JavaScript simple call function behavior - javascript

I want to ask about call function behavior. I get stuck every time when I try to understand call function.
Can anybody help me to understand what is going on by suggesting implementation of the find method?
Hoge = function (val) {
this.val = val;
//console.log("this.val" + this.val);
};
Hoge.prototype.find = function (callback) {
callback.call(this.val);
};
var h = new Hoge(1);
h.find((o) => {
console.log(o); // expected 1 but undefined
console.log(o === 1); // expected true but its false (caz o is undefined)
});

You're not passing call a thisArg argument. Well, you are, but it's value you want passed to the callback.
Hoge = function(val) {
this.val = val;
//console.log("this.val" + this.val);
};
Hoge.prototype.find = function(callback) {
// callback.call(this.val);
callback.call(this, this.val); // call wants a "this" argument
// callback(this.val); // Could just do this instead
};
var h = new Hoge(1);
h.find((o) => {
console.log(o); // expected 1 but undefined
console.log(o === 1); // expected true but its false (caz o is undefined)
});

Function#call's first parameter is the this value. To directly invoke a function, just use parentheses.
callback(this.val);
Hoge = function (val) {
this.val = val;
};
Hoge.prototype.find = function (callback) {
callback(this.val);
};
var h = new Hoge(1);
h.find((o) => {
console.log(o);
console.log(o === 1);
});

The first param in call will be the new this you want to use. Then onwards are the params you want to pass.
You are basically not making a lot of use .call here, and if you simply want to use o you can pass null and this.val.
Even simpler, simply invoke the callback function
Hoge = function (val) {
this.val = val;
//console.log("this.val" + this.val);
};
Hoge.prototype.find = function (callback) {
//Both work
callback.call(null,this.val);
callback(this.val);
};
var h = new Hoge(1);
h.find((o) => {
console.log(o); // expected 1 but undefined
console.log(o === 1); // expected true but its false (caz o is undefined)
});

Related

Implementing a Number.prototype.loop(callback)

How to pass a reference of an argument, originally passed to a prototype function, on to a callback function which, too, is passed to the same prototype function?
The objective of the implementation is to loop for the value of the Number by executing the callback function.
Number.prototype.loop = function(index, callback) {
return Array(this).fill(0).forEach((e, i) => {
if(callback)
callback();
});
};
var num = 3;
num.loop(index, function(){
console.log(index);
});
Solution
Apparently, the reference to index is supposed to be passed directly to the callback function in order to indicate that the actual index property of the Array in the prototype function is to be passed to the callback function.
Number.prototype.loop = function(callback) {
return Array(this).fill(0).forEach((e, i) => {
if(callback)
callback(i);
});
};
var num = 3;
num.loop((index) => {
console.log(index);
});
There are 2 errors.
Pass the index i to callback in Number.prototype.loop function instead of the caller:
num.loop(index, function(index) { → num.loop(function(index) {
Number.prototype.loop = function(index, callback) { → Number.prototype.loop = function(callback) {
callback(); → callback(i);
Pass the numerical value of this instead of the instance itself to the Array constructor:
Array(this) → Array(this.valueOf())
Number.prototype.loop = function(callback) {
var num = this.valueOf();
return Array(num).fill(0).forEach((e, i) => {
if (callback)
callback(i);
});
};
var num = 3;
num.loop(function(index) {
console.log(index);
});
You can extend a Number native class with a function loop as the following. However, it is advised to not extend native as per this eslint's rule described.
Number.prototype.loop = function (callback) {
[...Array(this.valueOf())].forEach((_, idx) => {
callback(idx);
})
};
const num = 30;
num.loop((idx) => {
console.log(idx);
})

Shorthand to manipulate an object attribute and reassign

I have a deeply nested object and I want to manipulate a value of it and reassign it again. Is there a shorthand way for this other than writing it all out again or assigning it to a variable:
createStops[idx]['place']['create'][stop][key][value] = createStops[idx]['place']['create'][stop][key][value].toString()
looks ugly doesn't it? Something like:
createStops[idx]['place']['create'][stop][key][value].toStringAndReassign()
but JS built in.
Edit: In my case it is a number, if it's for your case too please check out #MarkMeyer answer.
No, there isn't.
Assigning a new value requires an assignment.
Strings are immutable, so you can't convert an existing value into a string in-place.
Given a value that's a number, if you just want it to be a string, you can coerce to a string with an assignment operator:
let o = {
akey: {
akey:{
value: 15
}
}
}
o.akey.akey.value += ''
console.log(o)
No,
Going to the same index is needed to store the value
Although it is not possible as mentioned by #Quentin you can define a custom getter in your object like:
var foo = {
a: 5,
b: 6,
get c () {
return this.b.toString()+' text'
}
};
console.log(foo.c);
You're not reassigning the value as you are semantically formatting your values. In order to format your value you are mutating your initial object. If you do not pretend to modify an object for formatting purposes that will work just fine.
You do not have integrated functions to use like that, but you could use of some utilitary functions of your own to help you manage assignements and make it less verbal.
SPOIL : The final use look like
// call the function to do +1 at the specified key
executeFunctionAtKey(
// The object to change the value on
createStops,
// The path
`${idx}.place.create.${stop}.${key}.${value}`,
// The thing to do
(x) => x + 1,
);
const createStops = {
idx: {
place: {
create: {
stop: {
key: {
value: 5,
},
},
},
},
},
};
const idx = 'idx';
const stop = 'stop';
const key = 'key';
const value = 'value';
// Function that go to the specified key and
// execute a function on it.
// The new value is the result of the func
// You can do your toString there, or anything else
function executeFunctionAtKey(obj, path, func) {
const keys = path.split('.');
if (keys.length === 1) {
obj[path] = func(obj[key]);
return obj;
}
const lastPtr = keys.slice(0, keys.length - 1).reduce((tmp, x) => tmp[x], obj);
lastPtr[keys[keys.length - 1]] = func(lastPtr[keys[keys.length - 1]]);
return obj;
}
// call the function to do +1 at the specified key
executeFunctionAtKey(
// The object to change the value on
createStops,
// The path
`${idx}.place.create.${stop}.${key}.${value}`,
// The thing to do
(x) => x + 1,
);
console.log(createStops);
with the toString example from Number to String
const createStops = {
idx: {
place: {
create: {
stop: {
key: {
value: 5,
},
},
},
},
},
};
const idx = 'idx';
const stop = 'stop';
const key = 'key';
const value = 'value';
// Function that go to the specified key and
// execute a function on it.
// The new value is the result of the func
// You can do your toString there, or anything else
function executeFunctionAtKey(obj, path, func) {
const keys = path.split('.');
if (keys.length === 1) {
obj[path] = func(obj[key]);
return obj;
}
const lastPtr = keys.slice(0, keys.length - 1).reduce((tmp, x) => tmp[x], obj);
lastPtr[keys[keys.length - 1]] = func(lastPtr[keys[keys.length - 1]]);
return obj;
}
// call the function to do +1 at the specified key
executeFunctionAtKey(
// The object to change the value on
createStops,
// The path
`${idx}.place.create.${stop}.${key}.${value}`,
// The thing to do
(x) => x.toString(),
);
console.log(createStops);
Theoretically you could build a function that takes an object, a path and the property to set it to.
This will reduce the readability of your code, so i would advice using ordinary assignment. But if you need it check out the snippet below:
//
function setProp(object, path, val) {
var parts = path.split("/").filter(function (p) { return p.length > 0; });
var pathIndex = 0;
var currentTarget = object;
while (pathIndex < parts.length - 1) {
currentTarget = currentTarget[parts[pathIndex]];
pathIndex++;
}
if (val instanceof Function) {
currentTarget[parts[pathIndex]] = val(currentTarget[parts[pathIndex]]);
}
else {
currentTarget[parts[pathIndex]] = val;
}
return object;
}
var createStops = {
idx: {
place: {
create: {
stop: {
key: {
value: 5
}
}
}
}
}
};
function toString(p) { return p.toString(); }
console.log(JSON.stringify(createStops, null, 4));
setProp(createStops, 'idx/place/create/stop/key/value', toString);
console.log(JSON.stringify(createStops, null, 4));
UPDATE 1
Allowed passing functions and used OP JSON structure for snippet

JavaScript compose functions

I am reading a book which contains the following example:
var composition1 = function(f, g) {
return function(x) {
return f(g(x));
}
};
Then the author writes: "...naive implementation of composition, because it does not take the execution context into account..."
So the preferred function is that one:
var composition2 = function(f, g) {
return function() {
return f.call(this, g.apply(this, arguments));
}
};
Followed by an entire example:
var composition2 = function composition2(f, g) {
return function() {
return f.call(this, g.apply(this, arguments));
}
};
var addFour = function addFour(x) {
return x + 4;
};
var timesSeven = function timesSeven(x) {
return x * 7;
};
var addFourtimesSeven2 = composition2(timesSeven, addFour);
var result2 = addFourtimesSeven2(2);
console.log(result2);
Could someone please explain to me why the composition2 function is the preferred one (maybe with an example)?
EDIT:
In the meantime i have tried to use methods as arguments as suggested, but it did not work. The result was NaN:
var composition1 = function composition1(f, g) {
return function(x) {
return f(g(x));
};
};
var composition2 = function composition2(f, g) {
return function() {
return f.call(this, g.apply(this, arguments));
}
};
var addFour = {
myMethod: function addFour(x) {
return x + this.number;
},
number: 4
};
var timesSeven = {
myMethod: function timesSeven(x) {
return x * this.number;
},
number: 7
};
var addFourtimesSeven1 = composition1(timesSeven.myMethod, addFour.myMethod);
var result1 = addFourtimesSeven1(2);
console.log(result1);
var addFourtimesSeven2 = composition2(timesSeven.myMethod, addFour.myMethod);
var result2 = addFourtimesSeven2(2);
console.log(result2);
This just answers what composition2 actually does:
composition2 is used when you want to keep this as context in the functions itself. The following example shows that the result is 60 by using data.a and data.b:
'use strict';
var multiply = function(value) {
return value * this.a;
}
var add = function(value) {
return value + this.b;
}
var data = {
a: 10,
b: 4,
func: composition2(multiply, add)
};
var result = data.func(2);
// uses 'data' as 'this' inside the 'add' and 'multiply' functions
// (2 + 4) * 10 = 60
But yet, it still breaks the following example (unfortunately):
'use strict';
function Foo() {
this.a = 10;
this.b = 4;
}
Foo.prototype.multiply = function(value) {
return value * this.a;
};
Foo.prototype.add = function(value) {
return value + this.b;
};
var foo = new Foo();
var func = composition2(foo.multiply, foo.add);
var result = func(2); // Uncaught TypeError: Cannot read property 'b' of undefined
Because the context of composition2 (this) is undefined (and is not called in any other way, such as .apply, .call or obj.func()), you'd end up with this being undefined in the functions as well.
On the other hand, we can give it another context by using the following code:
'use strict';
var foo = new Foo();
var data = {
a: 20,
b: 8,
func: composition2(foo.multiply, foo.add)
}
var result = data.func(2);
// uses 'data' as 'this'
// (2 + 8) * 10 = 200 :)
Or by explicitly setting the context:
'use strict';
var multiply = function(value) {
return value * this.a;
};
var add = function(value) {
return value + this.b;
};
var a = 20;
var b = 8;
var func = composition2(multiply, add);
// All the same
var result1 = this.func(2);
var result2 = func.call(this, 2);
var result3 = func.apply(this, [2]);
composition1 would not pass arguments other than the first to g()
If you do:
var composition1 = function(f, g) {
return function(x1, x2, x3) {
return f(g(x1, x2, x3));
}
};
the function will work for the first three arguments. If you however want it to work for an arbitrary number, you need to use Function.prototype.apply.
f.call(...) is used to set this as shown in Caramiriel's answer.
I disagree with the author.
Think of the use-case for function-composition. Most of the time I utilize function-composition for transformer-functions (pure functions; argument(s) in, result out and this is irrelevant).
2nd. Utilizing arguments the way he does it leads into a bad practice/dead end, because it implies that the function g() might depend on multiple arguments.
That means, that the composition I create is not composable anymore, because it might not get all arguments it needs.
composition that prevents composition; fail
(And as a side-effect: passing the arguments-object to any other function is a performance no-go, because the JS-engine can't optimize this anymore)
Take a look at the topic of partial application, usually misreferenced as currying in JS, wich is basically: unless all arguments are passed, the function returns another function that takes the remaining args; until I have all my arguments I need to process them.
Then you should rethink the way you implement argument-order, because this works best when you define them as configs-first, data-last.Example:
//a transformer: value in, lowercased string out
var toLowerCase = function(str){
return String(str).toLowerCase();
}
//the original function expects 3 arguments,
//two configs and the data to process.
var replace = curry(function(needle, heystack, str){
return String(str).replace(needle, heystack);
});
//now I pass a partially applied function to map() that only
//needs the data to process; this is really composable
arr.map( replace(/\s[A-Z]/g, toLowerCase) );
//or I create another utility by only applying the first argument
var replaceWhitespaceWith = replace(/\s+/g);
//and pass the remaining configs later
arr.map( replaceWhitespaceWith("-") );
A slightly different approach is to create functions that are, by design, not intended to get all arguments passed in one step, but one by one (or in meaningful groups)
var prepend = a => b => String(a) + String(b); //one by one
var substr = (from, to) => value => String(str).substr(from, to); //or grouped
arr.map( compose( prepend("foo"), substr(0, 5) ) );
arr.map( compose( prepend("bar"), substr(5) ) );
//and the `to`-argument is undefined; by intent
I don't intend to ever call such functions with all the arguments, all I want to pass them is their configs, and to get a function that does the job on the passed data/value.
Instead of substr(0, 5, someString), I would always write someString.substr(0, 5), so why take any efforts to make the last argument (data) applyable in the first call?

Get function parameter names without calling the function?

I know I can get the String representation of a function without calling it like this
function storeData(id, data) { console.log("Doing stuff..") };
storeData.toString(); //"function storeData(id, data) { console.log("Doing stuff..") }"
And I could in theory parse the resulting String to pull out the variable names. Any takers on writing that code? Is there an easier way? (I don't need to worry about minification)
try to use the following code:
var STRIP_COMMENTS = /((\/\/.*$)|(\/\*[\s\S]*?\*\/))/mg;
var ARGUMENT_NAMES = /([^\s,]+)/g;
function getParamNames(func) {
var fnStr = func.toString().replace(STRIP_COMMENTS, '');
var result = fnStr.slice(fnStr.indexOf('(') + 1, fnStr.indexOf(')')).match(ARGUMENT_NAMES);
if (result === null)
result = [];
return result;
}
getParamNames(getParamNames) // returns ['func']
getParamNames(function (a, b, c, d) { }) // returns ['a','b','c','d']
getParamNames(function (a,/*b,c,*/d) { }) // returns ['a','d']
getParamNames(function () { }) // returns []

how capture the arguments number need in a function (currying function partial application)

I am working on the curring function and partial application,
I am trying to improve the function schonfinkelize:
function schonfinkelize(fn){
var
slice = Array.prototype.slice,
stored_args = slice.call(arguments, 1);
return function(){
var
new_args = slice.call(arguments),
args = stored_args.concat(new_args);
return fn.apply(null, args);
}
}
This function permit to pass as argument a function and a part of the argument of the function passed as argument (partial application) so the first time you return a function and then when you fire the function again the result.
function add(x, y, z){
return x + y + z;
}
var val = schonfinkelize(add, 1, 2);
console.log( val(3) ) // console output--> 6
I want check inside schonfinkelize the number of arguments need to the function "add" (but it should work with every function) so I can choose when return another function or directly the result of the function "add".
bacause if I use schonfinkelize in this way:
var val2 = schonfinkelize(add, 1, 2, 3);
console.log( val2 ) // --> function
console.log( val2() ) // --> 6
I have to fire the function two time, instead a want avoid this behavior and define directly the value if the arguments are sufficient.
A possible solution could be the following:
function schonfinkelize(fn){
var
slice = Array.prototype.slice,
stored_args = slice.call(arguments, 1);
//* I have added this ********
if(fn.apply(null, stored_args))
return fn.apply(null, stored_args);
//****************************
return function(){
var
new_args = slice.call(arguments),
args = stored_args.concat(new_args);
return fn.apply(null, args);
}
}
Could be because it returns immediately the result if the fn.apply(null, stored_args) return something that is not "null" or "NaN" but I think is not really performant and then I want work with the arguments.
As long as you put in place a requirement that the parameters defined for the function passed reflect the actually number of arguments that are to be ultimately received, you can use the .length property of the function to do the comparison of passed arguments to anticipated arguments.
function schonfinkelize(fn) {
if (fn.length === arguments.length - 1)
return fn.apply(this, [].slice.call(arguments, 1));
var
slice = Array.prototype.slice,
stored_args = slice.call(arguments, 1);
return function(){
var
new_args = slice.call(arguments),
args = stored_args.concat(new_args);
return fn.apply(null, args);
}
}
Side note... you can avoid the .slice() if you cache the fn in a new variable, and overwrite the first argument with the this value, then use .call.apply()...
if (fn.length === arguments.length - 1) {
var func = fn;
arguments[0] = this;
return func.call.apply(func, arguments);
}
In strict mode browsers you could even avoid having the make the new variable since the parameters are no longer mapped to changes in the arguments. But this doesn't work in browsers that don't support strict mode.
I don't think there is a correct way to determine number of arguments for arbitrary function. I prefer to store len in function if it is necessary, and check if it is defined, and if it is and if fn.len == stored_args.length then return function that just returns value.
function schonfinkelize(fn){
var
slice = Array.prototype.slice,
stored_args = slice.call(arguments, 1);
if (fn.len != undefined && fn.len == stored_args.length) {
var val = fn.apply(null, stored_args);
return function () {
return val;
};
}
return function () {
var
new_args = slice.call(arguments),
args = stored_args.concat(new_args);
return fn.apply(null, args);
};
}
var f = function (a, b, c) {
return a + b + c;
};
f.len = 3;
var g = schonfinkelize(f, 1, 2);
alert(g); // function () { var new_args = slice.call(arguments), args = stored_args.concat(new_args); return fn.apply(null, args); };
alert(g(3)); // 6
var g = schonfinkelize(f, 1, 2, 3);
alert(g); // function () { return val; };
alert(g()); // 6
I want propose also a personal evolution of the code but I have to said thanks to squint to has resolved the problem, simply suggest me to use the property .length.
The next level it is in my opinion permit to create a partial function able to be called every time you want until you finish to fill all the arguments, I have also simplified the code:
function schonfinkelize(fn, stored_args){
if(fn.length == stored_args.length)
return fn.apply(null, stored_args);
return function(){
var
new_args = arguments[0],
args = stored_args.concat(new_args);
if(fn.length == args.length)
return fn.apply(null, args);
return schonfinkelize(fn, args);
}
}
function add(x, y, w, z){
return x + y + w + z;
}
var
val = schonfinkelize(add, [1, 2, 3, 4]),
val2 = schonfinkelize(add, [1, 2]),
val3 = schonfinkelize(add, [1]);
// checking
console.log(val); // output --> 10 // called only 1 time
console.log(val2([3, 4])); // output --> 10 // called in 2 times
val3 = val3([2]);
val3 = val3([3]);
console.log(val3([4])); // output --> 10 // called 4 times!

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