var getLoginpasssystem = function(getPassForgotSystem,getLoginCheckSystem){
$(document).ready(function() {
$('#login' || '#lostpasswordform').submit(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: 'http://www.virtuelles-museum.com.udev/spielelogin/logsystem.php',
data: $(this).serialize(),
success: function(response) {
var data = JSON.parse(response);
if (data.success == "accepted") {
document.getElementById('inner').innerHTML = 'Herzlich Willkommen';
// location.href = 'index.php';
} else {
alert('Ungültige Email oder Password!');
}
}
});
});
})
}
The question is how to use two forms in one request with ajax. In this code I used ||, but it doesn't work. I mean the #login form works well but the #lostpasswordform doesn't work. When I click on the button it reloads the page instead of giving an alert.
The reason for this is the way you do your jQuery selection. Selecting multiple elements is done like this: $( "div, span, p.myClass" )
In other words it should work if you replace $('#login' || '#lostpasswordform') with $('#login, #lostpasswordform')
You can read more in detail about this in the jQuery docs
elector be used to select multiple elements. $("#login,#lostpasswordform").submit()
Use below code :
var getLoginpasssystem = function(getPassForgotSystem,getLoginCheckSystem){
$(document).ready(function() {
$("#login,#lostpasswordform").submit(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: 'http://www.virtuelles-museum.com.udev/spielelogin/logsystem.php',
data: $(this).serialize(),
success: function(response) {
var data = JSON.parse(response);
if (data.success == "accepted") {
document.getElementById('inner').innerHTML = 'Herzlich Willkommen';
// location.href = 'index.php';
} else {
alert('Ungültige Email oder Password!');
}
}
});
});
})
}
Related
let getLoginPassSystem = function (getPassForgotSystem, getLoginCheckSystem) {
$(document).ready(function () {
$('#login,#lostpasswordform,#register').submit(function (e) {
e.preventDefault();
$.ajax({
type: "POST",
url: 'http://www.virtuelles-museum.com.udev/spielelogin/logsystem.php',
data: $(this).serialize(),
success: function (response) {
var data = JSON.parse(response);
if (data.success == "accepted") {
document.getElementById('inner').innerHTML = 'Herzlich Willkommen';
// location.href = 'index.php';
} else {
alert('Ungültige Email oder Password!');
}
}
});
});
})
}
Well, I want to have for every form(#login,#lostpasswordform,#register) an different "alert". Is it actually possible?
You can save an alert massage in each div tag as data attribute. For example:
<div id="login" data-msg="message1"></div>
<div id="lostpasswordform" data-msg="message2"></div>
<div id="register" data-msg="message3"></div>
// then you can invoke them like this
let getLoginPassSystem = function (getPassForgotSystem, getLoginCheckSystem) {
$(document).ready(function () {
$('#login,#lostpasswordform,#register').submit(function (e) {
e.preventDefault();
let current_form = $(this);
$.ajax({
type: "POST",
url: 'http://www.virtuelles-museum.com.udev/spielelogin/logsystem.php',
data: $(this).serialize(),
success: function (response) {
var data = JSON.parse(response);
if (data.success == "accepted") {
document.getElementById('inner').innerHTML = 'Herzlich Willkommen';
// location.href = 'index.php';
} else {
alert(current_form.attr('data-msg'));
}
}
});
});
})
}
It seems like you can simply check the e.target - it will be different for every form.
You can get more information about Event.target here: https://developer.mozilla.org/en-US/docs/Web/API/Event/target
Im quiet confused with this code. Im reading this code of ajax which inserts the data automatically. but what im confused is this line if(result=='12') then trigger ajax what does 12 means why it should be 12 then conditioned to before ajax. Apparently im still learning ajax thanks. P.S this is working well btw im just confused with the code
here is the full code of the create function javascript / ajax
$('#btnSave').click(function(){
var url = $('#myForm').attr('action');
var data = $('#myForm').serialize();
//validate form
var empoyeeName = $('input[name=txtEmployeeName]');
var address = $('textarea[name=txtAddress]');
var result = '';
if(empoyeeName.val()==''){
empoyeeName.parent().parent().addClass('has-error');
}else{
empoyeeName.parent().parent().removeClass('has-error');
result +='1'; //ALSO THIS NUMBER 1 WHY SHOULD IT BE 1?
}
if(address.val()==''){
address.parent().parent().addClass('has-error');
}else{
address.parent().parent().removeClass('has-error');
result +='2'; //ALSO THIS NUMBER 2 WHY SHOULD IT BE 2?
}
if(result=='12'){ //HERE IS WHAT IM CONFUSED
$.ajax({
type: 'ajax',
method: 'post',
url: url,
data: data,
async: false,
dataType: 'json',
success: function(response){
if(response.success){
$('#myModal').modal('hide');
$('#myForm')[0].reset();
if(response.type=='add'){
var type = 'added'
}else if(response.type=='update'){
var type ="updated"
}
$('.alert-success').html('Employee '+type+' successfully').fadeIn().delay(4000).fadeOut('slow');
showAllEmployee();
}else{
alert('Error');
}
},
error: function(){
alert('Could not add data');
}
});
}
});
As I have explained in my commentaries, and since you wanted an example. This is how I will proceed in order to avoid checking for result == '12':
$('#btnSave').click(function()
{
var url = $('#myForm').attr('action');
var data = $('#myForm').serialize();
// Validate form
var empoyeeName = $('input[name=txtEmployeeName]');
var address = $('textarea[name=txtAddress]');
var formValid = true;
if (empoyeeName.val() == '')
{
empoyeeName.parent().parent().addClass('has-error');
formValid = false;
}
else
{
empoyeeName.parent().parent().removeClass('has-error');
}
if (address.val() == '')
{
address.parent().parent().addClass('has-error');
formValid = false;
}
else
{
address.parent().parent().removeClass('has-error');
}
// If form is not valid, return here.
if (!formValid)
return;
// Otherwise, do the ajax call...
$.ajax({
type: 'ajax',
method: 'post',
url: url,
data: data,
async: false,
dataType: 'json',
success: function(response)
{
if (response.success)
{
$('#myModal').modal('hide');
$('#myForm')[0].reset();
var type = '';
if (response.type=='add')
type = 'added';
else if (response.type=='update')
type ="updated";
$('.alert-success').html('Employee ' + type + 'successfully')
.fadeIn().delay(4000).fadeOut('slow');
showAllEmployee();
}
else
{
alert('Error');
}
},
error: function()
{
alert('Could not add data');
}
});
});
It's just checking existence of values and appending string to it.
if(empoyeeName.val()=='')
This check empty name and add error if name is empty. else it concat 1 to result.
if(address.val()=='')
This check empty address and add error if address is empty. else it concat 2 to result.
So if both of them are non empty that means result will be 12 and than only you make ajax call else show error.
hey guys i'm trying to make changes in my blade template using ajax , when i press the button it changes the value of data in database and i want to display this data at once on my blade template .
that's my java script code :
(function($){
$('.wishlistForm').on('submit', function(){
var form = $(this);
$.ajax({
url: form.attr('action'),
data: form.serialize(),
method: 'post',
dataType: 'json',
success: function(response){
var wishlistButton = form.find("button[type='submit']");
var x = parseInt($('.wish-btn-count').text());
if(response.actiondone == 'added') {
$('.wish-btn-count').text(x++);
console.log(x);
wishlistButton.text(response.message);
} else if(response.actiondone == 'removed') {
$('.wish-btn-count').text(x--);
console.log(x);
wishlistButton.text(response.message);
}
}
});
return false;
});
})(jQuery);
and here is the part i want to change in my template :
<div class="wish-btn-count" id="wishlist">
{{$wishlistcount}}
</div>
so how can i do it ? and for record it returns the value right in the console but don't show it in my view
Prevent the default submit event, so you can trigger the ajax
$('.wishlistForm').on('submit', function(e){
e.preventDefault();
This may be the solution.
If you are receiving json object response from the ajax call,first you have to parse that object and then use it.
Try this,
(function($){
$('.wishlistForm').on('submit', function(){
var form = $(this);
$.ajax({
url: form.attr('action'),
data: form.serialize(),
method: 'post',
dataType: 'json',
success: function(response){
/*Add this in your code*/
var response = JSON.parse(response.trim());
var wishlistButton = form.find("button[type='submit']");
var x = parseInt($('.wish-btn-count').text());
if(response.actiondone == 'added') {
$('.wish-btn-count').text(x++);
console.log(x);
wishlistButton.text(response.message);
} else if(response.actiondone == 'removed') {
$('.wish-btn-count').text(x--);
console.log(x);
wishlistButton.text(response.message);
}
}
});
return false;
});
})(jQuery);
I want to prevent multiple ajax calls (user holds enter key down or multi presses submit or other)
I'm thinking, the best way is to use a var with the previous form post values and compare them at each click/submit.. Is it the same? : Then do nothing
But I don't know how to go about it
Here is my javascript/jquery:
$('form').submit(function() {
$theform = $(this);
$.ajax({
url: 'validate.php',
type: 'POST',
cache: false,
timeout: 5000,
data: $theform.serialize(),
success: function(data) {
if (data=='' || !data || data=='-' || data=='ok') {
// something went wrong (ajax/response) or everything is ok, submit and continue to php validation
$('input[type=submit]',$theform).attr('disabled', 'disabled');
$theform.unbind('submit').submit();
} else {
// ajax/response is ok, but user input did not validate, so don't submit
console.log('test');
$('#jserrors').html('<p class="error">' + data + '</p>');
}
},
error: function(e) {
// something went wrong (ajax), submit and continue to php validation
$('input[type=submit]',$theform).attr('disabled', 'disabled');
$theform.unbind('submit').submit();
}
});
return false;
});
Not very creative with naming vars here:
var serial_token = '';
$('form').submit(function() {
$theform = $(this);
if ($(this).serialize() === serial_token) {
console.log('multiple ajax call detected');
return false;
}
else {
serial_token = $(this).serialize();
}
$.ajax({
url: 'validate.php',
type: 'POST',
cache: false,
timeout: 5000,
data: $theform.serialize(),
success: function(data) {
if (data=='' || !data || data=='-' || data=='ok') {
// something went wrong (ajax/response) or everything is ok, submit and continue to php validation
$('input[type=submit]',$theform).attr('disabled', 'disabled');
$theform.unbind('submit').submit();
} else {
// ajax/response is ok, but user input did not validate, so don't submit
console.log('test');
$('#jserrors').html('<p class="error">' + data + '</p>');
}
},
error: function(e) {
// something went wrong (ajax), submit and continue to php validation
$('input[type=submit]',$theform).attr('disabled', 'disabled');
$theform.unbind('submit').submit();
}
});
return false;
});
You could combine this with a timeout/interval function which aborts the submit, but the code above should just compare the data in the form
If you have some kind of submit button, just add a class 'disabled' to it when you start the ajax call, and check if it is present before trying to make the call. Remove the class when the server gives a response. Something like:
...
$theform = $(this);
$button = $theform.find('input[type=submit]');
if ($button.hasClass('disabled')) {
return false;
}
$button.addClass('disabled');
$.ajax({
....
},
complete: function () {
$button.removeClass('disabled');
}
});
...
Hi i have jquery request like below ,
$('#filterForm').submit(function(e){
e.preventDefault();
var dataString = $('#filterForm').serialize();
var class2011 = document.getElementById("2011").className;
//var validate = validateFilter();
alert(dataString);
if(class2011=='yearOn')
{
dataString+='&year=2011';
document.getElementById("2011").className='yearOff';
}
else
{
document.getElementById("2011").className='yearOn';
}
alert (dataString);
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
});
and my Form is like ,
<form method="post" name="filterForm" id="filterForm">
<!-- some input elements -->
</form>
Well, I am triggering jquery submit on submit event of a form ,(it's working fine)
I want pass one extra parameter inside form which is not in above form content but it's outside in page
it's like below
[Check this image link for code preview][1]
So how can i trigger above event , on click of , element with class yearOn ( check above html snippet ) and class yearOff , with additional parameter of year set to either 2011 or 2010
$(document).ready(function () {
$('#filterForm').submit(function (e) {
e.preventDefault();
var dataString = $('#filterForm').serialize();
if ($("#2011").hasClass('yearOn')) {
dataString += '&year=2011';
$("#2011").removeClass('yearOn').addClass('yearOff');
}
else {
$("#2011").removeClass('yearOff').addClass('yearOn');
}
$.ajax({
url: "/myServlet",
type: "POST",
data: dataString,
success: function (data) {
/*var a = data;
alert(data);*/
}
});
});
});
1.) If you are using jQuery already, you can use the $.post() function provided by jquery. It will make your life easier in most cases.
2.) I have always had a successful post with extra parameters this way:
Build you extra parameters here
commands={
year:'2011'
};
Combine it with your form serialize
var dataString=$.param(commands)+'&'+$("#filterForm").serialize();
Perform your post here
$.post("myServlet",data,
function(data) {
/*var a = data;
alert(data);*/
}
);
OR use $.ajax if you really love it
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
In the end, here is the full code the way you are doing it now
$('#filterForm').submit(function(e){
e.preventDefault();
var class2011 = document.getElementById("2011").className;
//var validate = validateFilter();
alert(dataString);
if(class2011=='yearOn') {
dataString+='&year=2011';
document.getElementById("2011").className='yearOff';
} else {
document.getElementById("2011").className='yearOn';
}
commands={
year:'2011'
};
var dataString=$.param(commands)+'&'+$("#filterForm").serialize();
alert (dataString);
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
});