Setting VideoJS Source via Javascript - javascript

I'm trying to set the source and type for Video.js dynamically via a JSON object that is retrieved from a remote method call.
radioPlayer = videojs("RadioPlayer");
function RadioListPage() {
$.getJSON(serviceURL + 'rbApp.cfc?method=Radio', function(data) {
$.each(data.DATA, function(index, itemData) {
$('#radioList').append('<div class="play" data-type="' + itemData[4] + '" data-src="' + itemData[3] + '" data-station="' + itemData[1] + '" data-id="' + itemData[0] + '"><img src="' + itemData[2] + '"></div>');
lastIDNumberVideo = itemData[0];
});
$('#radioList .play').click(function() {
var stationObject = new Object();
stationObject.src = $(this).data("src");
stationObject.type = $(this).data("type");
var jsonStr = JSON.stringify(stationObject);
radioPlayer.src(jsonStr);
radioPlayer.play();
});
loading('hide', 100);
});
}
VideoJS will throw an error that the stream isn't valid. However, if I take that jsonStr variable and hard code that value like this radioPlayer.src({"src":"http://wlca-stream.lc.edu:8004/wlca","type":"audio/mpeg"}) it plays with no issue. What am I missing here? Is this not possible to do?

The example code you show provides a JS object to the src() method, yet you're providing JSON. Try providing the object directly to the method.
Also note that I'd suggest you use a delegated event handler instead of binding events in the AJAX callback, which can lead to issues with duplicated events. Try this:
radioPlayer = videojs("RadioPlayer");
$('#radioList').on('click', '.play', function() {
radioPlayer.src({
src: $(this).data("src"),
type: $(this).data("type")
});
radioPlayer.play();
});
function RadioListPage() {
$.getJSON(serviceURL + 'rbApp.cfc?method=Radio', function(data) {
let html = data.DATA.map(item => `<div class="play" data-type="${item[4]}" data-src="${item[3]}" data-station="${item[1]}" data-id="${item[0]}"><img src="${item[2]}"></div>`);
$('#radioList').append(html);
lastIDNumberVideo = data.DATA.slice(-1)[0];
loading('hide', 100);
});
}

Related

access to DOM add dynamiclly, getScript, ajax

I use jQuery ajax to read context on my page dynamicly. But part of DOM is load in javaScript function call by getScript in ajax .done. But just after I load new content I need to get elements by class and use it in next function. Unfortunatly I can't find elements, that I create in javaScript function, and script with that function I call using jQuery getScript.
ok, my code:
$(document).ready(function() {
$('.link').click(function(){
var subpage = $(this).attr('data-subpage');
var src = 'subpages/'+ subpage + '/' + subpage +'.php';
var script = 'subpages/'+ subpage + '/js/' + subpage +'.js';
$.ajax({
url: src,
context: document.body,
dataType: 'html',
success: function(responseText){
$('#text').html(responseText); // responseText has only container <div id="insideText"></div> that I use in one function and load there by html() several divs. One of this div has class 'translate'. I need it in function Translator
}
})
.done(function(){
$.getScript(script); // here I call script where I load several divs to #insideText
Translator($('.active').attr('data-lang')).getTranslation() // part of function have to find all div.translate, but can't find it if they're load in script call in getScript. And this is a problem.
})
})
})
I hope, I explaine my problem quite clear. If not, plaese ask, I'll try again.
There's some way to do that?
//update//
After this script, call by getScript I still have problem with second 'done':
const Presenter = function(){
var presented, show, fullDesc, cont;
presented = [
{
url: 'demo/colorsGame/',
name: 'Graj w kolorki!',
desc: 'Graj w kolorki! Wybierz taki sam kolor, w jakim napisana jest nazwa wylosowanego koloru. Spiesz się, czas ucieka coraz szybciej i szybciej. Uważaj, bo mózg może cię oszukać i uznać za ważniejsze to, co jest napisane, a nie to co widzisz. Zobacz ile punktów jesteś w stanie zdobyć zanim popełnisz trzy błędy. Ćwicz swoją koncentrację.'
},
{
url: 'demo/sampleUserProfile/',
name: 'Sample User Profil',
desc: 'Mała próbka możliwości reactJS. Wkonany z użyciem biblioteki reactJS, menadzera pakietów webpack oraz na środowisku nodeJS przykładowy profil użytkownika. Like-uj i obserwuj do woli, a jeśli chcesz, wypowiedz się pod profilem.'
}
];
show = function(url, desc, name) {
fullDesc =
"<a href ='" + url + "'>" +
"<h1 class='translate'>" + name + "</h1>" +
"</a>" +
"<div>" +
"<p class='translate'>" + desc + "</p>" +
"</div>";
cont =
"<div id='webmin' class='clearfix'>" +
"<div>" +
fullDesc +
"</div>" +
"<div>" +
"<iframe src='" + url + "' scrolling='no'>" +
"ups, twoja przeglądarka nie obsługuje ramek" +
"</iframe>" +
"</div>"+
"</div>";
return cont;
};
return {
show: show,
presented: presented
}
};
display = function(){
var len, url, name, desc;
len = Presenter().presented.length;
for(let i = 0; i <= len; i++){
url = Presenter().presented[i].url;
name = Presenter().presented[i].name;
desc = Presenter().presented[i].desc;
$('#insidetext.apps').append(Presenter().show(url, desc, name));
}
};
display();
Hmm, I'm wondering, if iframe is not a problem here? And don't let script to be done to end?
getScript is just another ajax call and returns an xhr object which exposes done and fail methods. Use those methods to ensure your dom is properly loaded before trying to access it.
$(document).ready(function() {
$('.link').click(function(){
var subpage = $(this).attr('data-subpage');
var src = 'subpages/'+ subpage + '/' + subpage +'.php';
var script = 'subpages/'+ subpage + '/js/' + subpage +'.js';
$.ajax({
url: src,
context: document.body,
dataType: 'html'
})
.done(function(responseText){
$('#text').html(responseText);
$.getScript(script).done(function() {
Translator($('.active').attr('data-lang')).getTranslation() ;
}
})
})
})
Also, you should implement the .fail methods, in case your ajax requests fail.

Avoid duplicated function call in jquery?

I have build a function getuser() in which I recieve json data from php into javascript. I call this function when document gets ready. My problem is that I am also using jquery post for live updation of that record and for that reason I have to call that function getuser() again due to this it shows duplicate result. First when document gets ready socend on jquery post function.
HTML
<!--It has onclick event-->
<button type="submit" class="btn btn-primary modify" onclick="update_user()">UPDATE</button>
JQUERY
//This is function which gets json array from php
function getuser() {
$.get("getuser.php", function (data) {
var data = JSON.parse(data);
for (var i = 0, len = data.length; i < len; ++i) {
var student = data[i];
var slash = " / ";
$("#output").append("<tr><td>" + student.name + "</td><td>" + student.gender + "</td><td>" + student.age + "</td>" +
"<td>" + student.city + "</td><td><a href='#' style='text-decoration: none' class='update' id='" + student.id + "' onclick='reply_click(this.id)'>Update</a>" + slash + "<a style='text-decoration: none' href='#'>Delete</a></td></tr>");
}
});
}
//when document gets ready it will show the record
if($(document).ready()) {
// getuser();
getuser();
}
//This is jquery post. When I click button (in html section) it will get form values and sent to php page
//in return it will call getuser() function again which results of duplicate display of record
$(document).ready(function(){
$('.modify').click(function() {
var gender = '';
if($('.male').is(':checked')){
gender='Male';
}else{
gender='Female';
}
$.post("update.php",
{name: $('.name').val(),gender:gender,city:$('.city').val(),age:$('.age').val(),id:$('.id').val()},
function (data) {
//here is the function call again
getuser();
}
);
});
});
Kindy tell me that is there any way I avoid second call in post function and the record gets update without function call again.I need to avoid duplicate result. Thanks in advance!
First off, you need to read the docs on jquery document ready, and learn the difference between a function reference and actually calling a function. document.ready expects you to pass in a function definition to be called when the page is ready. It doesn't actively tell you if the page is ready, the first way you're calling it. The second way you're calling it is actually correct.
Second, replace $("#output").append with $("#output").html, which will update/replace the contents of that element every time, instead of just adding more and more.
Your if test will always return true because document.ready returns the JQuery object. So, you are always causing the call to getuser() to happen.
You can see the return value from document.ready() here:
console.log($(document).ready());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
This is an incorrect usage of document.ready(). You don't need to write a test for document.ready, just write a callback function for that event and let the browser do it correctly for you.
Read the docs on document.ready()
Solution:
This:
//when document gets ready it will show the record
if($(document).ready()) {
// getuser();
getuser();
}
Should be this:
//when document gets ready it will show the record
$( document ).ready(getuser);
Or even:
$(getuser);
As for you getting the results a second time, just overwrite the old results instead of appending them.
This: $("#output").append(...
Should be: $("#output").html(...
All of you thanks for your suggestions. I have found the solution here by just adding $("#tbody").html(''); in getuser() before loop. Here is the code which works fine for me
function getuser() {
$.get("getuser.php", function (data) {
var data = JSON.parse(data);
$("#tbody").html('');//newly added
for (var i = 0, len = data.length; i < len; ++i) {
var student = data[i];
var slash = " / ";
$("#output").append("<tr><td>" + student.name + "</td><td>" + student.gender + "</td><td>" + student.age + "</td>" +
"<td>" + student.city + "</td><td><a href='#' style='text-decoration: none' class='update' id='" + student.id + "' onclick='reply_click(this.id)'>Update</a>" + slash + "<a style='text-decoration: none' href='#'>Delete</a></td></tr>");
}
});
}
All of you thanks again!

How to pass a variable in ajax append function (into html element with razor)?

I need to pass the Id of a object into a html element (razor part), but it doesn't recognize it. Look like the Id is not in its scope, or something. Is there a way to pass the value into the razor part of my html element in the append function?
$.ajax({
data: data,
url: url + "?searchTerm=" + data
}).success(function (response) {
console.log(response);
var table = $('#companyTable');
var tBody = table.children('tbody');
tBody.html("");
var textbox = document.getElementById("searchBar");
textbox.value = "";
tBody.append(
"<tr><td>" +response.CompanyName + " </td><td>" +
response.CompanyIdNumber + "</td><td>" +
response.CompanyTaxNumber + "</td><td>" +
"<p><button onclick=\"location.href='#Url.Action("Edit", "Company", new { #id = response.CompanyId })'\"> Edit</button></p>" +
"</td></tr>"
);
table.removeClass("hidden");
var originalTable = $('#originalTable');
originalTable.remove();
}).error(function (response) {
console.log(response);
});
}
Thank you.
I do those things this way:
+ "<p><button onclick=\"location.href='#(Url.Action("Edit", "Company"))?id=" + response.CompanyId + "'\">Edit</button>"
You are totally missing the concept of server-side rendering and browser execution. Consider this example, your server renders your js code, and just leaves all work to browser, then browser stars to execute Ajax request somehow(button click), when Ajax completed - you have a response value, but this value exists only inside browser context, so it doesn't make sense to pass value into razor, as it already done its work while rendering your file
Now, what to do? The simplest solution would be to hardcore Url of company edit by yourself, as razor simply doesn't know anything what's happening client-side, example:
location.href="/company/1/edit" //where 1 is id from Ajax request
The easiest complete solution is
public ActionResult WhateverMethod()
{
// ....
var urlHelper = new UrlHelper(this.ControllerContext.RequestContext);
response.Url = Url.Action("Edit", "Company", new { #id = response.CompanyId });
// ....
}
And
tBody.append(
"<tr><td>" +response.CompanyName + " </td><td>"
+ response.CompanyIdNumber + "</td><td>"
+ response.CompanyTaxNumber + "</td><td>"
+ "<p><button onclick=\"location.href='" + response.Url + "'\"> Edit</button></p>"
+ "</td></tr>");
Calling a Razor methods in JavaScript is going to cause you nothing but grief.
response.CompanyId is considered as string , so try by concatenating it as below
var a="location.href='#Url.Action("Edit", "Company", new{#id='"+response.CompanyId+"'})'"
response.CompanyId ( "<tr><td>" +response.CompanyName + " </td><td>" +
response.CompanyIdNumber + "</td><td>" +
response.CompanyTaxNumber + "</td><td>" +
"<p><button onclick=\""+a +"\"> Edit</button></p>" + "</td></tr>")

jQuery read XML URL

My below code working well but i need to import XML data from xml URL not from HTML file like this
if i need to retrieve image from XML how i can do that.
var xml = "<shows><show><date>9/8</date><place>Toads Place</place><location>New Haven, CT</location><time>9PM</time></show></shows>"
$(document).ready(function(){
//$('#table').append('<h2>SHOWS</h2>');
$('#table').append('<table id="show_table">');
$(xml).find('show').each(function(){
var $show = $(this);
var date = $show.find('date').text();
var place = $show.find('place').text();
var location = $show.find('location').text();
var time = $show.find('time').text();
var html = '<tr><td class="bold">' + date + '</td><td class="hide">' + place + '</td><td>' + location + '</td><td class="bold">' + time + '</td></tr>';
$('#show_table').append(html);
});
//alert($('#show_table').html());
})
all what i need is change this var xml = "9/8 ... " to let the JQuery code read from the ONLINE URL
If you need to load XML data from the URL, you need to execute AJAX request, it may be something like this:
$(function() {
$.ajax({
type: "get",
url: "http://yoursite.com/yourfile.xml",
dataType: "xml",
success: function(data) {
/* handle data here */
$("#show_table").html(data);
},
error: function(xhr, status) {
/* handle error here */
$("#show_table").html(status);
}
});
});
Keep in mind, if you use AJAX you can place .xml file on the same domain name. In other case you need to set up cross-origin resource sharing (CORS).
EDITED:
I modified your code, now it appends td element to your table. But xml is still inside html.
var xml = "<shows><show><date>9/8</date><place>Toads Place</place><location>New Haven, CT</location><time>9PM</time></show></shows>"
$(function() {
$(xml).find('show').each(function() {
console.log(this);
var $show = $(this);
var date = $show.find('date').text();
var place = $show.find('place').text();
var location = $show.find('location').text();
var time = $show.find('time').text();
var html = '<tr><td class="bold">' + date + '</td><td class="hide">' + place + '</td><td>' + location + '</td><td class="bold">' + time + '</td></tr>';
$('#show_table').append($(html));
});
});
But you need to modify your html file, check my solution here: http://jsfiddle.net/a4m73/
EDITED: full solution with loading xml from URL
I combined two parts described above, check here: http://jsfiddle.net/a4m73/1/
Use jquery-xpath, then you can easily do what you want like:
$(xml).xpath("//shows/show");
if you want know more about xpath just take a look on XML Path Language (XPath) document.
var xml = "<shows><show><date>9/8</date><place>Toads Place</place><location>New Haven, CT</location><time>9PM</time></show></shows>";
$(document).ready(function () {
//$('#table').append('<h2>SHOWS</h2>');
$('#table').append('<table id="show_table">');
$(xml).xpath("//shows/show").each(function () {
var $show = $(this);
var date = $show.find('date').text();
var place = $show.find('place').text();
var location = $show.find('location').text();
var time = $show.find('time').text();
var html = '<tr><td class="bold">' + date + '</td><td class="hide">' + place + '</td><td>' + location + '</td><td class="bold">' + time + '</td></tr>';
$('#show_table').append(html);
});
})

How to get more JSON data on scroll or while scrolling?

I have the following code below which returns some results when the user searches a term.
Once i get some results,I want to add feature which will allow me to get more data when scrolling down ward?
NOTE: I dont want to use any plugin(s).
$(document).ready(function() {
$("#submit").click(function (event) { // wire up this as an onclick event to the submit button.
var searchTerm = $("#search").val(); // get the user-entered search term
var URL = "http://api.flickr.com/services/feeds/photos_public.gne";
//var URL = "http://api.flickr.com/services/feeds/photos_public.gne";
var ID = "25053835#N03";
//var MYID-"84215563#N08";
//var tagmode="&tagmode=any";
//var format ="&format=json";
var tags="&tags="+ searchTerm;
var tagmode="&tagmode=any";
var jsonFormat = "&format=json&jsoncallback=?";
var ajaxURL= URL+"?jsoncallback=?id="+ID+tags+tagmode+jsonFormat;
//var ajaxURL= URL+"?"+tags+tagmode+jsonFormat;
$.getJSON(ajaxURL,function(data){
//$("h1").text(data.title);
//alert(data.length);
var photoHTML;
$("#photos").empty();
if (data.items.length) {
alert(data.items.length);
$.each(data.items, function(i,photo) {
//var photoHTML = "<h4>" +photo.tags + "</h4>";
photoHTML = "<p>";
photoHTML += '<a href="' + photo.link + '">';
photoHTML += '<img src="' + photo.media.m + '" alt="' + photo.media.m + '" title="' + photo.media.m + '"></a>';
photoHTML = "</p>";
$('#photos').append(photoHTML).fadeIn(200);
});
} else {
alert(data.items.length);
photoHTML = "<h2> No Results</h2>";
$('#photos').append(photoHTML).fadeIn(200);
}
//$('#photos').append(photoHTML).fadeIn(200);
});
});
});
You could use the jquery .scroll() method. You have two options, save all data when page loads then display as user scrolls OR make ajax request every time there is a scroll down request.
$("#yourSelector").on('scroll', function(){
// do stuff
});
or simply using the shortcut:
$("#yourSelector").scroll(function(){
// do stuff
});
I hope this helps!
Here is a link to jquery scroll api to know about the options (such as specifying scroll DOWN): http://api.jquery.com/scroll/
You can also bind scroll event using jquery:
Put your whole code into a function:
function myfun(){
//-- you code
}
and call myfun() from both event:
on click event-
$("#submit").click(function (event) {
myfun();
});
on scroll event -
$("#yourSelector").scroll(function(){
myfun();
});

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