I have a cookie created in PHP with the jQuery method where the client enters a value in an input and this cookie is created with that Value while more values are created with a comma.
Example Creation cookie in jQuery:
<script type="text/javascript">
$(function () {
$("#btnAdd").click(function () {
if($('#addtokendelivery').val() === ''){
alert('Valor en Blanco');
}
else {
if ($.cookie('DeliveryToken')) {
$.cookie("DeliveryToken", $.cookie("DeliveryToken") + ',' + $("#addtokendelivery").val());
alert('Repartidores Agregados con Token´s: ' + $.cookie("DeliveryToken"));
} else{
$.cookie("DeliveryToken", $("#addtokendelivery").val());
alert('Repartidor Agregado con Token: ' + $.cookie("DeliveryToken"));
}
}
});
$("#btnRead").click(function () {
alert($.cookie("DeliveryToken"));
});
});
</script>
Example cookie in google chrome value:
DeliveryToken: value1,value2,value3
Example of variable to compare with in laravel:
$orderitemaddons32 = DB::table('users')->where('id', $id)->first();
$orderitemaddons32 = $orderitemaddons32->userdelivery_id;
//result variable dd laravel
"value1"
For example, if it detects that the value 1 is inside the cookie, it proceeds to display the page.
What I want is to verify in the laravel blade if the cookie matches the information of the variable that it creates in my function and to show the page, otherwise not to show it or to put a message that the information is not valid.
There are many ways to do what you want.
For having a condition before you proceed with a request or not, it's usual to use a middleware.
https://laravel.com/docs/8.x/middleware
From the middleware, you can continue with the request or to redirect the user to another page.
I guess your code could look like this in laravel:
$values = explode(',', $_COOKIE['DeliveryToken']);
if (in_array($orderitemaddons32, $values) {
//all good, proceed
// return $next($request);
} else {
/*
* return redirect()->route('home', [
* 'message' => 'The information is not valid'
* ]);
*/
}
Btw, I don't find it secure this kind of usage with cookies, I mean, setting them from javascript and not encrypting them and securing them in server side. One could easily change the value of cookie.
You could leave the cookies to laravel and thus use also the built-in functions.
Related
Data sent from this
www.example.com/modules/liaise/index.php?form_id=xxx
In normal condition, after submit, the page redirects to
www.example.com/modules/liaise/index.php
and sends mail.
Wantedly, I placed the reCAPTCHA in the same file (index.php).
Google captcha :
require_once "recaptchalib.php";
// your secret key
$secret = "secret key";
// empty response
$response = null;
// check secret key
$reCaptcha = new ReCaptcha($secret);
// if submitted check response
if ($_POST["g-recaptcha-response"]) {
$response = $reCaptcha->verifyResponse(
$_SERVER["REMOTE_ADDR"],
$_POST["g-recaptcha-response"]
);
}
if ($response != null && $response->success) {
//send mail
} else {
echo '
<script src="https://www.google.com/recaptcha/api.js?onload=onloadCallback&render=explicit" async defer></script>
<div id="html_element"></div>
<script>
var onloadCallback = function() {
grecaptcha.render("html_element", {
"sitekey" : "sitekey",
"callback" : correctCaptcha
});
};
var correctCaptcha = function(response) {
location.reload();
};
</script>';
}
Whenever I pass reCAPTCHA and page reloads, reCAPTCHA shows again.
I know data from previous page www.example.com/modules/liaise/index.php?form_id=xxx is still there by using
foreach($_POST as $key=>$value)
{
echo "$key=$value";
}
Is there any way by which I can resend data from previous url after reCAPTCHA is passed in the same page?
I am newbie in coding. Please be specific.
Thank you so much!
If your talking about re-sending your data as mail you can use something like this:
if (isset($_POST['form-input'])) {
// Send mail
}
and every time you reload the page and the Post data is not null or blank, it will run that code.
If you are wanting the reCAPTCHA to reload as success, I would say that's defeats the security of reCAPTCHA
Also I see that you have a typo esle should be else.
suppose I work with some kind of API and my file server.php handles the connection to the API service. on my client side I use AJAX call like this:
$http({
url : 'server/server.php',
method : 'GET',
data : { getContent : true }
});
in my server.php I handle it like this:
if(isset($_GET['getContent'])){
$content = get_content();
}
function get_content(){...}
i just wonder what prevents any one send AJAX call with the same getContent parameter and get all my data? how can i secure it and make sure only calls from my application will get the relevant data back?
thank you!
I guess you are concerned about CSRF attacks. Read more about this here: https://www.owasp.org/index.php/Cross-Site_Request_Forgery_%28CSRF%29_Prevention_Cheat_Sheet
One of the mostly used option to secure your request will be:
- Generate a token and send it with the request for a session. This token can be identified by your WebServer as originating from a specific client for a specific session
2022 Update
This is a 7 year old post and the link in the link-only "accepted" answer is broken.
So, I'm going to offer a basic walkthrough and a complete model.
Remember, the $_SESSION will be preserved even in the AJAX handler, if it's all from the same domain. So, you can use that to check things.
Use $_POST
I presume you're using $_POST and not $_GET since you're concerned about security. If not, then much of this might not be important anyway.
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
$post_method = true;
}
Ensure the $_SERVER['HTTP_REFERER'] is from your own site
if ( (!empty($_SERVER['HTTP_REFERER']))
&& ($_SERVER['HTTP_REFERER'] === "https://example.tld/my_sending_page.php") ) {
$from_my_server = true;
}
If you're not sure what this should be, run a test on your own server to see what this should be:
echo $_SERVER['HTTP_REFERER'];
Verify XMLHTTP/AJAX request via $_SERVER array
if ( (!empty($_SERVER['HTTP_X_REQUESTED_WITH']))
&& ( strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) === 'xmlhttprequest') ) {
$ajax = true;
} else {
$ajax = false;
}
Use a token
This is the hard part, but not too hard.
Create the token
Set the token in $_SESSION
Put the token in the AJAX header
AJAX responder: confirm the AJAX header token with the $_SESSION token
send_from_me.php
// Create the token
//$token = md5(rand(10000,99999)); // Not recommended, but possible
$token = bin2hex(random_bytes(64));
// Store in SESSION
$_SESSION["token"] = $token;
// Assuming your AJAX is this
const AJAX = new XMLHttpRequest();
// This goes inside your AJAX function somewhere before AJAX.send
//
AJAX.setRequestHeader("ajax-token", "<?php echo $_SESSION["token"]; ?>");
//
// That creates $_SERVER['HTTP_AJAX_TOKEN'] which we can use later
ajax_responder.php
session_start(); // Must have
if ($_SERVER['HTTP_AJAX_TOKEN'] === $_SESSION["token"]) {
$token_match = true;
} else {
echo "No script kiddies!";
exit();
}
// Now it's safe for your AJAX responder to proceed
Let's put all of this into a working example
sending_from.php
<?php
session_start();
$token = bin2hex(random_bytes(64));
$_SESSION["token"] = $token;
?>
<!DOCTYPE html>
<html>
<head>
<title>My AJAX Sender</title>
</head>
<body>
<script>
function ajaxFormData(formID, postTo, ajaxUpdate) {
// Bind a new event listener every time the <form> is changed:
const FORM = document.getElementById(formID); // <form> by ID
const FD = new FormData(FORM); // Bind to-send data to form element
const AJAX = new XMLHttpRequest(); // AJAX handler
// This runs when AJAX responds
AJAX.addEventListener( "load", function(event) {
document.getElementById(ajaxUpdate).innerHTML = event.target.responseText;
} );
// This runs if AJAX fails
AJAX.addEventListener( "error", function(event) {
document.getElementById(ajaxUpdate).innerHTML = 'Oops! Something went wrong.';
} );
// Add your token header
AJAX.setRequestHeader("ajax-token", "<?php echo $_SESSION["token"]; ?>");
// Open the POST connection
AJAX.open("POST", postTo);
// Data sent is from the form
AJAX.send(FD);
}
</script>
<div id="ajax_changes">Replace me with AJAX</div>
<form id="ajaxForm">
<input type="text" name="the_simple_response">
<button type="button" onclick="ajaxFormData('ajaxForm', 'ajax_responder.php', 'ajax_changes');">Send my Secure AJAX</button>
</form>
</body>
</html>
ajaxcheck.inc.php
<?php
$mysite = 'https://example.tld';
// All in one test
if (($_SERVER['REQUEST_METHOD'] == 'POST')
&& ((!empty($_SERVER['HTTP_REFERER'])) && ($_SERVER['HTTP_REFERER'] === "$mysite/my_sending_page.php"))
&& ((!empty($_SERVER['HTTP_X_REQUESTED_WITH'])) && ( strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) === 'xmlhttprequest'))
&& ($_SERVER['HTTP_AJAX_TOKEN'] === $_SESSION["token"])) {
$ajax_legit = true;
} else {
echo "No script kiddies!";
exit();
}
?>
ajax_responder.php
<?php
session_start();
// Do all that checking we're learning about by neatly including the file above
require_once('ajaxcheck.inc.php');
// Process your AJAX
echo $_POST['the_simple_response'];
?>
i just wonder what prevents any one send AJAX call with the same getContent parameter and get all my data?
Nothing. This URL is public thus anyone can make requests to it.
how can i secure it and make sure only calls from my application will get the relevant data back?
You can pass additional data (for example, some hashed value) that is verified on the server side.
$http({
url : 'server/server.php',
method : 'GET',
data : { getContent : true, hash : '0800fc577294c34e0b28ad2839435945' }
});
and
if(isset($_GET['getContent']))
{
if(isset($_GET['hash']) && validateHash($_GET['hash']))
{
$content = get_content();
}
}
function get_content(){...}
i just wonder what prevents any one send AJAX call with the same getContent parameter and get all my data?
The same way you would protect the data in any other request (e.g. with user authentication). There's nothing special about Ajax in regards to HTTP as far as the server is concerned.
how can i secure it and make sure only calls from my application will get the relevant data back?
You can't. The user can always inspect what their browser is asking the server for and replicate it.
Generally, people authenticate users rather than applications.
I have a javascript variable called "list". I need to send it as a POST data to another page and open that page in a new tab (with the POST data present).
This code:
jQuery.post('datadestination.php', list);
sends the data all right, but ofcourse it opens the page in the same tab.
I saw some solutions to similar problems using invisible form and things like that, but I could not get them to work. Is there any simple solution?
You can send a form using the target="_blank" attribute.
<form action="datadestination.php" method="POST" target="_blank" id="myform">
<input type="hidden" name="list" id="list-data"/>
<input type="submit" value="Submit">
</form>
Then in JS:
jQuery('#list-data').val(list);
jQuery('#myform').submit();
This is an implementation of Sergey's solution.
<?php // this is save.php
session_start();
// DO NOT just copy from _POST to _SESSION,
// as it could allow a malicious user to override security.
// Use a disposable variable key, such as "data" here.
// So even if someone passed _POST[isAdmin]=true, all that he would do
// is populate _SESSION[data][isAuthenticated], which nobody reads,
// not the all-important _SESSION[isAuthenticated] key.
if (array_key_exists('data', $_POST)) {
$_SESSION['data'] = $_POST['data'];
$_SESSION['data.timestamp'] = time();
// Let us let the client know what happened
$msg = 'OK';
} else {
$msg = 'No data was supplied';
}
Header('Content-Type: application/json; charset=utf8');
die(json_encode(array('status' => $msg)));
?>
In the first page:
$.post('save.php', { data: list }, function(response){
if (!response.status) {
alert("Error calling save");
return;
}
if (response.status !== 'OK') {
alert(response.status);
return;
}
// We had a response and it was "OK". We're good.
window.open('datadestination.php');
});
And in datadestination.php add the fix:
if (!array_key_exists('data', $_SESSION)) {
die("Problems? Did you perchance attempt to reload the page and resubmit?");
// For if he did, then yes, $_SESSION would have been cleared.
// Same if he is operating on more than one window or browser tab.
}
// Do something to validate data. For example we can use data.timestamp
// to assure data isn't stale.
$age = time();
if (array_key_exists($ts = 'data.timestamp', $_SESSION)) {
$age -= $_SESSION[$ts];
}
if ($age > 3600) {
die("Data is more than one hour old. Did someone change server time?!?");
// I actually had ${PFY} do that to me using NTP + --hctosys, once.
// My own time zone is (most of the year) exactly one hour past GMT.
}
// This is safe (we move unsecurity-ward):
$_POST = $_SESSION['data'];
unset($_SESSION['data'], $_SESSION['data.timestamp']);
// keep things clean.
// From here on, the script behaves "as if" it got a _POST.
Update
You can actually merge save.php and datadestination.php and use a "saving stub" savepost.php that you can recycle in other pages:
<?php
session_start();
// DO NOT just copy from _POST to _SESSION,
// as it could allow a malicious user to override security.
// Use a disposable variable key, such as "data" here.
if (array_key_exists('data', $_POST)) {
// Timestamp sent by AJAX
if (array_key_exists('ts', $_POST)) {
// TODO: verify ts, but beware of time zones!
$_SESSION['data'] = $_POST['data'];
Header("Content-Type: application/json;charset=UTF-8");
die(json_encode(array('status' => 'OK')));
}
die("Error");
}
// This is safe (we move unsecurity-ward):
$_POST = $_SESSION['data'];
unset($_SESSION['data']); // keep things clean.
?>
Now your call becomes
$.post('datadestination.php', { data: list, ts: Date.now() }, function(){
window.open('datadestination.php');
});
and in your datadestination.php (or anywhere else) you add
require 'savepost.php';
I suggest:
Pass that list with the jquery.post() function and save it in the SESSION array.
Open a new tab with the same file/address/URL with the window.open() function.
Retrieve saved data from the SESSION array.
This seems straightforward and clean to me.
I have a web page that allows users to complete quizzes. These quizzes use JavaScript to populate original questions each time it is run.
Disclaimer: JS Noob alert.
After the questions are completed, the user is given a final score via this function:
function CheckFinished(){
var FB = '';
var AllDone = true;
for (var QNum=0; QNum<State.length; QNum++){
if (State[QNum] != null){
if (State[QNum][0] < 0){
AllDone = false;
}
}
}
if (AllDone == true){
//Report final score and submit if necessary
NewScore();
CalculateOverallScore();
CalculateGrade();
FB = YourScoreIs + ' ' + RealScore + '%. (' + Grade + ')';
if (ShowCorrectFirstTime == true){
var CFT = 0;
for (QNum=0; QNum<State.length; QNum++){
if (State[QNum] != null){
if (State[QNum][0] >= 1){
CFT++;
}
}
}
FB += '<br />' + CorrectFirstTime + ' ' + CFT + '/' + QsToShow;
}
All the Javascript here is pre-coded so I am trying my best to hack it. I am however struggling to work out how to pass the variable RealScore to a MySql database via PHP.
There are similar questions here on stackoverflow but none seem to help me.
By the looks of it AJAX seems to hold the answer, but how do I implement this into my JS code?
RealScore is only given a value after the quiz is complete, so my question is how do I go about posting this value to php, and beyond to update a field for a particular user in my database on completion of the quiz?
Thank you in advance for any help, and if you require any more info just let me know!
Storing data using AJAX (without JQuery)
What you are trying to do can pose a series of security vulnerabilities, it is important that you research ways to control and catch these if you care about your web application's security. These security flaws are outside the scope of this tutorial.
Requirements:
You will need your MySQL database table to have the fields "username" and "score"
What we are doing is writing two scripts, one in PHP and one in JavaScript (JS). The JS script will define a function that you can use to call the PHP script dynamically, and then react according to it's response.
The PHP script simply attempts to insert data into the database via $_POST.
To send the data to the database via AJAX, you need to call the Ajax() function, and the following is the usage of the funciton:
// JavaScript variable declarations
myUsername = "ReeceComo123";
myScriptLocation = "scripts/ajax.php";
myOutputLocation = getElementById("htmlObject");
// Call the function
Ajax(myOutputLocation, myScriptLocation, myUsername, RealScore);
So, without further ado...
JavaScript file:
/**
* outputLocation - any HTML object that can hold innerHTML (span, div, p)
* PHPScript - the URL of the PHP Ajax script
* username & score - the respective variables
*/
function Ajax(outputLocation, PHPScript, username, score) {
// Define AJAX Request
var ajaxReq = new XMLHttpRequest();
// Define how AJAX handles the response
ajaxReq.onreadystatechange=function(){
if (ajaxReq.readyState==4 && xml.status==200) {
// Send the response to the object outputLocation
document.getElementById(outputLocation).innerHTML = ajaxReq.responseText;
}
};
// Send Data to PHP script
ajaxReq.open("POST",PHPScript,true);
ajaxReq.setRequestHeader("Content-type","application/x-www-form-urlencoded");
ajaxReq.send("username="username);
ajaxReq.send("score="score);
}
PHP file (you will need to fill in the MYSQL login data):
<?php
// MYSQL login data
DEFINE(MYSQL_host, 'localhost');
DEFINE(MYSQL_db, 'myDatabase');
DEFINE(MYSQL_user, 'mySQLuser');
DEFINE(MYSQL_pass, 'password123');
// If data in ajax request exists
if(isset($_POST["username"]) && isset($_POST["score"])) {
// Set data
$myUsername = $_POST["username"];
$myScore = intval($_POST["score"]);
} else
// Or else kill the script
die('Invalid AJAX request.');
// Set up the MySQL connection
$con = mysqli_connect(MYSQL_host,MYSQL_user,MYSQL_pass,MYSQL_db);
// Kill the page if no connection could be made
if (!$con) die('Could not connect: ' . mysqli_error($con));
// Prepare the SQL Query
$sql_query="INSERT INTO ".TABLE_NAME." (username, score)";
$sql_query.="VALUES ($myUsername, $myScore);";
// Run the Query
if(mysqli_query($con,$sql))
echo "Score Saved!"; // Return 0 if true
else
echo "Error Saving Score!"; // Return 1 if false
mysqli_close($con);
?>
I use these function for ajax without JQuery its just a javascript function doesnt work in IE6 or below. call this function with the right parameters and it should work.
//div = the div id where feedback will be displayed via echo.
//url = the location of your php script
//score = your score.
function Ajax(div, URL, score){
var xml = new XMLHttpRequest(); //sets xmlrequest
xml.onreadystatechange=function(){
if (xml.readyState==4 && xml.status==200){
document.getElementById(div).innerHTML=xml.responseText;//sets div
}
};
xml.open("POST",URL,true); //sets php url
xml.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xml.send("score="score); //sends data via post
}
//Your PHP-script needs this.
$score = $_POST["score"]; //obtains score from POST.
//save your score here
echo "score saved"; //this will be displayed in the div set for feedback.
so call the javascript function with the right inputs, a div id, the url to your php script and the score. Then it will send the data to the back end, and you can send back some feedback to the user via echo.
Call simple a Script with the parameter score.
"savescore.php?score=" + RealScore
in PHP Side you save it
$score = isset ($_GET['score']) ? (int)$_GET['score'] : 0;
$db->Query('INSERT INTO ... ' . $score . ' ...');
You could call the URL via Ajax or hidden Iframe.
Example for Ajax
var request = $.ajax({
url: "/savescore.php?score=" + RealScore,
type: "GET"
});
request.done(function(msg) {
alert("Save successfull");
});
request.fail(function(jqXHR, textStatus) {
alert("Error on Saving");
});
This question already has answers here:
What is the difference between client-side and server-side programming?
(3 answers)
Closed 9 years ago.
I hope to run a php code inside a javascript code too and I do like that :
<?php function categoryChecking(){
return false;
}?>
....
function openPlayer(songname, folder)
{
if(<?php echo categoryChecking() ?> == true)
{
if (folder != '')
{
folderURL = "/"+folder;
}else
{
folderURL = '';
}
var url = "/users/player/"+songname+folderURL;
window.open(url,'mywin','left=20,top=20,width=800,height=440');
}else{
alerte('you should click on a subcategory first');
}
}
....
<a href='javascript:void();' onClick="openPlayer('<?php echo $pendingSong['id']; ?>','')">
finally I get this error instead the alert message "you should click on a subcategory first"
ReferenceError: openPlayer is not defined
openPlayer('265','')
You're reduced your test case too far to see for sure what the problem is, but given the error message you are receiving, your immediate problem has nothing to do with PHP.
You haven't defined openPlayer in scope for the onclick attribute where you call it. Presumably, the earlier JS code is either not inside a script element at all or is wrapped inside a function which will scope it and prevent it from being a global.
Update: #h2ooooooo points out, in a comment, that your PHP is generating the JS:
if( == true)
Check your browser's error console. You need to deal with the first error messages first since they can have knock on effects. In this case the parse error in the script will cause the function to not be defined.
Once you resolve that, however, it looks like you will encounter problems with trying to write bi-directional code where some is client side and some is server side.
You cannot run PHP code from JavaScript, because PHP is a server-side language (which runs on the server) and JavaScript is a client-side language (which runs in your browser).
You need to use AJAX to send a HTTP request to the PHP page, and then your PHP page should give a response. The easiest way to send a HTTP request using AJAX, is using the jQuery ajax() method.
Create a PHP file ajax.php, and put this code in it:
<?php
$value = false; // perform category check
echo $value ? 'true' : 'false';
?>
Then, at your JavaScript code, you should first add a reference to jQuery:
<script type="text/javascript" src="jquery.js"></script>
Then, use this AJAX code to get the value of the bool:
<script type="text/javascript">
$.ajax('ajax.php')
.done(function(data) {
var boolValue = data == 'true'; // converts the string to a bool
})
.fail(function() {
// failed
});
</script>
So, your code should look like this:
function openPlayer(songname, folder) {
$.ajax('ajax.php')
.done(function (data) {
var boolValue = data == 'true'; // converts the string to a bool
if (boolValue) {
if (folder != '') {
folderURL = "/" + folder;
} else {
folderURL = '';
}
var url = "/users/player/" + songname + folderURL;
window.open(url, 'mywin', 'left=20,top=20,width=800,height=440');
} else {
alert('you should click on a subcategory first');
}
})
.fail(function () {
// failed
});
}