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Cookie PHP LARAVEL

I have a cookie created in PHP with the jQuery method where the client enters a value in an input and this cookie is created with that Value while more values are created with a comma.
Example Creation cookie in jQuery:
<script type="text/javascript">
$(function () {
$("#btnAdd").click(function () {
if($('#addtokendelivery').val() === ''){
alert('Valor en Blanco');
}
else {
if ($.cookie('DeliveryToken')) {
$.cookie("DeliveryToken", $.cookie("DeliveryToken") + ',' + $("#addtokendelivery").val());
alert('Repartidores Agregados con Token´s: ' + $.cookie("DeliveryToken"));
} else{
$.cookie("DeliveryToken", $("#addtokendelivery").val());
alert('Repartidor Agregado con Token: ' + $.cookie("DeliveryToken"));
}
}
});
$("#btnRead").click(function () {
alert($.cookie("DeliveryToken"));
});
});
</script>
Example cookie in google chrome value:
DeliveryToken: value1,value2,value3
Example of variable to compare with in laravel:
$orderitemaddons32 = DB::table('users')->where('id', $id)->first();
$orderitemaddons32 = $orderitemaddons32->userdelivery_id;
//result variable dd laravel
"value1"
For example, if it detects that the value 1 is inside the cookie, it proceeds to display the page.
What I want is to verify in the laravel blade if the cookie matches the information of the variable that it creates in my function and to show the page, otherwise not to show it or to put a message that the information is not valid.

There are many ways to do what you want.
For having a condition before you proceed with a request or not, it's usual to use a middleware.
https://laravel.com/docs/8.x/middleware
From the middleware, you can continue with the request or to redirect the user to another page.
I guess your code could look like this in laravel:
$values = explode(',', $_COOKIE['DeliveryToken']);
if (in_array($orderitemaddons32, $values) {
//all good, proceed
// return $next($request);
} else {
/*
* return redirect()->route('home', [
* 'message' => 'The information is not valid'
* ]);
*/
}
Btw, I don't find it secure this kind of usage with cookies, I mean, setting them from javascript and not encrypting them and securing them in server side. One could easily change the value of cookie.
You could leave the cookies to laravel and thus use also the built-in functions.

Secure ajax GET/POST request for server

suppose I work with some kind of API and my file server.php handles the connection to the API service. on my client side I use AJAX call like this:
$http({
url : 'server/server.php',
method : 'GET',
data : { getContent : true }
});
in my server.php I handle it like this:
if(isset($_GET['getContent'])){
$content = get_content();
}
function get_content(){...}
i just wonder what prevents any one send AJAX call with the same getContent parameter and get all my data? how can i secure it and make sure only calls from my application will get the relevant data back?
thank you!

I guess you are concerned about CSRF attacks. Read more about this here: https://www.owasp.org/index.php/Cross-Site_Request_Forgery_%28CSRF%29_Prevention_Cheat_Sheet
One of the mostly used option to secure your request will be:
- Generate a token and send it with the request for a session. This token can be identified by your WebServer as originating from a specific client for a specific session

2022 Update
This is a 7 year old post and the link in the link-only "accepted" answer is broken.
So, I'm going to offer a basic walkthrough and a complete model.
Remember, the $_SESSION will be preserved even in the AJAX handler, if it's all from the same domain. So, you can use that to check things.
Use $_POST
I presume you're using $_POST and not $_GET since you're concerned about security. If not, then much of this might not be important anyway.
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
$post_method = true;
}
Ensure the $_SERVER['HTTP_REFERER'] is from your own site
if ( (!empty($_SERVER['HTTP_REFERER']))
&& ($_SERVER['HTTP_REFERER'] === "https://example.tld/my_sending_page.php") ) {
$from_my_server = true;
}
If you're not sure what this should be, run a test on your own server to see what this should be:
echo $_SERVER['HTTP_REFERER'];
Verify XMLHTTP/AJAX request via $_SERVER array
if ( (!empty($_SERVER['HTTP_X_REQUESTED_WITH']))
&& ( strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) === 'xmlhttprequest') ) {
$ajax = true;
} else {
$ajax = false;
}
Use a token
This is the hard part, but not too hard.
Create the token
Set the token in $_SESSION
Put the token in the AJAX header
AJAX responder: confirm the AJAX header token with the $_SESSION token
send_from_me.php
// Create the token
//$token = md5(rand(10000,99999)); // Not recommended, but possible
$token = bin2hex(random_bytes(64));
// Store in SESSION
$_SESSION["token"] = $token;
// Assuming your AJAX is this
const AJAX = new XMLHttpRequest();
// This goes inside your AJAX function somewhere before AJAX.send
//
AJAX.setRequestHeader("ajax-token", "<?php echo $_SESSION["token"]; ?>");
//
// That creates $_SERVER['HTTP_AJAX_TOKEN'] which we can use later
ajax_responder.php
session_start(); // Must have
if ($_SERVER['HTTP_AJAX_TOKEN'] === $_SESSION["token"]) {
$token_match = true;
} else {
echo "No script kiddies!";
exit();
}
// Now it's safe for your AJAX responder to proceed
Let's put all of this into a working example
sending_from.php
<?php
session_start();
$token = bin2hex(random_bytes(64));
$_SESSION["token"] = $token;
?>
<!DOCTYPE html>
<html>
<head>
<title>My AJAX Sender</title>
</head>
<body>
<script>
function ajaxFormData(formID, postTo, ajaxUpdate) {
// Bind a new event listener every time the <form> is changed:
const FORM = document.getElementById(formID); // <form> by ID
const FD = new FormData(FORM); // Bind to-send data to form element
const AJAX = new XMLHttpRequest(); // AJAX handler
// This runs when AJAX responds
AJAX.addEventListener( "load", function(event) {
document.getElementById(ajaxUpdate).innerHTML = event.target.responseText;
} );
// This runs if AJAX fails
AJAX.addEventListener( "error", function(event) {
document.getElementById(ajaxUpdate).innerHTML = 'Oops! Something went wrong.';
} );
// Add your token header
AJAX.setRequestHeader("ajax-token", "<?php echo $_SESSION["token"]; ?>");
// Open the POST connection
AJAX.open("POST", postTo);
// Data sent is from the form
AJAX.send(FD);
}
</script>
<div id="ajax_changes">Replace me with AJAX</div>
<form id="ajaxForm">
<input type="text" name="the_simple_response">
<button type="button" onclick="ajaxFormData('ajaxForm', 'ajax_responder.php', 'ajax_changes');">Send my Secure AJAX</button>
</form>
</body>
</html>
ajaxcheck.inc.php
<?php
$mysite = 'https://example.tld';
// All in one test
if (($_SERVER['REQUEST_METHOD'] == 'POST')
&& ((!empty($_SERVER['HTTP_REFERER'])) && ($_SERVER['HTTP_REFERER'] === "$mysite/my_sending_page.php"))
&& ((!empty($_SERVER['HTTP_X_REQUESTED_WITH'])) && ( strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) === 'xmlhttprequest'))
&& ($_SERVER['HTTP_AJAX_TOKEN'] === $_SESSION["token"])) {
$ajax_legit = true;
} else {
echo "No script kiddies!";
exit();
}
?>
ajax_responder.php
<?php
session_start();
// Do all that checking we're learning about by neatly including the file above
require_once('ajaxcheck.inc.php');
// Process your AJAX
echo $_POST['the_simple_response'];
?>

i just wonder what prevents any one send AJAX call with the same getContent parameter and get all my data?
Nothing. This URL is public thus anyone can make requests to it.
how can i secure it and make sure only calls from my application will get the relevant data back?
You can pass additional data (for example, some hashed value) that is verified on the server side.
$http({
url : 'server/server.php',
method : 'GET',
data : { getContent : true, hash : '0800fc577294c34e0b28ad2839435945' }
});
and
if(isset($_GET['getContent']))
{
if(isset($_GET['hash']) && validateHash($_GET['hash']))
{
$content = get_content();
}
}
function get_content(){...}

i just wonder what prevents any one send AJAX call with the same getContent parameter and get all my data?
The same way you would protect the data in any other request (e.g. with user authentication). There's nothing special about Ajax in regards to HTTP as far as the server is concerned.
how can i secure it and make sure only calls from my application will get the relevant data back?
You can't. The user can always inspect what their browser is asking the server for and replicate it.
Generally, people authenticate users rather than applications.

Passing a JavaScript value to PHP on completion of quiz

I have a web page that allows users to complete quizzes. These quizzes use JavaScript to populate original questions each time it is run.
Disclaimer: JS Noob alert.
After the questions are completed, the user is given a final score via this function:
function CheckFinished(){
var FB = '';
var AllDone = true;
for (var QNum=0; QNum<State.length; QNum++){
if (State[QNum] != null){
if (State[QNum][0] < 0){
AllDone = false;
}
}
}
if (AllDone == true){
//Report final score and submit if necessary
NewScore();
CalculateOverallScore();
CalculateGrade();
FB = YourScoreIs + ' ' + RealScore + '%. (' + Grade + ')';
if (ShowCorrectFirstTime == true){
var CFT = 0;
for (QNum=0; QNum<State.length; QNum++){
if (State[QNum] != null){
if (State[QNum][0] >= 1){
CFT++;
}
}
}
FB += '<br />' + CorrectFirstTime + ' ' + CFT + '/' + QsToShow;
}
All the Javascript here is pre-coded so I am trying my best to hack it. I am however struggling to work out how to pass the variable RealScore to a MySql database via PHP.
There are similar questions here on stackoverflow but none seem to help me.
By the looks of it AJAX seems to hold the answer, but how do I implement this into my JS code?
RealScore is only given a value after the quiz is complete, so my question is how do I go about posting this value to php, and beyond to update a field for a particular user in my database on completion of the quiz?
Thank you in advance for any help, and if you require any more info just let me know!

Storing data using AJAX (without JQuery)
What you are trying to do can pose a series of security vulnerabilities, it is important that you research ways to control and catch these if you care about your web application's security. These security flaws are outside the scope of this tutorial.
Requirements:
You will need your MySQL database table to have the fields "username" and "score"
What we are doing is writing two scripts, one in PHP and one in JavaScript (JS). The JS script will define a function that you can use to call the PHP script dynamically, and then react according to it's response.
The PHP script simply attempts to insert data into the database via $_POST.
To send the data to the database via AJAX, you need to call the Ajax() function, and the following is the usage of the funciton:
// JavaScript variable declarations
myUsername = "ReeceComo123";
myScriptLocation = "scripts/ajax.php";
myOutputLocation = getElementById("htmlObject");
// Call the function
Ajax(myOutputLocation, myScriptLocation, myUsername, RealScore);
So, without further ado...
JavaScript file:
/**
* outputLocation - any HTML object that can hold innerHTML (span, div, p)
* PHPScript - the URL of the PHP Ajax script
* username & score - the respective variables
*/
function Ajax(outputLocation, PHPScript, username, score) {
// Define AJAX Request
var ajaxReq = new XMLHttpRequest();
// Define how AJAX handles the response
ajaxReq.onreadystatechange=function(){
if (ajaxReq.readyState==4 && xml.status==200) {
// Send the response to the object outputLocation
document.getElementById(outputLocation).innerHTML = ajaxReq.responseText;
}
};
// Send Data to PHP script
ajaxReq.open("POST",PHPScript,true);
ajaxReq.setRequestHeader("Content-type","application/x-www-form-urlencoded");
ajaxReq.send("username="username);
ajaxReq.send("score="score);
}
PHP file (you will need to fill in the MYSQL login data):
<?php
// MYSQL login data
DEFINE(MYSQL_host, 'localhost');
DEFINE(MYSQL_db, 'myDatabase');
DEFINE(MYSQL_user, 'mySQLuser');
DEFINE(MYSQL_pass, 'password123');
// If data in ajax request exists
if(isset($_POST["username"]) && isset($_POST["score"])) {
// Set data
$myUsername = $_POST["username"];
$myScore = intval($_POST["score"]);
} else
// Or else kill the script
die('Invalid AJAX request.');
// Set up the MySQL connection
$con = mysqli_connect(MYSQL_host,MYSQL_user,MYSQL_pass,MYSQL_db);
// Kill the page if no connection could be made
if (!$con) die('Could not connect: ' . mysqli_error($con));
// Prepare the SQL Query
$sql_query="INSERT INTO ".TABLE_NAME." (username, score)";
$sql_query.="VALUES ($myUsername, $myScore);";
// Run the Query
if(mysqli_query($con,$sql))
echo "Score Saved!"; // Return 0 if true
else
echo "Error Saving Score!"; // Return 1 if false
mysqli_close($con);
?>

I use these function for ajax without JQuery its just a javascript function doesnt work in IE6 or below. call this function with the right parameters and it should work.
//div = the div id where feedback will be displayed via echo.
//url = the location of your php script
//score = your score.
function Ajax(div, URL, score){
var xml = new XMLHttpRequest(); //sets xmlrequest
xml.onreadystatechange=function(){
if (xml.readyState==4 && xml.status==200){
document.getElementById(div).innerHTML=xml.responseText;//sets div
}
};
xml.open("POST",URL,true); //sets php url
xml.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xml.send("score="score); //sends data via post
}
//Your PHP-script needs this.
$score = $_POST["score"]; //obtains score from POST.
//save your score here
echo "score saved"; //this will be displayed in the div set for feedback.
so call the javascript function with the right inputs, a div id, the url to your php script and the score. Then it will send the data to the back end, and you can send back some feedback to the user via echo.

Call simple a Script with the parameter score.
"savescore.php?score=" + RealScore
in PHP Side you save it
$score = isset ($_GET['score']) ? (int)$_GET['score'] : 0;
$db->Query('INSERT INTO ... ' . $score . ' ...');
You could call the URL via Ajax or hidden Iframe.
Example for Ajax
var request = $.ajax({
url: "/savescore.php?score=" + RealScore,
type: "GET"
});
request.done(function(msg) {
alert("Save successfull");
});
request.fail(function(jqXHR, textStatus) {
alert("Error on Saving");
});

ajax, jquery and Iframe (creating a message box system)

I'm trying to create a sort of mail on my site.
So I have a table that contains three columns, let's say (for simplicity , but in reality) , with the two int fields ( from, to ) and a timestamp (date of sending )
a part of my page , I display a list of messages with a group by to to group all messages that are destined for the same person .
Eventually I want to display the entire conversation when clicking on the message but it is not obvious.
I tried jquery ajax and then an iframe but it is not great , because on one hand it does not return me anything (white pages) and secondly the reload each second is not great .
At first I would like to display the result of my request.
I have not set callback because I do not know what to do with an application in a jquery callback . I thought the easiest way was to do my processing in php and run my loop then displays everything in the iframe .
So I put it in jquery
$( ".load_message" ).click(function() {
//On marque uniquement l'id de l'expediteur et du destinataire
// pour chercher les messages expédiés par A vers B ou inversement
var from = $(this).closest('tr').find('span.from').text();
var to = $(this).closest('tr').find('span.to').text();
$.ajax({
type: 'POST',
url: 'pages_ajax/fetch-messages.php',
data: { from: from, to: to},
dataType: "json"
});
});
setInterval(refreshIframe1, 1000);
function refreshIframe1() {
$("#messages")[0].src = $("#messages")[0].src;
}
and the php page I have this:
<?php
session_start();
require_once("../../lib_php/librairie.php");
require_once("../../config/connexion.php");
//header('Content-Type: application/json; charset=utf8');
/**
* Fonction qui retourne une liste de messages
* #return int
*/
function fetchMessages() {
if (isset($_POST['from'])) {
$from = mysql_real_escape_string($_POST['from']);
$to = mysql_real_escape_string($_POST['to']);
$query = "SELECT `id`, `from`, `to`, `message`, `sent`, `read`, `direction`
FROM `cometchat`
WHERE `from` = {$from} || `from` = {$to} || `to` = {$to} || `to` = {$from}";
return $query;
} else {
return null;
}
}
if (isset($_POST['from'])) {
$liste_messages = fetchMessages();
if (!is_null($liste_messages)) {
$result_message = mysql_query($liste_messages);
while ($mess = mysql_fetch_assoc($result_message)):
?>
ici
<?php
endwhile;
}
}
?>
But for now nothing works I do not even have my messages while running the echo of my query in phpMyAdmin return me something. I guess I'm loosing context when reloading ($_POST are loosing themselves)
I would initially display the entire conversation in an iframe or a div, then after whatever it is automatically updated if ever there's new posts in the meantime a bit like the messaging system on Facebook with no reloading of the page.
Any help will be greatly appreciated.

it's been a while you asked the question hope u solved it. Anyway is what i can tell from your code and what you try to do:
Your jquery function have no callback (success, complete)
Your php code don't return anything, you just do a loop like you want to manipulate each record, and reading your post you want to have your ajax to read all value in a success callback... So don't need a loop except you want to parse it, just expose them with json_encode($mess);
setInterval 1s? argh!!! Will your server handle it? Use something like 10 à 30s or 4:
go for websocket solution like racket in php or use nodejs plateform (nodejs + socket.io + redis)
Hope it helped you out or someone else

Request timeout

I'm using some jQuery to display tweets but once the Twitter API limit is reached, the request is sent but just keeps loading and loading. This doesn't look good. I want to be able to determine if the request is taking too long and then obviously do stuff, like cancel the request, change the styling, etc.
So this is the code that sends the request:
var fileref = document.createElement('script');
fileref.setAttribute("type","text/javascript");
fileref.setAttribute("src", "http://search.twitter.com/search.json?q="+buildString+"&callback=TweetTick&rpp=50");
document.getElementsByTagName("head")[0].appendChild(fileref);
And this is the TweetTick function:
function TweetTick(ob)
{
var container=$('#tweet-container');
container.html('');
$(ob.results).each(function(el){
/* in here, a div is built for each tweet and then appended to container */
});
container.jScrollPane(); /* just adds the scrollbar */
}

You need to cache twitter api response on your server side.
How do I keep from running into the rate limit?

I had a very similar problem lately. I use this script by Remy Sharp for most of my twitter requests: http://remysharp.com/2007/05/18/add-twitter-to-your-blog-step-by-step/
What you need to realise is that the api timeout is per IP address. So if the api has timed out for you based on your testing, it won't have timed out for someone else on a different IP address. Now, if someone accessing the site is doing so within a corporation or business, and others in the same place are doing the same, that timeout will occur almost instantaneously.
To get around this you need to cache your results. The way I did this was as follows.
I created a twitter caching system using the following code:
$twitter_username = "tadywankenobi"; //
$number_of_tweets = "10";
$options[CURLOPT_URL] = 'http://api.twitter.com/1/statuses/user_timeline.xml?screen_name='.$twitter_username.'&count='.$number_of_tweets.'&include_rts=1';
$options[CURLOPT_PORT] = 80;
$options[CURLOPT_FOLLOWLOCATION] = true;
$options[CURLOPT_RETURNTRANSFER] = true;
$options[CURLOPT_TIMEOUT] = 60;
$tweets = cache($options);
$twxml = new SimpleXMLElement($tweets);
echo "<ul>";
for($i=0;$i<=($number_of_tweets-1);$i++){
$text = $twxml->status[$i]->text;
echo "<li>".auto_link_twitter($text)."</li>";
}
echo "</ul>";
function cache($options) {
$cache_filename = "/var/cache/tweets.xml";
if(!file_exists($cache_filename)){
$handle = fopen($cache_filename, 'w') or die('Cannot open file: '.$my_file);
fclose($handle);
}// Check if cache file exists and if not, create it
$time_expire = filectime($cache_filename) + 60*60; // Expire Time (1 hour) // Comment for first run
// Set time to check file against
if(filectime($cache_filename) >= $time_expire || filesize($cache_filename) == 0) {
// File is too old or empty, refresh cache
$curl = curl_init();
curl_setopt_array($curl, $options);
$response = curl_exec($curl);
curl_close($curl);
if($response){
file_put_contents($cache_filename, $response);
}
else{
unlink($cache_filename);
}
}else{
$response = file_get_contents($cache_filename);
}
return $response;
}
What the cache function at the end does is create a file on the server and stores the twitter xml feedback in there. The system then checks to see the age of that file and if it's younger than an hour old, it takes its results from there. Otherwise, it re-accesses twitter. You need to have the file writable in the /var/cache folder (create it if it's not there).
I've kinda hacked this code together a bit, so let me know if you run into any issues with it. It also uses an auto_link_twitter() function, which creates the links required within the twitter text. I didn't write that, so I'll try and find you a link to it now.
Hope that all helps,
T
UPDATE: I can't remember where I got the auto_link_twitter() function, so here it is. If the person who wrote it reads this post, my apologies, I couldn't find the source again.
function auto_link_twitter($text) {
// properly formatted URLs
$urls = "/(((http[s]?:\/\/)|(www\.))?(([a-z][-a-z0-9]+\.)?[a-z][-a-z0-9]+\.[a-z]+(\.[a-z]{2,2})?)\/?[a-z0-9._\/~#&=;%+?-]+[a-z0-9\/#=?]{1,1})/is";
$text = preg_replace($urls, " <a href='$1'>$1</a>", $text);
// URLs without protocols
$text = preg_replace("/href=\"www/", "href=\"http://www", $text);
// Twitter usernames
$twitter = "/#([A-Za-z0-9_]+)/is";
$text = preg_replace ($twitter, " <a href='http://twitter.com/$1'>#$1</a>", $text);
// Twitter hashtags
$hashtag = "/#([A-Aa-z0-9_-]+)/is";
$text = preg_replace ($hashtag, " <a href='http://twitter.com/#!/search?q=%23$1'>#$1</a>", $text);
return $text;
}

You can use specific jQuery methods to make a JSONP request. There is basic $.ajax method and shorthand method $.getJSON which fits better for you. To control timeout of the request you can use timeout parameter. Request exceeded timeout can be processed using the error callback.
$.ajax(
dataType: 'jsonp',
url: 'http://search.twitter.com/search.json',
data: {
q: buildString,
rpp: 50
},
jsonpCallback: 'TweetTick',
timeout: 30000,
error: function(jqXHR, textStatus, errorThrown) {
if (textStatus == 'timeout') {
alert('timeout exceeded');
}
}
);