I have an HTML form as shown below with some form fields and a submit and a delete button:
There is also a floating component which appears whenever there are changes in the form as shown in the same diagram with text: You have unsaved changes. This is a common component which appears for all the forms in my website.
When I submit the form using the form's Submit button, it validates all the fields as per the validations.
(for example: <input type="number" min="0"> will check that the number should be positive)
But if I submit the form from the Save button on the floating element, it does not checks for any validation, and just posts the request.
I tried using the following code, but the reportValidity() function doesn't do anything.
if (!form.checkValidity()) {
form.reportValidity();
}
form.checkValidity() and form.reportValidity() both are returning false when I do a console.log.
What am I missing here, and how can I fix this?
P.S. I tried this on chrome v98.
Edit: Adding HTML code:
<form method="post" action="/products/manage/{{.Product.ID}}/submit/">
<div class="form-group col-md-5">
<label>Product Quantity</label>
<input type="number" min="0" name="ProductQuantity" value="{{if .Product}}{{.Product.Qunatity}}{{else}}10{{end}}">
</div>
<button type="submit" class="btn btn-success" value="Submit">Submit</button>
<button type="submit" class="btn btn-danger" value="Delete" formaction="/products/manage/{{.Product.ID}}/delete/">Delete</button>
</form>
Save button calls this function:
function submitForm(form, url) {
const form = $(form)[0]
if (!form.checkValidity()) { //<- Added the code here
form.reportValidity();
}
var serialized = serializeForm(form);
// Do some more things then use HTTP to request the API
}
You can easily use the jQuery event handlers do the work for you.
A simplified example below:
Give your form some identifier (example: id="form1")
Catch the click event on button click
Trigger the submit event to submit that form
$('.unsavedChangesBtn').on('click',function(){
$('#form1').submit();
});
In below example you can submit the form either by clicking the submit button or the save button.
$('document').ready(function(){
$('#form1').on('submit',function(){
alert("SUBMITTED");
});
$('.unsavedChangesBtn').on('click',function(){
$('#form1').submit();
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form method="post" id="form1" action="javascript:void(0);">
<div class="form-group col-md-5">
<label>Product Quantity</label>
<input type="number" min="0" name="ProductQuantity" value="{{if .Product}}{{.Product.Qunatity}}{{else}}10{{end}}">
</div>
<button type="submit" class="btn btn-success" value="Submit">Submit</button>
<button type="submit" class="btn btn-danger" value="Delete" formaction="/products/manage/{{.Product.ID}}/delete/">Delete</button>
</form>
<button class="unsavedChangesBtn"> SAVE </button>
Related
I have form with required inputs, it actually sees empty field and shows message, but it calls function from submit button
<form action="">
<input required id="1" type="text">
<button type="submit" onclick="calculate()">Calculate</button>
</form>
An onclick listener will run whenever the button is clicked, no matter what.
You want the function to run only when the form starts to be submitted, so attach a submit listener to the form instead:
<form action="" onsubmit="calculate()">
<input required id="1" type="text">
<button type="submit">Calculate</button>
</form>
const calculate = (e) => {
console.log('calculating');
}
<form action="" onsubmit="calculate()">
<input required id="1" type="text">
<button type="submit">Calculate</button>
</form>
If at all possible, it would be much better to attach the event listener properly using Javascript instead of an inline HTML attribute:
document.querySelector('form').addEventListener('submit', calculate);
const calculate = (e) => {
e.preventDefault();
console.log('calculating');
};
document.querySelector('form').addEventListener('submit', calculate);
<form action="">
<input required id="1" type="text">
<button type="submit">Calculate</button>
</form>
I am using sweatalert2, when the form submitted sweatalert2 is coming but it closing with any press button (OK button) it close very fast. but when I use in a simple button without the form, it's working properly.
const sweatalert = () => {
return Swal('Good job!','You clicked the button!','success')
}
<!-- Include sweet alert 2. -->
<script src="https://cdnjs.cloudflare.com/ajax/libs/limonte-sweetalert2/7.32.4/sweetalert2.all.min.js"></script>
<form action="" method="post" enctype="multipart/form-data">
<input
type="submit"
name="addrecord"
class="btn btn-primary"
onclick="sweatalert()"
style="margin-left:100px;"
value="Add Record"
/>
</form>
<!-- Just here for visual purpose. -->
<hr/>
<p>Out side the form is OK.</p>
<input
type="submit"
name="addrecord"
class="btn btn-primary"
onclick="sweatalert()"
style="margin-left:100px;"
value="Add"
/>
This is happening because the form is submitting when you click the button. This means the page will refresh, and remove the alert generated. You can use e.preventDefault() to stop the submission from happening. You also need to make sure you pass the event through in your onclick callback:
onclick="sweatalert(event)"
See example below:
function sweatalert(e) {
e.preventDefault(); // stop default functionality of submission (ie. page refresh and data post)
swal(
'Good job!',
'You clicked the button!',
'success'
)
}
<script src="https://unpkg.com/sweetalert/dist/sweetalert.min.js"></script>
<form action="" method="post" enctype="multipart/form-data">
<button type="submit" name="addrecord" class="btn btn-primary" onclick="sweatalert(event)" style="margin-left:100px;">Add Record</button>
</form>
However, do note: This will stop the submission of the form occurring. If you want to submit the form and then display the alert after submitting your data to PHP you should use AJAX. If you use jQuery you can use $.post or $.ajax methods to send your data to PHP, and then use a callback function which will be called if your data was submitted successfully.
Swal returns a promise. Hence you need to prevent the default submit event and use .then() where you can submit() the form:
const sweatalert = (ele, evt) => {
evt.preventDefault();
Swal('Good job!','You clicked the button!','success').then((result) => {
ele.closest('form').submit(); // get the closest form and submit
});
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/limonte-sweetalert2/7.32.4/sweetalert2.all.min.js"></script>
<form action="" method="post" enctype="multipart/form-data">
<input
type="submit"
name="addrecord"
class="btn btn-primary"
onclick="sweatalert(this, event)"
style="margin-left:100px;"
value="Add Record"
/>
</form>
I am trying to create multiple forms which have two buttons, each will submit the form to different script, one via ajax and second one will just submit the form.
<?php foreach($objects as $object) : ?>
<div class="card-body">
<form id="edit-form" action="#" method="POST">
<input name="subject" value="<?=$object['subject']?>" type="text" id="title" class="input-xxlarge">
<textarea id="content" name="content" rows="25"><?=$object['content']?></textarea>
<button type="button" id="send-button" class="btn btn-primary">Send</button>
<input type="submit" id="submit-button" value="Submit"/>
</form>
</div>
<?php endforeach; ?>
First I am trying to get the current form, but I have problem with that. console.log shows something only on the first form, if I click on the buttons from other forms then It will do nothing.
$('#send-button').on('click', function(e) {
e.defaultPrevented;
$form = $(this);
$url = $form.attr('action');
$data = $form.serialize(); console.log($form);
console.log($url);
});
Is it because my button has same ID for every form ?
You shouln't use ID's multiple times on the same page. Try to use a class for that case. Also as stated in the comments use e.preventDefault(); to stop the event.
$(this) will result in the #send-button beeing targeted. To access the form you need to find the closest form element like this:
$form = $(this).closest('form');
html:
<form method="POST" action="#">
<input type="text">
<button type="button">send</button>
<input type="submit" value="submit" />
</form>
<form method="POST" action="#">
<input type="text">
<button type="button">send</button>
<input type="submit" value="submit" />
</form>
js:
$("form").each(function() {
var form = this;
$(form).find('button').on('click', function(e) {
e.preventDefault();
console.log(form);
console.log(this);
})
});
this will add events on every form you have on your page, button will submit form via script and submit will just submit it. also here's a fiddle to play with
I make some form different action within different button
<form id="form" method="post" class="form-horizontal" enctype="multipart/form-data">
<input name="name" class="form-control" type="text" required>
</form>
<button type="button" class="btn btn-primary" onClick="submitForm('<?php echo base_url('order/add');?>')">Submit</button>
<button type="button" class="btn btn-warning" onClick="submitForm('<?php echo base_url('order/print');?>')">Print</button>
Javascript
function submitForm(action)
{
document.getElementById('form').action = action;
document.getElementById('form').submit(
);
}
Then, my required attribute not working. Did I do something wrong? Let me know if there is other solution.
Thanks,
I can't give you a good explanation but you need the submit buttons inside the form.
So if you would have a button like:
<input type="submit" value="Submit">,
it will trigger the required attribute.
#Remn If you would still stay on your structure with submit inside a function you could trigger yourself the validation like:
if ($("form")[0].checkValidity())
{
$("form").submit()
}
and then do something with inputs that are invalid by passing through each required element ( input is set in code ):
$('form :input[required="required"]').each(function()
{
if(!this.validity.valid)
{
$(this).focus();
// break
return false;
}
});
In the below case the invalid inputs will be focused one by one.
The whole code is:
$( function () {
$("body").on("click", "#trigger", function() {
if ($("form")[0].checkValidity())
{
$("form").submit()
}
$('form :input[required="required"]').each(function()
{
if(!this.validity.valid)
{
$(this).focus();
// break
return false;
}
});
});
});
Where #trigger is an id I set on the button to submit, you can make your own functions to achieve your goal I just used on().
I hope it helps!
Please try bellow code. i hope solve your problem.
<html>
<head>
<title>Submit</title>
<script type="text/javascript" language="javascript">
function submitForm(action)
{
document.getElementById('form').action = action;
document.getElementById('form').submit(
);
//alert(document.getElementById('form').action);
}
</script>
</head>
<body>
<form id="form" method="get" class="form-horizontal" enctype="multipart/form-data">
<input name="name" class="form-control" type="text" required="required">
<button type="submit" class="btn btn-primary" onclick="return submitForm('<?php echo base_url('order/add');?>');" id="submit">Submit</button>
<button type="submit" class="btn btn-warning" onclick="return submitForm('<?php echo base_url('order/print');?>');" id="print">Print</button>
</form>
</body>
</html>
I have test your code by adding Javascript part in Script tag it is working fine. And i tested it on Chrome Windows 10.
<form id="form" method="post" class="form-horizontal" enctype="multipart/form-data">
<input name="name" class="form-control" type="text" required>
</form>
<button type="button" class="btn btn-primary" onClick="submitForm('<?php echo base_url('order/add'); ?>')">Submit</button>
<button type="button" class="btn btn-warning" onClick="submitForm('<?php echo base_url('order/print'); ?>')">Print</button>
<script>
function submitForm(action) {
document.getElementById('form').action = action;
document.getElementById('form').submit();
}
</script>
Using javascript's form.submit() function will cause input validation to be bypassed (according to the HTML specification in point 4 of the form submission algorithm). The only way to trigger HTML input validation is to use a click event on a submit button inside the form, either by the user actually clicking, or in javascript with something like form.querySelector('input[type="submit"]').click().
I am trying to disable a button on click, as well as change the text of the button. here is my code:
<input type="submit" value="Register" name="submit" id="submit" onClick="javascript:replaceButtonText('submit', 'Please wait...'); document.form1.submit.disabled=true;">
What is happening, is the button gets disabled, and the text changes, but the form does not do anything (submit). what am I doing wrong?
This works:
<html>
<body>
<form name="form1" method="post" action="myaction">
<input type="text" value="text1"/>
<input type="submit" value="Register" name="submit" id="submit"
onclick="javascript: replaceButtonText('submit1', 'Please wait...'); document.form1.submit.disabled=true; return true; ">
</form>
</body>
</html>
Form controls with a name are made available as named properties of the form they are in using their name. So:
document.form1.submit
refers to the button, not the submit method.
Writing:
< ... onclick="javascript:..." ...>
means that "javascript" is treated as a useless label, just don't do it. If you want the button to become disabled and change its label when the form is submitted, then use something like:
<form>
<input name=foo value=bar>
<input type="submit" onclick="
this.value='Please wait...';
this.disabled = true;
var theForm = this.form;
window.setTimeout(function(){theForm.submit();},1);
">
</form>
and let the form submit normally.
Of course the function in the onclick attribute should be a function call rather than a slab of code, but you get the idea.