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Javascript - InnerHTML doesn't edit the DOM

I'm working on a project with Laravel. Now I'm coding the feature which prints all activities responsible. Before I was using foreach loop in PHP to print all of my activities (from the DB).
But now I have to use JS to print these activities because I want to add a filter (and avoid page to reload).
I have created this script in my view :
<script>
containerE = document.getElementById("container");
var request = new XMLHttpRequest();
request.open("GET","{{route('APIManifs')}}", false);
request.send(null);
responses = JSON.parse(request.responseText);
function expandResults(value){
for (var i in responses){
if (responses[i].status === value) {
containerE.innerHTML = containerE.innerHTML +
"<div class=\'col-md-5 offset-1\' id=\'1\'>" +
"<div class=\'card\'>" +
"<a href='/manif/" + responses[i].id + "'"+" ><div class=\'card-header\' style=\'text-align: center\'>"+
"<img src='"+responses[i].image+"'><br>"+
responses[i].name+" | "+responses[i].date_add+"<br>"+
"</div> </a>"+
"<div class=\'card-body\'>"+
"Nom : "+responses[i].name+"<br>"+
"Description : "+responses[i].description+"<br>"+
"</div>"+
"</div>"+
"</div>";
containerE.innerHTML = containerE.innerHTML + "Arg";
console.log(responses[i].status+"=="+value);
}
else{
console.log(responses[i].status+"<>"+value);
}
}
}
</script>
I got the information but impossible to print my HTML in the DOM! When I copy paste the inner HTML code in the console it's work.
Do you have any ideas on how to accomplish this?
Thank's in advance!

How can convert a XML document into a Js String?

I need this XML document (register.xml):
<?xml version="1.0" encoding="utf-8"?>
<All>
<Shoe>
<Name>All Stars</Name>
<BrandName>Converse</BrandName>
<ReleaseDate>10/2/08</ReleaseDate>
</Shoe>
<Shoe>
<Name>All Star1s</Name>
<BrandName>Converse1</BrandName>
<ReleaseDate>11/2/08</ReleaseDate>
</Shoe>
Store in this Javascript variable:
var ShoesXML
Because I actually create a html table from this Js variable that contains XML data this way:
`
var ShoesXML = "<All><Shoe><Name>All Stars</Name><BrandName>Converse</BrandName><ReleaseDate>10/2/08</ReleaseDate><Picture>pic.jpg</Picture></Shoe><Shoe><Name>All Star1s</Name><BrandName>Converse1</BrandName><ReleaseDate>11/2/08</ReleaseDate></Shoe></All>";
$(document).ready(function() {
xmlDoc=$.parseXML( ShoesXML );
$(xmlDoc).find("Shoe").each(function(i, n) {
var html = "<tr>\n" +
"<td><span>" + $(n).find("Name").text() + "</span></td>\n" +
"<td>" + $(n).find("BrandName").text() + "</td>\n" +
"<td>" + $(n).find("ReleaseDate").text() + "</td>\n" +
"</tr>";
$("table.shoetable tbody").append(html);
});
});
THE PROBLEM IS that with this way
var ShoesXML = "<All><Shoe><Name>All Stars</Name><BrandName>Converse</BrandName><ReleaseDate>10/2/08</ReleaseDate><Picture>pic.jpg</Picture></Shoe><Shoe><Name>All Star1s</Name><BrandName>Converse1</BrandName><ReleaseDate>11/2/08</ReleaseDate></Shoe></All>";
I'm setting the value manually, but I need to get it from the actual (register.xml) document and then store it in:
var ShoesXML
For later use.

Avoid duplicated function call in jquery?

I have build a function getuser() in which I recieve json data from php into javascript. I call this function when document gets ready. My problem is that I am also using jquery post for live updation of that record and for that reason I have to call that function getuser() again due to this it shows duplicate result. First when document gets ready socend on jquery post function.
HTML
<!--It has onclick event-->
<button type="submit" class="btn btn-primary modify" onclick="update_user()">UPDATE</button>
JQUERY
//This is function which gets json array from php
function getuser() {
$.get("getuser.php", function (data) {
var data = JSON.parse(data);
for (var i = 0, len = data.length; i < len; ++i) {
var student = data[i];
var slash = " / ";
$("#output").append("<tr><td>" + student.name + "</td><td>" + student.gender + "</td><td>" + student.age + "</td>" +
"<td>" + student.city + "</td><td><a href='#' style='text-decoration: none' class='update' id='" + student.id + "' onclick='reply_click(this.id)'>Update</a>" + slash + "<a style='text-decoration: none' href='#'>Delete</a></td></tr>");
}
});
}
//when document gets ready it will show the record
if($(document).ready()) {
// getuser();
getuser();
}
//This is jquery post. When I click button (in html section) it will get form values and sent to php page
//in return it will call getuser() function again which results of duplicate display of record
$(document).ready(function(){
$('.modify').click(function() {
var gender = '';
if($('.male').is(':checked')){
gender='Male';
}else{
gender='Female';
}
$.post("update.php",
{name: $('.name').val(),gender:gender,city:$('.city').val(),age:$('.age').val(),id:$('.id').val()},
function (data) {
//here is the function call again
getuser();
}
);
});
});
Kindy tell me that is there any way I avoid second call in post function and the record gets update without function call again.I need to avoid duplicate result. Thanks in advance!

First off, you need to read the docs on jquery document ready, and learn the difference between a function reference and actually calling a function. document.ready expects you to pass in a function definition to be called when the page is ready. It doesn't actively tell you if the page is ready, the first way you're calling it. The second way you're calling it is actually correct.
Second, replace $("#output").append with $("#output").html, which will update/replace the contents of that element every time, instead of just adding more and more.

Your if test will always return true because document.ready returns the JQuery object. So, you are always causing the call to getuser() to happen.
You can see the return value from document.ready() here:
console.log($(document).ready());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
This is an incorrect usage of document.ready(). You don't need to write a test for document.ready, just write a callback function for that event and let the browser do it correctly for you.
Read the docs on document.ready()
Solution:
This:
//when document gets ready it will show the record
if($(document).ready()) {
// getuser();
getuser();
}
Should be this:
//when document gets ready it will show the record
$( document ).ready(getuser);
Or even:
$(getuser);
As for you getting the results a second time, just overwrite the old results instead of appending them.
This: $("#output").append(...
Should be: $("#output").html(...

All of you thanks for your suggestions. I have found the solution here by just adding $("#tbody").html(''); in getuser() before loop. Here is the code which works fine for me
function getuser() {
$.get("getuser.php", function (data) {
var data = JSON.parse(data);
$("#tbody").html('');//newly added
for (var i = 0, len = data.length; i < len; ++i) {
var student = data[i];
var slash = " / ";
$("#output").append("<tr><td>" + student.name + "</td><td>" + student.gender + "</td><td>" + student.age + "</td>" +
"<td>" + student.city + "</td><td><a href='#' style='text-decoration: none' class='update' id='" + student.id + "' onclick='reply_click(this.id)'>Update</a>" + slash + "<a style='text-decoration: none' href='#'>Delete</a></td></tr>");
}
});
}
All of you thanks again!

Image tag won't accept src

I am trying to make an image take a value in as a source, after the image tag (and a related radio button) has been created using JavaScript. I have discerned the following from testing and alert outputs:
If the image src is provided at the creation of the image tag using an exact filepath, it will show the image correctly (e.g. src='images/0.jpg'). However, this is not helpful since I need it to work for any given image, not a specific one.
If the image src is provided at the creation of the image tag using a variable containing a filepath, it fails to generate the image tag or the radio button at all (e.g. src='" + result + '").
NOTE: The last example is not present in the code below. The result was found by moving the '$.post' section to the line directly under the 'out +=' line within the for loop.
If the image src is left blank at the creation of the image tag, the image tag and radio button are created, though the image is blank as expected. If I then try to use 'getElementByID(imgID).src' to change the image source after this, it fails to do anything. ('imgID' here is an example, not what the code says).
On top of the above, using alerts and dumping info into divs indicate that the comicID is being correctly posted, and the filepath of the image src is definitely being found, and is being copied into the variable 'result' correctly, even one line before the creation of the tag or the attempt to edit it using 'getElementById'.
At this point I'm stumped, I don't know what could logically be stopping the src from reading in.
--
Javascript:
<script>
// Loads the user's comic list from the database.
function loadComic()
{
var xmlhttp = new XMLHttpRequest();
var getID = '<?php echo $_SESSION["userID"]; ?>';
var url = "loadCom.php?userID="+getID;
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState == 4 && xmlhttp.status == 200)
{
loadComicJSON(xmlhttp.responseText);
}
}
xmlhttp.open("GET", url, true);
xmlhttp.send();
}
// JSON parsing for 'loadComic'.
function loadComicJSON(response)
{
var arr = JSON.parse(response);
var i;
var out = "";
document.getElementById("loadList").innerHTML="";
if (arr.length == 0)
{
//Irrelevant manipulation of HTML.
}
else
{
out+="<br>";
for(i = 0; i < arr.length; i++)
{
out += "<hr><br><img name = '" + ('cm' + arr[i].comicID) + "' id='" + ('com' + arr[i].comicID) + "' onclick='resizeThumb(this)' height='100px;' src='' ><input name='comicList' type='radio' id='" + arr[i].comicID + "' value='" + arr[i].comicID + "'>" + arr[i].comicName + " </option><br><br>";
}
document.getElementById("loadList").innerHTML=out;
for(j=0; j< arr.length; j++)
{
tempID = (arr[j].comicID);
$.post("getCover.php", {comicID:tempID}, function(result)
{
document.getElementById("loadList").innerHTML+="<p>"+result+"</p>";
document.getElementById("com"+arr[j].comicID).src = result;
}
);
}
}
}
</script>
PHP (getCover.php):
<?php
if (isset($_POST["comicID"]))
{
include_once('includes/conn.inc.php');
$checkID = $_POST["comicID"];
$query = ("SELECT pageLocation FROM page WHERE comicID = '$checkID' ORDER BY pageNum");
$result = mysqli_query($conn, $query);
$row = mysqli_fetch_assoc($result);
print_r($row["pageLocation"]);
}
else
{
$checkID = null;
echo "Error. No comic found.";
}
?>
To my knowledge, loadList.php is working perfectly, so I didn't list its code to keep things relevant.

I copied your code and tweaked it a little so I could run it without the web services and it works great. Here is the HTML page I created:
<!DOCTYPE html>
<html>
<head lang="en">
<meta charset="UTF-8">
<title></title>
<script>
// JSON parsing for 'loadComic'.
function loadComicJSON()
{
var arr = [{comicID: 1},{comicID: 2},{comicID: 3}];
var result = "monkey.jpeg";
var i;
var out = "";
document.getElementById("loadList").innerHTML="";
if (arr.length == 0)
{
//Irrelevant manipulation of HTML.
}
else
{
out+="<br>";
for(i = 0; i < arr.length; i++)
{
out += "<hr><br><img name = '" + ('cm' + arr[i].comicID) + "' id='" + ('com' + arr[i].comicID) + "' onclick='resizeThumb(this)' height='100px;' src='' ><input name='comicList' type='radio' id='" + arr[i].comicID + "' value='" + arr[i].comicID + "'>" + arr[i].comicName + " </option><br><br>";
}
document.getElementById("loadList").innerHTML=out;
for(j=0; j< arr.length; j++)
{
var imgSrc;
tempID = (arr[j].comicID);
document.getElementById("loadList").innerHTML+="<p>"+result+"</p>";
document.getElementById("com"+arr[j].comicID).src = result;
}
}
}
</script>
</head>
<body>
<div id="loadList"></div>
<button onclick="loadComicJSON()">Try it</button>
</body>
</html>
As you can see, I created an array of JSON objects that hold the comicID and am statically creating the image as 'monkey.jpeg'.
The code works so there is either an issue with the 'response' that you pass into your loadComicJSON method or the result from your POST method.
Add a couple of console.log statements and look at the two values I mentioned and you will likely see the issue.

Solved the issue myself. It turned out that the $.post needed to be $.get and that it needed to technically be outside of a loop (i.e. in its own function) to work properly. Works fine now after that and a couple minor tweaks.

Append image in function jquery

Good evening.
I have this jquery code which allows me, once you press the Enter key, to post a comment.
Fattio that I run an append with the username and the content that the user wants to publish.
In addition to the username I would also like to "hang" the profile picture using their path. How do I post a photo?
Thanks for your help. Here's the code:
function commento_post(id_post)
{
$('.form-commento'+id_post).click(function ()
{
$('#ins_commento'+id_post).keydown(function (e)
{
var message = $("#commento"+id_post).val();
var username = $("#username").val();
var id_user = $("#id_user").val();
if(e.keyCode === 13)
{
$.ajax(
{
type: 'POST',
url: 'http://localhost/laravel/public/index.php/post/ins_commento',
data: { commento: message, id_post: id_post },
success: function(data)
{
$('#commento'+id_post).val('');
$('#commentscontainer'+id_post).append
(
/*$(".username-commento"+id_post).html
(*/
$('<a/>',
{
text : username, href : 'http://localhost/laravel/public/index.php/utente/'+id_user
}).css({'font-weight':'bold'})
//)
).append(' ').append(message).append($('<br/>'));
var el = $('#numero_commenti'+id_post);
var num = parseInt(el.text());
el.text(num + 1);
}
});
}
});
});
}

In your success function, you could simplify everything quite a bit in the following way while not using jQuery append so much, but just using a variable to store your code and then appending it in one go. This will allow you to append all sort of elements, it's easily parseable for the you and it reduces the amount of calls you have to make.
// Add whatever you want your final HTML to look like to this variable
var html = "<a href='http://localhost/laravel/public/index.php/utente/" + id_user + "' style='font-weight: bold;'>" + username + "</a>";
html += message;
// add an image
html += "<img src='path/to/image.jpg' />"
html += "<br />";
// append to code you constructed above in one go
$('#commentscontainer' + id_post).append(html);
Update
I amended an incorrect quote and changed + id_user + "to + id_user + "', which makes everything after it work.