hey guys i'm trying to make changes in my blade template using ajax , when i press the button it changes the value of data in database and i want to display this data at once on my blade template .
that's my java script code :
(function($){
$('.wishlistForm').on('submit', function(){
var form = $(this);
$.ajax({
url: form.attr('action'),
data: form.serialize(),
method: 'post',
dataType: 'json',
success: function(response){
var wishlistButton = form.find("button[type='submit']");
var x = parseInt($('.wish-btn-count').text());
if(response.actiondone == 'added') {
$('.wish-btn-count').text(x++);
console.log(x);
wishlistButton.text(response.message);
} else if(response.actiondone == 'removed') {
$('.wish-btn-count').text(x--);
console.log(x);
wishlistButton.text(response.message);
}
}
});
return false;
});
})(jQuery);
and here is the part i want to change in my template :
<div class="wish-btn-count" id="wishlist">
{{$wishlistcount}}
</div>
so how can i do it ? and for record it returns the value right in the console but don't show it in my view
Prevent the default submit event, so you can trigger the ajax
$('.wishlistForm').on('submit', function(e){
e.preventDefault();
This may be the solution.
If you are receiving json object response from the ajax call,first you have to parse that object and then use it.
Try this,
(function($){
$('.wishlistForm').on('submit', function(){
var form = $(this);
$.ajax({
url: form.attr('action'),
data: form.serialize(),
method: 'post',
dataType: 'json',
success: function(response){
/*Add this in your code*/
var response = JSON.parse(response.trim());
var wishlistButton = form.find("button[type='submit']");
var x = parseInt($('.wish-btn-count').text());
if(response.actiondone == 'added') {
$('.wish-btn-count').text(x++);
console.log(x);
wishlistButton.text(response.message);
} else if(response.actiondone == 'removed') {
$('.wish-btn-count').text(x--);
console.log(x);
wishlistButton.text(response.message);
}
}
});
return false;
});
})(jQuery);
Related
var getLoginpasssystem = function(getPassForgotSystem,getLoginCheckSystem){
$(document).ready(function() {
$('#login' || '#lostpasswordform').submit(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: 'http://www.virtuelles-museum.com.udev/spielelogin/logsystem.php',
data: $(this).serialize(),
success: function(response) {
var data = JSON.parse(response);
if (data.success == "accepted") {
document.getElementById('inner').innerHTML = 'Herzlich Willkommen';
// location.href = 'index.php';
} else {
alert('Ungültige Email oder Password!');
}
}
});
});
})
}
The question is how to use two forms in one request with ajax. In this code I used ||, but it doesn't work. I mean the #login form works well but the #lostpasswordform doesn't work. When I click on the button it reloads the page instead of giving an alert.
The reason for this is the way you do your jQuery selection. Selecting multiple elements is done like this: $( "div, span, p.myClass" )
In other words it should work if you replace $('#login' || '#lostpasswordform') with $('#login, #lostpasswordform')
You can read more in detail about this in the jQuery docs
elector be used to select multiple elements. $("#login,#lostpasswordform").submit()
Use below code :
var getLoginpasssystem = function(getPassForgotSystem,getLoginCheckSystem){
$(document).ready(function() {
$("#login,#lostpasswordform").submit(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: 'http://www.virtuelles-museum.com.udev/spielelogin/logsystem.php',
data: $(this).serialize(),
success: function(response) {
var data = JSON.parse(response);
if (data.success == "accepted") {
document.getElementById('inner').innerHTML = 'Herzlich Willkommen';
// location.href = 'index.php';
} else {
alert('Ungültige Email oder Password!');
}
}
});
});
})
}
I want to do search and it can search many times. when it is submitted, it will show value in textbox by using document.getelementById("").value. All work well but I added ajax for filter search, document.getelementById("").value couldn't work.
$(document).ready(function() {
$('#job_no').change(function() {
$.ajax({
type: 'POST',
data: {JOB_NO: $(this).val()},
url: 'select.php',
success: function(data) {
$('#input_na').html(data);
}
});
return false;
});
});
<script type="text/javascript">document.getElementById('input_na').value = "<?php echo $_POST['input_na'];?>";</script>
Try this:
$(document).ready(function() {
$('#job_no').change(function() {
var $this = $(this); //add this line
$.ajax({
type: 'POST',
data: {JOB_NO: $this.val()}, //change this line
url: 'select.php',
success: function(data) {
$('#input_na').html(data);
}
});
return false;
});
});
the 'this' in $.ajax(..) function will not refer to $('#job_no'), so it should be assigned to another variable "$this" for use inside the ajax function.
I am trying to make an ajax call for two separate click events. The difference is for the second click event the variable testOne should not be part of the call and instead there would be a new variable. How should I approach this?
var varOne = '';
var varTwo = '';
var varThree = '';
function testAjax(){
$.ajax({
type: "POST",
dataType: 'html',
url: "http://someblabla.php",
data: {
testOne: varOne,
testTwo: varOne
}
}).done(function(data) {
$('.result').html(data);
});
}
$('.clickOne').click(function(){
varOne = 'xyz123';
varTwo = '123hbz';
testAjax();
});
$('.clickTwo').click(function(){
//varOne = 'xyz123'; // I dont need this for this click
varTwo = '123hbz';
varThree = 'kjsddfag'; // this gets added
testAjax();
});
<div class="clickOne"></div>
<div class="clickTwo"></div>
Make some like this
function testAjax(data){
$.ajax({
type: "POST",
dataType: 'html',
url: "http://someblabla.php",
data: data,
}).done(function(data) {
$('.result').html(data);
});
}
$('.clickOne').click(function(){
var data= {
varOne: 'xyz123',
varTwo: '123hbz',
}
testAjax(data);
});
$('.clickTwo').click(function(){
var data= {
varThree : 'kjsddfag',
varTwo: '123hbz',
}
testAjax(data);
});
<div class="clickOne"></div>
<div class="clickTwo"></div>
You can also do the same in other way with minimum line of code, you can call the ajax on click event and pass the data based on the element triggered the click event.
like this:
$('.ajax').click(function(e){
if($(this).hasClass('clickOne')){
var data= { varOne: 'xyz123'; varTwo: '123hbz'; }
}else{
var data= { varThree : 'kjsddfag'; varTwo: '123hbz'; }
}
$.ajax({
type: "POST",
dataType: 'json',
url: "http://someblabla.php",
data: data,
}).done(function(data) {
$('.result').html(data);
});
e.preventDefault();
});
<div class="ajax clickOne"></div>
<div class="ajax clickTwo"></div>
In this way you can put as many conditions for different data variable.
You should be doing it like this:
function testAjax(data){
$.ajax({
type: "POST",
dataType: 'html',
url: "http://someblabla.php",
data: data
}).done(function(data) {
$('.result').html(data);
});
}
$('.clickOne').click(function(){
var data {
varOne = 'xyz123',
varTwo = '123hbz'
}
testAjax(data);
});
$('.clickTwo').click(function(){
var data = {
varTwo = '123hbz',
varThree = 'kjsddfag'
}
testAjax(data);
});
<div class="clickOne"></div>
<div class="clickTwo"></div>
This way you absolute control over which variables are added to which ajax call. You should not use global variables unless you really need them to be global, which doesn't seem to be the case.
You can pass whatever JavaScript object to the data parameter of the ajax method.
I just wanted to add something. I often hide value inside the value attribute of the button tags to produce something like this.
I haven't been able to test this of course but I thought it was worth mentioning.
jquery:
var fields = '';
function testAjax(){
$.ajax({
type: "POST",
dataType: 'html',
url: "http://someblabla.php",
data: fields
}).done(function(data) {
$('.result').html(data);
});
}
$('#btn').click(function(){
var varCount = 0;
var vars = $(this).val().split('|');
$.each( vars, function( key, value ) {
varCount++;
fields = fields + 'var' + varCount + '=' + value + '&';
});
fields = fields.slice(0,-1);
$(this).val('123hbz|kjsddfag');
testAjax();
});
html:
<button id="btn" value="xyz123|123hbz"></button>
A more optimized and cleaner version -
var varTwo='junk1'
var varOne='junk2'
var varThree='junk3'
function testAjax(data){
$.ajax({
type: "POST",
dataType: 'html',
url: "http://someblabla.php",
data: data,
}).done(function(data) {
$('.result').html(data);
});
}
$('.ajaxClick').click(function(){
var data={};
if(this.classList.contains('clickOne')){
data.varOne=varOne;
data.varTwo=varTwo;
}else{
data.varThree=varThree;
data.varTwo=varTwo;
}
testAjax(data);
});
<div class="ajaxClick clickOne"></div>
<div class="ajaxClick clickTwo"></div>
Hi i have jquery request like below ,
$('#filterForm').submit(function(e){
e.preventDefault();
var dataString = $('#filterForm').serialize();
var class2011 = document.getElementById("2011").className;
//var validate = validateFilter();
alert(dataString);
if(class2011=='yearOn')
{
dataString+='&year=2011';
document.getElementById("2011").className='yearOff';
}
else
{
document.getElementById("2011").className='yearOn';
}
alert (dataString);
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
});
and my Form is like ,
<form method="post" name="filterForm" id="filterForm">
<!-- some input elements -->
</form>
Well, I am triggering jquery submit on submit event of a form ,(it's working fine)
I want pass one extra parameter inside form which is not in above form content but it's outside in page
it's like below
[Check this image link for code preview][1]
So how can i trigger above event , on click of , element with class yearOn ( check above html snippet ) and class yearOff , with additional parameter of year set to either 2011 or 2010
$(document).ready(function () {
$('#filterForm').submit(function (e) {
e.preventDefault();
var dataString = $('#filterForm').serialize();
if ($("#2011").hasClass('yearOn')) {
dataString += '&year=2011';
$("#2011").removeClass('yearOn').addClass('yearOff');
}
else {
$("#2011").removeClass('yearOff').addClass('yearOn');
}
$.ajax({
url: "/myServlet",
type: "POST",
data: dataString,
success: function (data) {
/*var a = data;
alert(data);*/
}
});
});
});
1.) If you are using jQuery already, you can use the $.post() function provided by jquery. It will make your life easier in most cases.
2.) I have always had a successful post with extra parameters this way:
Build you extra parameters here
commands={
year:'2011'
};
Combine it with your form serialize
var dataString=$.param(commands)+'&'+$("#filterForm").serialize();
Perform your post here
$.post("myServlet",data,
function(data) {
/*var a = data;
alert(data);*/
}
);
OR use $.ajax if you really love it
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
In the end, here is the full code the way you are doing it now
$('#filterForm').submit(function(e){
e.preventDefault();
var class2011 = document.getElementById("2011").className;
//var validate = validateFilter();
alert(dataString);
if(class2011=='yearOn') {
dataString+='&year=2011';
document.getElementById("2011").className='yearOff';
} else {
document.getElementById("2011").className='yearOn';
}
commands={
year:'2011'
};
var dataString=$.param(commands)+'&'+$("#filterForm").serialize();
alert (dataString);
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
});
I'm trying to use the code below, but it's not working:
UPDATED WORKING:
$(document).ready(function() {
$('.infor').click(function () {
var datasend = $(this).html();
$.ajax({
type: 'POST',
url: 'http://domain.com/page.php',
data: 'im_id='+datasend',
success: function(data){
$('#test_holder').html(data);
}
});
});
});
As you can see I used $datasend as the var to send but it doesn't return the value of it, only its name.
I would change
$datasend = $(this).html;
to
var datasend = $(this).html();
Next I would change
data: 'im_id=$datasend',
to
data: 'im_id='+datasend,