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Referencing an existing function throws a ReferenceError [closed]

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Closed 5 days ago.
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I am trying to get the following script to work but it throws:
Uncaught ReferenceError: ZSOuput_account is not defined.
function ZSOutput_account(AccID) {
var accvar = AccID;
var urlRequest = 'https://1591725587001.contifico.com/sistema/reportes/cuentas/?pagina=1&cuenta=' + accvar + '&fecha_inicio=01/01/2022&fecha_fin=31/12/2022';
window.location.replace(urlRequest);
javascript:exportarExcel();
}
ZSOuput_account(2583907);
ZSOuput_account(2738049);

You are calling in a wrong way the function, it´s missing a ´t´ in your call

Unable to place unexpected identifier error [closed]

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Closed 2 years ago.
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Receiving the following error:
Uncaught SyntaxError: Unexpected identifier
The error states it is on this code line:
let whosUp = document.querySelector(#whosUp);
What is the unexpected identifier? Am I missing something? My complete function is below. I can include my entire file if necessary.
function whosUpFunc(){
let whosUp = document.querySelector(#whosUp);
if (gameOver === true){
whosUp.innerHTML = ""
}
else {whosUp.innerHTML = `Player ${currPlayer}'s turn`
};
}

The function document.querySelector expects a string as an argument. You're passing it #whosUp, which is triggering the SyntaxError.
let whosUp = document.querySelector(#whosUp);
Should be
let whosUp = document.getElementById('whosUp');

If statement and some() function in JS without arrow syntax [closed]

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Closed 4 years ago.
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Is it possible to write this if statement in JS without using arrow syntax?
// Arrow Syntax
if (!filters.some(e => e.label === filter_object.label))
{
// Do Something
}
// ? Not working...
if (!filters.some(function(e) { e.label === filter_object.label }))
{
// Do something
}

You need a return statement, because it is a classic function which returns undefined, if no different value is specified.
if (!filters.some(function(e) { return e.label === filter_object.label; })
// ^^^^^^

Basic Javascript i cannot understand [closed]

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Closed 8 years ago.
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var MyCountry = "trolling";
console.log(MyCountry).length;
console.log(MyCountry).substring(0, 3)
This is the error message I'm getting:
TypeError: 'undefined' is not an object (evaluating 'console.log(MyCountry).length')

You're putting .length and .substring on the result of console.log(), which is always undefined. Put them inside on the MyCountry instead.

This is what you want. You're closing your console.log() too soon both times.
var MyCountry = "trolling";
console.log(MyCountry.length);
console.log(MyCountry.substring(0, 3));

console.log() returns undefined, so you're calling .length on undefined.
If you want to log the length of MyCountry do console.log(MyCountry.length)
Also, console.log(MyCountry.substring(0, 3))

Function causes error [closed]

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Closed 8 years ago.
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I have created the mapWith function like this:
var mapWith=function(fn)
{
return funtion(list)
{
return Array.prototype.map.call(list,function(something){
return fn.call(this,something);
});
}
};
I use it on a function and an array:
var insertLatLong=function(obj)
{
//inserts to db...
}
var inception_cities=[{lat:35.0117,lng:135.7683},
{lat:48.8567,lng:2.3508},
{lat:-4.0500,lng:39.6667},
{lat:33.8600,lng:151.2111},
{lat:34.0500,lng:118.2500}];
var insertLocations=mapWith(insertLatLong);
insertLocations(inception_cities);
The error I get looks like this:
ReferenceError: list is not defined
at mapWith (/home/anr/Desktop/node js/mysql.js:11:17)
at Object.<anonymous> (/home/anr/Desktop/node js/mysql.js:40:21)

The error is caused because there's c missing in return funtion(list). Without it JavaScript thinks that you want to call something with name funtion. But you also want to pass list to it and since arguments are evaluated first then you get ReferenceError: it does not know what list is.