overloading with parameters is not to check the argument length or the types; checking the types will just make your code slow and you have the fun of Arrays, nulls, Objects, etc.
What most developers do is tack on an object as the last argument to their methods. This object can hold anything.
function foo(a, b, opts) {
// ...
if (opts['test']) { } //if test param exists, do something..
}
foo(1, 2, {"method":"add"});
foo(3, 4, {"test":"equals", "bar":"tree"});
Then you can handle it anyway you want in your method. [Switch, if-else, etc.]
I often do this:
C#:
public string CatStrings(string p1) {return p1;}
public string CatStrings(string p1, int p2) {return p1+p2.ToString();}
public string CatStrings(string p1, int p2, bool p3) {return p1+p2.ToString()+p3.ToString();}
CatStrings("one"); // result = one
CatStrings("one",2); // result = one2
CatStrings("one",2,true); // result = one2true
JavaScript Equivalent:
function CatStrings(p1, p2, p3)
{
var s = p1;
if(typeof p2 !== "undefined") {s += p2;}
if(typeof p3 !== "undefined") {s += p3;}
return s;
};
CatStrings("one"); // result = one
CatStrings("one",2); // result = one2
CatStrings("one",2,true); // result = one2true
This particular example is actually more elegant in javascript than C#. Parameters which are not specified are 'undefined' in javascript, which evaluates to false in an if statement. However, the function definition does not convey the information that p2 and p3 are optional. If you need a lot of overloading, jQuery has decided to use an object as the parameter, for example, jQuery.ajax(options). I agree with them that this is the most powerful and clearly documentable approach to overloading, but I rarely need more than one or two quick optional parameters.
EDIT: changed IF test per Ian's suggestion
There is no real function overloading in JavaScript since it allows to pass any number of parameters of any type. You have to check inside the function how many arguments have been passed and what type they are.
The correct answer is THERE IS NO OVERLOADING IN JAVASCRIPT.
Checking / Switching inside the function is not OVERLOADING.
The concept of overloading:
In some programming languages, function overloading or method overloading is the ability to create multiple methods of the same name with different implementations. Calls to an overloaded function will run a specific implementation of that function appropriate to the context of the call, allowing one function call to perform different tasks depending on context.
For example, doTask() and doTask(object O) are overloaded methods. To call the latter, an object must be passed as a parameter, whereas the former does not require a parameter, and is called with an empty parameter field. A common error would be to assign a default value to the object in the second method, which would result in an ambiguous call error, as the compiler wouldn't know which of the two methods to use.
https://en.wikipedia.org/wiki/Function_overloading
All suggested implementations are great, but truth to be told, there is no native implementation for JavaScript.
There are two ways you could approach this better:
Pass a dictionary (associative array) if you want to leave a lot of flexibility
Take an object as the argument and use prototype based inheritance to add flexibility.
Here is an approach that allows real method overloading using parameter types, shown below:
Func(new Point());
Func(new Dimension());
Func(new Dimension(), new Point());
Func(0, 0, 0, 0);
Edit (2018): Since this was written in 2011, the speed of direct method calls has greatly increased while the speed of overloaded methods have not.
It is not an approach I would recommend, but it is a worthwhile thought exercise to think about how you can solve these types of problems.
Here is a benchmark of the different approaches - https://jsperf.com/function-overloading. It shows that function overloading (taking types into account) can be around 13 times slower in Google Chrome's V8 as of 16.0(beta).
As well as passing an object (i.e. {x: 0, y: 0}), one can also take the C approach when appropriate, naming the methods accordingly. For example, Vector.AddVector(vector), Vector.AddIntegers(x, y, z, ...) and Vector.AddArray(integerArray). You can look at C libraries, such as OpenGL for naming inspiration.
Edit: I've added a benchmark for passing an object and testing for the object using both 'param' in arg and arg.hasOwnProperty('param'), and function overloading is much faster than passing an object and checking for properties (in this benchmark at least).
From a design perspective, function overloading is only valid or logical if the overloaded parameters correspond to the same action. So it stands to reason that there ought to be an underlying method that is only concerned with specific details, otherwise that may indicate inappropriate design choices. So one could also resolve the use of function overloading by converting data to a respective object. Of course one must consider the scope of the problem as there's no need in making elaborate designs if your intention is just to print a name, but for the design of frameworks and libraries such thought is justified.
My example comes from a Rectangle implementation - hence the mention of Dimension and Point. Perhaps Rectangle could add a GetRectangle() method to the Dimension and Point prototype, and then the function overloading issue is sorted. And what about primitives? Well, we have argument length, which is now a valid test since objects have a GetRectangle() method.
function Dimension() {}
function Point() {}
var Util = {};
Util.Redirect = function (args, func) {
'use strict';
var REDIRECT_ARGUMENT_COUNT = 2;
if(arguments.length - REDIRECT_ARGUMENT_COUNT !== args.length) {
return null;
}
for(var i = REDIRECT_ARGUMENT_COUNT; i < arguments.length; ++i) {
var argsIndex = i-REDIRECT_ARGUMENT_COUNT;
var currentArgument = args[argsIndex];
var currentType = arguments[i];
if(typeof(currentType) === 'object') {
currentType = currentType.constructor;
}
if(typeof(currentType) === 'number') {
currentType = 'number';
}
if(typeof(currentType) === 'string' && currentType === '') {
currentType = 'string';
}
if(typeof(currentType) === 'function') {
if(!(currentArgument instanceof currentType)) {
return null;
}
} else {
if(typeof(currentArgument) !== currentType) {
return null;
}
}
}
return [func.apply(this, args)];
}
function FuncPoint(point) {}
function FuncDimension(dimension) {}
function FuncDimensionPoint(dimension, point) {}
function FuncXYWidthHeight(x, y, width, height) { }
function Func() {
Util.Redirect(arguments, FuncPoint, Point);
Util.Redirect(arguments, FuncDimension, Dimension);
Util.Redirect(arguments, FuncDimensionPoint, Dimension, Point);
Util.Redirect(arguments, FuncXYWidthHeight, 0, 0, 0, 0);
}
Func(new Point());
Func(new Dimension());
Func(new Dimension(), new Point());
Func(0, 0, 0, 0);
The best way really depends on the function and the arguments. Each of your options is a good idea in different situations. I generally try these in the following order until one of them works:
Using optional arguments like y = y || 'default'. This is convenient if you can do it, but it may not always work practically, e.g. when 0/null/undefined would be a valid argument.
Using number of arguments. Similar to the last option but may work when #1 doesn't work.
Checking types of arguments. This can work in some cases where the number of arguments is the same. If you can't reliably determine the types, you may need to use different names.
Using different names in the first place. You may need to do this if the other options won't work, aren't practical, or for consistency with other related functions.
If I needed a function with two uses foo(x) and foo(x,y,z) which is the best / preferred way?
The issue is that JavaScript does NOT natively support method overloading. So, if it sees/parses two or more functions with a same names it’ll just consider the last defined function and overwrite the previous ones.
One of the way I think is suitable for most of the case is follows -
Lets say you have method
function foo(x)
{
}
Instead of overloading method which is not possible in javascript you can define a new method
fooNew(x,y,z)
{
}
and then modify the 1st function as follows -
function foo(arguments)
{
if(arguments.length==2)
{
return fooNew(arguments[0], arguments[1]);
}
}
If you have many such overloaded methods consider using switch than just if-else statements.
I'm not sure about best practice, but here is how I do it:
/*
* Object Constructor
*/
var foo = function(x) {
this.x = x;
};
/*
* Object Protoype
*/
foo.prototype = {
/*
* f is the name that is going to be used to call the various overloaded versions
*/
f: function() {
/*
* Save 'this' in order to use it inside the overloaded functions
* because there 'this' has a different meaning.
*/
var that = this;
/*
* Define three overloaded functions
*/
var f1 = function(arg1) {
console.log("f1 called with " + arg1);
return arg1 + that.x;
}
var f2 = function(arg1, arg2) {
console.log("f2 called with " + arg1 + " and " + arg2);
return arg1 + arg2 + that.x;
}
var f3 = function(arg1) {
console.log("f3 called with [" + arg1[0] + ", " + arg1[1] + "]");
return arg1[0] + arg1[1];
}
/*
* Use the arguments array-like object to decide which function to execute when calling f(...)
*/
if (arguments.length === 1 && !Array.isArray(arguments[0])) {
return f1(arguments[0]);
} else if (arguments.length === 2) {
return f2(arguments[0], arguments[1]);
} else if (arguments.length === 1 && Array.isArray(arguments[0])) {
return f3(arguments[0]);
}
}
}
/*
* Instantiate an object
*/
var obj = new foo("z");
/*
* Call the overloaded functions using f(...)
*/
console.log(obj.f("x")); // executes f1, returns "xz"
console.log(obj.f("x", "y")); // executes f2, returns "xyz"
console.log(obj.f(["x", "y"])); // executes f3, returns "xy"
Not everybody knows that you can do Destructuring assignment directly in a function signature.
Thanks to that you can easily define a very flexible method signature, which is, IMHO, superior to Java method overloading.
Example:
const myFunction = (({a, b, c}) => {
console.log(a, b, c);
});
myFunction({a: 1, b: 2});
myFunction({a: 1, b: 2, c: 3});
You don't even need to respect the order of the parameters, and there is naming consistency between the calling statement and the target method signature.
You can also assign default values:
const myFunction = (({a = 1, b = 2, c} = {}) => {
console.log(a, b, c);
});
I just tried this, maybe it suits your needs.
Depending on the number of the arguments, you can access a different function. You initialize it the first time you call it.
And the function map is hidden in the closure.
TEST = {};
TEST.multiFn = function(){
// function map for our overloads
var fnMap = {};
fnMap[0] = function(){
console.log("nothing here");
return this; // support chaining
}
fnMap[1] = function(arg1){
// CODE here...
console.log("1 arg: "+arg1);
return this;
};
fnMap[2] = function(arg1, arg2){
// CODE here...
console.log("2 args: "+arg1+", "+arg2);
return this;
};
fnMap[3] = function(arg1,arg2,arg3){
// CODE here...
console.log("3 args: "+arg1+", "+arg2+", "+arg3);
return this;
};
console.log("multiFn is now initialized");
// redefine the function using the fnMap in the closure
this.multiFn = function(){
fnMap[arguments.length].apply(this, arguments);
return this;
};
// call the function since this code will only run once
this.multiFn.apply(this, arguments);
return this;
};
Test it.
TEST.multiFn("0")
.multiFn()
.multiFn("0","1","2");
INTRODUCTION
So far reading through so many answers would give anyone a headache. Anyone trying to know the concept would need to know the following prerequisites.
Function overloading Definition, Function Length property, Function argument property
Function overloading in its simplest form means that a function performs different tasks on the basis of number of arguments that are being passed to it. Notably the TASK1, TASK2 and TASK3 are highlighted below and are being performed on the basis of the number of arguments being passed to the same function fooYo.
// if we have a function defined below
function fooYo(){
// do something here
}
// on invoking fooYo with different number of arguments it should be capable to do different things
fooYo(); // does TASK1
fooYo('sagar'); // does TASK2
fooYo('sagar','munjal'); // does TAKS3
NOTE
- JS does not provide inbuilt ability of function overloading.
Alternative
John E Resig (creator of JS) has pointed out an alternative which uses the above prerequisites to achieve the ability to implement function overloading.
The code below uses a straightforward but naive approach by using if-else or switch statement.
evaluates the argument-length property.
different values result in invocation of different functions.
var ninja = {
whatever: function() {
switch (arguments.length) {
case 0:
/* do something */
break;
case 1:
/* do something else */
break;
case 2:
/* do yet something else */
break;
//and so on ...
}
}
}
Another technique is much more clean and dynamic. The highlight of this technique is the addMethod generic function.
we define a function addMethod which is used to add different functions to an object with the same name but different functionalities.
below the addMethod function accepts three params object name object, function name name and the function that we want to be invoked fn.
Inside addMethod definition var old stores the reference to the previous function being stored by the help of closure - a protective bubble.
function addMethod(object, name, fn) {
var old = object[name];
object[name] = function(){
if (fn.length == arguments.length)
return fn.apply(this, arguments)
else if (typeof old == 'function')
return old.apply(this, arguments);
};
};
use debugger to understand the code flow.
below the addMethod adds three functions which when invoked using ninja.whatever(x) with the number of arguments x which can be anything i.e. either blank or one or more than one invokes different functions as defined while making use of the addMethod function.
var ninja = {};
debugger;
addMethod(ninja,'whatever',function(){ console.log("I am the one with ZERO arguments supplied") });
addMethod(ninja,'whatever',function(a){ console.log("I am the one with ONE arguments supplied") });
addMethod(ninja,'whatever',function(a,b){ console.log("I am the one with TWO arguments supplied") });
ninja.whatever();
ninja.whatever(1,2);
ninja.whatever(3);
Since JavaScript doesn't have function overload options object can be used instead. If there are one or two required arguments, it's better to keep them separate from the options object. Here is an example on how to use options object and populated values to default value in case if value was not passed in options object.
function optionsObjectTest(x, y, opts) {
opts = opts || {}; // default to an empty options object
var stringValue = opts.stringValue || "string default value";
var boolValue = !!opts.boolValue; // coerces value to boolean with a double negation pattern
var numericValue = opts.numericValue === undefined ? 123 : opts.numericValue;
return "{x:" + x + ", y:" + y + ", stringValue:'" + stringValue + "', boolValue:" + boolValue + ", numericValue:" + numericValue + "}";
}
here is an example on how to use options object
check this out. It is very cool.
http://ejohn.org/blog/javascript-method-overloading/
Trick Javascript to allow you to do calls like this:
var users = new Users();
users.find(); // Finds all
users.find("John"); // Finds users by name
users.find("John", "Resig"); // Finds users by first and last name
There is no way to function overloading in javascript.
So, I recommend like the following by typeof() method instead of
multiple function to fake overloading.
function multiTypeFunc(param)
{
if(typeof param == 'string') {
alert("I got a string type parameter!!");
}else if(typeof param == 'number') {
alert("I got a number type parameter!!");
}else if(typeof param == 'boolean') {
alert("I got a boolean type parameter!!");
}else if(typeof param == 'object') {
alert("I got a object type parameter!!");
}else{
alert("error : the parameter is undefined or null!!");
}
}
Good luck!
Another way to approach this is by using the special variable: arguments, this is an implementation:
function sum() {
var x = 0;
for (var i = 0; i < arguments.length; ++i) {
x += arguments[i];
}
return x;
}
so you can modify this code to:
function sum(){
var s = 0;
if (typeof arguments[0] !== "undefined") s += arguments[0];
.
.
.
return s;
}
You can now do function overloading in ECMAScript 2018 without polyfills, checking var length/type, etc., just use the spread syntax.
function foo(var1, var2, opts){
// set default values for parameters
const defaultOpts = {
a: [1,2,3],
b: true,
c: 0.3289,
d: "str",
}
// merge default and passed-in parameters
// defaultOpts must go first!
const mergedOpts = {...defaultOpts, ...opts};
// you can now refer to parameters like b as mergedOpts.b,
// or just assign mergedOpts.b to b
console.log(mergedOpts.a);
console.log(mergedOpts.b);
console.log(mergedOpts.c);
console.log(mergedOpts.d);
}
// the parameters you passed in override the default ones
// all JS types are supported: primitives, objects, arrays, functions, etc.
let var1, var2="random var";
foo(var1, var2, {a: [1,2], d: "differentString"});
// parameter values inside foo:
//a: [1,2]
//b: true
//c: 0.3289
//d: "differentString"
What is spread syntax?
The Rest/Spread Properties for ECMAScript proposal (stage 4) adds spread properties to object literals. It copies own enumerable properties from a provided object onto a new object.
More on mdn
Note: spread syntax in object literals doesn't work in Edge and IE and it is an experimental feature. see browser compatability
#Forwarding Pattern => the best practice on JS overloading
Forward to another function which name is built from the 3rd & 4th points :
Using number of arguments
Checking types of arguments
window['foo_'+arguments.length+'_'+Array.from(arguments).map((arg)=>typeof arg).join('_')](...arguments)
#Application on your case :
function foo(...args){
return window['foo_' + args.length+'_'+Array.from(args).map((arg)=>typeof arg).join('_')](...args);
}
//------Assuming that `x` , `y` and `z` are String when calling `foo` .
/**-- for : foo(x)*/
function foo_1_string(){
}
/**-- for : foo(x,y,z) ---*/
function foo_3_string_string_string(){
}
#Other Complex Sample :
function foo(...args){
return window['foo_'+args.length+'_'+Array.from(args).map((arg)=>typeof arg).join('_')](...args);
}
/** one argument & this argument is string */
function foo_1_string(){
}
//------------
/** one argument & this argument is object */
function foo_1_object(){
}
//----------
/** two arguments & those arguments are both string */
function foo_2_string_string(){
}
//--------
/** Three arguments & those arguments are : id(number),name(string), callback(function) */
function foo_3_number_string_function(){
let args=arguments;
new Person(args[0],args[1]).onReady(args[3]);
}
//--- And so on ....
As this post already contains a lot of different solutions i thought i post another one.
function onlyUnique(value, index, self) {
return self.indexOf(value) === index;
}
function overload() {
var functions = arguments;
var nroffunctionsarguments = [arguments.length];
for (var i = 0; i < arguments.length; i++) {
nroffunctionsarguments[i] = arguments[i].length;
}
var unique = nroffunctionsarguments.filter(onlyUnique);
if (unique.length === arguments.length) {
return function () {
var indexoffunction = nroffunctionsarguments.indexOf(arguments.length);
return functions[indexoffunction].apply(this, arguments);
}
}
else throw new TypeError("There are multiple functions with the same number of parameters");
}
this can be used as shown below:
var createVector = overload(
function (length) {
return { x: length / 1.414, y: length / 1.414 };
},
function (a, b) {
return { x: a, y: b };
},
function (a, b,c) {
return { x: a, y: b, z:c};
}
);
console.log(createVector(3, 4));
console.log(createVector(3, 4,5));
console.log(createVector(7.07));
This solution is not perfect but i only want to demonstrate how it could be done.
You can user the 'addMethod' from John Resig. With this method you can "overload" methods based on arguments count.
// addMethod - By John Resig (MIT Licensed)
function addMethod(object, name, fn){
var old = object[ name ];
object[ name ] = function(){
if ( fn.length == arguments.length )
return fn.apply( this, arguments );
else if ( typeof old == 'function' )
return old.apply( this, arguments );
};
}
I have also created an alternative to this method that uses caching to hold the variations of the function. The differencies are described here
// addMethod - By Stavros Ioannidis
function addMethod(obj, name, fn) {
obj[name] = obj[name] || function() {
// get the cached method with arguments.length arguments
var method = obj[name].cache[arguments.length];
// if method exists call it
if ( !! method)
return method.apply(this, arguments);
else throw new Error("Wrong number of arguments");
};
// initialize obj[name].cache
obj[name].cache = obj[name].cache || {};
// Check if a method with the same number of arguments exists
if ( !! obj[name].cache[fn.length])
throw new Error("Cannot define multiple '" + name +
"' methods with the same number of arguments!");
// cache the method with fn.length arguments
obj[name].cache[fn.length] = function() {
return fn.apply(this, arguments);
};
}
Function Overloading via Dynamic Polymorphism in 100 lines of JS
VanillaJS, no external dependencies
Full Browser Support - Array.prototype.slice, Object.prototype.toString
1114 bytes uglify'd / 744 bytes g-zipped
This is from a larger body of code which includes the isFn, isArr, etc. type checking functions. The VanillaJS version below has been reworked to remove all external dependencies, however you will have to define you're own type checking functions for use in the .add() calls.
Note: This is a self-executing function (so we can have a closure/closed scope), hence the assignment to window.overload rather than function overload() {...}.
window.overload = function () {
"use strict"
var a_fnOverloads = [],
_Object_prototype_toString = Object.prototype.toString
;
function isFn(f) {
return (_Object_prototype_toString.call(f) === '[object Function]');
} //# isFn
function isObj(o) {
return !!(o && o === Object(o));
} //# isObj
function isArr(a) {
return (_Object_prototype_toString.call(a) === '[object Array]');
} //# isArr
function mkArr(a) {
return Array.prototype.slice.call(a);
} //# mkArr
function fnCall(fn, vContext, vArguments) {
//# <ES5 Support for array-like objects
//# See: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Function/apply#Browser_compatibility
vArguments = (isArr(vArguments) ? vArguments : mkArr(vArguments));
if (isFn(fn)) {
return fn.apply(vContext || this, vArguments);
}
} //# fnCall
//#
function registerAlias(fnOverload, fn, sAlias) {
//#
if (sAlias && !fnOverload[sAlias]) {
fnOverload[sAlias] = fn;
}
} //# registerAlias
//#
function overload(vOptions) {
var oData = (isFn(vOptions) ?
{ default: vOptions } :
(isObj(vOptions) ?
vOptions :
{
default: function (/*arguments*/) {
throw "Overload not found for arguments: [" + mkArr(arguments) + "]";
}
}
)
),
fnOverload = function (/*arguments*/) {
var oEntry, i, j,
a = arguments,
oArgumentTests = oData[a.length] || []
;
//# Traverse the oArgumentTests for the number of passed a(rguments), defaulting the oEntry at the beginning of each loop
for (i = 0; i < oArgumentTests.length; i++) {
oEntry = oArgumentTests[i];
//# Traverse the passed a(rguments), if a .test for the current oArgumentTests fails, reset oEntry and fall from the a(rgument)s loop
for (j = 0; j < a.length; j++) {
if (!oArgumentTests[i].tests[j](a[j])) {
oEntry = undefined;
break;
}
}
//# If all of the a(rgument)s passed the .tests we found our oEntry, so break from the oArgumentTests loop
if (oEntry) {
break;
}
}
//# If we found our oEntry above, .fn.call its .fn
if (oEntry) {
oEntry.calls++;
return fnCall(oEntry.fn, this, a);
}
//# Else we were unable to find a matching oArgumentTests oEntry, so .fn.call our .default
else {
return fnCall(oData.default, this, a);
}
} //# fnOverload
;
//#
fnOverload.add = function (fn, a_vArgumentTests, sAlias) {
var i,
bValid = isFn(fn),
iLen = (isArr(a_vArgumentTests) ? a_vArgumentTests.length : 0)
;
//#
if (bValid) {
//# Traverse the a_vArgumentTests, processinge each to ensure they are functions (or references to )
for (i = 0; i < iLen; i++) {
if (!isFn(a_vArgumentTests[i])) {
bValid = _false;
}
}
}
//# If the a_vArgumentTests are bValid, set the info into oData under the a_vArgumentTests's iLen
if (bValid) {
oData[iLen] = oData[iLen] || [];
oData[iLen].push({
fn: fn,
tests: a_vArgumentTests,
calls: 0
});
//#
registerAlias(fnOverload, fn, sAlias);
return fnOverload;
}
//# Else one of the passed arguments was not bValid, so throw the error
else {
throw "poly.overload: All tests must be functions or strings referencing `is.*`.";
}
}; //# overload*.add
//#
fnOverload.list = function (iArgumentCount) {
return (arguments.length > 0 ? oData[iArgumentCount] || [] : oData);
}; //# overload*.list
//#
a_fnOverloads.push(fnOverload);
registerAlias(fnOverload, oData.default, "default");
return fnOverload;
} //# overload
//#
overload.is = function (fnTarget) {
return (a_fnOverloads.indexOf(fnTarget) > -1);
} //# overload.is
return overload;
}();
Usage:
The caller defines their overloaded functions by assigning a variable to the return of overload(). Thanks to chaining, the additional overloads can be defined in series:
var myOverloadedFn = overload(function(){ console.log("default", arguments) })
.add(function(){ console.log("noArgs", arguments) }, [], "noArgs")
.add(function(){ console.log("str", arguments) }, [function(s){ return typeof s === 'string' }], "str")
;
The single optional argument to overload() defines the "default" function to call if the signature cannot be identified. The arguments to .add() are:
fn: function defining the overload;
a_vArgumentTests: Array of functions defining the tests to run on the arguments. Each function accepts a single argument and returns truethy based on if the argument is valid;
sAlias (Optional): string defining the alias to directly access the overload function (fn), e.g. myOverloadedFn.noArgs() will call that function directly, avoiding the dynamic polymorphism tests of the arguments.
This implementation actually allows for more than just traditional function overloads as the second a_vArgumentTests argument to .add() in practice defines custom types. So, you could gate arguments not only based on type, but on ranges, values or collections of values!
If you look through the 145 lines of code for overload() you'll see that each signature is categorized by the number of arguments passed to it. This is done so that we're limiting the number of tests we are running. I also keep track of a call count. With some additional code, the arrays of overloaded functions could be re-sorted so that more commonly called functions are tested first, again adding some measure of performance enhancement.
Now, there are some caveats... As Javascript is loosely typed, you will have to be careful with your vArgumentTests as an integer could be validated as a float, etc.
JSCompress.com version (1114 bytes, 744 bytes g-zipped):
window.overload=function(){'use strict';function b(n){return'[object Function]'===m.call(n)}function c(n){return!!(n&&n===Object(n))}function d(n){return'[object Array]'===m.call(n)}function e(n){return Array.prototype.slice.call(n)}function g(n,p,q){if(q=d(q)?q:e(q),b(n))return n.apply(p||this,q)}function h(n,p,q){q&&!n[q]&&(n[q]=p)}function k(n){var p=b(n)?{default:n}:c(n)?n:{default:function(){throw'Overload not found for arguments: ['+e(arguments)+']'}},q=function(){var r,s,t,u=arguments,v=p[u.length]||[];for(s=0;s<v.length;s++){for(r=v[s],t=0;t<u.length;t++)if(!v[s].tests[t](u[t])){r=void 0;break}if(r)break}return r?(r.calls++,g(r.fn,this,u)):g(p.default,this,u)};return q.add=function(r,s,t){var u,v=b(r),w=d(s)?s.length:0;if(v)for(u=0;u<w;u++)b(s[u])||(v=_false);if(v)return p[w]=p[w]||[],p[w].push({fn:r,tests:s,calls:0}),h(q,r,t),q;throw'poly.overload: All tests must be functions or strings referencing `is.*`.'},q.list=function(r){return 0<arguments.length?p[r]||[]:p},l.push(q),h(q,p.default,'default'),q}var l=[],m=Object.prototype.toString;return k.is=function(n){return-1<l.indexOf(n)},k}();
there is no actual overloading in JS, anyway we still can simulate method overloading in several ways:
method #1:
use object
function test(x,options){
if("a" in options)doSomething();
else if("b" in options)doSomethingElse();
}
test("ok",{a:1});
test("ok",{b:"string"});
method #2:
use rest (spread) parameters
function test(x,...p){
if(p[2])console.log("3 params passed"); //or if(typeof p[2]=="string")
else if (p[1])console.log("2 params passed");
else console.log("1 param passed");
}
method #3:
use undefined
function test(x, y, z){
if(typeof(z)=="undefined")doSomething();
}
method #4:
type checking
function test(x){
if(typeof(x)=="string")console.log("a string passed")
else ...
}
Something like this can be done for function overloading.
function addCSS(el, prop, val) {
return {
2: function() {
// when two arguments are set
// now prop is an oject
for (var i in prop) {
el.style[i] = prop[i];
}
},
3: function() {
// when three arguments are set
el.style[prop] = val;
}
}[arguments.length]();
}
// usage
var el = document.getElementById("demo");
addCSS(el, "color", "blue");
addCSS(el, {
"backgroundColor": "black",
"padding": "10px"
});
Source
Function overloading in Javascript:
Function overloading is the ability of a programming language to create multiple functions of the same name with different implementations. when an overloaded function is called it will run function a specific implementation of that function appropriate to the context of the call. This context is usually the amount of arguments is receives, and it allows one function call to behave differently depending on context.
Javascript doesn't have built-in function overloading. However, this behaviour can be emulated in many ways. Here is a convenient simple one:
function sayHi(a, b) {
console.log('hi there ' + a);
if (b) { console.log('and ' + b) } // if the parameter is present, execute the block
}
sayHi('Frank', 'Willem');
In scenarios where you don't know how many arguments you will be getting you can use the rest operator which is three dots .... It will convert the remainder of the arguments into an array. Beware of browser compatibilty though. Here is an example:
function foo (a, ...b) {
console.log(b);
}
foo(1,2,3,4);
foo(1,2);
While Default parameters is not overloading, it might solve some of the issues that developers face in this area. The input is strictly decided by the order, you can not re-order as you wish as in classical overloading:
function transformer(
firstNumber = 1,
secondNumber = new Date().getFullYear(),
transform = function multiply(firstNumber, secondNumber) {
return firstNumber * secondNumber;
}
) {
return transform(firstNumber, secondNumber);
}
console.info(transformer());
console.info(transformer(8));
console.info(transformer(2, 6));
console.info(transformer(undefined, 65));
function add(firstNumber, secondNumber) {
return firstNumber + secondNumber;
}
console.info(transformer(undefined, undefined, add));
console.info(transformer(3, undefined, add));
Results in (for year 2020):
2020
16160
12
65
2021
2023
More info: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Functions/Default_parameters
The Typescript Handbook mentions Overloads. While checking types and doing different logic based on results has been mentioned before, this approach defining multiple named functions to work with a typing system might be interesting to readers. Here is how TypeScript achieves creating a function that accepts multiple types of arguments that will direct the function logic to do different things based on incoming arguments and types:
The answer is to supply multiple function types for the same function as a list of overloads. This list is what the compiler will use to resolve function calls. Let’s create a list of overloads that describe what our pickCard accepts and what it returns.
let suits = ["hearts", "spades", "clubs", "diamonds"];
function pickCard(x: { suit: string; card: number }[]): number;
function pickCard(x: number): { suit: string; card: number };
function pickCard(x: any): any {
// Check to see if we're working with an object/array
// if so, they gave us the deck and we'll pick the card
if (typeof x == "object") {
let pickedCard = Math.floor(Math.random() * x.length);
return pickedCard;
}
// Otherwise just let them pick the card
else if (typeof x == "number") {
let pickedSuit = Math.floor(x / 13);
return { suit: suits[pickedSuit], card: x % 13 };
}
}
let myDeck = [
{ suit: "diamonds", card: 2 },
{ suit: "spades", card: 10 },
{ suit: "hearts", card: 4 },
];
let pickedCard1 = myDeck[pickCard(myDeck)];
alert("card: " + pickedCard1.card + " of " + pickedCard1.suit);
let pickedCard2 = pickCard(15);
alert("card: " + pickedCard2.card + " of " + pickedCard2.suit);
With this change, the overloads now give us type checked calls to the pickCard function.
In order for the compiler to pick the correct type check, it follows a similar process to the underlying JavaScript. It looks at the overload list and, proceeding with the first overload, attempts to call the function with the provided parameters. If it finds a match, it picks this overload as the correct overload. For this reason, it’s customary to order overloads from most specific to least specific.
Note that the function pickCard(x): any piece is not part of the overload list, so it only has two overloads: one that takes an object and one that takes a number. Calling pickCard with any other parameter types would cause an error.
We made over.js to solve this problem is a very elegant way. You can do:
var obj = {
/**
* Says something in the console.
*
* say(msg) - Says something once.
* say(msg, times) - Says something many times.
*/
say: Over(
function(msg$string){
console.info(msg$string);
},
function(msg$string, times$number){
for (var i = 0; i < times$number; i++) this.say(msg$string);
}
)
};
This is an old question but one that I think needs another entry (although I doubt anyone will read it). The use of Immediately Invoked Function Expressions (IIFE) can be used in conjunction with closures and inline functions to allow for function overloading. Consider the following (contrived) example:
var foo;
// original 'foo' definition
foo = function(a) {
console.log("a: " + a);
}
// define 'foo' to accept two arguments
foo = (function() {
// store a reference to the previous definition of 'foo'
var old = foo;
// use inline function so that you can refer to it internally
return function newFoo(a,b) {
// check that the arguments.length == the number of arguments
// defined for 'newFoo'
if (arguments.length == newFoo.length) {
console.log("a: " + a);
console.log("b: " + b);
// else if 'old' is a function, apply it to the arguments
} else if (({}).toString.call(old) === '[object Function]') {
old.apply(null, arguments);
}
}
})();
foo(1);
> a: 1
foo(1,2);
> a: 1
> b: 2
foo(1,2,3)
> a: 1
In short, the use of the IIFE creates a local scope, allowing us to define the private variable old to store a reference to the initial definition of the function foo. This function then returns an inline function newFoo that logs the contents of both two arguments if it is passed exactly two arguments a and b or calls the old function if arguments.length !== 2. This pattern can be repeated any number of times to endow one variable with several different functional defitions.
I would like to share a useful example of overloaded-like approach.
function Clear(control)
{
var o = typeof control !== "undefined" ? control : document.body;
var children = o.childNodes;
while (o.childNodes.length > 0)
o.removeChild(o.firstChild);
}
Usage:
Clear(); // Clears all the document
Clear(myDiv); // Clears panel referenced by myDiv
JavaScript is untyped language, and I only think that makes sense to overload a method/function with regards to the number of params. Hence, I would recommend to check if the parameter has been defined:
myFunction = function(a, b, c) {
if (b === undefined && c === undefined ){
// do x...
}
else {
// do y...
}
};

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